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  • Why Oracle Retail Merchandise Operations Management?

    - by user801960
    Lara Livgard, Director of Oracle Retail Strategy, explains why retailers should choose Oracle Retail Merchandise Operations Management (MOM), sharing the benefits of the solutions and showcasing customer examples. MOM is a highly proven solution supporting over 275 live customers across the world across a range of vertical markets, through its flexible, modular architecture. The robust functionality and scalable nature of the MOM solutions provide the platform to support retail growth through acquisitions, international expansion and the addition of new formats, assortments and channels. Access this video on our YouTube Channel. Take a look at the Oracle Retail website for more information on Merchandise Operations Management.

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  • How do I determine the draw order in an isometric view flash game?

    - by Gajet
    This is for a flash game, with isometric view. I need to know how to sort object so that there is no need for z-buffer checking when drawing. This might seem easy but there is another restriction, a scene can have 10,000+ objects so the algorithm needs to be run in less than O(n^2). All objects are rectangular boxes, and there are 3-4 objects moving in the scene. What's the best way to do this? UPDATE in each tile there is only object (I mean objects can stack on top of each other). and we access to both map of Objects and Objects have their own position.

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  • Do CDNs work with POST operations?

    - by iddqd
    I'm using a CDN (Level3) for the first time and I'm a bit confused. I'm accessing dynamic URLs such as http://cdn.mysite.com?getItem=1234 that return text data. Do CDNs work with HTTP POST operations? When i issue a HTTP POST operation, my "real" server receives this request every time, so I'm wondering if the CDN has a problem with POST operations. If i use HTTP GET it seems to work, i call the URL once (from my application), i can see my server receiving the request. If i call it a second time, the CDN delivers it directly, my server doesn't get anything. However if i open same the link manually from a second browser tab, my server is asked to deliver again, shouldn't it be cached by now? Many thanks.

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  • Improving Shopfloor Data Collection with Oracle Manufacturing Operations Center

    Successful factories around the world leverage information to drive their production and supply chains. New tools are available today to further catapult the data collection, analysis, contextualization and collaboration to the various stakeholders involved in the manufacturing process. Oracle Manufacturing Operations Center (MOC) addresses the factory's need for accurate and timely information about product and process quality, insight into shop floor operations, and performance of production assets. It solves the complex problem of connecting fragmented disconnected shop floor data to the business context of your ERP and provides the solid foundation for running Continuous Improvement (CI) programs such as Lean and Six Sigma.

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  • SQL SERVER Merge Operations Insert, Update, Delete in Single Execution

    This blog post is written in response to T-SQL Tuesday hosted by Jorge Segarra (aka SQLChicken). I have been very active using these Merge operations in my development. However, I have found out from my consultancy work and friends that these amazing operations are not utilized by them most of the time. Here is my [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Ideas to automate customer order processing? [on hold]

    - by user2753657
    i am looking for a way to automate the order processing in my webshop. Normally, a user buys a product in my webshop, then, i receive an order confirmation email with order details, address etc. After receiving the order email, I login to my suppliers website and input the order details manually. My supplier then ships the item to the address specified by me. I am looking for ideas how to automate this process, especially in the case if i receive for example 4-5 order emails at one time (and not one by one with several hours between)... I was looking at the program Winautomation, but i am not sure if this fits my needs. Any ideas are appreciated. thanks!

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  • SQL - Order against two columns at the same time (intersecting)

    - by Alex
    I have a table with the fields CommonName and FirstName. Only either field has data, never both. Is there a way to order rows in an intersecting manner on SQL Server? Example: CommonName FirstName Bern Wade Ashley Boris Ayana I want records ordered like this: CommonName FirstName Ashley Ayana Bern Boris Wade Is this possible, and if so, how?

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • Order by Domain Extension Name using CodeIgniter Active Record Class

    - by allan
    $extension = “SUBSTRING_INDEX(domain_name, ‘.’, -1)”; $this->db->order_by($extension, “asc”); It says: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘asc LIMIT 50’ at line 44 But its working when I didn’t used the $this-db-order_by Active Record Class such as this one: $this-db-query(“SELECT * FROM domain ORDER BY SUBSTRING_INDEX(domain_name, ‘.’, -1)”); Anyone please help me. Thanks.

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  • MySQL specifying exact order with WHERE `id` IN (...)

    - by Gray Fox
    Is there an easy way to order MySQL results respectively by WHERE id IN (...) clause? Example: SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) to return Article with id = 4 Article with id = 2 Article with id = 5 Article with id = 9 Article with id = 3 and also SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) LIMIT 2,2 to return Article with id = 5 Article with id = 9

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  • RegEx to reverse order of list?

    - by quantomcat
    Is there a singular regular expression that can be used in, say, a text editor's search/replace dialog to reverse the order of the items in a list? For instance, take this list: First item Second item Third item Select it in a text editor like EditPad, bring up the search and replace box, apply a regex (run as a loop or not) and turn it into: Third item Second item First item Can this be done?

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  • MYSQL Select statment Order By with Group By

    - by mouthpiec
    I have the following simple SQL statment SELECT id, name, value_name, value_id FROM table GROUP BY id ORDER BY value_id DESC when grouping I would like to get the value_name and value_id of the tuple where the value_id is the biggest. The way it is i am getting the smallest value. For example 1, name1, valuename, 3 (where i know that there is a value_id of 5) Can you please help?

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  • Perl, foreach order

    - by Mike
    Does Perl's foreach loop operator require that the list items be presented in order? For example my @a=(1,2,3); foreach my $item (@a) { print $item; } will always print 1 2 3? I suspect so, but I can't find it documented.

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  • Substitute Items on Internal Sales Orders

    - by ChristineS-Oracle
    Oracle Order Management now enables you to substitute items on internal sales order lines to manage item availability.  Oracle Order Management enables you to substitute items on internal sales order lines to manage item availability. Source organizations can decide to ship a substitute item in case the original item is not available to be shipped. The application supports manual (using Related Items window) and automatic (using ATP functionality) substitutions.To substitute an item on ISO, you must ensure that the value of the Item Substitution on Internal Order system parameter is set to a value other than None. In addition, you must ensure to define substitute item relationships and automatic item substitution setup in the system. The application provides the option to not send the notifications when any change happens on the ISO related to quantity, schedule arrival date, or item. You can control these notifications using the OM: Send Notifications of Internal Order Change profile option. For additional information refer to the Oracle Order Management Release Notes for Release 12.2.4 (Doc ID 1906521.1).

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  • Multiple Denial of Service (DoS) vulnerabilities in FreeType

    - by chandan
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2012-1126 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 10.0 FreeType Font Engine Solaris 11 Contact Support Solaris 10 SPARC: 119812-16 X86: 119813-18 Solaris 9 Contact Support CVE-2012-1127 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1128 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1129 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1130 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1131 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1132 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1133 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1134 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1135 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1136 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1137 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1138 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1139 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1140 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1141 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1142 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 CVE-2012-1143 Numeric Errors vulnerability 4.3 CVE-2012-1144 Improper Restriction of Operations within the Bounds of a Memory Buffer vulnerability 9.3 This notification describes vulnerabilities fixed in third-party components that are included in Sun's product distribution.Information about vulnerabilities affecting Oracle Sun products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • prolog program to find equality of two lists in any order

    - by Happy Mittal
    I wanted to write a prolog program to find equality of two lists, the order of elements doesn't matter. So I wrote following: del( _ , [ ] , [ ] ) . del( X , [ X|T ] , T ). del( X , [ H|T ] , [ H|T1 ] ) :- X \= H , del( X , T , T1 ). member( X, [ X | _ ] ) . member( X, [ _ | T ] ) :- member( X, T ). equal( [ ], [ ] ). equal( [X], [X] ). equal( [H1|T], L2 ) :- member( H1, L2 ), del( H1, L2, L3), equal(T , L3 ). But when I give input like equal([1,2,3],X)., it doesn't show all possible values of X. instead the program hangs in the middle. What could be the reason?

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  • files build execution order

    - by Mahesh
    Hi, I have a data structure which is as given below: class File { public string Value { get; set; } public File[] Dependencies { get; set; } public bool Change { get; private set; } public File(string value,File[] dependencies) { Value = value; Dependencies = dependencies; Change = false; } } Basically, this data structure follows a typical build execution of files. Each File has a value and a list of dependencies which is again of type File. Every file is exposed with a property called Change which tells whether the file is changed or not. I brainstormed to form a algorithm which goes through all these files and build in an order( i.e typical build process ) but haven't got a better algorithm. Can anyone throw some light on this? Thanks a lot. Mahesh

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