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Search found 195 results on 8 pages for 'abhishek kaushik'.

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  • oracle using index even though there is no filter criteeria specified

    - by Kaushik
    In this query: SELECT WTTEMPLATE.TEMPLATEuID, MAX (WTTRX.VALUEDATE) AS template_last_use_date FROM wttemplate, wttrx WHERE WTTEMPLATE.TEMPLATEID = WTTRX.TEMPLATEID(+) AND WTTEMPLATE.CUSTID = WTTRX.CUSTID GROUP BY WTTEMPLATE.TEMPLATEuID The explain plan shows:index fast full scan using indexes on WTTEMPLATE.TEMPLATEID and (WTTRX.TEMPLATEID,WTTRX.CUSTID). My question is this: I have not specified any filter criteria , so how can it use indexes? It should do full scan...right?

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  • traverse a binary decison tree using python?

    - by kaushik
    how to traverse a binary decision tree using python language. given a tree,i want know how can we travesre from root to required leaf the feature of the required leaf are given in an dictionary form assume and have to traverse from root to leaf answering the questions at each node with the details given in feature list.. the decision tree node has format ((question)(left tree)(right tree)) while traversing it should answer question at each node and an choose left or right and traverse till leaf?

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  • In Python, how do I search a flat file for the closest match to a particular numeric value?

    - by kaushik
    have file data of format 3.343445 1 3.54564 1 4.345535 1 2.453454 1 and so on upto 1000 lines and i have number given such as a=2.44443 for the given file i need to find the row number of the numbers in file which is most close to the given number "a" how can i do this i am presently doing by loading whole file into list and comparing each element and finding the closest one any other better faster method? my code:i need to ru this for different file each time around 20000 times so want a fast method p=os.path.join("c:/begpython/wavnk/",str(str(str(save_a[1]).replace('phone','text'))+'.pm')) x=open(p , 'r') for i in range(6): x.readline() j=0 o=[] for line in x: oj=str(str(line).rstrip('\n')).split(' ') o=o+[oj] j=j+1 temp=long(1232332) end_time=save_a[4] for i in range((j-1)): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • index error:list out of range

    - by kaushik
    from string import Template from string import Formatter import pickle f=open("C:/begpython/text2.txt",'r') p='C:/begpython/text2.txt' f1=open("C:/begpython/text3.txt",'w') m=[] i=0 k='a' while k is not '': k=f.readline() mi=k.split(' ') m=m+[mi] i=i+1 print m[1] f1.write(str(m[3])) f1.write(str(m[4])) x=[] j=0 while j<i: k=j-1 l=j+1 if j==0 or j==i: j=j+1 else: xj=[] xj=xj+[j] xj=xj+[m[j][2]] xj=xj+[m[k][2]] xj=xj+[m[l][2]] xj=xj+[p] x=x+[xj] j=j+1 f1.write(','.join(x)) f.close() f1.close() It say line 33,xj=xj+m[l][2] has index error,list out of range please help thanks in advance

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  • how to speed up code??

    - by kaushik
    i want to speed my code compilation..I have searched the internet and heard that psyco is a very tool to improve the speed.i have searched but could get a site for download. i have installed any additional libraries or modules till date in my python.. can psyco user,tell where we can download the psyco and its installation and using procedures?? i use windows vista and python 2.6 does this work on this ??

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  • related to list and file handling?

    - by kaushik
    i have file with contents in list form such as [1,'ab','fgf','ssd'] [2,'eb','ghf','hhsd'] [3,'ag','rtf','ssfdd'] i want to read that file line by line using f.readline and assign thn to a list so as to use it is the prog as a list for using list properties tried like k=[ ] k=f.readline() print k[1] i xpected a result to show 2nd element in the list in first line but it showed the first bit and gave o/p as '1' how to get the xpected output.. please suggest

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  • Using classes for the first time,help in debugging

    - by kaushik
    here is post my code:this is no the entire code but enough to explain my doubt.please discard any code line which u find irrelavent enter code here saving_tree={} isLeaf=False class tree: global saving_tree rootNode=None lispTree=None def __init__(self,x): file=x string=file.readlines() #print string self.lispTree=S_expression(string) self.rootNode=BinaryDecisionNode(0,'Root',self.lispTree) class BinaryDecisionNode: global saving_tree def __init__(self,ind,name,lispTree,parent=None): self.parent=parent nodes=lispTree.getNodes(ind) print nodes self.isLeaf=(nodes[0]==1) nodes=nodes[1]#Nodes are stored self.name=name self.children=[] if self.isLeaf: #Leaf Node print nodes #Set the leaf data self.attribute=nodes print "LeafNode is ",nodes else: #Set the question self.attribute=lispTree.getString(nodes[0]) self.attribute=self.attribute.split() print "Question: ",self.attribute,self.name tree={} tree={str(self.name):self.attribute} saving_tree=tree #Add the children for i in range(1,len(nodes)):#Since node 0 is a question # print "Adding child ",nodes[i]," who has ",len(nodes)-1," siblings" self.children.append(BinaryDecisionNode(nodes[i],self.name+str(i),lispTree,self)) print saving_tree i wanted to save some data in saving_tree{},which i have declared previously and want to use that saving tree in the another function outside the class.when i asked to print saving_tree it printing but,only for that instance.i want the saving_tree{} to have the data to store data of all instance and access it outside. when i asked for print saving_tree outside the class it prints empty{}.. please tell me the required modification to get my required output and use saving_tree{} outside the class..

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  • How to specify java script files required by an angular app

    - by Vishal Kaushik
    I'm looking for a way to specify required js files by an angular app. So that, we don't need to include an array of tag for all the files which may be required by some ng-app. The main idea behind this requirement is - we might not need to load all the resources on the browser at once. Which ever ng-app gets loaded onto the screen, will fetch its dependencies on its own from the server. Is there any existing way within angularJS to achieve this goal..?

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  • directory and file related doubts??

    - by kaushik
    i have a directory with around 1000 files....i want to run a same code for each of these file... my code requires the file name to be inputted. i have written code to copy the information of one into other in other format... please suggest a method to copy all 1000 files one by one without need to change the file name every time and i have a field serial_num which need to be continous i.e if 1st file has upto 30 then while coping other file it should continue from 30not from 0 again require suggestion please thanks..

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  • command line arg?

    - by kaushik
    This is a module named XYZ. def func(x) ..... ..... if __name__=="__main__": print func(sys.argv[1]) Now I have imported this module in another code and want to use the func. How can i use it? import XYZ After this, where to give the argument, and syntax on how to call it, please?

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  • using python,How to cut the wav file between certain time ranges??

    - by kaushik
    How to cut the wav file between certain time ranges from multiple wav files and paste the segments together in a single wav file in continous time ?? For this i thou of a way,to store the contents of the wav file in array form and cut the segments required from the array copy thm in another file and convert it back into wav formant. but i hav no idea how to code it in python as i am a beginner in it.. plz help...any alternative methods which serve the purpose are also welcome.. Quick reply,xpected plzz.. Thanks in advance..

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  • wav file manupalation

    - by kaushik
    I want get the details of the wave such as its frames into a array of integers. Using fname.getframes we can ge the properties of the frame and save in list or anything for writing into another wav or anything,but fname.getframes gives information not in integers some thing like a "/xt/x4/0w' etc.. But i want them in integer so that would be helpful for manupation and smoothening join of 2 wav files

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  • any faster alternative??

    - by kaushik
    have file data of format 3.343445 1 3.54564 1 4.345535 1 2.453454 1 and so on upto 1000 lines and i have number given such as a=2.44443 for the given file i need to find the row number of the numbers in file which is most close to the given number "a" how can i do this i am presently doing by loading whole file into list and comparing each element and finding the closest one any other better faster method?

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  • Websphre portal does not startup

    - by Kaushik
    When I try to start up a websphere portal server, it hangs at the line : Server WebSphere_Portal open for e-business and although it means that the server started up successfully, it is not...because in the progress bar, i stll see 'Starting.....' I have tried deleting the wstemp and temp directories but beyond that I am not sure what I can do to debug the problem. The server with the same profile starts up great from another workspace, but when I come to this workspace, it just hangs at Server WebSphere_Portal open for e-business I am using RAD 7 and portal 6.1

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  • problem with f.readline()?

    - by kaushik
    I am reading one line at a time from a file, but at the end of each line it adds a '\n'. example: line is: 094 234 hii but my input is: 094 234 hii\n I want to read line by linem but I don't need to keep the newlines... My goal is to read a list from every line: I need ['094','234','hii'], not ['094','234','hii\n'] Any advice?

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  • Uploading Files to AWS S3 from an Android App

    - by Abhishek Kaushik
    Edited 7th June,14 My Android app needs to have a feature where clients can upload their files. I want AWS S3 as my storage. Moreover i dont want to use SECRET_KEY and ACCESS_KEY_ID on client side. What is the the best way to do this. Can someone provide the working code too ? I read that i can request to AWS for a signed URL and then make client directly upload to that URL. How to achieve this ?

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  • WPF - List View Row Index and Validation

    - by abhishek
    Hi, I have a ListView with TextBoxes in second column. I want to validate that my text box does not contain a number if the third column(data_type) is "Text". I am unable to do the validation. I tried a few approaches. In one approach I try to handle the MouseDown event and am trying to get the Row number so that I can get the data_type value of that row. I want to us this value in the Validate method. I have been struggling for a week now. Would appreciate if anybody could help. <ControlTemplate x:Key="validationTemplate"> <DockPanel> <TextBlock Foreground="Red" FontSize="20">!</TextBlock> <AdornedElementPlaceholder/> </DockPanel> </ControlTemplate> <Style x:Key="textBoxInError" TargetType="{x:Type TextBox}"> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={x:Static RelativeSource.Self}, Path=(Validation.Errors)[0].ErrorContent}"/> </Trigger> </Style.Triggers> </Style> <DataTemplate x:Key="textTemplate"> <TextBox HorizontalAlignment= "Stretch" IsEnabled="{Binding XPath=./@isenabled}" Validation.ErrorTemplate="{StaticResource validationTemplate}" Style="{StaticResource textBoxInError}"> <TextBox.Text> <Binding XPath="./@value" UpdateSourceTrigger="PropertyChanged"> <Binding.ValidationRules> <local:TextBoxMinMaxValidation> <local:TextBoxMinMaxValidation.DataType> <local:DataTypeCheck Datatype="{Binding Source={StaticResource dataProvider}, XPath='/[@id=CustomerServiceQueueName]'}"/> </local:TextBoxMinMaxValidation.DataType> <local:TextBoxMinMaxValidation.ValidRange> <local:Int32RangeChecker Minimum="{Binding Source={StaticResource dataProvider}, XPath=./@min}" Maximum="{Binding Source={StaticResource dataProvider}, XPath=./@max}"/> </local:TextBoxMinMaxValidation.ValidRange> </local:TextBoxMinMaxValidation> </Binding.ValidationRules> </Binding > </TextBox.Text> </TextBox> </DataTemplate> <DataTemplate x:Key="dropDownTemplate"> <ComboBox Name="cmbBox" HorizontalAlignment="Stretch" SelectedIndex="{Binding XPath=./@value}" ItemsSource="{Binding XPath=.//OPTION/@value}" IsEnabled="{Binding XPath=./@isenabled}" /> </DataTemplate> <DataTemplate x:Key="booldropDownTemplate"> <ComboBox Name="cmbBox" HorizontalAlignment="Stretch" SelectedIndex="{Binding XPath=./@value, Converter={StaticResource boolconvert}}"> <ComboBoxItem>True</ComboBoxItem> <ComboBoxItem>False</ComboBoxItem> </ComboBox> </DataTemplate> <local:ControlTemplateSelector x:Key="myControlTemplateSelector"/> <Style x:Key="StretchedContainerStyle" TargetType="{x:Type ListViewItem}"> <Setter Property="HorizontalContentAlignment" Value="Stretch" /> <Setter Property="Template" Value="{DynamicResource ListBoxItemControlTemplate1}"/> </Style> <ControlTemplate x:Key="ListBoxItemControlTemplate1" TargetType="{x:Type ListBoxItem}"> <Border SnapsToDevicePixels="true" x:Name="Bd" Background="{TemplateBinding Background}" BorderBrush="{DynamicResource {x:Static SystemColors.ActiveBorderBrushKey}}" Padding="{TemplateBinding Padding}" BorderThickness="0,0.5,0,0.5"> <GridViewRowPresenter SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"/> </Border> </ControlTemplate> <Style x:Key="CustomHeaderStyle" TargetType="{x:Type GridViewColumnHeader}"> <Setter Property="Background" Value="LightGray" /> <Setter Property="FontWeight" Value="Bold"/> <Setter Property="FontFamily" Value="Arial"/> <Setter Property="HorizontalContentAlignment" Value="Left" /> <Setter Property="Padding" Value="2,0,2,0"/> </Style> </UserControl.Resources> <Grid x:Name="GridViewControl" Height="Auto"> <Grid.RowDefinitions> <RowDefinition Height="*" /> <RowDefinition Height="34"/> </Grid.RowDefinitions> <ListView x:Name="ListViewControl" Grid.Row="0" ItemContainerStyle="{DynamicResource StretchedContainerStyle}" ItemTemplateSelector="{DynamicResource myControlTemplateSelector}" IsSynchronizedWithCurrentItem="True" ItemsSource="{Binding Source={StaticResource dataProvider}, XPath=//CONFIGURATION}"> <ListView.View > <GridView > <GridViewColumn Header="ID" HeaderContainerStyle="{StaticResource CustomHeaderStyle}" DisplayMemberBinding="{Binding XPath=./@id}"/> <GridViewColumn Header="VALUE" HeaderContainerStyle="{StaticResource CustomHeaderStyle}" CellTemplateSelector="{DynamicResource myControlTemplateSelector}" /> <GridViewColumn Header="DATATYPE" HeaderContainerStyle="{StaticResource CustomHeaderStyle}" DisplayMemberBinding="{Binding XPath=./@data_type}"/> <GridViewColumn Header="DESCRIPTION" HeaderContainerStyle="{StaticResource CustomHeaderStyle}" DisplayMemberBinding="{Binding XPath=./@description}" Width="{Binding ElementName=ListViewControl, Path=ActualWidth}"/> </GridView> </ListView.View> </ListView> <StackPanel Grid.Row="1"> <Button Grid.Row="1" HorizontalAlignment="Stretch" Height="34" HorizontalContentAlignment="Stretch" > <StackPanel HorizontalAlignment="Stretch" VerticalAlignment="Center" Orientation="Horizontal" FlowDirection="RightToLeft" Height="30"> <Button Grid.Row="1" Content ="Apply" Padding="0,0,0,0 " Margin="6,2,0,2" Name="btn_Apply" HorizontalAlignment="Right" VerticalContentAlignment="Center" HorizontalContentAlignment="Center" Width="132" IsTabStop="True" Click="btn_ApplyClick" Height="24" /> </StackPanel > </Button> </StackPanel > </Grid>

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  • Nested UIScrollView-iPhone photos application

    - by abhishek trivedi
    Hi, I have been facing the same nested UIScrollView problem for long time.I tried some open source codes like Scrolling madness ,three-20 and others but all fails finaly.I am trying to make a photo Viewer application same as iPhone.For that I have created the structure like this:- 1)one View controller. 2)on view of view controller one UIScrollView (i.e inner/parent scroll view) as a child. 3)on inner/parent scroll view number of child scroll views(i.e. outer/child scroll views) ,each represents one page of photos application. 4)On each scroll view one image View on which i am displaying my image. So what I want is when user scrolls the outer scroll view it should scroll horizontally with all the child views so I will get the look and feel of paging in photos application.Also when user is on one specific image(i.e. child/outer scroll view) he should be able to zoom in/out,swipes and perform single/double tapping.I was able to make it work in sdk 2.1,but it dosnt work since sdk 3.0.Please tell me the idea behind your project.Means which scroll view you are subclassing ,in which view to detect touches.How this completely child - parent relation should be. If possible provide any sample code also.

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  • jQuery datepicker validation message issue

    - by Abhishek
    Hi, I'm using the jquery datepicker plugin at http://plugins.jquery.com/project/datepick with the datepicker validation plugin. <script id="frmValidation" type="text/javascript"> $(document).ready(function(){ var validator = $("#frmTest").validate({ rules:{ fname: "required", dobPicker: "required" }, messages:{ fname: "Please enter a name", dobPicker: "Select a date" }, }); $('#dobPicker').datepick(); $.datepick.setDefaults({showOn: 'both', dateFormat: 'dd-mm-yy', yearRange:'1900:2010'}); }); </script> And the body of the document is as follows : <form id="frmTest" action="" method="post"> <div id="error-list"></div> <div class="form-row"> <span class="label"><label for="fname">Name</label></span> <input type="text" name="fname" /> </div> <div class="form-row"> <span class="label"><label for="dobPicker">DOB</label></span> <input type="text" id="dobPicker" name="dobPicker" style="margin-left: 4px;"/> </div> <div class="form-row"> <input type="submit" name="submit" value="submit"/> </div> </form> The form validates the first time but the error message for the datepicker does not disappear immediately a date is selected.. however it goes away if the date is selected the second time. Any help to make it go the first time a date is selected will be appreciated

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