Search Results

Search found 25022 results on 1001 pages for 'lua table'.

Page 496/1001 | < Previous Page | 492 493 494 495 496 497 498 499 500 501 502 503  | Next Page >

  • Replacing Text which does not match a pattern in Oracle

    - by kutekrish
    I have below text in a CLOB in a table Table Name: tbl1 Columns col1 - number (Primary Key) col2 - clob (as below) Row#1 ----- Col1 = 1 Col2 = 1331882981,ab123456,Some text here which can run multiple lines and have a lot of text... ~1331890329,pqr123223,Some more text... Row#2 ----- Col1 = 2 Col2 = 1331882981,abc333,Some text here which can run multiple lines and have a lot of text... ~1331890329,pqrs23,Some more text... Now I need to know how we can get below output Col1 Value ---- --------------------- 1 1331882981,ab123456 1 1331890329,pqr123223 2 1331882981,abc333 2 1331890329,pqrs23 ([0-9]{10},[a-z 0-9]+.), == This is the regular expression to match "1331890329,pqrs23" and I need to know how can replace which are not matching this regex and then split them into multiple rows

    Read the article

  • how to store data with many categories and many properties efficiently?

    - by Mickey Shine
    We have a large number of data in many categories with many properties, e.g. category 1: Book properties: BookID, BookName, BookType, BookAuthor, BookPrice category 2: Fruit properties: FruitID, FruitName, FruitShape, FruitColor, FruitPrice We have many categories like book and fruit. Obviously we can create many tables for them (MySQL e.g.), and each category a table. But this will have to create too many tables and we have to write many "adapters" to unify manipulating data. The difficulties are: 1) Every category has different properties and this results in a different data structure. 2) The properties of every categoriy may have to be changed at anytime. 3) Hard to manipulate data if each category a table (too many tables) How do you store such kind of data?

    Read the article

  • Best way to order by columns in relationships?

    - by Timmy
    im using sqlalchemy, and i have a few polymorphic tables, and i want to sort by a column in one of the relationship. i have tables a,b,c,d, with relationship a to b, b to c, c to d. a to b is one-to-many b to c and c to d are one-to-one, but polymorphic. given an item in table a, i will have a list of items b, c, d (all one to one). how do i use sqlalchemy to sort them by a column in table d?

    Read the article

  • How to make IE and Firefox display hidden elements the same (IE shifts visible element)

    - by Dale
    Rendering the same html in IE and Firefox gives me a different result because in IE, the hidden checkbox is not ignored, from a layout perspective: <html><head> <style type="text/css"> <!-- #checkboxhide { position: relative; visibility: hidden; font-size: 8.5pt; font-weight: font-family: verdana;} //--> </style> </head><body> <table><tr> <td>|</td> <td><span id="checkboxhide"><input type="checkbox" hidden="" name="blah"></span>|Greetings Earthings</td> </tr></table> </body></html> How can I get the two (or more) browsers to show the same thing?

    Read the article

  • Oracle: Finding Columns with only null values

    - by Jorge Valois
    I have a table with a lot of columns and a type column. Some columns seem to be always empty for a specific type. I want to create a view for each type and only show the relevant columns for each type. Working under the assumption that if a column has ONLY null values for a specific type, then that columns should not be part of the view, how can you find that out with queries? Is there a SELECT [columnName] FROM [table] WHERE [columnValues] ARE ALL [null] I know I COMPLETELY made it all up above... I'm just trying to get the idea across. Thanks in advance!

    Read the article

  • Hibernate Query - Get latest versions by timestamp?

    - by Slim
    I have a database that is being used as a sort of version control system. That is, instead of ever updating any rows, I add a new row with the same information. Each row also contains a version column that is a date timestamp, so the only difference is the new row will have a more recent timestamp. What I'm having trouble with is writing an efficient hibernate query to return the latest version of these rows. For the sake of example, these are rows in a table called Product, the timestamped column is version. There are multiple versions of multiple products in the table. So there may be multiple versions (rows) of ProductA, multiple versions of ProductB, etc. And I would like to grab the latest version of each. Can I do this in just a single hibernate query? session.createQuery("select product from Product product where...?"); Or would this require some intermediate steps?

    Read the article

  • Rails 3: Create an instance with 3 foreign keys.

    - by donald
    Hello, Having a reviews table: # Table name: reviews # # id :integer not null, primary key # wsp_id :integer # service_id :integer # user_id :integer # description :text # rating :integer # created_at :datetime # updated_at :datetime # belongs_to :wsp belongs_to :service belongs_to :user How can I create a review for a service and pass the wsp_id and user_id? Do I need to use nested routes? I am able to do @user.reviews.new(params[:review]) but I'm not being able of passing the wsp_id and the service_id. Here's my Reviews create controller. def create @review = current_user.reviews.new(params[:review]) if @review.save #Saved else #Error, not saved end end What am I doing wrong? Thank you!

    Read the article

  • How to assign HTML value to a asp.net string variable

    - by Zerotoinfinite
    I am using asp.net and C#. I want to send mail to my user in HTML format, I have the content in HTML format let say like this <table style="width:100%;"> <tr> <td style="width:20%; background-color:Blue;"></td> <td style="width:80%; background-color:Green;"></td> </tr> </table> Now I am unable to assign this to a string variable, so that I could send it as a mail. Please let me know how can I bind this whole HTML content into a varibale. Also, please note that the above code is only a demo, I have around 100 lines of HTML code.

    Read the article

  • sql unite fields to one result

    - by none
    i know this is a "not build in" or "the way dba thinks" but a programmer aproach , How could one request from 3 fields to get the one that is not null, into a result filed. lets say we have a table with f1,f2,f3,f4,f5. lets say f2,f3,f4 are the same type. lets say the content of the table be tupples of (key1,null,null,value1,value2) (key2,null,value3,value4,value5) (key3,null,null,null,value6) now if we return the first tupple then we get (key1) we get (key1,value1,value2) if we ask for key2 we get (key1,value3,value5) if we ask for key3 we get (key1,null,value6) how is it possible to get the fields in the priority of if you have value in f2, then its set into the returned field, only then if we have value in f3 then its set into the middle returned field, only then if we have value in f4 then its set into the middle returned field the main goal is to get the result into a sigel feild and prevent the overhead work needed at the result end.

    Read the article

  • Working by group by for grouping data into string format

    - by Shantanu Gupta
    I have a table that contains some data given below. It uses a tree like structure i.e. Department SubD1, SubD2 ..... PreSubD1, PreSubD1... PreSubD2, PreSubD2... pk_map_id preferences ImmediateParent Department_Id -------------------- -------------------- -------------------- -------------------- 20 14 5 1 21 15 5 1 22 16 6 1 23 9 4 2 24 4 3 2 25 24 20 2 26 25 20 2 27 23 13 2 I want to group my records on behalf of department then immediate parent then preferences each seperated by ',' i.e. department Immediate Parent preferences 1 5,6 14,15,16 2 4,3,20,13 9,4,24,25,23 and this table also Immediate parent preferences 5 14,15 6 16 4 9 3 4 20 24,25 13 13 In actual scenario all these are my ids which are to be replaced by their string fields. I am using sql server 2k5

    Read the article

  • Dates that intersect

    - by MikeAbyss
    Hi everyone, I've been researching this problem for awhile now and I can't seem to come to a solution, hopefully someone here can help. Currently I'm working with Microsoft SQL server management, I've been trying to do the following: Previously, the old query would just return the results that fit between two dates Heres the previous query: SELECT e.Name, o.StartDate, o.EndDate FROM dbo.Name e, dbo.Date o WHERE where e.Name = o.Name and o.StartDate <= '2010-09-28 23:59:59' and o.EndDate >= '2010-9-28 00:00:00' and e.Name like 'A' Example table that is produced after the query runs (The real table has a lot more rows obviously :P) : Name Start End A 2010-09-28 07:00:00 2010-09-28 17:00:00 A 2010-09-28 13:45:00 2010-09-28 18:00:00 A 2010-09-28 08:00:00 2010-09-28 16:00:00 A 2010-09-28 07:00:00 2010-09-28 15:30:00 However we need to change this, so that the query does the following: find the dates that intersect for a day x find the dates that don't intersect for a day x I've found a real useful site regarding this http://bloggingabout.net/blogs/egiardina/archive/2008/01/30/check-intersection-of-two-date-ranges-in-sql.aspx However the date to compare against is inputted, mine on the other hand has to all dates that intersect/don't intersect. Thanks for the help everyone.

    Read the article

  • How to make same UIWebView take data from different local .html files?

    - by Mike Rychev
    I have an app, where there's one UIWebView and a UITableView. I don't want to create many .xib's, so I decided to make one .xib for all elements of the table. When user chooses a table element, the UIWebView appears and I want it to load data from different .html's depending on the name of the parent controller. I tried this: if (selectedTableElement==@"FirstElement") { [childController.message loadRequest:[NSURLRequest requestWithURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:@"_" ofType:@"html"]isDirectory:NO]]]; } And then myWebView=message; But it didn't work. Thanks in advance!

    Read the article

  • create a model in create action from a class

    - by Pontek
    As a newbie to rails I can't find how to solve my issue ^^ I want to create a VideoPost from a form with a text field containing a video url (like youtube) I'm getting information on the video thanks to the gem https://github.com/thibaudgg/video_info And I want to save thoses information using a model of mine (VideoInformation). But I don't know how the create process should work. Thanks for any help ! I'm trying to create a VideoPost in VideoPostsController like this : def create video_info = VideoInfo.new(params[:video_url]) video_information = VideoInformation.create(video_info) #undefined method `stringify_keys' for #<Youtube:0x00000006a24120> if video_information.save @video_post = current_user.video_posts.build(video_information) end end My VideoPost model : # Table name: video_posts # # id :integer not null, primary key # user_id :integer # video_information_id :integer # created_at :datetime not null # updated_at :datetime not null My VideoInformation model (which got same attributes name than VideoInfo gem) : # Table name: video_informations # # id :integer not null, primary key # title :string(255) # description :text # keywords :text # duration :integer # video_url :string(255) # thumbnail_small :string(255) # thumbnail_large :string(255) # created_at :datetime not null # updated_at :datetime not null

    Read the article

  • Gridview inside UpdatePanel refresh

    - by Attilah
    I use a GridView to represent data from a table in my DB. the GridView has some template fields whose content are determined before displaying the Grid ( I use the RowDataBound event to determine content of template fields before displaying the GridView). The page displays a list of records from the table records and then, the recording process starts. after the process is over, the template fields should be updated. how do I automatically refresh the GridView after the process is finished ? it should be noted that the GridView is contained within an control and that I continuously poll the server using a Timer control that executes "GridView1.DataBind()" at the server level every 60 seconds. since the GridView is inside an UpdatePanel, calling DataBind() method on it doesn't seem to call the RowDataBound event. How can I solve this ?

    Read the article

  • Sorting and displaying a custom QVariant type.

    - by Kranar
    Hello, I have a custom type I'd like to use with QVariant but I don't know how to get the QVariant to display in a table or have it sort in a QSortFilterProxyModel. I register the type with Q_DECLARE_METATYPE and wrote streaming operators registered via qRegisterMetaTypeStreamOperators but for whatever reason when I use the type with a table model, it doesn't display anything and it doesn't sort. I should specify that this custom type can not be modified. It has a copy and default constructor, but I can not go in and modify the source code to get it to work with QVariant. Is there a way of non-intrusively getting the behaviour I'd like?

    Read the article

  • How do I select from a stored procedure in Sybase?

    - by Nick Fortescue
    My DBA has constructed me a stored procedure in a Sybase database, for which I don't have the definition. If I run it, it returns a resultset with a set of columns and values. I would like to SELECT further to reduce the rows in the result set. Is this possible? From this question it seems like I could insert the results into a temporary table, but I'm not sure I've got permissions to do this. Is there any way I can SELECT certain rows, or if not, can someone give me example code for simulating with a temporary table?

    Read the article

  • NSTableview weird error

    - by Matt S.
    I followed the guide here, but for some reason, the table view shows this in the console when I attempt to scroll through it: -[NSCFString objectAtIndex:]: unrecognized selector sent to instance 0x100227710

    Read the article

  • Help with MySQL and CASE WHEN with a range of values

    - by kickdaddy
    I have an accounts table and a records table where accounts have multiple records. I would like to break down the account totals by "count of records" range. i.e. show the breakdown of Count of Records | Count 0-25 | 100 25 - 50 | 122 50 - 100 | 300 etc. I am using the following query, but I can't get it to group by "grp" which is what I want, any help on the best way to modify query? Thanks! SELECT count(*) as ct, CASE WHEN COUNT(*) < 25 THEN '1-25' WHEN COUNT(*) >= 25 < 50 THEN '25-50' WHEN COUNT(*) >= 50 < 100 THEN '50-100' WHEN COUNT(*) >= 100 < 250 THEN '100-250' WHEN COUNT(*) >= 250 < 500 THEN '250-500' WHEN COUNT(*) >= 500 < 1000 THEN '500-1000' ELSE '1000+' END AS grp FROM records r,accounts a WHERE r.account_id=a.id ORDER BY ct

    Read the article

  • How to concatenate text on existing database entry?

    - by Starx
    I have a table, whose fields are id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using 'WHERE 1;' to denote every row. Anyone know how to accomplish this?

    Read the article

  • Multipart Identifier And Functions

    - by The King
    Here is my Query... Here I'm using a function Fn_getStagesForProject()... For which I need to pass the SWProjectID from Projects Table... The function takes the ID as parameter and return all stages that corressponds to the project, on which I need to filer only the row that contains StageLevel as 0. Select A.SWProjectID, A.ShortTitle, C.StageName as StageName, B.ExpectedCompletionDate as BudgetedReleaseDate From Projects as A left outer join ProjectBudgets as B on A.SWProjectID = B.SWProjectID Left outer join Fn_getStagesForProject(Projects.SWProjectID) as C on B.StageID = C.StageID Where C.StageLevel = 0 The error is The multi-part identifier "Projects.SWProjectID" could not be bound. I tried changing it to A.SWProjectID, but I still get the error... Thanks in advance for your help. Let me know, incase you need the Table Structure Raja

    Read the article

  • related categories - database design

    - by mike
    Hello! I'm looking for a little database design advice... I have a spreadsheet with a few columns in it. Column 1 being a list of categories and the rest being related categories(to the category in column 1). I'm trying to figure out what the best way to setup the tables would be... My thought so far is to have a table that just lists the categories then have a table with 2 columns that holds the id of the category and the id of a related category.... Would this be the best way to do this? Any better ideas?

    Read the article

  • INSERT SQL in Java

    - by Pierre
    Hello. I have a Java application and I want to use SQL database. I have a class for my connection : public class SQLConnection{ private static String url = "jdbc:postgresql://localhost:5432/table"; private static String user = "postgres"; private static String passwd = "toto"; private static Connection connect; public static Connection getInstance(){ if(connect == null){ try { connect = DriverManager.getConnection(url, user, passwd); } catch (SQLException e) { JOptionPane.showMessageDialog(null, e.getMessage(), "Connection Error", JOptionPane.ERROR_MESSAGE); } } return connect; } } And now, in another class I succeeded to print my values but when I attempt to insert a value nothing is happening ... Here's my code : try { Statement state = SQLConnection.getInstance().createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_READ_ONLY); Statement state2 = SQLConnection.getInstance().createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,ResultSet.CONCUR_UPDATABLE); state2.executeUpdate("INSERT INTO table(field1) VALUES (\"Value\")"); // Here's my problem ResultSet res = state.executeQuery("SELECT * FROM plateau");

    Read the article

< Previous Page | 492 493 494 495 496 497 498 499 500 501 502 503  | Next Page >