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  • color objects in C or C ++ [closed]

    - by jazz
    Possible Duplicate: Colors in C language i copied a game from a book which name is paratrooper i ask this question again i also provide the code of the objects which i create there i want to change the color of these objects but i didn't understand how to do that so can any one plz help me how to do that.Listen guys they are not the standard functions but i use the graphics library for these functions and i can't find the function in the library file of graphics. i hope u understand know.this code will not run properly so plz tell me something about the function which color it i can't put the image other wize i show u the image it will make alot easieer #include "graphics.h" #include "stdio.h" #include "conio.h" #include "process.h" #include "alloc.h" #include "stdlib.h" #include "math.h" #include "dos.h" main() { int gm=CGAHI, gd=CGA, key=0, area; initgraph(&gd, &gm, "C:\\tc\\bgi"); helidraw(246,50,-1); getch(); return 0; } helidraw ( int x, int y, int d ) { int direction, i, j ; if ( d ) direction = -1 ; else direction = 1 ; i = 3 ; j = 8 ; line ( x - j - 8, y - i - 2, x + j + 8, y - i - 2 ) ; line ( x - j + 5, y - i - 1, x + j - 5, y - i - 1 ) ; line ( x - j, y - i, x + j, y - i ) ; for ( ; i > 0 ; i--, j += 2 ) { putpixel ( x - ( direction * j ), y - i, 1 ) ; line ( x + ( direction * j ), y - i, x + ( direction * ( j - 8 ) ), y - i ) ; } i = 0 ; j -= 2 ; line ( x - ( direction * j ), y - i, x - ( direction * ( j + 17 ) ), y - i ) ; line ( x - ( direction * j ), y - i + 1, x - ( direction * ( j + 7 ) ), y - i + 1 ) ; putpixel ( x - ( direction * ( j + 19 ) ), y - i - 1, 1 ) ; for ( ; i < 3 ; i++, j -= 2 ) { putpixel ( x - j, y + i, 1 ) ; putpixel ( x + j, y + i, 1 ) ; } line ( x - j, y + i, x + j, y + i ) ; putpixel ( x - j + 3, y + i + 1, 1 ) ; putpixel ( x + j - 3, y + i + 1, 1 ) ; line ( x - j - 10, y + i + 2, x + j + 10, y + i + 2 ) ; putpixel ( x + ( direction * ( j + 12 ) ), y + i + 1, 1 ) ; }

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  • add color style to value based on condition

    - by rod
    Hi All, How do I conditionally add the style 'color:red' to the .CurrentDifference if the value happens to be a negative value? Thanks, rod. <div class="sRow"> <div class="sLabel p40"> Difference: </div> <%= (!String.IsNullOrEmpty(Model.Amount)?Model.Amount.CurrentDifference.ToString("c"):string.Empty) %> </div>

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  • Non-Linear color interpolation?

    - by user146780
    If I have a straight line that mesures from 0 to 1, then I have colorA(255,0,0) at 0 on the line, then at 0.3 I have colorB(20,160,0) then at 1 on the line I have colorC(0,0,0). How could I find the color at 0.7? Thanks

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  • Changing background color on UIScrollView?

    - by Andreas Johannessen
    Hi How do I change the black/gray color to white? This is just a simple view with a UIView attached to the UIViewControllers property together a with a webview that fills the UIView. UPDATE Here's the code that works: - (void)loadView { UIWebView *webview = [[UIWebView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 320.0f, 416.0f)]; [webView setBackgroundColor:[UIColor whiteColor]]; self.view = webView; [webview release]; } Thanks in advance.

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  • Color scaling function

    - by Tomas Pajonk
    I am trying to visualize some values on a form. They range from 0 to 200 and I would like the ones around 0 be green and turn bright red as they go to 200. Basically the function should return color based on the value inputted. Any ideas ?

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  • iPhone, change color to each letter

    - by Paul
    It is possible to change a NSString color by letter? For example, if you have NSString *A=@"ASDFGH"; show in UILabel ASD with red and FGH with blue. And another question.. If I have a NSString, can I access the letter I want? For example, in NSString *A=@"ASDFGH"; how can I know what is the second letter which is S, or the third, which is D?

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  • Create a Color Picker, similar to Photoshop's, using Javascript and HTML Canvas

    - by André Alçada Padez
    I am not at all versed in Computer Graphics and am in need of creating a color picker as a javascript tool to embed in an HTML page. First, and looking at Photoshop's one, i thought of the RGB palette as a three-dimensional matrix. My first attempt envolved: <script type="text/javascript"> var rgCanvas = document.createElement('canvas'); rgCanvas.width = 256; rgCanvas.height = 256; rgCanvas.style.border = '3px solid black'; for (g = 0; g < 256; g++){ for (r = 0; r < 256; r++){ var context = rgCanvas.getContext('2d'); context.beginPath(); context.moveTo(r,g); context.strokeStyle = 'rgb(' + r + ', ' + g + ', 0)'; context.lineTo(r+1,g+1); context.stroke(); context.closePath(); } } var bCanvas = document.createElement('canvas'); bCanvas.width = 20; bCanvas.height = 256; bCanvas.style.border = '3px solid black'; for (b = 0; b < 256; b++){ var context = bCanvas.getContext('2d'); context.beginPath(); context.moveTo(0,b); context.strokeStyle = 'rgb(' + 0 + ', ' + 0 + ', ' + b + ')'; context.lineTo(20, b); context.stroke(); context.closePath(); } document.body.appendChild(rgCanvas); document.body.appendChild(bCanvas); </script> this results in something like My thought is this is too linear, comparing to the ones i see in Photoshop and on the web. I would like to know the logic behind the color mapping in a picker like this: I don't really need the algorythms itself, i'm mainly trying to understand the logic. Thanks

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  • How to color a treeview node in javascript

    - by hero
    i have a treeview and a texbox that allows a user to search for nodes inside the treeview. i already wrote the JS function that determines if a node exists in the treeview. what i want is to color the node that the user have searched for. how can i do this??

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  • MKMapView Pins Refreshing Color on Click

    - by Dave C
    Hello, I have several custom MKPinAnnotationView on my map with different images(colored pins). Everything works fine until I either click on a pin or change the map to a different view(satellite/road)... when I do either of these, my pins will revert back to the classic red color. Any help would be greatly appreciated.

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