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  • Where can you find good examples of an End-User Software License?

    - by JFV
    Should I create my own End-User Software License (with a lawyer), or are there some good examples of one on the Internet? I'm getting close to rolling out my first Windows-based program for my side-business. I would like to have the end-users to agree not to: resell the software, change/modify it, use it in another application, etc. Any and all help appreciated! Thanks! JFV

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  • Drupal menu permissions question

    - by Luke
    I'm creating an admin module for my client that gives then access to some administration functionality concerning their content. I'm starting off my adding some permissions in my module by implementing hook_perm: function mymodule_perm() { return array( 'manage projects', ); } I can then create my menu by adding to the admin section that already exists: function mymodule_menu() { $items['admin/projects'] = array( 'title' => 'Projects', 'description' => 'Manage your projects.', 'page callback' => 'manage_projects_overview', 'access callback' => 'user_access', 'access arguments' => array('manage projects'), 'type' => MENU_NORMAL_ITEM, 'weight' => -100, ); $items['admin/projects/add'] = array( 'title' => 'Add project', 'access arguments' => array('manage projects'), 'page callback' => 'mymodule_projects_add', 'type' => MENU_NORMAL_ITEM, 'weight' => 1, ); return $items; } This will add a Projects section to the Administration area with an Add project sub section. All good. The behavior I want is that my client can only see the Projects section when they log in. I've accomplished this by ticking the "manage projects" permission for authenticated users. Now to give my client actual access to the Administration area I also need to tick "access administration pages" under the "system module" in the users permissions section. This works great, when I log in as my client I can only see the Projects section in the Administration area. There is one thing though, I my Navigation menu shown in the left column I can see the following items: - Administer - Projects - Content management - Site building - Site configuration - User management I was expecting only the see Administer and Projects, not the other ones. When I click e.g. Content Management I get a Content Management titled page with no options. Same for Site Building, Site Configuration and User Management. What's really odd is that Reports is not being shown which is also a top level Administration section. Why are these other items, besides my Projects section, being shown and how can I make them stop from appearing if I'm not logged in as administrator?

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  • Retrieve all user from domain

    - by user268515
    Hi my idea is to retrieve all users from google app domain using java. I retrieved all the user using Provisioning api but when i tried to store the data in the table using JPA its returning time out Error.... I dont know how to store the entire details at a stretch. Please Help me... Regards, sharun.

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  • download file on zend framework

    - by user1400
    hello all i am using upload files to server in my application, it works fine , i want other users could download these file ,but i get error i create a upload folder in public folder and i upload my files in upload folder now when i create a link (<a href="http://mytest/public/1.jpg">download image</a>) to these files i get error "The requested URL /public/upload/1.jpg was not found on this server." any one may help please? thanks

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  • Realtime MySQL search results on an advanced search page

    - by Andrew Heath
    I'm a hobbyist, and started learning PHP last September solely to build a hobby website that I had always wished and dreamed another more competent person might make. I enjoy programming, but I have little free time and enjoy a wide range of other interests and activities. I feel learning PHP alone can probably allow me to create 98% of the desired features for my site, but that last 2% is awfully appealing: The most powerful tool of the site is an advanced search page that picks through a 1000+ record game scenario database. Users can data-mine to tremendous depths - this advanced page has upwards of 50 different potential variables. It's designed to allow the hardcore user to search on almost any possible combination of data in our database and it works well. Those who aren't interested in wading through the sea of options may use the Basic Search, which is comprised of the most popular parts of the Advanced search. Because the advanced search is so comprehensive, and because the database is rather small (less than 1,200 potential hits maximum), with each variable you choose to include the likelihood of getting any qualifying results at all drops dramatically. In my fantasy land where I can wield AJAX as if it were Excalibur, my users would have a realtime Total Results counter in the corner of their screen as they used this page, which would automatically update its query structure and report how many results will be displayed with the addition of each variable. In this way it would be effortless to know just how many variables are enough, and when you've gone and added one that zeroes out the results set. A somewhat similar implementation, at least visually, would be the Subtotal sidebar when building a new custom computer on IBuyPower.com For those of you actually still reading this, my question is really rather simple: Given the time & ability constraints outlined above, would I be able to learn just enough AJAX (or whatever) needed to pull this one feature off without too much trouble? would I be able to more or less drop-in a pre-written code snippet and tweak to fit? or should I consider opening my code up to a trusted & capable individual in the future for this implementation? (assuming I can find one...) Thank you.

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  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

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  • New table for every user?

    - by SonOfOmer
    Hi everyone, I want to crate new table for each new user on the web site and I assume that there will be many users, I am sure that search performance will be good, but what is with maintenance?? It is MySQL which has no limit in number of tables. Thanks a lot.

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  • Using json_encode on objects in PHP

    - by Alan
    Hi, I'm trying to output lists of objects as json and would like to know if there's a way to make objects usable to json_encode? The code I've got looks something like $related = $user->getRelatedUsers(); echo json_encode($related); Right now, I'm just iterating through the array of users and individually exporting them into arrays for json_encode to turn into usable json for me. I've already tried making the objects iterable, but json_encode just seems to skip them anyway.

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  • Captcha in my Joomla site it not blocking spam robots.

    - by jax
    In my joomla install I have removed the email registration and instead added a Captcha field to the PHP code using the recaptcha.net method. For some reason I am still getting what I think are spam users (robots) but I don't know how they would get around the Captcha field. Anything I should check?

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  • how can I easily upload outlook contacts into my web application?

    - by Angela
    Hi, I am trying to find a way for our users to very easily upload their outlook contacts into our web application (mysql database). I'm not sure where to begin. I've seen various tools which are pretty complex. I am open to existing third-party solutions, but my hope is that there is something which is very simple to use or build. Thanks. PS: Ideally, it would not involve using visual basic.

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  • Nodejs: Change working directory when running node bin script

    - by user2433617
    I am trying to change the working directory when my nodejs script is run from a bin script. So simplified I have something like: #!/usr/bin/env node process.cd('/Users') When I then run this command like ./bin/nodefile it exits but stays in the same directory it started in. I have also tried shelljs, What is the best way to do this? I understand it's working but it's just in a separate process. Thanks.

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  • Can I dynamically embed fonts in Flex?

    - by Tam
    I'm wondering if I can dynamically embed fonts in Flex. I want to embed different fonts for different users so I don't want to embed all possible fonts in the same Flex file. If it's possible could you please post sample code.

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  • Uploading files to a server that has Real Time Antivirus scan running

    - by zecougar
    I need to allow users to upload files onto a server that has an antivirus program running with real-time scanning switched on. What would be a good design to ensure that infected files are not uploaded to the server. Questions - would large files be copied onto disk and then immediately scanned, or would they be scanned as they are copied and not allowed to appear on disk if infected Should i build a seperate infrastructure around this to specifically ionvoke a scan on the copied file ? this might be an issue if the file is deleted through the real-time scan

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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