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  • PHP Multi-Domain Sessions; ini_set Not Working?

    - by SumWon
    Hello, I'm trying to set it up so if you log in to my website the session carries over to all sub-domains of my website. For example, if you go to domain.com and log in, then go to sub.domain.com, you'll already be logged in at sub.domain.com. To my understanding, you would want to use ini_set('session.cookie_domain','.domain.com') and then session_start(), then set your session variables, but this isn't working. Example of what I'm doing: Code for domain.com: <?php ini_set('session.cookie_domain','.domain.com'); session_start(); $_SESSION['variable'] = 1; ?> Code for sub.domain.com: <?php session_start(); echo $_SESSION['variable']; ?> But $_SESSION['variable'] isn't set. I've also tried using ini_set() in the sub.domain.com code, but it made no difference. I've verified that setting session.cookie_domain is working by using ini_get(). What am I doing wrong? Thanks!

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  • CodeIgniter: help with this query

    - by iamjonesy
    Hi, I have just started my first CI app. I have a view that displays some posts. Each post can have multiple comments and I want to display the total number of comments next to each post. So far all my db call are in my controller (will be changing this). function index(){ $data['query'] = $this->db->get('posts'); $this->load->view('blog_view', $data); } In my view: <?php foreach($query->result() as $row): <div class="post-box"> <p><?php echo $row->body; ?><small>&nbsp;added by <?php echo $row->username; ?> on <?php echo date ('d/m/Y',strtotime($row->created)); ?>&nbsp;<a href="<?php echo base_url(); ?>blog/comments/<?php echo $row->id; ?>"><img src="<?php echo base_url(); ?>images/comments_icon.png" />&nbsp;0</a></small></p> </div> <?php endforeach; ?> I want to get the total number of comments where comment.post_id = the current record's id. and display it next to the comments icon. Any help with this most appreciated, Billy

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  • Is there a maximum number of input controls that can be used on an HTML form?

    - by Rich
    I have an ambitious requirement for an asp.net 2.0 web page that contains a table (gridview), and each row in the grid contains 6 select (dropdown) controls for data entry. The number of rows that will be displayed is dependent upon the user's search parameters, which are specified in another area of the page. Unfortunately, with the default (and even basic) search parameters specified, the grid could contain several hundred rows. I've noticed that the browser, in this case IE8, starts behaving rather erratically once I reach a large number of rows -- no documented evidence for the number of rows where this begins to be a problem. For example, trying to view the source of the page results in a message from IE stating that there was a problem with the page that forced the browser to reload it, and I never get the source. Obviously the page loads and renders rather slowly also. I know that my solution is probably going to involve paging the gridview such that it only displays 20 or so rows per page, and I'll have to write code to handle the saving of changes in the dropdown values when the user changes pages. I can probably turn off viewstate on the gridview also. However, the question I really want to pose is this -- has anyone seen a documented rule indicating the maximum number of input controls that an HTML browser form is supposed to be able to contain? I could not find anything on the Internet after doing a search, and I suspect the answer may be whatever the browser can handle based on the machine configuration it is running on. Any rules of thumb you use? Thanks for any suggestions. Rich

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  • How to catch this low level MySQL (?) error in PHP/Magento

    - by andnil
    When I'm executing the following statement in Magento with a really large $sku, the execution terminates without any errors thrown what so ever. There are no errors in either Magento's, Apache's or PHP's error logs. Mage::getModel('catalog/product')-loadByAttribute('sku', $sku); Question: How do I catch the error? I've tried to set custom error handlers, and for testing purposes I've also managed to trigger error situations where each of the error handler functions are invoked. But when running the previously mentioned Magento code with a large $sku, none of the error handling functions are executed. error_reporting( -1 ); set_error_handler( array( 'Error', 'captureNormal' ) ); set_exception_handler( array( 'Error', 'captureException' ) ); register_shutdown_function( array( 'Error', 'captureShutdown' ) ); For completeness, this is the $sku I'm passing to loadByAttribute(). (The sku is invalid, but that is not the issue) 1- 9685 0102046|1- 9685 1212100|1- 9685 1212092|1- 9685 1212096|1- 9685 1102100|1- 9685 1102108|1- 9685 1102112|1- 9685 1102092|1- 9685 0102048|1- 9685 0102054|1- 9685 0102056|1- 9685 0102058|1- 9685 1212104|1- 9685 1212108|1- 9685 0212058|1- 9685 0104050|1- 9685 0212050|1- 9685 0212056|1- 9685 0212044|1- 9685 0212048|1- 9685 0212052|1- 9685 0212054|1- 9685 1102104|1- 9685 1102124 Any insight into this matter is much appreciated! Update: Upon further investigation, this is the exact point in the code where execution terminates. when the foreach is executed I guess Magento goes into MySQL world and starts loading up data from the database. \Mage\Catalog\Model\Abstract.php public function loadByAttribute($attribute, $value, $additionalAttributes = '*') { $collection = $this->getResourceCollection() ->addAttributeToSelect($additionalAttributes) ->addAttributeToFilter($attribute, $value) ->setPage(1,1); foreach ($collection as $object) { // <--------------- HERE return $object; } return false; } Note, I'm ONLY interested in finding out how to properly CATCH these kinds of errors, not "fix" the logic. This is so that I can present a proper error message to the user. The example above with the malformed sku is contrived and I have no desire to make my Magento app work with those erroneous skus.

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  • Help - use PHP-broswer, or proxy or get_page_contents or include page, or something else ??

    - by userlite
    Hi, I am trying to develop a web application for which I need to capture a specific user-driven event (such as mouse dblclick) occurring on a different-website page loaded through my website. What I want to do is : User visits my website - hosted by me. There, user types in any website URL (e.g.: http://www.example.com) That URL page gets loaded as is. When user double-clicks mouse over any link or image from that page, a popup/side-panel is displayed with content related to that particular image or link. I can do this with a combination of PHP get_page_contents or include-page, and javascript dblclick. However, when user clicks on any link or submits a form, the control goes to that other website, where I cannot show the side-panel. I might be able to handle the links by proxifying them when user clicks on any of them. How do I handle forms submission and other stuff ? I can use a full-featured proxy, but that will be too heavy just for the purpose of capturing the event. My question is that is there a way to write some kind of light PHP script that sits on my website - that loads other websites contents as is, but lets me capture the mouse-dblclick event to show related-content in the side panel . I have already searched the internet, but could not find anything. Any help is really appreciated. Thanks.

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  • How do you send email from IMAP account with PHP?

    - by arthurakay
    I'm having an issue sending email via PHP/IMAP - and I don't know if it's because: I don't correctly understand IMAP, or there's an issue with my server My application opens an IMAP connection to an email account to read messages in the inbox. It does this successfully. The problem I have is that I want to send messages from this account and have them display in the outbox/sent folder. As far as I can tell, the PHP imap_mail() function doesn't in any way hook into the IMAP stream I currently have open. My code executes without throwing an error. However, the email never arrives to the recipient and never displays in my sent folder. private function createHeaders() { return "MIME-Version: 1.0" . "\r\n" . "Content-type: text/html; charset=iso-8859-1" . "\r\n" . "From: " . $this->accountEmail . "\r\n"; } private function notifyAdminForCompleteSet($urlToCompleteSet) { $message = " <p> In order to process the latest records, you must visit <a href='$urlToCompleteSet'>the website</a> and manually export the set. </p> "; try { imap_mail( $this->adminEmail, "Alert: Manual Export of Records Required", wordwrap($message, 70), $this->createHeaders() ); echo(" ---> Admin notified via email!\n"); } catch (Exception $e) { throw new Exception("Error in notifyAdminForCompleteSet()"); } } I'm guessing I need to copy the message into the IMAP account manually... or is there a different solution to this problem? Also, does it matter if the domain in the "from" address is different than that of the server on whicn this script is running? I can't explain why the message is never sent.

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  • How do I create and populate a non-uniformly structured array in PHP?

    - by stormist
    I am trying to decide on a data structure for an array that has a date for the key and the amount of bandwidth consumed as values. examples Key Consumed Policy October 50 Basic November 75 Basic December 100 Basic Some months, but not all, will have more than one policy. In that case, I need break them down by policy once the total is shown. So for the above example, assume December had 3 policies. The table i construct from my array would then need to show: Key Consumed Policy October 50 Basic November 75 Basic December 100 .. December 25 Basic December 25 Extended December 50 Premium Could all this data be represented in an array ? $myArray['december'] would be a different data structure than the others because it would need a last entry, probably another array, that had the policy names as keys and the amount of data consumed as values. Does PHP allow for arrays that are not structured uniformly? i.e. key october and November have only 2 entries under their key while December has 2 entries plus a 3rd which is an additional array. My best guess is something like: Array ( [October] => "50", "Basic" [November] => "75", "Basic" [December] => "100", "..", Array( [Basic] => 25 [Extended] =>25 [Premium] => 50 ) ) My question is if this is possible and how to declare it and populate it with values with PHP. Thanks in advance for any clarifications or assistance!

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  • Get Form Input via Ajax

    - by user3651491
    I have a jqgrid plugin which I call via Ajax. I have index.php and a getGridData.php. How will I pass form input in getGridData.php via ajax and use it in getGridData.php? I tried serialize but I can't pass or access it on getGridData.php. I need it as parameters for mysql. Here's my code. <script language="javascript" type="text/javascript"> function jgGrid() { $(document).ready(function () { $("#grid").jqGrid({ url: "inc/Controller/getGridData.php"+$("#thisForm").serialize(), data : formData, datatype: "json", mtype: "POST", colNames: ["SiteID", "TerminalID", "TransactionType", "Amount", "ServiceStatus"], colModel: [ { name: "SiteID"}, { name: "TerminalID"}, { name: "TransactionType"}, { name: "Amount"}, { name: "ServiceStatus"}, ], pager: "#pager", rowNum: 10, rowList: [10,20], sortname: "SiteID", sortorder: "asc", height: 'auto', viewrecords: true, gridview: true, caption: "" }); }); } </script> getGridData.php include('../Model/Queries.php'); $cardnumber = $_POST['cardnumber']; $transact_type = $_POST['transact_type']; $fromdate = $_POST['fromdate']; $todate = $_POST['todate']; $loyalty = new Queries(); $get_mid = $loyalty->loyaltyConn($cardnumber); $somedata = json_encode($loyalty->nposConn($get_mid, $transact_type, $fromdate, $todate)); echo $somedata;

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  • How to increase my "advanced" knowledge of PHP further? (quickly)

    - by Kerry
    I have been working with PHP for years and gotten a very good grasp of the language, created many advanced and not-so-advanced systems that are working very well. The problem I'm running into is that I only learn when I find a need for something that I haven't learned before. This causes me to look up solutions and other code that handles the problem, and so I will learn about a new function or structure that I hadn't seen before. It is in this way that I have learned many of my better techniques (such as studying classes put out by Amazon, Google or other major companies). The main problem with this is the concept of not being able to learn something if you don't know it exists. For instance, it took me several months of programming to learn about the empty() function, and I simply would check the string length using strlen() to check for empty values. I'm now getting into building bigger and bigger systems, and I've started to read blogs like highscalability.com and been researching MySQL replication and server data for scaling. I know that structure of your code is very important to make full systems work. After reading a recent blog about reddit's structure, it made me question if there is some standard or "accepted systems" out there. I have looked into frameworks (I've used Kohana, which I regretted, but decided that PHP frameworks were not for me) and I prefer my own library of functions rather than having a framework. My current structure is a mix between WordPress, Kohana and my own knowledge. The ways I can see as being potentially beneficial are: Read blogs Read tutorials Work with someone else Read a book What would be the best way(s) to "get to the next level" the level of being a very good system developer?

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  • Retrieving values from a table in HTML using jQuery?

    - by Mo
    Hi i was just wondering whats the best way to retrieve the following labels and values from this HTMl code using jquery and storing them in to a array or hash map of some sort where i have for e.g "DataSet:" : "prod" or ["Dataset", "Prod"]? <table id="metric_summary"> <tbody> <tr class="editable_metrics"> <td><label>DataSet:</label></td> <td><input name="DataSet" value="prod"></td> </tr> <tr class="editable_metrics"> <td><label>HostGroup:</label></td> <td><input name="HostGroup" value="MONITOR-PORTAL-IAD"></td> </tr> <tr class="editable_metrics"> <td><label>Host:</label></td> <td><input name="Host" value="ALL"></td> </tr> <tr class="editable_metrics"> <td><label>Class:</label></td> <td><input name="Class" value="CPU"></td> </tr> <tr class="editable_metrics"> <td><label>Object:</label></td> <td><input name="Object" value="cpu"></td> </tr> <tr class="editable_metrics"> <td><label>Metric:</label></td> <td><input name="Metric" value="CapacityCPUUtilization"></td> </tr> thanks

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  • Duplicate information from sql result

    - by puddleJumper
    I looked in about 18 other posts on here an most people are asking how to delete the records not just hide them. So my problem: I have a database with staff members who are associated with locations. Many of the staff members are associated with more than one location. What I want to do is to only display the first location listed in the mysql result and skip over the others. I have the sql query linking the tables together and it works aside from it showing the same information for those staff members that are in those other locations multiple times so example would be like this: This is the sql statement I have currently SELECT staff_tbl.staffID, staff_tbl.firstName, staff_tbl.middleInitial, staff_tbl.lastName, location_tbl.locationID, location_tbl.staffID, officelocations_tbl.locationID, officelocations_tbl.officeName, staff_title_tbl.title_ID, staff_title_tbl.staff_ID, titles_tbl.titleID, titles_tbl.titleName FROM staff_tbl INNER JOIN location_tbl ON location_tbl.staffID = staff_tbl.staffID INNER JOIN officelocations_tbl ON location_tbl.locationID = officelocations_tbl.locationID INNER JOIN staff_title_tbl ON staff_title_tbl.staff_ID = staff_tbl.staffID INNER JOIN titles_tbl ON staff_title_tbl.title_ID = titles_tbl.titleID and my php is <?php do { ?> <tr> <td><?php echo $row_rs_Staff_Info['firstName']; ?>&nbsp; <?php echo $row_rs_Staff_Info['lastName']; ?></td> <td><?php echo $row_rs_Staff_Info['titleName']; ?>&nbsp; </td> <td><?php echo $row_rs_Staff_Info['officeName']; ?>&nbsp; </td> </tr> <?php } while ($row_mysqlResult = mysql_fetch_assoc($rs_mysqlResult)); ?> What I would like to know is there a way using php to select only the first entry listed for each person and display that and just skip over the other two. I was thinking it could be done by possibly adding the staffID's to an array and if they are in there to skip over the next one listed in the staff_title_tbl but wasn't quite sure how to write it that way. Any help would be great thank you in advance.

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  • How to limit a user to entering 10 keywords or less using PHP & MySQL?

    - by G4TV
    I'm trying to limit my users to entering at least 10 keywords and was wondering how would I be able to do this using PHP & MySQL with my current Keyword script? Here is the add keywords PHP MySQL code. if (isset($_POST['tag']) && trim($_POST['tag'])!=='') { $tags = explode(",", $_POST['tag']); for ($x = 0; $x < count($tags); $x++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = "INSERT INTO tags (tag) VALUES ('" . mysqli_real_escape_string($mysqli, strtolower(htmlentities(trim(strip_tags($tags[$x]))))) . "')"; if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM tags WHERE tag='" . mysqli_real_escape_string($mysqli, strtolower(htmlentities(trim(strip_tags($tags[$x]))))) . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO question_tags (tag_id, question_id, user_id, date_created) VALUES ('$id', '$question', '$user', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } } }

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  • Parallel MySQL queries for HTML table - WHILE(x or y)?

    - by Beti Chode
    I'm trying to create a table using PHP. What I need is a table with two columns. So I have an SQL table with 4 fields - primary key id, language, word and definition. The language for each is either Arabic or Russian. I want a table that does the following: | defintion | |____________________| | | | rus1 | arab1 | | rus2 | arab2 | | rus3 | arab3 | | rus4 | | So it divides the list by English word, creates a for each English word, then lists Russian equivalents in the left column and Arabic in the right. However there are often not the same number for both. What I am doing right now is running a WHILE loop in a WHILE loop. The outer loop is running fine but I think I am doing the inner loop wrong. Here is the bulk of the code: $definitions=mysql_query("SELECT DISTINCT definition FROM words") WHILE($row=mysql_fetch_array($definitions) { ECHO '<tr><th colspan="2">' . $row['definition'] . '</th></tr>'; $russian="SELECT * FROM words WHERE language='Russian' AND definition='".$row['definition']."'"; $arabic="SELECT * FROM words WHERE language='Arabic' AND definition='".$row['definition']."'"; WHILE($rus=mysql_fetch_array($russian) or $arb=mysql_fetch_array($arabic)) { ECHO '<tr><td>'.$rus['word'].'</td><td>'.$arb['word'].'</td></tr>'; } } Sadly I am getting soemthing like this: | defintion | |____________________| | | | rus1 | | | rus2 | | | rus3 | | | rus4 | | | | arab1 | | | arab2 | | | arab3 | Not sure what other way I can do this? I tried changing the or to || thinking the different precedence would cause another outcome, but then I get ONLY the Russian column. I'm out of ideas, you guys are my only hope!

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  • make selectable area using javascript

    - by Mher
    lets say I have a html page. <html> <body> ... This is my HTML Page, full of html objects and mouse events on them ... <div id='blocker' style="height: 100%; position: absolute; width: 100%; top: 0px; left: 0px; right: 0px; bottom: 0px; z-index: 1001; background: none repeat scroll 0% 0% black; opacity: 0.5;"></div> <div id='window_to_my_html_page' style="display: block; left: 50px; top: 50px; width: 200px; height: 200px; z-index: 1002; position: absolute;"></div> </body> </html> In this example div which id is 'blocker' will block all mouse events from my page. All my HTML page elements behind of my second div(which id is 'window_to_my_html_page') must be active, all mouse events must work on them, this div must be like a window to my HTML page I want to make all elements from my HTML page active(to work as normal) inside this area (left: 50px; top: 50px; width: 200px; height: 200px).... and other content, outside of this area make inactive The question: how can I do it?

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  • [PHP] Does unsetting array values during iterating save on memory?

    - by saturn_rising
    Hello fellow code warriors, This is a simple programming question, coming from my lack of knowledge of how PHP handles array copying and unsetting during a foreach loop. It's like this, I have an array that comes to me from an outside source formatted in a way I want to change. A simple example would be: $myData = array('Key1' => array('value1', 'value2')); But what I want would be something like: $myData = array([0] => array('MyKey' => array('Key1' => array('value1', 'value2')))); So I take the first $myData and format it like the second $myData. I'm totally fine with my formatting algorithm. My question lies in finding a way to conserve memory since these arrays might get a little unwieldy. So, during my foreach loop I copy the current array value(s) into the new format, then I unset the value I'm working with from the original array. E.g.: $formattedData = array(); foreach ($myData as $key => $val) { // do some formatting here, copy to $reformattedVal $formattedData[] = $reformattedVal; unset($myData[$key]); } Is the call to unset() a good idea here? I.e., does it conserve memory since I have copied the data and no longer need the original value? Or, does PHP automatically garbage collect the data since I don't reference it in any subsequent code? The code runs fine, and so far my datasets have been too negligible in size to test for performance differences. I just don't know if I'm setting myself up for some weird bugs or CPU hits later on. Thanks for any insights. -sR

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  • what this json must work?

    - by user1772630
    hi i search alot for get a respone from php back and if that respone is ok do someting and if its false do something else(!!!!!!!! WHENE I HAVE OTHER OUTPUT FROM THAT PHP !!!!!!) this is my index file <head> <script src="jquery-1.7.2.js" type="text/javascript"></script> <script src="js.js" type="text/javascript"></script> </head> <body> <p> click </p> <input type="text" id="who"> <br> <input type="text" id="why"> <div id="bg" align="center"> </div> </body> this is my JS file $(document).ready(function(){ $('p').click(function(){ var who = $('input#who').val(); var why = $('input#why').val(); $.post('file.php',{who:who,why:why},function(data) { if(data.success){ alert(data.message); } else{ alert('ERROR:' + data.message); } }); }); }); and this is my file.php <?php $response = array('success' => 'true', 'code' => "jQuery('#bg').html('\"Javascript\", \"json\", \"PHP\"');"); echo json_encode($response); ?> my question : 1- why this is not work i get alert (error:undifined) 2- how i can get some result from that php file when its have other output like this: <?php echo "1"; echo "2"; echo "3"; and now echo that json ?> thanks :(

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  • A quiz with results

    - by Keon Davies
    I'm currently working on programming a quiz withe results. I've tried this: <html> <body> <h1></h1> <form> <ol> <li> How much are you willing to spend on a phone per month?</li> <ul> <li><input type = "radio" name = "q1" id="q1_1"> £5-£10.</input></li> <li><input type = "radio" name = "q1" id="q1_2"> £10-£15.</input></li> <li><input type = "radio" name = "q1" id="q1_3"> £15-£20.</input></li> <li><input type = "radio" name = "q1" id="q1_4"> £20-£25.</input></li> <li><input type = "radio" name = "q1" id="q1_5"> £25-£30.</input></li> <li><input type = "radio" name = "q1" id="q1_6"> £30-£35.</input></li> <li><input type = "radio" name = "q1" id="q1_7"> £35-£40.</input></li> </ul> <li> Are you good with technology</li> <ul> <li><input type = "radio" name = "q2" id="q2_1"> Yes.</input></li> <li><input type = "radio" name = "q2" id="q2_2"> No.</input></li> </ul> <li> Are you looking for an easy to use phone</li> <ul> <li><input type = "radio" name = "q3" id="q3_1"> Yes.</input></li> <li><input type = "radio" name = "q3" id="q3_2"> No.</input></li> </ul> <li> Are you looking for a modern type of phone?</li> <ul> <li><input type = "radio" name = "q4" id="q4_1"> Yes.</input></li> <li><input type = "radio" name = "q4" id="q4_2"> No.</input></li> </ul> <li> How big do you want the phone to be?</li> <ul> <li><input type = "radio" name = "q5" id="q5_1"> Big.</input></li> <li><input type = "radio" name = "q5" id="q5_2"> Medium.</input></li> <li><input type = "radio" name = "q5" id="q5_3"> Small.</input></li> <li><input type = "radio" name = "q5" id="q5_4"> I don't really mind.</input></li> </ul> <li> Do you care about the colour of the phone?</li> <ul> <li><input type = "radio" name = "q6" id="q6_1"> Yes.</input></li> <li><input type = "radio" name = "q6" id="q6_2"> No.</input></li> </ul> <li> Have you ever owned a phone before?</li> <ul> <li><input type = "radio" name = "q7" id="q7_1"> Yes.</input></li> <li><input type = "radio" name = "q7" id="q7_2"> No.</input></li> </ul> <li> Do you want to be able to use the phone to get out of awkward social situations?</li> <ul> <li><input type = "radio" name = "q8" id="q8_1"> Yes.</input></li> <li><input type = "radio" name = "q8" id="q8_2"> No.</input></li> </ul> <li> Do you want to be able to access the app store and download apps using your phone?</li> <ul> <li><input type = "radio" name = "q9" id="q9_1"> Yes.</input></li> <li><input type = "radio" name = "q9" id="q9_2"> No.</input></li> </ul> <li> What happened to the last phone you owned?</li> <ul> <li><input type = "radio" name = "q10" id="q10_1"> I got bored of it.</input></li> <li><input type = "radio" name = "q10" id="q10_2"> It broke.</input></li> <li><input type = "radio" name = "q10" id="q10_3"> The contract ran out.</input></li> <li><input type = "radio" name = "q10" id="q10_4"> Other.</input></li> </ul> </ol> <input type = "button" value = "Submit" onclick="getResults()"> <input type = "reset" value = "Clear"></input> <textarea id="result">The right phone for you will be displayed here.</textarea> </html> <script> function getResults() { if (document.getElementById('q1_1').checked && document.getElementById('q2_1').checked && document.getElementById('q3_1').checked && document.getElementById('q4_1').checked && document.getElementById('q5_1').checked && document.getElementById('q6_1').checked && document.getElementById('q7_1').checked && document.getElementById('q8_1').checked && document.getElementById('q9_1').checked && document.getElementById('q10_1').checked ) { document.getElementById('result').innerHTML = 'Unfortunately, the iPhone is the right phone for you.'; } } </script> </body> But it's just too long winded. Is there any other ways I can design a quiz like this but without having to write a block of code for each radio button?

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  • Success function not being called when form is submitted. jQuery / validationEngine / PHP form proce

    - by Tom Hartman
    Hi, I've been trying to figure out why the following script's success function isn't running. Everything in my form works perfectly, and the form contents are being emailed correctly, but the success function isn't being called. If anyone could review my code and let me know why my success function isn't being called I would very much appreciate it! Here is the HTML form with notification divs, which are hidden via css: <div id="success" class="notification"> <p>Thank you! Your message has been sent.</p> </div> <div id="failure" class="notification"> <p>Sorry, your message could not be sent.</p> </div> <form id="contact-form" method="post" action="" class="jqtransform"> <label for="name">Name:</label> <input name="name" id="name" type="text" class="validate[required] input" /> <label for="company">Company:</label> <input name="company" id="company" type="text" class="input" /> <label for="phone">Phone:</label> <input name="phone" id="phone" type="text" class="input" /> <label for="email">Email:</label> <input name="email" id="email" type="text" class="validate[required,email] input" /> <div class="sep"></div> <label for="subject">Subject:</label> <input name="subject" id="subject" type="text" class="validate[required] input" /> <div class="clear"></div> <label for="message">Message:</label> <textarea name="message" id="message" class="validate[required]"></textarea> <div id="check-services"> <input type="checkbox" name="services[]" value="Contractor Recommendation" /> <div>Contractor Recommendation</div> <input type="checkbox" name="services[]" value="Proposal Review" /> <div>Proposal Review</div> <input type="checkbox" name="services[]" value="Existing Website Review" /> <div>Existing Website Review</div> <input type="checkbox" name="services[]" value="Work Evaluation" /> <div>Work Evaluation</div> <input type="checkbox" name="services[]" value="Layman Translation" /> <div>Layman Translation</div> <input type="checkbox" name="services[]" value="Project Management" /> <div>Project Management</div> </div> <div class="sep"></div> <input name="submit" id="submit" type="submit" class="button" value="Send" /> <input name="reset" id="reset" type="reset" class="button" value="Clear" onclick="$.validationEngine.closePrompt('.formError',true)" /> </form> Here is the javascript: // CONTACT FORM VALIDATION AND SUBMISSION $(document).ready(function(){ $('#contact-form').validationEngine({ ajaxSubmit: true, ajaxSubmitFile: 'lib/mail.php', scroll: false, success: function(){ $('#success').slideDown(); }, failure: function(){ $('#failure').slideDown(); $('.formError').animate({ marginTop: '+30px' }); } }); }); And here is my PHP mailer script: <?php $name = $_POST['name']; $company = $_POST['company']; $phone = $_POST['phone']; $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; $services = $_POST['services']; $to = '[email protected]'; $subject = 'THC - Contact'; $content .= "You received a message from ".$name.".\r\n\n"; if ($company): $content .= "They work for ".$company.".\r\n\n"; endif; $content .= "Here's the message:\r\n\n".$message."\r\n\n"; $content .= "And they are interested in the services below:\r\n\n"; $content .= implode("\r\n",$services); if ($phone): $content .= "\r\n\nYou can reach them at ".$phone."."; else: $content .= "\r\n\nNo phone number was provided."; endif; $headers = "From: ".$name."\r\n"; $headers .= "Reply-To: ".$email."\r\n"; if (mail($to,$subject,$content,$headers)): return true; else: return false; endif; ?>

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  • Why does Cacti keep waiting for dead poller processes?

    - by Oliver Salzburg
    sorry for the length I am currently setting up a new Debian (6.0.5) server. I put Cacti (0.8.7g) on it yesterday and have been battling with it ever since. Initial issue The initial issue I was observing, was that my graphs weren't updating. So I checked my cacti.log and found this concerning message: POLLER: Poller[0] Maximum runtime of 298 seconds exceeded. Exiting. That can't be good, right? So I went checking and started poller.php myself (via sudo -u www-data php poller.php --force). It will pump out a lot of message (which all look like what I would expect) and then hang for a minute. After that 1 minute, it will loop the following message: Waiting on 1 of 1 pollers. This goes on for 4 more minutes until the process is forcefully ended for running longer than 300s. So far so good I went on for a good hour trying to determine what poller might still be running, until I got to the conclusion that there simply is no running poller. Debugging I checked poller.php to see how that warning is issued and why. On line 368, Cacti will retrieve the number of finished processes from the database and use that value to calculate how many processes are still running. So, let's see that value! I added the following debug code into poller.php: print "Finished: " . $finished_processes . " - Started: " . $started_processes . "\n"; Result This will print the following within seconds of starting poller.php: Finished: 0 - Started: 1 Waiting on 1 of 1 pollers. Finished: 1 - Started: 1 So the values are being read and are valid. Until we get to the part where it keeps looping: Finished: - Started: 1 Waiting on 1 of 1 pollers. Suddenly, the value is gone. Why? Putting var_dump() in there confirms the issue: NULL Finished: - Started: 1 Waiting on 1 of 1 pollers. The return value is NULL. How can that be when querying SELECT COUNT()...? (SELECT COUNT() should always return one result row, shouldn't it?) More debugging So I went into lib\database.php and had a look at that db_fetch_cell(). A bit of testing confirmed, that the result set is actually empty. So I added my own database query code in there to see what that would do: $finished_processes = db_fetch_cell("SELECT count(*) FROM poller_time WHERE poller_id=0 AND end_time>'0000-00-00 00:00:00'"); print "Finished: " . $finished_processes . " - Started: " . $started_processes . "\n"; $mysqli = new mysqli("localhost","cacti","cacti","cacti"); $result = $mysqli->query("SELECT COUNT(*) FROM poller_time WHERE poller_id=0 AND end_time>'0000-00-00 00:00:00';"); $row = $result->fetch_assoc(); var_dump( $row ); This will output Finished: - Started: 1 array(1) { ["COUNT(*)"]=> string(1) "2" } Waiting on 1 of 1 pollers. So, the data is there and can be accessed without any problems, just not with the method Cacti is using? Double-check that! I enabled MySQL logging to make sure I'm not imagining things. Sure enough, when the error message is looped, the cacti.log reads as if it was querying like mad: 06/29/2012 08:44:00 PM - CMDPHP: Poller[0] DEVEL: SQL Cell: "SELECT count(*) FROM cacti.poller_time WHERE poller_id=0 AND end_time>'0000-00-00 00:00:00'" 06/29/2012 08:44:01 PM - CMDPHP: Poller[0] DEVEL: SQL Cell: "SELECT count(*) FROM cacti.poller_time WHERE poller_id=0 AND end_time>'0000-00-00 00:00:00'" 06/29/2012 08:44:02 PM - CMDPHP: Poller[0] DEVEL: SQL Cell: "SELECT count(*) FROM cacti.poller_time WHERE poller_id=0 AND end_time>'0000-00-00 00:00:00'" But none of these queries are logged my MySQL. Yet, when I add my own database query code, it shows up just fine. What the heck is going on here?

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  • Can't get Postfix Admin to use Dovecot password hashing

    - by Paul
    I'm setting up Postfix Admin 2.91 and trying to use dovecot:SHA512-CRYPT for password hashing. In config.inc.php I have set: // dovecot:CRYPT-METHOD = use dovecotpw -s 'CRYPT-METHOD'. Example: dovecot:CRAM-MD5 // (WARNING: don't use dovecot:* methods that include the username in the hash - you won't be able to login to PostfixAdmin in this case) $CONF['encrypt'] = 'dovecot:SHA512-CRYPT'; // If you use the dovecot encryption method: where is the dovecotpw binary located? // for dovecot 1.x // $CONF['dovecotpw'] = "/usr/sbin/dovecotpw"; // for dovecot 2.x (dovecot 2.0.0 - 2.0.7 is not supported!) $CONF['dovecotpw'] = "/usr/sbin/doveadm pw"; I have also tried SHA256-CRYPT and MD5-CRYPT with same results (as I understand it, these do not include usernames in the hash) In running setup.php, I get the following message when trying to create an admin account: can't encrypt password with dovecotpw, see error log for details Server error log reports: 1624#0: *6 FastCGI sent in stderr: "PHP message: dovecotpw password encryption failed. PHP message: STDERR output: sh: 1: /usr/sbin/doveadm: not found" while reading response header from upstream <...> upstream: "fastcgi://unix:/var/run/php5-fpm.sock:" <...> A couple quick checks: # ll /usr/sbin/doveadm -rwxr-xr-x 1 root root 423264 Feb 13 23:23 /usr/bin/doveadm* # doveadm pw -l CRYPT MD5 MD5-CRYPT SHA SHA1 SHA256 SHA512 SMD5 SSHA SSHA256 SSHA512 PLAIN CLEAR CLEARTEXT PLAIN-TRUNC CRAM-MD5 SCRAM-SHA-1 HMAC-MD5 DIGEST-MD5 PLAIN-MD4 PLAIN-MD5 LDAP-MD5 LANMAN NTLM OTP SKEY RPA SHA256-CRYPT SHA512-CRYPT # doveadmin pw -s SHA512-CRYPT Enter new password: Retype new password: {SHA512-CRYPT}$6$<long string here>/ Using Dovecot 2.2, PHP 5.5, MariaDB 10, Postfix 2.11, nginx 1.6.0, Ubuntu 12.04.

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  • We Convert your PSD into Xhtml

    - by Aditi
    From last few months we have been receiving a lot of inquires for  Psd into Xhtml projects, while we were majorly focusing on custom WordPress, Magento, Drupal & Joomla Projects. Now we are offering PSD into Xhtml/CSS service at an affordable price looking at its demand. We also will cater PSD into any CMS, like wordpress, Drupal, Magento or Joomla. Our custom services will continue as it is. It is very convenient to get your design converted by our Xhtml & CSS experts. We assure 24 hour delivery time. At JustSkins, we have a structured conversion model that works well for any kind of potentially enriched web business solution. Our customized slicing guidelines, besides, W3C approved XHTML and CSS code naming conventions makes us stand distinct from the competitors. Why Should You Let us do it for you? W3C Compliant HTML/XHTML and CSS Codes Well Structured and Written Code. Clean and Hand Coded Mark up no use of WYSIWYG. We offer Fast turn around timeDesign converted into Xhtml/CSS just in one business day. Multi- Browser Accessible Websites Cross-Platform Support. Excellent Customer Service. Affordable We at JustSkins are team of efficient programmers with vast experience in templating for   content management systems (CMS),  Joomla, Drupal, WordPress and other Open Source technologies. Contact us today for your requirement!

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  • Apache2 on Raspbian: Multiviews is enabled but not working

    - by Christian L
    I recently moved webserver, from a ubuntuserver set up by my brother (I have sudo) to a rasbianserver set up by my self. On the other server multiviews worked out of the box, but on the raspbian it does not seem to work althoug it seems to be enabled out of the box there as well. What I am trying to do is to get it to find my.doma.in/mobile.php when I enter my.doma.in/mobile in the adress field. I am using the same available-site-file as I did before, the file looks as this: <VirtualHost *:80> ServerName my.doma.in ServerAdmin [email protected] DocumentRoot /home/christian/www/do <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /home/christian/www/do> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> From what I have read various places while googling this issue I found that the negotiation module had to be enabled so I tried to enable it. sudo a2enmod negotiation Giving me this result Module negotiation already enabled I have read through the /etc/apache2/apache2.conf and I did not find anything in particular that seemed to be helping me there, but please do ask if you think I should post it. Any ideas on how to solve this through getting Multiviews to work?

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  • Zipcodes in CSV Generation

    - by BRADINO
    When exporting to CSV format, then opening in a spreadsheet program like Excel zipcodes that start with a zero or zeroes have the preceding zeros stripped off. Obviously it is because the spreadsheet sees that column as integers and preceding zeros in integers are useless. A quick and dirty trick to force Excel (hopefully you are using OpenOffice) to display the full zipcode, we wrap it in double quotes and put an equal sign in front of it, to force it to be a string like this: $zipcode = 00123; $data = '="' . $zipcode . '"' ; So if you are doing the straight query to CSV export, using the fputcsv function it would look something like this. Basically just overwrite the value in the row and then continue along. while ($row = mysql_fetch_assoc($query)){         $row['zipcode'] = '="'.$row['zipcode'].'"';     fputcsv($output, $row); } php csv zipcode csv number csv force string

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  • Fatal error: Incompatible file format: The encoded file has format major ID 1, whereas the Loader expects 4 in ... on line 0

    - by Eugene
    I am using Ubuntu 10.04 and for some time I had to keep a downgraded PHP 5.2 package because I need to run Zend encrypted scripts. Recently I noticed that Zend released beta version of their loader (http://forums.zend.com/viewtopic.php?f=57&t=1365&start=80#p22073) so I updated to the native PHP 5.3 package, downloaded the .so file, added this to php.ini ;zend_extension=/etc/php5/ZendOptimizer.so zend_extension=/etc/php5/ZendGuardLoader.so zend_loader.enable=1 zend_loader.disable_licensing=0 zend_loader.obfuscation_level_support=3 and restarted the server. Now I am getting this error: Fatal error: Incompatible file format: The encoded file has format major ID 1, whereas the Loader expects 4 in ... on line 0 Do you by chance know an easy fix for this? Or should I downgrade back and wait till when they release something more stable?

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  • Downgrade form php5 5.3.10 to php5 5.3.2 in ubuntu 12.04

    - by iori
    i wanted to install php5 5.3.2, so first deleted all the php5 files sudo apt-get purge php5 php5-cli php5-common php5-mysql and also delete the deb files form /var/cache/apt/archives so now there is no deb file on the system then i add this person repository sudo apt-add-repository ppa:sushkov/personal because he add php5.3.2 and then i updated it and upgraded it sudo apt-get update && sudo apt-get upgrade then i installed php5 sudo apt-get install php5 php5-cli php5-common php5-mysql now when i check the php version it says php5.3.10 and when i run this command sudo apt-cache show php5 it says Package: php5 Version: 5.3.15-1~dotdeb.0 Architecture: all Maintainer: Guillaume Plessis <[email protected]> Installed-Size: 0 Depends: libapache2-mod-php5 (>= 5.3.15-1~dotdeb.0) | libapache2-mod-php5filter (>= 5.3.15-1~dotdeb.0) | php5-cgi (>= 5.3.15-1~dotdeb.0) | php5-fpm (>= 5.3.15-1~dotdeb.0), php5-common (>= 5.3.15-1~dotdeb.0) Filename: dists/squeeze/php5/binary-i386/php5_5.3.15-1~dotdeb.0_all.deb now i dont know how to downgrade, is there any way that i change something in the repository and write sudo apt-get install php5 it will install php5.3.2 which i want instead of php5.3.10 Thanks

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