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  • CodeIgniter Unable to Access Error Message Error

    - by 01010011
    Hi, I've created this registration form for registering new users to a website using CodeIgniter. My problem is, whenever I enter a username that already exists in my database, instead of giving me my error message which explains this to the user, it instead gives me this error message: Unable to access an error message corresponding to your field name Here are snippets of the code from my controller. Any assistance will be appreciated: function register() $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Username','trim|required|alpha_numeric|min_length[6]|xss_clean|strtolower|callback_username_not_exists); ... } function username_not_exists($username) { $this->form_validation->set_message('username','That %s already exists.'); if($this->User_model->check_exists_username($username)) { return false; } else { return true; }

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  • Fulltext search on many tables

    - by Rob
    I have three tables, all of which have a column with a fulltext index. The user will enter search terms into a single text box, and then all three tables will be searched. This is better explained with an example: documents doc_id name FULLTEXT table2 id doc_id a_field FULLTEXT table3 id doc_id another_field FULLTEXT (I realise this looks stupid but that's because I've removed all the other fields and tables to simplify it). So basically I want to do a fulltext search on name, a_field and another_field, and then show the results as a list of documents, preferably with what caused that document to be found, e.g. if another_field matched, I would display what another_field is. I began working on a system whereby three fulltext search queries are performed and the results inserted into a table with a structure like: search_results table_name row_id score (This could later be made to cache results for a few days with e.g. a hash of the search terms). This idea has two problems. The first is that the same document can be in the search results up to three times with different scores. Instead of that, if the search term is matched in two tables, it should have one result, but a higher score. The second is that parsing the results is difficult. I want to display a list of documents, but I don't immediately know the doc_id without a join of some kind; however the table to join to is dependant on the table_name column, and I'm not sure how to accomplish that. Wanting to search multiple related tables like this must be a common thing, so I guess what I'm asking is am I approaching this in the right way? Can someone tell me the best way of doing it please.

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  • Sql query problem

    - by LiveEn
    I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

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  • Should you do validation checks that go outside the possiblility of normal user activity?

    - by Scarface
    Hey guys I have been thinking about form security a lot lately. I have been told time and time again to check if form input is a number if you are expecting a number or escape it in case (unless you use proper mysqli formatting) to avoid injection. 1.After the safety checks are done, should I do additional logic checks? For example, if the user is sending a friend request to them-self for example even if my user interface will not show the form if the user is looking at their own page.

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  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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  • Best practices to store CreditCard information into DataBase

    - by Garis Suero
    In my country the online payments are not an old thing, the first time i saw a web application taking payments directly to a local bank account was last year. So, Im a newbie coding web payment system. My question is, what are the best practices to store creditcard information into the database... I have many ideas: encrypting the creditcard, database security restriction, etc. What have you done?

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  • Non Working Relationship

    - by Dominik K.
    Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

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  • Looking for a good database structure to achieve Facebook/SO like notifications

    - by user156814
    I want to be able to have notifications on my site, similar to the way SO does it. I have looked for a good table structure to do this, but I cant seem to figure it out. I was thinking something like this. Notifications id, notification_type_id, user_id, type_id Notification Types id, notification_text Where the notification type would relate to either a new post, a new comment, or whatever features I add later down the line... User Id would relate to whoever the notification is for. Type_id and notification type would go hand in hand, so if the notification_type was a new comment, the type_id would be the comment_id to go to. This seems good to me, but i want to be able to notify ALL users when something changes.. like on facebook when you comment on something, you get a notification that someone else has also commented on the same thing after you. I cant seem to figure this out... Help wanted Thanks

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  • Using Active Objects and BLOBs

    - by Andrew L.
    I am in a group of people who are creating a Defect Tracking program as a project. We have been using Active Objects and have run into some issues. Currently maximum file size for the blob is approx. 2Mb but we want to be able to increase it up to 2Gb. We currently have been looking at many sites and have not been able to find out how to increase the size. We are currently storing the blob as an array of bytes. Our current error says, Packet for Query is too large? We don't know how to set the variable, and we don't know how to set it using AO. We are programming this in Java, too. We are wondering if anyone has a solution to this problem. Thanks for the Help.

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  • cakephp and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • A tale from a Stalker

    - by Peter Larsson
    Today I thought I should write something about a stalker I've got. Don't get me wrong, I have way more fans than stalkers, but this stalker is particular persistent towards me. It all started when I wrote about Relational Division with Sets late last year(http://weblogs.sqlteam.com/peterl/archive/2010/07/02/Proper-Relational-Division-With-Sets.aspx) and no matter what he tried, he didn't get a better performing query than me. But this I didn't click until later into this conversation. He must have saved himself for 9 months before posting to me again. Well... Some days ago I get an email from someone I thought i didn't know. Here is his first email Hi, I want a proper solution for achievement the result. The solution must be standard query, means no using as any native code like TOP clause, also the query should run in SQL Server 2000 (no CTE use). We have a table with consecutive keys (nbr) that is not exact sequence. We need bringing all values related with nearest key in the current key row. See the DDL: CREATE TABLE Nums(nbr INTEGER NOT NULL PRIMARY KEY, val INTEGER NOT NULL); INSERT INTO Nums(nbr, val) VALUES (1, 0),(5, 7),(9, 4); See the Result: pre_nbr     pre_val     nbr         val         nxt_nbr     nxt_val ----------- ----------- ----------- ----------- ----------- ----------- NULL        NULL        1           0           5           7 1           0           5           7           9           4 5           7           9           4           NULL        NULL The goal is suggesting most elegant solution. I would like see your best solution first, after that I will send my best (if not same with yours)   Notice there is no name, no please or nothing polite asking for my help. So, on the top of my head I sent him two solutions, following the rule "Work on SQL Server 2000 and only standard non-native code".     -- Peso 1 SELECT               pre_nbr,                              (                                                           SELECT               x.val                                                           FROM                dbo.Nums AS x                                                           WHERE              x.nbr = d.pre_nbr                              ) AS pre_val,                              d.nbr,                              d.val,                              d.nxt_nbr,                              (                                                           SELECT               x.val                                                           FROM                dbo.Nums AS x                                                           WHERE              x.nbr = d.nxt_nbr                              ) AS nxt_val FROM                (                                                           SELECT               (                                                                                                                     SELECT               MAX(x.nbr) AS nbr                                                                                                                     FROM                dbo.Nums AS x                                                                                                                     WHERE              x.nbr < n.nbr                                                                                        ) AS pre_nbr,                                                                                        n.nbr,                                                                                        n.val,                                                                                        (                                                                                                                     SELECT               MIN(x.nbr) AS nbr                                                                                                                     FROM                dbo.Nums AS x                                                                                                                     WHERE              x.nbr > n.nbr                                                                                        ) AS nxt_nbr                                                           FROM                dbo.Nums AS n                              ) AS d -- Peso 2 CREATE TABLE #Temp                                                         (                                                                                        ID INT IDENTITY(1, 1) PRIMARY KEY,                                                                                        nbr INT,                                                                                        val INT                                                           )   INSERT                                            #Temp                                                           (                                                                                        nbr,                                                                                        val                                                           ) SELECT                                            nbr,                                                           val FROM                                             dbo.Nums ORDER BY         nbr   SELECT                                            pre.nbr AS pre_nbr,                                                           pre.val AS pre_val,                                                           t.nbr,                                                           t.val,                                                           nxt.nbr AS nxt_nbr,                                                           nxt.val AS nxt_val FROM                                             #Temp AS pre RIGHT JOIN      #Temp AS t ON t.ID = pre.ID + 1 LEFT JOIN         #Temp AS nxt ON nxt.ID = t.ID + 1   DROP TABLE    #Temp Notice there are no indexes on #Temp table yet. And here is where the conversation derailed. First I got this response back Now my solutions: --My 1st Slt SELECT T2.*, T1.*, T3.*   FROM Nums AS T1        LEFT JOIN Nums AS T2          ON T2.nbr = (SELECT MAX(nbr)                         FROM Nums                        WHERE nbr < T1.nbr)        LEFT JOIN Nums AS T3          ON T3.nbr = (SELECT MIN(nbr)                         FROM Nums                        WHERE nbr > T1.nbr); --My 2nd Slt SELECT MAX(CASE WHEN N1.nbr > N2.nbr THEN N2.nbr ELSE NULL END) AS pre_nbr,        (SELECT val FROM Nums WHERE nbr = MAX(CASE WHEN N1.nbr > N2.nbr THEN N2.nbr ELSE NULL END)) AS pre_val,        N1.nbr AS cur_nbr, N1.val AS cur_val,        MIN(CASE WHEN N1.nbr < N2.nbr THEN N2.nbr ELSE NULL END) AS nxt_nbr,        (SELECT val FROM Nums WHERE nbr = MIN(CASE WHEN N1.nbr < N2.nbr THEN N2.nbr ELSE NULL END)) AS nxt_val   FROM Nums AS N1,        Nums AS N2  GROUP BY N1.nbr, N1.val;   /* My 1st Slt Table 'Nums'. Scan count 7, logical reads 14 My 2nd Slt Table 'Nums'. Scan count 4, logical reads 23 Peso 1 Table 'Nums'. Scan count 9, logical reads 28 Peso 2 Table '#Temp'. Scan count 0, logical reads 7 Table 'Nums'. Scan count 1, logical reads 2 Table '#Temp'. Scan count 3, logical reads 16 */  To this, I emailed him back asking for a scalability test What if you try with a Nums table with 100,000 rows? His response to that started to get nasty.  I have to say Peso 2 is not acceptable. As I said before the solution must be standard, ORDER BY is not part of standard SELECT. Try this without ORDER BY:  Truncate Table Nums INSERT INTO Nums (nbr, val) VALUES (1, 0),(9,4), (5, 7)  So now we have new rules. No ORDER BY because it's not standard SQL! Of course I asked him  Why do you have that idea? ORDER BY is not standard? To this, his replies went stranger and stranger Standard Select = Set-based (no any cursor) It’s free to know, just refer to Advanced SQL Programming by Celko or mail to him if you accept comments from him. What the stalker probably doesn't know, is that I and Mr Celko occasionally are involved in some conversation and thus we exchange emails. I don't know if this reference to Mr Celko was made to intimidate me either. So I answered him, still polite, this What do you mean? The SELECT itself has a ”cursor under the hood”. Now the stalker gets rude  But however I mean the solution must no containing any order by, top... No problem, I do not like Peso 2, it’s very non-intelligent and elementary. Yes, Peso 2 is elementary but most performing queries are... And now is the time where I started to feel the stalker really wanted to achieve something else, so I wrote to him So what is your goal? Have a query that performs well, or a query that is super-portable? My Peso 2 outperforms any of your code with a factor of 100 when using more than 100,000 rows. While I awaited his answer, I posted him this query Ok, here is another one -- Peso 3 SELECT             MAX(CASE WHEN d = 1 THEN nbr ELSE NULL END) AS pre_nbr,                    MAX(CASE WHEN d = 1 THEN val ELSE NULL END) AS pre_val,                    MAX(CASE WHEN d = 0 THEN nbr ELSE NULL END) AS nbr,                    MAX(CASE WHEN d = 0 THEN val ELSE NULL END) AS val,                    MAX(CASE WHEN d = -1 THEN nbr ELSE NULL END) AS nxt_nbr,                    MAX(CASE WHEN d = -1 THEN val ELSE NULL END) AS nxt_val FROM               (                              SELECT    nbr,                                        val,                                        ROW_NUMBER() OVER (ORDER BY nbr) AS SeqID                              FROM      dbo.Nums                    ) AS s CROSS JOIN         (                              VALUES    (-1),                                        (0),                                        (1)                    ) AS x(d) GROUP BY           SeqID + x.d HAVING             COUNT(*) > 1 And here is the stats Table 'Nums'. Scan count 1, logical reads 2, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0. It beats the hell out of your queries…. Now I finally got a response from my stalker and now I also clicked who he was. This is his reponse Why you post my original method with a bit change under you name? I do not like it. See: http://www.sqlservercentral.com/Forums/Topic468501-362-14.aspx ;WITH C AS ( SELECT seq_nbr, k,        DENSE_RANK() OVER(ORDER BY seq_nbr ASC) + k AS grp_fct   FROM [Sample]         CROSS JOIN         (VALUES (-1), (0), (1)         ) AS D(k) ) SELECT MIN(seq_nbr) AS pre_value,        MAX(CASE WHEN k = 0 THEN seq_nbr END) AS current_value,        MAX(seq_nbr) AS next_value   FROM C GROUP BY grp_fct HAVING min(seq_nbr) < max(seq_nbr); These posts: Posted Tuesday, April 12, 2011 10:04 AM Posted Tuesday, April 12, 2011 1:22 PM Why post a solution where will not work in SQL Server 2000? Wait a minute! His own solution is using both a CTE and a ranking function so his query will not work on SQL Server 2000! Bummer... The reference to "Me not like" are my exact words in a previous topic on SQLTeam.com and when I remembered the phrasing, I also knew who he was. See this topic http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=159262 where he writes a query and posts it under my name, as if I wrote it. So I answered him this (less polite). Like I keep track of all topics in the whole world… J So you think you are the only one coming up with this idea? Besides, “M S solution” doesn’t work.   This is the result I get pre_value        current_value                             next_value 1                           1                           5 1                           5                           9 5                           9                           9   And I did nothing like you did here, where you posted a solution which you “thought” I should write http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=159262 So why are you yourself using ranking function when this was not allowed per your original email, and no cte? You use CTE in your link above, which do not work in SQL Server 2000. All this makes no sense to me, other than you are trying your best to once in a lifetime create a better performing query than me? After a few hours I get this email back. I don't fully understand it, but it's probably a language barrier. >>Like I keep track of all topics in the whole world… J So you think you are the only one coming up with this idea?<< You right, but do not think you are the first creator of this.   >>Besides, “M S Solution” doesn’t work. This is the result I get <<   Why you get so unimportant mistake? See this post to correct it: Posted 4/12/2011 8:22:23 PM >> So why are you yourself using ranking function when this was not allowed per your original email, and no cte? You use CTE in your link above, which do not work in SQL Server 2000. <<  Again, why you get some unimportant incompatibility? You offer that solution for current goals not me  >> All this makes no sense to me, other than you are trying your best to once in a lifetime create a better performing query than me? <<  No, I only wanted to know who you will solve it. Now I know you do not have a special solution. No problem. No problem for me either. So I just answered him I am not the first, and you are not the first to come up with this idea. So what is your problem? I am pretty sure other people have come up with the same idea before us. I used this technique all the way back to 2007, see http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=93911 Let's see if he returns...  He did! >> So what is your problem? << Nothing Thanks for all replies; maybe we have some competitions in future, maybe. Also I like you but you do not attend it. Your behavior with me is not friendly. Not any meeting… Regards //Peso

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  • In SQL, if we rename INNER JOIN as INTERSECT JOIN, LEFT OUTER JOIN as LEFT UNION JOIN, and FULL OUTE

    - by Jian Lin
    In SQL, the name Join gives an idea of "merging" or a sense of "union", making something bigger. But in fact, as in the other post http://stackoverflow.com/questions/2706051/in-sql-a-join-is-actually-an-intersection-and-it-is-also-a-linkage-or-a-sidew it turns out that a Join (Inner Join) is actually an Intersection. So if we think of Join = Inner Join = Intersect Join Left Outer Join = Left Union Join Full Outer Join = Full Union Join = Union Join then we always get a feel of what's happening, and maybe never forget what they are easily. In a way, we can think of Intersect as "making it less", therefore it is excluding something. That's why the name "Join" won't go with the idea of "Intersect". But in fact, both Intersect and Union can be thought of as: Union: bringing something together and merge them unconditionally. Intersect: bringing something together and merge them based on some condition. so the "bringing something together" is probably what "Join" is all about. It is like, Intersection is a "half glass of water" -- we can thinking of it as "excluding something" or as "bringing something together and accepting the common ones". So if the word "Intersect Join" is used, maybe a clear picture is there, and "Union Join" can be a clear picture too. Maybe the word "Inner Join" and "Outer Join" is very clear when we use SQL a lot. Somehow, the word "Outer" tends to give a feeling that it is "outside" and excluding something rather than a "Union".

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  • Database design grouping contacts by lists and companies

    - by Serge
    Hi, I'm wondering what would be the best way to group contacts by their company. Right now a user can group their contacts by custom created lists but I'd like to be able to group contacts by their company as well as store the contact's position (i.e. Project Manager of XYZ company). Database wise this is what I have for grouping contacts into lists contact [id_contact] [int] PK NOT NULL, [lastName] [varchar] (128) NULL, [firstName] [varchar] (128) NULL, ...... contact_list [id_contact] [int] FK, [id_list] [int] FK, list [id_list] [int] PK [id_user] [int] FK [list_name] [varchar] (128) NOT NULL, [description] [TEXT] NULL Should I implement something similar for grouping contacts by company? If so how would I store the contact's position in that company and how can I prevent data corruption if a user modifies a contact's company name. For instance John Doe changed companies but the other co-workers are still in the old company. I doubt that will happen often (might not even happen at all) but better be safe than sorry. I'm also keeping an audit trail so in a way the contact would still need to be linked to the old company as well as the new one but without confusing what company he's actually working at the moment. I hope that made sense... Has anyone encountered such a problem? UPDATE Would something like this make sense contact_company [id_contact_company] [int] PK [id_contact] [int] FK [id_company] [int] FK [contact_title] [varchar] (128) company [id_company] [int] PK NOT NULL, [company_name] [varchar] (128) NULL, [company_description] [varchar] (300) NULL, [created_date] [datetime] NOT NULL This way a contact can work for more than one company and contacts can be grouped by companies

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  • HTML anchor too pull all Sticky Posts ?

    - by Gnee
    Is there a way to format an tag to send a query, pull all Sticky Posts, and loop through them? Since 'sticky' is not a category, I cant format the link in the normal : http://mysite.com/category/cars I'm thinking is probably going to have to be some kind of url query string sent in as GET.

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  • internet explorer and google chrome rendering issues

    - by jeansymolanza
    hi guys, i'm trying to build a login and main page on dreamweaver for a client and testing them in google chrome and internet explorer but i am running into a lot of unexpected difficulties. the main thing has to be the way the tables are being rendered on the different pages. it seems to appear well on google chrome but when i test the page under internet explorer there have been issues with the way the footer is being rendered. i've included several images showing the problem: login page on IE8 http://i39.tinypic.com/iz9lw3.jpg login page on google chrome http://i44.tinypic.com/1zn0qd2.jpg main page on IE8 http://i41.tinypic.com/2d0gyhf.jpg main page on google chrome http://i42.tinypic.com/2ry58aw.jpg login fail on IE8 http://i40.tinypic.com/2jea9ac.jpg login fail on google chrome http://i43.tinypic.com/sl35h2.jpg please help! i have included the source code below. i spent an entire night trying to figure out what was wrong but to little success. login page: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" href="resources/css_01.css"> <link rel="shortcut icon" href="resources/favicon.ico"> <title>Speedy CMS</title> <script src="SpryAssets/SpryValidationTextField.js" type="text/javascript"></script> <script src="SpryAssets/SpryValidationPassword.js" type="text/javascript"></script> <link href="SpryAssets/SpryValidationTextField.css" rel="stylesheet" type="text/css" /> <link href="SpryAssets/SpryValidationPassword.css" rel="stylesheet" type="text/css" /> </head> <body class="oneColElsCtr" background="resources/bg_01.jpg"> <div id="container"> <div id="mainContent"> <!-- start #mainContent --> <table id="Table_01" width="1024" height="100%" border="0" cellpadding="0" cellspacing="0"> <tr> <td valign="top" rowspan="3"> <img src="resources/login_01.png" width="93" height="440" alt=""></td> <td valign="top" rowspan="3"> <img src="resources/login_02.png" width="457" height="440" alt=""></td> <td valign="top"> <img src="resources/login_03.png" width="474" height="86" alt=""></td> </tr> <tr> <td valign="top"><img src="resources/login_04.png" width="474" height="89" /></td> </tr> <tr> <td valign="top" width="100%" height="100%" align="left"> <form ACTION="<?php echo $loginFormAction; ?>" METHOD="POST" name="login" > <h3 class="login">Username</h3> <span id="sprytextfield1"> <input name="username" type="text" class="input" /> </span> <h3 class="login">Password</h3> <span id="sprypassword1"> <input name="password" type="password" class="input" /> </span> <p></p> <div align="left" style="width:474px; padding-top: 10px; padding-left: 100px;"> <input name="login" type="submit" id="Log in" value="Log in" class="btn"/> </div> </p> </form> </td> </tr> </table> </div> </div> <!-- end #mainContent --> <!-- start #footer --> <?php include("resources/footer.php"); ?> <!-- end #footer --> <script type="text/javascript"> <!-- var sprytextfield1 = new Spry.Widget.ValidationTextField("sprytextfield1"); var sprypassword1 = new Spry.Widget.ValidationPassword("sprypassword1"); //--> </script> </body> </html> main page: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" href="resources/css_01.css"> <link rel="shortcut icon" href="resources/favicon.ico"> <title>Speedy CMS</title> <body class="oneColElsCtr" background="resources/bg_01.jpg"> <div id="container"> <div id="mainContent"> <!-- start #mainContent --> <table id="Table_01" width="1024" border="0" cellpadding="0" cellspacing="0"> <tr> <td rowspan="7"> <img src="resources/main_01.png" width="93" height="440" alt=""></td> <td colspan="2"> <img src="resources/main_02.png" width="457" height="95" alt=""></td> <td colspan="3" valign="bottom"> <!-- start #navbar --> <?php include("resources/navbar.php"); ?> <!-- end #navbar --> </td> </tr> <tr> <td colspan="2"> <img src="resources/main_04.png" width="457" height="1" alt=""></td> <td colspan="3" rowspan="2" valign="top"><a class="bottom2" href="<?php echo $logoutAction ?>">Log off</a></td> </tr> <tr> <td colspan="2"> <img src="resources/main_06.png" width="457" height="29" alt=""></td> </tr> <tr> <td rowspan="4"> <img src="resources/main_07.png" width="456" height="315" alt=""></td> <td colspan="2"> <img src="resources/main_08.png" width="75" height="94" alt=""></td> <td rowspan="3"> <img src="resources/main_09.png" width="6" height="281" alt=""></td> <td align="left" valign="middle" style="padding-left:20px;"><h2 class="home">Hello, <?php echo $_SESSION['MM_Username']; ?></h2></td> </tr> <tr> <td rowspan="3"> <img src="resources/main_11.png" width="1" height="221" alt="" /></td> <td> <img src="resources/main_12.png" width="74" height="90" alt=""></td> <td align="left" valign="middle" style="padding-left:20px;"><h3 class="home"><?php echo date("l F d, Y, h:i A"); ?></h3></td> </tr> <tr> <td> <img src="resources/main_14.png" width="74" height="97" alt="" /></td> <td align="left" valign="middle" style="padding-left:20px;"><h3 class="home">You currently have <a href="progress.php" class="main"><?php echo $totalCases; ?> claims</a> running</h3></td> </tr> <tr> <td colspan="3"> <img src="resources/main_16.png" width="474" height="34" alt=""></td> </tr> </table> </div> </div> <!-- end #mainContent --> <!-- start #footer --> <?php include("resources/footer.php"); ?> <!-- end #footer --> </body> </html> <?php mysql_free_result($tbl_accident); ?> login fail page <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link rel="stylesheet" href="resources/css_01.css"> <link rel="shortcut icon" href="resources/favicon.ico"> <title>Speedy CMS</title> <script src="SpryAssets/SpryValidationTextField.js" type="text/javascript"></script> <script src="SpryAssets/SpryValidationPassword.js" type="text/javascript"></script> <link href="SpryAssets/SpryValidationTextField.css" rel="stylesheet" type="text/css" /> <link href="SpryAssets/SpryValidationPassword.css" rel="stylesheet" type="text/css" /> </head> <body class="oneColElsCtr" background="resources/bg_02.jpg"> <div id="container"> <div id="mainContent"> <table id="Table_01" width="1024" height="" border="0" cellpadding="0" cellspacing="0"> <tr> <td rowspan="4"> <img src="resources/default2_01.png" width="93" height="440" alt=""></td> <td colspan="2"><img src="resources/default_02.png" width="457" height="95" /></td> <td valign="bottom"></td> </tr> <tr> <td colspan="2"> <img src="resources/default2_03.png" width="457" height="1" alt=""></td> <td> <img src="resources/default2_04.png" width="474" height="1" alt=""></td> </tr> <tr> <td colspan="3"> <div align="left" style="padding-left: 18px;"> <h3 class="loginfail">Sorry, but your username and password is incorrect.</h3> <h4 class="loginfail">Please try again!</h4> <form ACTION="<?php echo $loginFormAction; ?>" METHOD="POST" name="login" > <h5 class="loginfail">Username</h5> <span id="sprytextfield1"> <input name="username" type="text" class="input2" /> </span> <h5 class="loginfail">Password</h5> <span id="sprypassword1"> <input name="password" type="password" class="input2" /> </span> <img src="resources/spacer.gif" width="1" height="5" alt="" /> <p></p> <div align="left" style="width:474px; padding-top: 10px;"> <input name="login" type="submit" id="Log in" value="Log in" class="btn"/> </div> </p> </form> </td> </tr> <tr> <td colspan="3" height="100%"> </td> </tr> <tr> <td> <img src="resources/spacer.gif" width="93" height="1" alt=""></td> <td> <img src="resources/spacer.gif" width="337" height="1" alt=""></td> <td> <img src="resources/spacer.gif" width="120" height="1" alt=""></td> <td> <img src="resources/spacer.gif" width="474" height="1" alt=""></td> </tr> </table> </div> </div> <!-- start #footer --> <?php include("resources/footer2.php"); ?> <!-- end #footer --> <script type="text/javascript"> <!-- var sprytextfield1 = new Spry.Widget.ValidationTextField("sprytextfield1"); var sprypassword1 = new Spry.Widget.ValidationPassword("sprypassword1"); //--> </script> </body> </html> footer.php <table width="1024px" border="0" cellspacing="0" cellpadding="0" style="padding-left: 200px; padding-top: 10px; padding-bottom: 36px; text-align: left;"> <!-- speedy claim links --> <td width="33%" valign="top"> <div class="bottom" style="padding-left: 40px; text-align: left;">Learn About Us</div> <div class="hr" style="margin-left: 40px; width: 200px;"><hr /></div> <div style="padding-left: 40px; text-align: left;"> <a href="http://www.speedyclaim.co.uk/php/gifts.php" class="bottom2" target="_blank">Free Gifts</a><BR /> <a href="http://www.speedyclaim.co.uk/php/calculator.php" class="bottom2" target="_blank">Injury Calculator</a><BR /> <a href="http://www.speedyclaim.co.uk/php/aboutus.php" class="bottom2" target="_blank">About Us</a><BR /> <a href="http://www.speedyclaim.co.uk/php/claimonline.php" class="bottom2" target="_blank">Claim Online</a><BR /> <a href="http://www.speedyclaim.co.uk/php/contactus.php" class="bottom2" target="_blank">Contact Us</a><BR /> </div> </td> <!-- speedy claim links --> <td width="33%" valign="top"> <div class="bottom" style="padding-left: 40px; text-align: left;">Get Help</div> <div class="hr" style="margin-left: 40px; width: 200px;"><hr /></div> <div style="padding-left: 40px;"> <a href="http://www.speedyclaim.co.uk/php/services.php#roadaccident" class="bottom2" target="_blank">Road Traffic Accident</a><BR /> <a href="http://www.speedyclaim.co.uk/php/services.php#workaccident" class="bottom2" target="_blank">Work Accident</a><BR /> <a href="http://www.speedyclaim.co.uk/php/services.php#criminalinjury" class="bottom2" target="_blank">Criminal Injury</a><BR /> <a href="http://www.speedyclaim.co.uk/php/services.php#medicalnegligence" class="bottom2" target="_blank">Medical Neglicence</a><BR /> <a href="http://www.speedyclaim.co.uk/php/services.php#publicl" class="bottom2" target="_blank">Public Liability</a><BR /> <a href="http://www.speedyclaim.co.uk/php/services.php#taxiaccident" class="bottom2" target="_blank">Taxi Related Accident</a><BR /> </div> <!-- speedline --> <td width="33%" valign="top"> <div class="bottom" style="padding-left: 40px; text-align: left;">Taxi Service</div> <div class="hr" style="margin-left: 40px; width: 200px;"><hr /></div> <div style="padding-left: 40px;"> <a href="http://www.speedlinetaxi.com/airport.asp" class="bottom2" target="_blank">Airport Meet & Greet</a><BR /> <a href="http://www.speedlinetaxi.com/register.asp" class="bottom2" target="_blank">Automated Booking</a><BR /> <a href="http://www.speedlinetaxi.com/business.asp" class="bottom2" target="_blank">Business Accounts</a><BR /> <a href="http://www.speedlinetaxi.com/technology.asp" class="bottom2" target="_blank">Technology</a><BR /> <a href="https://ebook.autocab.net/3037" class="bottom2" target="_blank">E-Booking</a><BR /> <a href="http://www.speedlinetaxi.com/recruitment.asp" class="bottom2" target="_blank">Recruitment</a><BR /> <a href="http://www.speedlinetaxi.com/feedback.asp" class="bottom2" target="_blank">Feedback</a><BR /> <BR /> </div> </td> <tr> <td colspan="3" valign="top" style="padding-top:5px; padding-left:40px;"> <span class="bottom"> &copy; <?php echo date("Y")?> Speedline </span> </td> </tr> </table> footer2.php <table width="100%" border="0" cellspacing="0" cellpadding="0" style="padding-left: 188px; padding-top: 10px; text-align: left;" align="center"> <!-- speedy claim links --> <tr> <td width="99%" valign="top" style="padding-top:5px; padding-left:40px; padding-bottom: 10px;"> <span class="bottom"> &copy; <?php echo date("Y")?> Speedline </span> </td> </tr> </table> css_01.css html, body { height: 100%; margin: 0 0 1px; padding: 0; } body { font: 100% Arial, Helvetica, sans-serif; background-repeat: repeat-x; margin: 0; /* it's good practice to zero the margin and padding of the body element to account for differing browser defaults */ padding: 0; text-align: center; /* this centers the container in IE 5* browsers. The text is then set to the left aligned default in the #container selector */ color: #000000; } .oneColElsCtr #container { width: 1024px; margin: 0 auto; /* the auto margins (in conjunction with a width) center the page */ text-align: left; /* this overrides the text-align: center on the body element. */ } .oneColElsCtr #mainContent { padding: 0 0px; /* remember that padding is the space inside the div box and margin is the space outside the div box */ text-align: right; } .loginfail { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #3399cc; } .login { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #3399cc; padding-left: 100px; } .navbar { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #FFF; font-size: 16px; } .navbar:hover { font-family: Arial, Helvetica, sans-serif; text-decoration:underline; color: #FFF; font-size: 16px; } .login2 { font-family: Arial, Helvetica, sans-serif; font-size: 10px; text-decoration:none; color: #3399cc; } .window { font-family: Arial, Helvetica, sans-serif; font-size: 12px; text-decoration:none; } .login2:hover { font-family: Arial, Helvetica, sans-serif; font-size: 10px; text-decoration:underline; color: #3399cc; } .main { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #3399cc; } .main:hover { font-family: Arial, Helvetica, sans-serif; text-decoration:underline; color: #3399cc; } .form { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #3399cc; } .form:hover { font-family: Arial, Helvetica, sans-serif; text-decoration:underline; color: #3399cc; } .input { margin-left: 100px; background-color:#FFF; border: none; width: 14em; height: 1.2em; font-family: Arial, Helvetica, sans-serif; font-size: 22px; } .input2 { background-color: #F2F2F2; border: none; width: 14em; height: 1.2em; font-family: Arial, Helvetica, sans-serif; font-size: 22px; } .btn { height: 2em; width: 8em; color: #FFF; background: #3399cc; font-weight: bold; font-size: 18px; border: none; } .btn:hover { color: #FFF; background: #333; cursor: pointer; /* cursor: hand; for IE5 */ } .bottom { font-family: Arial, Helvetica, sans-serif; font-size: 12px; font-weight: bold; color: #7e8081; } .bottom2 { font-family: Arial, Helvetica, sans-serif; font-size: 12px; text-decoration: none; color: #7e8081; } .bottom2:hover { font-family: Arial, Helvetica, sans-serif; font-size: 12px; text-decoration: underline; color: #7e8081; } .bottom3 { font-family: Arial, Helvetica, sans-serif; font-size: 12px; text-decoration: none; color: #333; } .bottom3:hover { font-family: Arial, Helvetica, sans-serif; font-size: 12px; text-decoration: underline; color: #333; } div.hr { height: 1px; background: #CCC url(hr1.gif) no-repeat scroll center; } div.hr hr { display: none; } .home { font-family: Arial, Helvetica, sans-serif; text-decoration:none; color: #3399cc; } .form2 { font-family: Arial, Helvetica, sans-serif; text-decoration:none; font-size: 12px; } .rta {border-width: 1px; border-style: solid; border-color: #CCC; } .box { width: 100%; padding-right: 3px; color: #000; text-decoration:none; } .box:hover { width: 100%; padding-right: 3px; color: #000; text-decoration:underline;} .box2 { width: 100%; color: #C00; text-decoration:none; } .box2:hover { width: 100%; padding-right: 3px; color: #C00; text-decoration:underline;} thanking in you advance. God bless.

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  • Problem with SQL, ResultSet in java

    - by aphex
    How can I iterate ResultSet ? I've tried with the following code, but i get the error java.sql.SQLException: Illegal operation on empty result set. while ( !rs.isLast()) { rs.next(); int id = rs.getInt("person_id"); SQL.getInstance().getSt().execute("INSERT ref_person_pub(person_id) VALUES(" + id + ")"); }

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  • How should I go about creating a point system for users like SO and yahoo answers?(PHP)

    - by ggfan
    I am creating a voting system for a Q&A site project in which if a user asks a question, he/she losses -5 points; answer a question +5, vote a question +1, etc. (kind of like SO and yahoo answers) --To create the basic arithmetic, I have a "users_points" table that relates the user_id and their total points. +---+---------+ | 1 | 100 | +---+---------+ | 2 | 54 | +---+---------+ --Basically if the users does certain task, it would + or - the points. How do I prevent users from say voting an answer up 100 times. ex: I want a user to be only able to vote once per question, etc.

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  • ON DELETE RESTRICT Causing Error 150

    - by Levi Hackwith
    CREATE TABLE project ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), INDEX(name, created_at) ) ENGINE = INNODB; CREATE TABLE role ( id INTEGER NOT NULL, name VARCHAR(50) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE organization ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(100) NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE user ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, role_id INTEGER NOT NULL, organization_id INTEGER NOT NULL, last_login_at DATETIME NOT NULL, last_ip_address VARCHAR(25) NOT NULL, username VARCHAR(45) NOT NULL, password CHAR(32) NOT NULL, email_address VARCHAR(255) NOT NULL, first_name VARCHAR(45) NOT NULL, last_name VARCHAR(45) NOT NULL, address_1 VARCHAR(100) NOT NULL, address_2 VARCHAR(25) NULL, city VARCHAR(25) NOT NULL, state CHAR(2) NOT NULL, zip_code VARCHAR(10) NOT NULL, primary_phone_number VARCHAR(10) NOT NULL, secondary_phone_number VARCHAR(10) NOT NULL, is_primary_organization_contact TINYINT NOT NULL DEFAULT '0', is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), CONSTRAINT fk_user_role_id FOREIGN KEY (role_id) REFERENCES role (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_user_organization_id FOREIGN KEY (organization_id) REFERENCES organization (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE project_user ( user_id INTEGER NOT NULL, project_id INTEGER NOT NULL, PRIMARY KEY (user_id, project_id), CONSTRAINT fk_project_user_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE CASCADE, CONSTRAINT fk_project_user_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_category ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_type ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_status ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, project_id INTEGER NOT NULL, created_by INTEGER NOT NULL, submitted_by INTEGER NOT NULL, assigned_to INTEGER NULL, category_id INTEGER NOT NULL, type_id INTEGER NOT NULL, title VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, contact_type_id TINYINT NOT NULL, affects_all_clients TINYINT NOT NULL DEFAULT '0', is_billable TINYINT NOT NULL DEFAULT '1', esimated_hours DECIMAL(4, 1) NOT NULL DEFAULT '0', hours_worked DECIMAL (4, 1) NOT NULL DEFAULT '0', status_id TINYINT NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_created_by FOREIGN KEY (created_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_submitted_by FOREIGN KEY (submitted_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_assigned_to FOREIGN KEY (assigned_to) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_category_id FOREIGN KEY (category_id) REFERENCES ticket_category (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_type_id FOREIGN KEY (type_id) REFERENCES ticket_type (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_status_id FOREIGN KEY (status_id) REFERENCES ticket_status (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_time_entry ( id INTEGER NOT NULL AUTO_INCREMENT, user_id INTEGER NOT NULL, ticket_id INTEGER NOT NULL, started_at DATETIME NOT NULL, ended_at DATETIME NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_time_entry_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_time_entry_ticket_id FOREIGN KEY (ticket_id) REFERENCES ticket (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; The ticket table's create statement causes an error 150. I have no clue why. When I remove the ON DELETE RESTRICT statements from the table declaration, it works. Why is that?

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  • Linq for java

    - by Milhous
    Would a LINQ for java be a useful tool? I have been working on a tool that will allow a java object to map to a row in a database. Would this be useful for java programmers? What features would be useful?

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  • Case insensitive duplicates SQL

    - by hdx
    So I have a users table where the user.username has many duplicates like: username and Username and useRnAme john and John and jOhn That was a bug and these three records should have been only one. I'm trying to come up with a SQL query that lists all of these cases ordered by their creation date, so ideally the result should be something like this: username jan01 useRnAme jan02 Username jan03 john feb01 John feb02 jOhn feb03 Any suggestions will be much appreciated

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  • Symfony fk issue on insertion

    - by Daniel Hertz
    Hi, I posted a similar problem but it could not be resolved. I create a relational database of users and groups but for some reason I cannot insert test data with fixtures properly. Here is a sample of the schema: User: actAs: { Timestampable: ~ } columns: name: { type: string(255), notnull: true } email: { type: string(255), notnull: true, unique: true } nickname: { type: string(255), unique: true } password: { type: string(300), notnull: true } image: { type: string(255) } Group: actAs: { Timestampable: ~ } columns: name: { type: string(500), notnull: true } image: { type: string(255) } type: { type: string(255), notnull: true } created_by_id: { type: integer } relations: User: { onDelete: SET NULL, class: User, local: created_by_id, foreign: id, foreignAlias: groups_created } FanOf: actAs: { Timestampable: ~ } columns: user_id: { type: integer, primary: true } group_id: { type: integer, primary: true } relations: User: { onDelete: CASCADE, local: user_id, foreign: id, foreignAlias: fanhood } Group: { onDelete: CASCADE, local: group_id, foreign: id, foreignAlias: fanhood } And this is the data i try to input: User: user1: name: Danny email: [email protected] nickname: danny password: f05050400c5e586fa6629ef497be Group: group1: name: Mets type: sports FanOf: fans1: user_id: user1 group_id: group1 I keep getting this error: SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (`krowdd`.`fan_of`, CONSTRAINT `fan_of_user_id_user_id` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE CASCADE) The users and groups are clearly being created before the "fanhood" is so why am I getting this error?? Thanks!

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