C++ difference between "char *" and "char * = new char[]"
- by nashmaniac
So, if I want to declare an array of characters I can go this way
char a[2];
char * a ;
char * a = new char[2];
Ignoring the first declaration, the other two use pointers. As far as I know the third declaration is stored in heap and is freed using the delete operator . does the second declaration also hold the array in heap ? Does it mean that…
