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  • Correct way to make datasources/resources a deploy-time setting

    - by Draemon
    I have a web-app that requires two settings: A JDBC datasource A string token I desperately want to be able to deploy one .war to various different containers (jetty,tomcat,gf3 minimum) and configure these settings at application level within the container. My code does this: InitialContext ctx = new InitialContext(); Context envCtx = (javax.naming.Context) ctx.lookup("java:comp/env"); token = (String)envCtx.lookup("token"); ds = (DataSource)envCtx.lookup("jdbc/datasource") Let's assume I've used the glassfish management interface to create two jdbc resources: jdbc/test-datasource and jdbc/live-datasource which connect to different copies of the same schema, on different servers, different credentials etc. Say I want to deploy this to glassfish with and point it at the test datasource, I might have this in my sun-web.xml: ... <resource-ref> <res-ref-name>jdbc/datasource</res-ref-name> <jndi-name>jdbc/test-datasource</jndi-name> </resource-ref> ... but sun-web.xml goes inside my war, right? surely there must be a way to do this through the management interface Am I even trying to do the right thing? Do other containers make this any easier? I'd be particularly interested in how jetty 7 handles this since I use it for development. EDIT Tomcat has a reasonable way to do this: Create $TOMCAT_HOME/conf/Catalina/localhost/webapp.xml with: <?xml version="1.0" encoding="UTF-8"?> <Context antiResourceLocking="false" privileged="true"> <!-- String resource --> <Environment name="token" value="value of token" type="java.lang.String" override="false" /> <!-- Linking to a global resource --> <ResourceLink name="jdbc/datasource1" global="jdbc/test" type="javax.sql.DataSource" /> <!-- Derby --> <Resource name="jdbc/datasource2" type="javax.sql.DataSource" auth="Container" driverClassName="org.apache.derby.jdbc.EmbeddedDataSource" url="jdbc:derby:test;create=true" /> <!-- H2 --> <Resource name="jdbc/datasource3" type="javax.sql.DataSource" auth="Container" driverClassName="org.h2.jdbcx.JdbcDataSource" url="jdbc:h2:~/test" username="sa" password="" /> </Context> Note that override="false" means the opposite. It means that this setting can't be overriden by web.xml. I like this approach because the file is part of the container configuration not the war, but it's not part of the global configuration; it's webapp specific. I guess I expect a bit more from glassfish since it is supposed to have a full web admin interface, but I would be happy enough with something equivalent to the above.

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  • Importing a large delimited file to a MySQL table

    - by Tom
    I have this large (and oddly formatted txt file) from the USDA's website. It is the NUT_DATA.txt file. But the problem is that it is almost 27mb! I was successful in importing the a few other smaller files, but my method was using file_get_contents which it makes sense why an error would be thrown if I try to snag 27+ mb of RAM. So how can I import this massive file to my MySQL DB without running into a timeout and RAM issue? I've tried just getting one line at a time from the file, but this ran into timeout issue. Using PHP 5.2.0. Here is the old script (the fields in the DB are just numbers because I could not figure out what number represented what nutrient, I found this data very poorly document. Sorry about the ugliness of the code): <? $file = "NUT_DATA.txt"; $data = split("\n", file_get_contents($file)); // split each line $link = mysql_connect("localhost", "username", "password"); mysql_select_db("database", $link); for($i = 0, $e = sizeof($data); $i < $e; $i++) { $sql = "INSERT INTO `USDA` (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17) VALUES("; $row = split("\^", trim($data[$i])); // split each line by carrot for ($j = 0, $k = sizeof($row); $j < $k; $j++) { $val = trim($row[$j], '~'); $val = (empty($val)) ? 0 : $val; $sql .= ((empty($val)) ? 0 : $val) . ','; // this gets rid of those tildas and replaces empty strings with 0s } $sql = rtrim($sql, ',') . ");"; mysql_query($sql) or die(mysql_error()); // query the db } echo "Finished inserting data into database.\n"; mysql_close($link); ?>

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  • Array within Form collecting multiple values with the same name possible?

    - by JM4
    Good afternoon, I will first start with the goal I am trying to accomplish and then give a very basic sample of what I need to do. Goal Instead of collecting several variables and naming them with keys individually, I have decided to give in and use an array structure to handle all inputs of the same type and rules. Once I have the variables, I will validate against them and if 'ok' store them in a MySQL table. The table will hold consumer information and will need to store multiple rows of the same type of information. First Pass I will leave out the validation portion of this question because I feel I need to first understand the basics. <form action="?" method="POST" name="Form"> Member 1 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 1 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 1 Email: <input type="text" name="MemberEmail[]" /><br /> Member 2 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 2 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 2 Email: <input type="text" name="MemberEmail[]" /><br /> Member 3 First Name:<input type="text" name="MemberFirstName[]" /><br /> Member 3 Last Name: <input type="text" name="MemberLastName[]" /><br /> Member 3 Email: <input type="text" name="MemberEmail[]" /><br /> <input type="submit" name="submit" value="Continue" /> </form> I am hoping that each input given for First Name (a required field) will generate a unique key for that particular entry and not overwrite any data entered. Because I am carrying information from page to page (checkout form), I am turning the POST variables into SESSION variables then storing in a mysql database in the end. My hope is to have: <?php $conn = mysql_connect("localhost", "username", "password"); mysql_select_db("DBname",$conn); $sql = "INSERT INTO tablename VALUES ('$_SESSION[Member1FirstName]', '$_SESSION[Member1LastName]', '$_SESSION[Member1Email]', '$_SESSION[Member2FirstName]', '$_SESSION[Member2LastName]', '$_SESSION[Member2Email]', '$_SESSION[Member1FirstName]', '$_SESSION[Member3LastName]', '$_SESSION[Member3Email]')"; $result = mysql_query($sql, $conn) or die(mysql_error()); Header ("Location: completed.php"); ?> Where Member1, Member2, and Member3 values will appear on their own row within the table. I KNOW my code is wrong but I am giving a first shot at the overall business purpose I am trying to achieve and trying to learn how to code the right way. I am very, very new to programming so any 'baby advice' is greatly appreciated.

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  • IE6 CSS tooltip not appearing

    - by Lauren
    I'm using a tooltip that works in FF, Chrome, and IE7-8, but in IE6 it doesn't appear. You can go to this page http://www.avaline.com/ Bags/ Eco-Friendly-Bags/R1500 and login with [email protected] password:test02, then hit the "add to cart" button and hover over the question marks to see (or not see) the tooltips. This is the relevant HTML and CSS: <DIV class=oewBox id=oewImpLocDiv style="BACKGROUND-IMAGE: url(/images/img/org4.gif)"> <A class=tooltip href="#"><SPAN class=""><STRONG>More than 2 imprint locations?</STRONG> Test </SPAN></A> </DIV> <style> /* Rule from element "style" attribute */ element.style { BACKGROUND-IMAGE: url(/images/img/org4.gif) } /* Rule N°8 from inline stylesheet */ .oewBox { PADDING-RIGHT: 8px; PADDING-LEFT: 40px; PADDING-BOTTOM: 16px; MARGIN: 0px 0px 6px; PADDING-TOP: 6px; BORDER-BOTTOM: #ff7c14 3px solid } /* Rule N°7 from inline stylesheet */ .oewBox { BACKGROUND-POSITION: 0px 0px; BACKGROUND-IMAGE: none; BACKGROUND-REPEAT: no-repeat } /* Rule N°11 from /site/av-files/mainstyles.css */ A:active { COLOR: #3b88c4; TEXT-DECORATION: none } /* Rule N°10 from /site/av-files/mainstyles.css */ A:hover { COLOR: #000; TEXT-DECORATION: none } /* Rule N°9 from /site/av-files/mainstyles.css */ A:visited { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°8 from /site/av-files/mainstyles.css */ A:link { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°7 from /site/av-files/mainstyles.css */ A { COLOR: #3b88c4; TEXT-DECORATION: underline } /* Rule N°52 from inline stylesheet */ A.tooltip { BACKGROUND: url(/images/img/question.gif) no-repeat; FLOAT: right; WIDTH: 19px; HEIGHT: 20px } /* Rule N°54 from inline stylesheet */ A.tooltip:hover SPAN { BORDER-RIGHT: #ff7c14 1px solid; BORDER-TOP: #ff7c14 1px solid; DISPLAY: inline; BACKGROUND: #ffffff; BORDER-LEFT: #ff7c14 1px solid; COLOR: #000; BORDER-BOTTOM: #ff7c14 1px solid; POSITION: absolute } /* Rule N°53 from inline stylesheet */ A.tooltip SPAN { PADDING-RIGHT: 3px; DISPLAY: none; PADDING-LEFT: 3px; FONT-WEIGHT: normal; FONT-SIZE: 11px; PADDING-BOTTOM: 2px; MARGIN-LEFT: -245px; WIDTH: 230px; PADDING-TOP: 2px } </style>

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  • php pdo connection scope

    - by Scarface
    Hey guys I have a connection class I found for pdo. I am calling the connection method on the page that the file is included on. The problem is that within functions the $conn variable is not defined even though I stated the method was public (bare with me I am very new to OOP), and I was wondering if anyone had an elegant solution other then using global in every function. Any suggestions are greatly appreciated. CONNECTION class PDOConnectionFactory{ // receives the connection public $con = null; // swich database? public $dbType = "mysql"; // connection parameters // when it will not be necessary leaves blank only with the double quotations marks "" public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; // arrow the persistence of the connection public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ // it carries through the connection $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } } PAGE USED ON include("includes/connection.php"); $db = new PDOConnectionFactory(); $conn = $db->getConnection(); function test(){ try{ $sql = 'SELECT * FROM topic'; $stmt = $conn->prepare($sql); $result=$stmt->execute(); } catch(PDOException $e){ echo $e->getMessage(); } } test();

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  • Parsing XML data with Namespaces in PHP

    - by osbmedia
    I'm trying to work with this XML feed that uses namespaces and i'm not able to get past the colon in the tags. Here's how the XML feed looks like: <r25:events pubdate="2010-05-19T13:58:08-04:00"> <r25:event xl:href="event.xml?event_id=328" id="BRJDMzI4" crc="00000022" status="est"> <r25:event_id>328</r25:event_id> <r25:event_name>Testing 09/2005-08/2006</r25:event_name> <r25:alien_uid/> <r25:event_priority>0</r25:event_priority> <r25:event_type_id xl:href="evtype.xml?type_id=105">105</r25:event_type_id> <r25:event_type_name>CABINET</r25:event_type_name> <r25:node_type>C</r25:node_type> <r25:node_type_name>cabinet</r25:node_type_name> <r25:state>1</r25:state> <r25:state_name>Tentative</r25:state_name> <r25:event_locator>2005-AAAAMQ</r25:event_locator> <r25:event_title/> <r25:favorite>F</r25:favorite> <r25:organization_id/> <r25:organization_name/> <r25:parent_id/> <r25:cabinet_id xl:href="event.xml?event_id=328">328</r25:cabinet_id> <r25:cabinet_name>cabinet 09/2005-08/2006</r25:cabinet_name> <r25:start_date>2005-09-01</r25:start_date> <r25:end_date>2006-08-31</r25:end_date> <r25:registration_url/> <r25:last_mod_dt>2008-02-27T14:22:43-05:00</r25:last_mod_dt> <r25:last_mod_user>abc00296004</r25:last_mod_user> </r25:event> </r25:events> And here is what I'm using for code - I'll trying to throw these into a bunch of arrays where I can format the output however I want: <?php $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://somedomain.com/blah.xml"); curl_setopt ($ch, CURLOPT_HTTPHEADER, Array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $output = curl_exec($ch); curl_close($ch); $xml = new SimpleXmlElement($output); foreach ($xml->events->event as $entry){ $dc = $entry->children('http://www.collegenet.com/r25'); echo $entry->event_name . "<br />"; echo $entry->event_id . "<br /><br />"; }

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  • Can't insert a record in a oracle database using C#

    - by Gya
    try { int val4 = Convert.ToInt32(tbGrupa.Text); string MyConString = "Data Source=**;User ID=******;Password=*****"; OracleConnection conexiune = new OracleConnection(MyConString); OracleCommand comanda = new OracleCommand(); comanda.Connection = conexiune; conexiune.Open(); comanda.Transaction = conexiune.BeginTransaction(); int id_stud = Convert.ToInt16(tbCodStud.Text); string nume = tbNume.Text; string prenume = tbPrenume.Text; string initiala_tatalui = tbInitiala.Text; string email = tbEmail.Text; string facultate = tbFac.Text; int grupa = Convert.ToInt16(tbGrupa.Text); string serie = tbSeria.Text; string forma_de_inv = tbFormaInvatamant.Text; DateTime data_acceptare_coordonare = dateTimePicker1.Value; DateTime data_sustinere_licenta = dateTimePicker2.Value; string sustinere = tbSustinereLicenta.Text; string parola_acces = tbParola.Text; try { comanda.Parameters.AddWithValue("id_stud", id_stud); comanda.Parameters.AddWithValue("nume", nume); comanda.Parameters.AddWithValue("prenume", prenume); comanda.Parameters.AddWithValue("initiala_tatalui", initiala_tatalui); comanda.Parameters.AddWithValue("facultate", facultate); comanda.Parameters.AddWithValue("email", email); comanda.Parameters.AddWithValue("seria", serie); comanda.Parameters.AddWithValue("grupa", grupa); comanda.Parameters.AddWithValue("forma_de_inv", forma_de_inv); comanda.Parameters.AddWithValue("data_acceptare_coordonare", data_acceptare_coordonare); comanda.Parameters.AddWithValue("data_sustinere_licenta", data_sustinere_licenta); comanda.Parameters.AddWithValue("sustinere_licenta", sustinere); comanda.Parameters.AddWithValue("parola_acces", parola_acces); comanda.Transaction.Commit(); MessageBox.Show("Studentul " + tbNume.Text + " " + tbPrenume.Text + " a fost adaugat în baza de date!"); } catch (Exception er) { comanda.Transaction.Rollback(); MessageBox.Show("ER1.1:" + er.Message); MessageBox.Show("ER1.2:" + er.StackTrace); } finally { conexiune.Close(); } } catch (Exception ex) { MessageBox.Show("ER2.1:"+ex.Message); MessageBox.Show("ER2.2:"+ex.StackTrace); }

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  • Arrays become null after passing to function in PHP

    - by William
    So when I pass my filled arrays to the function createform the form is created with $max_avatars options, but they have no name or value. Why are my arrays becoming null? <?php $avatar_image_name = array('hacker','samurai','cool','happy','thatsnice','angry','tv','bang'); $avatar_name = array('Hacker','Samurai','Cool','Happy','That\'s nice','Angry','TV','Bang'); $max_avatars = 6; createform($max_avatars, $avatar_image_name, $avatar_name); ?> The function createform: function createform($max_avatars, $avatar_image_name, $avatar_name) { $string ='<table id="formtable"> <tr><td class="formtext">Name:</td><td><input type="text" name=name size=25 /></td></tr> <tr><td class="formtext">Trip:</td><td><input type="text" name=trip size=25 /> (<font style="color: #ff0000">Don\'t use your password</font>)</td></tr> <tr><td class="formtext">Comment</td><td><textarea name=post rows="4" cols="50"></textarea></td></tr> <tr><td class="formtext">Avatar:</td> <td> <select name=avatar>'; for($i = 0; $i < $max_avatars; $i++){ $string = ($string . '<option value="'.$avatar_image_name[i].'">'.$avatar_name[i].'</option>'); } $string = ($string . '</select> </td> <tr><td class="formtext">Extra</td><td>Fortune: <input type="radio" name="extra" value="fortune" /> Poker: <input type="radio" name="extra" value="poker" /></td></tr> </table> <input type=submit value="Submit" id="submitbutton">'); echo $string; }

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  • Configuring a Context specific Tomcat Security Realm

    - by Andy Mc
    I am trying to get a context specific security Realm in Tomcat 6.0, but when I start Tomcat I get the following error: 09-Dec-2010 16:12:40 org.apache.catalina.startup.ContextConfig validateSecurityRoles INFO: WARNING: Security role name myrole used in an <auth-constraint> without being defined in a <security-role> I have created the following context.xml file: <Context debug="0" reloadable="true"> <Resource name="MyUserDatabase" type="org.apache.catalina.UserDatabase" description="User database that can be updated and saved" factory="org.apache.catalina.users.MemoryUserDatabaseFactory" pathname="conf/my-users.xml" /> <Realm className="org.apache.catalina.realm.UserDatabaseRealm" resourceName="MyUserDatabase"/> </Context> Created a file: my-users.xml which I have placed under WEB-INF/conf which contains the following: <tomcat-users> <role rolename="myrole"/> <user username="test" password="changeit" roles="myrole" /> </tomcat-users> Added the following lines to my web.xml file: <web-app ...> ... <security-constraint> <web-resource-collection> <web-resource-name>Entire Application</web-resource-name> <url-pattern>/*</url-pattern> </web-resource-collection> <auth-constraint> <role-name>myrole</role-name> </auth-constraint> </security-constraint> <login-config> <auth-method>BASIC</auth-method> </login-config> ... </web-app> But seem to get the error wherever I put conf/my-users.xml. Do I have to specify an explicit PATH in the pathname or is it relative to somewhere? Ideally I would like to have it packaged up as part of my WAR file. Any ideas?

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  • PHP Strange error "0:". Possible Object syntax problem?

    - by Michael Stone
    I'm trying to transfer a site from one hosting company to another. I was using 000webhost until the client had hosting and a domain. Now that the client has their domain and hosting, using FatCow.com, I can not for the life of me, debug my PHP code. I'm not getting any errors. I have a successful DB connection. If you procedurally display data, it works, but when I try to use my original objects, something is breaking and just returns "0:". I have all errors on. On old server where the site worked: PHP Version 5.2.11 MySQL Version: 5.0.81 On new server where I get the "0:": PHP Version 5.2.12 MySQL Version 5.0.32 I've setup a test page to test just the output of the variables with the DB connection. Below is my code: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); try { $link = mysql_connect('connectionstring', 'username', 'password'); if (!$link) { die('Could not connect: ' . mysql_error()); } else{ $db = mysql_select_db('a8210422_lit'); } if($db){ include_once('admin/classes/clsPOW.php'); include_once('admin/classes/clsProviders.php'); $pow = new POW(); $prov = new Providers(); $new = $pow->getNew(); $newAr = $new->val(); $get = $prov->getAll($newAr['providerId']); $getAr = $get->val(); $img = $getAr['image']; $name = $getAr['provider']; $desc = $getAr['description']; $zip = $getAr['zip']; $web = $getAr['link']; if($zip==0){ $zip = "Unavailable"; } print $img; print $name; print $desc; print $zip; print $web; } else{ print 'fail!'; } } //catch exception catch(Exception $e) { echo 'Message: ' .$e->getMessage(); } ?>

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  • radgridview delete update in asp.net

    - by abhi
    i have written the follwing to display data from the datagrid and den insert new rows but how do i perform update and delete plss help here's my code using System; using System.Data; using System.Configuration; using System.Collections; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using Telerik.Web.UI; using System.Data.SqlClient; public partial class Default6 : System.Web.UI.Page { string strQry, strCon; SqlDataAdapter da; SqlConnection con; DataSet ds; protected void Page_Load(object sender, EventArgs e) { strCon = "Data Source=MINETDEVDATA; Initial Catalog=ML_SuppliersProd; User Id=sa; Password=@MinetApps7;"; con = new SqlConnection(strCon); strQry = "SELECT * FROM table1"; da = new SqlDataAdapter(strQry, con); SqlCommandBuilder cmdbuild = new SqlCommandBuilder(da); ds = new DataSet(); da.Fill(ds, "table1"); RadGrid1.DataSource = ds.Tables["table1"]; RadGrid1.DataBind(); Label3.Visible = false; Label4.Visible = false; Label5.Visible = false; txtFname.Visible = false; txtLname.Visible = false; txtDesignation.Visible = false; } protected void Submit_Click(object sender, EventArgs e) { Label3.Visible = true; Label4.Visible = true; Label5.Visible = true; txtFname.Visible = true; txtLname.Visible = true; txtDesignation.Visible = true; } protected void Button2_Click(object sender, EventArgs e) { DataSet ds = new DataSet("EmployeeSet"); da.Fill(ds, "table1"); DataTable EmployeeTable = ds.Tables["table1"]; DataRow row = EmployeeTable.NewRow(); row["Fname"] = txtFname.Text.ToString(); row["Lname"] = txtLname.Text.ToString(); row["Designation"] = txtDesignation.Text.ToString(); EmployeeTable.Rows.Add(row); da.Update(ds, "table1"); //RadGrid1.DataSource = ds.Tables["table1"]; //RadGrid1.DataBind(); txtFname.Text = ""; txtLname.Text = ""; txtDesignation.Text = ""; } protected void RadGrid1_DeleteCommand(object source, GridCommandEventArgs e) { } } }

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  • Passing Variables Along in a Function

    - by John
    Hello, In the function show_commentbox() below, I would like to pass along the variables $_SESSION['loginid'], $submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl. With the setup below, it's not working. How could I change it to make show_commentbox() pass the variables along? Thanks in advance, John index.php: <?php $submission = $_GET['submission']; require_once "header.php"; include "login.php"; include "comments.php"; include "commentformonoff.php"; ?> In header.php: require_once ("function.inc.php"); In comments.php: $uid = $_SESSION['loginid']; $submissiondate = mysql_real_escape_string($_GET['submissiondate']); $submittor = mysql_real_escape_string($_GET['submittor']); $countcomments = mysql_real_escape_string($_GET['countcomments']); $dispurl = mysql_real_escape_string($_GET['dispurl']); $url = mysql_real_escape_string($_GET['url']); $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox(); } else { echo "Login to comment"; } } else { echo "Login to comment"; } } else { show_commentbox(); } ?> In display.functions.inc.php: function show_commentbox() { echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; }

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  • Why does my Spring Controller direct me to the wrong page?

    - by kc2001
    I am writing my first Spring 3.0.5 MVC app and am confused about why my controller mappings aren't doing what I expect. I have a VerifyPasswordController that is called after a user tries to log in by entering his name and password. // Called upon clicking "submit" from /login @RequestMapping(value = "/verifyPassword", method = RequestMethod.POST) @ModelAttribute("user") public String verifyPassword(User user, BindingResult result) { String email = user.getEmail(); String nextPage = CHOOSE_OPERATION_PAGE; // success case if (result.hasErrors()) { nextPage = LOGIN_PAGE; } else if (!passwordMatches(email, user.getPassword())) { nextPage = LOGIN_FAILURE_PAGE; } else { // success } return nextPage; } I can verify in the debugger that this method is being called, but afterwards, the verifyPassword page is displayed rather than the chooseOperation page. The console output of WebLogic seems to show that my mapping are correct: INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation.*] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation/] onto handler 'chooseOperationController' Here is the ChooseOperationController: @Controller @SessionAttributes("leaveRequestForm") public class ChooseOperationController implements PageIfc, AttributeIfc { @RequestMapping(value = "/chooseOperation") @ModelAttribute("leaveRequestForm") public LeaveRequest setUpLeaveRequestForm( @RequestParam(NAME_ATTRIBUTE) String name) { LeaveRequest form = populateFormFromDatabase(name); return form; } // helper methods omited } I welcome any advice, particularly "generic" techniques for debugging such mapping problems. BTW, I've also tried to "redirect" to the desired page, but got the same result. servlet-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> <context:component-scan base-package="com.engilitycorp.leavetracker" /> <beans:bean id="leaveRequestForm" class="com.engilitycorp.leavetracker.model.LeaveRequest" /> </beans:beans> The constants: String LOGIN_FAILURE_PAGE = "loginFailure"; String LOGIN_PAGE = "login"; String CHOOSE_OPERATION_PAGE = "chooseOperation";

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  • Problem passing variables in php form.

    - by Joshxtothe4
    I have the following php form. I am trying to make it so that when the form is loaded, the values will be assigned the appropriate check- variable. This variable will contain either "checked or "". If it contains checked, the way it is displayed with the html should cause the relevant checkbox to be checked. As it is, the variables do not seem to be being passed. When I echo out $deleted or $notice from within the submitinfo branch, they are blank. Furthermore, nothing is being inserted into the database, and I am not getting any database error. How can I check this? <?php if (isset($_GET["cmd"])) $cmd = $_GET["cmd"]; else if (isset($_POST["cmd"])) $cmd = $_POST["cmd"]; else die("Invalid URL"); if (isset($_GET["pk"])) { $pk = $_GET["pk"]; } if (isset($_POST["deleted"])) { $deleted = $_POST["deleted"]; } if (isset($_POST["notice"])) { $notice = $_POST["notice"]; } $con = mysqli_connect("localhost","user","password", "db"); if (!$con) { echo "Can't connect to MySQL Server. Errorcode: %s\n". mysqli_connect_error(); exit; } $con->set_charset("utf8"); $getformdata = $con->query("select * from STATUS where ARTICLE_NO = '$pk'"); $checkDeleted = ""; $checkNotice = ""; while ($row = mysqli_fetch_assoc($getformdata)) { $checkDeleted = $row['deleted']; $checkNotice = $row['notice']; } if($cmd=="submitinfo") { $statusQuery = "INSERT INTO STATUS VALUES (?, ?)"; if ($statusInfo = $con->prepare($statusQuery)) { $statusInfo->bind_param("ss", $deleted, $notice); $statusInfo->execute(); $statusInfo->close(); echo "true"; } else { echo "false"; } print_r($con->error); } if($cmd=="EditStatusData") { echo "<form name=\"statusForm\" action=\"test.php\" method=\"post\" enctype=\"multipart/form-data\"> <h1>Editing information for auction: ".$pk."</h1> Löschung Ebay: <input type=\"checkbox\" name=\"deleted\" value=\"checked\" ".$checkDeleted." /> <br /> Abmahnung: <input type=\"checkbox\" name=\"notice\" value=\"checked\" ".$checkNotice." /> <br /> <input type=\"hidden\" name=\"cmd\" value=\"submitinfo\" /> <input name=\"Submit\" type=\"submit\" value=\"submit\" /> </form>"; } else { print_r($con->error); }

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  • Hibernate MappingException Unknown entity: $Proxy2

    - by slynn1324
    I'm using Hibernate annotations and have a VERY basic data object: import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class State implements Serializable { /** * */ private static final long serialVersionUID = 1L; @Id private String stateCode; private String stateFullName; public String getStateCode() { return stateCode; } public void setStateCode(String stateCode) { this.stateCode = stateCode; } public String getStateFullName() { return stateFullName; } public void setStateFullName(String stateFullName) { this.stateFullName = stateFullName; } } and am trying to run the following test case: public void testCreateState(){ Session s = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction t = s.beginTransaction(); State state = new State(); state.setStateCode("NE"); state.setStateFullName("Nebraska"); s.save(s); t.commit(); } and get an org.hibernate.MappingException: Unknown entity: $Proxy2 at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:628) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1366) at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:121) .... I haven't been able to find anything referencing the $Proxy part of the error - and am at a loss.. Any pointers to what I'm missing would be greatly appreciated. hibernate.cfg.xml <property name="hibernate.connection.driver_class">org.hsqldb.jdbcDriver</property> <property name="connection.url">jdbc:hsqldb:hsql://localhost/xdb</property> <property name="connection.username">sa</property> <property name="connection.password"></property> <property name="current_session_context_class">thread</property> <property name="dialect">org.hibernate.dialect.HSQLDialect</property> <property name="show_sql">true</property> <property name="hbm2ddl.auto">update</property> <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property> <mapping class="com.test.domain.State"/> in HibernateUtil.java public static SessionFactory getSessionFactory(boolean testing ) { if ( sessionFactory == null ){ try { String configPath = HIBERNATE_CFG; AnnotationConfiguration config = new AnnotationConfiguration(); config.configure(configPath); sessionFactory = config.buildSessionFactory(); } catch (Exception e){ e.printStackTrace(); throw new ExceptionInInitializerError(e); } } return sessionFactory; }

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  • Account confirmation email sent as SPAM :( PHP

    - by praveen
    Hi, I'm using PHPMailer to send a confirmation email for newly registered users in my social network. But i found out most of them have ended up in user's spam list. (hotmail and yahoo). How to avoid this? This is my script $mail=new PHPMailer(); $mail->IsSMTP(); $mail->SMTPAuth = mSMTPAuth(); $mail->SMTPSecure = mSMTPSecure(); $mail->Host = mHost(); $mail->Port = mPort(); $mail->Username = mUsername(); $mail->Password = mPassword(); $mail->From = mFrom(); $mail->FromName = "SiteName"; $mail->Subject = "SiteName New Account Activation"; $mail->IsHTML(true); $mail->WordWrap = 50; $mail->Body = "<h2>Welcome to " .$sitename. " " .$username. "! </h2><br><br>"; $mail->Body .= "Please click on the link below to verify your email address:<br><br>"; $mail->Body .= "<a href='".$base. "verify.php?a=" .$gen_key."'>".$base. "verify.php?a=" .$gen_key."</a>"; $mail->Body .= "<br><br>Regards<br>"; $mail->AltBody = "Welcome to " .$sitename. " " .$username. "!\n\nTo verify your email address, please click on the link below:\n\n".$base. "verify.php?a=" .$gen_key; $mail->AddAddress($email); $mail->Send(); $mail->ClearAddresses(); Please help. This is really confusing. Thanks in advance

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  • How do I write sql data into a textbox after a submit type event

    - by Matt
    Finishing up some homework and Im having trouble with figuring out how to take information generated in sql column(a primary key set up to assign a record number to a customer example 1046) at submit and writing it to my redirected recipt page. I call it recipt.aspx. Any takers Professor says to use a datareader...but things go bad after that. public partial class _Default : System.Web.UI.Page { String cnStr = "EDITED FOR THE PURPOSE OF NOT DISPLAYED SQL SERVERta Source=111.11.111.11; uid=xxxxxxx; password=xxxx; database=xxxxxx; "; String insertStr; SqlDataReader reader; SqlConnection myConnection = new SqlConnection(); protected void submitbutton_Click(object sender, EventArgs e) { myConnection.ConnectionString = cnStr; try { //more magic happens as myConnection opens myConnection.Open(); insertStr = "insert into connectAssignment values ('" + TextBox2.Text + "','" + TextBox3.Text + "','" + TextBox4.Text + "','" + TextBox5.Text + "','" + bigtextthing.Text + "','" + DropDownList1.SelectedItem.Value + "')"; //magic happens as Connection string is assigned to connection object and passes in the SQL statment //associate the command to the the myConnection connection object SqlCommand cmd = new SqlCommand(insertStr, myConnection); cmd.ExecuteNonQuery(); Session["passmyvalue1"] = TextBox2.Text; Session["passmyvalue2"] = TextBox3.Text; Session["passmyvalue3"] = TextBox4.Text; Session["passmyvalue4"] = TextBox5.Text; Session["passmyvalue5"] = bigtextthing.Text; Session["I NEED SOME HELP RIGHT HERE"] =Textbox6.Text; Response.Redirect("receipt.aspx"); } catch { bigtextthing.Text = "Error submitting" + "Possible casues: Internet is down,server is down, check your settings!"; } finally { myConnection.Close(); TextBox2.Text = ""; TextBox3.Text = ""; TextBox4.Text = ""; TextBox5.Text = ""; bigtextthing.Text = ""; } //reset validators? } The recipt page public partial class _Default : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if(Session["passmyvalue1"] != null) { TextBox1.Text = (string)Session["passmyvalue1"]; TextBox2.Text = (string)Session["passmyvalue2"]; TextBox3.Text = (string)Session["passmyvalue3"]; TextBox4.Text = (string)Session["passmyvalue4"]; TextBox5.Text = (string)Session["passmyvalue5"]; TextBox6.Text = I don't know ; } } } THanks for the help

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  • problem to create session of facebook

    - by khoyendra
    try { HttpClient http = new HttpClient(); http.setParams(new HttpClientParams()); //http.getHostConfiguration().setHost("http://www.facebook.com/"); http.setState(new HttpState()); String api_key = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"; String secret = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"; // String appId=124812364218050; //http://www.facebook.com/developers/editapp.php?app_id=124812364218050 FacebookRestClient client = new FacebookRestClient(api_key, secret); client.setIsDesktop(true); // String sessionKey = request.getParameter(FacebookParam.SESSION_KEY.toString()); // boolean b = client.users_setStatus("This is a test..."); // System.out.println("User Status RESULT : " + b); String token = client.auth_createToken(); final String loginId = "http://www.facebook.com/login.php"; GetMethod get = new GetMethod(loginId + "?api_key=" + api_key + "&v=1.0&auth_token=" +token); System.out.println("Get="+get); http.executeMethod(get); PostMethod post = new PostMethod(loginId); post.addParameter(new NameValuePair("api_key", api_key)); post.addParameter(new NameValuePair("v", "1.0")); post.addParameter(new NameValuePair("auth_token", token)); post.addParameter(new NameValuePair("fbconnect","true")); post.addParameter(new NameValuePair("return_session","true")); post.addParameter(new NameValuePair("session_key_only","true")); post.addParameter(new NameValuePair("req_perms","read_stream,publish_stream")); post.addParameter(new NameValuePair("email", email)); post.addParameter(new NameValuePair("pass", password)); System.out.println("Token ="+token); int postStatus = http.executeMethod(post); System.out.println("Response : " + postStatus); session = client.auth_getSession(token); // Here I am getting error System.out.println("Session string: " + session); long userid = client.users_getLoggedInUser(); System.out.println("User Id is : " + userid); } catch (Exception e) { e.printStackTrace(); } please solve my problem i cannot create session of facebook.

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  • Inserting checkbox values

    - by rabeea
    hey i have registration form that has checkboxes along with other fields. i cant insert the selected checkbox values into the data base. i have made one field in the database for storing all checked values. this is the code for checkbox part in the form: Websites, IT and Software Writing and Content <pre><input type="checkbox" name="expertise[]" value="Design and Media"> Design and Media <input type="checkbox" name="expertise[]" value="Data entry and Admin"> Data entry and Admin </pre> <pre><input type="checkbox" name="expertise[]" value="Engineering and Skills"> Engineering and Science <input type="checkbox" name="expertise[]" value="Seles and Marketing"> Sales and Marketing </pre> <pre><input type="checkbox" name="expertise[]" value="Business and Accounting"> Business and Accounting <input type="checkbox" name="expertise[]" value="Others"> Others </pre> and this is the corresponding php code for inserting data $checkusername=mysql_query("SELECT * FROM freelancer WHERE fusername='{$_POST['username']}'"); if (mysql_num_rows($checkusername)==1) { echo "username already exist"; } else { $query = "insert into freelancer(ffname,flname,fgender,femail,fusername,fpwd,fphone,fadd,facc,facc_name,fbank_details,fcity,fcountry,fexpertise,fprofile,fskills,fhourly_rate,fresume) values ('".$_POST['first_name']."','".$_POST['last_name']."','".$_POST['gender']."','".$_POST['email']."','".$_POST['username']."','".$_POST['password']."','".$_POST['phone']."','".$_POST['address']."','".$_POST['acc_num']."','".$_POST['acc_name']."','".$_POST['bank']."','".$_POST['city']."','".$_POST['country']."','".implode(',',$_POST['expertise'])."','".$_POST['profile']."','".$_POST['skills']."','".$_POST['rate']."','".$_POST['resume']."')"; $result = ($query) or die (mysql_error()); this code inserts data for all fields but the checkbox value field remains empty???

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  • Rails send mail with GMail

    - by Danny McClelland
    Hi Everyone, I am on rails 2.3.5 and have the latest Ruby installed and my application is running well, except, GMail emails. I am trying to setup my gmail imap connection which has worked previously but now doesnt want to know. This is my code: # Be sure to restart your server when you modify this file # Uncomment below to force Rails into production mode when # you don't control web/app server and can't set it the proper way # ENV['RAILS_ENV'] ||= 'production' # Specifies gem version of Rails to use when vendor/rails is not present RAILS_GEM_VERSION = '2.3.5' unless defined? RAILS_GEM_VERSION # Bootstrap the Rails environment, frameworks, and default configuration require File.join(File.dirname(__FILE__), 'boot') Rails::Initializer.run do |config| # Gems config.gem "capistrano-ext", :lib => "capistrano" config.gem "configatron" # Make Time.zone default to the specified zone, and make Active Record store time values # in the database in UTC, and return them converted to the specified local zone. config.time_zone = "London" # The internationalization framework can be changed to have another default locale (standard is :en) or more load paths. # All files from config/locales/*.rb,yml are added automatically. # config.i18n.load_path << Dir[File.join(RAILS_ROOT, 'my', 'locales', '*.{rb,yml}')] #config.i18n.default_locale = :de # Your secret key for verifying cookie session data integrity. # If you change this key, all old sessions will become invalid! # Make sure the secret is at least 30 characters and all random, # no regular words or you'll be exposed to dictionary attacks. config.action_controller.session = { :session_key => '_base_session', :secret => '7389ea9180b15f1495a5e73a69a893311f859ccff1ffd0fa2d7ea25fdf1fa324f280e6ba06e3e5ba612e71298d8fbe7f15fd7da2929c45a9c87fe226d2f77347' } config.active_record.observers = :user_observer end ActiveSupport::CoreExtensions::Date::Conversions::DATE_FORMATS.merge!(:default => '%d/%m/%Y') ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.merge!(:default => '%d/%m/%Y') require "will_paginate" ActionMailer::Base.delivery_method = :smtp ActionMailer::Base.smtp_settings = { :enable_starttls_auto => true, :address => "smtp.gmail.com", :port => 587, :domain => "XXXXXXXX.XXX", :authentication => :plain, :user_name => "XXXXXXXXXX.XXXXXXXXXX.XXX", :password => "XXXXX" } But the above just results in an SMTP auth error in the production log. I have read varied reports of this not working in Rails 2.2.2 but nothing for 2.3.5, anyone got any ideas? Thanks, Danny

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  • can't insert arecord in a oracle database using C#

    - by Gya
    try { int val4 = Convert.ToInt32(tbGrupa.Text); string MyConString = "Data Source=**;User ID=******;Password=*****"; OracleConnection conexiune = new OracleConnection(MyConString); OracleCommand comanda = new OracleCommand(); comanda.Connection = conexiune; conexiune.Open(); comanda.Transaction = conexiune.BeginTransaction(); int id_stud = Convert.ToInt16(tbCodStud.Text); string nume = tbNume.Text; string prenume = tbPrenume.Text; string initiala_tatalui = tbInitiala.Text; string email = tbEmail.Text; string facultate = tbFac.Text; int grupa = Convert.ToInt16(tbGrupa.Text); string serie = tbSeria.Text; string forma_de_inv = tbFormaInvatamant.Text; DateTime data_acceptare_coordonare = dateTimePicker1.Value; DateTime data_sustinere_licenta = dateTimePicker2.Value; string sustinere = tbSustinereLicenta.Text; string parola_acces = tbParola.Text; try { comanda.Parameters.AddWithValue("id_stud", id_stud); comanda.Parameters.AddWithValue("nume", nume); comanda.Parameters.AddWithValue("prenume", prenume); comanda.Parameters.AddWithValue("initiala_tatalui", initiala_tatalui); comanda.Parameters.AddWithValue("facultate", facultate); comanda.Parameters.AddWithValue("email", email); comanda.Parameters.AddWithValue("seria", serie); comanda.Parameters.AddWithValue("grupa", grupa); comanda.Parameters.AddWithValue("forma_de_inv", forma_de_inv); comanda.Parameters.AddWithValue("data_acceptare_coordonare", data_acceptare_coordonare); comanda.Parameters.AddWithValue("data_sustinere_licenta", data_sustinere_licenta); comanda.Parameters.AddWithValue("sustinere_licenta", sustinere); comanda.Parameters.AddWithValue("parola_acces", parola_acces); comanda.Transaction.Commit(); MessageBox.Show("Studentul " + tbNume.Text + " " + tbPrenume.Text + " a fost adaugat în baza de date!"); } catch (Exception er) { comanda.Transaction.Rollback(); MessageBox.Show("ER1.1:" + er.Message); MessageBox.Show("ER1.2:" + er.StackTrace); } finally { conexiune.Close(); } } catch (Exception ex) { MessageBox.Show("ER2.1:"+ex.Message); MessageBox.Show("ER2.2:"+ex.StackTrace); } }

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  • How a database is loaded into an application?

    - by Audel
    Hi All i need is a simple explanation on how does this function work I also attached a piece of php which I think is the one that retrieves the data from the database. Please correct me if I'm wrong Cheers. function loadDatabaseRecords () { // Mozilla/Safari if (window.XMLHttpRequest) { xmlHttpReq = new XMLHttpRequest(); } // IE else if (window.ActiveXObject) { xmlHttpReq = new ActiveXObject("Microsoft.XMLHTTP"); } alert ("To Server (Load Records):\n\najax-open-DB.php"); xmlHttpReq.open('GET', "ajax-open-DB.php", true); xmlHttpReq.onreadystatechange = loadDatabaseRecordsCallback; xmlHttpReq.send(null); } <?php $link = mysql_connect ("ipaddress", "localhost", "password"); mysql_select_db ("database1"); $query = "SELECT * from addressbook"; $result = mysql_query ($query); print "<table>"; print "<tr>"; print "<th>Firstname</th><th>Lastname</th><th>Address</th><th>Telephone</th>"; print "</tr>"; for ($i = 0; $i < mysql_num_rows ($result); $i ++) { $row = mysql_fetch_object ($result); print "<tr>"; print "<td>$row->firstname</td>"; print "<td>$row->lastname</td>"; print "<td>$row->address</td>"; print "<td>$row->telephone</td>"; print "</tr>"; } print "</table>"; mysql_close ($link); ?>

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  • Strategies for "Always-Connected" Windows Client Data Architecture

    - by magz2010
    Hi. Let me start by saying: this is my 1st post here, this is a bit lenghty, and I havent done Windows Forms development in years....with that in mind please excuse me if this isn't directly a programming question and please bear with me as I really need the help!! I have been asked to develop a Windows Forms app for our company that talks to a central (local area network) Linux Server hosting a PostgreSQL database. The app is to allow users to authenticate themselves into the system and thereafter conduct the usual transactions with the PG database. Ordinarily, I would propose writing a webforms app against Mono, but the clients need to utilise local resources such as USB peripheral devices, so that is out of the question. While it might not seem clear, my questions are italised below: Dilemma #1: The application is meant to be always connected. How should I structure my DAL/BLL - Should this reside on the server or with the client? Dilemma #2: I have been reading up on Client Application Services (CAS), and it seems like a great fit for authentication, as everything is exposed via URIs. I know that a .NET Data Provider exists for PostgreSQL, but not too sure if CAS will all work on a Linux (Debian) server? Believe me, I would get my hands dirty and try myself, but I need to come up with a logical design first before resources are allocated to me for "trial purposes"! Dilemma #3: If the DAL/BLL is to reside on the server, is there any way I can create data services, and expose only these services to authenticated clients. There is a (security) requirement whereby a connection string with username and password to the database cannot be present on any client machines...even if security on the database side is quite rigid. I'm guessing that the only way for this to work would be to create the various CRUD data service methods that are exposed by an ASP.NET app, and have the WindowsForms make a request for data or persist data to the ASP.NET app (thru a URI) and have that return a resultset or value. Would I be correct in assuming this? Should I be looking into WCF Data Services? and will WCF work with a non-SQL Server database? Thank you for taking the time out to read this, but know that I am desperately seeking any advice on this! THANKS A MILLION!!!!

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  • Running OpenMPI on Windows XP

    - by iamweird
    Hi there. I'm trying to build a simple cluster based on Windows XP. I compiled OpenMPI-1.4.2 successfully, and tools like mpicc and ompi_info work too, but I can't get my mpirun working properly. The only output I can see is Z:\orterun --hostfile z:\hosts.txt -np 2 hostname [host0:04728] Failed to initialize COM library. Error code = -2147417850 [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\mca\ess\hnp\ess_hnp_module.c at line 218 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_plm_init failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\runtime\orte_init.c at line 132 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_ess_set_name failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\..\..\openmpi -1.4.2\orte\tools\orterun\orterun.c at line 543 Where z:\hosts.txt appears as follows: host0 host1 Z: is a shared network drive available to both host0 and host1. What my problem is and how do I fix it? Upd: Ok, this problem seems to be fixed. It seems to me that WideCap driver and/or software components causes this error to appear. A "clean" machine runs local task successfully. Anyway, I still cannot run a task within at least 2 machines, I'm getting following message: Z:\mpirun --hostfile z:\hosts.txt -np 2 hostname connecting to host1 username:cluster password:******** Save Credential?(Y/N) y [host0:04728] This feature hasn't been implemented yet. [host0:04728] Could not connect to namespace cimv2 on node host1. Error code =-2147024891 -------------------------------------------------------------------------- mpirun was unable to start the specified application as it encountered an error. More information may be available above. -------------------------------------------------------------------------- I googled a little and did all the things as described here: http://www.open-mpi.org/community/lists/users/2010/03/12355.php but I'm still getting the same error. Can anyone help me? Upd2: Error code -2147024891 might be WMI error WBEM_E_INVALID_PARAMETER (0x80041008) which occures when one of the parameters passed to the WMI call is not correct. Does this mean that the problem is in OpenMPI source code itself? Or maybe it's because of wrong/outdated wincred.h and credui.lib I used while building OpenMPI from the source code?

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  • .NET datetime issue with SQL stored procedure

    - by DanO
    I am getting the below error when executing my application on a Windows XP machine with .NET 2.0 installed. On my computer Windows 7 .NET 2.0 - 3.5 I am not having any issues. The target SQL server version is 2005. This error started occurring when I added the datetime to the stored procedure. I have been reading alot about using .NET datetime with SQL datetime and I still have not figured this out. If someone can point me in the right direction I would appreciate it. Here is the where I believe the error is coming from. private static void InsertRecon(string computerName, int EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) { SqlConnection DBC = new SqlConnection("server=server;UID=InventoryServer;Password=pass;database=Inventory;connection timeout=30"); SqlCommand CMD = new SqlCommand(); try { CMD.Connection = DBC; CMD.CommandType = CommandType.StoredProcedure; CMD.CommandText = "InsertReconData"; CMD.Parameters.Add("@CNAME", SqlDbType.NVarChar); CMD.Parameters.Add("@ENCRYPTEXIST", SqlDbType.Int); CMD.Parameters.Add("@RUNTIME", SqlDbType.Time); CMD.Parameters.Add("@ENCRYPTSIZE", SqlDbType.BigInt); CMD.Parameters.Add("@TIMEWRITTEN", SqlDbType.DateTime); CMD.Parameters["@CNAME"].Value = computerName; CMD.Parameters["@ENCRYPTEXIST"].Value = EncryptState; CMD.Parameters["@RUNTIME"].Value = FindTime; CMD.Parameters["@ENCRYPTSIZE"].Value = EncryptSize; CMD.Parameters["@TIMEWRITTEN"].Value = timeWritten; DBC.Open(); CMD.ExecuteNonQuery(); } catch (System.Data.SqlClient.SqlException e) { PostMessage(e.Message); } finally { DBC.Close(); CMD.Dispose(); DBC.Dispose(); } } Unhandled Exception: System.ArgumentOutOfRangeException: The SqlDbType enumeration value, 32, is invalid. Parameter name: SqlDbType at System.Data.SqlClient.MetaType.GetMetaTypeFromSqlDbType(SqlDbType target) at System.Data.SqlClient.SqlParameter.set_SqlDbType(SqlDbType value) at System.Data.SqlClient.SqlParameter..ctor(String parameterName, SqlDbType dbType) at System.Data.SqlClient.SqlParameterCollection.Add(String parameterName, SqlDbType sqlDbType) at ReconHelper.getFilesInfo.InsertRecon(String computerName, Int32 EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) at ReconHelper.getFilesInfo.Main(String[] args)

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