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  • issue when outputting an http:// address in a sub-array with json and php

    - by Patrick
    Im trying to achieve an output like this {"status":"ok","0":{"id":"11","title":"digg","url":"http://www.digg.com"}} but instead i am getting this {"status":"ok","0":{"id":"11","title":"digg","url":"http:\/\/www.digg.com"}} this is the php code im using to generate the json $links = array('id'=>'11','title'=>'digg','url'=>"http://www.digg.com"); $msg = array('status'=>'ok',$links); echo json_encode($msg); any idea what is causing this?

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  • Profiling a Java Spring application

    - by niklassaers
    Hi guys, I have a Spring application that I believe has some bottlenecks, so I'd like to run it with a profiler to measure what functions take how much time. Any recommendations to how I should do that? I'm running STS, the project is a maven project, and I'm running Spring 3.0.1 Cheers Nik

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  • Question about JSON?

    - by Alex
    Hi all, I have a fairly simple question: In Javascript how can I return the boolean (if its found in the JSON) rather than the actual value? Example: var myJSON = { "foo" : "bar", "bar" : "foo" }; var keyToLookFor = "foo"; var found = myJSON[keyToLookFor]; if (found) { // I know I can test if the string exists in the if } // but is there a way I could just return something like: return found; // instead of testing found in the if statement and then returning true?

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  • parsing JSON in java ?

    - by bukuai
    How to parsing JSON in java? { "code": 100, "message": "SUCCESS", "result": { "list": [ { "cardNumber": "ALUFZZ5SZ1Q5", "expireTime": 1270742400, "surplusThreshold": 4, "uid": 771292, "useTime": 1270214375, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1QD", "expireTime": 1270828800, "surplusThreshold": 7, "uid": 784289, "useTime": 1270302200, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1RC", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 773664, "useTime": 1270300871, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1UM", "expireTime": 1270828800, "surplusThreshold": 10, "uid": 779560, "useTime": 1270282841, "wareId": 1145 }, { "cardNumber": "ALUFZZ5SZ1VT", "expireTime": 1270656000, "surplusThreshold": 2, "uid": 754099, "useTime": 1270106775, "wareId": 1145 } ], "pageCount": 61, "pageIndex": 2, "pageSize": 5, "recordCount": 308 } }

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  • Retrieving data from a JSON sub array in javascript, where identifier starts with an integer

    - by Archie Ec
    I must be missing something simple here, but I'm having trouble retrieving data from a JSON array response. I can access objects with identifiers that start with letters, but not ones that start with numbers. For example, I can access data.item[0].specs.overview.details But I can't access data.item[0].specs.9a99.details If anyone can point me in the right direction, I'd really appreciate it. Thanks.

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  • DataContractJsonSerializer generating Ghost string to JSON keys?

    - by Anil Namde
    DataContractJsonSerializer this is nice class added in the .net framework which can be used to serialize/desirealize object into JSON. Now following is the example i am trying [Serializable] class User { public string name; public string userId; } Now following is the output generated Output : Notice structure where only "name" is expected instead of k__BackingField Now this is the problem after digging so much i am not sure from where < and _BackingField is coming ? { "<name>k__BackingField":"test user", "<userId>k__BackingField":100001}

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  • convert json string into array or object...

    - by qulzam
    I get some json data form the web which is like: [{"pk": 1, "model": "stock.item", "fields": {"style": "f/s", "name": "shirt", "color": "red", "sync": 1, "fabric_code": "0012", "item_code": "001", "size": "34"}}, {"pk": 2, "model": "stock.item", "fields": {"style": "febric", "name": "Trouser", "color": "red", "sync": 1, "fabric_code": "fabric code", "item_code": "0123", "size": "44"}}] How can i use it in the C# winforms desktop application. I already get this data in the form of string. All types of answer are welcome.

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  • using json object data in jquery select

    - by Ratna
    {"names": [ {"patientName": "Ratna"}, {"patientName": "raju" }, {"patientName": "krishna"}, {"patientName": "kishore"}, {"patientName": "Kishore1"}, {"patientName": "mahesh"} ]} this is the JSON object i'm getting from Ajax call so now i want to add all patientName values to select box through jquery can any one tell me how to accomplish this ?? here i'm using $.ajax() function for ajax call thanks in advance

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  • How to get data source for Spring Security Web in Java code

    - by user1443689
    I'm creating a ZK Web application which uses Spring Security for authentication and I'm trying to implement a create user function, where the administrator supplies the details and the user account is created. I've got to the part where I want to put this data into the database, but now I'm thinking I shouldn't hard code the connection to the database, there must be a way to get the connection details from the Spring Security configuration. Is there? If so how?

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  • Need to Post json data using jQuery.ajax

    - by Anil Bhat
    I have a json of the following format which I need to send in the Ajax request through POST method: { “gbus”: [ { "code": "*" } ], “regions”: [ { "code": "*" } ], “offices”: [ { "code": "*" } ], “contracttypes”: [ { "code": "*" } ], “jobnumbers”: [ { "code": "*" } ], “disciplines”: [ { "code": "*" } ] } Its not working for me, giving 500 error always when I try to submit it. Please suggest if you have any idea.

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  • Spring Framework 3.0.5 MVC Issue

    - by user578923
    I know that this may be absolutely dumb but for the life of me I cannot figure out why I'm getting these errors in my Spring Project, it is basically from the MVC tutorial with a few modifications. This is the error I get when running my tomcat server. `Caused by: java.lang.NoClassDefFoundError: org/springframework/web/servlet/mvc/SimpleFormController at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:634) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:142) at java.net.URLClassLoader.defineClass(URLClassLoader.java:277) at java.net.URLClassLoader.access$000(URLClassLoader.java:73) at java.net.URLClassLoader$1.run(URLClassLoader.java:212) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1581) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1511) at org.springframework.util.ClassUtils.forName(ClassUtils.java:257) at org.springframework.beans.factory.support.AbstractBeanDefinition.resolveBeanClass(AbstractBeanDefinition.java:408) at org.springframework.beans.factory.support.AbstractBeanFactory.doResolveBeanClass(AbstractBeanFactory.java:1271) at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1242) ... 54 more Caused by: java.lang.ClassNotFoundException: org.springframework.web.servlet.mvc.SimpleFormController at java.net.URLClassLoader$1.run(URLClassLoader.java:217) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:205) at java.lang.ClassLoader.loadClass(ClassLoader.java:321) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:294) at java.lang.ClassLoader.loadClass(ClassLoader.java:266) ... 71 more` I just cannot figure out the issue with my classpath...I would appreciate any help. Here are all the jars in my classpath. I know that the class is inside the web-servlet jar but it's not seeing it. Is there a conflict? aopalliance.jar aspectjweaver.jar commons-codec.jar commons-dbcp.jar commons-logging.jar commons-pool.jar jstl.jar org.springframework.aop-3.0.5.RELEASE.jar org.springframework.asm-3.0.5.RELEASE.jar org.springframework.aspects-3.0.5.RELEASE.jar org.springframework.beans-3.0.5.RELEASE.jar org.springframework.context.support-3.0.5.RELEASE.jar org.springframework.context-3.0.5.RELEASE.jar org.springframework.core-3.0.5.RELEASE.jar org.springframework.expression-3.0.5.RELEASE.jar org.springframework.instrument.tomcat-3.0.5.RELEASE.jar org.springframework.instrument-3.0.5.RELEASE.jar org.springframework.jdbc-3.0.5.RELEASE.jar org.springframework.jms-3.0.5.RELEASE.jar org.springframework.orm-3.0.5.RELEASE.jar org.springframework.oxm-3.0.5.RELEASE.jar org.springframework.test-3.0.5.RELEASE.jar org.springframework.transaction-3.0.5.RELEASE.jar org.springframework.web.portlet-3.0.5.RELEASE.jar org.springframework.web.servlet-3.0.5.RELEASE.jar org.springframework.web.struts-3.0.5.RELEASE.jar org.springframework.web-3.0.5.RELEASE.jar postgresql-9.0-801.jdbc3.jar servlet-api.jar spring-security-config-3.0.5.RELEASE.jar spring-security-core-3.0.5.RELEASE.jar spring-security-web-3.0.5.RELEASE.jar standard.jar

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  • MVC JSON ViewData Question

    - by user325142
    Can ViewData be set & returned in an ActionResult that returns Json() ? Im asking because It's not working for me but when I put the same ViewData code into a Action method that returns a View() it works? Thanks

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  • Status messages on the Spring MVC-based site (annotation controller)

    - by linpulee
    What is the best way to organize status messages on the Spring MVC-based site? I mean messages which, for example, returns when user has sent What is the best way to organize status messages ("Your data has been successfully saved/added/deleted") on the Spring MVC-based site using annotation controller? So, the issue is in the way of sending the message from POST-method in contoller.

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  • Python | How to send a JSON response with name assign to it

    - by MMRUser
    How can I return an response (lets say an array) to the client with a name assign to it form a python script. echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; in this scenario it returns an array with the name(jsonValidateReturn) assign to it also this can be accessed by jsonValidateReturn[1],so I want to do the same using a python script. I tried it once but it didn't go well array_to_js = [vld_id, vld_error, False] array_to_js[2] = False jsonValidateReturn = simplejson.dumps(array_to_js) return HttpResponse(jsonValidateReturn, mimetype='application/json') Thanks.

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  • @Transactional in Spring+Hibernate

    - by Arun Kumar
    I an using Spring 3.1 + Hibernate 4.x in my web application. In my DAO, i am saving User type object as following sessionFactory.getCurrentSession().save(user); But getting following exception: org.hibernate.HibernateException: save is not valid without active transaction I googled and found similar question on SO, with following solution: Session session=getSessionFactory().getCurrentSession(); Transaction trans=session.beginTransaction(); session.save(entity); trans.commit(); That solves the problem. But in that solution, there is lot of mess of beginning and committing the transactions manually. Can't i use sessionFactory.getCurrentSession().save(user); directly without begin/commit of transactions manually? I try to use @Transactional on my service/dao methods too, but the problem persists. EDIT : Here is my Hibernate Config File: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.1.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.1.xsd"> <!-- enable the configuration of transactional behavior based on annotations --> <tx:annotation-driven transaction-manager="txManager"/> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource" p:driverClassName="${db.driverClassName}" p:url="${db.url}" p:username="${db.username}" p:password="${db.password}" /> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="packagesToScan" value="com.myapp.entities" /> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <!--Transaction Manager Added --> <bean id="txManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory"> <ref bean="sessionFactory" /> </property> </bean> </beans> Please help.

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  • Configuring servlet for using spring

    - by dominolog
    Hello How to configure my web application in Eclipse (based on Servlets and deployed to Tomcat) to use Spring framework. I need only IoC container (Beans only and ApplicationContext), not Spring MVC. How to configure web.xml for this? Regards

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