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  • Remove short tag in html 4 validation using aspx

    - by iPhone Fun
    hi all, I am new to HTML 4 validations, in that if I put HEAD runat="server" tag I am getting this error - Error Line 6, Column 82: character data is not allowed here …lesheet" type="text/css" media="all" / In the head tag I have called css files. So if any one know about thin can help me,how to solve this error? Thanks in advance. and sorry for my bad english...

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  • Undefined index: email in C:\wamp\www\emailvalidate.php on line 4

    - by klari
    I am new to Ajax. In my Ajax I get the following error message : Notice: Undefined index: address in C:\wamp\www\test\sample.php on line 11 I googled but I didn't get a solution for my specified issue. Here is what I did. HTML Form with Ajax (test1.php) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script> function loadXMLDoc() { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("mydiv").innerHTML=xmlhttp.responseText; } } xmlhttp.open("POST","test2.php",true); xmlhttp.send(); } </script> </head> <body> <form id="form1" name="form1" method="post" action="sample.php"> <p> <label for="mail"></label> <input type="text" name="mail" id="mail" onblur="loadXMLDoc()" /> <input type="submit" name="submit" id="submit" value="Submit" /> </p> <p><div id = 'mydiv'></div></p> </form> </body> </html> test2.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php echo "Your Address is ".$_POST['address']; ?> </body> </html> I am sure it is very simple issue but I don't know how to solve it. Any help ?

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  • Message passing chrome extension

    - by Mayur Kataria
    I wants to create an extension where content script will send message to background page and then on browser action means clicking on extension icon will access that background page and get some data.I am using chrome Version 23.0.1271.64 m on windows8. I am getting following error. Port error: Could not establish connection. Receiving end does not exist. I tried to solve the same. but people are using sendRequest which is not supported by chrome20+. i also found solution mentioned for chrome 20+. But not working. Please help. Below is the file contents. manifest.json { "name": "Test Extension", "version": "1.0", "manifest_version": 2, "description": "A test extension.", "background": "background.html", "content_scripts": [ { "matches": ["<all_urls>"], "js": ["jquery.js","content.js"] } ], "permissions": ["tabs", "http://*/", "https://*/"], "browser_action": { "default_icon": "icon.png", "default_popup": "popup.html" } } background.html <html> <head> <script src="background.js"></script> </head> <body> <h1>Wy</h1> </body> </html> background.js chrome.extension.onMessage.addListener(function(request, sender, sendResponse) { // Chrome 20+ alert(request); console.log('received in listener'); sendResponse({farewell: "goodbye"}); }); content.js $(function(){ console.log('start-sending message'); chrome.extension.sendMessage({greeting: "hello"},function(response){alert(response);}); console.log('end-sending message'); }); popup.html <!doctype html> <html> <head> <title>Getting Started Extension's Popup</title> </style> <!-- JavaScript and HTML must be in separate files for security. --> <script src="jquery.js"></script> <script src="popup.js"></script> </head> <body> </body> </html> popup.js $(function(){ var str_html = "<tr><td width='60%'>S</td><td width='40%'>15</td></tr><tr><td width='60%'>M</td><td width='40%'>25</td></tr>"; $('#sizes_container').html(str_html); var bkg = chrome.extension.getBackgroundPage(); console.log(bkg); });

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  • Track only iframe history

    - by evanwong
    I have a page which contains an iframe and I want to track the history of the iframe only. I tried to use the history object like this: <!DOCTYPE html> <html> <head> <title></title> <script type="text/javascript"> function checkFrameHistory() { alert(window.frames["test2"].history.length); } function checkThisHistory() { alert(history.length); } </script> </head> <body> <iframe name="test2" src="test2.html"></iframe> <div> <input type="button" onclick="checkFrameHistory()" value="Frame history"/> <input type="button" onclick="checkThisHistory()" value="This history"/> </div> </body> </html> test2.html <!DOCTYPE html> <html> <head> <title></title> <script type="text/javascript"> function checkMyHistory() { alert(history.length); } </script> </head> <body> <div> Test2 </div> <div> <input type="button" onclick="checkMyHistory()" value="My history"/> </div> </body> </html> but it actually gave me the history including the parent window. For instance, I went to another site in the main window and came back to my iframe test site. Both window.frames["test2"].history.length and history.length still gave me the same count by increasing the length by 2. Did I do it wrong? Is there a way to track only the iframe history?

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  • May be an IE z-index bug?

    - by baikaishiuc
    Below is my code. when open the page in ie browser, then select the text in div, the text will be replaced by some shadow quad blank . If you delete a line z-index:0, in css class test1, the ie will perform correctly. In my project , the z-index must be set greater than zero, so I couldn't delete the line. I found a solution is to set bg_img.filter = "" when pannel.z-index greater than 0, then ie will also working good. But unfortunately, the bg_img.filter.alpha must be set, too. So how could I do? test .test1 { position:absolute; background:#ffffff; left:20px; top:20px; border:1px solid; width:198px; height:500px; filter: progid:DXImageTransform.Microsoft.Shadow(color="#999999", Direction=135, Strength=5); z-index:0; } </style> <script> function init () { var pannel = document.createElement ('div'); var bg_img = document.createElement ('div'); var head = document.createElement ('div'); pannel.setAttribute('class', 'test1'); pannel.setAttribute('className', 'test1'); bg_img.style.cssText = "position:relative;left:0px;top:0px;" + "width:198px;" + "height:500px;" + "filter:alpha(opacity=100);"; head.style.cssText = "position:absolute;" + "left:0px;" + "top:0px;" + "width:180px;" + "height:20px;"; document.body.appendChild (pannel); pannel.appendChild(bg_img); pannel.appendChild(head); head.innerHTML = "<div>yusutechasdf</div><div>innerhtml</div>" } </script>

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  • Where am I? * (no branch)

    - by Neofizz
    I've been getting familiar with creating, merging and deleting branches. I like to know where I am so I don't commit work into the wrong branch. I use git branch -a to see which branches I have. I think the asterix * shows which branch I'm currently on. What does it mean when I get: * (no branch) master origin/HEAD Because when I $git checkout mybranch I expect to see * mybranch master origin/HEAD

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  • walking list in KDB/kernel debugger

    - by user291849
    I need to walk a link list in the kernel debugger. How can I determine the head pointer and walk the list? I have a listing and can find the address and location in the code where I check to see if I have a head, so I know the specific code location and address. But not sure how to determine the pointer or how to determine the next element and pointer on the list.

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  • Why is the data I am printing not in a table format

    - by udaya
    Hi This is my program .when i submit the print button i can print the datas but they are not aligned in the table formatthe format in which i need the print to be...How can i print in the correct format <html> <head> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.1.min.js" > </script> <script type="text/javascript"> function PrintElem(elem) { //alert('ddd'); Popup($(elem).text()); } function Popup(data) { var mywindow = window.open('', 'mydiv', 'height=400,width=600'); mywindow.document.write('<html><head><title>my div</title>'); /*optional stylesheet*/ //mywindow.document.write('<link rel="stylesheet" href="main.css" type="text/css" />'); mywindow.document.write('</head><body >'); mywindow.document.write(data); mywindow.document.write('</body></html>'); mywindow.document.close(); mywindow.print(); return true; } </script> </head> <body> <div id="mydiv"> <table width="200" border="1"> <tr> <td>sss</td> <td>sssss;</td> <td>snssbsp;</td> </tr> <tr> <td>ssss;</td> <td>sssnbsp;</td> <td>snbsp;</td> </tr> <tr> <td>snbsp;</td> <td>snbsp;</td> <td>snbsp;</td> </tr> </table> </div> <input type="button" value="Print Div" onClick="PrintElem('#mydiv')" /> </body> </html>

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  • My webpage ignores changes in CSS file

    - by Pavel
    No matter what I change in my .css file, the page remains the same - what's more, neither changing the link tag so that it points to another .css file nor deleting it completely makes no difference. Other changes in html code are applied. The sourcecode of the webpage shows everything as it should be. This behavior started when I redirected the link tag from previous file to the one I use now (plus there have been some changes in the tag while this problem occured, to test the behavior of my webpage); changes in neither file affect the page. For the first time when this happened, this was caused by copies of head tag in included chunks of code (for header, left menu etc. - their head part overrode the head part of the main page) and the problem was solved by removing these redundant heads from these files. But it happened again when I changed the link tag for the next time. I couldn't find any head parts in my included files, but the problem lasts (only solution I can see now is to delete the included files and copy the code directly to the file, but this would mean lots of redundant code). How can I solve this problem, so that my page response to changes in .css files without increasing redundancy? How to ensure that I can change the link to .css file just on one place with no such problems? Do I have to unload the CSS file somehow? I saw this problem both in Firefox and in Chrome. I use PSPad to write the code, just in case it would play role. EDIT: I have cleared browser cache now, and I changed the link to .css files from one to another before, but nothing helped. Now I accept the best answer saying the problem is in caching and I start a related question to find out how to solve the caching issue. If the other question's answers would say that in this case I can be sure that problem isn't in caching (very unlikely, but fail of ordinary methods of caching-problems-solving is unlikely too), I'd update this question and start searching for other possible problems, but now the message seems to be clear: when webpage ignores changes in .css files, caching is to blame.

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  • Pass data to another page

    - by user2331416
    I am trying to pass some data from one page to another page by using jquery but it dose not working, below is the code which I want to click the text in source page and the destination page will hide the current text. Source page: <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <script type="text/javascript"> $(function () { $("a.pass").bind("click", function () { var url = "Destination.html?name=" + encodeURIComponent($("a.pass").text()); window.location.href = url; }); }); </script> </head> <body> <a class="pass">a</a><br /> <a class="pass">b</a><br /> <a class="pass">c</a><br /> <a class="pass">d</a> </body> </html> Destination page: <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <script type="text/javascript"> var queryString = new Array(); $(function () { if (queryString.length == 0) { if (window.location.search.split('?').length > 1) { var params = window.location.search.split('?')[1].split('&'); for (var i = 0; i < params.length; i++) { var key = params[i].split('=')[0]; var value = decodeURIComponent(params[i].split('=')[1]); queryString[key] = value; } } } if (queryString["name"] != null) { var data = queryString["name"] $("p.+'data'").hide(); } }); </script> </head> <body> <p class="a">a</p> <p class="b">b</p> <p class="c">c</p> <p class="d">d</p> </body> </html> Please Help.

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  • Apache outputs all urls of a second domain as a subfolder of the primary domain name

    - by s_rathbone
    Hi all, would anyone be able to possibly give me some guidance.. Basically, i have a 'shared hosting' account with a large internet hosting provider, and my account lets me have multiple seperate domains within this folder structure.(note: not aliased domains and not sub domains). so, my goal is to have 2 domains set up. i have already purchased the two domain names i need: The first domain is the 'primary' domain name for the root folder(eg. www.example1.com) and the second domain name is set for one of its sub folders(eg. www.example2.com is set to the folder www.example1.com/sites/music). The problem is that when apache returns a page of the second domain back to the browser, apache writes the hyperlinks as if it's a sub folder of the first domain ( eg. www.example2.com/index.html. comes out as http://www.example1.com/sites/music/index.html). Now, I have done some reading on this, looking though "Apache: the definitive guide"(o'reilly), and although it was useful, couldn't really find the answer. i'm guessing this issue is most likely an apache setup issue in http.conf, rather than an issue with the hosting company itself (which is why im posting it here) and I have also been to the official documentation for apache site, and i am guessing i might need to use something like the rewritebase directive in htaccess files.. but im really not sure, im more of a java programmer guy, and have been struggling with this for a couple of days. Any guidance would be REALLY appreciated. If it helps, my hosting company is godaddy, and my sites are hosted on linux. My problem was originally with wordpress which i reinstalled a number of times in various ways to correct the problem, but ive just done a test with a very simple static html, and it still has the same issue with relative urls like this: <html> <head></head><body><a href="images/dog.html">Pictures of Dogs</a></body> </html> However, it is fine if i hardcode the urls like this: <html> <head></head><body><a href="http://www.example2.com/images/dog.html">Pictures of Dogs</a></body> </html> Thanks heaps, Steve R NOW FIXED Ok, the problem has now been fixed, and i didn't need to modify any .conf or .htaccess files. The problem was, that when I went to install the second application into a second domain from the godaddy site, one of the setup questions is that it asks you which site you want it installed to. after that it asks for the desired folder path. However, the problem was that the second domain name was already pointing to the correct subfolder of the primary domain. So when I started installing wordpress again and came to the menu to select which site it was for, and it listed only the primary domain as an option, i assumed that this was like a label of "which hosting account?", or "which primary domain will your application will be installed under?" because I already knew that in the next step i was specifiying the folder. In order to correct this, you must make sure that your second domain is added to your domain list so that it will be listed as an option during the installation process. For further details please read tystips.com/archives/52/how2-save-money-host-multiple-wordpress-blogs-on-a-single-godaddy-hosting-account/

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  • Intelligent "Subtraction" of one text logfile from another

    - by Vi
    Example: Application generates large text log file A with many different messages. It generates similarly large log file B when does not function correctly. I want to see what messages in file B are essentially new, i.e. to filter-out everything from A. Trivial prototype is: Sort | uniq both files Join files sort | uniq -c grep -v "^2" This produces symmetric difference and inconvenient. How to do it better? (including non-symmetric difference and preserving of messages order in B) Program should first analyse A and learn which messages are common, then analyse B showing with messages needs attention. Ideally it should automatically disregard things like timestamps, line numbers or other volatile things. Example. A: 0:00:00.234 Received buffer 0x324234 0:00:00.237 Processeed buffer 0x324234 0:00:00.238 Send buffer 0x324255 0:00:03.334 Received buffer 0x324255 0:00:03.337 Processeed buffer 0x324255 0:00:03.339 Send buffer 0x324255 0:00:05.171 Received buffer 0x32421A 0:00:05.173 Processeed buffer 0x32421A 0:00:05.178 Send buffer 0x32421A B: 0:00:00.134 Received buffer 0x324111 0:00:00.137 Processeed buffer 0x324111 0:00:00.138 Send buffer 0x324111 0:00:03.334 Received buffer 0x324222 0:00:03.337 Processeed buffer 0x324222 0:00:03.338 Error processing buffer 0x324222 0:00:03.339 Send buffer 0x3242222 0:00:05.271 Received buffer 0x3242FA 0:00:05.273 Processeed buffer 0x3242FA 0:00:05.278 Send buffer 0x3242FA 0:00:07.280 Send buffer 0x3242FA failed Result: 0:00:03.338 Error processing buffer 0x324222 0:00:07.280 Send buffer 0x3242FA failed One of ways of solving it can be something like that: Split each line to logical units: 0:00:00.134 Received buffer 0x324111,0:00:00.134,Received,buffer,0x324111,324111,Received buffer, \d:\d\d:\d\d\.\d\d\d, \d+:\d+:\d+.\d+, 0x[0-9A-F]{6}, ... It should find individual words, simple patterns in numbers, common layouts (e.g. "some date than text than number than text than end_of_line"), also handle combinations of above. As it is not easy task, user assistance (adding regexes with explicit "disregard that","make the main factor","don't split to parts","consider as date/number","take care of order/quantity of such messages" rules) should be supported (but not required) for it. Find recurring units and "categorize" lines, filter out too volatile things like timestamps, addresses or line numbers. Analyse the second file, find things that has new logical units (one-time or recurring), or anything that will "amaze" the system which has got used to the first file. Example of doing some bit of this manually: $ cat A | head -n 1 0:00:00.234 Received buffer 0x324234 $ cat A | egrep -v "Received buffer" | head -n 1 0:00:00.237 Processeed buffer 0x324234 $ cat A | egrep -v "Received buffer|Processeed buffer" | head -n 1 0:00:00.238 Send buffer 0x324255 $ cat A | egrep -v "Received buffer|Processeed buffer|Send buffer" | head -n 1 $ cat B | egrep -v "Received buffer|Processeed buffer|Send buffer" 0:00:03.338 Error processing buffer 0x324222 0:00:07.280 Send buffer 0x3242FA failed This is a boring thing (there are a lot of message types); also I can accidentally include some too broad pattern. Also it can't handle complicated things like interrelation between messages. I know that it is AI-related. May be there are already developed tools?

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  • Apache doesn't run multiple requests

    - by Reinderien
    I'm currently running this simple Python CGI script to test rudimentary IPC: #!/usr/bin/python -u import cgi, errno, fcntl, os, os.path, sys, time print("""Content-Type: text/html; charset=utf-8 <!doctype html> <html lang="en"> <head> <meta charset="utf-8" /> <title>IPC test</title> </head> <body> """) ftempname = '/tmp/ipc-messages' master = not os.path.exists(ftempname) if master: fmode = 'w' else: fmode = 'r' print('<p>Opening file</p>') sys.stdout.flush() ftemp = open(ftempname, fmode) print('<p>File opened</p>') if master: print('<p>Operating as master</p>') sys.stdout.flush() for i in range(10): print('<p>' + str(i) + '</p>') sys.stdout.flush() time.sleep(1) ftemp.close() os.remove(ftempname) else: print('<p>Operating as a slave</p>') ftemp.close() print(""" </body> </html>""") The 'server-push' portion works; that is, for the first request, I do see piecewise updates. However, while the first request is being serviced, subsequent requests are not started, only to be started after the first request has finished. Any ideas on why, and how to fix it? Edit: I see the same non-concurrent behaviour with vanilla PHP, running this: <!doctype html> <html lang="en"> <!-- $Id: $--> <head> <meta charset="utf-8" /> <title>IPC test</title> </head> <body> <p> <?php function echofl($str) { echo $str . "</b>\n"; ob_flush(); flush(); } define('tempfn', '/tmp/emailsync'); if (file_exists(tempfn)) $perms = 'r+'; else $perms = 'w'; assert($fsync = fopen(tempfn, $perms)); assert(chmod(tempfn, 0600)); if (!flock($fsync, LOCK_EX | LOCK_NB, $wouldblock)) { assert($wouldblock); $master = false; } else $master = true; if ($master) { echofl('Running as master.'); assert(fwrite($fsync, 'content') != false); assert(sleep(5) == 0); assert(flock($fsync, LOCK_UN)); } else { echofl('Running as slave.'); echofl(fgets($fsync)); } assert(fclose($fsync)); echofl('Done.'); ?> </p> </body> </html>

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  • Apache server doesn't create directory or file under www-data user [duplicate]

    - by Harkonnen
    This question already has an answer here: What permissions should my website files/folders have on a Linux webserver? 4 answers very newbie to Apache here I installed Apache 2.4 on my Arch server where I installed newznab (a newsgroups indexer). I have noticed that all files newznab needs to create are created under my login user, and not apache default user (www-data). I read here that it's bad security practice to allow www-data to write files. I agree. But as an apache newbie, I would like to know where (in the httpd.conf I suppose ?) the user allowed to write files can be configured, because I want another account to be allowed to write files instead of my main account.

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  • Moving a file using PuTTY

    - by Paul Trotter
    I am newbie struggling to move a file on a Linux VPS using PuTTY. I can log in with a user in PuTTY at this point I can navigate to see the file I wish to move (~/servers/apache-solr-3.6.2/example/webapps/solr.war). By using cd .. a couple of times from the directory I begin at when I first log in to PuTTY I can then navigate to the location I wish to move the file to: usr/local/jakarta/apache-tomcat-5.5.36/webapps/ I know that I need to use cp to copy the file and have tried variations on: cp ~/servers/apache-solr-3.6.2/example/webapps/solr.war usr/local/jakarta/apache-tomcat-5.5.36/webapps However each time I get 'No such file or directory' I have tried excluding the ~/ and the start and I have tried specifying solr.war at the end of the command. Please excuse the newbie question, but I would really appreciate some advice on what I am doing wrong here.

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  • Back up Linux environment

    - by joesavage
    I'm currently in the process of installing a bunch of stuff I need and getting setup my Linode that I recently purchased. Being a Linux newbie, I'm doing pretty well - but one small mistake can screw everything up for me. I've currently got apache2 and some other things successfully installed and setup how I want them, and DO NOT want this to be ruined by some newbie mistake. What is the easiest way to backup the actual environment itself so that I can restore the backed up environment (with apache2 and things fully working) if I mess up?

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  • Unable to install Win XP nor Win 7 after installing Ubuntu 11.1

    - by Pablo C. Garcia
    I'll try to make this scenario as clear as possible. Laptop Specs HP dv6-2189la: 500 HDD 4GB Ram Intel i7 Personal Specs - Linux newbie running for the first time. Quite confused :( I had Windows 7 x64, decided to start fresh new so I planned on formatting. Since I use it for work and didn't require it for another week, I didn't rush into installing Win 7 immediately as I wanted to try Ubuntu for quite a while. 1) Downloaded Ubuntu 11.1 2) Burned ISO to CD 3) Installed Ubuntu using the full HDD of 500GB erasing Win7 4) Ubuntu ran awesome (especially for me being a Linux Newbie from scratch) I used Ubuntu for a while, but now I need to get back to work with Win 7. Tried running the installation CD for Win 7 and it just skips to Ubuntu without loading. Checked BIOS, tried other discs, even tried the disc on another computer and it works. Since that didn't work, I tried running Win XP. This CD does load, it starts loading files, drives, kernel, blah blah and before even getting to install it Blue screens with error 0x0000007b. I already used Gparted and created up to 250 GB space for Windows. Formatted to NTFS. I really don´t know what do now. I've tried almost everything I know within my knowledge. I could say I'm an advanced PC user, but I bumped into the Linux wall starting from scratch. All suggestions will be appreciated. Thanks!

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  • ubuntu 11.10 foreman error

    - by user1060759
    Like this post I am also trying to complete this heroku tutorial I have installed and used everything (node.js, npm, express) successfully until I got to Foreman. I installed Foreman by first installing Ruby: alex@ubuntu:~$ sudo apt-get install ruby1.9.1 then installing Foreman. I am a newbie to Unix so I "sudo" perhaps unnecessarily here, but I got confirmation in the terminal that it had installed but also some errors: alex@ubuntu:~/NodeHelloWorld$ sudo gem install foreman Invalid gemspec in [/var/lib/gems/1.8/specifications/foreman-0.26.1.gemspec]: invalid date format in specification: "2011-11-10 00:00:00.000000000Z" Invalid gemspec in [/var/lib/gems/1.8/specifications/term-ansicolor-1.0.7.gemspec]: invalid date format in specification: "2011-10-13 00:00:00.000000000Z" Invalid gemspec in [/var/lib/gems/1.8/specifications/foreman-0.26.1.gemspec]: invalid date format in specification: "2011-11-10 00:00:00.000000000Z" Invalid gemspec in [/var/lib/gems/1.8/specifications/term-ansicolor-1.0.7.gemspec]: invalid date format in specification: "2011-10-13 00:00:00.000000000Z" Successfully installed term-ansicolor-1.0.7 Successfully installed foreman-0.26.1 Then when I try to start foreman I get similar: alex@ubuntu:~/NodeHelloWorld$ foreman start Invalid gemspec in [/var/lib/gems/1.8/specifications/foreman-0.26.1.gemspec]: invalid date format in specification: "2011-11-10 00:00:00.000000000Z" Invalid gemspec in [/var/lib/gems/1.8/specifications/term-ansicolor-1.0.7.gemspec]: invalid date format in specification: "2011-10-13 00:00:00.000000000Z" /usr/lib/ruby/vendor_ruby/1.8/rubygems.rb:926:in `report_activate_error': Could not find RubyGem foreman (>= 0) (Gem::LoadError) from /usr/lib/ruby/vendor_ruby/1.8/rubygems.rb:244:in `activate_dep' from /usr/lib/ruby/vendor_ruby/1.8/rubygems.rb:236:in `activate' from /usr/lib/ruby/vendor_ruby/1.8/rubygems.rb:1307:in `gem' from /usr/local/bin/foreman:18 Can anyone help me? I am a newbie to Unix after finally dumping windows as I found I could not get foreman-windows to work for me either I have found this post from someone with apparently the same issue. Does this mean my version of ruby could be wrong? I am running 1.9.1, though again new to ruby as well; alex@ubuntu:~/NodeHelloWorld$ ruby1.9.1 -v ruby 1.9.2p290 (2011-07-09 revision 32553) [i686-linux] Thanks

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  • When is the right time to join open source project for programmer?

    - by Mahesh
    Most of the newcomers in programming start with basic projects to start with programming. Most of the C++ progammers spend some time with puzzles and contests but this is not always helpful. Sometimes you've to spend some time on real projects. Starting your own open source project could be a problem in self-learning for newbie cause of lack of mentors and peers who can't look at your code and give suggestions. Open source projects can solve this problem, some projects could be best suited for new programmers. Besides everybody is newbie at some point. So i'll try and make this question a bit from beginners perspective. I tried few questions on stack overflow before asking this like How do i join & Bare minimum you need and how to get involved with open source and what level of programming etc. But this is not helping me when it comes to self-evaluating with skills. How to find that out ? How can i check what it takes to join open source project and am i really that comfortable with huge source code etc. My question is when to consider yourself comfortable joining open source programming ? I mean how will you test yourself that you're ready to take burden of big/small projects of open source ? how will you test yourself to see if you could work with version control/other programmers/tight schedule etc ?

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  • Advantages of Scala vs. Groovy with JAVA EE 6 Applications.

    - by JAVA EE Wannabe
    Please let me first emphasize that I am not looking for flare wars. I just want advices from people who have real experiences. I started learning JAVA EE 6 as real newbie and am having had time choosing what tools to use. First problem is what is the advantage of using Scala vs. Groovy with Java EE 6 apps over Java? I've seen on some blogs people mentioning you gonna write less code but as a newbie I don't know what other advantages and disadvantages are there. Second problem is Netbeans 6.9 or Helios 3.6.1? I realized that with eclipse I can easily mix EE 6 applications with Groovy or Scala without any problems (I only did this by displaying a String message from Scala and Groovy classes.). With Netbeans the only I can think of is having separate Java project libraries and using the jars in my web app. But also realize to the extent of my little knowledge Netbeans has better support for Java EE 6. Please need your expert advice. Thanks.

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  • Why do VMs need to be "stack machines" or "register machines" etc.?

    - by Prog
    (This is an extremely newbie-ish question). I've been studying a little about Virtual Machines. Turns out a lot of them are designed very similarly to physical or theoretical computers. I read that the JVM for example, is a 'stack machine'. What that means (and correct me if I'm wrong) is that it stores all of it's 'temporary memory' on a stack, and makes operations on this stack for all of it's opcodes. For example, the source code 2 + 3 will be translated to bytecode similar to: push 2 push 3 add My question is this: JVMs are probably written using C/C++ and such. If so, why doesn't the JVM execute the following C code: 2 + 3..? I mean, why does it need a stack, or in other VMs 'registers' - like in a physical computer? The underlying physical CPU takes care of all of this. Why don't VM writers simply execute the interpreted bytecode with 'usual' instructions in the language the VM is programmed with? Why do VMs need to emulate hardware, when the actual hardware already does this for us? Again, very newbie-ish questions. Thanks for your help

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  • Unable to start Ubuntu 12.04. The system is running in low-graphics

    - by kaleidoscpicsoul
    I am a newbie to Ubuntu. I installed Ubuntu 12.04 using a USB Stick and it was running all fine for a few weeks and this error popped up. According to one of my friend, the best way was to re-install Ubuntu. Being from a non unix background i thought the same too and after the second install it happened again, but only this time was much quicker, in 3 days. I don't want to re-install Ubuntu every time this happens. I am a complete newbie to Linux which means that i am really bad at using terminal. I know there are other people who fixed this issue using this very same forum, but unfortunately the answers provided are too complex for me to understand. Please let me know how to do this. Things I want to let you know: I would need help step by step if that is alright with you. After i get the error i get the options and i click exit to console login I get the following message in a black screen (which i think is a command line sort of thing): * Stopping save kernel messages [OK] apache2: Could not reliably determine the server's fully qualified domain name,using 127.0.1.1 for ServerName [OK] * Starting web server apache2 and a blinking cursor. So basically it looks like a dead end for my non unixy eye. And one final thing is before this issue had happened i had tried configuring Python to Apache2. For that i had uninstalled and installed LAMP server several time and edited the configuration files too. I don't know if this really is a concern, but I don't know.. I have a USB with Ubuntu 12.04 in it so i can install it anytime. (But i want to know what the issue is rather than running away) . I migrated to Ubuntu from Windows and i have no plans to go back. I think that's from my side. Please let me know if there are any questions.

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  • Mobile enabled web apps with ASP.NET MVC 3 and jQuery Mobile

    - by shiju
    In my previous blog posts, I have demonstrated a simple web app using ASP.NET MVC 3 and EF Code First. In this post, I will be focus on making this application for mobile devices. A single web site will be used for both mobile browsers and desktop browsers. If users are accessing the web app from mobile browsers, users will be redirect to mobile specific pages and will get normal pages if users are accessing from desktop browsers. In this demo app, the mobile specific pages are maintained in an ASP.NET MVC Area named Mobile and mobile users will be redirect to MVC Area Mobile. Let’s add a new area named Mobile to the ASP.NET MVC app. For adding Area, right click the ASP.NET MVC project and  select Area from Add option. Our mobile specific pages using jQuery Mobile will be maintained in the Mobile Area. ASP.NET MVC Global filter for redirecting mobile visitors to Mobile area Let’s add an ASP.NET MVC Global filter for redirecting mobile visitors to Mobile area. The below Global filter is taken from the sample app http://aspnetmobilesamples.codeplex.com/ created by the ASP.NET team. The below filer will redirect the Mobile visitors to an ASP.NET MVC Area Mobile. public class RedirectMobileDevicesToMobileAreaAttribute : AuthorizeAttribute     {         protected override bool AuthorizeCore(System.Web.HttpContextBase httpContext)         {             // Only redirect on the first request in a session             if (!httpContext.Session.IsNewSession)                 return true;               // Don't redirect non-mobile browsers             if (!httpContext.Request.Browser.IsMobileDevice)                 return true;               // Don't redirect requests for the Mobile area             if (Regex.IsMatch(httpContext.Request.Url.PathAndQuery, "/Mobile($|/)"))                 return true;               return false;         }           protected override void HandleUnauthorizedRequest(AuthorizationContext filterContext)         {             var redirectionRouteValues = GetRedirectionRouteValues(filterContext.RequestContext);             filterContext.Result = new RedirectToRouteResult(redirectionRouteValues);         }           // Override this method if you want to customize the controller/action/parameters to which         // mobile users would be redirected. This lets you redirect users to the mobile equivalent         // of whatever resource they originally requested.         protected virtual RouteValueDictionary GetRedirectionRouteValues(RequestContext requestContext)         {             return new RouteValueDictionary(new { area = "Mobile", controller = "Home", action = "Index" });         }     } Let’s add the global filer RedirectMobileDevicesToMobileAreaAttribute to the global filter collection in the Application_Start() of Global.asax.cs file   GlobalFilters.Filters.Add(new RedirectMobileDevicesToMobileAreaAttribute(), 1); Now your mobile visitors will be redirect to the Mobile area. But the browser detection logic in the RedirectMobileDevicesToMobileAreaAttribute filter will not be working in some modern browsers and some conditions. But the good news is that ASP.NET’s browser detection feature is extensible and will be greatly working with the open source framework 51Degrees.mobi. 51Degrees.mobi is a Browser Capabilities Provider that will be working with ASP.NET’s Request.Browser and will provide more accurate and detailed information. For more details visit the documentation page at http://51degrees.codeplex.com/documentation. Let’s add a reference to 51Degrees.mobi library using NuGet We can easily add the 51Degrees.mobi from NuGet and this will update the web.config for necessary configuartions. Mobile Web App using jQuery Mobile Framework jQuery Mobile Framework is built on top of jQuery that provides top-of-the-line JavaScript in a unified User Interface that works across the most-used smartphone web browsers and tablet form factors. It provides an easy way to develop user interfaces for mobile web apps. The current version of the framework is jQuery Mobile Alpha 3. We need to include the following files to use jQuery Mobile. The jQuery Mobile CSS file (jquery.mobile-1.0a3.min.css) The jQuery library (jquery-1.5.min.js) The jQuery Mobile library (jquery.mobile-1.0a3.min.js) Let’s add the required jQuery files directly from jQuery CDN . You can download the files and host them on your own server. jQuery Mobile page structure The basic jQuery Mobile page structure is given below <!DOCTYPE html> <html>   <head>   <title>Page Title</title>   <link rel="stylesheet" href="http://code.jquery.com/mobile/1.0a3/jquery.mobile-1.0a1.min.css" />   <script src="http://code.jquery.com/jquery-1.5.min.js"></script>   <script src="http://code.jquery.com/mobile/1.0a3/jquery.mobile-1.0a3.min.js"></script> </head> <body> <div data-role="page">   <div data-role="header">     <h1>Page Title</h1>   </div>   <div data-role="content">     <p>Page content goes here.</p>      </div>   <div data-role="footer">     <h4>Page Footer</h4>   </div> </div> </body> </html> The data- attributes are the new feature of HTML5 so that jQuery Mobile will be working on browsers that supporting HTML 5. You can get a detailed browser support details from http://jquerymobile.com/gbs/ . In the Head section we have included the Core jQuery javascript file and jQuery Mobile Library and the core CSS Library for the UI Element Styling. These jQuery files are minified versions and will improve the performance of page load on Mobile Devices. The jQuery Mobile pages are identified with an element with the data-role="page" attribute inside the <body> tag. <div data-role="page"> </div> Within the "page" container, any valid HTML markup can be used, but for typical pages in jQuery Mobile, the immediate children of a "page" are div element with data-roles of "header", "content", and "footer". <div data-role="page">     <div data-role="header">...</div>     <div data-role="content">...</div>     <div data-role="footer">...</div> </div> The div data-role="content" holds the main content of the HTML page and will be used for making user interaction elements. The div data-role="header" is header part of the page and div data-role="footer" is the footer part of the page. Creating Mobile specific pages in the Mobile Area Let’s create Layout page for our Mobile area <!DOCTYPE html> <html> <head>     <title>@ViewBag.Title</title>     <link rel="stylesheet" href="http://code.jquery.com/mobile/1.0a3/jquery.mobile-1.0a3.min.css" />     <script src="http://code.jquery.com/jquery-1.5.min.js"></script>     <script src="http://code.jquery.com/mobile/1.0a3/jquery.mobile-1.0a3.min.js"></script>     </head>      <body> @RenderBody()    </body> </html> In the Layout page, I have given reference to jQuery Mobile JavaScript files and the CSS file. Let’s add an Index view page Index.chtml @{     ViewBag.Title = "Index"; } <div data-role="page"> <div data-role="header">      <h1>Expense Tracker Mobile</h1> </div> <div data-role="content">   <ul data-role="listview">     <li>@Html.Partial("_LogOnPartial")</li>      <li>@Html.ActionLink("Home", "Index", "Home")</li>      <li>@Html.ActionLink("Category", "Index", "Category")</li>                          <li>@Html.ActionLink("Expense", "Index", "Expense")</li> </ul> </div> <div data-role="footer">           Shiju Varghese | <a href="http://weblogs.asp.net/shijuvarghese">Blog     </a> | <a href="http://twitter.com/shijucv">Twitter</a>   </div> </div>   In the Index page, we have used data-role “listview” for showing our content as List View Let’s create a data entry screen create.cshtml @model MyFinance.Domain.Category @{     ViewBag.Title = "Create Category"; }   <div data-role="page"> <div data-role="header">      <h1>Create Category</h1>             @Html.ActionLink("Home", "Index","Home",null, new { @class = "ui-btn-right" })      </div>       <div data-role="content">     @using (Html.BeginForm("Create","Category",FormMethod.Post))     {       <div data-role="fieldcontain">        @Html.LabelFor(model => model.Name)        @Html.EditorFor(model => model.Name)        <div>           @Html.ValidationMessageFor(m => m.Name)        </div>         </div>         <div data-role="fieldcontain">         @Html.LabelFor(model => model.Description)         @Html.EditorFor(model => model.Description)                   </div>                    <div class="ui-body ui-body-b">         <button type="submit" data-role="button" data-theme="b">Save</button>       </div>     }        </div> </div>   In jQuery Mobile, the form elements should be placed inside the data-role="fieldcontain" The below screen shots show the pages rendered in mobile browser Index Page Create Page Source Code You can download the source code from http://efmvc.codeplex.com   Summary We have created a single  web app for desktop browsers and mobile browsers. If a user access the site from desktop browsers, users will get normal web pages and get mobile specific pages if users access from mobile browsers. If users are accessing the website from mobile devices, we will redirect to a ASP.NET MVC area Mobile. For redirecting to the Mobile area, we have used a Global filer for the redirection logic and used open source framework 51Degrees.mobi for the better support for mobile browser detection. In the Mobile area, we have created the pages using jQuery Mobile and users will get mobile friendly web pages. We can create great mobile web apps using ASP.NET MVC  and jQuery Mobile Framework.

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