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• I need help with a SQL query. Fetching an entry, it's most recent revision and it's fields.

  - by Tigger ate my dad

  Hi there, I'm building a CMS for my own needs, and finished planning my database layout. Basically I am abstracting all possible data-models into "sections" and all entries into one table. The final layout is as follows: Database diagram: I have yet to be allowed to post images, so here is a link to a diagram of my database. Entries (section_entries) are children of their section (sections). I save all edits to the entries in a new revision (section_entries_revisions), and also track revisions on the sections (section_revisions), in order to match the values of a revision, to the fields of the section that existed when the entry-revision was made. The section-revisions can have a number of fields (section_revision_fields) that define the attributes of entries in the section. There is a many-to-many relationship between the fields (section_revision_fields) and the entry-revisions (section_entry_revisions), that stores the values of the attributes defined by the section revision. Feel free to ask questions if the diagram is confusing. Now, this is the most complex SQL I've ever worked with, and the task of fetching my data is a little daunting. Basically what i want help with, is fetching an entry, when the only known variables are; section_id, section_entry_id. The query should fetch the most recent revision of that entry, and the section_revision model corresponding to section_revision_id in the section_entry_revisions table. It should also fetch the values of the fields in the section-revision. I was hoping for a query result, where there would be as many rows as fields in the section. Each row would contain the information of the entry and the section, and then information for one of the fields (e.g. each row corresponding to a field and it's value). I tried to explain the best I could. Again, feel free to ask questions if my description somehow lacking. I hope someone is up for the challenge. Best regards. :-)

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• Recursive t-sql query

  - by stackoverflowuser

  Hi I have a table as shown below. ID ParentID Node Name Node Type ------------------------------------------------------------------ 525 524 Root Area Level 1 526 525 C Area Level 2 527 525 A Area Level 2 528 525 D Area Level 2 671 525 E Area Level 2 660 527 B Area Level 3 672 671 F Area Level 3 How can i write a recursive t-sql query to generate below output? Output ("Root" node not required in the output): Node ID ----------------------- A 527 A/B 660 C 526 D 528 E 671 E/F 672 Thanks

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• How to move a google doc into a folder using Zend Gdata

  - by Andre

  Hi Guys I am really struggling with moving a document from my root folder to another folder using zend gdata here is how i am trying to do it, but its not working. $service = Zend_Gdata_Docs::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($gUser, $gPass, $service); $link = "https://docs.google.com/feeds/documents/private/full/spreadsheet:0AUFNVEpLOVg2U0E"; // Not real id for privacy purposes $docs = new Zend_GData_Docs($client); // Attach a category object of folder to this entry // I have tried many variations of this including attaching label categories $cat = new Zend_Gdata_App_Extension_Category('My Folder Name','http://schemas.google.com/docs/2007#folder'); $entry = $docs->getDocumentListEntry($link); $entry->setCategory(array($cat)); $return = $docs->updateEntry($entry,$entry->getEditLink()->href); When I run this I get No errors, but nothing seems to change, and the return data does not contain the new category. EDIT: Ok I realised that its not the category but the link that decides which "collection" (folder) a resource belongs too. https://developers.google.com/google-apps/documents-list/#managing_collections_and_their_contents says that each resource has as et of parent links, so I tried changing my code to do set link instead of set category, but this did not work. $folder = "https://docs.google.com/feeds/documents/private/full/folder%3A0wSFA2WHc"; $rel = "http://schemas.google.com/docs/2007#parent"; $linkObj = new Zend_Gdata_App_Extension_Link($folder,$rel,'application/atom+xml', NULL,'Folder Name'); $links = $entry->getLink(); array_push($links,$linkObj); $entry->setLink($links); $return = $docs->updateEntry($entry,$entry->getEditLink()->href); EDIT: SOLVED [nearly] OK Here is how to move/copy, sort of, from one folder to another: simpler than initially thought, but problem is it creates a reference and NOT a move! It now in both places at the same time.... // Folder you wnat to move too $folder = "https://docs.google.com/feeds/folders/private/full/folder%asdsad"; $data = $docs->insertDocument($entry, $folder); // Entry is the entry you want moved using insert automatically assigns link & category for you...

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• Copy all files and folder from one directory to another directory PHP

  - by santosh

  Hi, I have directory called "mysourcedir" it has sonme files and folders. so i want to copy all content from this directory to some other "destinationfolder" on Linux server using PHP. function full_copy( $source, $target ) { if ( is_dir( $source ) ) { @mkdir( $target ); $d = dir( $source ); while ( FALSE !== ( $entry = $d->read() ) ) { if ( $entry == '.' || $entry == '..' ) { continue; } $Entry = $source . '/' . $entry; if ( is_dir( $Entry ) ) { $this->full_copy( $Entry, $target . '/' . $entry ); continue; } copy( $Entry, $target . '/' . $entry ); } $d->close(); }else { copy( $source, $target ); } } I am trying this code, but it does some problem, it creates directory "mysourcedir" at destination location. I am expecting to just copy all files and folders at destination,. Please suggest

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• How to select all parent objects into DataContext using single LINQ query ?

  - by too

  I am looking for an answer to a specific problem of fetching whole LINQ object hierarchy using single SELECT. At first I was trying to fill as much LINQ objects as possible using LoadOptions, but AFAIK this method allows only single table to be linked in one query using LoadWith. So I have invented a solution to forcibly set all parent objects of entity which of list is to be fetched, although there is a problem of multiple SELECTS going to database - a single query results in two SELECTS with the same parameters in the same LINQ context. For this question I have simplified this query to popular invoice example: public static class Extensions { public static IEnumerable<T> ForEach<T>(this IEnumerable<T> collection, Action<T> func) { foreach(var c in collection) { func(c); } return collection; } } public IEnumerable<Entry> GetResults(AppDataContext context, int CustomerId) { return ( from entry in context.Entries join invoice in context.Invoices on entry.EntryInvoiceId equals invoice.InvoiceId join period in context.Periods on invoice.InvoicePeriodId equals period.PeriodId // LEFT OUTER JOIN, store is not mandatory join store in context.Stores on entry.EntryStoreId equals store.StoreId into condStore from store in condStore.DefaultIfEmpty() where (invoice.InvoiceCustomerId = CustomerId) orderby entry.EntryPrice descending select new { Entry = entry, Invoice = invoice, Period = period, Store = store } ).ForEach(x => { x.Entry.Invoice = Invoice; x.Invoice.Period = Period; x.Entry.Store = Store; } ).Select(x => x.Entry); } When calling this function and traversing through result set, for example: var entries = GetResults(this.Context); int withoutStore = 0; foreach(var k in entries) { if(k.EntryStoreId == null) withoutStore++; } the resulting query to database looks like (single result is fetched): SELECT [t0].[EntryId], [t0].[EntryInvoiceId], [t0].[EntryStoreId], [t0].[EntryProductId], [t0].[EntryQuantity], [t0].[EntryPrice], [t1].[InvoiceId], [t1].[InvoiceCustomerId], [t1].[InvoiceDate], [t1].[InvoicePeriodId], [t2].[PeriodId], [t2].[PeriodName], [t2].[PeriodDateFrom], [t4].[StoreId], [t4].[StoreName] FROM [Entry] AS [t0] INNER JOIN [Invoice] AS [t1] ON [t0].[EntryInvoiceId] = [t1].[InvoiceId] INNER JOIN [Period] AS [t2] ON [t2].[PeriodId] = [t1].[InvoicePeriodId] LEFT OUTER JOIN ( SELECT 1 AS [test], [t3].[StoreId], [t3].[StoreName] FROM [Store] AS [t3] ) AS [t4] ON [t4].[StoreId] = ([t0].[EntryStoreId]) WHERE (([t1].[InvoiceCustomerId]) = @p0) ORDER BY [t0].[InvoicePrice] DESC -- @p0: Input Int (Size = 0; Prec = 0; Scale = 0) [186] -- Context: SqlProvider(Sql2008) Model: AttributedMetaModel Build: 3.5.30729.1 SELECT [t0].[EntryId], [t0].[EntryInvoiceId], [t0].[EntryStoreId], [t0].[EntryProductId], [t0].[EntryQuantity], [t0].[EntryPrice], [t1].[InvoiceId], [t1].[InvoiceCustomerId], [t1].[InvoiceDate], [t1].[InvoicePeriodId], [t2].[PeriodId], [t2].[PeriodName], [t2].[PeriodDateFrom], [t4].[StoreId], [t4].[StoreName] FROM [Entry] AS [t0] INNER JOIN [Invoice] AS [t1] ON [t0].[EntryInvoiceId] = [t1].[InvoiceId] INNER JOIN [Period] AS [t2] ON [t2].[PeriodId] = [t1].[InvoicePeriodId] LEFT OUTER JOIN ( SELECT 1 AS [test], [t3].[StoreId], [t3].[StoreName] FROM [Store] AS [t3] ) AS [t4] ON [t4].[StoreId] = ([t0].[EntryStoreId]) WHERE (([t1].[InvoiceCustomerId]) = @p0) ORDER BY [t0].[InvoicePrice] DESC -- @p0: Input Int (Size = 0; Prec = 0; Scale = 0) [186] -- Context: SqlProvider(Sql2008) Model: AttributedMetaModel Build: 3.5.30729.1 The question is why there are two queries and how can I fetch LINQ objects without such hacks?

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• How to get Tkinter to input text and submit with button

  - by Rob

  Hi I was wondering if anybody could help me submit code from the test fields to the login fields from Tkinter import * import tkMessageBox if ( __name__ == "__main__" ): import resources.lib.mechanize as mechanize mechanize # Start Browser br = mechanize.Browser(factory=mechanize.RobustFactory()) # User-Agent (Firefox) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://razetheworld.com/wp-login.php?redirect_to=http%3A%2F%2Frazetheworld.com') br.select_form(name="loginform") br['log'] = 'entryWidget_U must enter here' br['pwd'] = 'entryWidget_P must enter here' br.submit(name="wp-submit") print br.geturl() def displayText(): """ Display the Entry text value. """ global entryWidget_U global entryWidget_P if entryWidget_U.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Username") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_U.get().strip()) if entryWidget_P.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Password") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_P.get().strip()) if __name__ == "__main__": root = Tk() root.title("Tkinter Entry Widget") root["padx"] = 40 root["pady"] = 20 # Create a text frame to hold the text Label and the Entry widget textFrame_U = Frame(root) textFrame_P = Frame(root) #Create a Label in textFrame entryLabel = Label(textFrame_U) entryLabel["text"] = "Enter Username:" entryLabel.pack(side=LEFT) entryLabel = Label(textFrame_P) entryLabel["text"] = "Enter Password:" entryLabel.pack(side=LEFT) # Create an Entry Widget in textFrame entryWidget_U = Entry(textFrame_U) entryWidget_U["width"] = 50 entryWidget_U.pack(side=LEFT) entryWidget_P = Entry(textFrame_P) entryWidget_P["width"] = 50 entryWidget_P.pack(side=LEFT) textFrame_U.pack() textFrame_P.pack() button = Button(root, text="Login", command=#Run br.submit(name="wp-submit")) button.pack() root.mainloop()

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• Can the lock function be used to implement thread-safe enumeration?

  - by Daniel

  I'm working on a thread-safe collection that uses Dictionary as a backing store. In C# you can do the following: private IEnumerable<KeyValuePair<K, V>> Enumerate() { if (_synchronize) { lock (_locker) { foreach (var entry in _dict) yield return entry; } } else { foreach (var entry in _dict) yield return entry; } } The only way I've found to do this in F# is using Monitor, e.g.: let enumerate() = if synchronize then seq { System.Threading.Monitor.Enter(locker) try for entry in dict -> entry finally System.Threading.Monitor.Exit(locker) } else seq { for entry in dict -> entry } Can this be done using the lock function? Or, is there a better way to do this in general? I don't think returning a copy of the collection for iteration will work because I need absolute synchronization.

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• How to check successful copy() function execution in php?

  - by OM The Eternity

  How to check successful copy() function execution in php? I am using the following code: <? function full_copy( $source, $target ) { if ( is_dir( $source ) ) { @mkdir( $target ); $d = dir( $source ); while ( FALSE !== ( $entry = $d->read() ) ) { if ( $entry == '.' || $entry == '..' ) { continue; } $Entry = $source . '/' . $entry; if ( is_dir( $Entry ) ) { full_copy( $Entry, $target . '/' . $entry ); continue; } copy( $Entry, $target . '/' . $entry ); } $d->close(); }else { copy( $source, $target ); } } $source ='.'; $destination = '/html/parth/'; full_copy($source, $destination); ?> I do not get anything in my parth folder. Why? I am using Windows, Script is executed on fedora system (its my server)...

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• Submitting software to a competition, it becomes their property?

  - by myrkos

  So I'm about to submit a game to a competition, but as I looked through the rules a chunk grabbed my attention: All Entries become the sole and exclusive property of Sponsor and will not be acknowledged or returned. Sponsor shall own all right, title and interest in and to each Entry, including without limitation all results and proceeds thereof and all elements or constituent parts of Entry (including without limitation the Mobile App, the Design Documents, the Video Trailer, the Playable and all illustrations, logos, mechanicals, renderings, characters, graphics, designs, layouts or other material therein) and all copyrights and renewals and extensions of copyrights therein and thereto. Without limitation of the foregoing, each Eligible Entrant shall and hereby does absolutely and irrevocably assign and transfer all of his or her right, title and interest in his or her Entry to Sponsor, and Sponsor shall have the right and may authorize others to use, copy, sublicense, transmit, modify, manipulate, publish, delete, reproduce, perform, distribute, display and otherwise exploit the Entry (and to create and exploit derivative works thereof) in any manner, including without limitation to embody the Entry, in whole or in part, in apps and other works of any kind or nature created, developed, published or distributed by Sponsor and to and register as a trademark in any country in Sponsor’s name any component of the Entry, without such Eligible Entrant reserving any rights or claims with respect thereto. Sponsor shall have the exclusive right, in perpetuity, throughout the Territory to change, adapt, modify, use, combine with other material and otherwise exploit the Entry in all media now known or hereafter devised and in any manner, in its sole and absolute discretion, without the need for any payment or credit to Entrant. So the game will become the sponsor's property; however, they don't ask for source code. So will I still own the rights to the source code, whatever that means? And if it doesn't win said competition, will I be able to publish it myself without their trademarks? I am very new to software legality stuff, so I would appreciate any clarification. Since there's a possibility I won't even own the source, is it possible to make the game core engine open source software with a not-very-restrictive license and include that in the project, so I at least still own the game engine? Or does it not work that way?

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• Unzipping in Java and FileUtil.copy

  - by Geertjan

  Via NetBeans File Systems API, which provides FileUtil.copy below, which means a dependency on NetBeans Utilities API: private void unzipEpubFile(String folder, File file) throws IOException { final AtomicBoolean canceled = new AtomicBoolean(); //define and start progress bar here... // ProgressHandle handle = // ProgressHandleFactory.createHandle( // Bundle.MSG_unpacking(zip.getName()), // new Cancellable() { // @Override // public boolean cancel() { // return canceled.compareAndSet(false, true); // } // }); //then unzip 'file' into 'root": try { List folders = new ArrayList<>(); try (InputStream is = new FileInputStream(file)) { ZipInputStream zis = new ZipInputStream(is); ZipEntry entry; while ((entry = zis.getNextEntry()) != null) { if (canceled.get()) { return; } String n = entry.getName(); File f = new File(folder, n); if (n.endsWith("/")) { if (!f.isDirectory()) { if (!f.mkdirs()) { throw new IOException("could not make " + f); } if (entry.getTime() > 0) { if (!f.setLastModified(entry.getTime())) { // oh well } } } folders.add(f); } else { //handle.progress(Bundle.MSG_creating(n)); File p = f.getParentFile(); if (!p.isDirectory() && !p.mkdirs()) { throw new IOException("could not make " + p); } try (OutputStream os = new FileOutputStream(f)) { FileUtil.copy(zis, os); } if (entry.getTime() > 0) { if (!f.setLastModified(entry.getTime())) { // oh well } } } } } //handle.switchToDeterminate(folders.size()); if (canceled.get()) { } } finally { //stop progress bar } } Mostly from NetBeans IDE sources for working with projects and ZIP files.

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• Creating a three level ASP.NET menu with SiteMap, how do i do it?

  - by user270399

  I want to create a three level menu, I have got a recursive function today that works with three levels. But the thing is how do i output the third lever? Using two repeaters i have managed to get a hold of the first two levels through the ChildNodes property. But that only gives me the second level. What if a want the third level? Example code below. How do i get the third level? :) <asp:Repeater ID="FirstLevel" DataSourceID="SiteMapDataSource" runat="server" EnableViewState="false"> <ItemTemplate> <li class="top"> <a href='/About/<%#Eval("Title")%>.aspx' class="top_link"><span class="down"><%#Eval("Title")%></span><!--[if gte IE 7]><!--></a><!--<![endif]--> <asp:Repeater runat="server" ID="SecondLevel" DataSource='<%#((SiteMapNode)Container.DataItem).ChildNodes%>'> <HeaderTemplate><!--[if lte IE 6]><table><tr><td><![endif]--><ul class="sub"></HeaderTemplate> <ItemTemplate> <li> <a href='<%#((string)Eval("Url")).Replace("~", "")%>' style="text-align: left;"><%#Eval("Title")%></a> Third repeater here? </li> </ItemTemplate> <FooterTemplate></ul><!--[if lte IE 6]></td></tr></table></a><![endif]--></FooterTemplate> </asp:Repeater> </li> </ItemTemplate> </asp:Repeater>

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• Fasted way to develop data entry screens for a .NET backend ?

  - by jay23

  I am a .NET / C# back end guy. I am working on a app that will have about 200 different data entry screens. For me exposing DTO as a collection for CRUD (IUpdatable and IQueryable) is the easy part, can do it in sleep :-). What I am trying to decide is what type of front end technology will allow me to develop these data entry screens fast. They don't have to be fancy but they are not just plain grid either and on average they have about 15 form fields and some client side data validation (no db look up) Options I am looking at are Use ExtJS on the front and REST / JSON on the back. ASP.NET RIA but I do not know SL (Well XAML) Plain ASP.NET / MVC One idea I had was the DTO will contain the meta data about the form (As Attributes) and the form can be dynamically generated, but i do not want to reinvent the wheel if their is an easy way. I have looked at RAD software but all of them look at the DB and generate screens. I rather want some thing that can look at my DTO and generate screens. Jay

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• When is it possible to override top-level bindings in (R7RS) scheme?

  - by Marc

  I have read the current draft of the forthcoming R7RS scheme standard (small language), but I don't understand under which conditions it is not an error to redefine top-level bindings. I guess that it is possible to define or set! a binding that has been introduced at the top-level of a program a second time. But what about imported bindings from an external library? Is it possible to override these bindings by the standard? On page 26/27 of the report, it says: The top level of a program may also include import declarations. In a library declaration, it is an error to import the same identifier more than once with different bindings, or to redefine or mutate an imported binding with define, define-syntax or set!. However, a REPL should permit these actions. Does it mean that redefining is only an error when it does happen in libraries for imported bindings? I understand that it prohibits optimisations by compilers if the compiler does not know whether, say + still means the built-in addition or is any other user-specified error. But from this perspective, it does not make sense to restrict forbidding to rebind on the library level, when it would also make sense (at least) for imported bindings in programs. P.S.: As this is all about the environment of a scheme program: am I right in saying that environments are not first class citizens because one cannot get hold of the current environment? (Which, in turn, allows a compiled program to forget about the chosen names of the bindings.)

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• Repercussions of Raising Domain Functional Level to 2008 on Mac computers running 10.6.2 with OD

  - by JohnyV

  We have recently replaced all of our 2003 server domain controllers to 2008 r2 and have tried to implement PSO's but have found that the domain functional level must be raised to 2008. We have a mac server in our environment that runs open directory and it is integrated into AD. Does anyone know if I do raise the domain functional level (which makes sense since we only have 2008 r2 domain controllers) what the repercussions (if any) there will be on the macs in the environment? Macs are running 10.6.2 and mac server runs the same. Mac server is running OD and also bound to AD.

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• High level command line program for burning CDs and DVDs?

  - by stickmangumby

  I'm sick of screwing around trying to script a clean solution to burn multiple files and folders to CDs and DVDs with wodim, growisofs and genisoimage. I'm looking for a high level command line program that uses sensible defaults and takes arguments something like this: [program-name] [cd|dvd] /path/to/dir1/ /path/to/dir2/ /path/to/file ... It should then do all the low level copying and ISO generation transparently and just burn the damn disk! Does anyone have any suggestions? I've looked at several programs but it seems there are too many choices to trawl through and not enough information about them online. Thanks :)

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• Is there an way to get the top level classes included in a puppet node?

  - by pwan

  Is there an easy way to return the top level classes applied to a node. By this I mean the classes included in a node definition or ENC equivalent For example with the sample node below, I'd like to return 'return::me' and 'return::me2' for somehost, but not 'dontreturn::me' class return::me { include dontreturn::me } node "somehost" { include return::me include return::me2 } I see that /var/lib/puppet/state/classes.txt includes the full list of classes applied to the node, but that includes any additional classes included by to the top level classes. Is there some way to get at this data with a puppet faces command ? I suspect 'puppet nodes' might be useful, but I haven't been able to get it return what I what.

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• mdadm starts resync on every boot

  - by Anteru

  Since a few days (and I'm positive it started shortly before I updated my server from 13.04-13.10) my mdadm is resyncing on every boot. In the syslog, I get the following output [ 0.809256] md: linear personality registered for level -1 [ 0.811412] md: multipath personality registered for level -4 [ 0.813153] md: raid0 personality registered for level 0 [ 0.815201] md: raid1 personality registered for level 1 [ 1.101517] md: raid6 personality registered for level 6 [ 1.101520] md: raid5 personality registered for level 5 [ 1.101522] md: raid4 personality registered for level 4 [ 1.106825] md: raid10 personality registered for level 10 [ 1.935882] md: bind<sdc1> [ 1.943367] md: bind<sdb1> [ 1.945199] md/raid1:md0: not clean -- starting background reconstruction [ 1.945204] md/raid1:md0: active with 2 out of 2 mirrors [ 1.945225] md0: detected capacity change from 0 to 2000396680192 [ 1.945351] md: resync of RAID array md0 [ 1.945357] md: minimum _guaranteed_ speed: 1000 KB/sec/disk. [ 1.945359] md: using maximum available idle IO bandwidth (but not more than 200000 KB/sec) for resync. [ 1.945362] md: using 128k window, over a total of 1953512383k. [ 2.220468] md0: unknown partition table I'm not sure what's up with that detected capacity change, looking at some old logs, this does have appeared earlier as well without a resync right afterwards. In fact, I let it run yesterday until completion and rebooted, and then it wouldn't resync, but today it does resync again. For instance, yesterday I got: [ 1.872123] md: bind<sdc1> [ 1.950946] md: bind<sdb1> [ 1.952782] md/raid1:md0: active with 2 out of 2 mirrors [ 1.952807] md0: detected capacity change from 0 to 2000396680192 [ 1.954598] md0: unknown partition table So it seems to be a problem that the RAID array does not get marked as clean after every shutdown? How can I troubleshoot this? The disks themselves are both fine, SMART tells me no errors, everything ok.

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• Why is Log4j rootLogger not filtering log events according to event level?

  - by Derek Mahar

  Why is the Log4j rootLogger in my application not filtering log events according to level? In my log4j.properties, I have several loggers: log4j.rootLogger=info,stdout log4j.logger.com.name.myapp=debug,myapp log4j.logger.org.castor=debug,castor log4j.logger.org.exolab.castor=debug,castor log4j.logger.org.hibernate=debug,hibernate log4j.logger.org.springframework=debug,spring Each of the loggers receive and record numerous log events at levels DEBUG and above, which is what I expect. The rootLogger, however, despite being set to level INFO, is displaying all of these events, too, including the DEBUG events, which is not what I expect. Instead, I would expect it to filter the DEBUG events, but display only the events at level INFO and higher (WARN, ERROR, and FATAL). Why is rootLogger displaying all of the events?

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• In Log4Net XML configuration is Priority the same thing as Level?

  - by Michael Levy

  I inherited some code that uses the priority element under the root in its xml configuraiton. This is just like the example at http://iserialized.com/log4net-for-noobs/ which shows: <root> <priority value="ALL" /> <appender-ref ref="LogFileAppender" /> <appender-ref ref="ConsoleAppender"/> </root> However, the log4net configuration examples at http://logging.apache.org/log4net/release/manual/configuration.html always show it using the level element: <root> <level value="DEBUG" /> <appender-ref ref="A1" /> </root> In this type of configuration is <priority> the same as <level> ? Can someone point me to somewhere in the docs where this is explained?

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• Why can't untrusted code change the log level under Java Logging?

  - by cdmckay

  I'm have a Java app that also runs as an applet. The app also happens to use a library called BasicPlayer to play .ogg files. BasicPlayer has a built-in logger that uses Apache Logging Commons to create a logger for BasicPlayer.class using the built-in Java logger. The only way that I know about to turn off the BasicPlayer logging is to run this code: Logger.getLogger(BasicPlayer.class.getName()).setLevel(Level.OFF); This works fine when running as a regular app. However, when running as an applet, this code will throw a SecurityException because for some reason applets can't change the log level of non-anonymous loggers (see here for a sorta-explanation). Why would they do this? Who cares if an applet changes the log level?

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• Do we need Record Level Locking when we already have Transaction for online ordering? (of concert ti

  - by Jian Lin

  For online ordering of concert seat or airline ticket, do we need Record Level Locking or is Transaction good enough? For concert ticket (say, seat Number 20B), or airline ticket (even with overbooking, the limit is 210, for example), I think the website cannot lock any record or begin transaction when showing the ticket purchase screen. But after the user clicks "Confirm Purchase", then the server should Begin a Transaction, Purchase Seat Number 20B, and try to Commit. If another user already bought Seat 20B in a previous transaction, then it is the "Commit" part that the current transaction will fail? So... we don't need Record Level Locking? Do Transactions always go serialized (one after another), so that's why we can know for sure there is no "race condition"? In what situation is Record Level Locking needed then?

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• find() or children() to search top-level children only for a style?

  - by user291701

  Hi, I'd like to find if a child element exists which has either of two class styles applied. My code looks like this: var listOfMatchedResults = $("#parentList").find(".myStyle1, .myStyle2"); My styles are defined like this: .parent li, .myStyle0 { } .parent li.myStyle1 { } .parent li.myStyle2 { } I don't need to traverse more than one level deeper than the children level, like: <ul id='parentList'> <li><p>foo</p><p>grok</p></li> <li class='myStyle2'><p>Here</p><p>I am!</p></li> <li><p>foo</p><p>grok</p></li> </ul> I'm not clear as to what find() is doing, is it going into each of the paragraph elements too? I just need it to traverse the top-level children - is there a way to specify that? Thank you

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• Javascript points calculating system

  - by coolboycsaba

  I trying to create a points calculating system with javascript, but the problem is with the mathematical part. I have saved on the server the points number, and based on that number I want to decide the level. Sorry for my bad english, I cant explain very well :D. I want something like: level 1 need 0 points level 2 needs 100 points level 3 needs 240 points level 4 needs 420 points level 5 needs 640 points and so on.... I need a mathematical function to calculate each level with it. Something that if I know the level to calculate the points needed, and if I know only the points to calculate the level.

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• Apache: How to enable Directory Index browsing at the Doc Root level?

  - by Brian Lacy

  I have several web development projects running on Fedora 13. I generally setup Apache to serve my larger projects as Virtual Hosts, but I've got several small projects cycling through that I don't really care to setup a VirtualHost for each one. Instead I'd like them all under a subdirectory of the main VirtualHost entry. I just want Apache to serve me the directory index when I browse to the host name. For example, the hostname projects.mydomain.com refers to /var/www/projects, and that directory contains only subdirectories (no index file). Unfortunately when I browse to the host directly I get: Forbidden You don't have permission to access / on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request. But my virtual host entry in my apache config looks like this: <VirtualHost *> ServerName projects.mydomain.com DocumentRoot /var/www/projects <Directory "/var/www/projects"> Options +FollowSymlinks +Indexes AllowOverride all </Directory> </VirtualHost> What am I missing here?

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• SQL SERVER – Quiz and Video – Introduction to Hierarchical Query using a Recursive CTE

  - by pinaldave

  This blog post is inspired from SQL Queries Joes 2 Pros: SQL Query Techniques For Microsoft SQL Server 2008 – SQL Exam Prep Series 70-433 – Volume 2.[Amazon] | [Flipkart] | [Kindle] | [IndiaPlaza] This is follow up blog post of my earlier blog post on the same subject - SQL SERVER – Introduction to Hierarchical Query using a Recursive CTE – A Primer. In the article we discussed various basics terminology of the CTE. The article further covers following important concepts of common table expression. What is a Common Table Expression (CTE) Building a Recursive CTE Identify the Anchor and Recursive Query Add the Anchor and Recursive query to a CTE Add an expression to track hierarchical level Add a self-referencing INNER JOIN statement Above six are the most important concepts related to CTE and SQL Server.  There are many more things one has to learn but without beginners fundamentals one can’t learn the advanced  concepts. Let us have small quiz and check how many of you get the fundamentals right. Quiz 1) You have an employee table with the following data. EmpID FirstName LastName MgrID 1 David Kennson 11 2 Eric Bender 11 3 Lisa Kendall 4 4 David Lonning 11 5 John Marshbank 4 6 James Newton 3 7 Sally Smith NULL You need to write a recursive CTE that shows the EmpID, FirstName, LastName, MgrID, and employee level. The CEO should be listed at Level 1. All people who work for the CEO will be listed at Level 2. All of the people who work for those people will be listed at Level 3. Which CTE code will achieve this result? WITH EmpList AS (SELECT Boss.EmpID, Boss.FName, Boss.LName, Boss.MgrID, 1 AS Lvl FROM Employee AS Boss WHERE Boss.MgrID IS NULL UNION ALL SELECT E.EmpID, E.FirstName, E.LastName, E.MgrID, EmpList.Lvl + 1 FROM Employee AS E INNER JOIN EmpList ON E.MgrID = EmpList.EmpID) SELECT * FROM EmpList WITH EmpListAS (SELECT EmpID, FirstName, LastName, MgrID, 1 as Lvl FROM Employee WHERE MgrID IS NULL UNION ALL SELECT EmpID, FirstName, LastName, MgrID, 2 as Lvl ) SELECT * FROM BossList WITH EmpList AS (SELECT EmpID, FirstName, LastName, MgrID, 1 as Lvl FROM Employee WHERE MgrID is NOT NULL UNION SELECT EmpID, FirstName, LastName, MgrID, BossList.Lvl + 1 FROM Employee INNER JOIN EmpList BossList ON Employee.MgrID = BossList.EmpID) SELECT * FROM EmpList 2) You have a table named Employee. The EmployeeID of each employee’s manager is in the ManagerID column. You need to write a recursive query that produces a list of employees and their manager. The query must also include the employee’s level in the hierarchy. You write the following code segment: WITH EmployeeList (EmployeeID, FullName, ManagerName, Level) AS ( –PICK ANSWER CODE HERE ) SELECT EmployeeID, FullName, ” AS [ManagerID], 1 AS [Level] FROM Employee WHERE ManagerID IS NULL UNION ALL SELECT emp.EmployeeID, emp.FullName mgr.FullName, 1 + 1 AS [Level] FROM Employee emp JOIN Employee mgr ON emp.ManagerID = mgr.EmployeeId SELECT EmployeeID, FullName, ” AS [ManagerID], 1 AS [Level] FROM Employee WHERE ManagerID IS NULL UNION ALL SELECT emp.EmployeeID, emp.FullName, mgr.FullName, mgr.Level + 1 FROM EmployeeList mgr JOIN Employee emp ON emp.ManagerID = mgr.EmployeeId Now make sure that you write down all the answers on the piece of paper. Watch following video and read earlier article over here. If you want to change the answer you still have chance. Solution 1) 1 2) 2 Now compare let us check the answers and compare your answers to following answers. I am very confident you will get them correct. Available at USA: Amazon India: Flipkart | IndiaPlaza Volume: 1, 2, 3, 4, 5 Please leave your feedback in the comment area for the quiz and video. Did you know all the answers of the quiz? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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