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  • StackOverflowError occured as using java.util.regex.Matcher

    - by Captain Kidd
    Hi guys I try to catch text by Regular Expression. I list codes as follows. Pattern p=Pattern.compile("<@a>(?:.|\\s)+?</@a>"); Matcher m = p.matcher(fileContents.toString()); while(m.find()) { //Error will be thrown at this point System.out.println(m.group()); } If the length of text I want to catch is too long, system will throw me a StackOverflowError. Otherwise, the codes work well. Please help me how to solve this problem.

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  • What is proper RegEx expession for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Regex - Modifying strings except in specified enclosures - PHP

    - by Kovo
    I have found similar answers to my current needs on SO, however I am still trying to grasp modifying strings based on a rule, except in certain enclosures within those strings. Example of what Im trying to accomplish now: preg_replace("/\s*,\s*/", ",", $text) I found the above in many places. It will remove spaces before and after all commas in a string. That works great. However, if I want to exclude modifying commas found within " ", I am not sure how that rule has to be modified. Any help? Thanks! EDIT: I want to clarify my question: I would like all whitespace before and after the commas in the following sentence removed, except commas found in double or single quotes: a, b , c "d, e f g , " , h i j ,k lm,nop Expected result: a,b,c "d, e f g , ",h i j,k lm,nop

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  • Need to add underscore to my regex

    - by TaMeR
    I suck at regular expression and just can't seem to figure this out. '/^[A-Za-z0-9](?:.[A-Za-z0-9]+)*$/' As it's right now it allows dots anytime after the first char and I like to add _ so that it allows both. Thanks

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  • Ruby RegEx not matching valid expression

    - by Matthew Carriere
    I have the following expression: ^\w(\s(+|-|\/|*)\s\w)*$ This simply looks to match a mathematical expression, where a user is prompted for terms separated by basic operators (ex: price + tax) The user may enter more than just 2 terms and one operator (ex: price + tax + moretax) I tested this expression in Rubular http://rubular.com/ With the terms: a + a (MATCH) a + a + a (MATCH) a + a + a + a a a + a a Everything works, but when I use it in Ruby it does not work! expression =~ /^\w(\s(+|-|\/|*)\s\w)*$/ I started picking the expression apart and noticed that if I remove the start of line caret it finds matches but isn't correct. a + a (MATCH) a a (MATCH) <-- this is not correct Why is this expression not working in Ruby code? (I am using Ruby 1.8.7 p174)

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  • What is proper RegEx expression for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Javascript how many characters replaced in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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  • Java Regex for matching quoted string with escaped quotes

    - by kayahr
    I know there are already many questions like mine but I found no answer which works in Java. So I write a new question. I have text files with content like this: key1 = "This is a \"test\" text with escapes using '\\' characters"; key2 = 'It must work with \'single\' quotes and "double" quotes'; I need a regular expression which matches the values in the double-quotes (or single-quotes). This regular expression must support the escaped quotes and escaped backslashes. The regular expression must work with Java standard Pattern/Matcher classes.

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  • understanding this regex

    - by DarthVader
    I m trying to understand what the following does. ^([^=]+)(?:(?:\\=)(.+))?$ Any ideas? This is being used here. Obviously it s command line parser but i m trying to understand the syntax so i can actually run the program. This is from commandline-jmxclient , they have no documents on setting JMX properties but in their source code, there is such an option, so i just want to understand how i can invoke that method. Matcher m = Client.CMD_LINE_ARGS_PATTERN.matcher(command); if ((m == null) || (!m.matches())) { throw new ParseException("Failed parse of " + command, 0); } this.cmd = m.group(1); if ((m.group(2) != null) && (m.group(2).length() > 0)) this.args = m.group(2).split(","); else this.args = null;

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  • bash: assign grep regex results to array

    - by Ryan
    Hello everyone, I am trying to assign a regular expression result to an array inside of a bash script but I am unsure whether that's possible, or if I'm doing it entirely wrong. The below is what I want to happen, however I know my syntax is incorrect: indexes[4]=$(echo b5f1e7bfc2439c621353d1ce0629fb8b | grep -o '[a-f0-9]\{8\}') such that: index[1]=b5f1e7bf index[2]=c2439c62 index[3]=1353d1ce index[4]=0629fb8b Any links, or advice, would be wonderful :)

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  • Regex optional match in python fails

    - by AaronG
    tickettypepat = (r'MIS Notes:.**(//p//)?.**') retype = re.search(tickettypepat,line) if retype: print retype.group(0) print retype.group(1) Given the input. MIS Notes: //p// Can anyone tell me why group(0) is MIS Notes: //p// and group(1) is returning as None?

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  • cant get regex to work as i want

    - by Jorm
    With this function: function bbcode_parse($str) { $str = htmlentities($str); $find = array( '/\\*\*(.[^*]*)\*\*/is', ); $replace = array( '<b>' ); $str = preg_replace($find, $replace, $str); return $str; } And with text "My name is **bob**" I get in source code Hi my name is <b> Been trying to get this to work for a while now. Would appricate some expert help :)

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  • Regex to use each letter only once?

    - by gtcaz
    Is it possible to construct a PCRE-style regular expression that will only match each letter in a list only once? For example, if you have the letters "lrsa" and you try matching a word list against: ^[lrsa]*m[lrsa]*$ you're going to match "lams" (valid), but also "lamas" (invalid for our purposes because you only had one "a"). If your letter set was "lrsaa", you would want to match "lamas". Is this possible with regular expressions, or should I handle it programmatically?

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  • JS regex and angle brackets

    - by chaz
    Seriously, why can't I parse a string with angle brackets using the Javascript regular expression object? var r = new RegExp(), r; r.compile("\\<div\\>", "g"); r = r.exec("<div>Hello</div>"); //Equals null yo Why does that not work?

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  • get particular string using regex java

    - by hussain
    i want to know how to get the string from group of string String j = "<a href=\"/watch?v=4Qx-lBqOqiQ&feature=popular\" onclick=\"\" onmousedown=\"yt.analytics.urchinTracker(\'/Events/Home/PersonalizedHome/POP/Logged_Out');\" ><span class=\"video-thumb video-thumb-220 \" id=\"video-thumb-4Qx-lBqOqiQ-8821469\"><img src=\"http://i1.ytimg.com/vi/4Qx-lBqOqiQ/hqdefault.jpg\" class=\"vimg220\" alt=\"Dog Squirrel Chasing A Squirrel\" title=\"Dog Squirrel Chasing A Squirrel\" onclick=\";yt.www.watch.watch5.IEshenanigans(event, this)\"><span class=\"video-time\"><span>1:08</span></span><span class=\"video-actions\"><button class=\"yt-uix-button-short yt-uix-button yt-uix-button-arrowbutton\" onclick=\"; return false;\" type=\"button\"> <img class=\"yt-uix-button-arrow\" src=\"http://s.ytimg.com/yt/img/pixel-vfl73.gif\" alt=\"\"> hai</a>"; i want to get the string href=\"/watch?v=4Qx-lBqOqiQ&feature=popular\" and src=\"http://i1.ytimg.com/vi/4Qx-lBqOqiQ/hqdefault.jpg\" thanks and advance

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  • UNIX-style RegExp Replace running extremely slowly under windows. Help? EDIT: Negative lookahead ass

    - by John Sullivan
    I'm trying to run a unix regEXP on every log file in a 1.12 GB directory, then replace the matched pattern with ''. Test run on a 4 meg file is took about 10 minutes, but worked. Obviously something is murdering performance by several orders of magnitude. Find: ^(?!.*155[0-2][0-9]{4}\s.*).*$ -- NOTE: match any line NOT starting 155[0-2]NNNN where in is a number 0-9. Replace with: ''. Is there some justifiable reason for my regExp to take this long to replace matching text, or is the program I am using (this is windows / a program called "grepWin") most likely poorly optimized? Thanks. UPDATE: I am noticing that searching for ^(155[0-2]).$ takes ~7 seconds in a 5.6 MB file with 77 matches. Adding the Negative Lookahead Assertion, ?=, so that the regExp becomes ^(?!155[0-2]).$ is causing it to take at least 5-10 minutes; granted, there will be thousands and thousands of matches. Should the negative lookahead assertion be extremely detrimental to performance, and/or a large quantity of matches?

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  • php regex filename

    - by Patrick
    Hi, anyone can help me with a preg_match? I'd like to use php's preg_match to determine if an input is a valid filename or not (only the filename + file extension, not the full path). General rules: 1) filename = a-z, A-Z, 0-9 2) extension = 3 or 4 letters Thank you!

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  • How to get rid of duplicates in regex

    - by Emmanuel Smith
    Suppose I had a string, "cats cats cats and dogs dogs dogs." What regular expression would I use in order to replace that string with,"cats and dogs." i.e. removing duplicates. The expression however must only remove duplicates that follow after each other. For instance: "cats cats cats and dogs dogs dogs and cats cats and dogs dogs" Would return: "cats and dogs and cats and dogs"

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  • Regex: Strip HTML attributes except SRC

    - by Ian Silber
    Hi, I'm trying to write a regular expression that will strip all tag attributes except for the SRC attribute. For example: <p id="paragraph" class="green">This is a paragraph with an image <img src="/path/to/image.jpg" width="50" height="75"/></p> Would be returned as: <p>This is a paragraph with an image <img src="/path/to/image.jpg" /></p> I have a regular expression to strip all attributes, but I'm trying to tweak it to leave in src. Here's what I have so far: <?php preg_replace('/<([A-Z][A-Z0-9]*)(\b[^>]*)>/i', '<$1>', '<html><goes><here>'); Using PHP's preg_replace() for this. Thanks! Ian

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