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  • tablednd post issue help please

    - by netrise
    Hi plz i got a terrible headache my script is very simple Why i can’t get $_POST['table-2'] after submiting update button, i want to get ID numbers sorted # index.php <head> <script src="jquery.js" type="text/javascript"></script><br /> <script src="jquery.tablednd.js" type="text/javascript"></script><br /> <script src="jqueryTableDnDArticle.js" type="text/javascript"></script><br /> </head> <body> <form method='POST' action=index.php> <table id="table-2" cellspacing="0" cellpadding="2"> <tr id="a"><td>1</td><td>One</td><td><input type="text" name="one" value="one"/></td></tr> <tr id="b"><td>2</td><td>Two</td><td><input type="text" name="two" value="two"/></td></tr> <tr id="c"><td>3</td><td>Three</td><td><input type="text" name="three" value="three"/></td></tr> <tr id="d"><td>4</td><td>Four</td><td><input type="text" name="four" value="four"/></td></tr> <tr id="e"><td>5</td><td>Five</td><td><input type="text" name="five" value="five"/></td></tr> </table> <input type="submit" name="update" value="Update"> </form> <?php $result[] = $_POST['table-2']; foreach($result as $value) { echo "$value<br/>"; } ?> </body> # jqueryTableDnDArticle.js …………. $(“#table-2?).tableDnD({ onDragClass: “myDragClass”, onDrop: function(table, row) { var rows = table.tBodies[0].rows; var debugStr = “Row dropped was “+row.id+”. New order: “; for (var i=0; i<rows.length; i++) { debugStr += rows[i].id+" "; } //$("#debugArea").html(debugStr); $.ajax({ type: "POST", url: "index.php", data: $.tableDnD.serialize(), success: function(html){ alert("Success"); } }); }, onDragStart: function(table, row) { $("#debugArea").html("Started dragging row "+row.id); } });

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  • Trigger user control post back from client side

    - by Narmatha Balasundaram
    Can a post back to the user control be triggered from javascript (on the client side) without updatepanels? What I am trying to achieve is this Initially the page and the user control are loaded with default values The parent pages makes a PageMethod request When the data is available (from the PageMethod request), the user control has to be reloaded to update with the new values

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  • MVC + Extjs + IIS6 + Wildcard Mapping = Post Form resulting in 302 object moved

    - by Orkun Balkanci
    Everything seems to work fine until i want to submit the form and update the database. Wildcard mapping works on requests like "/navigation/edit/1", but when i submit the form as: var ajaxPost = function(Url, Params) { Ext.Ajax.request({ url: Url, params: Params, method: 'POST', async: false, scope: this }); }; it says "200 bad response: syntax error" and in firebug there is "Failed to load source for: http://.../Navigation/edit/1". Any help?

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  • Using the Jersey client to do a POST operation

    - by Jon
    Hello, In a Java method, I'd like to use a Jersey client object to do a POST operation on a RESTful web service (also written using Jersey) but am not sure how to use the client to send the values that will be used as FormParam's on the server. I'm able to send query params just fine. Thanks in advance.

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  • Getting 404 when attempting to POST file to Google Cloud Storage from service account

    - by klactose
    I'm wondering if anyone can tell me the proper syntax & formatting for a service account to send a POST Object to bucket request? I'm attempting it programmatically using the HttpComponents library. I manage to get a token from my GoogleCredential, but every time I construct the POST request, I get: HTTP/1.1 403 Forbidden <?xml version='1.0' encoding='UTF-8'?><Error><Code>AccessDenied</Code><Message>Access denied.</Message><Detailsbucket-name</Details></Error The Google documentation that describes the request methods, mentions posting using html forms, but I'm hoping that wasn't suggesting the ONLY way to get the job done. I know that HttpComponents has a way to explicitly create form data by using UrlEncodedFormEntity, but it doesn't support multipart data. Which is why I went with using the MultipartEntity class. My code is below: MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE ); String token = credential.getAccessToken(); entity.addPart("Authorization", new StringBody("OAuth " + token)); String date = formatDate(new Date()); entity.addPart("Date", new StringBody(date)); entity.addPart("Content-Encoding", new StringBody("UTF-8")); entity.addPart("Content-Type", new StringBody("multipart/form-data")); entity.addPart("bucket", new StringBody(bucket)); entity.addPart("key", new StringBody("fileName")); entity.addPart("success_action_redirect", new StringBody("/storage")); File uploadFile = new File("pathToFile"); FileBody fileBody = new FileBody(uploadFile, "text/xml"); entity.addPart("file", fileBody); httppost.setEntity(entity); System.out.println("Posting URI = "+httppost.toString()); HttpResponse response = client.execute(httppost); HttpEntity resp_entity = response.getEntity(); As I mentioned, I am able to get an actual token, so I'm pretty sure the problem is in how I've formed the request as opposed to not being properly authenticated. Keep in mind: This is being performed by a service account. Which means that it does have Read/Write access Thanks for reading, and I appreciate any help!

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  • How to use type: "POST" in jsonp ajax call

    - by MKS
    Hi Guy, I am using JQuery ajax jsonp. I have got below JQuery Code: $.ajax({ type:"GET", url: "Login.aspx", // Send the login info to this page data: str, dataType: "jsonp", timeout: 200000, jsonp:"skywardDetails", success: function(result) { // Show 'Submit' Button $('#loginButton').show(); // Hide Gif Spinning Rotator $('#ajaxloading').hide(); } }); The above code is working fine, I just want to send the request as "POST" instead of "GET", Please suggest how can I achieve this. Thanks

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  • POST request from Python to PHP

    - by RainbowHat
    Python params = urllib.parse.urlencode({'spam': '1', 'eggs': '2', 'bacon': '3'}) binary_data = params.encode('utf-8') reg = urllib.request.Request("http://www.abc.com/abc/smart/ap/request/",binary_data) reg.add_header('Content-Type','application/x-www-form-urlencoded') f = urllib.request.urlopen(reg) print(f.read()) PHP if($_SERVER['REQUEST_METHOD'] == 'POST') { //parse_str($_SERVER['QUERY_STRING']); var_dump($_SERVER['QUERY_STRING']); } When i try print binary_data , it does show the parameter but by the time it reaches the PHP , i see nothing. Any idea?

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  • MVC how to implement two different post actions

    - by AnonyMouse
    I'm developing this really important squirrel application. There is a wizard where squirrels are added to the database. So say there are three screens to this wizard: Squirrel name details Height and weight Nut storage So at each step of the wizard I'm wanting to save the details to the database. The Height and weight view looks like: @model HeightWeightViewModel @{ ViewBag.Title = "Height and weight"; } <h2>Height and weight</h2> @using (Html.BeginForm()) { <h3>Height</h3> <div> @Html.EditorFor(model => model.Squirrel.Height) </div> <h3>Weight</h3> <div> @Html.EditorFor(model => model.Squirrel.Weight) </div> <input type="submit" value="Previous" /> <input type="submit" value="Next" /> } So I'm hoping that Previous and Next buttons will save these details. The Previous button while saving will also take the user to the Squirrel name details page. The Next will save and take the user to the nut storage page. I got the Next button working using: public ActionResult Edit(SquirrelViewModel squirrelViewModel) { _unitOfWork.SaveHeightWeight(squirrelViewModel); return RedirectToAction("Edit", "NutStorage", new { id = squirrelViewModel.Squirrel.Id }); } So the Next button saves the details and sends the user to the NutStorage page. The Previous button does the same as Next but I actually want it to send the user to the first step of the Wizard after saving. I'm not sure how to do this. Would I have another method to post to for Previous? I can't image how to implement this. Maybe I should be using ActionLinks instead of submit buttons but that would not post the details to be saved. Can anyone suggest how to get the previous button to save and send the user to the first page of the wizard while still having the Next functionality working?

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  • Receiving the post response using curl

    - by Larry Battle
    Hello, I'm trying to make a script that will download search results from a HTTPS website using POST. So far, I'm able to download the web page before the submission but not the response page containing the search results. The problem seems to be that curl isn't waiting long enough for the response page to appear. The website behaviors likes this. Website appears- input form data - click submit - progressing icon appears - returns new web page with search results( new data but the url doesn't change ) My code: curl -d "postData" -k url

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  • Post bacc CS certificate of Java Certification?

    - by gwozdz
    I have a BS in biology, MS in Environmental Science, but I've been writing software in C++ and Java throughout grad school and a bit in my current job. I'd love to transition to a programming career. I've thought about getting what's called a "Post baccalaureate Certificate" or Java certification in lieu of another degree in CS. Which is more useful in terms of getting a job?

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  • post row where radio button is checked

    - by ognjenb
    View: <form id="numbers-form" method="post" action="/Numbers/Numbers"> <table id="numbers"> <tr> <th> prvi_br </th> <th> drugi_br </th> <th> treci_br </th> </tr> <% int rb = 1; %> <% foreach (var item in Model) { %> <tr> <td> <%= Html.Encode(item.prvi_br) %> <input type="radio" name="<%= Html.Encode(rb) %>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.prvi_br) %>'/> </td> <td> <%= Html.Encode(item.drugi_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.drugi_br) %>'/> </td> <td> <%= Html.Encode(item.treci_br) %> <input type="radio" name="<%= Html.Encode(rb)%>" value="<%= Html.Encode(rb) %>" id='<%= Html.Encode(item.treci_br) %>'/> </td> </tr> <% rb++; %> <% } %> </table> <p> <input type="submit" value="Save" /> </p> </form> Controller action: [HttpPost] public ActionResult Numbers(int[] rb) { brojevi br = new brojevi(); for (int i = 1; i <= rb.Length; i++) //in this line I have error:Object reference not set to an instance of an object. { br.prvi_br = i; br.drugi_br = i+1; br.treci_br = i+3; } numbers.AddTobrojevi(br); numbers.SaveChanges(); return View(); } I try to post data row in wich radio button is checked but failed, what is wrong??

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  • Wordpress plugin $post

    - by Jordan Pagaduan
    I have already get how to insert in the database. My only problem is to get the value of text box to insert in the database. Here is my code: function dbAdd() { global $wpdb; $new_title = $_POST['new_title']; $new_author = $_POST['new_author']; $new_url = $_POST['new_url']; if($wpdb->insert('wp_podcast_data', array( 'mp3_id' => '', 'title' => '$new_title', 'creator' => '$new_author', 'url' => '$new_url') )) { echo"<h1>Save Successfully!</h1>"; }else { echo mysql_error(); } } ---------------------------------------------------------- function player_manager_index() { if($_SERVER['REQUEST_METHOD']=='POST') { dbAdd(); } ?> <h3>Podcast Player Manager (This Plug is not yet finish)</h3><br /> <p>Note: This Player Manager needs the URL of mp3 file that you want to include in your podcast player.</p> <form method="post" action=""> <label for="new_title" style="display:block; padding-top: 5px; cursor: default;">Title</label><input type="text" id="new_title" name="new_title" size="50" /> <label for="new_author" style="display:block; padding-top: 5px; cursor: default;">Author</label><input type="text" id="new_author" name="new_author" size="50" /> <label for="new_url" style="display:block; padding-top: 5px; cursor: default;">URL</label><input type="text" id="new_url" name="new_url" size="50" /> <div><input type="submit" value="Add New" style="margin-left: 20px; margin-top: 15px;" /></div> </form> Please Help me. I'm newbie in wordpress. Thank you so much.

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