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  • shell script stopped working --- need to rewrite?

    - by OopsForgotMyOtherUserName
    The script below worked on my Mac OS X. I'm now using Ubuntu OS, and the script is no longer working. I'm wondering if there's something that I need to change here? I did change the first line from #!/bin/bash to #!/bin/sh, but it's still throwing up an error.... Essentially, I get an error when I try to run it: Syntax error: end of file unexpected (expecting ")") #!/bin/sh REMOTE='ftp.example.com' USER='USERNAME' PASSWORD='PASSWORD' CMDFILE='/jtmp/rc.ftp' FTPLOG='/jtmp/ftplog' PATTERN='SampFile*' date > $FTPLOG rm $CMDFILE 2>/dev/null LISTING=$(ftp -in $REMOTE <<EOF user $USER $PASSWORD cd download ls $PATTERN quit EOF ) echo "open $REMOTE" >> $CMDFILE echo "user $USER $PASSWORD" >> $CMDFILE echo "verbose" >> $CMDFILE echo "bin" >> $CMDFILE echo "cd download" >> $CMDFILE for FILE in $LISTING do echo "get $FILE" >> $CMDFILE done echo "quit" >> $CMDFILE ftp -in < $CMDFILE >> $FTPLOG 2>&1 rm $CMDFILE

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  • Skipping a line and reading another line in shell script while loop

    - by parameswar
    i have a code which reads a file line by line using a while loop. Inside the while loop, i have certain conditions. Is there a way using which i can skip the current line and read the next line based upon the condition ? Let me be precise: while read Line do //some sample conditions a=$Line if [ "a" == "b" ] //i want to go to the next line from this point. done < **inputfile** Any help would be appreciated.

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  • Shell complains 'cannot execute binary file'

    - by Negai
    Hi everyone, I've playing around with linux and noticed that for some mysterious reason commands like '/bin/sh ' just will not work. Each time I'm trying to start a process it yields 'cannot execute binary file' error message. m@sanctuary:~$ sh sed /bin/sed: /bin/sed: cannot execute binary file When I first launch sh and try to execute sed, it succeeds. I'm starting to loose my wits. It would be just great, if somebody could help me. Thank you.

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  • Shell scripting and test expressions

    - by Paul
    Hi, I'm trying to test whether a directory path exists when a file is passed to my script. I use dirname to strip and save the path. I want my script to run only if the path exists. This is my attempt below. FILE=$1 DIRNAME=dirname $FILE if [ -z $DIRNAME ] ; then echo "Error no file path" exit 1 fi But this doesn't work. Actual when there is no file path dirname $FILE still returns "." to DIRNAME, i.e. this directory. So how do i distinguish between "." and "/bla/bla/bla". Thanks.

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  • Shell script for generating HTML out put

    - by user1638016
    The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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  • replace new lines with comas in shell

    - by mpapis
    I want to replace new lines in text with coma or space but do not change the last new line. I know of this question: How to replace new lines with tab characters - but it does produce an tab on end instead of new line. So far I have come with: awk 'NR>1{printf","} {printf $1} END{printf"\n"}' Is there an easier way to do this? This is not an assignment, I am just curious want to level up my scripting.

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  • Send mass emails php (probably a shell question?)

    - by Rob
    I've got 80,000 users on my site and i've recently turned away from the forum script i've been using and built something very simple myself that works just as well (the forum script was too bloated and resource intensive for my simple site) The only thing i've lost is the ability to mass email all my members. So i'm looking to come up with a script to do it myself. After looking around (including questions on here) I decided using Swift Mailer would be a good idea. However i've been through all the documentation and can't see how to send say "100 at a time" and i'm not sure how to go about it. To put it simply. I have an admin panel with a form with two inputs "subject" and "message". When I click submit what is the safest way for me to send 80,000 emails without crashing my server or being marked as spam? I'm on quite a beefy dedicated server so don't have the problems associated with shared servers. Thanks in advance for any advice!

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  • MacVim, Command-T: SEGV

    - by Ramon Tayag
    Details: OSX 10.7.4 I installed the latest MacVim via Homebrew: $ command-t brew install macvim ==> Downloading https://github.com/b4winckler/macvim/tarball/snapshot-64 Already downloaded: /Library/Caches/Homebrew/macvim-7.3-64.tgz ==> ./configure --with-features=huge --with-tlib=ncurses --enable-multibyte --with-macarchs=x86_64 --enable-perlinterp --enable-pythoninterp --enable-rubyinterp --enable-t ==> make getenvy ==> make ==> Caveats MacVim.app installed to: /usr/local/Cellar/macvim/7.3-64 To link the application to a normal Mac OS X location: brew linkapps or: ln -s /usr/local/Cellar/macvim/7.3-64/MacVim.app /Applications ==> Summary /usr/local/Cellar/macvim/7.3-64: 1733 files, 27M, built in 53 seconds $ command-t brew linkapps Linking /usr/local/Cellar/macvim/7.3-64/MacVim.app Finished linking. Find the links under ~/Applications. $ command-t ruby -v ruby 1.8.7 (2011-12-28 patchlevel 357) [universal-darwin11.0] $ command-t rvm list rvm rubies ree-1.8.7-2012.02 [ i686 ] ruby-1.8.7-p358 [ i686 ] ruby-1.9.2-p290 [ x86_64 ] ruby-1.9.2-p320 [ x86_64 ] ruby-1.9.3-p194 [ x86_64 ] # Default ruby not set. Try 'rvm alias create default <ruby>'. # => - current # =* - current && default # * - default $ command-t cd ~/.vim/bundle/vim-command-t/ruby/command-t ruby extconf.rb $ command-t ruby extconf.rb checking for ruby.h... yes creating Makefile $ command-t make cc -arch i386 -arch x86_64 -pipe -bundle -undefined dynamic_lookup -o ext.bundle ext.o match.o matcher.o -L. -L/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib -L. -arch i386 -arch x86_64 -lruby -lpthread -ldl -lobjc ld: warning: ignoring file ext.o, file was built for unsupported file format which is not the architecture being linked (i386) ld: warning: ignoring file match.o, file was built for unsupported file format which is not the architecture being linked (i386) ld: warning: ignoring file matcher.o, file was built for unsupported file format which is not the architecture being linked (i386) $ command-t mvim MacVim then opens here. But when I open Command-T, MacVim crashes and I see this in the command line: $ command-t dyld: lazy symbol binding failed: Symbol not found: _rb_intern2 Referenced from: /Users/ramon/.vim/bundle/vim-command-t/ruby/command-t/ext.bundle Expected in: flat namespace dyld: Symbol not found: _rb_intern2 Referenced from: /Users/ramon/.vim/bundle/vim-command-t/ruby/command-t/ext.bundle Expected in: flat namespace Vim: Caught deadly signal TRAP Vim: Finished. The problem I have is very similar to this, except that I switched to the system Ruby and still got the error.

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  • OS X: How can I copy the shell path to clipboard?

    - by lexu
    When working with files on my mac I employ a mixed approach of shell/finder or keyboard/mouse, similar to working with 4NT and Explorer on Windows. One thing I use(d) extensively on Windows is to copy the path of the current directory to the clipboard. This is an extended feature of TakeCommand by JPSoft, on Windows. Is there a way to copy the current path from the bash shell to the mac's clipboard, so I can use it in 'file open' and/or similar dialogues?

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  • grep --exclude/--include syntax (do not grep through certain files)

    - by Piskvor
    I'm looking for the string "foo=" (without quotes) in text files in a directory tree. It's on a common Linux machine, I have bash shell: grep -ircl "foo=" * In the directories are also many binary files which match "foo=". As these results are not relevant and slow down the search, I want grep to skip searching these files (mostly JPEG and PNG images): how would I do that? I know there are the --exclude=PATTERN and --include=PATTERN options, but what is the pattern format? manpage of grep says: --include=PATTERN Recurse in directories only searching file matching PATTERN. --exclude=PATTERN Recurse in directories skip file matching PATTERN. Searching on grep include, grep include exclude, grep exclude and variants did not find anything relevant If there's a better way of grepping only in certain files, I'm all for it; moving the offending files is not an option, I can't search only certain directories (the directory structure is a big mess, with everything everywhere). Also, I can't install anything, so I have to do with common tools (like grep or the suggested find). UPDATES: @Adam Rosenfield's answer is just what I was looking for: grep -ircl --exclude=*.{png,jpg} "foo=" * @rmeador's answer is also a good solution: grep -Ir --exclude="*\.svn*" "pattern" * It searches recursively, ignores binary files, and doesn't look inside Subversion hidden folders.(...)

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  • extract payload from tcpflow output

    - by Felipe Alvarez
    Tcpflow outputs a bunch of files, many of which are HTTP responses from a web server. Inside, they contain HTTP headers, including Content-type: , and other important ones. I'm trying to write a script that can extract just the payload data (i.e. image/jpeg; text/html; et al.) and save it to a file [optional: with an appropriate name and file extension]. The EOL chars are \r\n (CRLF) and so this makes it difficult to use in GNU distros (in my experiences). I've been trying something along the lines of: sed /HTTP/,/^$/d To delete all text from the the beginning of HTTP (incl) to the end of \r\n\r\n (incl) but I have found no luck. I'm looking for help from anyone with good experience in sed and/or awk. I have zero experience with Perl, please I'd prefer to use common GNU command line utilities for this Find a sample tcpflow output file here. Thanks, Felipe

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  • In-Proc SxS opens for shell extension in managed code?

    - by Jens Granlund
    The recommendation used to be "Do not write in-process shell extensions in managed code." But with .NET Framework 4 and In-Process Side-by-Side the main reason not to write shell extensions in managed code should be resolved. With that said, I have three questions. Is it now okay to write shell extensions in managed code? Which problems, if any might there be with writing shell extensions in managed code? What reasons might there be to write shell extensions in unmanaged code?

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  • How can I get the associated ref path for a git SHA?

    - by andreb
    Hi, I want to be able to pass anything to a git command (maybe its a SHA, maybe it's just something like "origin/master" or "devel/epxerimental" etc.) and git tells me the ref path of the branch that the passed something lives in, e.g. <git_command> 0dc27819b8e9 => output: refs/heads/master <git_command> xyz/test => output: refs/remotes/xyz/master ... I've been looking at git show or git log or git rev-parse and apart from --pretty=format:%d I couldn't find anything. (--pretty=format:%d output is quite strange with lotsa free space and empty lines and sometimes more than one ref paths are on one line bunched together). There has to be a better way? Thanks for reading. Andre

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  • Prevent Java from parsing the command line parameters

    - by User1
    Would like to make anapplication in Java that will not automatically parse parameters used on the command-line. Currently, java requires public static void main(string[]) as the entry point signature. I would like just a single string that I parse myself. Can this be done at all? Here's an example: java MyProgram.class Hello World I would want it to give me Hello World without requiring quotes around that string. I would even settle for java giving me the entire java MyProgram.class Hello World. I'm thinking this is something beyond Java and has more to do with the shell.

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  • Xcode "Build and Archive" from command line

    - by Dan Fabulich
    Xcode 3.2 provides an awesome new feature under the Build menu, "Build and Archive" which generates an .ipa file suitable for Ad Hoc distribution. You can also open the Organizer, go to "Archived Applications," and "Submit Application to iTunesConnect." Is there a way to use "Build and Archive" from the command line (as part of a build script)? I'd assume that xcodebuild would be involved somehow, but the man page doesn't seem to say anything about this.

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  • add a start up item via command line (mac)

    - by adam n
    How can I add a start up item via command line on a mac? From googling, I know you have to edit ~/Library/Preferences/com.apple.loginitems.plist using defaults write com.apple.loginitems [key] [value] but i'm not sure exactly which things to edit.

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  • How to handle crash from system command in Perl on windows

    - by Pete
    I am calling a command-line program from my perl script, when these programs crash, I am prompted with a messagebox asking me if I want to notify Microsoft. Since this is an automated system it would be desirable if I could suppress that message and continue with other things in my script. Is this possible?

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  • how to start growl via the command line

    - by adam n
    I have a bash script that uses growlnotify to send notifications. However, growlnotify doesn't work if Growl isn't already running, and it won't auto start Growl if it needs it, either. So I want to be able to check if Growl is running, and then start it if it isn't. I'm thinking of doing something like: g=$(ps -e | grep Growl | grep -v grep) if [ -z "$g" ] # Growl isn't running then # (start Growl) fi How would I start Growl via the command line?

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  • dos command flex core

    - by msaif
    can i execute some dos like command from flex just like attrib c:\a.txt -h. function available in c exec(), in java Runtime.getRuntime().exec(). but in flex is there any available?

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  • Java: Using Command line arguments to process the names of files

    - by Kat
    I'm a writing a program that will determine the number of lines, characters, and average word length for a text file. For the program, the specifications say that the file or files will be entered as a command line argument and that we should make a TestStatistic object for each file entered. I don't understand how to write the code for making the TestStatistic objects if the user enters more than one file.

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