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Search found 218 results on 9 pages for 'gaurav gg goyal'.

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  • Django facebook integration error

    - by Gaurav
    I'm trying to integrate facebook into my application so that users can use their FB login to login to my site. I've got everything up and running and there are no issues when I run my site using the command line python manage.py runserver But this same code refuses to run when I try and run it through Apache. I get the following error: Environment: Request Method: GET Request URL: http://helvetica/foodfolio/login Django Version: 1.1.1 Python Version: 2.6.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'foodfolio.app', 'foodfolio.facebookconnect'] Installed Middleware: ('django.contrib.sessions.middleware.SessionMiddleware', 'facebook.djangofb.FacebookMiddleware', 'django.middleware.common.CommonMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'facebookconnect.middleware.FacebookConnectMiddleware') Template error: In template /home/swat/website-apps/foodfolio/facebookconnect/templates/facebook/js.html, error at line 2 Caught an exception while rendering: No module named app.models 1 : <script type="text/javascript"> 2 : FB_RequireFeatures(["XFBML"], function() {FB.Facebook.init("{{ facebook_api_key }}", " {% url facebook_xd_receiver %} ")}); 3 : 4 : function facebookConnect(loginForm) { 5 : FB.Connect.requireSession(); 6 : FB.Facebook.get_sessionState().waitUntilReady(function(){loginForm.submit();}); 7 : } 8 : function pushToFacebookFeed(data){ 9 : if(data['success']){ 10 : var template_data = data['template_data']; 11 : var template_bundle_id = data['template_bundle_id']; 12 : feedTheFacebook(template_data,template_bundle_id,function(){}); Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/swat/website-apps/foodfolio/app/controller.py" in __showLogin__ 238. context_instance = RequestContext(request)) File "/usr/lib/pymodules/python2.6/django/shortcuts/__init__.py" in render_to_response 20. return HttpResponse(loader.render_to_string(*args, **kwargs), **httpresponse_kwargs) File "/usr/lib/pymodules/python2.6/django/template/loader.py" in render_to_string 108. return t.render(context_instance) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 178. return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 71. result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 946. autoescape=context.autoescape)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py" in render 779. bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py" in render_node 81. raise wrapped Exception Type: TemplateSyntaxError at /foodfolio/login Exception Value: Caught an exception while rendering: No module named app.models

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  • Why I am not able to update the column based on a condition which is not the primary key

    - by Gaurav Sharma
    Why I am not able to update the column based on a condition which is not the primary key. I am trying to update the constituencies table where name matches a specific criterial as shown below but the below queries shows an error Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'table constituencies set city_id = '1' where constituencies.name = "East Delhi"' at line 1 update table constituencies set city_id = '1' where constituencies.name = "East Delhi"; update table constituencies set city_id = '1' where constituencies.name = "South Delhi"; update table constituencies set city_id = '1' where constituencies.name = "Delhi Sadar"; update table constituencies set city_id = '1' where constituencies.name = "Karol Bagh"; update table constituencies set city_id = '1' where constituencies.name = "New Delhi"; update table constituencies set city_id = '1' where constituencies.name = "Outer Delhi"; update table constituencies set city_id = '1' where constituencies.name = "North East Delhi"; update table constituencies set city_id = '1' where constituencies.name = "North West Delhi"; update table constituencies set city_id = '1' where constituencies.name = "West Delhi"; Is it necessary that the condition should be checked with a primary key only ? Please throw some light on the above.

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  • noscript tag appears even if javascript is turned on in IE8

    - by Gaurav Sharma
    ghost noscript tag more info here I am facing exactly this issue, how shall I handle this for Internet Explorer browsers :-( ? Explanation: I have included the following noscript tag in my application's layout <noscript style="background:#ffcc00;font-size:200%;font-family:verdana;text-align:center;text-transform:uppercase;font-weight:bold;padding:0.8em;">javascript is disabled, please enable it first.</noscript> Now when I view this layout in IE8 the noscript tag CSS is displaying at the top of the page without the content in it, making the layout look faulty. Please help...

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  • router connect configuration in cakephp 1.3

    - by Gaurav Sharma
    Hello everyone, I have defined the following rule in the router.php file of my cakephp 1.3 based application Router::connect('/tags/*',array('plugin' => 'tags', 'controller' => 'Tags', 'action' => 'index', 'admin' => false)); I have used the tags plugin. When I display the tags related to a topic then the URL on the tags appears something like this http://localhost/testapp/tags/Tags/view/{tag_key_name} I want to make this url for any action to tags plugin like this http://localhost/testapp/Tags/{action}/{tag_key_name} for (view, admin_view and admin_edit) and http://localhost/testapp/Tags/{action} for (index, admin_index and any other action that does not require an id or keyname for execution)

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  • How do I show information to users belonging to different groups (web) in modx

    - by Gaurav Sharma
    Hello Everyone, I have created a website using modx evolution v1.0.2. The website that I have developed has 12 different types of users (categorized in groups). Each user will be shown a different price depending on the group to which he belongs. Till now I have been able to fetch the group name of current logged in user (created a snippet for that), but how can I achieve the above mentioned functionality so that each user should be able to see only the price that I have coded according to his group. For example: If a user is associated with the 'ocassional' group then he should be shown the price as , say, 50 bucks and if a user is associated with the 'regular' group then he should be shown the price as, say, 40 bucks I can easily do this by coding a single snippet for every product's variant, but there are a lot of variants (more than 100 and growing). I have created a resource(page) for every product and it's variant. Every variant has a price. It is this price that I want to be shown according to the logged in user group membership. I hope I am able to explain my query clearly. Please help me do this functionality. Thanks

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  • How do I set the bake command to use a different template in cakephp

    - by Gaurav Sharma
    Hi all, I wanted bake command to bake a view of my liking. So I searched bakery and found this Modify-default-HTML-produced-by-baked-templates. But after reading this I was not able to modify the template because I wanted to define some CSS in it and those files are not containing any CSS code (they contain only php code inside them). Also if I have designed my own CSS file for the new template then how do I tell bake command to pick that specified css file for new template ? I am totally confused over here. Has anybody done this similar kinda work using cakePHP. Any help would be greatly appreciable. NOTE: I am using cakePHP v 1.3 latest stable release. Thanks

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  • Symmetric ds issue

    - by gaurav
    Hi , I am using postgresql8.3 and include symmetris ds 1.5.1 in my application.But the replication is done fine for client to server . but the replication is not done from server to client. I am newer to use the symmetric ds .Can anyone plese let me know the checklist of using symmetric ds for cheching that my symmetric ds is well configure or not. Thank You very Much

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  • yahoo's attribute exchange -> blank data is coming

    - by Gaurav Sharma
    Hello everybody, I am trying to build openid login system for my website. To do this I used JanRain's php openid library v 2.1.3. I am also using openid selector to select the openid provider from the list. I first created the attributes array that I need to fetch from the provider as follows: $attribute[] = Auth_OpenID_AX_AttrInfo::make('http://axschema.org/contact/email',2,1, 'email'); $attribute[] = Auth_OpenID_AX_AttrInfo::make('http://axschema.org/namePerson/first',1,1, 'firstname'); $attribute[] = Auth_OpenID_AX_AttrInfo::make('http://axschema.org/namePerson/last',1,1, 'lastname'); $attribute[] = Auth_OpenID_AX_AttrInfo::make('http://axschema.org/namePerson',1,1, 'fullname'); $attribute[] = Auth_OpenID_AX_AttrInfo::make('http://axschema.org/namePerson/friendly',1,1, 'username'); $ax = new Auth_OpenID_AX_FetchRequest; foreach($attribute as $attr) { $ax-add($attr); } $auth_request-addExtension($ax); and in the finish_auth.php file I wrote this to fetch the attributes returned $ax = new Auth_OpenID_AX_FetchResponse(); $obj = $ax-fromSuccessResponse($response); Google gives me all the attributes requested but yahoo doesn't (as stated here that yahoo now supports attribute exchange). Is there any limitation set by yahoo on attribute exchange too. (they give limited websites access to sreg extension of openid). :( Please help me, I am stuck over here. Thanks

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  • values assigned to Template variables disappear after page refresh in modx

    - by Gaurav Sharma
    Hi all, I created a template variable in modx by the name 'test_var'. Then in the home page resource edit content editor I wrote [*test_var*]. Then I published the resource. Then for checking if it works I executed the page using the preview button. The value appeared fine but when I refreshed the page, the value of the template variable disappeared ? This is very strange. Please help me what I am doing wrong. Thanks

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  • database schema explanation of the cakedc tags plugin

    - by Gaurav Sharma
    Hello everyone, I found an awesome tags plugin on cakedc site. This plugin makes your tagging concerns very easy and is able to make anything taggable. Has anyone used it? I find it a bit difficult to understand few things listed below: difference between the name and keyname columns of the tags table. the use of columns 'identifier', 'weight' in tags table Thanks

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  • How do I secure all the admin actions in all controllers in cakePHP

    - by Gaurav Sharma
    Hello Everyone, I am developing an application using cakePHP v 1.3 on windows (XAMPP). Most of the controllers are baked with the admin routing enabled. I want to secure the admin actions of every controller with a login page. How can I do this without repeating much ? One solution to the problem is that "I check for login information in the admin_index action of every controller" and then show the login screen accordingly. Is there any better way of doing this ? The detault URL to admin (http://localhost/app/admin) is pointing to the index_admin action of users controller (created a new route for this in routes.php file) Thanks

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  • query optimization

    - by Gaurav
    I have a query of the form SELECT uid1,uid2 FROM friend WHERE uid1 IN (SELECT uid2 FROM friend WHERE uid1='.$user_id.') and uid2 IN (SELECT uid2 FROM friend WHERE uid1='.$user_id.') The problem now is that the nested query SELECT uid2 FROM friend WHERE uid1='.$user_id.' returns a very large number of ids(approx. 5000). The table structure of the friend table is uid1(int), uid2(int). This table is used to determine whether two users are linked together as friends. Any workaround? Can I write the query in a different way? Or is there some other way to solve this issue. I'm sure I am not the first person to face such a problem. Any help would be greatly appreciated.

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  • Developing a custom-validation in asp.net for specific control and criteria

    - by Gaurav
    Hello There is another relevant question asked Validation Check in asp.net In the same scenario we need a custom validator control which will alert user for any wrong entry. This will work like this : Developer will pass the control-name, input-value and format-required For instance like for textbox it can be: txtName,txtName.Text, allow-alphabets-only The accordingly format if the user input is invalid he/she will be got prompt. Please suggest the right way to do the smae. Thanks in advance.

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  • PHP Video Editing and Streaming

    - by Gaurav Padia
    Hi, I am developing online video streaming website on PHP. I need two functionalities: Need to add title/text at bottom of the video dynamically. Need to add background music to video dynamically. Is it possible with PHP or any available open source library? Can anyone guide me or provide links to this type of library ? Thanks.

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  • Evaluating a function at a particular value in parallel

    - by Gaurav Kalra
    Hi. The question may seem vague, but let me explain it. Suppose we have a function f(x,y,z ....) and we need to find its value at the point (x1,y1,z1 .....). The most trivial approach is to just replace (x,y,z ...) with (x1,y1,z1 .....). Now suppose that the function is taking a lot of time in evaluation and I want to parallelize the algorithm to evaluate it. Obviously it will depend on the nature of function, too. So my question is: what are the constraints that I have to look for while "thinking" to parallelize f(x,y,z...)? If possible, please share links to study.

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  • display HTML content from database with formatting in it

    - by Gaurav Sharma
    Hi all, I have used wmd-editor in my cakephp v1.3 application. The config which I have written is as follows: wmd_options = { output: "HTML", lineLength: 40, buttons: "bold italic | link blockquote code image | ol ul heading hr", autostart: true }; When I submit the form the HTML in the wmd enabled textarea is saved in the database with htmlentities() done to the text then I am displaying it with html_entity_decode() method. but the text is displayed as it is including the HTML coding like this <p><strong>hello dear friends</strong></p>\n\n<pre><code>I want to make sure that everything that you type is visible clearly.\nadasfafas\n</code></pre>\n\n<blockquote>\n <p>sadgsagasdgxcbxcbxc</p>\n</blockquote>\n\n<p><em>sadfgsgasdsgasgs</em></p>\n\n<p><b><a href="http://kumu.in">this is the link</a></b></p> Please help me solve this problem Thanks

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  • How to get the place name by latitude and longitude using openstreetmap in android

    - by Gaurav kumar
    In my app i am using osm rather than google map.I have latitude and longitude.So from here how i will query to get the city name from osm database..please help me. final String requestString = "http://nominatim.openstreetmap.org/reverse?format=json&lat=" + Double.toString(lat) + "&lon=" + Double.toString(lon) + "&zoom=18&addressdetails=1"; RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(requestString)); try { @SuppressWarnings("unused") Request request = builder.sendRequest(null, new RequestCallback() { @Override public void onResponseReceived(Request request, Response response) { if (response.getStatusCode() == 200) { String city = ""; try { JSONValue json = JSONParser.parseStrict(response); JSONObject address = json.isObject().get("address").isObject(); final String quotes = "^\"|\"$"; if (address.get("city") != null) { city = address.get("city").toString().replaceAll(quotes, ""); } else if (address.get("village") != null) { city = address.get("village").toString().replaceAll(quotes, ""); } } catch (Exception e) { } } } }); } catch (Exception e1) { }

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  • reply to a comment via email and directly post it on the website commenting system

    - by Gaurav Sharma
    Hello Everybody, I have developed a website using PHP and MYSQL. The website has a commenting system through which registered users of the website can post comments on the feedback posted by different users. When a comment is posted for a feedback an email is sent to the user who posted that feedback notifying him of new comments on his feedback. Now what I want is that a feedback owner should be able to post a new comment in response to that comment by simply replying to the email that has been sent by the website. I hope I was able to explain my query properly. If it needs any improvement in explanation, I would be glad to know and make changes accordingly Thanks

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  • cahoots - zend framework application is not running

    - by Gaurav Sharma
    hello everyone, I downloaded cahoots from sourceforge.net. It is a zend framework application. Very nicely done and I must say that it should be a nice tutorial for everyone who is struggling to learn Zend framework. But my problem is that even after reading the instructions this application is still not running. The application just doesn't run at all giving an error message. I have tried my best. no success :( Also I wanted to execute the application as "http://localhost/cahoots" but it runs by this URL "http://localhost/cahoots/public". why is it so.? I am using XAMPP v 1.7.1 with mod-rewrite enabled. Please guide me through the process. Any good tutorials on zend framework with zend tool would be appreciable. I want to learn this framework. Thanks

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  • present a static page url as different url which is SEO friendly

    - by Gaurav Sharma
    Hi, I have developed a site, which has some static pages. Like explore, home, feedback. The link for these goes as follows website.com/views/explore.php website.com/index.php website.com/views/feedback.php I want to write a different SEO URL for each of the URL mentioned above. Is it possible ? i.e. for example website.com/views/explore.php should be convereted/visible as website.com/explore website.com/views/feedback.php should be convereted/visible as website.com/give/feedback and so on

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