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  • JSON object array to store data of a form in local storage temporary (PhoneGap project)

    - by Nadeesha
    I am building a data aqusition system using PhoneGap. .I am trying to store my form data temporary on local storage using JSON,Data should be visible after I close and reopen the application (after pressing Get Data button),But after I close it only the lastly entered record is visible This is my code <!DOCTYPE html> <html> <head> <title>Household Profile DB storage</title> <meta charset="utf-8"> <meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1,width=device-width" /> <link rel="stylesheet" href="jquery.mobile-1.4.2/jquery.mobile-1.4.2.min.css"> <link rel="stylesheet" href="css/table.css"> <script type="text/javascript" src="js/jquery-1.9.1.min.js"></script> <script type="text/javascript" src="jquery.mobile-1.4.2/jquery.mobile-1.4.2.min.js"></script> <script type="text/javascript" src="js/iscroll.js"></script> <script type="text/javascript" charset="utf-8"> function onDeviceReady() { persistData(homeId,owner,gramaND,contactNo,address,race); } function saveLocal(form){ if (window.localStorage) { var fhomeId = form.homeId.value, fowner = form.owner.value, fgramaND = form.gramaND.value, fcontactNo= form.contactNo.value, faddress = form.address.value, frace = form.race.value; alert("hi"); var highscores = [{"homeId": fhomeId, "owner":fowner, "gramaND":fgramaND, "contactNo":fcontactNo, "address":faddress, "race":frace}]; localStorage.setItem("highscores",JSON.stringify(highscores)); alert("The data has been stored successfully."); } else { alert("Your Browser does not support LocalStorage."); } } function readLocal(){ if (window.localStorage) { var scores =[]; //Get the highscores object scores = localStorage.getItem("highscores"); scores = JSON.parse(scores); for (i=0;i<scores.length;i++){ var text = "homeId :"+scores[i].homeId +"<br>"+ "owner:"+ scores[i].owner+"<br>"+ "address"+scores[i].address +"<br>"+ "gramaND"+scores[i].gramaND +"<br>"+ "contactNo"+scores[i].contactNo+"<br>" + '<Button value="DELETE" onclick="'+scores.splice(i, 0)+'><>/Button>'; var tbodyx = document.getElementsByTagName("tbody"); var tr=document.createElement("TR"); var td=document.createElement("TD"); td.innerHTML = text; tr.appendChild(td); tbody.appendChild(tr); } } } </script> </head> <body> <div data-role="page" id="page1"> <!--/header--> <div data-role="header" data-position="inline" data-theme="b"> <a href="#" data-icon="back" data-rel="back" title="Go back">Back</a> <h1>Household Profile</h1> <a href="index.html" data-icon="home">Menu</a> </div> <!--/header--> <div id="wrapper"> <form id="userInput" action ="" method="GET"> <div data-role="content"> <div data-role="fieldcontain"> <label > Home ID </label> <input class="inputClass" id="homeId" placeholder="H0001" value="" data-mini="true" type="text"> </div> <div data-role="fieldcontain"> <label > Owner </label> <input class="inputClass" id="owner" placeholder="Aberathne" value="" type="text"> </div> <div data-role="fieldcontain"> <label class="select">GramaNiladhari Division</label> <select class="inputClass" id="gramaND"> <option value="GramaNiladhari Division 1">GramaNiladhari Division 1</option> <option value="GramaNiladhari Division 2">GramaNiladhari Division 2</option> <option value="GramaNiladhari Division 3">GramaNiladhari Division 3</option> <option value="GramaNiladhari Division 4">GramaNiladhari Division 4</option> </select> </div> <div data-role="fieldcontain"> <label > Contact No </label> <input class="inputClass" id="contactNo" placeholder="071-9545-073" value="" type="number"> </div> <div data-role="fieldcontain"> <label >Address:</label> <textarea cols="40" rows="8" class="inputClass" id="address"></textarea> </div> <div class="ui-block-a"><button type="submit" data-theme="d">Location in a Map</button></div> <div data-role="fieldcontain"> <label >Race</label> <select class="inputClass" id="race"> <option value=" Sinhalese"> Sinhalese</option> <option value=" Sri Lanka Tamils"> Sri Lanka Tamils</option> <option value=" Moors"> Moors</option> <option value=" Indian Tamils "> Indian Tamils </option> <option value=" Malays "> Malays </option> <option value=" Burghers "> Burghers </option> </select> </div> <input class="buttonClass" type="button" value="Insert Data" onclick="saveLocal(this.form);"> </div> </form> </div> <input class="buttonClass" type="button" value="get Data" onclick="readLocal();"> <!-- <p id="dhomeId"></p> <p id="downer"></p> <p id="dgramaND"></p> <p id="dcontactNo"></p> <p id="daddress"></p> <p id="drace"></p>--> <table border="1"> <tbody id="tbody"> <tr><td>test1</td></tr> <tr><td>test2</td></tr> </tbody> </table> </div> </body> </html> Also I need to expand my code to edit and delete record from local storage.

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  • Question about JSON?

    - by Alex
    Hi all, I have a fairly simple question: In Javascript how can I return the boolean (if its found in the JSON) rather than the actual value? Example: var myJSON = { "foo" : "bar", "bar" : "foo" }; var keyToLookFor = "foo"; var found = myJSON[keyToLookFor]; if (found) { // I know I can test if the string exists in the if } // but is there a way I could just return something like: return found; // instead of testing found in the if statement and then returning true?

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  • Need help helping in converting jquery, ajax, json and asp.net

    - by Haja Mohaideen
    I am tying out this tutorial, http://www.ezzylearning.com/tutorial.aspx?tid=5869127. It works perfectly. What I am now trying to do is to host the aspx contents as html file. This html file is hosted on my wampserver which is on my laptop. The asp.net code hosted on my test server. When I try to access, I get the following error, Resource interpreted as Script but transferred with MIME type text/html: "http://201.x.x.x/testAjax/Default.aspx/AddProductToCart?callback=jQuery17103264484549872577_1346923699990&{%20pID:%20%226765%22,%20qty:%20%22100%22,%20lblType:%20%2220%22%20}&_=1346923704482". jquery.min.js:4 Uncaught SyntaxError: Unexpected token < I am not sure how to solve this problem. index.html code $(function () { $('#btnAddToCart').click(function () { var result = $.ajax({ type: "POST", url: "http://202.161.45.124/testAjax/Default.aspx/AddProductToCart", crossDomain: true, data: '{ pID: "6765", qty: "100", lblType: "20" }', contentType: "application/json; charset=utf-8", dataType: "jsonp", success: succeeded, failure: function (msg) { alert(msg); }, error: function (xhr, err) { alert(err); } }); }); }); function succeeded(msg) { alert(msg.d); } function btnAddToCart_onclick() { } </script> </head> <body> <form name="form1" method="post"> <div> <input type="button" id="btnAddToCart" onclick="return btnAddToCart_onclick()" value="Button" /> </div> </form> aspx.vb Imports System.Web.Services Imports System.Web.Script.Services <ScriptService()> Public Class WebForm1 Inherits Page Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Session("test") = "" End Sub <WebMethod()> <ScriptMethod(UseHttpGet:=False, ResponseFormat:=ResponseFormat.Json)> Public Shared Function AddProductToCart(pID As String, qty As String, lblType As String) As String Dim selectedProduct As String = String.Format("+ {0} - {1} - {2}", pID, qty, lblType) HttpContext.Current.Session("test") += selectedProduct Return HttpContext.Current.Session("test").ToString() End Function End Class

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  • parsing JSON in java ?

    - by bukuai
    How to parsing JSON in java? { "code": 100, "message": "SUCCESS", "result": { "list": [ { "cardNumber": "ALUFZZ5SZ1Q5", "expireTime": 1270742400, "surplusThreshold": 4, "uid": 771292, "useTime": 1270214375, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1QD", "expireTime": 1270828800, "surplusThreshold": 7, "uid": 784289, "useTime": 1270302200, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1RC", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 773664, "useTime": 1270300871, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1UM", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 779560, "useTime": 1270282841, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1VT", "expireTime": 1270656000, "surplusThreshold": 2, "uid": 754099, "useTime": 1270106775, "wareId": 1145 } ], "pageCount": 61, "pageIndex": 2, "pageSize": 5, "recordCount": 308 } }

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  • Retrieving data from a JSON sub array in javascript, where identifier starts with an integer

    - by Archie Ec
    I must be missing something simple here, but I'm having trouble retrieving data from a JSON array response. I can access objects with identifiers that start with letters, but not ones that start with numbers. For example, I can access data.item[0].specs.overview.details But I can't access data.item[0].specs.9a99.details If anyone can point me in the right direction, I'd really appreciate it. Thanks.

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  • using json object data in jquery select

    - by Ratna
    {"names": [ {"patientName": "Ratna"}, {"patientName": "raju" }, {"patientName": "krishna"}, {"patientName": "kishore"}, {"patientName": "Kishore1"}, {"patientName": "mahesh"} ]} this is the JSON object i'm getting from Ajax call so now i want to add all patientName values to select box through jquery can any one tell me how to accomplish this ?? here i'm using $.ajax() function for ajax call thanks in advance

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  • convert json string into array or object...

    - by qulzam
    I get some json data form the web which is like: [{"pk": 1, "model": "stock.item", "fields": {"style": "f/s", "name": "shirt", "color": "red", "sync": 1, "fabric_code": "0012", "item_code": "001", "size": "34"}}, {"pk": 2, "model": "stock.item", "fields": {"style": "febric", "name": "Trouser", "color": "red", "sync": 1, "fabric_code": "fabric code", "item_code": "0123", "size": "44"}}] How can i use it in the C# winforms desktop application. I already get this data in the form of string. All types of answer are welcome.

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  • DataContractJsonSerializer generating Ghost string to JSON keys?

    - by Anil Namde
    DataContractJsonSerializer this is nice class added in the .net framework which can be used to serialize/desirealize object into JSON. Now following is the example i am trying [Serializable] class User { public string name; public string userId; } Now following is the output generated Output : Notice structure where only "name" is expected instead of k__BackingField Now this is the problem after digging so much i am not sure from where < and _BackingField is coming ? { "<name>k__BackingField":"test user", "<userId>k__BackingField":100001}

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  • How to get data source for Spring Security Web in Java code

    - by user1443689
    I'm creating a ZK Web application which uses Spring Security for authentication and I'm trying to implement a create user function, where the administrator supplies the details and the user account is created. I've got to the part where I want to put this data into the database, but now I'm thinking I shouldn't hard code the connection to the database, there must be a way to get the connection details from the Spring Security configuration. Is there? If so how?

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  • Spring Framework 3.0.5 MVC Issue

    - by user578923
    I know that this may be absolutely dumb but for the life of me I cannot figure out why I'm getting these errors in my Spring Project, it is basically from the MVC tutorial with a few modifications. This is the error I get when running my tomcat server. `Caused by: java.lang.NoClassDefFoundError: org/springframework/web/servlet/mvc/SimpleFormController at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:634) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142) at java.net.URLClassLoader.defineClass(URLClassLoader.java:277) at java.net.URLClassLoader.access$000(URLClassLoader.java:73) at java.net.URLClassLoader$1.run(URLClassLoader.java:212) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1581) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1511) at org.springframework.util.ClassUtils.forName(ClassUtils.java:257) at org.springframework.beans.factory.support.AbstractBeanDefinition.resolveBeanClass(AbstractBeanDefinition.java:408) at org.springframework.beans.factory.support.AbstractBeanFactory.doResolveBeanClass(AbstractBeanFactory.java:1271) at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1242) ... 54 more Caused by: java.lang.ClassNotFoundException: org.springframework.web.servlet.mvc.SimpleFormController at java.net.URLClassLoader$1.run(URLClassLoader.java:217) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) ... 71 more` I just cannot figure out the issue with my classpath...I would appreciate any help. Here are all the jars in my classpath. I know that the class is inside the web-servlet jar but it's not seeing it. Is there a conflict? aopalliance.jar aspectjweaver.jar commons-codec.jar commons-dbcp.jar commons-logging.jar commons-pool.jar jstl.jar org.springframework.aop-3.0.5.RELEASE.jar org.springframework.asm-3.0.5.RELEASE.jar org.springframework.aspects-3.0.5.RELEASE.jar org.springframework.beans-3.0.5.RELEASE.jar org.springframework.context.support-3.0.5.RELEASE.jar org.springframework.context-3.0.5.RELEASE.jar org.springframework.core-3.0.5.RELEASE.jar org.springframework.expression-3.0.5.RELEASE.jar org.springframework.instrument.tomcat-3.0.5.RELEASE.jar org.springframework.instrument-3.0.5.RELEASE.jar org.springframework.jdbc-3.0.5.RELEASE.jar org.springframework.jms-3.0.5.RELEASE.jar org.springframework.orm-3.0.5.RELEASE.jar org.springframework.oxm-3.0.5.RELEASE.jar org.springframework.test-3.0.5.RELEASE.jar org.springframework.transaction-3.0.5.RELEASE.jar org.springframework.web.portlet-3.0.5.RELEASE.jar org.springframework.web.servlet-3.0.5.RELEASE.jar org.springframework.web.struts-3.0.5.RELEASE.jar org.springframework.web-3.0.5.RELEASE.jar postgresql-9.0-801.jdbc3.jar servlet-api.jar spring-security-config-3.0.5.RELEASE.jar spring-security-core-3.0.5.RELEASE.jar spring-security-web-3.0.5.RELEASE.jar standard.jar

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  • Need to Post json data using jQuery.ajax

    - by Anil Bhat
    I have a json of the following format which I need to send in the Ajax request through POST method: { “gbus”: [ { "code": "*" } ], “regions”: [ { "code": "*" } ], “offices”: [ { "code": "*" } ], “contracttypes”: [ { "code": "*" } ], “jobnumbers”: [ { "code": "*" } ], “disciplines”: [ { "code": "*" } ] } Its not working for me, giving 500 error always when I try to submit it. Please suggest if you have any idea.

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  • MVC JSON ViewData Question

    - by user325142
    Can ViewData be set & returned in an ActionResult that returns Json() ? Im asking because It's not working for me but when I put the same ViewData code into a Action method that returns a View() it works? Thanks

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  • Status messages on the Spring MVC-based site (annotation controller)

    - by linpulee
    What is the best way to organize status messages on the Spring MVC-based site? I mean messages which, for example, returns when user has sent What is the best way to organize status messages ("Your data has been successfully saved/added/deleted") on the Spring MVC-based site using annotation controller? So, the issue is in the way of sending the message from POST-method in contoller.

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  • @Transactional in Spring+Hibernate

    - by Arun Kumar
    I an using Spring 3.1 + Hibernate 4.x in my web application. In my DAO, i am saving User type object as following sessionFactory.getCurrentSession().save(user); But getting following exception: org.hibernate.HibernateException: save is not valid without active transaction I googled and found similar question on SO, with following solution: Session session=getSessionFactory().getCurrentSession(); Transaction trans=session.beginTransaction(); session.save(entity); trans.commit(); That solves the problem. But in that solution, there is lot of mess of beginning and committing the transactions manually. Can't i use sessionFactory.getCurrentSession().save(user); directly without begin/commit of transactions manually? I try to use @Transactional on my service/dao methods too, but the problem persists. EDIT : Here is my Hibernate Config File: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.1.xsd"> <!-- enable the configuration of transactional behavior based on annotations --> <tx:annotation-driven transaction-manager="txManager"/> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource" p:driverClassName="${db.driverClassName}" p:url="${db.url}" p:username="${db.username}" p:password="${db.password}" /> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="packagesToScan" value="com.myapp.entities" /> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <!--Transaction Manager Added --> <bean id="txManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory"> <ref bean="sessionFactory" /> </property> </bean> </beans> Please help.

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  • Python | How to send a JSON response with name assign to it

    - by MMRUser
    How can I return an response (lets say an array) to the client with a name assign to it form a python script. echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; in this scenario it returns an array with the name(jsonValidateReturn) assign to it also this can be accessed by jsonValidateReturn[1],so I want to do the same using a python script. I tried it once but it didn't go well array_to_js = [vld_id, vld_error, False] array_to_js[2] = False jsonValidateReturn = simplejson.dumps(array_to_js) return HttpResponse(jsonValidateReturn, mimetype='application/json') Thanks.

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