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  • How can I get columns name from select query in php?

    - by Farshad Mehrvarzan
    I want to execute a SELECT query but I don't how many columns to select. Like: select name, family from persons; How can I know which columns to select? "I am currently designing a site for the execute query by users. So when the user executes this query, I won't know which columns selected. But when I want to show the results and draw a table for the user I should know which columns selected."

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  • SQL Querying for Threaded Messages

    - by Harper
    My site has a messaging feature where one user may message another. The messages support threading - a parent message may have any number of children but only one level deep. The messages table looks like this: Messages - Id (PK, Auto-increment int) - UserId (FK, Users.Id) - FromUserId (FK, Users.Id) - ParentMessageId (FK to Messages.Id) - MessageText (varchar 200) I'd like to show messages on a page with each 'parent' message followed by a collapsed view of the children messages. Can I use the GROUP BY clause or similar construct to retrieve parent messages and children messages all in one query? Right now I am retrieving parent messages only, then looping through them and performing another query for each to get all related children messages. I'd like to get messages like this: Parent1 Child1 Child2 Child3 Parent2 Child1 Parent3 Child1 Child2

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • Retrieving multiple rows from a loop-created form... Stuck.

    - by hangston
    Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking.

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • Are Conditional subquery

    - by Tobias Schulte
    I have a table foo and a table bar, where each foo might have a bar (and a bar might belong to multiple foos). Now I need to select all foos with a bar. My sql looks like this SELECT * FROM foo f WHERE [...] AND ($param IS NULL OR (SELECT ((COUNT(*))>0) FROM bar b WHERE f.bar = b.id)) with $param being replaced at runtime. The question is: Will the subquery be executed even if param is null, or will the dbms optimize the subquery out?

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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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  • PHP:Wrong Login info does not redirect to the specific page

    - by sdr
    <?php include 'lib/db_conn.php'; $uid=$_REQUEST['uid']; $pass=$_REQUEST['pass']; if(($uid==NULL && $pass==NULL) ||($uid==NULL) ||($pass==NULL)) { header("location:index.php?msg=Fields can't be left blank.."); } $pass=md5($pass); $sql1="SELECT * FROM `tb_user` WHERE `email`='$uid' AND `pass`='$pass'"; $rs1=mysql_query($sql1) or die (mysql_error()); $row1=mysql_fetch_array($rs1) or die (mysql_error()); $email=$row1['email']; if($uid==$email) { session_start(); $_SESSION['id']=$row1['id']; header("location:home.php"); } else { header("location:index.php?msg=Wrong Credentials.."); } ?>

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  • Getting a table's values into a tree

    - by Jason
    So, I have a table like such: id|root|kw1|kw2|kw3|kw4|kw5|name 1| A| B| C| D| E| F|fileA 2| A| B| | | | |fileB 3| B| C| D| E| | |fileC 4| A| B| | | | |fileD (several hundred rows...) And I need to get it into a tree like the following: *A *B -fileB -fileD *C *D *E *F -fileA *B *C *D *E -fileC I'm pretty sure the table is laid out poorly but it's what I have to live with. I've read a little about Adjacency List Model & Modified Preorder Tree Traversal but I don't think my data is laid out correctly. I think this requires a recursive function, but I'm not at all sure how to go about that. I'm open to any ideas of how to get this done even if it means extracting the data into a new table just to process this. Are there any good options available to me or any good ways to do this? (Examples are a bonus of course)

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  • Which field is explain telling me to index?

    - by shady
    I don't understand what this explain statement is saying. Which field needs an index?. The first line to me is confusing because ref is null. Here's the query I'm using: SELECT pp.property_id AS 'good_prop_id', pr.site_number AS 'pr.site_number', CONCAT(pr.site_street_name, ' ', pr.site_street_type) AS 'pr.partial_addr', pr.county FROM realval_newdb.preforeclosures AS pr INNER JOIN realval_newdb.properties_preforeclosures AS pp USE INDEX (mee_id) ON (pr.mee_id = pp.mee_id) INNER JOIN listings_copy AS lc ON (pr.site_number = lc.site_number) AND (lc.site_street_name = CONCAT(pr.site_street_name, ' ', pr.site_street_type)) WHERE lc.site_county = pr.county LIMIT 1; Can anyone help me optimize this query?

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  • How to run a set of SQL queries from a file, in PHP?

    - by Harish Kurup
    I have some set of SQL queries which is in a file(i.e query.sql), and i want to run those queries in files using PHP, the code that i have wrote is not working, //database config's... $file_name="query.sql"; $query==file($file_name); $array_length=count($query); for($i=0;$i<$array_length;$i++) { $data .= $query[$i]; } echo $data; mysql_query($data); it echos the SQL Query from the file but throws an error at mysql_query() function...

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  • Fetch image from folder via datatable does not work after placing image in subdirectory

    - by Arnold Bishkoff
    I am having trouble wrapping my head around the following I have code that fetches an image via smarty in a line img src="getsnap.php?picid={$data[$smarty.section.sec.index].picno|default:$nextpic}&typ=pic&width={$config.disp_snap_width}&height={$config.disp_snap_height}" class="smallpic" alt="" / this works if i pull the image from /temp/userimages/userid/imageNo.ext but because an OS can segfault if you store too many folders or images in a directory i have code that assigns the user image to a subdirectory based upon division of a subdir per 1000 userids. so in thise case i have user id 94 whos images get stored in /siteroot/temp/userimages/000000/94/pic_1.jpg (through 10) or tn_1 (through 10).jpg here is the code for getsnap.php <?php ob_start(); if ( !defined( 'SMARTY_DIR' ) ) { include_once( 'init.php' ); } include('core/snaps_functions.php'); if (isset($_REQUEST['username']) && $_REQUEST['username'] != '') { $userid = $osDB-getOne('select id from ! where username = ?',array(USER_TABLE, $_REQUEST['username']) ); } else { // include ( 'sessioninc.php' ); if( !isset($_GET['id']) || (isset($_GET['id'])&& (int)$_GET['id'] <= 0 ) ) { $userid = $_SESSION['UserId']; } else { $userid = $_GET['id']; } } if (!isset($_GET['picid']) ) { if ((isset($_REQUEST['type']) && $_REQUEST['type'] != 'gallery') || !isset($_REQUEST['type']) ) { $defpic = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and default_pic = ? and active = ? ',array(USER_SNAP_TABLE, $userid,'0','Y','Y' ) ); if ($defpic != '') { $picid = $defpic; } else { $picid = $osDB-getOne('select picno from ! where userid = ? and ( album_id is null or album_id = ?) and active=? order by rand()',array(USER_SNAP_TABLE, $userid,'0','Y' ) ); } unset( $defpic); } } else { $picid = $_GET['picid']; } $typ = isset( $_GET['typ'])?$_GET['typ']:'pic' ; $cond = ''; if ( ($config['snaps_require_approval'] == 'Y' || $config['snaps_require_approval'] == '1') && $userid != $_SESSION['UserId'] ) { $cond = " and active = 'Y' "; } $sql = 'select * from ! where userid = ? and picno = ? '.$cond; //Get the pic $row =& $osDB-getRow ( $sql, array( USER_SNAP_TABLE, $userid, $picid ) ); //Okay pic was found in the DB, Lets actually do something // $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; $img = getPicture($zimg, $userid, $picid, $typ, $row); //$img = getPicture($userid, $picid, $typ, $row); //$img = getPicture($dir, $userid, $picid, $typ, $row); $ext = ($typ = 'tn')?$row['tnext']:$row['picext']; // Now pic is built as // something pic_x.ext ie pic_2.jpg if ( $img != '' && ( ( hasRight('seepictureprofile') && ( $config['snaps_require_approval'] == 'Y' && $row['active'] == 'Y' ) ||$config['snaps_require_approval'] == 'N' ) || $userid == $_SESSION['UserId'] ) ) { $img2 = $img; //$img2 = $dir.'/'.$img; } else { $gender = $osDB-getOne( 'select gender from ! where id = ?', array( USER_TABLE, $userid ) ) ; if ($gender == 'M') { $nopic = SKIN_IMAGES_DIR.'male.jpg'; } elseif ($gender == 'F') { $nopic = SKIN_IMAGES_DIR.'female.jpg'; } elseif ($gender == 'D') { $nopic = SKIN_IMAGES_DIR.'director.jpg'; } $img2 = imagecreatefromjpeg($nopic); $ext = 'jpg'; } ob_end_clean(); header("Pragma: public"); header("Content-Type: image/".$ext); header("Content-Transfer-Encoding: binary"); header("Cache-Control: must-revalidate"); $ExpStr = "Expires: " . gmdate("D, d M Y H:i:s", time() - 30) . " GMT"; header($ExpStr); $id = $userid; $dir = str_pad(($id - ($id % 1000))/100000,6,'0',STR_PAD_LEFT); $zimg = USER_IMAGES_DIR.$dir; //header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); //header("Content-Disposition: attachment; filename=$dir.'/'.profile_".$userid."".$typ.".".$ext); //header("Content-Disposition: attachment; filename=profile"$dir".'/'.".$userid."_".$typ.".".$ext); header("Content-Disposition: attachment; filename=profile_".$userid."_".$typ.".".$ext); /* if ($_SESSION['browser'] != 'MSIE') { header("Content-Disposition: inline" ); } */ if ($ext == 'jpg') { imagejpeg($img2); } elseif ($ext == 'gif') { imagegif($img2); } elseif ($ext == 'png') { imagepng($img2); } elseif ($ext == 'bmp') { imagewbmp($img2); } imagedestroy($img2); ?

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  • jQuery selectable() elements update values

    - by Josh
    Basically what I'm trying to do is update the value attribute of a hidden input field contained within the selected element when the selectable() UI stops running. If the element is selected, then the input's value should be the name attribute of that particular LI, whereas if the element is not selected, the value should be updated as empty. HTML Sample: <ul id="selector"> <li class="networkicon shr-digg" name="shr-digg"> <div></div> <label>Digg</label> <input type="hidden" value="" name="bookmark[]" /> </li> <li class="networkicon shr-reddit" name="shr-reddit"> <div></div> <label>Reddit</label> <input type="hidden" value="" name="bookmark[]" /> </li> <li class="networkicon shr-newsvine" name="shr-newsvine"> <div></div> <label>Newsvine</label> <input type="hidden" value="" name="bookmark[]" /> </li> </ul> Script Sample: $(function() { $("#selector").selectable({ filter: 'li', selected: function(event, ui) { $(".ui-selected").each(obj, function() { $(this).children('input').val($(this).attr('name')); }); }, unselected: function(event, ui) { $(".ui-selected").each(obj, function() { $(this).children('input').val(''); }); } }); });

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  • Explain this SQL query in plain English.

    - by Kevinniceguy
    Please explain, in plain English, what question this SQL query answers: SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • JOIN (SELECT DISTINCT [..] substitute

    - by FRKT
    Hello, I'd like to find a substitute for using SELECT DISTINCT in a derived table. Let's say I have three tables: CREATE TABLE `trades` ( `tradeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `employeeID` int(11) unsigned NOT NULL, `corporationID` int(11) unsigned NOT NULL, `profit` int(11) NOT NULL, KEY `tradeID` (`tradeID`), KEY `employeeID` (`employeeID`), KEY `corporationID` (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `corporations` ( `corporationID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `employees` ( `employeeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`employeeID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 Let's say I'd like to find out how much profit a specific employee has generated. Simple: SELECT SUM(profit) FROM trades JOIN employees ON trades.employeeID = employees.employeeID AND employees.employeeID = 1; It gets trickier if I'd like to query how much revenue a specific corporation has, however. I cannot simply replicate the aforementioned query, because two or more employees from the same company might be involved in the same trade. This query should do the trick: SELECT SUM(profit) FROM trades JOIN (SELECT DISTINCT tradeID FROM trades WHERE trades.corporationID = 1) ... unfortunately, DISTINCT JOINs seem crazy ineffective. Is there any alternative I can use to determine how much revenue a corporation has, taking into account that a corporation might be listed several times with the same tradeID?

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  • 2 Select or 1 Join query ?

    - by xRobot
    I have 2 tables: book ( id, title, age ) ---- 100 milions of rows author ( id, book_id, name, born ) ---- 10 millions of rows Now, supposing I have a generic id of a book. I need to print this page: Title: mybook authors: Tom, Graham, Luis, Clarke, George So... what is the best way to do this ? 1) Simple join like this: Select book.title, author.name From book, author WHERE ( author.book_id = book.id ) AND ( book.id = 342 ) 2) For avoid the join, I could make 2 simple query: Select title FROM book WHERE id = 342 Select name FROM author WHERE book_id = 342 What is the most efficient way ?

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