Search Results

Search found 18753 results on 751 pages for 'form submission'.

Page 47/751 | < Previous Page | 43 44 45 46 47 48 49 50 51 52 53 54  | Next Page >

  • Drupal filter_form form input

    - by ernie
    This drupal form snippet will give me a textarea with user able to change filter to full html/wysiwyg mode. My Questions: How can I default to to full html mode? function MY_MODULE_admin() { $form = array(); $form['format'] = filter_form($form->format); // MY_MODULE - ** Image 1 ** $form['MY_MODULE_image_1'] = array( '#type' => 'textarea', '#title' => t('Image 1'), '#default_value' => variable_get('setup_image_1', 'image_1.jpg'), '#description' => "Current value =" .variable_get('setup_image_1', 'image_1.jpg'), '#required' => TRUE, );

    Read the article

  • post image and other data using mulipart form data in iphone

    - by abdulsamad
    Hi all I am sending some data and and an image to the server using multipart/form-data in objective C. kindly give me some Php code that how can i save the image on the server i am able to get the other variables on the server that i am passing with the image. kindly see my obj C code and php and tell me where i am wrong. your help will be highly appreciated. here i make the POST request. ////////////////////// NSString *stringBoundary, *contentType, *baseURLString, *urlString; NSData *imageData; NSURL *url; NSMutableURLRequest *urlRequest; NSMutableData *postBody; // Create POST request from message, imageData, username and password baseURLString = @"http://localhost:8888/Test.php"; urlString = [NSString stringWithFormat:@"%@", baseURLString]; url = [NSURL URLWithString:urlString]; urlRequest = [[[NSMutableURLRequest alloc] initWithURL:url] autorelease]; [urlRequest setHTTPMethod:@"POST"]; // Set the params NSString *path = [[NSBundle mainBundle] pathForResource:@"LibraryIcon" ofType:@"png"]; imageData = [[NSData alloc] initWithContentsOfFile:path]; // Setup POST body stringBoundary = [NSString stringWithString:@"0xKhTmLbOuNdArY"]; contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", stringBoundary]; [urlRequest addValue:contentType forHTTPHeaderField:@"Content-Type"]; // Setting up the POST request's multipart/form-data body postBody = [NSMutableData data]; [postBody appendData:[[NSString stringWithFormat:@"\r\n\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"source\"\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"lighttable"] dataUsingEncoding:NSUTF8StringEncoding]]; // So Light Table show up as source in Twitter post [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"title\"\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:book.title] dataUsingEncoding:NSUTF8StringEncoding]]; // title [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"isbn\"\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:book.isbn] dataUsingEncoding:NSUTF8StringEncoding]]; // isbn [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"price\"\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:txtPrice.text] dataUsingEncoding:NSUTF8StringEncoding]]; // Price [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"condition\"\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithString:txtCondition.text] dataUsingEncoding:NSUTF8StringEncoding]]; // Price NSString *imageFileName = [NSString stringWithFormat:@"photo.jpeg"]; [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"upload\"; filename=\"%@\"\r\n",imageFileName] dataUsingEncoding:NSUTF8StringEncoding]]; //[postBody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"upload\"\r\n\n\n"]dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:[@"Content-Type: image/jpeg\r\n\r\n" dataUsingEncoding:NSUTF8StringEncoding]]; [postBody appendData:imageData]; [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; // [postBody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", stringBoundary] dataUsingEncoding:NSUTF8StringEncoding]]; NSLog(@"postBody=%@", [[NSString alloc] initWithData:postBody encoding:NSASCIIStringEncoding]); [urlRequest setHTTPBody:postBody]; NSLog(@"Image data=%@",[[NSString alloc] initWithData:imageData encoding:NSASCIIStringEncoding]); // Spawn a new thread so the UI isn't blocked while we're uploading the image [NSThread detachNewThreadSelector:@selector(uploadingDataWithURLRequest:) toTarget:self withObject:urlRequest]; I the method uploadingDataWithURLRequest i post the request to the server... Here is my php Code ?php $title = $_POST['title']; $isbn = $_POST['isbn']; $price = $_POST['price']; $condition = $_POST['condition']; $image=$_FILES['image']['name']; if($image) { $filename = 'newimage.jpeg'; file_put_contents($filename, $image); echo "image is there"; } else { echo "image is nil"; } ?> I am unable to get the image on server kindly help me where i am wrong.

    Read the article

  • How to add css to form elements if attribute class is already being used in Jquery

    - by Gublooo
    Hey guys This is probably a dumb question - I'm using Jquery to validate the form. So the form elements have the class="required" attribute. input type="text" name="last_name" class="required"/ Now if i want to apply some css properties to the input fields of this form - how do I do that. I do not want to declare a general css for all input elements - I have declared the css as follows: input.form { color: #000; background: #fff; border: 2px solid #E1E1E1; font-size: 16pt; width:150px; } And I want to use it this way input class="form" type="text" name="last_name" class="required"/ But this wont work as there are two class attributes here. So how do I handle this. Thanks

    Read the article

  • Close box triggers validation for non-modal form

    - by Governor
    I have two form classes inheriting from a common base. One of the forms is called modally and the other non-modally. Validation is required on focus changes but not when the form is cancelled. When the Close Box is selected on the modal form it closes properly without any validation being triggered on it's controls. When the Close Box is selected on the non-modal form, validation events are triggered. A Cancel button with CausesValidation set false works fine in both cases. I have tried setting CausesValidation on the non-modal form to false but the problem remains. I should mention that the forms are mdi children. Any ideas? Thx.

    Read the article

  • Can't seem to get Prototype AJAX form validation to work in conjunction with Codeigniter

    - by MattB
    Is there some kind of trick involved? Here's how I would envision it working: 1) User tries submitting the form 2) Event.observe captures this and sends an AJAX request to a special validation URL (PHP using Codeigniter) 3) If no errors were returned, continue submitting the original form 4) If errors were found, cancel form submission and display Mostly, I can't seem to get a separate AJAX validation request to work as the form continues submitting. I could use Event.stop(event), but have not found a way to re-start the process if no validation errors exist from the validation call. I'd post code, but I have about 15 examples of things I've tried and it would just clutter this question. Any ideas? :-( I didn't think form validation would be this difficult. Many thanks, - Matt

    Read the article

  • How to override form just on one page?

    - by user363036
    OK so this is my hook form alter function.It is causing all the registration forms on site to be over written which I do not want as I just want it on this page. function special_registration_form_alter(&$form, $form_state, $form_id) { if ($form_id == 'user_register') { drupal_set_title(t('Custom registration')); $form['firstname'] = array('#type' = 'textfield', '#title' = t('First Name: *'), '#required' = TRUE, '#size' = 45, '#weight' = - 100,); $form['lastname'] = array('#type' = 'textfield', '#title' = t('Last Name: *'), '#required' = TRUE, '#size' = 45, '#weight' = - 99,); } I only first name and last name to be captured and stored in a different table just on this page. On other pages I just want the good old fashioned form. Do I still need to change the weight? I know I am missing something elementary.

    Read the article

  • Add CSS to Form Type is Symfony2

    - by Umair Iqbal
    I have an edit form, The form is made through symfony2 Form types. I checked the documentation but couldn't find any option for adding CSS to the form. The form display the data correctly and everything is fine what I want to do is to add styling to each field. My Edit Type is public function buildForm(FormBuilder $builder, array $options) { $builder ->add('id', 'hidden') ->add('patent_name', 'text', array('label' => 'Patent Name')) ->add('description', 'textarea', array('label' => 'Description', 'required' => false)) ->add('appln_auth','text', array('label' => 'Application Authorization')) ; } Anyone has any idea ho I can add css ? Thanks

    Read the article

  • Apache HttpClient making multipart form post

    - by Russ
    I'm pretty green to HttpClient and I'm finding the lack of (and or blatantly incorrect) documentation extremely frustrating. I'm trying to implement the following post (listed below) with Apache Http Client, but have no idea how to actually do it. I'm going to bury myself in documentation for the next week, but perhaps more experienced HttpClient coders could get me an answer sooner. Post: Content-Type: multipart/form-data; boundary=---------------------------1294919323195 Content-Length: 502 -----------------------------1294919323195 Content-Disposition: form-data; name="number" 5555555555 -----------------------------1294919323195 Content-Disposition: form-data; name="clip" rickroll -----------------------------1294919323195 Content-Disposition: form-data; name="upload_file"; filename="" Content-Type: application/octet-stream -----------------------------1294919323195 Content-Disposition: form-data; name="tos" agree -----------------------------1294919323195--

    Read the article

  • jQuery Ajax form submit, to call php login script

    - by Stevie Jenowski
    Thanks for checking out my problem... I'm having trouble submitting a login form via Ajax for a php script to run and return a new set of html items which will be replacing the HTML in #userlinks.... heres what I have so far $("#login_form").submit(function() { return false; }); $('#login_button').click(function(event) { $form = $(this).parent("form"); $.post($form.attr("action"), $form.serialize(), function(data){ $('#userlinks').html(data); }); }); The php script checks for post data of username && password, yet all I'm getting is a page refresh and no changes. Nothing returns unless I turn login_button into a link and change the script a bit... Any help would be appreciated!

    Read the article

  • button in the form cause it be submitted automatically

    - by Spiderman
    has the HTML version changed lately (like from ie7 to IE8?) I notice the following change that cause me some troulbe - I am having a code that is similar to this: <form method="POST" action="/admin/modify"> <input type="text"/> <button onclick="dosomething()">Press</button> </form> <script type="text/javascript"> function doSomething(){ // doesn't matter what actually } </script> What is weired to me in this code is that by pressing the button inside the form, all I want is to perform some javascript action but eventaully it causes the form to be submitted too, even when I am not willing to do it. So - is it true? and if so how can I perform some java script actoin inside a from but prevent the form from being submitted automatically?

    Read the article

  • Problem Passing Variable to Submit Form in Firefox

    - by George
    In the following example, I have a link that sends a variable to a function which checks if the variable is true and, if so, submits a form on the page. This has been tested and works in IE, Safari, and Chrome, but not Firefox. Trying to figure out what's wrong in Firefox. The function which checks 'action' and then submits form 'login' : function submit(action) { if (action == "submit") { document.login.submit(); } } Link to pass action variable and submit form: <a href="javascript:submit('submit');">SEND FORM</a> When I remove the check and just have the following, it works fine in Firefox: function submit() { document.login.submit(); } <a href="javascript:submit();">SEND FORM</a>

    Read the article

  • How can I access form elements when using an ASP.NET MVC Ajax form?

    - by Patrick
    I've got an ajax form in an MVC 2 application. I cannot find the proper way to access the form elements within the Ajax form decleration. I can access the name of the elements with Request.Form.Keys but I can't access the actual values. I've read numerous examples of posting forms with jQuery but my form has elements created dynamically based on route values (sometimes it could be 2 text boxes sometimes 10, given unique names like so: <%= Html.TextBox("Evaluation"+Model.EvaluationId.ToString())) so I couldn't find a way to make that work with jQuery. Is there another way that I for elements can be accessed?

    Read the article

  • Method of getting text on a windows form ( unmanaged C++ project )

    - by Donovan
    I'm in the process of learning C++. I've created a boilerplate Win32 app within VC++ 2008. I've studied through the code and am ready do do a bit of experimenting. I thought it would be cool to print all the windows messages received in the message loop to the form created via the boilerplate code. I for the life of me, can't figure out the method of getting text onto that form. I can't seem to identify and named object that I can use to reference that damn form. The best I can figure is I need to use the handle to reference the form somehow. Still, even if I did know how to reference the form, I'm not sure I know how I would create a label to display the text. Anyway, if someone could just point out what methodology I need to learn to make this happen it would be much appreciated. Thanks, Donovan

    Read the article

  • How can ishow Form in process1 from Form in process2 ?

    - by Al0NE
    Hi I'm trying to show hidden form in process1 from another one was called by : Process.Start(@"F:\MyOtherFormPath\MyOtherForm.exe",this.Handle.ToInt32()); As you can see i passed the handle number of the hidden form ,which i'm calling the "MyOtherForm" from, and i used this number to get a handle and show the hidden form from my "MyOtherForm" like this : Form newFrm = Form.FromHandle(new IntPtr(long.Parse(handleNumberOfMyHiddenForm))); newFrm.show(); But it didn't work, any way to do this . P.S: it didn't throw any exception . thanx in advanced ..

    Read the article

  • vb.net add text to form without interaction

    - by user228058
    I have a winform project which lists all the files in a specified folder. It allows the user to select a new destination for each file, and when the user has chosen the destinations for all files that he would like to be moved, it moves the files, one by one. My next step is, I need to display a confirm form when the files are being moved, and add each file's name and destination to the confirm form as it is being moved. My question is: How can I add more text to the confirm form's controls after I already loaded it (using confirm.showdialog() from my other form, without any user interaction? I imagine that I need to do it from the original form, because it needs to display each one when it starts to move that file, but I'm open to any suggestions:) TIA

    Read the article

  • Submitting a form from Email

    - by bubbl
    I was working on a project to submit a form from an email. The scenario is this. We will send a form to list of emails where in the customer has to fill in the form and once they hit submit, the form should be submitted and server should be able to retrieve the values that is provided by the person filling in.When i tried, it was not considering the submit button as form submit and no action is being performed. Can anyone help me to resolve this. Thanks in advance.

    Read the article

  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

    Read the article

  • Theming Drupal Add Block form via forms API.

    - by hfidgen
    Hiya, Can anyone advise me on customising the Add Block form? (/admin/build/block/add) I want to hide the "User specific visibility settings" and "Role specific visibility settings" from users. This is what i've got so far, but obviously it's not right and I can't figure out what the array is. Anyone got the experience on this? function theme_add_block_form($form) { $form['roles']['#prefix'] = '<div class="hidden">'; $form['roles']['#suffix'] = '</div>'; return drupal_render($form); } Thanks, H

    Read the article

  • aggregate form elements into object ? [Solved]

    - by Mahmoud
    hey all i am trying to aggregate form elements into object and then send it via ajax here is the code that i start using but i cant figure out how to do the rest $('.jcart').live('submit', function() { }); Update 1: html form http://pasite.org/code/572 Update 2: I have successfully submit the form using ajax but it still refreshes the page after submiting this what i did function adding(form){ $( "form.jcart" ).livequery('submit', function() {var b=$(this).find('input[name=<?php echo $jcart['item_id']?>]').val();var c=$(this).find('input[name=<?php echo $jcart['item_price']?>]').val();var d=$(this).find('input[name=<?php echo $jcart['item_name']?>]').val();var e=$(this).find('input[name=<?php echo $jcart['item_qty']?>]').val();var f=$(this).find('input[name=<?php echo $jcart['item_add']?>]').val();$.post('<?php echo $jcart['path'];?>jcart-relay.php',{"<?php echo $jcart['item_id']?>":b,"<?php echo $jcart['item_price']?>":c,"<?php echo $jcart['item_name']?>":d,"<?php echo $jcart['item_qty']?>":e,"<?php echo $jcart['item_add']?>":f} }); return false; }

    Read the article

  • c# passing something from child form to parent

    - by Alan Bennett
    hi guys. so i have this form and on it is a combo box populated from a database via a SQL method. and i have another form which allows us to maintain the database table etc. so i make a new instance of the second form doing: Form1 frm = new Form2; frm.show(); once i have done what ever i wanted to do on the second form and i close it, i need to somehow trigger an event or something which will refresh the combo box and the code behind it. i was thinking of some onchange or focus event for the whole form, the problem is i have 5 of these combo boxes and running all the SQL again. i also thought of passing somesort of variable thro but then i would still need an event for that. any ideals would be awesome

    Read the article

  • passing something from child form to parent

    - by Alan Bennett
    so i have this form and on it is a combo box populated from a database via a SQL method. and i have another form which allows us to maintain the database table etc. so i make a new instance of the second form doing: Form1 frm = new Form2; frm.show(); once i have done what ever i wanted to do on the second form and i close it, i need to somehow trigger an event or something which will refresh the combo box and the code behind it. i was thinking of some onchange or focus event for the whole form, the problem is i have 5 of these combo boxes and running all the SQL again. i also thought of passing somesort of variable thro but then i would still need an event for that. any ideals would be awesome

    Read the article

  • jQuery.Form wont submit

    - by kim
    Im´trying to submit a form without refreshing the page, but I´m having a problem. When I click submit the page refreshes and anothing gets posted. Here is the code, what am I doing wrong? (I´m a newbie) jQuery 1.4.2 and the jQuery Form Plugin 2.43 is present. tnx $(document).ready(function() { var options = { target: '#output2', url: https://graph.facebook.com/<%=fbUid%>/feed, type: post, clearForm: true // clear all form fields after successful submit //dataType: null // 'xml', 'script', or 'json' (expected server response type) //resetForm: true // reset the form after successful submit // $.ajax options can be used here too, for example: //timeout: 3000 }; // bind to the form's submit event $('#fbPostStatus').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit(options); // !!! Important !!! // always return false to prevent standard browser submit and page navigation return false; }); });

    Read the article

  • Setting a form field's value during validation

    - by LaundroMat
    I read about this issue already, but I'm having trouble understanding why I can't change the value of a form's field during validation. I have a form where a user can enter a decimal value. This value has to be higher than the initial value of the item the user is changing. During clean(), the value that was entered is checked against the item's previous value. I would like to be able to re-set the form field's value to the item's initial value when a user enters a lower value. Is this possible from within the clean() method, or am I forced to do this in the view? Somehow, it doesn't feel right to do this in the view... (To make matters more complicated, the form's fields are built up dynamically, meaning I have to override the form's clean() method instead of using the clean_() method).

    Read the article

  • Login form to an a secured app in tomcat

    - by patricio
    I have a normal HTML page in a normal Apache http server (http://yyy.yyy.yyy.yyy/index.html ), with an authentication form, with that form I need to access with the credentials to an application located in other server with diferent IP , that server have a secured application with tomcat: here is the login form in the apache http server: <form method="POST" id="theForm" action="http://xxx.xxx.xxx.xxx:8080/securedapp/j_security_check"> <input name="j_username" type="text" class="tx_form" id="j_username" size="20" /> <input name="j_password" type="password" class="tx_form" id="textfield2" size="20" /> <input name="btn" type="submit" value="login" /> </form> the submit only works random in chrome and dont work in IE and FF. im doing something wrong?

    Read the article

  • Form variable does not refresh with ajax call

    - by ChrisOPeterson
    I'm building a simple email sending form and wanted to make it with ajax. The form submits correctly the first time but if you make any subsequent changes to the text in the form and then submit again then jquery does not pick up on the changes and posts the old data. Whats going on? <script type="text/javascript"> var $j = jQuery.noConflict(); $j(document).ready(function() { var submit_url = "mail_submit.php"; var send_email = $j("#sendemail"); send_email.click(function() { var form = $j("#post"); $j.post(submit_url, form.serialize(), function(data) { alert(data); }); }); });

    Read the article

< Previous Page | 43 44 45 46 47 48 49 50 51 52 53 54  | Next Page >