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• sorting two tables (full join)

  - by Ruslan

  i'm joining tables like: select * from tableA a full join tableB b on a.id = b.id But the output should be: row without null fields row with null fields in tableB row with null fields in tableA Like: a.id a.name b.id b.name 5 Peter 5 Jones 2 Steven 2 Pareker 6 Paul null null 4 Ivan null null null null 1 Smith null null 3 Parker

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• Source for Names to use in web scraping

  - by PyNEwbie

  Can anyone suggest a good source of names that I can use to help analyze some tables on web pages. The first column of the tables I am scraping have names alone, names and titles or just titles. The names can be as varied as John Smith to Vikram Saksena. I have been poking around for a compiled list of words that can be found in proper names.

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• Clarification How CRF(Conditional random Field) works using examples

  - by Moges.A

  I read different documents how CRF(conditional random field) works but all the papers puts the formula only. Is there any one who can send me a paper that describes about CRF with examples like if we have a sentence "Mr.Smith was born in New York. He has been working for the last 20 years in Microsoft company." if the above sentence is given as an input to train, how does the Model works during the training taking in to consideration for the formula for CRF? Moges.A

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• Capitalization of Person names in programming

  - by Albert

  Hey all, Is anyone aware of some code/rules on how to capitalize the names of people correctly? John Smith Johan van Rensburg Derrick von Gogh Ruby de La Fuente Peter Maclaurin Garry McDonald (these may not be correct, just some sample names and how the capitalization could be/work) This seems like a losing battle... If anyone has some code or rules on when and how to capitalize names, let me know :) Cheers, Albert

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• Convert javascript string to an array

  - by dev.e.loper

  I'm retrieving an array of objects from a hidden html input field. The string I'm getting is: "{"id":"1234","name":"john smith","email":"[email protected]"},{"id":"4431","name":"marry doe","email":"[email protected]"}" Now I need to pass this as an array of objects again. How do I convert this string into array of objects?

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• When to address managed heap fragmentation

  - by emddudley

  I was reading a blog entry by Josh Smith where he used a cache mechanism in order to "reduce managed heap fragmentation". His caching reduces the number of short-lived objects being created at the cost of slightly slower execution speed. How much of a problem is managed heap fragmentation in a managed language like C#? How can you diagnose if it's an issue? In what situations would you typically need to address it?

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• Convert javascript string to a literal

  - by dev.e.loper

  I'm retrieving an array of objects from a hidden html input field. The string I'm getting is: "{"id":"1234","name":"john smith","email":"[email protected]"},{"id":"4431","name":"marry doe","email":"[email protected]"}" Now I need to pass this as an array of objects again. How do I convert this string into array of objects?

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• In MVVM should the ViewModel or Model implement INotifyPropertyChanged?

  - by Edward Tanguay

  Most MVVM examples I have worked through have had the Model implement INotifyPropertyChanged, but in Josh Smith's CommandSink example the ViewModel implements INotifyPropertyChanged. I'm still cognitively putting together the MVVM concepts, so I don't know if: you have to put the INotifyPropertyChanged in the ViewModel to get CommandSink to work this is just an aberration of the norm and it doesn't really matter you should always have the Model implement INotifyPropertyChanged and this is just a mistake which would be corrected if this were developed from a code example to an application What have been others' experiences on MVVM projects you have worked on?

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• Instantiating multiple beans of the same class with Spring annotations

  - by Francois

  With an XML configured Spring bean factory, I can easily instantiate multiple instances of the same class with different parameters. How can I do the same with annotations? I would like something like this: @Component(firstName=”joe”, lastName=”smith) @Component(firstName=”mary”, lastName=”Williams”) public class Person { /* blah blah */ }

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• What's the right way to display a DBIx::Class ResultSet in my Catalyst project that uses Template To

  - by Thelema

  Given a DBIx::Class resultset, for example: my $rs = $c->model("DB::Card")->search({family_name => "Smith"}); the tutorials I've read use the stash to pass an arrayref of rows: $c->stash->{cards} = [$rs->all]; This results in the query getting executed at this point, and the resulting objects stuffed into the stash, so they can be used in TemplateToolkit as: [% FOREACH card IN cards %] [% card.given_name %] [% card.family_name %] [%END%] Is there a proper way to have TT iterate over the rows as they get fetched from the DB?

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• How is this plugin designed to crash IE6, crashing IE6?

  - by jjclarkson

  Chad Smith came out with a jQuery plugin designed to crash the IE6 browser. ;jQuery.crash=function(x){for(x in document.open);}; What is this doing exactly to cause the problem?

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• Receiving a JSON string & saving one of the array paramaters to the database as a full string

  - by ElTren

  Hi I have a JSON string that looks like this (Usingt Rails and a REST service) { person: { name:"Pepe", last:"Smith" hats:[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] } } I want to be able to able to get that JSON, and save the Person to the database, but I want to save the "hats".. as a string to the database; without parsing it or anything like that i.e. I want to save this to SQL: hats = "[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] }" Is there a way to do this in rails?

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• dbms_xmlschema fail to validate with complexType

  - by Andrew

  Preface: This works on one Oracle 11gR1 (Solaris 64) database and not on a second and we can't figure out the difference between the two databases. Somehow the complexType causes the validation to fail with this error: ORA-31154: invalid XML document ORA-19202: Error occurred in XML processing LSX-00200: element "shiporder" not empty ORA-06512: at "SYS.XMLTYPE", line 354 ORA-06512: at line 13 But the schema is valid (passes this online test: http://www.xmlme.com/Validator.aspx) -- Cleanup any existing schema begin dbms_xmlschema.deleteschema('shiporder.xsd',dbms_xmlschema.DELETE_CASCADE); end; -- Define the problem schema (adapted from http://www.w3schools.com/schema/schema_example.asp) begin dbms_xmlschema.registerSchema('shiporder.xsd','<?xml version="1.0" encoding="ISO-8859-1" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="shiporder"> <xs:complexType> <xs:sequence> <xs:element name="orderperson" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> </xs:schema>',owner=>'SCOTT'); end; -- Attempt to validate declare bbb xmltype; begin bbb := XMLType('<?xml version="1.0" encoding="ISO-8859-1"?> <shiporder xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="shiporder.xsd"> <orderperson>John Smith</orderperson> </shiporder>'); XMLType.schemaValidate(bbb); end; Now if I gut the schema definition and leave only a string in the XML then the validation passes: begin dbms_xmlschema.deleteschema('shiporder.xsd',dbms_xmlschema.DELETE_CASCADE); end; begin dbms_xmlschema.registerSchema('shiporder.xsd','<?xml version="1.0" encoding="ISO-8859-1" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="shiporder" type="xs:string"/> </xs:schema>',owner=>'SCOTT'); end; DECLARE xml XMLTYPE; BEGIN xml := XMLTYPE('<?xml version="1.0" encoding="ISO-8859-1"?> <shiporder xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="shiporder.xsd"> John Smith </shiporder>'); XMLTYPE.schemaValidate(xml); END;

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• How do I alphabetize the items in two different CheckBoxLists?

  - by Matthew Jones

  I have two checkboxes (Recommended and Others) which have peoples names (concatenated, i.e. John Smith is one item). I want to alphabetize the selected members of each list into one. How can I do this?

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• Prolog: Error Handling and Find Unique

  - by anotherstat

  Given: fruitid('Apple', 'Granny Smith', 1). fruitid('Apple', 'Cox', 2). fruitid('Pear', 'Bartlett', 3). How would I go about finding only unique items for instance: is_unique(FruitName):- In the example clauses the answer would be Pear. I'm also trying to add error handling to my code, so in this instance if an input is: is_unique(pineapple) How could I catch this and output an error message? Thanks, AS

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• f# types' properties in inconsistent order and of slightly differing types

  - by philbrowndotcom

  I'm trying to iterate through an array of objects and recursively print out each objects properties. Here is my object model: type firmIdentifier = { firmId: int ; firmName: string ; } type authorIdentifier = { authorId: int ; authorName: string ; firm: firmIdentifier ; } type denormalizedSuggestedTradeRecommendations = { id: int ; ticker: string ; direction: string ; author: authorIdentifier ; } Here is how I am instantiating my objects: let getMyIdeasIdeas = [| {id=1; ticker="msfqt"; direction="buy"; author={authorId=0; authorName="john Smith"; firm={firmId=12; firmName="Firm1"}};}; {id=2; ticker="goog"; direction="sell"; author={authorId=1; authorName="Bill Jones"; firm={firmId=13; firmName="ABC Financial"}};}; {id=3; ticker="DFHF"; direction="buy"; author={authorId=2; authorName="Ron James"; firm={firmId=2; firmName="DEFFirm"}};}|] And here is my algorithm to iterate, recurse and print: let rec recurseObj (sb : StringBuilder) o= let props : PropertyInfo [] = o.GetType().GetProperties() sb.Append( o.GetType().ToString()) |> ignore for x in props do let getMethod = x.GetGetMethod() let value = getMethod.Invoke(o, Array.empty) ignore <| match value with | :? float | :? int | :? string | :? bool as f -> sb.Append(x.Name + ": " + f.ToString() + "," ) |> ignore | _ -> recurseObj sb value for x in getMyIdeas do recurseObj sb x sb.Append("\r\n") |> ignore If you couldnt tell, I'm trying to create a csv file and am printing out the types for debugging purposes. The problem is, the first element comes through in the order you'd expect, but all subsequent elements come through with a slightly different (and confusing) ordering of the "child" properties like so: RpcMethods+denormalizedSuggestedTradeRecommendationsid: 1,ticker: msfqt,direction: buy,RpcMethods+authorIdentifierauthorId: 0,authorName: john Smith,RpcMethods+firmIdentifierfirmId: 12,firmName: Firm1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 2,ticker: goog,direction: sell,RpcMethods+authorIdentifierauthorName: Bill Jones,RpcMethods+firmIdentifierfirmName: ABC Financial,firmId: 13,authorId: 1, RpcMethods+denormalizedSuggestedTradeRecommendationsid: 3,ticker: DFHF,direction: buy,RpcMethods+authorIdentifierauthorName: Ron James,RpcMethods+firmIdentifierfirmName: DEFFirm,firmId: 2,authorId: 2, Any idea what is going on here?

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• How to order by last name on a full name column?

  - by GateKiller

  I have a SQL Table with a column called FullName which contains, for example, "John Smith". How can order the data by the last name that appears in the FullName column? For a long name like "Laurence John Fishburne", I would like to order the data by the word "Fishburne". Thus, names are stored in the order First Name Middle Names Last Name I am using Microsoft SQL Server 2005.

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• Ruby: How to get the first character of a string

  - by Shpigford

  How can I get the first character in a string using Ruby? Ultimately what I'm doing is taking someone's last name and just creating an initial out of it. So if the string was "Smith" I just want "S".

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• How to make an id auto_increment from where it last left off after a record delete?

  - by Sammy

  This isn't that big of a deal but I was wondering if it can be done. Right now when I insert a new record, the id field which is auto_increment and set as primary key increases it's value by one: id | first_name | last_name ------------------------------ 1 | John | Smith 2 | Jane | Doe But if I delete record 2, the next one I insert is going to have an id of 3. Is there any way to make it have an id of 2 automatically (without having to manually insert it)?

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• Regular expression to match last item without delimiter

  - by Steven

  I have a string of names like this "J. Smith; B. Jones; O. Henry" I can match all but the last name with \w+.*?; Is there a regular expression that will match all the names, including the last one?

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• Doing order by using the Jaro-Winkler distance algorithm?

  - by Pentium10

  I am wondering how would I be able to run a SQLite order by in this manner select * from contacts order by jarowinkler(contacts.name,'john smith'); I know Android has a bottleneck with user defined functions, do I have an alternative?

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• How to access data from multiple tables

  - by Vinay Pandey

  Hi All, How to write linq query to access data from multiple table.How do you write Linq query for the following sql query:- "select * from user,employee where user.Name='smith' and employee.company='xyz'"

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• Spring MVC, REST, and HATEOAS

  - by SingleShot

  I'm struggling with the correct way to implement Spring MVC 3.x RESTful services with HATEOAS. Consider the following constraints: I don't want my domain entities polluted with web/rest constructs. I don't want my controllers polluted with view constructs. I want to support multiple views. Currently I have a nicely put together MVC app without HATEOAS. Domain entities are pure POJOs without any view or web/rest concepts embedded. For example: class User { public String getName() {...} public String setName(String name) {...} ... } My controllers are also simple. They provide routing and status, and delegate to Spring's view resolution framework. Note my application supports JSON, XML, and HTML, yet no domain entities or controllers have embedded view information: @Controller @RequestMapping("/users") class UserController { @RequestMapping public ModelAndView getAllUsers() { List<User> users = userRepository.findAll(); return new ModelAndView("users/index", "users", users); } @RequestMapping("/{id}") public ModelAndView getUser(@PathVariable Long id) { User user = userRepository.findById(id); return new ModelAndView("users/show", "user", user); } } So, now my issue - I'm not sure of a clean way to support HATEOAS. Here's an example. Let's say when the client asks for a User in JSON format, it comes out like this: { firstName: "John", lastName: "Smith" } Let's also say that when I support HATEOAS, I want the JSON to contain a simple "self" link that the client can then use to refresh the object, delete it, or something else. It might also have a "friends" link indicating how to get the user's list of friends: { firstName: "John", lastName: "Smith", links: [ { rel: "self", ref: "http://myserver/users/1" }, { rel: "friends", ref: "http://myserver/users/1/friends" } ] } Somehow I want to attach links to my object. I feel the right place to do this is in the controller layer as the controllers all know the correct URLs. Additionally, since I support multiple views, I feel like the right thing to do is somehow decorate my domain entities in the controller before they are converted to JSON/XML/whatever in Spring's view resolution framework. One way to do this might be to wrap the POJO in question with a generic Resource class that contains a list of links. Some view tweaking would be required to crunch it into the format I want, but its doable. Unfortunately nested resources could not be wrapped in this way. Other things that come to mind include adding links to the ModelAndView, and then customizing each of Spring's out-of-the-box view resolvers to stuff links into the generated JSON/XML/etc. What I don't want is to be constantly hand-crafting JSON/XML/etc. to accommodate various links as they come and go during the course of development. Thoughts?

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• regex find content question

  - by jeff

  Trying to use regex refind tag to find the content within the brackets in this example using coldfusion joe smith <[email protected]> The resulting text should be [email protected] Not having any luck. Any suggestions?

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• Applying styles to a GridView matching certain criteria

  - by NickK

  Hi everyone. I'm fairly new to ASP.Net so it's probably just me being a bit stupid, but I just can't figure out why this isn't working. Basically, I have a GridView control (GridView1) on a page which is reading from a database. I already have a CSS style applied to the GridView and all I want to do is change the background image applied in the style depending on if a certain cell has data in it or not. The way I'm trying to handle this change is updating the CSS class applied to each row through C#. I have the code below doing this: protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e) { GridViewRow row = e.Row; string s = row.Cells[7].Text; if (s.Length > 0) { row.CssClass = "newRowBackground"; } else { row.CssClass = "oldRowBackground"; } } In theory, the data from Cell[7] will either be null or be a string (in this case, likely a person's name). The problem is that when the page loads, every row in the GridView has the new style applied to it, whether it's empty or not. However, when I change it to use hard coded examples, it works fine. So for example, the below would work exactly how I want it to: protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e) { GridViewRow row = e.Row; string s = row.Cells[7].Text; if (s == "Smith") //Matching a name in one of the rows { row.CssClass = "newRowBackground"; } else { row.CssClass = "oldRowBackground"; } } It seems as if the top piece of code is always returning the string with a value greater than 0, but when I check the database the fields are all null (except for my test record of "Smith"). I'm probably doing something very simple that's wrong here, but I can't see what. Like I said, I'm still very new to this. One thing I have tried is changing the argument in the if statement to things like: if (s != null), if (s != "") and if (s == string.empty) all with no luck. Any help is greatly appreciated and don't hesitate to tell me if I'm just being stupid here. :)

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