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  • Simple way to encode a string according to a password?

    - by RexE
    Does Python have a built-in, simple way of encoding/decoding strings using a password? Something like this: >>> encode('John Doe', password = 'mypass') 'sjkl28cn2sx0' >>> decode('sjkl28cn2sx0', password = 'mypass') 'John Doe' I would like to use these encrypted strings as URL parameters. My goal is obfuscation, not strong security. I realize I could use a database table to store keys and values, but am trying to be minimalist.

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  • Apache Rewrite - put parts of query string in replacement string

    - by Rangi Robinson
    Hello, I'd like to rewrite: www.example.com/file.html?username=john&number=1234 To: www.example.com/users/john But I can't figure out how to extract the "username" value from the query string. I've been Googling this all morning and reading the official docs but no luck. I need to solve this problem with a rewrite, rather than changing the application. Any help much appreciated! Rangi

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  • Minimalist, Tiny Javascript Template System?

    - by Parand
    I'm looking for a minimalist template system for javascript, ala John Resig's Javascript Micro Templating. The smaller the better, and if it's jquery based even better. Recommendations? I tried John's micro-templating but ran into a few issues, wanted to see if there are more baked / better packaged solutions out there. [Update] I tried Resig's Micro Templating again and it's working well for me. Would still like to hear about other alternatives if there are any.

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  • Any Name Entity Recognition - web services available

    - by Gublooo
    Hello I wanted to know if there are any paid or free named entity recognition web services available. Basically I'm looking for something - where if I pass a text like: "John had french fries at Burger King" It should be identify - something along the lines: Person: John Organization: Burger King I've heard of Annie from GATE - but I dont think it has a web service available. Thanks

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  • Having to hit the site login button twice after first turning on computer

    - by John
    Hello, The code below is for a login that I'm using. It works fine, but when I first try logging in after turning on my computer, it only works the second time that I hit the "Login" button. Any idea how I can make it not require hitting the "Login" button twice in this situation? Thanks in advance, John function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } EDIT: Here is another function that is used. function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; }

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  • Positioning Text Triggered by a Function

    - by John
    Hello, I would like the text below classed with "logintocomment" to appear 30 px below the bottom of the table classed with "commentecho." Instead, with the CSS and code below, the text classed with "logintocomment" is appearing at the bottom of the browser window. Any idea how I can make it do what I want? Thanks in advance, John In index file: include "comments.php"; include "commentformonoff.php"; In the file comments.php: echo "<table class=\"commentecho\">"; The file: commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { echo "<div class='logintocomment'>Login to comment</div>"; } } else { show_commentbox($submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl); } ?> The CSS: table.commentecho { margin-top: 230px; margin-left: 30px; text-align: left; font-family: "Times New Roman", Times, serif; font-weight: normal; font-size: 15px; color: #000000; width: 600px; table-layout:fixed; background-color: #FFFFFF; border: 2px #FFFFFF; border-collapse: collapse; border-spacing: 2px; padding: 1px; text-decoration: none; vertical-align: text-bottom; margin-bottom: 30px; } table.commentecho td { border: 2px solid #fff; text-align: left; height: 18px; overflow:hidden; } table.commentecho td a{ padding: 2px; color: #000000; text-decoration: none; overflow:hidden; height: 18px; } table.commentecho td a:hover{ background-color: #FFFFFF; padding: 2px; color: #FF0000; text-decoration: none; overflow:hidden; height: 18px; } .logintocomment { margin-top: 30px; margin-left: 30px; width:250px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 20px; color:#000000; }

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  • How to find index of an object by key and value in an javascript array

    - by return1.at
    Given: var peoples = [ { "attr1": "bob", "attr2": "pizza" }, { "attr1": "john", "attr2": "sushi" }, { "attr1": "larry", "attr2": "hummus" } ]; Wanted: Index of object where attr === value for example attr1 === "john" or attr2 === "hummus" Update: Please, read my question carefully, i do not want to find the object via $.inArray nor i want to get the value of a specific object attribute. Please consider this for your answers. Thanks!

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  • Need help with SQL Query

    - by StackOverflowNewbie
    Say I have 2 tables: Person - Id - Name PersonAttribute - Id - PersonId - Name - Value Further, let's say that each person had 2 attributes (say, gender and age). A sample record would be like this: Person->Id = 1 Person->Name = 'John Doe' PersonAttribute->Id = 1 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Gender' PersonAttribute->Value = 'Male' PersonAttribute->Id = 2 PersonAttribute->PersonId = 1 PersonAttribute->Name = 'Age' PersonAttribute->Value = '30' Question: how do I query this such that I get a result like this: 'John Doe', 'Male', '30'

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  • Get list of duplicate rows in MySql

    - by user347033
    Hi, i have a table like this ID nachname vorname 1 john doe 2 john doe 3 jim doe 4 Michael Knight I need a query that will return all the fields (select *) from the records that have the same nachname and vorname (in this case, records 1 and 2). Can anyone help me with this? Thanks

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  • Can Ejabberd Support Offline File Transfer?

    - by user359277
    Hi, I am working on a xmpp client, using eJabberd as server. My question is How can I support offline file transferring? I only want to do the offline file transferring for Image file. For example, I can transfer an image to John even he is offline. When John come back Online, the server will send him the image. How can I do that? Thanks

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  • Using GET Method to Maintain Variables After Logging In

    - by John
    Hello, I am using a login system. When I navigate to comments/index.php without logging in, some variables get passed along using the GET method just fine. Then, if I log in while I am on this page, these variables disappear. The variables that disappear are $submission, $submissionid, and $url. I thought I could use the GET method to keep them live after logging in by appending ?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.' to the URL of the login form action as seen below. But the variables still disappeared after I made this addition. The relevant code I am trying to use is below. Any idea what I can do to make it do what I want? Thanks in advance, John In comments/index.php: require_once "header.php"; include "login.php"; include "comments.php"; In login.php: if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } In comments.php: $url = mysql_real_escape_string($_GET['url']); echo '<div class="subcommenttitle"><a href="http://www.'.$url.'">'.$submission.'</a></div>'; $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); The login function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?submission='.$submission.'&submissionid='.$submissionid.'&url='.$url.'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Passing Variables Along in a Function

    - by John
    Hello, In the function show_commentbox() below, I would like to pass along the variables $_SESSION['loginid'], $submissionid, $submission, $url, $submittor, $submissiondate, $countcomments, $dispurl. With the setup below, it's not working. How could I change it to make show_commentbox() pass the variables along? Thanks in advance, John index.php: <?php $submission = $_GET['submission']; require_once "header.php"; include "login.php"; include "comments.php"; include "commentformonoff.php"; ?> In header.php: require_once ("function.inc.php"); In comments.php: $uid = $_SESSION['loginid']; $submissiondate = mysql_real_escape_string($_GET['submissiondate']); $submittor = mysql_real_escape_string($_GET['submittor']); $countcomments = mysql_real_escape_string($_GET['countcomments']); $dispurl = mysql_real_escape_string($_GET['dispurl']); $url = mysql_real_escape_string($_GET['url']); $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); commentformonoff.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_commentbox(); } else { echo "Login to comment"; } } else { echo "Login to comment"; } } else { show_commentbox(); } ?> In display.functions.inc.php: function show_commentbox() { echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; }

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  • Converting OpenGL co-ordinates to lower UIView (and UIImagePickerController)

    - by John Qualis
    Hi, I am new to OpenGL over iPhone. I am developing an iPhone app similar to a barcode reader but with an extra OpenGL layer. The bottommost layer is UIImagePickerController, then I use UIView on top and draw a rectangle at certain co-ordinates on the iphone screen. So far everything is OK. Then I am trying to draw an OpenGL 3-D model in that rectangle. I am able to load a 3-D model in the iPhone based on this code here - http://iphonedevelopment.blogspot.com/2008/12/start-of-wavefront-obj-file-loader.html I am not able to transform the co-ordinates of the rectangle into OpenGL co-ordinates. Appreciate any help. Do I need to use a matrix to translate the currentPosition of the 3-D model so it is drawn within myRect? The code is given below.. Appreciate any help/pointers in this regards. John -(void)setupView:(GLView*)view { const GLfloat zNear = 0.01, zFar = 1000.0, fieldOfView = 45.0; GLfloat size; glEnable(GL_DEPTH_TEST); glMatrixMode(GL_PROJECTION); size = zNear * tanf(DEGREES_TO_RADIANS(fieldOfView) / 2.0); CGRect rect = view.bounds; glFrustumf(-size, size, -size / (rect.size.width / rect.size.height), size / (rect.size.width / rect.size.height), zNear, zFar); glViewport(0, 0, rect.size.width, rect.size.height); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glClearColor(0.0f, 0.0f, 0.0f, 0.0f); NSString *path = [[NSBundle mainBundle] pathForResource:@"plane" ofType:@"obj"]; OpenGLWaveFrontObject *theObject = [[OpenGLWaveFrontObject alloc] initWithPath:path]; Vertex3D position; position.z = -8.0; position.y = 3.0; position.x = 2.0; theObject.currentPosition = position; self.plane = theObject; [theObject release]; } (void)drawView:(GLView*)view; { static GLfloat rotation = 0.0; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glLoadIdentity(); glColor4f(0.0, 0.5, 1.0, 1.0); // the coordinates of the rectangle are // myRect.x, myRect.y, myRect.width, myRect.height // Do I need to use a matrix to translate the currentPosition of the // 3-D model so it is drawn within myRect? //glOrthof(-160.0f, 160.0f, -240.0f, 240.0f, -1.0f, 1.0f); [plane drawSelf]; }

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  • Document-oriented database - What if the document definitions change?

    - by Sebastian Hoitz
    As I understand it, you can enter any non-structured information into a document-oriented database. Let's imagine a document like this: { name: 'John Blank', yearOfBirth: 1960 } Later, in a new version, this structure is refactored to { firstname: 'John', lastname: 'Blank', yearOfBirth: 1960 } How do you do this with Document-Oriented databases? Do you have to prepare merge-scripts, that alter all your entries in the database? Or are there better ways you can handle changes in the structure?

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  • How to order by last name on a full name column?

    - by GateKiller
    I have a SQL Table with a column called FullName which contains, for example, "John Smith". How can order the data by the last name that appears in the FullName column? For a long name like "Laurence John Fishburne", I would like to order the data by the word "Fishburne". Thus, names are stored in the order First Name Middle Names Last Name I am using Microsoft SQL Server 2005.

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  • Making a Login Work After Cache, Cookies, etc. Have Been Cleared

    - by John
    Hello, I am using the code below for a user login. The first I try to login after cache / cookies, etc. have been cleared, the browser refreshes and the user name is not logged in. After that, logging in works fine. Any idea how I can make it work the first time? Thanks in advance, John index.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../index.php?username='.$username.'&password='.$password.'');} require_once "header.php"; include "login.php"; require_once "footer.php"; ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?> show_loginform function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?'.$_SERVER['QUERY_STRING'].'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/.../register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/.../lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • Simplest way to print an array in Java

    - by Alex Spurling
    What's the simplest way of printing an array of primitives or of objects in Java? Here are some example inputs and outputs: int[] intArray = new int[] {1, 2, 3, 4, 5}; //output: [1, 2, 3, 4, 5] String[] strArray = new String[] {"John", "Mary", "Bob"}; //output: [John, Mary, Bob]

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  • Arrays of Objects: For each element in array 1, does an object value exist as a value in any of the objects in array 2

    - by DevOtts
    I have two arrays which contain objects in each element of the array. var array1 = [{firstName: "John", lastName: "McDonald"}, {firstName: "Sandy", lastName: "Johnson"},....,] var array2 = [{userName: "Donald"}, {userName: "John"},....,] In psuedo-code, I want to do the following: for each element in array1, is array1[i].firstName == to any of the userName's in array2. In plain english I want to look at each firstname in array1 and see if it exists at all in array2 as the value associated with the userName property.

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • Variable name as a string in Javascript

    - by fish potato
    Is there a way to get a variable name as a string in Javascript? (like NSStringFromSelector in Cocoa) I would like to do like this: var myFirstName = 'John'; alert(variablesName(myFirstName) + ":" + myFirstName); --> myFirstName:John -- added I'm trying to connect a browser and another program using JavaScript. I would like to send instance names from a browser to another program for callback method.

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  • printing dynamically string in one line in python

    - by EngHamoud
    I'm trying to print strings in one line. I've found solutions but they don't works with windows correctly. I have text file contains names and I want to print them like this name=john then change john to next name and keep name=, I've made this code but didn't work correctly with windows: op = open('names.txt','r') print 'name=', for i in op.readlines(): print '\r'+i.strip('\n') thank you for your time

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  • Add custom method to string object [closed]

    - by cru3l
    Possible Duplicate: Can I add custom methods/attributes to built-in Python types? In Ruby you can override any built-in object class with custom method, like this: class String def sayHello return self+" is saying hello!" end end puts 'JOHN'.downcase.sayHello # >>> 'john is saying hello!' How can i do that in python? Is there a normally way or just hacks?

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