Search Results

Search found 36111 results on 1445 pages for 'mysql update'.

Page 464/1445 | < Previous Page | 460 461 462 463 464 465 466 467 468 469 470 471  | Next Page >

  • Form validation

    - by kielie
    Hi guys, I need to create a form that has many of the same fields, that have to be inserted into a database, but the problem I have is that if a user only fills in one or two of the rows, the form will still submit the blank data of the empty fields along with the one or two fields the user has filled in. How can I check for the rows that have not been filled in and leave them out of the query? or check for those that have been filled in and add them to the query. . . The thank_you.php file will capture the $_POST variables and add them to the database. <form method="post" action="thank_you.php"> Name: <input type="text" size="28" name="name1" /> E-mail: <input type="text" size="28" name="email1" /> <br /> Name: <input type="text" size="28" name="name2" /> E-mail: <input type="text" size="28" name="email2" /> <br /> Name: <input type="text" size="28" name="name3" /> E-mail: <input type="text" size="28" name="email3" /> <br /> Name: <input type="text" size="28" name="name4" /> E-mail: <input type="text" size="28" name="email4" /> <input type="image" src="images/btn_s.jpg" /> </form> I am assuming that I could use javascript or jQuery to accomplish this, how would I go about doing this? Thanx in advance for the help.

    Read the article

  • Is it possible for a Grails Domain to have no 'id'?

    - by firnnauriel
    Is it possible to create a table that has no 'id'? For example, this is my domain: class SnbrActVector { int nid String term double weight static mapping = { version false id generator: 'identity' } static constraints = { } } When I run this SQL statement, it fails: insert into snbr_act_vector values (5, 'term', 0.5) I checked the table and 'id' is already set to autoincrement. I'm thinking that another option is to remove the 'id' itself. Or is there another workaround for this? Please assume that it is not an option to change the givent SQL statement.

    Read the article

  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

    Read the article

  • PHP:Wrong Login info does not redirect to the specific page

    - by sdr
    <?php include 'lib/db_conn.php'; $uid=$_REQUEST['uid']; $pass=$_REQUEST['pass']; if(($uid==NULL && $pass==NULL) ||($uid==NULL) ||($pass==NULL)) { header("location:index.php?msg=Fields can't be left blank.."); } $pass=md5($pass); $sql1="SELECT * FROM `tb_user` WHERE `email`='$uid' AND `pass`='$pass'"; $rs1=mysql_query($sql1) or die (mysql_error()); $row1=mysql_fetch_array($rs1) or die (mysql_error()); $email=$row1['email']; if($uid==$email) { session_start(); $_SESSION['id']=$row1['id']; header("location:home.php"); } else { header("location:index.php?msg=Wrong Credentials.."); } ?>

    Read the article

  • alter mysqldump file before import

    - by julio
    Hi-- I have a mysqldump file created from an earlier version of a product that can't be imported into a new version of the product, since the db structure has changed slightly (mainly altering a column that was NOT NULL DEFAULT 0 to UNIQUE KEY DEFAULT NULL). If I just import the old dump file, it will error out since the column that has default values of 0 now breaks the UNIQUE constraint. It would be easy enough to either manually alter the mysqldump file, or import into a temp table and change it, then copy to the new table. However, is there a way to do this programatically, so it will be repeatable and not manual? (this will need to happen for many instances of this product). I'm thinking something like disabling key constraints for the import, then setting all values that = 0 to NULL, then re-enabling the key constraints? Is this possible? Any help appreciated.

    Read the article

  • making sure "expiration_date - X" falls on a valid "date_of_price" (if not, use the next valid date_

    - by bobbyh
    I have two tables. The first table has two columns: ID and date_of_price. The date_of_price field skips weekend days and bank holidays when markets are closed. table: trading_dates ID date_of_price 1 8/7/2008 2 8/8/2008 3 8/11/2008 4 8/12/2008 The second table also has two columns: ID and expiration_date. The expiration_date field is the one day in each month when options expire. table: expiration_dates ID expiration_date 1 9/20/2008 2 10/18/2008 3 11/22/2008 I would like to do a query that subtracts a certain number of days from the expiration dates, with the caveat that the resulting date must be a valid date_of_price. If not, then the result should be the next valid date_of_price. For instance, say we are subtracting 41 days from the expiration_date. 41 days prior to 9/20/2008 is 8/10/2008. Since 8/10/2008 is not a valid date_of_price, we have to skip 8/10/2008. The query should return 8/11/2008, which is the next valid date_of_price. Any advice would be appreciated! :-)

    Read the article

  • Use concat and maintain length of variable

    - by user1682055
    I'm trying to use concat on some variables. These variables have been declared as chars: declare v_order_date char(10); declare v_quantity char(11); declare v_plant char(100); I have a cursor where I am setting these as some outputs. To call the results, I am setting v_msg as set v_msg := concat( v_msg, '\n', v_order_date, v_quantity, v_plant); However, the result I am getting when I select v_msg is: 2012-01-222501008 Creeping Buttercup but I want to maintain the length of the declared variables in my select that looks like this 2012-01-22 250 1008 Creeping Buttercup Are there any suggestions? Thank you.

    Read the article

  • How to bring out checboxes based on drop down list selection from DB

    - by user2199877
    I got stuck again. Can't overcome this step: loop through (in a form of checkboxes) pallets based on the lot drop down list selection, so it can be further submitted to complete the table. Please, please help. So, basically, first submit button (drop down menu) brings into the table lot number and description and also checkboxes to choose pallets. Second submit button (checboxes) brings into the table pallets numbers and weights. Thank you for any help. <?php mysql_connect('localhost','user',''); mysql_select_db('base'); $query="SELECT DISTINCT lot_number FROM pl_table"; $result=mysql_query($query); ?> <form action="" method="POST"> <select name="option_chosen"> <option>-- Select lot --</option> <?php while(list($lot_number)=mysql_fetch_row($result)) { echo "<option value=\"".$lot_number."\">".$lot_number."</option>"; } ?> </select> <input type='submit' name='submitLot' value='Submit' /> </form> <!-- need help here <h4>-- Select pallets --</h4> <form action="" method="POST"> <input type='submit' name='submitPal' value='Submit'/> </form> --> <table border="1" id="table"> <tr> <th width=80 height=30>Lot<br/>number</th> <th width=110 height=30>Description</th> <th width=90 height=30>Pallet<br/>number</th> <th width=60 height=30>Net</th> <th width=60 height=30>Gross</th> </tr> <?php if($_SERVER['REQUEST_METHOD'] =='POST') {$option_chosen=$_POST['option_chosen']; $query="SELECT * FROM pl_table WHERE lot_number='$option_chosen'"; $run=mysql_query($query); $row=mysql_fetch_array($run, MYSQLI_ASSOC); echo "<tr><td>".''."</td>"; echo "<td rowspan='5'>".$row['descr']."</td>"; echo "<td><b>".'Total weight'."<b></td>"; echo "<td>".''."</td><td>".''."</td></tr>"; echo "<td>".$row['lot_number']."</td>"; echo "<td colspan='3'>".''."</td>"; //This to be echoed when "select pallets" submited //echo "<tr><td>".$row['lot_number']."</td>"; //echo "<td>".$row['pallet_number']."</td>"; //echo "<td>".$row['net']."</td><td>".$row['gross']."</td></tr>"; } ?> </table> the table +--------------------------+-------------------------+---------+-------+ | id | lot_number | descr | pallet_number | net | gross | +--------------------------+-------------------------+---------+-------+ | 1 | 111 | black | 1 | 800 | 900 | | 2 | 111 | black | 2 | 801 | 901 | | 3 | 111 | black | 3 | 802 | 902 | | 4 | 222 | white | 1 | 800 | 900 | | 5 | 222 | white | 2 | 801 | 901 | | 6 | 222 | white | 3 | 802 | 902 | +--------------------------+-------------------------+---------+-------+

    Read the article

  • Difficulty with sql query

    - by João Madureira Pires
    I have the following tables: TableA (id, tableB_id, tableC_id) TableB (id, expirationDate) TableC (id, expirationDate) I want to retrieve all the results from TableA ordered by tableB.expirationDate and tableC.expirationDate. How can I do this?

    Read the article

  • How to structure this query...?

    - by SpikETidE
    Hi Everyone... Consider the following table.... hotel facilities 1 internet 1 swimming pool 1 wi-fi 1 parking 2 swimming pool 2 sauna 2 parking 3 toilets 3 bungee-jumping 3 internet 4 parking 4 swimming pool I need to select only the hotels that have parking, swimming pool and internet....? I worked out the following.... SELECT hotel FROM table WHERE facilties IN(internet, swimming pool, parking) This query selects the hotels that has atleast one among the choices. But what i need is a query that selects the hotels that has ALL of the selected facilities... Thanks for your suggestions....

    Read the article

  • storing image_id after uploading image in article table

    - by Bader
    According to this question i successed to create upload image , but now i need to store the image_id to another table called articles , i do not know if this is correct , but i tried to select the image_id from table image like this $select_image=mysql_query("select image_id from image where image_name = $fileName") or die(mysql_error()); and fetch the result to my article insert query like this $fetch=mysql_fetch_array($select_image); $qeuery=mysql_query("insert into articles (article_name,article_category,article_subcategory,article_body,article_summary,article_tags,article_photo,article_timedate) values ('$article_title','$CategoryID','$ProductID','$article_body','$article_summary','$fetch[image_id]','$time')") or die ('Error, Query Faild'.mysql_error()); is this correct ? the mysql_error keeps saying " Unknown column 'Penguins.jpg' in 'where clause'"

    Read the article

  • Getting a table's values into a tree

    - by Jason
    So, I have a table like such: id|root|kw1|kw2|kw3|kw4|kw5|name 1| A| B| C| D| E| F|fileA 2| A| B| | | | |fileB 3| B| C| D| E| | |fileC 4| A| B| | | | |fileD (several hundred rows...) And I need to get it into a tree like the following: *A *B -fileB -fileD *C *D *E *F -fileA *B *C *D *E -fileC I'm pretty sure the table is laid out poorly but it's what I have to live with. I've read a little about Adjacency List Model & Modified Preorder Tree Traversal but I don't think my data is laid out correctly. I think this requires a recursive function, but I'm not at all sure how to go about that. I'm open to any ideas of how to get this done even if it means extracting the data into a new table just to process this. Are there any good options available to me or any good ways to do this? (Examples are a bonus of course)

    Read the article

  • SELECT(IF(IN query.

    - by Harold
    There are 3 tables. Products, Options and Prod_Opts_relations. The latter holds product_id and option_id so i should be able to figure out which options are selected for any given product. Now i want to retrieve all options from the options table where the value of an extra alias field should hold checked or unchecked depending on the existance of a mathing record in the relations table for a give product id. Thus far i came up with this: SELECT IF(IN(SELECT id_option FROM prod_opt_relations WHERE id_product='18'),'y','n') AS booh ,optionstable.id AS parent_id ,optionstable.name_en AS parent_english ,optionstable.name_es AS parent_spanish FROM product_options AS optionstable WHERE 1 resulting in syntax errors. Alas i just cannot figure out where things go wrong here

    Read the article

  • Best way to construct this query?

    - by Andrew
    I have two tables set up similar to this (simplified for the quest): actions- id - user_id - action - time users - id - name I want to output the latest action for each user. I have no idea how to go about it. I'm not great with SQL, but from what I've looked up, it should look something like the following. not sure though. SELECT `users`.`name`, * FROM users, actions JOIN < not sure what to put here > ORDER BY `actions`.`time` DESC < only one per user_id > Any help would be appreciated.

    Read the article

  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

    Read the article

  • 2 Select or 1 Join query ?

    - by xRobot
    I have 2 tables: book ( id, title, age ) ---- 100 milions of rows author ( id, book_id, name, born ) ---- 10 millions of rows Now, supposing I have a generic id of a book. I need to print this page: Title: mybook authors: Tom, Graham, Luis, Clarke, George So... what is the best way to do this ? 1) Simple join like this: Select book.title, author.name From book, author WHERE ( author.book_id = book.id ) AND ( book.id = 342 ) 2) For avoid the join, I could make 2 simple query: Select title FROM book WHERE id = 342 Select name FROM author WHERE book_id = 342 What is the most efficient way ?

    Read the article

  • Zend Framework multiple databases

    - by Uffo
    I'm currently using only one database with Zend Framework, but now I have to add ONE MORE. I'm using this code right now: public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db->adapter, $config->db->toArray()); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); } What code do I need to write in order to use ONE MORE database; and how I will reference it, when I need to make some queries or so.. Best Regards!

    Read the article

  • PHP form validation submit problem

    - by TaG
    Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

    Read the article

  • How do large sites accomplish row-level permissions?

    - by JayD3e
    So I am making a small site using cakephp, and my ACL is set up so that every time a piece of content is created, an ACL rule is created to link the owner of the piece of content to the actual content. This allows each owner to edit/delete their own content. This method just seems so inefficient, because there is an equivalent amount of ACL rules as content in the database. I was curious, how do big sites, with millions of pieces of content, solve this problem?

    Read the article

  • Rails find :conditions

    - by Sam
    I have a Reservation model that I'm searching for with three fields. The container_id must always be self.id but as confirmed and auto_confirmed only one needs to be true. I have the following but it doesn't preform what I need: Reservation.find(:all, :conditions => ['container_id = ? AND confirmed = ? OR auto_confirm = ?', self.id, true, true,]) How should I change this?

    Read the article

  • Selecting records with specific month and year in SQL Server 2005

    - by John
    I want to list records with a particular month and year. The table name is 'Arrival' and 'date' is the field that stores the date that the record was added. This is to be done from a C# application. For example, if the user selects month as 'April' and year as '2009' in the application, it will list all the records that were added on April,2009. (I only need the query, hope I can figure out the rest :) )

    Read the article

  • Database Design for One to One relationships

    - by Greelmo
    I'm trying to finalize my design of the data model for my project, and am having difficulty figuring out which way to go with it. I have a table of users, and an undetermined number of attributes that apply to that user. The attributes are in almost every case optional, so null values are allowed. Each of these attributes are one to one for the user. Should I put them on the same table, and keep adding columns when attributes are added (making the user table quite wide), or should I put each attribute on a separate table with a foreign key to the user table. I have decided against using the EAV model. Thanks!

    Read the article

< Previous Page | 460 461 462 463 464 465 466 467 468 469 470 471  | Next Page >