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  • Oracle access from iOS

    - by Michael Lowman
    I'm developing an iPad app that needs read-only access to an Oracle database. Is there any way to do this? As far as I can see, the only options are using OCI, which requires a prebuilt binary in the form of the instant client (and not built for ARM), or OJDBC drivers. Both of these seem to be out of the question. In my research I have discovered that libmysqlclient compiles for arm with minimal tuning. This is a stretch, but is there any possible way to use this to my advantage? I have seen this product providing odbc connectivity through the use of a Windows gateway machine using the ODBC client libraries, but this solution really isn't an option for me at the present time. Any ideas?

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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • Fetch image from folder via datatable does not work after placing image in subdirectory

    - by Arnold Bishkoff
    I am having trouble wrapping my head around the following I have code that fetches an image via smarty in a line img src="getsnap.php?picid={$data[$smarty.section.sec.index].picno|default:$nextpic}&typ=pic&width={$config.disp_snap_width}&height={$config.disp_snap_height}" class="smallpic" alt="" / this works if i pull the image from /temp/userimages/userid/imageNo.ext but because an OS can segfault if you store too many folders or images in a directory i have code that assigns the user image to a subdirectory based upon division of a subdir per 1000 userids. so in thise case i have user id 94 whos images get stored in /siteroot/temp/userimages/000000/94/pic_1.jpg (through 10) or tn_1 (through 10).jpg here is the code for getsnap.php <?php ob_start(); if ( !defined( 'SMARTY_DIR' ) ) { include_once( 'init.php' ); } include('core/snaps_functions.php'); if (isset($_REQUEST['username']) && $_REQUEST['username'] != '') { $userid = $osDB-getOne('select id from ! where username = ?',array(USER_TABLE, $_REQUEST['username']) ); } else { // include ( 'sessioninc.php' ); if( !isset($_GET['id']) || (isset($_GET['id'])&& (int)$_GET['id'] <= 0 ) ) { $userid = $_SESSION['UserId']; } else { $userid = $_GET['id']; } } if (!isset($_GET['picid']) ) { if ((isset($_REQUEST['type']) && $_REQUEST['type'] != 'gallery') || !isset($_REQUEST['type']) ) { $defpic = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and default_pic = ? and active = ? ',array(USER_SNAP_TABLE, $userid,'0','Y','Y' ) ); if ($defpic != '') { $picid = $defpic; } else { $picid = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and active=? order by rand()',array(USER_SNAP_TABLE, $userid,'0','Y' ) ); } unset( $defpic); } } else { $picid = $_GET['picid']; } $typ = isset( $_GET['typ'])?$_GET['typ']:'pic' ; $cond = ''; if ( ($config['snaps_require_approval'] == 'Y' || $config['snaps_require_approval'] == '1') && $userid != $_SESSION['UserId'] ) { $cond = " and active = 'Y' "; } $sql = 'select * from ! where userid = ? and picno = ? '.$cond; //Get the pic $row =& $osDB-getRow ( $sql, array( USER_SNAP_TABLE, $userid, $picid ) ); //Okay pic was found in the DB, Lets actually do something // $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; $img = getPicture($zimg, $userid, $picid, $typ, $row); //$img = getPicture($userid, $picid, $typ, $row); //$img = getPicture($dir, $userid, $picid, $typ, $row); $ext = ($typ = 'tn')?$row['tnext']:$row['picext']; // Now pic is built as // something pic_x.ext ie pic_2.jpg if ( $img != '' && ( ( hasRight('seepictureprofile') && ( $config['snaps_require_approval'] == 'Y' && $row['active'] == 'Y' ) ||$config['snaps_require_approval'] == 'N' ) || $userid == $_SESSION['UserId'] ) ) { $img2 = $img; //$img2 = $dir.'/'.$img; } else { $gender = $osDB-getOne( 'select gender from ! where id = ?', array( USER_TABLE, $userid ) ) ; if ($gender == 'M') { $nopic = SKIN_IMAGES_DIR.'male.jpg'; } elseif ($gender == 'F') { $nopic = SKIN_IMAGES_DIR.'female.jpg'; } elseif ($gender == 'D') { $nopic = SKIN_IMAGES_DIR.'director.jpg'; } $img2 = imagecreatefromjpeg($nopic); $ext = 'jpg'; } ob_end_clean(); header("Pragma: public"); header("Content-Type: image/".$ext); header("Content-Transfer-Encoding: binary"); header("Cache-Control: must-revalidate"); $ExpStr = "Expires: " . gmdate("D, d M Y H:i:s", time() - 30) . " GMT"; header($ExpStr); $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; //header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); //header("Content-Disposition: attachment; filename=$dir.'/'.profile_".$userid."".$typ.".".$ext); //header("Content-Disposition: attachment; filename=profile"$dir".'/'.".$userid."_".$typ.".".$ext); header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); /* if ($_SESSION['browser'] != 'MSIE') { header("Content-Disposition: inline" ); } */ if ($ext == 'jpg') { imagejpeg($img2); } elseif ($ext == 'gif') { imagegif($img2); } elseif ($ext == 'png') { imagepng($img2); } elseif ($ext == 'bmp') { imagewbmp($img2); } imagedestroy($img2); ?

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • Incorrect string encodings

    - by James
    Note: I have read all of the related PHP, UTF-8, character encoding articles that are usually suggested, but my question relates to data inserted before I applied such techniques. I am wishing to retrospectively fix all character encoding problems. Now all connections are set as utf8 using PDO. PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8' Unfortunately, a large amount of data was inserted that is of questionable encoding before I had implemented correct character encoding practices. As displayed by: $sql = "SELECT name FROM data LIMIT 3"; foreach ($pdo->query($sql) as $row) { $name = $row['name']; echo $name . "\n"; echo utf8_encode($name) . "\n"; echo utf8_decode($name) . "\n"; echo htmlspecialchars($name, ENT_QUOTES, 'UTF-8') . "\n"; echo htmlspecialchars(utf8_encode($name), ENT_QUOTES, 'UTF-8') . "\n"; echo htmlspecialchars(utf8_decode($name), ENT_QUOTES, 'UTF-8') . "\n"; echo '<hr/>'; } Which produces: Antonín Dvořák AntonÃÆÃ­n DvoÃâ¦Ãâ¢ÃÆÃ¡k Anton??­n Dvo??????¡k Antonín Dvořák AntonÃÆÃ­n DvoÃâ¦Ãâ¢ÃÆÃ¡k ---------- Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶ ñÃâ¬Ã¡Ã´ ýáùáÿÃâ¬ÃµÃ¡Ã¶ ????? ?????????? Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶ ñÃâ¬Ã¡Ã´ ýáùáÿÃâ¬ÃµÃ¡Ã¶ ---------- Tiësto Tiësto Tiësto Tiësto Tiësto Tiësto ---------- When removing 'SET NAMES utf8' with PDO it produces the data: Antonín DvoÅák Antonín DvoÃÂák Antonín Dvorák Antonín DvoÅák Antonín DvoÃÂák Antonín Dvorák ---------- ???? ????????? Ô±ÖÕ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿ÖÕµÕ¡Õ¶ ???? ????????? ???? ????????? Ô±ÖÕ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿ÖÕµÕ¡Õ¶ ???? ????????? ---------- Tiësto Tiësto Ti?sto Tiësto Tiësto ---------- And here is a dump of the database rows concerned: DROP TABLE IF EXISTS `data`; CREATE TABLE IF NOT EXISTS `data` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(80) NOT NULL, PRIMARY KEY (`id`), KEY `name` (`name`(10)), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=0; INSERT INTO `data` (`id`, `name`) VALUES (0, 'Antonín Dvořák'), (1, 'Ô±Ö€Õ¡Õ´ Ô½Õ¡Õ¹Õ¡Õ¿Ö€ÕµÕ¡Õ¶'), (2, 'Tiësto'); The 3rd and 6th lines of the 3rd row "Tiësto" are then correctly echoed. I'm just unsure what is the best way to correct encodings/detect the encodings of bad strings and correct, etc.

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  • jQuery selectable() elements update values

    - by Josh
    Basically what I'm trying to do is update the value attribute of a hidden input field contained within the selected element when the selectable() UI stops running. If the element is selected, then the input's value should be the name attribute of that particular LI, whereas if the element is not selected, the value should be updated as empty. HTML Sample: <ul id="selector"> <li class="networkicon shr-digg" name="shr-digg"> <div></div> <label>Digg</label> <input type="hidden" value="" name="bookmark[]" /> </li> <li class="networkicon shr-reddit" name="shr-reddit"> <div></div> <label>Reddit</label> <input type="hidden" value="" name="bookmark[]" /> </li> <li class="networkicon shr-newsvine" name="shr-newsvine"> <div></div> <label>Newsvine</label> <input type="hidden" value="" name="bookmark[]" /> </li> </ul> Script Sample: $(function() { $("#selector").selectable({ filter: 'li', selected: function(event, ui) { $(".ui-selected").each(obj, function() { $(this).children('input').val($(this).attr('name')); }); }, unselected: function(event, ui) { $(".ui-selected").each(obj, function() { $(this).children('input').val(''); }); } }); });

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • Currently using View, Should I use a hard table instead?

    - by 1001010101
    I am currently debating whether my table, mapping_uGroups_uProducts, which is a view formed by the following table: CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `db`.`mapping_uGroups_uProducts` AS select distinct `X`.`upID` AS `upID`,`Z`.`ugID` AS `ugID` from ((`db`.`mapping_uProducts_Products` `X` join `db`.`productsInfo` `Y` on((`X`.`pID` = `Y`.`pID`))) join `db`.`mapping_uGroups_Groups` `Z` on((`Y`.`gID` = `Z`.`gID`))); My current query is: SELECT upID FROM uProductsInfo \ JOIN fs_uProducts USING (upID) column \ JOIN mapping_uGroups_uProducts USING (upID) -- could be faster if we use hard table and index \ JOIN mapping_fs_key USING (fsKeyID) \ WHERE fsName="OVERALL" \ AND ugID=1 \ ORDER BY score DESC \ LIMIT 0,30; which is pretty slow. (for 30 results, it requires about 10 secondes). I think the reason for my query being so slow is definitely due to the fact that that particular query relies on a VIEW which has no index to speed things up. +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | 1 | PRIMARY | mapping_fs_key | const | PRIMARY,fsName | fsName | 386 | const | 1 | Using temporary; Using filesort | | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 19706 | Using where | | 1 | PRIMARY | uProductsInfo | eq_ref | PRIMARY | PRIMARY | 4 | mapping_uGroups_uProducts.upID | 1 | Using index | | 1 | PRIMARY | fs_uProducts | ref | upID | upID | 4 | db.uProductsInfo.upID | 221 | Using where | | 2 | DERIVED | X | ALL | PRIMARY | NULL | NULL | NULL | 40772 | Using temporary | | 2 | DERIVED | Y | eq_ref | PRIMARY | PRIMARY | 4 | db.X.pID | 1 | Distinct | | 2 | DERIVED | Z | ref | PRIMARY | PRIMARY | 4 | db.Y.gID | 2 | Using index; Distinct | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ 7 rows in set (0.48 sec) The explain here looks pretty cryptic, and I don't know whether I should drop view and write a script to just insert everything in the view to a hard table. ( obviously, it will lose the flexibility of the view since the mapping changes quite frequently). Does anyone have any idea to how I can optimize my schema better?

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  • Error in computed Field of select Query

    - by Shehzad Bilal
    This Query is giving me an error of #1054 - Unknown column 'totalamount' in 'where clause' SELECT (amount1 + amount2) as totalamount FROM `Donation` WHERE totalamount > 1000 I know i can resolve this error by using group by clause and replace my where condition with having clause. But is there any other solution beside using having clause. If group by is the only solution then I want to know why I have to use group by clause even I havent use any aggregate function thanks.

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  • GROUP BY a date, with ordering by date.

    - by standard
    Take this simple query: SELECT DATE_FORMAT(someDate, '%y-%m-%d') as formattedDay FROM someTable GROUP BY formatterDay This will select rows from a table with only 1 row per date. How do I ensure that the row selected per date is the earliest for that date, without doing an ordered subquery in the FROM? Cheers

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  • need code for show result inside table html

    - by klox
    dear all..i have a textfield <tr> <td> <td><input type="text" id="model_name"></td> </td> </tr> and a cell <tr> <td><div id="value">//i want data show here after fill textfield</div> </td> </tr> beside that, i've a table "settingdata" in database it consist of 2 field:itemdata and remark.. itemdata's value are "UD" and remark's value are "FM=87.5-108.0MHZ"... what must i do if i want after type model name "car01UD" at textfield inside <div id="value"></div> can show "FM=87.5-108.0mhz"...

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  • PHP FUNCTION TO AUTOMATICALLY REMOVE WHITESPACE AND TRIM DOWN IDENTIFIERS

    - by H8 MY H0ST
    I HAVE A WEBSITE WHICH GETS WAY TOO MUCH TRAFFIC. MY HOST IS MAKING ME UPGRADE AND I'M LIKE MAN MY SITE MAKES $0 CUZ I AINT NO SPAMMER YA DIGG? I WILL CUT DOWN ON THE BANDWITH AND THEY'RE LIKE OKAY. GONNA DO GZIP. BUT I NEED LIKE A FUNCTION TO STRIP ALL WHITESPACE AND EXTRA SHIT FROM OUTPUT TOO IF POSSIBLE. AND THEN STUFF THAT CAN TURN MY #WRAPPER INTO LIKE #A #B #C ?? USING ZEND FRAMEWORK AT THE MOMENT. THANK YOU ALL VERY MUCH FOR YOUR TIME.

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  • Query multiple currencies

    - by TiuTalk
    I need store multiple currencies on my database... Here's the problem: Example Tables: [ Products ] id (INT, PK) name (VARCHAR) price (DECIMAL) currency (INT, FK) [ Currencies ] id (INT, PK) name (VARCHAR) conversion (DECIMAL) # To U$ I'll store the product price with the currency selected by the user... Later I need to search the products using a price interval like "Search products with price from U$ 50 to U$ 100" and I need the system convert these values "on the fly" to run the SQL Query and filter the products. And I really don't know how to make this query... :/

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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • How to do an additional search on archive in rails if record not found, by extending model?

    - by Nick Gorbikoff
    Hello, I was wondering if somebody knows an elegant solution to the following: Suppose I have a table that holds orders, with a bunch of data. So I'm at 1M records, and searches begin to take time. So I want to speed it up by archiving some data that is more than 3 years old - saving it into a table called orders-archive, and then purging them from the orders table. So if we need to research something or customer wants to pull older information - they still can, but 99% of the lookups are done on the orders no older than a year and a half - so there is no reason to keep looking through older data all the time. These move & purge operations can be then croned to be done on a weekly basis. I already did some tests and I know that I will slash my search times by about 4 times. So far so good, right? However I was thinking about how to implement older archival lookups and the only reasonable thing I can think of is some sort of if-else If not found in orders, do a search in orders-archive. However - I have about 20 tables that I want to archive and god knows how many searches / finds are done through out the code, that I don't want to modify. So I was wondering if there is an elegant rails-way solution to this problem, by extending a model somehow? Has anyone dealt with similar case before? Thank you.

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  • Getting a table's values into a tree

    - by Jason
    So, I have a table like such: id|root|kw1|kw2|kw3|kw4|kw5|name 1| A| B| C| D| E| F|fileA 2| A| B| | | | |fileB 3| B| C| D| E| | |fileC 4| A| B| | | | |fileD (several hundred rows...) And I need to get it into a tree like the following: *A *B -fileB -fileD *C *D *E *F -fileA *B *C *D *E -fileC I'm pretty sure the table is laid out poorly but it's what I have to live with. I've read a little about Adjacency List Model & Modified Preorder Tree Traversal but I don't think my data is laid out correctly. I think this requires a recursive function, but I'm not at all sure how to go about that. I'm open to any ideas of how to get this done even if it means extracting the data into a new table just to process this. Are there any good options available to me or any good ways to do this? (Examples are a bonus of course)

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • Correct Sql Script for Formula

    - by Madan Madan
    Can anyone help me write SQL script for the following formula? If DEP = 1 If DROP 1 PLV = 334.86 * exp(0.3541 * ACTIVE_DAYS) + 0.25 * DROP + 20 * DEP Else If DROP < 0 PLV = DROP + 70 * ACTIVE_DAYS Else PLV = 0.25 * DROP + 70 * ACTIVE_DAYS The SQL script which I have is the following SELECT IF(dep=1, if(dep=1, (334.86 * exp(0.3541 * act_days)) + (0.25 * 'drop') + (20 * dep), if('drop'<0, 'drop' + (70 * act_days), (0.25 * 'drop') + (70 * act_days))),'0') as PLV But the above query is not right as something is missing where the formula says Else PLV = 0.26 * DROP Thanks,

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  • How can I perform this query between related tables without using UNION?

    - by jeremy
    Suppose I have two separate tables that I watch to query. Both of these tables has a relation with a third table. How can I query both tables with a single, non UNION based query? I want the result of the search to rank the results by comparing a field on each table. Here's a theoretical example. I have a User table. That User can have both CDs and books. I want to find all of that user's books and CDs with a single query matching a string ("awesome" in this example). A UNION based query might look like this: SELECT "book" AS model, name, ranking FROM book WHERE name LIKE 'Awesome%' UNION SELECT "cd" AS model, name, ranking FROM cd WHERE name LIKE 'Awesome%' ORDER BY ranking DESC How can I perform a query like this without the UNION? If I do a simple left join from User to Books and CDs, we end up with a total number of results equal to the number of matching cds timse the number of matching books. Is there a GROUP BY or some other way of writing the query to fix this?

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