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  • Zend_Form: Is this really the way we should be doing things?

    - by Francis Daigle
    OK. I understand how to use Zend_Form and it's implementation of the decorator pattern. My question is, is this the best way to be going about creating forms? Shouldn't a documents forms be left to to the front-end rather than generating forms programmatically? Doesn't this kinda violate the whole idea of keeping things separate? I mean, really, even providing that you have a good understanding of the methodology being employed, does it really save one that much time? I guess what I'm looking for is some guidance as to what might be considered 'best practice'. I'm not saying that Zend_Form doesn't have it's place, I'm just wondering if it should be used in all cases (or not). And this has nothing to do with validation. I'm just thinking that something more akin to using the 'ViewScript' approach might be more appropriate in most cases. Your thoughts?

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  • How do detect that transaction has already been started?

    - by xelurg
    I am using Zend_Db to insert some data inside a transaction. My function starts a transaction and then calls another method that also attempts to start a transaction and of course fails(I am using MySQL5). So, the question is - how do I detect that transaction has already been started? Here is a sample bit of code: try { Zend_Registry::get('database')->beginTransaction(); $totals = self::calculateTotals($Cart); $PaymentInstrument = new PaymentInstrument; $PaymentInstrument->create(); $PaymentInstrument->validate(); $PaymentInstrument->save(); Zend_Registry::get('database')->commit(); return true; } catch(Zend_Exception $e) { Bootstrap::$Log->err($e->getMessage()); Zend_Registry::get('database')->rollBack(); return false; } Inside PaymentInstrument::create there is another beginTransaction statement that produces the exception that says that transaction has already been started.

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  • Zend_Registry: real life examples

    - by takeshin
    Do you find Zend_Registry useful? For which tasks it should be used? For which not? Global state for variables is not a good practice. Main objects may have global state injected via $front->setParam('paramName', $object), so what's the purpose of Zend_Registry?.

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  • Zend_Router requirements mismatch

    - by elbicho
    Hello you all: I have two routes that match a url with the same apparent pattern, the difference lies in the $actionRoute, this should only be matched if the variable :action on it equals 'myaction'. If I go to /en/mypage/whatever/myaction it goes as expected through $actionRoute. If I go to /en/mypage/whatever/blahblah it gets rejected by $actionRoute and matched by $genRoute. If I go to /en/mypage/whatever it should be matched by $genRoute but it gets matched by $actionRoute instead throwing and exception because the action noactionAction() does not exist. Don't know what I'm doing wrong, I'd appreciate your help. $genRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:var2', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'index', 'var1' => 'noone', 'var2' => 'no' ), array( 'var1' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}' ) ); $actionRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:action', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'noaction', 'var1' => 'noone', ), array( 'action' => '(myaction)+?', 'var' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}', ) ); $router->addRoute('genroute',$genRoute); $router->addRoute('actionroute',$actionRoute);

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  • how to add multiple modules to a single page in digitalus

    - by jspeshu
    when i do some thing like this i can see the module <div id='search' class="module"> <digitalusControl type='moduleSelector' id='module' label="searchM" group='mods' /> </div> but i want to have two modules so i make something like this <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulesearch' label="searchM" group='mods' /> </div> <div id='search' class="module"> <digitalusControl type='moduleSelector' id='modulenews' label="newsM" group='mods' /> </div> plz help how can i create multiple modules since i can't create another element "digitalusControl" with id "module" i really need this plz help EDIT: even worse a template with only one module, this single line is not working for me

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  • findBy(x) Using Zend_Navigation with custom route

    - by Stephen
    I am creating my navigation from a db generated array and defining which route to use for some of the uris. when I set the route i am no longer able to use findByUri() as the uri seems to be moved under the properties key example array being used: [id] => 7 [label] => Legal [controller] => index [uri] => /legal [route] => cmsPage [visible] => 1 [params] => Array ( [first] => legal ) snippet of the output: [_properties:protected] => Array ( [uri] => /legal [created] => 2012-10-20 10:23:23 ) When I don't define the route I am able to use findByUri() successfully. currently I am looping through each to find the property that matches the request but it seems a long / wrong approach Is there a way to search by the nested param - or am i doing something wrong with the setup (everything else behaves as expected)

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  • ZF: Url View Helper Acting Strangely

    - by moteutsch
    I have the following route defined: $route = new Zend_Controller_Router_Route( 'users/:id', array( 'controller' => 'users', 'action' => 'profile', 'id' => '' ) ); When I am on the page via the shortened URL (localhost/users/someuser), the URLs defined in the layout file all link to "localhost/users". Here is the code in the layout: <li><a href="<?php echo $this->url(array('controller' => 'index'), null, true); ?>">Home</a></li> <li><a href="<?php echo $this->url(array('controller' => 'search'), null, true); ?>">Search</a></li> <!-- etc. --> How can I fix the code so that the links in the layout file point to the correct URLs?

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  • Magento quantity field doesn't work

    - by madmax
    Hi, i simply can't find a solution to my problem! The quantity field worked as it should. After a few months of programming on the whole shop, i wanted to test the quantity field and recognized that it doesn't function. I only can add one product to the cart although i typed “3” in the quantity field. I didn’t change anything in product/view.phtml and addtocart.phtml. Don't know where i have to search for this error. Maybe someone can give me a tip... greets max

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  • ZendFramework Zend_Form_Element_File setDestination vs rename filter

    - by bibstha
    The code says Zend_Form_element_File::setDestination() is depricated and to use the rename filter. However the rename filter is currently codes such that when path is set, only temporary name is given. Original filename is lost. <?php $file = new Zend_Form_Element_File(); $file->setDestination('/var/www/project/public'); ?> vs <?php $file = new Zend_Form_Element_File(); $file->addFilter('Rename', array('target' => '/var/www/project/public')); ?> Any solution to upload files so that it preserves original filename structure but checks for existing file and appends _1.ext or _2.ext?

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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • SQL CREATE TABLE Error

    - by Adam M-W
    Hi, I've been stuck on this one simple(ish) thing for the last 1/2 hour so I thought I might try to get a quick answer here. What exactly is incorrect about my SQL syntax, assuming I'm using mysql 5.1 CREATE TABLE 'users' ( 'id' MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, 'username' VARCHAR(20) NOT NULL, 'password' VARCHAR(40) NOT NULL, 'salt' VARCHAR(40) DEFAULT NULL, 'email' VARCHAR(80) NOT NULL, 'created_on' INT(11) UNSIGNED NOT NULL, 'last_login' INT(11) UNSIGNED DEFAULT NULL, 'active' TINYINT(1) UNSIGNED DEFAULT NULL, ) ENGINE InnoDB; Also, does anyone have any good tutorials about how to use Zend_Auth for complete noobs? Thanks.

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  • ZF Site in ZF Site? How do I redirect form subdirectory to another subdirecotry?

    - by AD
    The deal is that I have a ZF site for which root directory is /public. How should I go about redirecting to a subdirectory if I want to do next? I want to have another subdirectory under /public/ that would not be linked to a main website in any way except it using save ZF. Lets say I have this: /public/newsite/ which will include a complete modular ZF (just I have it for the main site). That is the root directory for the NEWSITE would be /public/newsite/public. So my question how do I modify my .htaccess rules so it would redirect any requests from /public/newsite/ to /public/newsite/public/? Thank you in advance.

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  • My store returns no code id and breaks 404 error. Magento

    - by numerical25
    I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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  • Serialising my JSON output problem in JQuery

    - by davykiash
    Am trying to validate my form using an AJAX call $("#button").click(function() { $.ajax({ type: "POST", url: "<?php echo $this->baseUrl() ?>/expensetypes/async", data: 'fs=' + JSON.stringify($('#myform').serialize(true)), contentType: "application/json; charset=utf-8", dataType: "json" }); }); On my controller my code is as follows //Map the form from the client-side call $myFormData = Zend_Json::decode($this->getRequest()->getParam("fs") ,Zend_Json::TYPE_ARRAY); $form = new Form_Expensetypes(); $form->isValid($myFormData); However from firebug my output is as follows fs="id=&expense_types_code=AAA&expense_types_desc=CCCC&expense_types_linkemail=XXXX&expense_types_budgetamount=22222&expense_types_budgetperiod=22222" What I expect is something similar to fs{"expense_types_code":"AAA","expense_types_desc":"CCCC","expense_types_linkemail":"XXXX","expense_types_budgetamount":"22222"} How do I achieve this type of serialisation?

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  • Defining a function to a Row

    - by Siedrix
    Hi, im making an application and i need to implement diferent level of user permits. I coul have the function $this->view->users->hasPermits($this->view->user); By declaring a function on the model, an things could be easy to implement. But i would like to be able to have the next function doing the same: $this->view->user->hasPermits(); Is there a way to do this? do i need to extend the Zend_Db_Table_Row class? any ideas?

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  • [Zend_Framework] Group by date with Zend_Db

    - by rasouza
    I have several entries in a table with name and date. I'd like to fetchAll with Zend_Db then get a grouped-by-date array. It happens that if I use group(), Zend_Db_Select method, it excludes some entries and I need them all. Actually, what I'm trying to do is to render several tables, one for each different date, with data inside. I have no ideia. How do I do that? Thx in advance

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  • memory leak in Zend_Db_Table_Row?

    - by Vincenzo
    This is the code I have: <?php $start = memory_get_usage(); $table = new Zend_Db_Table('user'); for ($i = 0; $i < 5; $i++) { $row = $table->createRow(); $row->name = 'Test ' . $i; $row->save(); unset($row); echo (memory_get_usage() - $start) . "\n"; } This is what I see: 90664 93384 96056 98728 101400 Isn't it a memory leak? When I have 500 objects to insert into DB in one script I'm getting memory overflow. Can anyone help?

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