Search Results

Search found 25551 results on 1023 pages for 'linux validated rpm oracl'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 490/1023 | < Previous Page | 486 487 488 489 490 491 492 493 494 495 496 497  | Next Page >

  • User permissions linux. (proftpd / nginx)

    - by user55745
    I've been having a complete nightmare trying to configure proftpd. I've got proftp server working with an sql database. However I want to have any files uploaded able to viewed by the webserver running on the same box. The folders get created in /var/tmp/ as rwx------ 2 ftpuser ftpgroup 4096 Oct 8 20:35 50730c4346512 drwx------ 2 ftpuser ftpgroup 4096 Oct 8 20:38 50730f3a811ca I've tried adding www-data to group with the following usermod -g www-data ftpuser But this doesn't allow the web server access. In proftpd.conf I have the following umask set Umask 0022 It doesn't seem to make a difference what I set that value to. /etc/group (sure I've messed up one of these two but I'm getting desperate) ftpgroup:x:2001:www-data www-data:x:33:ftpgroup /etc/passwd www-data:x:33:33:www-data:/var/www:/bin/sh proftpd:x:108:65534::/var/run/proftpd:/bin/false ftp:x:109:65534::/srv/ftp:/bin/false ftpuser:x:2001:33:proftpd user www-data:/bin/null:/bin/false The ftpuser table in the database has uid / gid set to 2oo1 for both. I'm going absolutely crazy trying to solve this any help would be greatly appreciated. p.s Also, although if I manually connect to the ftp server I can upload files via FileZilla. Although this isn't working for the web-camera, although there is talky talky going on between the server and the camera.

    Read the article

  • Is there a best practice for concatenating MP3 Files, adjusting sample rates to match, while preserving original files?

    - by Scott
    Hello overflow community! Does anyone know if there is a "best practice" to concatenate mp3 files to create new files, while preserving the original files? I am working on a CentOS Linux machine, in command line. I will eventually call the command line from a PHP script. I have been doing research and I have come up with a process that I think could work. It combines general advice from different forums, blogs, and sources like this one. So here I go: Create a temporary folder Loop through files to create a new, converted copy, of file into a "raw" format (which one, I don't know. I didn't know "raw" files existed before too long ago. I could use some suggestions on this) Store the path to the temporary files, in the temporary folder, and then loop through the files to concatenate them and then put the new merged file the final "processed directory" Delete the contents of the temporary file with the temporary raw files inside. Convert the final file from "raw" to mp3 and enjoy the finished result I'm thinking that this course of action might be best because I can't necessarily control the quality of the original "source" mp3s. The only other option I could think of would be to create a script that would perform a similar process upon files being added to the system leaving only the files with the "proper" format and removing the original "erroneous" file. Hopefully you can see that I have put some thought into this and that I'm trying to leverage the collective knowledge of this community to choose the best direction. Perhaps there is a better path that I could take? By concatenate, I mean to join together in sequence to create a new audio file from the "concatenated files."

    Read the article

  • Executing system command in php, differs in using broswer and in using command line

    - by Amit
    Hi, I have to execute a Linux "more" command in php from a particular offset, format the result and display the result in Browser. My Code for the above is : <html> <head> <META HTTP-EQUIV=REFRESH CONTENT=10> <META HTTP-EQUIV=PRAGMA CONTENT=NO-CACHE> <title>Runtime Access log</title> </head> <body> <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "<br/>No of lines are : $accessDisplay[0] <br/>"; ?> The output at the browser is :: No of lines are : 3428 (This is wrong) While executing the same command using command line gives a different output. My code snippet for the same is : <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "No of lines are : $accessDisplay[0] \n"; ? The output at the command line is :: No of lines are : 279 (This is correct) While executing the same command directly in command line, gives me output as 279. I am unable to understand why the output of the same command is wrong in the browser. Its actually giving the word count of lines, ignoring the offset parameter. Please help !! Thanks, Amit

    Read the article

  • Deploying a Rails app on an Ubuntu server using Git

    - by NudeCanalTroll
    I'm completely new to Linux, but today I find myself setting up a server (Ubuntu 10.04 LTS lucid) from scratch to host a Rails application. Anyway, I managed to get a Rails app up and running on the server itself, but I had to scrap that because I want to use Git. So I setup a git repository on the server, then pushed all the code from my local machine to the repository. Buuuut, of course Git doesn't actually store the files themselves in the repository -- all the code for my Rails app is now only on my local machine. How am I supposed to tell the server to host that? Right now my solution is to have the server use git to pull the code from its own repository. That's the code I'll host for all the world to see. In order to update the code, I guess I'll have to do something like this: Update the code on my local machine. Do some git adds, git commits, and a git push. On the server, do a git pull to update the code. So my question is, am I doing this the right way? enter code here

    Read the article

  • linux macvlan - stop from broadcasting hostname

    - by staticfloat
    I am trying to simulate two different computers on one box, using the macvlan module (which is awesome, by the way) but I have one small problem; When I create the macvlan Ubuntu 11.10 very helpfully starts broadcasting its hostname on both interfaces, creating an amazing amount of confusion for everything that deals with hostnames. Does anyone know how to stop ubuntu from advertising its hostname on a certain interface? Thanks!

    Read the article

  • How do I grep for entire, possibly wrapped, lines of code?

    - by NXT
    When searching code for strings, I constantly run into the problem that I get meaningless, context-less results. For example, if a function call is split across 3 lines, and I search for the name of a parameter, I get the parameter on a line by itself and not the name of the function. For example, in a file containing ... someFunctionCall ("test", MY_CONSTANT, (some *really) - long / expression); grepping for MY_CONSTANT would return a line that looked like this: MY_CONSTANT, Likewise, in a comment block: ///////////////////////////////////////// // FIXMESOON, do..while is the wrong choice here, because // it makes the wrong thing happen ///////////////////////////////////////// Grepping for FIXMESOON gives the very frustrating answer: // FIXMESOON, do..while is the wrong choice here, because When there are thousands of hits, single line results are a little meaningless. What I would like to do is have grep be aware of the start and stop points of source code lines, something as simple as having it consider ";" as the line separator would be a good start. Bonus points if you can make it return the entire comment block if the hit is inside a comment. I know you can't do this with grep alone. I also am aware of the option to have grep return a certain number of lines of content. Any suggestions on how to accomplish under Linux? FYI my preferred languages are C and Perl. I'm sure I could write something, but I know that somebody must have already done this. Thanks!

    Read the article

  • recvfrom returns invalid argument when *from* is passed

    - by Aditya Sehgal
    I am currently writing a small UDP server program in linux. The UDP server will receive packets from two different peers and will perform different operations based on from which peer it received the packet. I am trying to determine the source from where I receive the packet. However, when select returns and recvfrom is called, it returns with an error of Invalid Argument. If I pass NULL as the second last arguments, recvfrom succeeds. I have tried declaring fromAddr as struct sockaddr_storage, struct sockaddr_in, struct sockaddr without any success. Is their something wrong with this code? Is this the correct way to determine the source of the packet? The code snippet follows. ` /*TODO : update for TCP. use recv */ if((pkInfo->rcvLen=recvfrom(psInfo->sockFd, pkInfo->buffer, MAX_PKTSZ, 0, /* (struct sockaddr*)&fromAddr,*/ NULL, &(addrLen) )) < 0) { perror("RecvFrom failed\n"); } else { /*Apply Filter */ #if 0 struct sockaddr_in* tmpAddr; tmpAddr = (struct sockaddr_in* )&fromAddr; printf("Received Msg From %s\n",inet_ntoa(tmpAddr->sin_addr)); #endif printf("Packet Received of len = %d\n",pkInfo->rcvLen); } `

    Read the article

  • DVI output only working on Windows, not during booting or on Linux

    - by Mononofu
    So yesterday I booted my laptop up and the external monitor I have it connected to just stayed black. At first, I thought the problem would go away when Ubuntu was loaded, but it didn't. I tried to reboot a few times, to no avail. Then I decided to give Windows 7 a try, and suddenly (at the login-screen), my external monitor turned on and worked like normal. I have connected the monitor via DVI, and this only seems to work with Windows now. I don't even get a signal in my BIOS! Mind you, everything was working fine before that, and I didn't change a single thing. I then tried to connect the monitor via VGA (from my DVI jack, which can output VGA using an adaptor), and it worked again. However, 1920x1200 using VGA looks like crap - black print on white background is basically illegible. Do you have any ideas how to fix this peculiar problem? I only use windows for gaming, so it's no real help that it still works normally. Please also excuse any spelling mistakes, I am practically typing this blindly. Edit: I only have one graphics card in my laptop, and I can't select anything related to that in my BIOS. In fact, I can pretty much do almost nothing there. My laptop is a Nexoc Osiris E703, graphics gard is a GeForce Go 7900 GTX. As I mentioned before, DVI output during booting and on Ubuntu was working fine for years before yesterday!

    Read the article

  • Make Errors: Missing Includes in C++ Script?

    - by Abs
    Hello all, I just got help in how to compile this script a few mintues ago on SO but I have managed to get errors. I am only a beginner in C++ and have no idea what the below erros means or how to fix it. This is the script in question. I have read the comments from some users suggesting they changed the #include parts but it seems to be exactly what the script has, see this comment. [root@localhost wkthumb]# qmake-qt4 && make g++ -c -pipe -O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fstack-protector --param=ssp-buffer-size=4 -m32 -march=i386 -mtune=generic -fasynchronous-unwind-tables -Wall -W -D_REENTRANT -DQT_NO_DEBUG -DQT_GUI_LIB -DQT_CORE_LIB -I/usr/lib/qt4/mkspecs/linux-g++ -I. -I/usr/include/QtCore -I/usr/include/QtGui -I/usr/include -I. -I. -I. -o main.o main.cpp main.cpp:5:20: error: QWebView: No such file or directory main.cpp:6:21: error: QWebFrame: No such file or directory main.cpp:8: error: expected constructor, destructor, or type conversion before ‘*’ token main.cpp:11: error: ‘QWebView’ has not been declared main.cpp: In function ‘void loadFinished(bool)’: main.cpp:18: error: ‘view’ was not declared in this scope main.cpp:18: error: ‘QWebSettings’ has not been declared main.cpp:19: error: ‘QWebSettings’ has not been declared main.cpp:20: error: ‘QWebSettings’ has not been declared main.cpp: In function ‘int main(int, char**)’: main.cpp:42: error: ‘view’ was not declared in this scope main.cpp:42: error: expected type-specifier before ‘QWebView’ main.cpp:42: error: expected `;' before ‘QWebView’ make: *** [main.o] Error 1 I have the web kit on my Fedora Core 10 machine: qt-4.5.3-9.fc10.i386 qt-devel-4.5.3-9.fc10.i386 Thanks all for any help

    Read the article

  • linux intrusion detection software

    - by Sam Hammamy
    I have an Ubuntu VPS that I use for practice and deploying prototypes as I am a python developer. I recently started teaching my self sys admin tasks, like installing OpenLDAP. I happened to turn off the ufw firewall for just a minute, and when I ran an netstat command, I saw a foreign ip connected to ssh that I traced to china. I'd like to know a few things: 1) Is there any good network intrusion detection software, such that if any IP that's outside a specific range connects to the VPN, I can be notified? -- I am thinking about scripting this, but I'm pretty sure there's something useful out there and I believe in the wisdom of crowds. 2) How did this person gain access to my server? Is it because my firewall was down? Or is it because they browsed my LDAP directory and from there figured out a way to connect (there was a clear text password in the tree but it wasn't one used by the server's sshd)?

    Read the article

  • DVI output _only_ working on Windows, not during booting or on Linux

    - by Mononofu
    So yesterday I booted my laptop up and the external monitor I have it connected to just stayed black. At first, I thought the problem would go away when Ubuntu was loaded, but it didn't. I tried to reboot a few times, to no avail. Then I decided to give Windows 7 a try, and suddenly (at the login-screen), my external monitor turned on and worked like normal. I have connected the monitor via DVI, and this only seems to work with Windows now. I don't even get a signal in my BIOS! Mind you, everything was working fine before that, and I didn't change a single thing. I then tried to connect the monitor via VGA (from my DVI jack, which can output VGA using an adaptor), and it worked again. However, 1920x1200 using VGA looks like crap - black print on white background is basically illegible. Do you have any ideas how to fix this peculiar problem? I only use windows for gaming, so it's no real help that it still works normally. Please also excuse any spelling mistakes, I am practically typing this blindly. Edit: I only have one graphics card in my laptop, and I can't select anything related to that in my BIOS. In fact, I can pretty much do almost nothing there. My laptop is a Nexoc Osiris E703, graphics gard is a GeForce Go 7900 GTX. As I mentioned before, DVI output during booting and on Ubuntu was working fine for years before yesterday!

    Read the article

  • Can a Linux system crash cause network issues?

    - by Supratik
    I have a Ubuntu box in my network which crashed, all the system connected to the switch in which the Ubuntu system was connected started giving problem. I removed that system from the network, since that was the last change I made in my network and everything was fine. So, to confirm this I again connected the system back to the network and the same network outage happened. When I checked the links it was fine. When I rebooted the problematic system and again connected back to the network switch everything started working. I think possibly the crash of the Ubuntu system could have caused this outage. Is there any possibility that a kernel crash can cause network issues?

    Read the article

  • SDK Platform Tools component missing - Similar to Android Eve below

    - by Hertfordkc
    Ubuntu Linux 10.04//Eclipse 3.5.2 I'm new to Eclipse and Android. Eclipse is up and running simple Jave apps OK. I moved on to downloading the Android SDK starter package, which seemed to go OK. Ran the SDK manager and downladed Platforms 7,8 & 9. Installed the ADT package in Eclipse. I've tried to load the SDK path into the Eclipse Preferences, but it won't retain the path. After restart, Elipse says it can't find SDK package. Also,one message said that the (revision?) number of the ADT couldn't be found. I've reinstalled Eclipse a couple of times, and then gone through the SDK & ADT download procedures a couple of times and am stuck. Any suggestions will be appreciated. Hertfordkc Stupid question caused by not thoroughly reading the Android Developers Guide and the tutorials before trying to start a project. Don't know why I didn't get a message about a missing XML file.

    Read the article

  • Linux RAID0 - relocating member disk

    - by qdot
    I've got an issue I would rather handle with the array online - I am using RAID0 for temporary video storage - data that is low-cost to restore, but that is used frequently. The software array looks like this: md1 : active raid0 sdb1[2] sdc1[3] sdd1[0] sde1[1] 1953487616 blocks 64k chunks I have another partition (sda1) in this system, that I want to use to replace sdc1 (The drives are of varying age, and sdc1 is definitely the slowest one, limiting the entire array's sequential read performance to only 300MB/s). Is there a way to migrate the data from sdc1 to sda1 while the array is still online?

    Read the article

  • windows printer spool gets stuck with file at 64kb from linux and mac

    - by Juan Diego
    Hi I have two printers one on a file server with windows 2003, and other with windows XP. The thing is that when i try to print from my machine, my file stays in queue for ever, it says 64kb out of whatever the file i send. I have seen similar problems with some machines that run on Mac OS X. The windows machines apparently have no problems printing. They are not connect through active directory, just the network. In the past I have seen people install non microsoft windows Printer server on windows, i dont remember the name of any of the programs. I have being googling a lot and have not found anything to replace the microsoft print spooler service, maybe i am mistaken. Everyday I have to restart the print spooler service i even created a bat file for it. I am out of ideas here.

    Read the article

  • Linux (redhat) how to change password to previous password

    - by ring bearer
    Is there a way to change password to value same as the previous password? I know this is a security flaw, but would like to know however. when I try this: [mrbean@wwwserver ~]$ passwd Changing password for user mrbean. Changing password for mrbean (current) UNIX password: New UNIX password: -- here i typed same password BAD PASSWORD: is too similar to the old one.

    Read the article

  • Why does PEAR get installed to my user directory?

    - by webworm
    I am new to Linux and I am attempting to install the PHP PEAR library on a virtual server which is running Ubuntu. I am following a tutorial that covers installing PEAR but have run up against an area where I am confused. When running the PEAR installation program I am prompted as to what I want the INSTALL_PREFIX to be. Evidently the INSTALL_PREFIX, among other things, determines where PEAR will be installed. The tutorial suggest the value of INSTALL_PREFIX be the following path ... "/home/MY_USER_NAME/pear" where MY_USER_NAME = my user account Having come from a Windows world, applications are installed on the system where everyone can use them. If I install PEAR underneath my user directory will other developers on the system be able to make use of PEAR in their PHP scripts? I want to make PEAR available to all users and not just myself. Could someone explain to me the difference between installing for all users and installing just for myself? Does the install location matter? Should I be installing PEAR in a different location? Thanks for any suggestions. P.S. The tutorial I am following is located at the following URL ... http://articles.sitepoint.com/article/getting-started-with-pear/2

    Read the article

  • Give the mount point of a path

    - by Charles Stewart
    The following, very non-robust shell code will give the mount point of $path: (for i in $(df|cut -c 63-99); do case $path in $i*) echo $i;; esac; done) | tail -n 1 Is there a better way to do this? Postscript This script is really awful, but has the redeeming quality that it Works On My Systems. Note that several mount points may be prefixes of $path. Examples On a Linux system: cas@txtproof:~$ path=/sys/block/hda1 cas@txtproof:~$ for i in $(df -a|cut -c 57-99); do case $path in $i*) echo $i;; esac; done| tail -1 /sys On a Mac osx system cas local$ path=/dev/fd/0 cas local$ for i in $(df -a|cut -c 63-99); do case $path in $i*) echo $i;; esac; done| tail -1 /dev Note the need to vary cut's parameters, because of the way df's output differs: indeed, awk is better. Answer It looks like munging tabular output is the only way within the shell, but df /dev/fd/impossible | tail -1 | awk '{ print $NF}' is a big improvement on what I had. Note two differences in semantics: firstly, df $path insists that $path names an existing file, the script I had above doesn't care; secondly, there are no worries about dereferncing symlinks. It's not difficult to write Python code to do the job.

    Read the article

  • Network Bridging on Linux for OpenVPN

    - by Coyote
    I've been following all the OpenVPN Bridge tutorials I can, but I'm still missing something. Does anyone know of a super detailed tutorial\explanation of bridging? If anyone has bridging running, can I get a copy of your interfaces file to see how you've got it going. (Obviously change the ip address, just please change them consistently.)

    Read the article

  • rsync windows to linux permission denied

    - by user64908
    Using Command rsync -avzP --delete --omit-dir-times ../../ [email protected]:/var/www/mysite/ I'm getting rsync: mkstemp "/var/www/mysite/.." failed: Permission denied (13) If ext is in the www-data group should I still set all the files to be owned by user www-data? I am trying to publish the files with rsync and then set the permissions using sudo chown -R www-data doc sudo chgrp -R www-data doc but I can't even rsync because of the permission denied. The SSH works fine, the rsync too except when it tries to write over or update some of the files in /var/www Client * Windows 7 * Cygwin 1.7.16 (GNU bash, version 4.1.10(4)-release (i686-pc-cygwin)) * rsync version 3.0.9 protocol version 30 Server * Ubuntu 12.04 * Apache2 * Root Accounts [ubuntu,ext] * Groups [www-data] * sudo vigr has www-data:x:33:ubuntu,ext I have already configure this http://stackoverflow.com/questions/2124169/cwrsync-ignores-nontsec-on-windows-7 This article has also managed to confuse me http://unix.stackexchange.com/questions/41687/how-should-i-rsync-files-in-var-www-if-i-want-them-to-be-owned-by-www-data What is the right procedure?

    Read the article

  • DIsable my nv video card driver in linux

    - by Dahaka Wang
    I'm trying to passthrough my nv video card to my domU, but I could not bind my video card to the pciback driver I only have one video card with the pci number 0000:03:00.0, so I used the following command echo -n "0000:03:00.0" > /sys/bus/pci/drivers/nouveau/bind to unbind the nouveau driver from my video card. The screen went black because I have forcefully removed the video driver, therefore I ssh'd into the computer to run further commands I ran: echo -n "0000:03:00.0" > /sys/bus/pci/drivers/pciback/bind to try to bind it to my pciback driver, but I got: bash: echo: write error: No such device I found out that this was the message shown when trying to bind a PCI device which is already bound. Therefore, I think that something was still using my video card Can anyone help me out? Thanks a lot!

    Read the article

  • Garbage data from serial port.

    - by sasayins
    Hi I wrote a code in Linux platform that read the data in serial port, my code below: int fd; char *rbuff=NULL; struct termios new_opt, old_opt; int ret; fd = open("/dev/ttyS0", O_RDWR | O_NOCTTY); if( fd == -1 ) { printf("Can't open file: %s\n", strerror(errno)); return -1; } tcgetattr(fd, &old_opt); new_opt.c_cflag = B115200 | CS8 | CLOCAL | CREAD; new_opt.c_iflag = IGNPAR /*| ICRNL*/; new_opt.c_oflag = 0; new_opt.c_lflag = ICANON; tcsetattr(fd, TCSANOW, &new_opt); rbuff = malloc(NBUFF); printf("reading..\n"); memset(rbuff,0x00,NBUFF); ret = read(fd, rbuff, NBUFF); printf("value:%s",rbuff); if(ret == -1) { printf("Read error:%s\n",strerror(errno)); return -1; } tcsetattr(fd, TCSANOW, &old_opt); close(fd); My problem is the code above doesn't read the first data that was transmitted, then the second transmission the data is garbage, then the third is the normal data. Did I missed a setting in the serial port? Thanks.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 486 487 488 489 490 491 492 493 494 495 496 497  | Next Page >