Search Results

Search found 20043 results on 802 pages for 'password assistant mac'.

Page 48/802 | < Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >

  • Problem upgrading eclipse rcp app from 3.3 to 3.5 on Mac OS

    - by Alb
    I previously had an eclipse rcp app based on eclipse 3.3 pugins deployed on both windows and mac OS X 10.4. i'm now trying to port the app to java 1.6 and eclipse 3.5 (Build id: 20100218-1602) plugins on Mac OS X 10.5.8 (Leopard). I can launch the product from eclipse 3.5 on windows but not on Mac OS X. I have the 64bit cocoa eclipse IDE and java 6. In the launch configuration I set runtime JRE to JVM 1.6.0 and added required plugins. The plugins validate and everything else looks similar to windows configuration where it works, but when I launch i only get the following two lines in the console: 2010-03-16 13:29:32.742 java[758:10b] [Java CocoaComponent compatibility mode]: Enabled 2010-03-16 13:29:32.744 java[758:10b] [Java CocoaComponent compatibility mode]: Setting timeout for SWT to 0.100000 and then the program appears to just hang indefinitely. There is nothing written to the .log file so I'm not sure what error there is. EDIT: Here's what Yourkit profiling says before all cpu activity stops. +----------------------------------------------------------------------------+----------------+-----------------+ | Name | Time (ms) | Own Time (ms) | +----------------------------------------------------------------------------+----------------+-----------------+ | +---<All threads> | 2,799 100 % | | | | | | | | +---org.eclipse.equinox.launcher.Main.main(String[]) | 1,924 69% | 0 | | | | | | | +---org.eclipse.osgi.framework.eventmgr.EventManager$EventThread.run() | 632 23 % | 0 | | | | | | | +---java.lang.Thread.run() | 135 5 % | 0 | | | | | | | +---java.lang.ClassLoader.loadClassInternal(String) | 106 4 % | 0 | +----------------------------------------------------------------------------+----------------+-----------------+ , and this in the exceptions tab: Exception staticstics +----------------------------------------+--------------+ | Name | Count | +----------------------------------------+--------------+ | +---java.lang.ClassNotFoundException | 102 11 % | | | | | | +---java.net.MalformedURLException | 4 0 % | | | | | | +---java.lang.NoSuchMethodException | 3 0 % | | | | | | +---java.lang.NumberFormatException | 2 0 % | | | | | | +---java.io.FileNotFoundException | 1 0 % | | | | | | +---java.lang.UnsatisfiedLinkError | 1 0 % | +----------------------------------------+--------------+ and here's more details on the ClassNotFoundExceptions mentioned above: java.lang.ClassNotFoundException Start Level Event Dispatcher native ID: 0x8B0B group: 'main' 78 Thread-4 native ID: 0x10B group: 'main' 22 Framework Event Dispatcher native ID: 0xD207 group: 'main' 2 Anyone know why I don't see a trace for this in Eclipse or in any log files? any ideas where I should look? [Updated on: Tue, 16 March 2010 09:37]

    Read the article

  • Make WebStart Java desktop application to start on system startup on Windows and Mac

    - by parxier
    I developed small cross-platform (Windows and Mac) SWT desktop application. It is distributed with WebStart. So far so good, everything works. I've got a new requirement to make my app start on system startup (with no user interaction). What is the best way to accomplish that? In JNLP file I've got this: <shortcut online="false"> <desktop/> <menu submenu="CompanyName"/> </shortcut> On Windows WebStart creates a desktop link [app_name].lnk and it points to javaws.exe and then some Java cache file as a parameter with funny name like ..\Sun\Java\Deployment\cache\6.0\4\2c0a6a781-213476. I can possibly programmatically find that link on user's machine by name... erm... and then copy it into user's Startup folder. I can see a problem here though as user can disable WebStart desktop shortcut creation option all together. On Mac WebStart pops up a dialog to prompt user for the location where to create an [app_name].app (user is allowed to change link name there!) file that launches an application. On Mac I don't event know where the Startup folder is located (and it seems to be much more complex there). Is there Java library out there that abstracts start app on system startup concept on different platforms as SWT does for GUI abstraction?

    Read the article

  • Can't play wav file from Javascript in Firefox for Mac

    - by Mike Royle
    I have the following html file that plays a wav file when the user hovers over the 'Play' anchor tag. It works perfectly on IE, Chrome, Firefox, Opera, Safari on both Windows and Mac - except for Firefox on the Mac which does not play the file. <html> <head> <title></title> <script> function PlayAudio() { var s = document.getElementById("soundFile"); s.Play(); } </script> </head> <body> <embed src="MySound.wav" enablejavascript="true" type="audio/wav" autostart="false" width="0" height="0" id="soundFile" /> <a href="#" onmouseover="PlayAudio()">Play</a> </body> </html> If the autostart attribute of the embed tag is set to true then the wav file plays as expected in Firefox for Mac, but not on the mouseover of the anchor tag. Any ideas?

    Read the article

  • data validation on wpf passwordbox:type password, re-type password

    - by black sensei
    Hello Experts !! I've built a wpf windows application in with there is a registration form. Using IDataErrorInfo i could successfully bind the field to a class property and with the help of styles display meaningful information about the error to users.About the submit button i use the MultiDataTrigger with conditions (Based on a post here on stackoverflow).All went well. Now i need to do the same for the passwordbox and apparently it's not as straight forward.I found on wpftutorial an article and gave it a try but for some reason it wasn't working. i've tried another one from functionalfun. And in this Functionalfun case the properties(databind,databound) are not recognized as dependencyproperty even after i've changed their name as suggested somewhere in the comments plus i don't have an idea whether it will work for a windows application, since it's designed for web. to give you an idea here is some code on textboxes <Window.Resources> <data:General x:Key="recharge" /> <Style x:Key="validButton" TargetType="{x:Type Button}" BasedOn="{StaticResource {x:Type Button}}" > <Setter Property="IsEnabled" Value="False"/> <Style.Triggers> <MultiDataTrigger> <MultiDataTrigger.Conditions> <Condition Binding="{Binding ElementName=txtRecharge, Path=(Validation.HasError)}" Value="false" /> </MultiDataTrigger.Conditions> <Setter Property="IsEnabled" Value="True" /> </MultiDataTrigger> </Style.Triggers> </Style> <Style x:Key="txtboxerrors" TargetType="{x:Type TextBox}" BasedOn="{StaticResource {x:Type TextBox}}"> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}"/> <Setter Property="Validation.ErrorTemplate"> <Setter.Value> <ControlTemplate> <DockPanel LastChildFill="True"> <TextBlock DockPanel.Dock="Bottom" FontSize="8" FontWeight="ExtraBold" Foreground="red" Padding="5 0 0 0" Text="{Binding ElementName=showerror, Path=AdornedElement.(Validation.Errors)[0].ErrorContent}"></TextBlock> <Border BorderBrush="Red" BorderThickness="2"> <AdornedElementPlaceholder Name="showerror" /> </Border> </DockPanel> </ControlTemplate> </Setter.Value> </Setter> </Trigger> </Style.Triggers> </Style> </Window.Resources> <TextBox Margin="12,69,12,70" Name="txtRecharge" Style="{StaticResource txtboxerrors}"> <TextBox.Text> <Binding Path="Field" Source="{StaticResource recharge}" ValidatesOnDataErrors="True" UpdateSourceTrigger="PropertyChanged"> <Binding.ValidationRules> <ExceptionValidationRule /> </Binding.ValidationRules> </Binding> </TextBox.Text> </TextBox> <Button Height="23" Margin="98,0,0,12" Name="btnRecharge" VerticalAlignment="Bottom" Click="btnRecharge_Click" HorizontalAlignment="Left" Width="75" Style="{StaticResource validButton}">Recharge</Button> some C# : class General : IDataErrorInfo { private string _field; public string this[string columnName] { get { string result = null; if(columnName == "Field") { if(Util.NullOrEmtpyCheck(this._field)) { result = "Field cannot be Empty"; } } return result; } } public string Error { get { return null; } } public string Field { get { return _field; } set { _field = value; } } } So what are suggestion you guys have for me? I mean how would you go about this? how do you do this since the databinding first purpose here is not to load data onto the fields they are just (for now) for data validation. thanks for reading this.

    Read the article

  • C Privilege Escalation (With Password)

    - by AriX
    Hey everyone, I need to write a C program that will allow me to read/write files that are owned by root. However, I can only run the code under another user. I have the root password, but there are no "sudo" or "su" commands on the system, so I have no way of accessing the root account (there are practically no shell commands whatsoever, actually). I don't know a whole lot about UNIX permissions, so I don't know whether or not it is actually possible to do this without exploiting the system in some way or running a program owned by root itself (with +s or whatever). Any advice? Thanks! P.S. No, this isn't anything malicious, this is on an iPhone.

    Read the article

  • Windows computer account appears to reset its own password, why?

    - by David Yu
    Has anyone seen this where a computer account appears to reset its password? The password for user 'WEST\SQLCLUSTER$' was reset by 'WEST\SQLCLUSTER$' on 'DOMAINCONTROLLER.WEST.company.corp' at '04/23/10 20:47:41' Event Type: Success Audit Event Source: Security Event Category: Account Management Event ID: 628 Date: Friday, April 23, 2010 Time: 8:47 PM User: WEST\SQLCLUSTER$ Computer: DOMAINCONTROLLER.WEST.company.corp Description: User Account password set: Target Account Name: SQLCLUSTER$ Target Domain: WEST Target Account ID: WEST\SQLCLUSTER$ Caller User Name: SQLCLUSTER$ Caller Domain: WEST Caller Logon ID: (0x0,0x7A518945)

    Read the article

  • Help with password complexity regex

    - by Alex
    I'm using the following regex to validate password complexity: /^.*(?=.{6,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ In a nutshell: 2 lowercase, 2 uppercase, 2 numbers, min length is 6 and max length is 12. It works perfectly, except for the maximum length, when I'm using a minimum length as well. For example: /^.*(?=.{6,})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ This correctly requires a minimum length of 6! And this: /^.*(?=.{,12})(?=.*[0-9]{2})(?=.*[A-Z]{2})(?=.*[a-z]{2}).*$/ Correctly requires a maximum length of 12. However, when I pair them together as in the first example, it just doesn't work!! What gives? Thanks!

    Read the article

  • In Apache, how do I set up password protection?

    - by rphello101
    I'm attempting to set up a server using Apache. In the conf file, I inserted the code: <Directory /> Options FollowSymLinks AllowOverride AuthConfig AuthType Basic AuthName "Restricted Files" AuthBasicProvider file AuthUserFile C:\...\serverpass.txt Require user Admin </Directory> In order to try and get Apache to require a password. I created the username and password with htpasswd -c. When I got to localhost though, it doesn't prompt me for a username and password?

    Read the article

  • Opening a password encrypted access database using DAO VB.NET

    - by prasoon99
    I create a database like this: Sub Main() Dim wrkDefault As Workspace Dim dbE As DBEngine Dim dbs As Database 'Get default Workspace. dbE = New DBEngine wrkDefault = dbE.Workspaces(0) 'Set the database filename Dim DBFilename As String DBFilename = "c:\mydb.mdb" 'Make sure there isn't already a file with the same name of 'the new database file. If Dir(DBFilename) <> "" Then MsgBox("File already exists!") Exit Sub End If 'Create a new encrypted database with the specified 'collating order. 'lock database with the password 'hello' dbs = wrkDefault.CreateDatabase(DBFilename, _ LanguageConstants.dbLangGeneral & ";pwd=hello;", DatabaseTypeEnum.dbEncrypt) dbs.Close() End Sub How do I open this database again in VB.NET using DAO?

    Read the article

  • MembershipUser class CreateUser password paramter

    - by d3020
    I'm using the ASP.NET Configuration for my users and their roles. I'm also using the MembershipUser class with its function CreateUser. I have it working, but was curious about something. When I add a new user and pass this function its password parameter (which in this case is coming from a textbox on the page). It seems like it only finds and accepts that textbox value when it is 6 chars or more. For example, if I type in ab123 it'll say object not set to instance of an object. However if I do abc123 it works fine. Where is that being told to do that. I didn't know if this was something I could change or where it might be doing that. Thanks.

    Read the article

  • Sending forgot password emails

    - by GeoffreyF67
    I am building a service that will have a 'forgot my password' feature. In addition to that, it will also email users when results are ready from my service. I would like to ensure delivery of my emails so I was looking around to find a service that would let me send emails. All that I've been able to find so far are services that require a user to opt-in to a list. In other words, I've been unable to find any that will let me send customized messages to individual users. I am currently using swiftmailer for php but would really like to find a service to do this...Anyone know of one? G-Man

    Read the article

  • C++ password masking

    - by blaxc
    hi... i'm writing a code to receive password input. Below is my code... the program run well but the problem is other keys beside than numerical and alphabet characters also being read, for example delete, insert, and etc. can i know how can i avoid it? tq... string pw=""; char c=' '; while(c != 13) //Loop until 'Enter' is pressed { c = _getch(); if(c==13) break; if(c==8) { if(pw.size()!=0) //delete only if there is input { cout<<"\b \b"; pw.erase(pw.size()-1); } } if((c>47&&c<58)||(c>64&&c<91)||(c>96&&c<123)) //ASCii code for integer and alphabet { pw += c; cout << "*"; } }

    Read the article

  • Implementing password hashing/salting algorithm from crackstation.net

    - by Mason240
    I am trying to implement a password hashing/salting algorithm from crackstation.net, but I am unsure how implement it. Storing the password upon user registration seems to be as simple as passing the password into create_hash(). $password = create_hash($_POST['Password']; I'm not following how to validate upon user login. validate_password($password, $good_hash) returns either true or false, and takes $password as parameter, so it seems like a no brainer except for the second parameter $good_hash. Where does this param come from? It is my understanding that password is turned into a hash value every time its used, and that the hash value is what is stored and compared. So why would I have both the $password and $good_hash values? Quick overview of the functions: function create_hash($password){ calls pbkdf2() } function validate_password($password, $good_hash){ calls pbkdf2() calls slow_equals() } function slow_equals($a, $b){ } function pbkdf2($algorithm, $password, $salt, $count, $key_length, $raw_output = false){ } Of course a different, better method for this would also be just as helpful. Thank you

    Read the article

  • How can I set the BIOS/EFI security password on IBM System x servers by script/ASU?

    - by christian123
    I want to deploy IBM System x servers (like IBM System x 3550 M2) automatically and need to set a security password in the bios (actually it's uefi). I found this nice tool named ASU: http://www-947.ibm.com/systems/support/supportsite.wss/docdisplay?brandind=5000008&lndocid=MIGR-55021 Unfortunately I cannot see an option to set the password. Forum searches only show me people who want to reset the password using this tool. Does anybody know how to automatically deploy system passwords on IBM Intel-based servers?

    Read the article

  • whats the default username and password for an ubuntu live cd?

    - by Rory McCann
    What's the username and password for an ubuntu live cd image? I ask cause I've recently copied the contents of an ubuntu based live iso (easypeasy, the ldistro for nwtbooks) onto a harddisk, but the squash fs is corrupt. Most likely cause I copied it live. :) so it's not autologging in. Is there a username/password for this? Update: I tried username ubuntu and a blank password, it didn't work

    Read the article

  • password-check directive in angularjs

    - by mpm
    I'm writing a password verify directive : Directives.directive("passwordVerify",function(){ return { require:"ngModel", link: function(scope,element,attrs,ctrl){ ctrl.$parsers.unshift(function(viewValue){ var origin = scope.$eval(attrs["passwordVerify"]); if(origin!==viewValue){ ctrl.$setValidity("passwordVerify",false); return undefined; }else{ ctrl.$setValidity("passwordVerify",true); return viewValue; } }); } }; }); html : <input data-ng-model='user.password' type="password" name='password' placeholder='password' required> <input data-ng-model='user.password_verify' type="password" name='confirm_password' placeholder='confirm password' required data-password-verify="user.password"> Given 2 password fields in a form, if both password values are equal then the field affected by the directive is valid. The issue is that it works one way (i.e. when I type a password in the password-verify field). However, when the original password field is updated, the password-verify doesn't become valid. Any idea how I could have a "two way binding verify?"

    Read the article

  • Password protected web content-- basic question

    - by nickpish
    I'm looking to create a password-protected section of my website that requires user login, and I'm wondering what approach would provide the simplest solution. For the most part, the site will be very simple and static-- i.e. no real requirement for a database/backend-- with the protected content contained in a single directory, which I've already configured on my server via htaccess. I guess I'm wondering ultimately if it's possible to use a script of some sort that will enable access to this protected directory via a form and thereby bypass the need for configuring a mySQL/PHP solution? Furthermore, this protected content is not exactly hyper-sensitive, but private nonetheless. Thanks much for any direction here.

    Read the article

  • Username correct, password incorrect?

    - by jonnnnnnnnnie
    In a login system, how can you tell if the user has entered the password incorrectly? Do you perform two SQL queries, one to find the username, and then one to find the username and matching (salted+hashed etc) password? I'm asking this because If the user entered the password incorrectly, I want to update the failed_login_attempts column I have. If you perform two queries wouldn't that increase overhead? If you did a query like this, how would you tell if the password entered was correct or not, or whether the username doesn't exist: SELECT * FROM author WHERE username = '$username' AND password = '$password' LIMIT 1 ( ^ NB: I'm keeping it simple, will use hash and salt, and will sanitize input in real one.) Something like this: $user = perform_Query() // get username and password? if ($user['username'] == $username && $user['password'] == $password) { return $user; } elseif($user['username'] == $username && $user['password'] !== $password) { // here the password doesn't match // update failed_login_attemps += 1 }

    Read the article

  • Windows Sharing requires password

    - by Linux Intel
    I have 3 machines on my local network Machine A , Machine B and Machine C OS on all machines is : Windows 7 64bit. Sharing Permissions on all machines : Everyone ( Read/Write ) no domain. Sharing folder name : project Machine A is sharing folder over the network without password. Machine B is sharing folder over the network without password. Machine C is sharing folder over the network without password. Machine A can normally access B and C without password required. Machine B can normally access A and C without password required Machine C can normally access Machine B without password. My problem is *Machine C* requires a password when it access Machine A also the shared folder in Machine A don't have password protected and Machine B can access Machine A without a password ! How can i solve the problem .?

    Read the article

  • System wide Proxy settings when on a windows network with a password

    - by sav
    I'm using Ubuntu on a windows network. I want to connect to the world wide web. I have followed the steps here which I have found very useful. However when I try to ping a website (eg: ping www.wikipedia.org) I get no reply. I can ping local computers on my network, but I need to go through our proxy to get to the world wide web. I can even browse wikipedia using firefox, I just needed to enter the proxy configuration script location and my username and password. I'm quite sure the reason I'm having this trouble is because I havn't entered a username and password. I'm not sure how to do this on a system wide level. ultimately I would like to be able to use package managers like synaptic but first I need them to be able to connect to the internet. EDIT As sugested I created a /etc/apt/apt.conf file like Acquire::http::Proxy "http://chrisav:[email protected]:8080"; Acquire::https::Proxy "https://chrisav:[email protected]:8080"; Acquire::ftp::Proxy "ftp://chrisav:[email protected]:8080"; Acquire::socks::Proxy "socks://chrisav:[email protected]:8080"; However I still cant ping wikipedia when I try installing stuff I get chris@chris-Ubuntu:~$ sudo apt-get install kate Reading package lists... Done Building dependency tree Reading state information... Done E: Unable to locate package kate

    Read the article

  • PDFtk Password Protection Help

    - by Dave W.
    I am using Ubuntu 11.10 and am looking for a solution to password protect a bunch of pdf files in a directory in batch. I came across PDFtk and it looks like it might do what I need, but I've reviewed the command line PDFtk examples and can't figure out if there is a way to do it in batch without having to individually specify the output file name for every file. I'm hoping a command-line guru can take a look at the PDFtk syntax and tell me if there is some trick / command that will allow me to password protect a directory of pdf files (e.g., *.pdf) and overwrite the existing files using the same name, or consistently rename the individual output files without having to specify each output name individually. Here's a link to the PDFtk command line examples page: http://www.pdflabs.com/tools/pdftk-the-pdf-toolkit/ Thanks for your help. I think I've answered my own question. Here's a bash script that appears to do the trick. I'd welcome help evaluating why the code I've commented out doesn't work... #!/bin/bash # Created by Dave, 2012-02-23 # This script uses PDFtk to password protect every PDF file # in the directory specified. The script creates a directory named "protected_[DATE]" # to hold the password protected version of the files. # # I'm using the "user_pw" parameter, # which means no one will be able to open or view the file without # the password. # # PDFtk must be installed for this script to work. # # Usage: ./protect_with_pdftk.bsh [FILE(S)] # [FILE(S)] can use wildcard expansion (e.g., *.pdf) # This part isn't working.... ignore. The goal is to avoid errors if the # directory to be created already exists by only attempting to create # it if it doesn't exists # #TARGET_DIR="protected_$(date +%F)" #if [ -d "$TARGET_DIR" ] #then #echo # echo "$TARGET_DIR directory exists!" #else #echo # echo "$TARGET_DIR directory does not exist!" #fi # mkdir protected_$(date +%F) for i in *pdf ; do pdftk "$i" output "./protected_$(date +%F)/$i" user_pw [PASSWORD]; done echo "Complete. Output is in the directory: ./protected_$(date +%F)"

    Read the article

  • How to Reenable Apple Java 6 Plug-in for Mac EBS Users

    - by Steven Chan (Oracle Development)
    Apple's Java for OS X 2012-006 update uninstalled the Apple-provide Java applet plug-in from all Mac web browsers. Mac OS X users running Java-based applications are instructed to download the latest version of the Java 7 applet plug-in from Oracle. For more information about Oracle's Java 7 for Mac, see: Mac Java 7 FAQ: Install, Remove, Revert, Configure, Sys Req (Java.com) We're currently certifying Oracle E-Business Suite with Mac desktops running Java 7. We have identified some compatibility issues and are working with the Java team on fixes right now. Until that certification is completed, EBS users on Mac platforms can follow these instructions from Apple to ensure continued access to the E-Business Suite: Java for OS X 2012-006: How to re-enable the Apple-provided Java SE 6 applet plug-in and Web Start functionality (Apple.com) Related Articles Planning Bulletin for JRE 7: What EBS Customers Can Do Today

    Read the article

  • Still prompted for a password after adding SSH public key to a server

    - by Nathan Arthur
    I'm attempting to setup a git repository on my Dreamhost web server by following the "Setup: For the Impatient" instructions here. I'm having difficulty setting up public key access to the server. After successfully creating my public key, I ran the following command: cat ~/.ssh/[MY KEY].pub | ssh [USER]@[MACHINE] "mkdir ~/.ssh; cat >> ~/.ssh/authorized_keys" ...replacing the appropriate placeholders with the correct values. Everything seemed to go through fine. The server asked for my password, and, as far as I can tell, executed the command. There is indeed a ~/.ssh/authorized_keys file on the server. The problem: When I try to SSH into the server, it still asks for my password. My understanding is that it shouldn't be asking for my password anymore. What am I missing? EDIT: SSH -v Log: Macbook:~ michaeleckert$ ssh -v [USER]@[SERVER URL] OpenSSH_6.2p2, OSSLShim 0.9.8r 8 Dec 2011 debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: /etc/ssh_config line 53: Applying options for * debug1: Connecting to [SERVER URL] [[SERVER IP]] port 22. debug1: Connection established. debug1: identity file /Users/michaeleckert/.ssh/id_rsa type -1 debug1: identity file /Users/michaeleckert/.ssh/id_rsa-cert type -1 debug1: identity file /Users/michaeleckert/.ssh/id_dsa type -1 debug1: identity file /Users/michaeleckert/.ssh/id_dsa-cert type -1 debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_6.2 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.5p1 Debian-6+squeeze3 debug1: match: OpenSSH_5.5p1 Debian-6+squeeze3 pat OpenSSH_5* debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA [STRING OF NUMBERS AND LETTERS SEPARATED BY SEMI-COLONS] debug1: Host ‘[SERVER URL]' is known and matches the RSA host key. debug1: Found key in /Users/michaeleckert/.ssh/known_hosts:2 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/michaeleckert/.ssh/id_rsa debug1: Trying private key: /Users/michaeleckert/.ssh/id_dsa debug1: Next authentication method: password [USER]@[SERVER URL]'s password: debug1: Authentication succeeded (password). Authenticated to [SERVER URL] ([[SERVER IP]]:22). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Sending environment. debug1: Sending env LANG = en_US.UTF-8 Welcome to [SERVER URL] Any malicious and/or unauthorized activity is strictly forbidden. All activity may be logged by DreamHost Web Hosting. Last login: Sun Nov 3 12:04:21 2013 from [MY IP] [[SERVER NAME]]$

    Read the article

  • WebDriver with firefox-x11 on Mac

    - by binil
    I am trying to run a headless test for a web application using WebDriver on Mac OS X 10.6.3. My plan is to run firefox-x11 with Xvfb, but WebDriver is unable to launch firefox-x11. My code is: System.setProperty("webdriver.firefox.bin", "/opt/local/bin/firefox-x11-devel-standalone"); WebDriver browser = new FirefoxDriver(); try { browser.get("http://google.com"); } finally { browser.close(); } but this fails with: org.openqa.selenium.WebDriverException: Unable to start firefox cleanly. Exit value: 1 Ran from: [/opt/local/bin/firefox-x11-devel-standalone, --verbose, -silent] System info: os.name: 'Mac OS X', os.arch: 'x86_64', os.version: '10.6.3', java.version: '1.6.0_17' Driver info: driver.version: firefox at org.openqa.selenium.firefox.FirefoxBinary.copeWithTheStrangenessOfTheMac(FirefoxBinary.java:200) at org.openqa.selenium.firefox.FirefoxBinary.startProfile(FirefoxBinary.java:83) at org.openqa.selenium.firefox.FirefoxBinary.clean(FirefoxBinary.java:264) at org.openqa.selenium.firefox.FirefoxLauncher.startProfile(FirefoxLauncher.java:66) at org.openqa.selenium.firefox.internal.NewProfileExtensionConnection.<init>(NewProfileExtensionConnection.java:45) at org.openqa.selenium.firefox.internal.ExtensionConnectionFactory.connectTo(ExtensionConnectionFactory.java:44) When I manually launch /opt/local/bin/firefox-x11-devel-standalone from the terminal, it seems to work fine despite some harmless errors shown. So, I tried to patch the org.openqa.selenium.firefox.FirefoxBinary.copeWithTheStrangenessOfTheMac(ProcessBuilder) method to ignore the errors and exit value of 1. Now it proceeds further, but fails with: Caused by: org.openqa.selenium.WebDriverException: Failed to connect to binary FirefoxBinary(/opt/local/bin/firefox-x11-devel-standalone) on port 7055; process output follows: Xlib: extension "RANDR" missing on display "/tmp/launch-tElCRZ/org.x:0". Dynamic session lookup supported but failed: launchd did not provide a socket path, verify that org.freedesktop.dbus-session.plist is loaded! (firefox-bin:88837): Gtk-CRITICAL **: gtk_widget_has_screen: assertion `GTK_IS_WIDGET (widget)' failed ?Xlib: extension "RANDR" missing on display "/tmp/launch-tElCRZ/org.x:0". Dynamic session lookup supported but failed: launchd did not provide a socket path, verify that org.freedesktop.dbus-session.plist is loaded! (firefox-bin:88877): Gtk-CRITICAL **: gtk_widget_has_screen: assertion `GTK_IS_WIDGET (widget)' failed ? System info: os.name: 'Mac OS X', os.arch: 'x86_64', os.version: '10.6.3', java.version: '1.6.0_17' Driver info: driver.version: firefox at org.openqa.selenium.firefox.internal.NewProfileExtensionConnection.connectToBrowser(NewProfileExtensionConnection.java:60) at org.openqa.selenium.firefox.internal.NewProfileExtensionConnection.<init>(NewProfileExtensionConnection.java:49) at org.openqa.selenium.firefox.internal.ExtensionConnectionFactory.connectTo(ExtensionConnectionFactory.java:44) ... 4 more Caused by: org.openqa.selenium.firefox.NotConnectedException: Failed to start up socket within 45000 at org.openqa.selenium.firefox.internal.AbstractExtensionConnection.connectToBrowser(AbstractExtensionConnection.java:143) at org.openqa.selenium.firefox.internal.NewProfileExtensionConnection.connectToBrowser(NewProfileExtensionConnection.java:58) ... 6 more Has anyone got WebDriver to work with firefox-x11? This post seems to suggest that one person had got it working, but it does not contain much details.

    Read the article

  • How do I get the same key bindings in vmware's Window and Mac [closed]

    - by ragnarius
    I have a macbook but sometimes I run Windows in vmware to program in Visual Studio. I have a swedish keyboard, to get the curly brace '{' I press alt(=option)+shift+8 in mac, but to get the same character in vmware/windows I should press alt+7. Obviously, I would like to have the same keyboard layout in mac and windows, how can I make this happen? I have been recommended to use autohotkey on Windows, but I have a problem mapping AltGr shift 8 to a character (i.e. <^!+8:{ does not work) (I state the question in this forum because I think that only programmers can answer it, we are the only ones that use the characters []{} )

    Read the article

< Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >