Search Results

Search found 5522 results on 221 pages for 'django registration'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 5/221 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Django - Override admin site's login form

    - by TrojanCentaur
    I'm currently trying to override the default form used in Django 1.4 when logging in to the admin site (my site uses an additional 'token' field required for users who opt in to Two Factor Authentication, and is mandatory for site staff). Django's default form does not support what I need. Currently, I've got a file in my templates/ directory called templates/admin/login.html, which seems to be correctly overriding the template used with the one I use throughout the rest of my site. The contents of the file are simply as below: # admin/login.html: {% extends "login.html" %} The actual login form is as below: # login.html: {% load url from future %}<!DOCTYPE html> <html> <head> <title>Please log in</title> </head> <body> <div id="loginform"> <form method="post" action="{% url 'id.views.auth' %}"> {% csrf_token %} <input type="hidden" name="next" value="{{ next }}" /> {{ form.username.label_tag }}<br/> {{ form.username }}<br/> {{ form.password.label_tag }}<br/> {{ form.password }}<br/> {{ form.token.label_tag }}<br/> {{ form.token }}<br/> <input type="submit" value="Log In" /> </form> </div> </body> </html> My issue is that the form provided works perfectly fine when accessed using my normal login URLs because I supply my own AuthenticationForm as the form to display, but through the Django Admin login route, Django likes to supply it's own form to this template and thus only the username and password fields render. Is there any way I can make this work, or is this something I am just better off 'hard coding' the HTML fields into the form for?

    Read the article

  • Django tests failing on invalid keyword argument

    - by Darwin Tech
    I have a models.py like so: from django.db import models from django.contrib.auth.models import User from datetime import datetime class UserProfile(models.Model): user = models.OneToOneField(User) def __unicode__(self): return self.user.username class Project(models.Model): user = models.ForeignKey(UserProfile) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) product = models.ForeignKey('tool.product') module = models.ForeignKey('tool.module') model = models.ForeignKey('tool.model') zipcode = models.IntegerField(max_length=5) def __unicode__(self): return unicode(self.id) And my tests.py: from django.test import TestCase, Client # --- import app models from django.contrib.auth.models import User from tool.models import Module, Model, Product from user_profile.models import Project, UserProfile # --- unit tests --- # class UserProjectTests(TestCase): fixtures = ['admin_user.json'] def setUp(self): self.product1 = Product.objects.create( name='bar', ) self.module1 = Module.objects.create( name='foo', enable=True ) self.model1 = Model.objects.create( module=self.module1, name='baz', enable=True ) self.user1 = User.objects.get(pk=1) ... def test_can_create_project(self): self.project1 = Model.objects.create( user=self.user1, product=self.product1, module=self.module1, model=self.model1, zipcode=90210 ) self.assertEquals(self.project1.zipcode, 90210) But I get a TypeError: 'product' is an invalid keyword argument for this function error. I'm not sure what is failing but I'm guessing something to do with the FK relationships... Any help would be much appreciated.

    Read the article

  • Django: Overriding the save() method: how do I call the delete() method of a child class

    - by Patti
    The setup = I have this class, Transcript: class Transcript(models.Model): body = models.TextField('Body') doPagination = models.BooleanField('Paginate') numPages = models.PositiveIntegerField('Number of Pages') and this class, TranscriptPages(models.Model): class TranscriptPages(models.Model): transcript = models.ForeignKey(Transcript) order = models.PositiveIntegerField('Order') content = models.TextField('Page Content', null=True, blank=True) The Admin behavior I’m trying to create is to let a user populate Transcript.body with the entire contents of a long document and, if they set Transcript.doPagination = True and save the Transcript admin, I will automatically split the body into n Transcript pages. In the admin, TranscriptPages is a StackedInline of the Transcript Admin. To do this I’m overridding Transcript’s save method: def save(self): if self.doPagination: #do stuff super(Transcript, self).save() else: super(Transcript, self).save() The problem = When Transcript.doPagination is True, I want to manually delete all of the TranscriptPages that reference this Transcript so I can then create them again from scratch. So, I thought this would work: #do stuff TranscriptPages.objects.filter(transcript__id=self.id).delete() super(Transcript, self).save() but when I try I get this error: Exception Type: ValidationError Exception Value: [u'Select a valid choice. That choice is not one of the available choices.'] ... and this is the last thing in the stack trace before the exception is raised: .../django/forms/models.py in save_existing_objects pk_value = form.fields[pk_name].clean(raw_pk_value) Other attempts to fix: t = self.transcriptpages_set.all().delete() (where self = Transcript from the save() method) looping over t (above) and deleting each item individually making a post_save signal on TranscriptPages that calls the delete method Any ideas? How does the Admin do it? UPDATE: Every once in a while as I'm playing around with the code I can get a different error (below), but then it just goes away and I can't replicate it again... until the next random time. Exception Type: MultiValueDictKeyError Exception Value: "Key 'transcriptpages_set-0-id' not found in " Exception Location: .../django/utils/datastructures.py in getitem, line 203 and the last lines from the trace: .../django/forms/models.py in _construct_form form = super(BaseInlineFormSet, self)._construct_form(i, **kwargs) .../django/utils/datastructures.py in getitem pk = self.data[pk_key]

    Read the article

  • Configuration problems with django and mod_wsgi

    - by Jimbo
    Hi, I've got problems on getting django to work on apache 2.2 with mod_wsgi. Django is installed and mod_wsgi too. I can even see a 404 page when accessing the path and I can login to django admin. But if I want to install the tagging module I get the following error: Traceback (most recent call last): File "setup.py", line 49, in <module> version_tuple = __import__('tagging').VERSION File "/home/jim/django-tagging/tagging/__init__.py", line 3, in <module> from tagging.managers import ModelTaggedItemManager, TagDescriptor File "/home/jim/django-tagging/tagging/managers.py", line 5, in <module> from django.contrib.contenttypes.models import ContentType File "/usr/lib/python2.5/site-packages/django/contrib/contenttypes/models.py", line 1, in <module> from django.db import models File "/usr/lib/python2.5/site-packages/django/db/__init__.py", line 10, in <module> if not settings.DATABASE_ENGINE: File "/usr/lib/python2.5/site-packages/django/utils/functional.py", line 269, in __getattr__ self._setup() File "/usr/lib/python2.5/site-packages/django/conf/__init__.py", line 40, in _setup self._wrapped = Settings(settings_module) File "/usr/lib/python2.5/site-packages/django/conf/__init__.py", line 75, in __init__ raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) ImportError: Could not import settings 'mysite.settings' (Is it on sys.path? Does it have syntax errors?): No module named mysite.settings My httpd.conf: Alias /media/ /home/jim/django/mysite/media/ <Directory /home/jim/django/mysite/media> Order deny,allow Allow from all </Directory> Alias /admin/media/ "/usr/lib/python2.5/site-packages/django/contrib/admin/media/" <Directory "/usr/lib/python2.5/site-packages/django/contrib/admin/media/"> Order allow,deny Allow from all </Directory> WSGIScriptAlias /dj /home/jim/django/mysite/apache/django.wsgi <Directory /home/jim/django/mysite/apache> Order deny,allow Allow from all </Directory> My django.wsgi: import sys, os sys.path.append('/home/jim/django') sys.path.append('/home/jim/django/mysite') os.chdir('/home/jim/django/mysite') os.environ['DJANGO_SETTINGS_MODULE'] = 'mysite.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I try to get this to work since a few days and have read several blogs and answers here on so but nothing worked.

    Read the article

  • Django Error: NameError name 'current_datetime' is not defined

    - by Diego
    I'm working through the book "The Definitive Guide to Django" and am stuck on a piece of code. This is the code in my settings.py: ROOT_URLCONF = 'mysite.urls' I have the following code in my urls.py from django.conf.urls.defaults import * from mysite.views import hello, my_homepage_view urlpatterns = patterns('', ('^hello/$', hello), ) urlpatterns = patterns('', ('^time/$', current_datetime), ) And the following is the code in my views.py file: from django.http import HttpResponse import datetime def hello(request): return HttpResponse("Hello World") def current_datetime(request): now = datetime.datetime.now() html = "<html><body>It is now %s.</body></html>" % now return HttpResponse(html) Yet, I get the following error when I test the code in the development server. NameError at /time/ name 'current_datetime' is not defined Can someone help me out here? This really is just a copy-paste from the book. I don't see any mistyping.

    Read the article

  • Django Admin drop down combobox and assigned values

    - by Daniel Garcia
    I have several question for the Django Admin feature. Im kind of new in Django so im not sure how to do it. Basically what Im looking to do is when Im adding information on the model. Some of the fields i want them to be drop-downs and maybe combo-boxes with AutoCompleteMode. Also looking for some fields to have the same information, for example if i have a datatime field I want that information to feed the fields day, month and year from hoti.hotiapp.models import Occurrence from django.contrib import admin class MyModelAdmin(admin.ModelAdmin): exclude = ['reference',] admin.site.register(Occurrence, MyModelAdmin) Anything helps Thanks in advance

    Read the article

  • Alternate datasource for django model?

    - by slypete
    I'm trying to seamlessly integrate some legacy data into a django application. I would like to know if it's possible to use an alternate datasource for a django model. For example, can I contact a server to populate a list of a model? The server would not be SQL based at all. Instead it uses some proprietary tcp based protocol. Copying the data is not an option, as the legacy application will continue to be used for some time. Would a custom manager allow me to do this? This model should behave just like any other django model. It should even pluggable to the admin interface. What do you think? Thanks, Pete

    Read the article

  • Django Custom Template Tages: Inclusion Tags

    - by Harry
    Hello world! Im trieng to build my own template tags Im have no idea why I get the errors I get, im following the django doc's. this is my file structure of my app: pollquiz/ __init__.py show_pollquiz.html showpollquiz.py This is showpollquiz.py: from django import template from pollquiz.models import PollQuiz, Choice register = template.Library() @register.inclusion_tag('show_pollquiz.html') def show_poll(): poll = Choice.objects.all() return { 'poll' : poll } html file: <ul> {% for poll in poll <li>{{ poll.pollquiz }}</li> {% endfor </ul> in my base.html file im am including like this {% load showpollquiz %} and {% poll_quiz %} Bu then I get the the error: Exception Value: Caught an exception while rendering: show_pollquiz.html I have no idea why this happens. Any ideas? Please keep in mind Im still new to Django

    Read the article

  • UnicodeEncodeError when uploading files in Django admin

    - by Samuel Linde
    Note: I asked this question on StackOverflow, but I realize this might be a more proper place to ask this kind of question. I'm trying to upload a file called 'Testaråäö.txt' via the Django admin app. I'm running Django 1.3.1 with Gunicorn 0.13.4 and Nginx 0.7.6.7 on a Debian 6 server. Database is PostgreSQL 8.4.9. Other Unicode data is saved to the database with no problem, so I guess the problem must be with the filesystem somehow. I've set http { charset utf-8; } in my nginx.conf. LC_ALL and LANG is set to 'sv_SE.UTF-8'. Running 'locale' verifies this. I even tried setting LC_ALL and LANG in my nginx init script just to make sure locale is set properly. Here's the traceback: Traceback (most recent call last): File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/handlers/base.py", line 111, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 307, in wrapper return self.admin_site.admin_view(view)(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 93, in _wrapped_view response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/views/decorators/cache.py", line 79, in _wrapped_view_func response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/sites.py", line 197, in inner return view(request, *args, **kwargs) File "/srv/django/letebo/app/cms/admin.py", line 81, in change_view return super(PageAdmin, self).change_view(request, obj_id) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 28, in _wrapper return bound_func(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 93, in _wrapped_view response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 24, in bound_func return func(self, *args2, **kwargs2) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/transaction.py", line 217, in inner res = func(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 985, in change_view self.save_formset(request, form, formset, change=True) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 677, in save_formset formset.save() File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 482, in save return self.save_existing_objects(commit) + self.save_new_objects(commit) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 613, in save_new_objects self.new_objects.append(self.save_new(form, commit=commit)) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 717, in save_new obj.save() File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 460, in save self.save_base(using=using, force_insert=force_insert, force_update=force_update) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 504, in save_base self.save_base(cls=parent, origin=org, using=using) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 543, in save_base for f in meta.local_fields if not isinstance(f, AutoField)] File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/fields/files.py", line 255, in pre_save file.save(file.name, file, save=False) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/fields/files.py", line 92, in save self.name = self.storage.save(name, content) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 48, in save name = self.get_available_name(name) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 74, in get_available_name while self.exists(name): File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 218, in exists return os.path.exists(self.path(name)) File "/srv/.virtualenvs/letebo/lib/python2.6/genericpath.py", line 18, in exists st = os.stat(path) UnicodeEncodeError: 'ascii' codec can't encode characters in position 52-54: ordinal not in range(128) I tried running Gunicorn with debugging turned on, and the file uploads without any problem at all. I suppose this must mean that the issue is with Nginx. Still beats me where to look, though. Here are the raw response headers from Gunicorn and Nginx, if it makes any sense: Gunicorn: HTTP/1.1 302 FOUND Server: gunicorn/0.13.4 Date: Thu, 09 Feb 2012 14:50:27 GMT Connection: close Transfer-Encoding: chunked Expires: Thu, 09 Feb 2012 14:50:27 GMT Vary: Cookie Last-Modified: Thu, 09 Feb 2012 14:50:27 GMT Location: http://my-server.se:8000/admin/cms/page/15/ Cache-Control: max-age=0 Content-Type: text/html; charset=utf-8 Set-Cookie: messages="yada yada yada"; Path=/ Nginx: HTTP/1.1 500 INTERNAL SERVER ERROR Server: nginx/0.7.67 Date: Thu, 09 Feb 2012 14:50:57 GMT Content-Type: text/html; charset=utf-8 Transfer-Encoding: chunked Connection: close Vary: Cookie 500 UPDATE: Both locale.getpreferredencoding() and sys.getfilesystemencoding() outputs 'UTF-8'. locale.getdefaultlocale() outputs ('sv_SE', 'UTF8'). This seem correct to me, so I'm still not sure why I keep getting these errors.

    Read the article

  • registration form with payment system ( paypal ) [closed]

    - by Alecs
    I'm using an ajax registration form plugin for my website and I'm thinking to implement also Paypal. Here is how I want to implement it : I have 3 labels ( Name, Phone, Email, ) and a " Buy " button. After the user is typing his name, phone and email they click on "Buy" and they will be redirected to the paypal payment page or if it's possible to stay on the same page. Probably, what I need to know is how to make the "Buy " only after the forms ( name, phone, email ) are validated. Is there a plugin, or a snippet of code already made to not start something which already exists.

    Read the article

  • django-admin - how to modify ModelAdmin to create multiple objects at once?

    - by skrobul
    let's assume that I have very basic model class Message(models.Model): msg = models.CharField(max_length=30) this model is registered with admin module: class MessageAdmin(admin.ModelAdmin): pass admin.site.register(Message, MessageAdmin) Currently when I go into the admin interface, after clicking "Add message" I have only one form where I can enter the msg. I would like to have multiple forms (formset perhaps) on the "Add page" so I can create multiple messages at once. It's really annoying having to click "Save and add another" every single time. Ideally I would like to achieve something like InlineModelAdmin but it turns out that you can use it only for the models that are related to the object which is edited. What would you recommend to use to resolve this problem?

    Read the article

  • Django: How do I add arbitrary html attributes to input fields on a form?

    - by User
    I have an input field that is rendered with a template like so: <div class="field"> {{ form.city }} </div> Which is rendered as: <div class="field"> <input id="id_city" type="text" name="city" maxlength="100" /> </div> Now suppose I want to add an autocomplete="off" attribute to the input element that is rendered, how would I do that? Or onclick="xyz()" or class="my-special-css-class"?

    Read the article

  • Insert django form into template dynamically using javascript??

    - by qulzam
    I want to add same django form instance on same template. i already add one before and other add dynamically using javascript. for example 'form" is a django form: newcell.innerHTML = {{ form.firstname }}; The problem is that when i submit the form, in view the request object has only one value (that is not add using javascript). how can i get the values of other form elements values that is added dynamically runtime.

    Read the article

  • Django : debugging templatetags

    - by interstar
    How on earth do people debug Django templatetags? I created one, based on a working example, my new tag looks the same to me as the existing one. But I just get a 'my_lib' is not a valid tag library: Could not load template library from django.templatetags.my_lib, No module named my_lib I know that this is probably because of something failing when defining the lib. But how do I see what's going on? What do you use to debug this situation?

    Read the article

  • Django models query

    - by Hulk
    Code: class criteria(models.Model): details = models.CharField(max_length = 512) Headerid = models.ForeignKey(Header) def __unicode__(self): return self.id() the details corresponds to a textarea in the UI and a validation is done for 512 characters but when this is saved. /home/project/django/django/core/handlers/base.py in get_response, line 109 Is this any thing related with schema or number of characters entered from UI

    Read the article

  • Tying in to Django Admin's Model History

    - by akdom
    The Setup: I'm working on a Django application which allows users to create an object in the database and then go back and edit it as much as they desire. Django's admin site keeps a history of the changes made to objects through the admin site. The Question: How do I hook my application in to the admin site's change history so that I can see the history of changes users make to their "content" ?

    Read the article

  • Django: Generating a queryset from a GET request

    - by Nimmy Lebby
    I have a Django form setup using GET method. Each value corresponds to attributes of a Django model. What would be the most elegant way to generate the query? Currently this is what I do in the view: def search_items(request): if 'search_name' in request.GET: query_attributes = {} query_attributes['color'] = request.GET.get('color', '') if not query_attributes['color']: del query_attributes['color'] query_attributes['shape'] = request.GET.get('shape', '') if not query_attributes['shape']: del query_attributes['shape'] items = Items.objects.filter(**query_attributes) But I'm pretty sure there's a better way to go about it.

    Read the article

  • 2-step user registration with Django

    - by David S
    I'm creating a website with Django and want a fairly common 2-step user registration. What I mean by this is that the user fills in the some basic user information + some application specific information (sort of like a coupon value). Upon submit, an email is sent to ensure email address is valid. This email should contain a link to click on to "finish" the registration. When the link is clicked, the user is marked as validated and they are directed to a new page to complete optional "user profile" type information. So, pretty basic stuff. I have done some research and found django-registration by James Bennett. I do know who James is and have seen him at PyCons and DjanoCons in the past. There is obviously very few people in the world that know Django better than James (so, I know the quality of the code/app is good). But, it almost seems like a bit of over kill. I've read through the docs and was a bit confused (maybe I'm just being a bit dense today). I believe that if I do use django-registration, I will need to have some custom forms, etc. Is there anything else out there I should evaluate? Or are there any good tutorials or videos on using django-registration? I've done a bit of googling, but haven't found anything. But, I suspect that it might be a case of a lot of very common words that don't really find what you are looking for (django user registration tutorial/example). Or is just a case where it would be just about as easy to build your own solution with Django forms, etc? Here is the tech stack I'm using: Python 2.7.2 Django 1.3.1 PostgreSQL 9.1 psycopg2 2.4.1 Twitter Bootstrap 2.0.2

    Read the article

  • Django attribute error: 'module' object has no attribute 'is_usable'

    - by Robert A Henru
    Hi, I got the following error when calling the url in Django. It's working before, I guess it's related with some accidental changes I made, but I have no idea what they are. Thanks before for the help, Robert Environment: Request Method: GET Request URL: http://localhost:8000/time/ Django Version: 1.2 Python Version: 2.6.1 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', 'djlearn.books'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware') Traceback: File "/Library/Python/2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/Users/rhenru/Workspace/django/djlearn/src/djlearn/../djlearn/views.py" in current_datetime 16. return render_to_response('current_datetime.html',{'current_date':now,}) File "/Library/Python/2.6/site-packages/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/Library/Python/2.6/site-packages/django/template/loader.py" in render_to_string 181. t = get_template(template_name) File "/Library/Python/2.6/site-packages/django/template/loader.py" in get_template 157. template, origin = find_template(template_name) File "/Library/Python/2.6/site-packages/django/template/loader.py" in find_template 128. loader = find_template_loader(loader_name) File "/Library/Python/2.6/site-packages/django/template/loader.py" in find_template_loader 111. if not func.is_usable: Exception Type: AttributeError at /time/ Exception Value: 'module' object has no attribute 'is_usable'

    Read the article

  • django crispy-forms inline forms

    - by abolotnov
    I'm trying to adopt crispy-forms and bootstrap and use as much of their functionality as possible instead of inventing something over and over again. Is there a way to have inline forms functionality with crispy-forms/bootstrap like django-admin forms have? Here is an example: class NewProjectForm(forms.Form): name = forms.CharField(required=True, label=_(u'???????? ???????'), widget=forms.TextInput(attrs={'class':'input-block-level'})) group = forms.ModelChoiceField(required=False, queryset=Group.objects.all(), label=_(u'?????? ????????'), widget=forms.Select(attrs={'class':'input-block-level'})) description = forms.CharField(required=False, label=_(u'???????? ???????'), widget=forms.Textarea(attrs={'class':'input-block-level'})) class Meta: model = Project fields = ('name','description','group') def __init__(self, *args, **kwargs): self.helper = FormHelper() self.helper.form_class = 'horizontal-form' self.helper.form_action = 'submit_new_project' self.helper.layout = Layout( Field('name', css_class='input-block-level'), Field('group', css_class='input-block-level'), Field('description',css_class='input-block-level'), ) self.helper.add_input(Submit('submit',_(u'??????? ??????'))) self.helper.add_input(Submit('cancel',_(u'? ?????????'))) super(NewProjectForm, self).__init__(*args, **kwargs) it will display a decent form: How do I go about adding a form that basically represents this model: class Link(models.Model): name = models.CharField(max_length=255, blank=False, null=False, verbose_name=_(u'????????')) url = models.URLField(blank=False, null=False, verbose_name=_(u'??????')) project = models.ForeignKey('Project') So there will be a project and name/url links and way to add many, like same thing is done in django-admin where you are able to add extra 'rows' with data related to your main model. On the sreenshot below you are able to fill out data for 'Question' object and below that you are able to add data for QuestionOption objects -you are able to click the '+' icon to add as many QuestionOptions as you want. I'm not looking for a way to get the forms auto-generated from models (that's nice but not the most important) - is there a way to construct a form that will let you add 'rows' of data like django-admin does?

    Read the article

  • ProgrammingError when aggregating over an annotated & grouped Django ORM query

    - by ento
    I'm trying to construct a query to get the "average, maximum, minimum number of items purchased by a single user". The data source is this simple sales record table: class SalesRecord(models.Model): id = models.IntegerField(primary_key=True) user_id = models.IntegerField() product_code = models.CharField() price = models.IntegerField() created_at = models.DateTimeField() A new record is inserted into this table for every item purchased by a user. Here's my attempt at building the query: q = SalesRecord.objects.all() q = q.values('user_id').annotate( # group by user and count the # of records count=Count('id'), # (= # of items) ).order_by() result = q.aggregate(Max('count'), Min('count'), Avg('count')) When I try to execute the code, a ProgrammingError is raised at the last line: (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM (SELECT sales_records.user_id AS user_id, COUNT(sales_records.`' at line 1") Django's error screen shows that the SQL is SELECT FROM (SELECT `sales_records`.`player_id` AS `player_id`, COUNT(`sales_records`.`id`) AS `count` FROM `sales_records` WHERE (`sales_records`.`created_at` >= %s AND `sales_records`.`created_at` <= %s ) GROUP BY `sales_records`.`player_id` ORDER BY NULL) subquery It's not selecting anything! Can someone please show me the right way to do this? Hacking Django I've found that clearing the cache of selected fields in django.db.models.sql.BaseQuery.get_aggregation() seems to solve the problem. Though I'm not really sure this is a fix or a workaround. @@ -327,10 +327,13 @@ # Remove any aggregates marked for reduction from the subquery # and move them to the outer AggregateQuery. + self._aggregate_select_cache = None + self.aggregate_select_mask = None for alias, aggregate in self.aggregate_select.items(): if aggregate.is_summary: query.aggregate_select[alias] = aggregate - del obj.aggregate_select[alias] + if alias in obj.aggregate_select: + del obj.aggregate_select[alias] ... yields result: {'count__max': 267, 'count__avg': 26.2563, 'count__min': 1}

    Read the article

  • Django - provide additional information in template

    - by Ninefingers
    Hi all, I am building an app to learn Django and have started with a Contact system that currently stores Contacts and Addresses. C's are a many to many relationship with A's, but rather than use Django's models.ManyToManyField() I've created my own link-table providing additional information about the link, such as what the address type is to the that contact (home, work etc). What I'm trying to do is pass this information out to a view, so in my full view of a contact I can do this: def contact_view_full(request, contact_id): c = get_object_or_404(Contact, id=contact_id) a = [] links = ContactAddressLink.objects.filter(ContactID=c.id) for link in links: b = Address.objects.get(id=link.AddressID_id) a.append(b) return render_to_response('contact_full.html', {'contact_item': c, 'addresses' : a }, context_instance=RequestContext(request)) And so I can do the equivalent of c.Addresses.all() or however the ManyToManyField works. What I'm interested to know is how can I pass out information about the link in the link object with the 'addresses' : a information, so that when my template does this: {% for address in addresses %} <!-- ... --> {% endfor %} and properly associate the correct link object data with the address. So what's the best way to achieve this? I'm thinking a union of two objects might be an idea but I haven't enough experience with Django to know if that's considered the best way of doing it. Suggestions? Thanks in advance. Nf

    Read the article

  • What is causing this OverflowError in Django?

    - by orokusaki
    I'm using a normal ModelForm.save() to create an object, and this exception comes up. It worked fine before until I added commit_manually, transaction.rollback() and transaction.commit() to my view. Has anyone else ran into this? Is this because of sqlite3? OverflowError: long too big to convert C:\Python26\Lib\site-packages\django-trunk\django\db\backends\sqlite3\base.py in execute, line 197 params: (203866156270872165269663274649746494334L,) query: u'SELECT (1) AS "a", "auth_user"."id", "auth_user"."username", "auth_user"."first_name", "auth_user"."last_name", "auth_user"."email", "auth_user"."password", "auth_user"."is_staff", "auth_user"."is_active", "auth_user"."is_superuser", "auth_user"."last_login", "auth_user"."date_joined" FROM "auth_user" WHERE "auth_user"."id" = ? LIMIT 1' self <django.db.backends.sqlite3.base.SQLiteCursorWrapper object at 0x015D5A98> Why would that L param be passed in, and

    Read the article

  • Django model operating on a queryset

    - by jmoz
    I'm new to Django and somewhat to Python as well. I'm trying to find the idiomatic way to loop over a queryset and set a variable on each model. Basically my model depends on a value from an api, and a model method must multiply one of it's attribs by this api value to get an up-to-date correct value. At the moment I am doing it in the view and it works, but I'm not sure it's the correct way to achieve what I want. I have to replicate this looping elsewhere. Is there a way I can encapsulate the looping logic into a queryset method so it can be used in multiple places? I have this atm (I am using django-rest-framework): class FooViewSet(viewsets.ModelViewSet): model = Foo serializer_class = FooSerializer bar = # some call to an api def get_queryset(self): # Dynamically set the bar variable on each instance! foos = Foo.objects.filter(baz__pk=1).order_by('date') for item in foos: item.needs_bar = self.bar return items I would think something like so would be better: def get_queryset(self): bar = # some call to an api # Dynamically set the bar variable on each instance! return Foo.objects.filter(baz__pk=1).order_by('date').set_bar(bar) I'm thinking the api hit should be in the controller and then injected to instances of the model, but I'm not sure how you do this. I've been looking around querysets and managers but still can't figure it out nor decided if it's the best method to achieve what I want. Can anyone suggest the correct way to model this with django? Thanks.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >