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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

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  • get me the latest Change from Select Query in below given condition

    - by OM The Eternity
    I have a Table structure as id, trackid, table_name, operation, oldvalue, newvalue, field, changedonetime Now if I have 3 rows for the same "trackid" same "field", then how can i select the latest out of the three? i.e. for e.g.: id = 100 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPL newvalue = IPLcccc field = name live = 0 changedonetime = 2010-04-30 17:54:39 and id = 101 trackid = 152 table_name = jos_menu operation= UPDATE oldvalue = IPLcccc newvalue = IPL2222 field = name live = 0 changedonetime = 2010-04-30 18:54:39 As u can see above the secind entry is the latest change, Now what query I should use to get the only one and Latest row out of many such rows... $distupdqry = "select DISTINCT trackid,table_name from jos_audittrail where live = 0 AND operation = 'UPDATE'"; $disupdsel = mysql_query($distupdqry); $t_ids = array(); $t_table = array(); while($row3 = mysql_fetch_array($disupdsel)) { $t_ids[] = $row3['trackid']; $t_table[] = $row3['table_name']; //$t_table[] = $row3['table_name']; } //echo "<pre>";print_r($t_table);echo "<pre>"; //exit; for($n=0;$n<count($t_ids);$n++) { $qupd = "SELECT * FROM jos_audittrail WHERE operation = 'UPDATE' AND trackid=$t_ids[$n] order by changedone DESC "; $seletupdaudit = mysql_query($qupd); $row4 = array(); $audit3 = array(); while($row4 = mysql_fetch_array($seletupdaudit)) { $audit3[] = $row4; } $updatefield = ''; for($j=0;$j<count($audit3);$j++) { if($j == 0) { if($audit3[$j]['operation'] == "UPDATE") { //$insqry .= $audit2[$i]['operation']." "; //echo "<br>"; $updatefield .= "UPDATE `".$audit3[$j]['table_name']."` SET "; } } if($audit3[$j]['operation'] == "UPDATE") { $updatefield .= $audit3[$j]['field']." = '".$audit3[$j]['newvalue']."', "; } } /*echo "<pre>"; print_r($audit3); exit;*/ $primarykey = "SHOW INDEXES FROM `".$t_table[$n]."` WHERE Key_name = 'PRIMARY'"; $prime = mysql_query($primarykey); $pkey = mysql_fetch_array($prime); $updatefield .= "]"; echo $updatefield = str_replace(", ]"," WHERE ".$pkey['Column_name']." = '".$t_ids[$n]."'",$updatefield); } In the above code I am fetching ou the distinct IDs in which update operation has been done, and then accordingly query is fired to get all the changes done on different fields of the selected distinct ids... Here I am creating the Update query by fetching the records from the initially described table which is here mentioned as audittrail table... Therefore I need the last made change in the field so that only latest change can be selected in the select queries i have used... please go through the code.. and see how can i make the required change i need finally..

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  • is it correct to unset the session variable for a particular index as the vay whole session is made

    - by OM The Eternity
    is it correct to unset the session variable for a particular index as the vay whole session is made unset in PHP? I know this works: unset($_SESSION['bannersize']) But does this works ? : unset($_SESSION['bannersize'][3]) or is there any other way to unset any particular desired index of the session and then again rearrange the values inside it to remove the empty index..?

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  • Folders and its files do get copied.. pls help me in given code..

    - by OM The Eternity
    I have a joomla folder, and i have a script which has to copy the complete joomla folder to another new folder..below is the code which copies only the files contain in the main folder but NOT the other directories existing in the joomla folder, I know that i have to plcae some check for dir_exist function and create it if do not exist.. also I want this code to perform a function to overrite the previously existing files and folders.. how can i accomplish thisss?????? <?php $source = '/var/www/html/pranav_test/'; $destination = '/var/www/html/parth/'; $sourceFiles = glob($source . '*'); foreach($sourceFiles as $file) { $baseFile = basename($file); if (file_exists($destination . $baseFile)) { $originalHash = md5_file($file); $destinationHash = md5_file($destination . $baseFile); if ($originalHash === $destinationHash) { continue; } } copy($file, $destination . $baseFile); } ?> Thanks to @alex who helped me to get the code... But I need more support pls help...

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  • need export query rather than creating file for mysqldump without triggers.. See description

    - by OM The Eternity
    I have code as $db_name = "db"; $outputfile = "/somewhere"; $new_db_name = 'newdb'; $cmd = 'mysqldump --skip-triggers %s > %s 2>&1'; $cmd = sprintf($cmd, escapeshellarg($db_name), escapeshellcmd($output_file)); exec($cmd, $output, $ret); if ($ret !=0 ) { //log error message in $output } Then to import: $cmd = 'mysql --database=%s < %s 2>&1'; $cmd = sprintf($cmd, escapeshellarg($new_db_name), escapeshellcmd($output_file)); exec($cmd, $output, $ret); //etc. unlink($outputfile); Bow here what should i do to get the export query, rather than creating a file everytime?

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  • code doesnot delete specific extra files but deletes all, also no recursion for directory, help me t

    - by OM The Eternity
    I have to compare two folder structure and with reference of source folder I want to delete all the files/folders present in other destination folder which do not exist in reference source folder, how could i do this? $original = scan_dir_recursive('/var/www/html/copy2'); $mirror = scan_dir_recursive('/var/www/html/copy1'); function scan_dir_recursive($dir) { $all_paths = array(); $new_paths = scandir($dir); foreach ($new_paths as $path) { if ($path == '.' || $path == '..') { continue; } $path = $dir . DIRECTORY_SEPARATOR . $path; if (is_dir($path)) { $all_paths = array_merge($all_paths, scan_dir_recursive($path)); } else { $all_paths[] = $path; } } return $all_paths; } foreach($mirror as $mirr) { if($mirr != '.' && $mirr != '..') { if(!in_array($mirr, $original)) { unlink($mirr); // delete the file } } } The above code shows what i did.. Here My copy1 folder contains extra files than copy2 folders hence i need these extra files to be deleted. Below given output is are arrays of original Mirror and of difference of both.. Original Array ( [0] => /var/www/html/copy2/Copy (5) of New Text Document.txt [1] => /var/www/html/copy2/Copy of New Text Document.txt ) Mirror Array ( [0] => /var/www/html/copy1/Copy (2) of New Text Document.txt [1] => /var/www/html/copy1/Copy (3) of New Text Document.txt [2] => /var/www/html/copy1/Copy (5) of New Text Document.txt ) Difference Array ( [0] => /var/www/html/copy1/Copy (2) of New Text Document.txt [1] => /var/www/html/copy1/Copy (3) of New Text Document.txt [2] => /var/www/html/copy1/Copy (5) of New Text Document.txt ) when i iterate a loop to delete on difference array all files has to be deleted as per displayed output.. how can i rectify this.. the loop for deletion is given below. $dirs_to_delete = array(); foreach ($diff_path as $path) { if (is_dir($path)) { $dirs_to_delete[] = $path; } else { unlink($path); } } while ($dir = array_pop($dirs_to_delete)) { rmdir($dir); }

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  • I am getting error as "operation aboarded, Internet explorer can't open the page"

    - by OM The Eternity
    I have created a shopping cart site, and i have got two complains for the same issue, but i am not able to track the main problem... They whenever they complete the process and reach at the last page they get the error message as "operation aboarded, Internet explorer can't open the page" Could someone helo me out? what could be the reason behind this.. i tried to get the error in IE-6,7,8 but I didnt get any error... ?

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  • Is PHP a web Technology or a scripting language?

    - by OM The Eternity
    Its very basic and silly question.... Is PHP a web Technology or a scripting language? I believe as it is scripting language, but why other believes it as web technology? and if its a scripting language then in which web technology does the PHP counts in? i know it might seem a vague question to some people, but lets face the truth many of us are confused about it.. So geeks please clarify me....

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  • Error in configuration file

    - by OM The Eternity
    I have copied my project folder from my live server to my local host and edited the config file as per localhost, but still i am displayed with the "Internal Server Error:500" The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, admin@localhost and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. I cannot understand what should be the problem here, please help me to track the issue here....

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  • Want to avoid the particular rows from select join query... See description

    - by OM The Eternity
    I have a Select Left Join Query whis displays me the rows for the latest changedone(its a time) column name ("field" should not be equal) column name ("trackid" should not be equal), and column name "Operation should be "UPDATE" ", below is the query I am talking about... SELECT j1. * FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON ( j1.trackid != j2.trackid AND j1.field != j2.field AND j1.changedone < j2.changedone ) WHERE j1.operation = 'UPDATE' AND j2.id IS NULL Now here I don't want a row to be displayed with a two particular column's value i.e. "field's value" the value is "LastvisitDate" and "hits" Now if if append the condition in the above query that " AND j1.field != 'lastvistDate' AND j1.field != 'hits' " theni do not get any result... The table structure is jos_audittrail: id trackid operation oldvalue newvalue table_name live changedone(its a time) I hope i have given the details properly If u still find something missing I will try to provide it more better way... Pls help me to avoid those two rows with those to mentioned value of "field"

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  • How to sync two folders in PHP?

    - by OM The Eternity
    I am using windows, Mysql DB, PHP I am building the Joomla Component whose one of the functionality is to synchronize the folders I want to sync two folders of different name.. How can I do this? It has to be dne in the same machine, no two different servers are involved in it.. How to sync two folders in PHP?

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