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  • Drop down table and jquery

    - by Marcelo
    Hi, I'm trying to make a drop down table using jQuery, with a similar code like here: (from the topic: Conditional simple drop down list?) <body> <div id="myQuestions"> <select id="QuestionOptions"> <option value="A">Question A</option> <option value="B">Question B</option> </select> </div> <div id="myAnswers"> <div id="A" style="display: none;"> <div id="QuestionC"> <p>Here is an example question C.</p> </div> <div id="QuestionD"> <select id="QuestionOptionsD"> <option value="G">Question G</option> <option value="H">Question H</option> </select> </div> </div> <div id="B" style="display: none;"> <div id="QuestionE"> <p>Here is an example question E.</p> </div> <div id="QuestionF"> <select id="QuestionOptionsF"> <option value="I">Question I</option> <option value="J">Question J</option> </select> </div> </div> </div> And the jQuery part $(function () { $('#QuestionOptions').change(function () { $('#myAnswers > div').hide(); $('#myAnswers').find('#' + $(this).val()).show(); }); }); My problem is, when I finish to table the part of "myQuestions", and start to table the part of "myAnswers", the dynamic part of the table doesn't work. In this case, the myAnswers part won't be hidden, it'll be shown since the beginning. I tried to put everything in one table, then I tried to create a different table for myQuestions, then another table for myAnswers and it didn't work. Does anyone know where am I mistaking ? Sorry for any mistake in English, I'm not a native speaker. Thanks in advance.

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  • Selecting an item in an HTML SELECT list using keyboard doesnt trigger the CLICK event

    - by Jimbo
    I have an HTML select list which, when an item is selected, must show different information beneath it. The onclick or JQuery change events are triggered when a select list item is selected by being clicked on (mouse), but not when the user uses key presses (keyboard). Any idea what event to watch in order to determine when the selected list item has changed? Here is a BASIC test example: <select id="mylist" name="mylist"> <option value="">(none)</option> <option value="1">Test 1</option> <option value="2">Test 2</option> <option value="3">Test 3</option> </select> <span id="myspan"></span> <script type="text/javascript"> $("#mylist").change(function() { $("#myspan").html($("#mylist").attr("selectedIndex")); }); </script>

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  • Change a dropdown depending on another dropdown

    - by Eric Evans
    I'm trying to create a three select dropdowns that represent a persons birthday. I'm taking into consideration that there are 4 months with 30 days, 7 with 31 ,and 1 with 28 or 29 depending if it's a leap year or not. I would like the days dropdown to show the number of days depending on which month is chosen in the month dropdown. Here's what I have now. Here's the html for the select <!Doctype html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Birthday validation</title> <script src="jquery-1.11.1.min.js"></script> <script src="birthday_drop.js"></script> <link href="style.css" rel="stylesheet /> </head> <body> <h2>Birthday</h2> <fieldset class="birthday-picker"> <select class="birth-month" name="birth[month]"><option>Month</option></select> <select class="birth-day" name="birth[day]"><option>Day</option></select> <select class="birth-year" name="birth[year]"><option>Year</option></select> </fieldset> </body> </html> Here's the jquery that populates the dropdowns and my attempt to use the change function /** * Created by Eric Evans on 8/19/14. */ $(document).ready(function(){ var months = ['January','February','March','April','May','June','July','August','September','October','November','December']; for(i=0; i < months.length; i++){ $("<option value=' + months[i] + '>" + months[i] + "</option>").appendTo('.birth-month'); } for(i=0; i <= 31; i++){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-day'); } var myYear = new Date().getFullYear(); for(i=myYear; i >= 1950; i--){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-year'); } $('.birth-month').change(function(){ if($(this).val() == 'April'){ for(i=0; i <= 30; i++){ $("<option value=' + i + '>" + i + "</option>").appendTo('.birth-day'); } } }); }); Any help would be greatly appreciated

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  • Looping through selected values in multiple select combobox JQuery

    - by Roland
    I have the following scenario. I have a combobox where multiple selection is available. <select id="a" multiple="multiple"> <option value="">aaaa</option> <option value="">bbbb</option> <option value="">cccc</option> <option value="">dddd</option> </select> Now I also have a button <button type="button" id="display">Display</button> When a user clicks on this button, it should list all the selected values of the dropdown in an alert box My JS code looks as follows $(document).ready(function() { $('#display').click(function(){ alert($('#a').val()); }); }); Any pointers will be appreciated

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  • Want to calculate the sum of the count rendered by group by option..

    - by Vijay
    i have a table with the columns such id, tid, companyid, ttype etc.. the id may be same for many companyid but unique within the companyid and tid is always unique and i want to calculate the total no of transactions entered in the table, a single transaction may be inserted in more than one row, for example, id tid companyid ttype 1 1 1 xxx 1 2 1 may be null 2 3 1 yyy 2 4 1 may be null 2 5 1 may be null the above entries should be counted as only 2 transactions .. it may be repeated for many companyids.. so how do i calculate the total no of transactions entered in the table i tried select sum(count(*)) from transaction group by id,companyId; but doesn't work select count(*) from transaction group by id; wont work because the id may be repeated for different companyids.

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  • Using onboard and pci-e graphics card at the same time

    - by Endle
    Hello wonderful people. I know there are several other posts with similar questions. I also know how to use Google. I also have read up on posts discussing bumblebee, crossfire, ati catylist and many other interesting topics. I would just like someone to give me advice on how to use the onboard and pci-e graphics at the same time. I know the computer is capable of doing this. It works in Windows. I can use the VGA and DVI onboard port and the HDMI port of the add on card all at the same time. Works great in Windows 7, In Ubuntu, it seems only one or the other will work. I can use any combination of two displays on either adapter: VGA and HDMI..HDMI and DVI..so forth and so on. I have started experimenting with xorg.conf files, but have not been able to get any of them to work. Here is my last attempt at writing an xorg.conf file: Section "ServerLayout" Identifier "X.org Configured" Screen 0 "Screen0" 0 0 Screen 1 "Screen1" LeftOf "Screen0" Screen 2 "Screen2" LeftOf "Screen1" InputDevice "Mouse0" "CorePointer" InputDevice "Keyboard0" "CoreKeyboard" EndSection Section "Device" Identifier "Onboard Video" Driver "radeon" BusID "PCI:01:05.0" EndSection Section "Device" Identifier "Graphics Card" Driver "radeon" BusID "PCI:02:00.0" EndSection Section "Monitor" Identifier "CRT2" Option "VendorName" "ViewSonic" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Monitor" Identifier "DVI1" VendorName "ACR" ModelName "P224W" Option "DPMS" EndSection Section "Monitor" Identifier "DVI2" Option "VendorName" "Acer" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Screen" Identifier "Screen0" Device "Onboard Video" Monitor "CRT2" DefaultDepth 24 SubSection "Display" Depth 24 Modes "1280x1024" EndSubSection EndSection Section "Screen" Identifier "Screen1" Device "Graphics Card" Monitor "DVI1" DefaultDepth 24 SubSection "Display" Depth 24 Modes "1920x1080" EndSubSection

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  • Jquery Var Returned As object

    - by alex
    I'm trying to pass a variable from one function to another, but the var elmId is being returned as an object and giving an error. When we click on any of the generated divs we should be able to change the size of the div by choosing a width / height value from the drop down menus. I'm trying to pass the clicked div id which is elmId to function displayVals but it is not working. If we replace "#"+elmId in the function displayVals with the actual id of the first div created with is "#divid1" then it works. Why is the value of var elmId not being passed to displayVals <link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.7/themes/base/jquery-ui.css" type="text/css" media="all" /> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.7/jquery-ui.min.js" type="text/javascript"></script> <style> .aaa{width:100px; height:100px; background-color:#ccc;} button{width:100px; height:20px;} </style> <button class="idiv">div</button> <select id="width"> <option>100px</option> <option>200px</option> <option>300px</option> </select> <select id="height"> <option>100px</option> <option>200px</option> <option>300px</option> </select> <p></p> <script type="text/javascript"> var divId = 1; $("button").click(function(){ var elm = $('<div id=divid' + divId + ' class=aaa></div>'); elm.appendTo('p'); divId++; }); $("p").click(function(e){ var elmType = $(e.target)[0].nodeName, elmId = $(e.target)[0].id; return displayVals(elmId); }); function displayVals(elmId) { var iwidth = $("#width").val(); var iheight = $("#height").val(); $("#"+elmId).css({width:iwidth, height:iheight}); console.log(elmId); } $("select").change(displayVals); displayVals(); </script>

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  • How to validate an array in a PHP form?

    - by SlAcKeR
    I'm fairly new to php and was wondering how do I validate the array for the states and where do I place the php code at? I already did the address part but I'm stuck at the states part. Here is the validation code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. $address = mysqli_real_escape_string(htmlentities($_POST['address'])); } Here is the form code. <li><label for="address-1">Address 1: </label><input type="text" name="address-1" id="address-1" size="25" class="input-size" value="<?php if (isset($_POST['address'])) echo $_POST['address']; ?>" /></li> <li><label for="state-province">State/Province: </label> <?php echo '<select name="state-province" id="state-province">' . "\n"; foreach($state_options as $option) { if ($option == $state) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • XML Processing on iPhone: What is the best option?

    - by gonso
    Hello Im building a new version of an iPhone application and Im wondering if I should review how my app communicates with the server. My iPhone client sends and receives XML over HTTP requests. To send the information I use ASIHTTPRequest framework. I "manually" build the XML request by appending strings. To parse the response Im using a NSXMLParser. My question is if I have better options to A) Create an XML string from a memory object. B) Create a memory object from the XML string. Is there anything like JAXB to marshal XML into object? Thanks Gonso

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  • Modify php shopping cart to support multiple drop down menus

    - by Thomas
    I have a shopping cart script that I am trying to modify to support multiple product selection. As it is now, the customer can select a product from a single drop down menu. Now, I would like to add multiple dropdown menus (all populated with the same options). Here is the php that outputs the dropdown menu: if($eshopoptions['options_num']>1){ $opt=$eshopoptions['options_num']; $replace.="\n".'<label for="eopt'.$theid.'"><select id="eopt'.$theid.'" name="option">'; for($i=1;$i<=$opt;$i++){ $option=$eshop_product['products'][$i]['option']; $price=$eshop_product['products'][$i]['price']; if($option!=''){ if($price!='0.00') $replace.='<option value="'.$i.'">'.stripslashes(esc_attr($option)).' @ '.sprintf( _c('%1$s%2$s|1-currency symbol 2-amount','eshop'), $currsymbol, number_format($price,2)).'</option>'."\n"; else $replace.='<option value="'.$i.'">'.stripslashes(esc_attr($option)).'</option>'."\n"; } } Is there some really simple way of getting the code to output the menu say 3 times instead of once?

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  • print issue in safari

    - by designersvsoft
    I have used below css for select tag. select { vertical-align:middle; float:left; border:1px solid #cccccc; background-color:#F0F0F0; padding:2px; font-size:14px; height:35px ;} Here is the HTML version: <select> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="mercedes">Mercedes</option> <option value="audi">Audi</option> </select> If I see the print preview, it is not good on safari browser. Please help us.

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  • How to resume an ftp download at any point? (shell script, wget option)?

    - by Dave
    hi! i want to download a huge file from an ftp server in chunks of 50-100MB each. At each point, i want to be able to set the "starting" point and the length of the chunk i want. i wont have the "previous" chunks saved locally (ie i cant ask the program to "resume" the downlaod). what is the best way of going about that? i use wget mostly, but would something else be better?

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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  • Drag and Drop Multiple select boxes

    - by Roland
    I have two multiple select boxes. I need to use JQuery to drag selected items from one combobox to the next. Is this at all possible? I need to drag items from this box <select id="select1" multiple=multiple> <option value="1">test1</option> <option value="2">test2</option> <option value="3">test3</option> </select> to this box <select id="select2" multiple=multiple> <option value="4">test4</option> </select> Any pointers help will be appreciated

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  • Getting jQuery to recognise .change() in IE

    - by Philip Morton
    I'm using jQuery to hide and show elements when a radio button group is altered/clicked. It works fine in browsers like Firefox, but in IE 6 and 7, the action only occurs when the user then clicks somewhere else on the page. To elaborate, when you load the page, everything looks fine. In Firefox, if you click a radio button, one table row is hidden and the other one is shown immediately. However, in IE 6 and 7, you click the radio button and nothing will happen until you click somewhere on the page. Only then does IE redraw the page, hiding and showing the relevant elements. Here's the jQuery I'm using: $(document).ready(function(){ $(".hiddenOnLoad").hide(); $("#viewByOrg").change(function () { $(".visibleOnLoad").show(); $(".hiddenOnLoad").hide(); }); $("#viewByProduct").change(function () { $(".visibleOnLoad").hide(); $(".hiddenOnLoad").show(); }); }); Here's the part of the XHTML that it affects. Apologies if it's not very clean, but the whole page does validate as XHTML 1.0 Strict: <tr> <td>View by:</td> <td> <p> <input type="radio" name="viewBy" id="viewByOrg" value="organisation" checked="checked"/> Organisation </p> <p> <input type="radio" name="viewBy" id="viewByProduct" value="product"/> Product </p> </td> </tr> <tr class="visibleOnLoad"> <td>Organisation:</td> <td> <select name="organisation" id="organisation" multiple="multiple" size="10"> <option value="1">Option 1</option> <option value="2">Option 2</option> </select> </td> </tr> <tr class="hiddenOnLoad"> <td>Product:</td> <td> <select name="product" id="product" multiple="multiple" size="10"> <option value="1">Option 1</option> <option value="2">Option 2</option> </select> </td> </tr> If anyone has any ideas why this is happening and how to fix it, they would be very much appreciated!

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  • How to create a drop down menu like the one displayed on Amazon?

    - by webdev_newbee
    I am kind of new to web development. I am trying to create a drop down menu, something I have now is like: <select> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="opel">Opel</option> <option value="audi">Audi</option> </select> but this is not exactly what I want. I want to create a drop down list very similar to the one on Amazon.com (the dropdown list beside "Search"), shown in following pic. so whenever user click on the button, the list will be displayed in the button as text. Please feel free to give me any ideas. Thank you,

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  • Selecting unique elements using XSLT.

    - by AJ
    I have the following XML: <option> <title>ABC</title> <desc>123</desc> </option> <option> <title>ABC</title> <desc>12345</desc> </option> <option> <title>ABC</title> <desc>123</desc> </option> <option> <title>EFG</title> <desc>123</desc> </option> <option> <title>EFG</title> <desc>456</desc> </option> Using XSLT, I want to transform it into: <choice> <title>ABC</title> <desc>123</desc> <desc>12345</desc> </choice> <choice> <title>EFG</title> <desc>123</desc> <desc>456</desc> </choice>

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  • jQuery Hide Div(s) on focus of drop down menu or text (live search) input

    - by webwrks
    Can anyone help me? I'm trying to hide the #hideme div when the a user clicks the drop down menu (to select something) or puts the focus on the text field. Thanks! #hideme { background:#ccc; } <script> $(function(){ $('#skill_select').click(function(){ $('#hideme').hide(); }); }): </script> <select> <option selected="selected">Pick from the list</option> <option>Option One</option> <option>Option Two</option> </select> or <input type="text" value="type something"> <br/><br/> <div id="hideme">Hide Me Please</div>

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