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  • zend_application showing blank page

    - by daniel
    Hi, I'm using Zend_Application to bootstrap my app. class Bootstrap extends Zend_Application_Bootstrap_Bootstrap { public static $frontController = null; public static $registry = null; protected function _initEnvironment() { ini_set('display_errors', true); //date_default_timezone_set('Europe/London'); } protected function _initRegistry() { self::$registry = new Zend_Registry(array(), ArrayObject::ARRAY_AS_PROPS); Zend_Registry::setInstance(self::$registry); } protected function _initConfiguration() { $config = new Zend_Config_Ini( BASE_PATH . '/data/server/settings.ini', APPLICATION_ENV ); self::$registry->configuration = $config; } protected function _initLogging() { $config = self::$registry->configuration; $logger = new Zend_Log(new Zend_Log_Writer_Stream($config->logging->file)); Zend_Registry::set('logger', $logger); } protected function _initFrontController() { self::$frontController = Zend_Controller_Front::getInstance(); self::$frontController->throwExceptions(true); self::$frontController->returnResponse(true); self::$frontController->setControllerDirectory( APPLICATION_PATH .'/controllers' ); self::$frontController->setParam('registry', self::$registry); return self::$frontController; } protected function _initView() { $config = self::$registry->configuration; $view = new Zend_View; $viewRenderer = new Zend_Controller_Action_Helper_ViewRenderer($view); Zend_Controller_Action_HelperBroker::addHelper($viewRenderer); Zend_Layout::startMvc( array( 'layoutPath' => APPLICATION_PATH . "/layouts/scripts", 'layout' => "layout" ) ); return $view; } protected function _initDatabase() { $config = self::$registry->configuration; $params = array('host' => $config->database->hostname, 'username' => $config->database->username, 'password' => $config->database->password, 'dbname' => $config->database->database); $db = Zend_Db::factory($config->database->type, $params); Zend_Registry::set('db', $db); } protected function _initPlaceholders() { $view = $this->getResource('View'); $view->doctype('XHTML1_STRICT'); $view->headTitle('Greplin') ->setSeparator(' / '); $view->headLink()->prependStylesheet('/src/css/header.css'); $view->headScript()->prependFile('/js/site.js'); return $view; } } When I run the app I get a blank page. Filenames / paths are intact. If I add die() to the bottom of my layout.phtml, I get the page. Something is resetting the headers and sending a blank page. My error reporting is on and I get unrelated errors. What could this be?! Thanks!

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  • How to detect column conflicts with Hibernate?

    - by Slim
    So let's say I have an ArrayList full of Products that need to be committed to the database via Hibernate. There are already a large number of Products in the database. Each product has an ID. Note this is NOT the PK that is autogenerated by Hibernate. My questions is: what is the best way to detect conflicts with this ID? I am looking for a relatively efficient method of obtaining, from the the database, a List of Products that share an ID with any of the Products in my ArrayList. This is all in a single table called Products and the ID attribute is in column ProductID. The way I've done it is grabbing a list of all Products in the database, and compared each one with each entry in my ArrayList - but that is seriously inefficient and I don't think it would work well with a larger database. How should it be done? Thanks. I say "relatively" efficient because efficiency is not the primary concern, but it shouldn't take noticeably long to test against a table of ~1000-5000 rows. Help? EDIT* I'm very new to hibernate and below is the best I've come up with. How does this look? for(long id : idList){ //idList just holds the IDs of each Product in my ArrayList Query query = session.createQuery("select product from Product product where product.id = :id"); query.setLong("id", id); for(int i = 0; i < query.list().size(); i++){ listOfConflictingProducts.add((Product) query.list().get(i)); } }

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  • creating multiple users for a c#.net winform application using sql server express

    - by sqlchild
    i have a single sql database in sql server express. i have a login MAINLOGIN, for this database. i want insertion of data in this database through multiple users, U1,U2,U3, each having different userids & passwords. These users would be created by MAINLOGIN , manually or via the winform application. So while creating MAINLOGIN , i would give him permission to further create logins. For this what should i do? i cannot create MULTIPLE users, because for one database, only one user can be created under one login. so should i create multiple logins, L1,L2,L3, then map, U1, U2, U3 to them. Or, is there a better way to do this? like application roles etc. i dont want to use windows authentication. because if i know the system password, then i could simply connect sql via the application and insert wrong data.

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  • Visual Studio 2010 and Silverlight - Adding Data Sources

    - by Villager
    Hello, I am interested in building a Silverlight application that uses RIA Services. I am using this video (http://live.visitmix.com/MIX10/Sessions/CL08) as an example. In that video, the presenter uses the "data sources" tab to populate the view. However, I cannot figure out how to add a data source from within Visual Studio 2010. I have a database on my local machine. This database is the sample AdventureWorks database. When I select my Silverlight application, there is a UserRegistrationContext in the data sources window. However, I cannot figure out how to add a new one that connects to my AdventureWorks database. Can somebody tell me how to do this? Thank you!

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  • Storing rich text documents

    - by David Veeneman
    This is a follow-up to another question I asked earlier today. I am creating a desktop app that stores rich text documents created in WPF (in a RichTextBox control). The app uses SQL Compact, and up until now, I had planned to store each document in a binary column in the database. I am rethinking that approach. Would it be better practice to store each rich text document in the file system, rather than saving it to the database? I figure I could put the documents in the same folder with the database, then store a relative path to each document in its database record, along with other information about the document (tags and so on). I'd like to know some pros and cons of that approach, along with ideas of what is generally considered best practice for this sort of thing. Thanks for your help.

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  • How can I get DocId when adding a document in Lucene index?

    - by Rohit
    I am indexing a row of data from database in Lucene.Net. A row is equivalent of Document. I want to update my database with the DocId, so that I can use the DocId in the results to be able to retrieve rows quickly. I currently first retrive the PK from the result docs which I think should be slower than retriving directly from the database using DocId. How can I find the DocId when adding a document to Lucene?

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  • php and mysql site design question

    - by Jacksta
    I am trying to build a website with mysql and php. This is the first site I have attempted so I want to write a little plan and get some feedback. The site allows users to add some text in a text field as a “comment”. Once the comment has been entered into the site it is added to the database where it can be voted for by other users. When a new comment has been added to the database it needs to create a new page, e.g. www.xxxxx.com/commentname or www.xxxxxx.com/?id=99981. There will be a list of "Comments" in the database along with the number of votes for each comment. The home page will have two functions. 1) Allow users to add a "comment" 2) Display two tables, each with 20 rows containing most "popular comments" and "recent comments" Each comment will generate its one page where the comment will be displayed. Here users can read the comment and Vote for the comment if they wish. Please help me out by explaining how to do the following. -Generate a new page whenever a comment is added to the database -Add a vote to the vote count in the comment database. -Display the top 20 most popular comments as per number of votes.

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  • Question about the benefit of using an ORM

    - by johnny
    I want to use an ORM for learning purposes and am try nhibernate. I am using the tutorial and then I have a real project. I can go the "old way" or use an ORM. I'm not sure I totally understand the benefit. On the one hand I can create my abstractions in code such that I can change my databases and be database independent. On the other it seems that if I actually change the database columns I have to change all my code. Why wouldn't I have my application without the ORM, change my database and change my code, instead of changing my database, orm, and code? Is it that they database structure doesn't change that much? I believe there are real benefits because ORMs are used by so many. I'm just not sure I get it yet. Thank you. EDIT: In the tutorial they have many files that are used to make the ORM work http://www.hibernate.org/362.html In the event of an application change, it seems like a lot of extra work just to say that I have "proper" abstraction layers. Because I'm new at it it doesn't look that easy to maintain and again seems like extra work, not less.

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  • Single website multiple connection strings using asp mvc 2 and nhibernate

    - by jjjjj
    Hi In my website i use ASP MVC 2 + Fluent NHibernate as orm, StructureMap for IoC container. There are several databases with identical metadata(and so entities and mappings are the same). On LogOn page user fiils in login, password, rememberme and chooses his server from dropdownlist (in fact he chooses database). Web.config contains all connstrings and we can assume that they won't be changed in run-time. I suppose that it is required to have one session factory per database. Before using multiple databases, i loaded classes to my StructureMap ObjectFactory in Application_Start ObjectFactory.Initialize(init => init.AddRegistry<ObjectRegistry>()); ObjectFactory.Configure(conf => conf.AddRegistry<NhibernateRegistry>()); NhibernateRegistry class: public class NhibernateRegistry : Registry { public NhibernateRegistry() { var sessionFactory = NhibernateConfiguration.Configuration.BuildSessionFactory(); For<Configuration>().Singleton().Use( NhibernateConfiguration.Configuration); For<ISessionFactory>().Singleton().Use(sessionFactory); For<ISession>().HybridHttpOrThreadLocalScoped().Use( ctx => ctx.GetInstance<ISessionFactory>().GetCurrentSession()); } } In Application_BeginRequest i bind opened nhibernate session to asp session(nhibernate session per request) and in EndRequest i unbind them: protected void Application_BeginRequest( object sender, EventArgs e) { CurrentSessionContext.Bind(ObjectFactory.GetInstance<ISessionFactory>().OpenSession()); } Q1: How can i realize what SessionFactory should i use according to authenticated user? is it something like UserData filled with database name (i use simple FormsAuthentication) For logging i use log4net, namely AdoNetAppender which contains connectionString(in xml, of course). Q2: How can i manage multiple connection strings for this database appender, so logs would be written to current database? I have no idea how to do that except changing xml all the time and reseting xml configuration, but its really bad solution.

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  • How to use SQL - INSERT...ON DUPLICATE KEY UPDATE?

    - by Probocop
    Hi, I have a script which captures tweets and puts them into a database. I will be running the script on a cronjob and then displaying the tweets on my site from the database to prevent hitting the limit on the twitter API. So I don't want to have duplicate tweets in my database, I understand I can use 'INSERT...ON DUPLICATE KEY UPDATE' to achieve this, but I don't quite understand how to use it. My database structure is as follows. Table - Hash id (auto_increment) tweet user user_url And currently my SQL to insert is as follows: $tweet = $clean_content[0]; $user_url = $clean_uri[0]; $user = $clean_name[0]; $query='INSERT INTO hash (tweet, user, user_url) VALUES ("'.$tweet.'", "'.$user.'", "'.$user_url.'")'; mysql_query($query); How would I correctly use 'INSERT...ON DUPLICATE KEY UPDATE' to insert only if it doesn't exist, and update if it does? Thanks

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  • One big call vs. multiple smaller TSQL calls

    - by BrokeMyLegBiking
    I have a ADO.NET/TSQL performance question. We have two options in our application: 1) One big database call with multiple result sets, then in code step through each result set and populate my objects. This results in one round trip to the database. 2) Multiple small database calls. There is much more code reuse with Option 2 which is an advantage of that option. But I would like to get some input on what the performance cost is. Are two small round trips twice as slow as one big round trip to the database, or is it just a small, say 10% performance loss? We are using C# 3.5 and Sql Server 2008 with stored procedures and ADO.NET.

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  • 3-Tier architecture-layering and the term-mishmash

    - by Rookian
    Hi! I am confused about the different possibilities to express a 3-Tier architecture. Data-Access-Layer Business-Layer Presentation Layer (User Interface) or Database (aka Backend) Business-Layer Presentation Layer (User Interface) Why can you skip the database in the 1st approach? Both use a database! Does the database belong to the layering or not?! What is wrong and what is right? Can someone of you clarify this :)? Thanks in advance!

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  • Beginner assembly programming memory usage question

    - by Daniel
    I've been getting into some assembly lately and its fun as it challenges everything i have learned. I was wondering if i could ask a few questions When running an executable, does the entire executable get loaded into memory? From a bit of fiddling i've found that constants aren't really constants? Is it just a compiler thing? const int i = 5; _asm { mov i, 0 } // i is now 0 and compiles fine So are all variables assigned with a constant value embedded into the file as well? Meaning: int a = 1; const int b = 2; void something() { const int c = 3; int d = 4; } Will i find all of these variables embedded in the file (in a hex editor or something)? If the executable is loaded into memory then "constants" are technically using memory? I've read around on the net people saying that constants don't use memory, is this true?

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  • Is it okay if my ViewModel 'creates' bindable user controls for my View?

    - by j0rd4n
    I have an entry-point View with a tab control. Each tab is going to have a user control embedded within it. Each embedded view inherits from the same base class and will need to be updated as a key field on the entry-point view is updated. I'm thinking the easiest way to design this page is to have the entry-point ViewModel create and expose a collection of the tabbed views so the entry-point View can just bind to the user control elements using a DataTemplate on the tab control. Is it okay for a ViewModel to instantiate and provide UI elements for its View?

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  • Mapping relationships from multiple databases in NHibernate

    - by mannish
    I have a multi-database application configured with NHibernate. The entities that correspond to tables from each database are in their own separate assemblies (an assembly per database if you will). I have a need/desire to relate an entity from one database to an entity of another database. Everything up to this point works as I want it to (the application handles multiple session factories, etc.). The relationship I want is many-to-one, but in reality my application only cares about one side of the relationship (for reasons that aren't relevant). The relevant entities are Project and PMProject, where a Project HAS A PMProject. When I map the many-to-one, I get the following error: NHibernate.MappingException: An association from the table PROJECTS refers to an unmapped class: SDMS.PPRM.PMProject The Project mapping itself reads (ignore the funky column naming; it's an Oracle db): <many-to-one name="PMProject" class="SDMS.PPRM.PMProject" column="PM_PROJECT_ID" cascade="none" /> In the class attribute, I'm referencing the appropriate assembly, but I get that error which seems to tell me it simply can't find the mapping file for PMProject. But that file exists (it's set as embedded resource), the session factory instantiation works without fail; so I'm at a loss on how to tell the Project mapping how/where to look for the appropriate mapping. Is there something I'm missing? A better way to go about this? Thanks in advance.

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  • How to show all the tables from multiple databases

    - by saorabh
    How to select all the tables from multiple databases in mySql.. I am doing the following steps but not able to achive the goal. <?php $a = "SHOW DATABASES"; $da = $wpdb->get_results($a); foreach($da as $k){ echo '<pre>'; print_r ($k->Database);//prints all the available databases echo '</pre>'; $nq = "USE $k->Database";//trying to select the individual database $newda = $wpdb->get_results($nq); $alld = "SELECT * FROM $k->Database"; $td = $wpdb->get_results($alld); var_dump($td);//returns empty array } ?> Please Help me

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  • DataGridView live display of datatable using virtual mode

    - by Chris
    I have a DataGridView that will display records (log entries) from a database. The amount of records that can exist at a time is very large. I would like to use the virtual mode feature of the DataGridView to display a page of data, and to minimize the amount of data that has to be transferred across a network at a given time. Polling for data is out of the question. There will be several clients running at a time, all of which are on the same network and viewing the records. If they all poll for data, the network will run very slowly. The data is read-only to the user; they won't be able to edit any of it, just view it. I need to know when updates occur in the database, and I need to update the screen with those updates accordingly using virtual mode. If a page of data a user is viewing contains data that has change, he/she will see those updates on that page. If updates were made to data in the database, but not in the data the user is viewing, then not much really changes on the user screen (Maybe just the scroll bar if records were added or removed). My current approach is using SQL server change tracking with the sync framework. Each client has a local SQL Server CE instance and database file that is kept in sync with the main database server. I use the information from the synchronization event to see if any changes were made to the main database and were sync'ed to the client. I need to use the DataGridView virtual mode here because I can't have thousands of records loaded into the DataGridView at once, otherwise memory usage goes through the roof. The main challenge right now is knowing how to use virtual mode to provide a seamless experience to the user by allowing them to scroll up and down through the records, and also have records update on the fly without interfering with the user inappropriately. Has anybody dealt with this issue before, and if so, where I can see how they did it? I've gone through some of the MSDN documentation and examples on virtual mode. So far, I haven't found documentation and/or examples on their site that explains how to do what I am trying to accomplish.

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  • Id property not populated

    - by fingers
    I have an identity mapping like so: Id(x => x.GuidId).Column("GuidId") .GeneratedBy.GuidComb().UnsavedValue(Guid.Empty); When I retrieve an object from the database, the GuidId property of my object is Guid.Empty, not the actual Guid (the property in the class is of type System.Guid). However, all of the other properties in the object are populated just fine. The database field's data type (SQL Server 2005) is uniqueidentifier, and marked as RowGuid. The application that is connecting to the database is a VB.NET Web Site project (not a "Web Application" or "MVC Web Application" - just a regular "Web Site" project). I open the NHibernate session through a custom HttpModule. Here is the HttpModule: public class NHibernateModule : System.Web.IHttpModule { public static ISessionFactory SessionFactory; public static ISession Session; private static FluentConfiguration Configuration; static NHibernateModule() { if (Configuration == null) { string connectionString = cfg.ConfigurationManager.ConnectionStrings["myDatabase"].ConnectionString; Configuration = Fluently.Configure() .Database(MsSqlConfiguration.MsSql2005.ConnectionString(cs => cs.Is(connectionString))) .ExposeConfiguration(c => c.Properties.Add("current_session_context_class", "web")) .Mappings(x => x.FluentMappings.AddFromAssemblyOf<LeadMap>().ExportTo("C:\\Mappings")); } SessionFactory = Configuration.BuildSessionFactory(); } public void Init(HttpApplication context) { context.BeginRequest += delegate { Session = SessionFactory.OpenSession(); CurrentSessionContext.Bind(Session); }; context.EndRequest += delegate { CurrentSessionContext.Unbind(SessionFactory); }; } public void Dispose() { Session.Dispose(); } } The strangest part of all, is that from my unit test project, the GuidId property is returned as I would expect. I even rigged it to go for the exact row in the exact database as the web site was hitting. The only differences I can think of between the two projects are The unit test project is in C# Something with the way the session is managed between the HttpModule and my unit tests The configuration for the unit tests is as follows: Fluently.Configure() .Database(MsSqlConfiguration.MsSql2005.ConnectionString(cs => cs.Is(connectionString))) .Mappings(x => x.FluentMappings.AddFromAssemblyOf<LeadDetailMap>()); I am fresh out of ideas. Any help would be greatly appreciated. Thanks

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  • Outlook AppointmentItem - How do I programmatically add RTF to its Body?

    - by Stuart Harris
    I would like to set the Body of an AppointmentItem to a string of RTF that contains an embedded image. Setting Microsoft.Office.Interop.Outlook.AppointmentItem.Body results in the RTF appearing as-is in the appointment. I have tried using Redemption which wraps the appointment and exposes an RTFBody property, but the RTF formatting (including the image) is lost. In this example (which doesn't have an embedded image) the RTF appears in the document as-is. Has anyone managed to do this? var appointment = (AppointmentItem)app.CreateItem(OlItemType.olAppointmentItem); appointment.Subject = "test subject"; appointment.Start = DateTime.Now; appointment.End = DateTime.Now.AddHours(1); appointment.Body = @"{\rtf1\ansi\deff0{\fonttbl{\f0 Arial;}}{\colortbl ;\red0\green0\blue255;}\pard\cf1\f0\fs24 Test}"; appointment.Save();

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • How to create a non-persistent Elixir/SQLAlchemy object?

    - by siebert
    Hi, because of legacy data which is not available in the database but some external files, I want to create a SQLAlchemy object which contains data read from the external files, but isn't written to the database if I execute session.flush() My code looks like this: try: return session.query(Phone).populate_existing().filter(Phone.mac == ident).one() except: return self.createMockPhoneFromLicenseFile(ident) def createMockPhoneFromLicenseFile(self, ident): # Some code to read necessary data from file deleted.... phone = Phone() phone.mac = foo phone.data = bar phone.state = "Read from legacy file" phone.purchaseOrderPosition = self.getLegacyOrder(ident) # SQLAlchemy magic doesn't seem to work here, probably because we don't insert the created # phone object into the database. So we set the id fields manually. phone.order_id = phone.purchaseOrderPosition.order_id phone.order_position_id = phone.purchaseOrderPosition.order_position_id return phone Everything works fine except that on a session.flush() executed later in the application SQLAlchemy tries to write the created Phone object to the database (which fortunatly doesn't succeed, because phone.state is longer than the data type allows), which breaks the function which issues the flush. Is there any way to prevent SQLAlchemy from trying to write such an object? Ciao, Steffen

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  • Specify .doc file encoding when creating with php?

    - by arma
    Hey, Currently i try to create some of my database export work more automated and i decided to go with exporting data from MySql database to .doc file in php. So im doing some database work and store complete html to a $str variable and then write/make new file: $fp = fopen($file, 'w+'); fwrite($fp,$str); fclose($fp); The problem here is not creating .doc file, but when i download and view that .doc file it's not in UTF-8 it's in unicode.

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