Search Results

Search found 10060 results on 403 pages for 'column'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 5/403 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • R ggplot2: Arrange facet_grid by non-facet column (and labels using non-facet column)

    - by tommy-o-dell
    I have a couple of questions regarding facetting in ggplot2... Let's say I have a query that returns data that looks like this: (note that it's ordered by Rank asc, Alarm asc and two Alarms have a Rank of 3 because their Totals = 1798 for Week 4, and Rank is set according to Total for Week 4) Rank Week Alarm Total 1 1 BELTWEIGHER HIGH HIGH 1000 1 2 BELTWEIGHER HIGH HIGH 1050 1 3 BELTWEIGHER HIGH HIGH 900 1 4 BELTWEIGHER HIGH HIGH 1800 2 1 MICROWAVE LHS 200 2 2 MICROWAVE LHS 1200 2 3 MICROWAVE LHS 400 2 4 MICROWAVE LHS 1799 3 1 HI PRESS FILTER 2 CLOG SW 1250 3 2 HI PRESS FILTER 2 CLOG SW 1640 3 3 HI PRESS FILTER 2 CLOG SW 1000 3 4 HI PRESS FILTER 2 CLOG SW 1798 3 1 LOW PRESS FILTER 2 CLOG SW 800 3 2 LOW PRESS FILTER 2 CLOG SW 1200 3 3 LOW PRESS FILTER 2 CLOG SW 800 3 4 LOW PRESS FILTER 2 CLOG SW 1798 (duplication code below) Rank = c(rep(1,4),rep(2,4),rep(3,8)) Week = c(rep(1:4,4)) Total = c( 1000,1050,900,1800, 200,1200,400,1799, 1250,1640,1000,1798, 800,1200,800,1798) Alarm = c(rep("BELTWEIGHER HIGH HIGH",4), rep("MICROWAVE LHS",4), rep("HI PRESS FILTER 2 CLOG SW",4), rep("LOW PRESS FILTER 2 CLOG SW",4)) spark <- data.frame(Rank, Week, Alarm, Total) Now when I do this... s <- ggplot(spark, aes(Week, Total)) + opts( panel.background = theme_rect(size = 1, colour = "lightgray"), panel.grid.major = theme_blank(), panel.grid.minor = theme_blank(), axis.line = theme_blank(), axis.text.x = theme_blank(), axis.text.y = theme_blank(), axis.title.x = theme_blank(), axis.title.y = theme_blank(), axis.ticks = theme_blank(), strip.background = theme_blank(), strip.text.y = theme_text(size = 7, colour = "red", angle = 0) ) s + facet_grid(Alarm ~ .) + geom_line() I get this.... Notice that it's facetted according to Alarm and that the facets are arranged alphabetically. Two Questions: How can I can I keep it facetted by alarm but displayed in the correct order? (Rank asc, Alarm asc). Also, how can I keep it facetted by alarm but show labels from Rank instead of Alarm? Note that I can't just facet on Rank because ggplot2 would see only 3 facets to plot where there are really 4 different alarms. Thanks kindly for the help! Tommy

    Read the article

  • Dynamically change the width of Datagrid column in FLEX.

    - by user120118
    Hi, Can we change the width of the datagrid column dynamically by clicking on the border of the column in order to display the complete string which is too long to be displayed and needs to be scrolled ? If so, How ? Also, how can we ensure that the column width changes dynamically based on the number of characters / length of string; since many a times the data is too long to be displayed. Can we set the column width to take the length of data into consideration before displaying onto the datagrid ?

    Read the article

  • SQL Server: SELECT rows with MAX(Column A), MAX(Column B), DISTINCT by related columns

    - by z531
    Scenario: Table A MasterID, Added Date, Added By, Updated Date, Updated By, 1, 1/1/2010, 'Fred', null, null 2, 1/2/2010, 'Barney', 'Mr. Slate', 1/7/2010 3, 1/3/2010, 'Noname', null, null Table B MasterID, Added Date, Added By, Updated Date, Updated By, 1, 1/3/2010, 'Wilma', 'The Great Kazoo', 1/5/2010 2, 1/4/2010, 'Betty', 'Dino', 1/4/2010 Table C MasterID, Added Date, Added By, Updated Date, Updated By, 1, 1/5/2010, 'Pebbles', null, null 2, 1/6/2010, 'BamBam', null, null Table D MasterID, Added Date, Added By, Updated Date, Updated By, 1, 1/2/2010, 'Noname', null, null 3, 1/4/2010, 'Wilma', null, null I need to return the max added date and corresponding user, and max updated date and corresponding user for each distinct record when tables A,B,C&D are UNION'ed, i.e.: 1, 1/5/2010, 'Pebbles', 'The Great Kazoo', 1/5/2010 2, 1/6/2010, 'BamBam', 'Mr. Slate', 1/7/2010 3, 1/4/2010, 'Wilma', null, null I know how to do this with one date/user per row, but with two is beyond me. DBMS is SQL Server 2005. T-SQL solution preferred. Thanks in advance, Dave

    Read the article

  • Sort a data grid based on a specified column.

    - by o vamsi krishna
    Developed a winform project using VB 2008. I'm using a .xls sheet as source. My appln has 7 columns and unspecified rows. I want to sort all the columns based on a specified column and allot a serial number as per the sorted order. If two items in the specified column are same we should consider another column for the equal items and sort them in that order. plz help me in this issue.

    Read the article

  • iPhone Orientation Relayout From Single Column to Double Column

    - by kkrizka
    I am trying to create a UIView in Interface Builder that shows to the user two boxes containing some text. This UIView should support both landscape and portrait modes. When in portrait orientation, the two boxes should be centered horizontally and be under each other. Like in the picture below: But when in landscape orientation, it should show the two boxes centered vertically and by side by side. Like in the picture below: Is this possible using only the autosizing options (or any other IB options), or do I have to relayout the view in code on orientation change events? I would prefer using only IB. I tried locking the top and left margins of the top box and locking the bottom and right margins of the bottom box. But the problem is that for it to work I also need to shrink the two boxes as one changes from portrait to landscape, because otherwise they would overlap.

    Read the article

  • inserting null values in datetime column and integer column

    - by reggie
    I am using C# and developing a winform application. I have a project class which has the project attributes. the constructor of the project class is as follows: newProject = new Project(GCD_ID.IsNull() ? (int?)null : Convert.ToInt32(GCD_ID), txt_Proj_Desc.Text, txt_Prop_Name.Text, ST.ID.ToString().IsNull() ? null: ST.ID.ToString(), cmbCentre.Text, SEC.ID.ToString().IsNull() ? null : SEC.ID.ToString(), cmbZone.Text, FD.ID.ToString().IsNull() ? null : FD.ID.ToString(), DT.ID.ToString().IsNull() ? null : DT.ID.ToString(), OP.ID.ToString().IsNull() ? null : OP.ID.ToString(), T.ID.ToString().IsNull() ? null : T.ID.ToString(), CKV.ID.ToString().IsNull() ? null : CKV.ID.ToString(), STAT.ID.ToString().IsNull() ? null : STAT.ID.ToString(), MW.IsNull() ? (Double?)null : Convert.ToDouble(MW), txt_Subject.Text, Ip_Num.IsNull() ? (int?)null : Convert.ToInt32(Ip_Num), H1N_ID.IsNull() ? (int?)null : Convert.ToInt32(H1N_ID), NOMS_Slip_Num.IsNull() ? (int?)null : Convert.ToInt32(NOMS_Slip_Num), NMS_Updated.IsNull() ? (DateTime?)null : Convert.ToDateTime(NMS_Updated), Received_Date.IsNull() ? (DateTime?)null : Convert.ToDateTime(Received_Date), Actual_IS_Date.IsNull() ? (DateTime?)null : Convert.ToDateTime(Actual_IS_Date), Scheduled_IS_Date.IsNull() ? (DateTime?)null : Convert.ToDateTime(Scheduled_IS_Date), UpSt.ID.ToString().IsNull() ? null : UpSt.ID.ToString(), UpFd.ID.ToString().IsNull() ? null : UpFd.ID.ToString(), txtHVCircuit.Text, cmbbxSIA.Text); My problem is that i cannot insert values into the database when the datetime variables and the integer variables are null. all this data are assigned to the variable from textboxes on the form.. bELOW is the database function which takes in all the variables and insert them into the database. public static void createNewProject(int? GCD_ID, string Project_Desc, string Proponent_Name, int Station_ID, string OpCentre, int Sector_ID, string PLZone, int Feeder, int DxTx_ID, int OpControl_ID, int Type_ID, int ConnKV_ID, int Status_ID, double? MW, string Subject, int? Ip_Num, int? H1N_ID, int? NOMS_Slip_Num, DateTime? NMS_Updated, DateTime? Received_Date, DateTime? Actual_IS_Date, DateTime? Scheduled_IS_Date, int UP_Station_ID, int UP_Feeder_ID, string @HV_Circuit, string SIA_Required) { SqlConnection conn = null; try { //Takes in all the employee details to be added to the database. conn = new SqlConnection(databaseConnectionString); conn.Open(); SqlCommand cmd = new SqlCommand("createNewProject", conn); cmd.CommandType = CommandType.StoredProcedure; cmd.Parameters.Add(new SqlParameter("GCD_ID", GCD_ID)); cmd.Parameters.Add(new SqlParameter("Project_Desc", MiscFunctions.Capitalize(Project_Desc))); cmd.Parameters.Add(new SqlParameter("Proponent_Name", MiscFunctions.Capitalize(Proponent_Name))); cmd.Parameters.Add(new SqlParameter("Station_ID", Station_ID)); cmd.Parameters.Add(new SqlParameter("OpCentre", OpCentre)); cmd.Parameters.Add(new SqlParameter("Sector_ID", Sector_ID)); cmd.Parameters.Add(new SqlParameter("PLZone", PLZone)); cmd.Parameters.Add(new SqlParameter("Feeder", Feeder)); cmd.Parameters.Add(new SqlParameter("DxTx_ID", DxTx_ID)); cmd.Parameters.Add(new SqlParameter("OpControl_ID", OpControl_ID)); cmd.Parameters.Add(new SqlParameter("Type_ID", Type_ID)); cmd.Parameters.Add(new SqlParameter("ConnKV_ID", ConnKV_ID)); cmd.Parameters.Add(new SqlParameter("Status_ID", Status_ID)); cmd.Parameters.Add(new SqlParameter("MW", MW)); cmd.Parameters.Add(new SqlParameter("Subject", Subject)); cmd.Parameters.Add(new SqlParameter("Ip_Num", Ip_Num)); cmd.Parameters.Add(new SqlParameter("H1N_ID", H1N_ID)); cmd.Parameters.Add(new SqlParameter("NOMS_Slip_Num", NOMS_Slip_Num)); cmd.Parameters.Add(new SqlParameter("NMS_Updated", NMS_Updated)); cmd.Parameters.Add(new SqlParameter("Received_Date", Received_Date)); cmd.Parameters.Add(new SqlParameter("Actual_IS_Date", Actual_IS_Date)); cmd.Parameters.Add(new SqlParameter("Scheduled_IS_Date", Scheduled_IS_Date)); cmd.Parameters.Add(new SqlParameter("UP_Station_ID", UP_Station_ID)); cmd.Parameters.Add(new SqlParameter("UP_Feeder_ID", UP_Feeder_ID)); cmd.Parameters.Add(new SqlParameter("HV_Circuit", HV_Circuit)); cmd.Parameters.Add(new SqlParameter("SIA_Required", SIA_Required)); cmd.ExecuteNonQuery(); } catch (Exception e) //returns if error incurred. { MessageBox.Show("Error occured in createNewProject" + Environment.NewLine + e.ToString()); } finally { if (conn != null) { conn.Close(); } } } My question is, how do i insert values into the database. please please help

    Read the article

  • c# ListView focus on second column

    - by James
    I have a ListView with several columns, let's say column A,B,C,D in that order, sorted by column A. In long lists I could press a letter on my keyboard and scroll down to the first item in column A that begins with the letter pressed. A new column has been inserted at the beginning, yet I still want to be able to press a letter on my keyboard and scroll according to the values in column A which is now the second column. How can I set the focus back to column A without making it the first column?

    Read the article

  • virtual column for drop down in the ruby on rails.

    - by pramod
    How to place a drop down for the virtual column, in the ruby on rails. The virutal column does not exist in my table , but I want to get the value from the drop down ,when user saves the data. for example, product_price is a virtual column , which doesn't exist in my database table. But I would like to have a dropdown, with product price to be displayed from another table. And when user selects the product_price, the selected product_price should be gettable in an object as self.product_price. Virtual column for labels is working fine, but for drop down its not working for me..any info woud be Thankful...

    Read the article

  • Enable or disable column based on other column

    - by kundan
    Hello, I have Application with 3 columns Result - Radio button pass and Fail IF Fail - Radio Button Minor and Major Be Specific - Multiple Choice - Active X control/ Browser/ Display / Others I want to disable If fail and Be specific if Result is selected pass. How can I do it Thanks Kundan

    Read the article

  • Transformation of records 1 column 3 row -> 1 row 3 column

    - by Nehal Rupani
    First look at below query SELECT count(id) as total_record, id, modeller, MONTHNAME(completed_date) as current_month, Quarter(completed_date) as current_quarter, Difficulty, YEAR(completed_date) as current_year FROM model WHERE modeller != '' AND completed_date BETWEEN '2010-04-01' AND '2010-05-31' AND Difficulty != '' Group by Difficulty, Month(completed_date) Order by Month(completed_date) ASC Results I am getting is Modeller Month Year Difficulty ------------------------------------- XYZ Jan 2010 23 XYZ Jan 2010 14 XYZ Jan 2010 15 ABC Feb 2010 5 ABC Feb 2010 14 ABC Feb 2010 6 I want result like Modeller Month Year Difficulty -------------------------------------- XYZ Jan 2010 23, 14, 15 ABC Feb 2010 5, 14, 6 My database is Mysql for application i am developing so any help would be greatly appericated.

    Read the article

  • Check for unique rows, but ignore one particular column

    - by user269148
    I have an XML document, that looks like this: Column A to S with headers, and there are 1922 rows. This is an backup of some SMS, and I want to get rid of duplicates. The problem is, that the Time in the readable_date header has been messed up. There is nothing wrong with the date, but the clock time is wrong, so I have split that column in three, with Year, day and clock. I know I can use a standard filter, but it only looks for unique rows in a single column. What I want to perform, is to make a row check similar to this: F(x)=Check if Column 2A to (infinate) is equal to Column 3A to (infinate), but ignore column(R). IF True, then delete Column 3A to (infinate) Otherwise Check IF column 2A to (infinate) is equal Column 4A to (infinate) and so on. I need to ignore a particular column in a row every time, and need to do this for a complete sheet. And the formula check should apply for every row, when the first one is done checking for duplicates... If anyone else has a better solution, please say so. Anyway, anyone who can help?

    Read the article

  • Find MySQL entries with same set of column B values for their common column A value

    - by nnsd44g
    I have: +----+------+------+ | id | A | B | +----+------+------+ | 1 | 1 | 1 | < | 2 | 1 | 2 | < | 3 | 2 | 2 | | 4 | 2 | 3 | | 5 | 3 | 1 | < | 6 | 3 | 2 | < | 7 | 4 | 4 | | 8 | 4 | 5 | +----+------+------+ I need to select the entries that have the same set of B values for their common A value. So, in this case, I need ids 1, 2 and 5, 6 because in those cases the sequence of B values is 1, 2. Is this possible? Thanks!

    Read the article

  • MySQL Query Where Column Like Column

    - by shmeeps
    I'm working on a small project that involves grabbing a list of contacts which are stored for each group. Essentially, the database is set up so that each group has a primary and secondary contact stored as, unsurprisingly, Group.Primary and Group.Secondary. The objective is to pull every Primary and Secondary contact for each Group and display them in a sortable table. I have the sortable table all worked out, but I have come across a small problem. Each primary and secondary field can have more than one contact separated by a comma. For instance, if Primary contained 123,256 , it would need to pull both Contacts with IDs 123 and 256. I had intended to use a query formatted like this: SELECT * FROM Group G, Contacts C WHERE G.Primary LIKE %C.ID% OR G.Secondary LIKE %C.ID% so that I could just skip the comma part, but I can't seem to find a working query for this. My question to you is, am I just overlooking something here? Is there a simple query that would let me do this? Or am I better off getting the groups and contacts separately, and combine the two later. I think the former is a little easier to understand when read, which is a plus as this is a shared project, but if that is not possible I will do the latter. This code is simplified, but it gets the point across.

    Read the article

  • Select rows with same column A but different column B

    - by Flip Booth
    ID Zip Room ----------- ---------- ------ 317 94087 S105 318 94087 L603 1739 94404-1801 L603 1823 94401-2129 L603 1824 94401-2129 L603 2135 94404-1801 L603 2268 95136-1459 S604 2269 95136-1459 S604 3704 92673-6417 L402 4479 93454-9670 L402 4480 93454-9670 L402 4782 92395-4681 L402 4783 92395-4681 L402 4852 92886-4411 L402 4853 92886-4411 L402 4959 92673-6417 L402 5153 91773-4028 L402 5202 91773-4028 L402 5211 91765-2959 L402 5212 91765-2959 L402 5388 92336-0605 L402 5392 92336-0605 L402 5727 92870 L402 5728 92870 L402 5831 92557 L402 5916 92557 L402 How do I select ID's that has THE SAME zip but different Room ? In the table above, I want the result to be: ID Zip Room ----------- ---------- ------ 317 94087 S105 318 94087 L603 Using SQL Server 2008

    Read the article

  • How to find rows between other rows w/ID then add class

    - by Ravex
    Hi guys. i'm stuck with my table. need create toggle rows function. but i no idea how to find sub rows in table. Some one can help me? I have table with many rows 500 All Rows have class="row-1,row-2.....row-600 etc" And all main rows also have class="parent" between each "parent" rows i have 6 rows So i need for toggle/collapse purposes find all (sub)rows betwen parent rows. and add class with id like in prevous parent row. For example: parent have class="row-1 parent" all sub must have - class="child-row-1" default table <table id="table"> <tr class="row-1 odd parent"> <th class="column-1">st. 3 - 5</th> <th class="column-2">Profile</th> <th class="column-3">Purpose</th> </tr> <tr class="row-2 even"> <td class="column-1">Metal Stamp</td> <td class="column-2">Width</td> <td class="column-3">Price</td> </tr> <tr class="row-3 odd"> <td class="column-1">Circle 3 - 5</td> <td class="column-2">28-110</td> <td class="column-3">21500</td> </tr> <tr class="row-4 even"> <td class="column-1">Circle 3 - 5</td> <td class="column-2">115-180</td> <td class="column-3">20700</td> </tr> <tr class="row-5 odd"> <td class="column-1">Cube 3 - 5</td> <td class="column-2">63-80</td> <td class="column-3">21500</td> </tr> <tr class="row-6 even"> <td class="column-1">Cube 3 - 5</td> <td class="column-2">100-220</td> <td class="column-3">20700</td> </tr> <tr class="row-7 odd"> <td class="column-1">Line 3 - 5</td> <td class="column-2">10-50 ? 40-200</td> <td class="column-3">27000</td> </tr> </table> in the end it should look like this: <table id="table"> <tr class="row-1 odd parent"> <th class="column-1">st. 3 - 5</th> <th class="column-2">Profile</th> <th class="column-3">Purpose</th> </tr> <tr class="row-2 even child-row-1"> <td class="column-1">Metal Stamp</td> <td class="column-2">Width</td> <td class="column-3">Price</td> </tr> <tr class="row-3 odd child-row-1"> <td class="column-1">Circle 3 - 5</td> <td class="column-2">28-110</td> <td class="column-3">21500</td> </tr> <tr class="row-4 even child-row-1"> <td class="column-1">Circle 3 - 5</td> <td class="column-2">115-180</td> <td class="column-3">20700</td> </tr> <tr class="row-5 odd child-row-1"> <td class="column-1">Cube 3 - 5</td> <td class="column-2">63-80</td> <td class="column-3">21500</td> </tr> <tr class="row-6 even child-row-1"> <td class="column-1">Cube 3 - 5</td> <td class="column-2">100-220</td> <td class="column-3">20700</td> </tr> <tr class="row-7 odd child-row-1"> <td class="column-1">Line 3 - 5</td> <td class="column-2">10-50 ? 40-200</td> <td class="column-3">27000</td> </tr> </table>

    Read the article

  • SQL SERVER – Identifying Column Data Type of uniqueidentifier without Querying System Tables

    - by pinaldave
    I love interesting conversations with related to SQL Server. One of my friends Madhivanan always comes up with an interesting point of conversation. Here is one of the conversation between us. I am very confident this blog post will for sure enable you with some new knowledge. Madhi: How do I know if any table has a uniqueidentifier column used in it? Pinal:  I am sure you know that you can do it through some DMV or catalogue views. Madhi: I know that but how can we do that without using DMV or catalogue views? Pinal: Hm… what can I use? Madhi: You can use table name. Pinal: Easy, just say SELECT YourUniqueIdentCol FROM Table. Madhi: Hold on, the question seems to be not clear to you – you do know the name of the column. The matter of the fact, you do not know if the table has uniqueidentifier column. Only information you have is table name. Pinal: Madhi, this seems like you are changing the question when I am close to answer. Madhi: Well, are you clear now? Let me say it again – How do I know if any table has a uniqueidentifier column and what is its value without using any DMV or System Catalogues? Only information you know is table name and you are allowed to return any kind of error if table does not have uniqueidentifier column. Pinal: Do you know the answer? Madhi: Yes. I just wanted to test your knowledge about SQL. Pinal: I will have to think. Let me accept I do not know it right away. Can you share the answer please? Madhi: I won! Here it goes! Pinal: When I have friends like you – who needs enemies? Madhi: (laughter which did not stop for a minute). CREATE TABLE t ( GuidCol UNIQUEIDENTIFIER DEFAULT newsequentialid() ROWGUIDCOL, data VARCHAR(60) ) INSERT INTO t (data) SELECT 'test' INSERT INTO t (data) SELECT 'test1' SELECT $rowguid FROM t DROP TABLE t This is indeed very interesting to me. Please note that this is not the optimal way and there will be many other ways to retrieve uniqueidentifier name and value. What I learned from this was if I am in a rush to check if the table has uniqueidentifier and I do not know the name of the same, I can use SELECT TOP (1) $rowguid and quickly know the name of the column. I can later use the same columnname in my query. Madhi did teach me this new trick. Did you know this? What are other ways to get the check uniqueidentifier column existence in a database? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Getting Started with the New Column Store Index of SQL Server 2012

    Column Store Index, a new feature in SQL Server 2012, improves performance of data warehouse queries several folds. Arshad Ali shows you how to create column store index, and how to use index query hint to include or exclude a column store index. Schedule Azure backupsRed Gate’s Cloud Services makes it simple to create and schedule backups of your SQL Azure databases to Azure blob storage or Amazon S3. Try it for free today.

    Read the article

  • Table and Column Checksums

    - by Ricardo Peres
    Following my last posts on Change Data Capture and Change Tracking, here is another tip regarding tracking changes: table and colum checksums. The concept is: each time a column value changes, the checksum also changes. You can use this simple method to see if a table has changed very easily, however, beware, different column values may generate the same checksum. Here's the SQL: -- table checksum SELECT CHECKSUM_AGG(BINARY_CHECKSUM(*)) FROM TableName -- column checksum SELECT CHECKSUM_AGG(BINARY_CHECKSUM(ColumnName)) FROM TableName -- integer column checksum SELECT CHECKSUM_AGG(IntegerColumnName) FROM TableName Here are the reference links on the CHECKSUM, CHECKSUM_AGG and BINARY_CHECKSUM functions: CHECKSUM CHECKSUM_AGG BINARY_CHECKSUM SyntaxHighlighter.config.clipboardSwf = 'http://alexgorbatchev.com/pub/sh/2.0.320/scripts/clipboard.swf'; SyntaxHighlighter.brushes.Xml.aliases = ['xml']; SyntaxHighlighter.all();

    Read the article

  • Context Menu for add and remove datalist column [migrated]

    - by Kadir Ozgur
    When I right click on Datalist Columns then a context menu appears whose items are add columns, remove column etc. When I removed a column and if I want to remove one more column then it shows me to remove previous column. Everytime, it shows me to remove the previous ones. if (mnu.Name.StartsWith("Rem")) { //getview(); //datalist.Items.Refresh(); //rows.Clear(); //datalist.ItemsSource = rows; int id = listwork.dispidx(util.valint(/*mnu.Name.Substring(3)*/util.valint(mnu.Tag)), ListWork.eArtIdx.dispord); int delid = listwork.delcol(id); GridViewColumnCollection gw = getview().Columns; if (delid >= 0 && delid < gw.Count) gw.RemoveAt(delid); listsortnr = 0; //weil wir ja Colonnen gelöschte haben showsortlist(listwork.querydef.Sortcol); //rows.Clear(); DoRefresh(); }

    Read the article

  • Should I use multiple column primary keys or add a new column?

    - by Covar
    My current database design makes use of a multiple column primary key to use existing data (that would be unique anyway) instead of creating an additional column assigning each entry an arbitrary key. I know that this is allowed, but was wondering if this is a practice that I might want to use cautiously and possibly avoid (much like goto in C). So what are some of the disadvantages I might see in this approach or reasons I might want a single column key?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >