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• Visual C# 2008 Express connection to SQL Server 2008 Express problem

  - by Phil

  Hi guys, I have a problem with Visual C# 2008 express (SP1) connecting to SQL Server 2008 express. The "Add Connection" window (wherever initiated) doesn't list existing sql server and no option for sql server except a compact edition. Note that, I've got the VWD 2008 express (SP1) on the same machine which shows the window regularly (with SQL server listed) and SQL Server Management studio works fine with the server as well. I've seen other similar posts, did take some advices: reinstalled the VC#, services run ok, etc... but with no success with VC# so far. Again, on the same machine the VWD shows the dialog with sql server option regularly, but VC# shows only 3 options in "Change data source" dialog (1. Microsoft Access Database File (OLE DB) 2. Microsoft SQL Server Compact 3.5, 3. Microsoft SQL Server Database File) Any idea? Thanks in advice, Phil

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• git push problem -argh!

  - by phil swenson

  Dunno what's going on, no response from github on this prob so I'm asking here. Tried a git push for the first time in a month or so and got this. Turned on export GIT_CURL_VERBOSE=1 and did a push and get this: localhost:send2mobile_rails phil$ git push Password: * Couldn't find host github.com in the .netrc file; using defaults * About to connect() to github.com port 443 (#0) * Trying 207.97.227.239... * Connected to github.com (207.97.227.239) port 443 (#0) * SSL connection using DHE-RSA-AES256-SHA * Server certificate: * subject: O=*.github.com; OU=Domain Control Validated; CN=*.github.com * start date: 2009-12-11 05:02:36 GMT * expire date: 2014-12-11 05:02:36 GMT * subjectAltName: github.com matched * issuer: C=US; ST=Arizona; L=Scottsdale; O=GoDaddy.com, Inc.; OU=http://certificates.godaddy.com/repository; CN=Go Daddy Secure Certification Authority; serialNumber=07969287 * SSL certificate verify ok. > GET /303devworks/send2mobile_rails.git/info/refs?service=git-receive-pack HTTP/1.1 User-Agent: git/1.7.1 Host: github.com Accept: */* Pragma: no-cache < HTTP/1.1 401 Authorization Required < Server: nginx/0.7.61 < Date: Tue, 01 Jun 2010 10:53:13 GMT < Content-Type: text/html; charset=iso-8859-1 < Connection: keep-alive < Content-Length: 0 < WWW-Authenticate: Basic realm="Repository" < * Connection #0 to host github.com left intact * Issue another request to this URL: 'https://[email protected]/MYUSERHERE/send2mobile_rails.git/info/refs?service=git-receive-pack' * Couldn't find host github.com in the .netrc file; using defaults * Re-using existing connection! (#0) with host github.com * Connected to github.com (207.97.227.239) port 443 (#0) * Server auth using Basic with user '303devworks' > GET /303devworks/send2mobile_rails.git/info/refs?service=git-receive-pack HTTP/1.1 Authorization: Basic MzAzZGVfd29sa3M6Y29nbmwzNzIw User-Agent: git/1.7.1 Host: github.com Accept: */* Pragma: no-cache < HTTP/1.1 200 OK < Server: nginx/0.7.61 < Date: Tue, 01 Jun 2010 10:53:13 GMT < Content-Type: application/x-git-receive-pack-advertisement < Connection: keep-alive < Status: 200 OK < Pragma: no-cache < Content-Length: 153 < Expires: Fri, 01 Jan 1980 00:00:00 GMT < Cache-Control: no-cache, max-age=0, must-revalidate < * Expire cleared * Connection #0 to host github.com left intact Counting objects: 166, done. Delta compression using up to 4 threads. Compressing objects: 100% (133/133), done. * Couldn't find host github.com in the .netrc file; using defaults * About to connect() to github.com port 443 (#0) * Trying 207.97.227.239... * connected * Connected to github.com (207.97.227.239) port 443 (#0) * SSL re-using session ID * SSL connection using DHE-RSA-AES256-SHA * old SSL session ID is stale, removing * Server certificate: * subject: O=*.github.com; OU=Domain Control Validated; CN=*.github.com * start date: 2009-12-11 05:02:36 GMT * expire date: 2014-12-11 05:02:36 GMT * subjectAltName: github.com matched * issuer: C=US; ST=Arizona; L=Scottsdale; O=GoDaddy.com, Inc.; OU=http://certificates.godaddy.com/repository; CN=Go Daddy Secure Certification Authority; serialNumber=07969287 * SSL certificate verify ok. * Server auth using Basic with user 'MYUSERHERE' > POST /303devworks/send2mobile_rails.git/git-receive-pack HTTP/1.1 Authorization: Basic JzAzZGV1d29ya3M6Y25nb29zNzIq User-Agent: git/1.7.1 Host: github.com Accept-Encoding: deflate, gzip Content-Type: application/x-git-receive-pack-request Accept: application/x-git-receive-pack-result Expect: 100-continue Transfer-Encoding: chunked * The requested URL returned error: 411 * Closing connection #0 error: RPC failed; result=22, HTTP code = 411 Writing objects: 100% (140/140), 2.28 MiB | 1.93 MiB/s, done. Total 140 (delta 24), reused 0 (delta 0) ^C localhost:send2mobile_rails phil$

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• How to find the filename of a script being run when it is executed from a symlink on linux

  - by Phil Boltt

  Hi, If I have a python script that is executed via a symlink, is there a way that I can find the path to the script rather than the symlink? I've tried using the methods suggested in this question, but they always return the path to the symlink, not the script. For example, when this is saved as my "/usr/home/philboltt/scripts/test.py" : #!/usr/bin/python import sys print sys.argv[0] print __file__ and I then create this symlink ln -s /usr/home/philboltt/scripts/test.py /usr/home/philboltt/test and execute the script using /usr/home/philboltt/test I get the following output: /usr/home/philboltt/test /usr/home/philboltt/test Thanks! Phil

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• Setting minimum number of decimal places for std::ostream precision

  - by Phil Boltt

  Hi, Is there a way to set the "minimum" number of decimal places that a std::ostream will output? For example, say I have two doubles that I want to print: double a = 0; double b = 0.123456789; I can set my maximum decimal precision so that I output b exactly std::cout << std::setprecision(9) << b << std::endl; Is there a way to set "minimum" precision so that std::cout << a << std::endl; yields "0.0", not just "0"? Thanks! Phil

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• FTP server deatails according to domain

  - by Phil Jackson

  Hello, What I am trying to accomplish is getting relative and absolute paths to files, images and folders that reside on a remote server. I have website address, and FTP details (these are required when signing up). What i need to know is whether the FTP details correspond correctly with the website. Firstly I used (this is all in PHP I forgot to add) : $conn_id = ftp_connect("ftp.".$WEBSITE); if($login_result = ftp_login ($conn_id, $ftpUser, $ftpPass)) which works. BUT what i dont know, and am not sure about at all, will ("ftp.".$WEBSITE) be sufficient for all "FTP servers"? Regards, Phil Jackson

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• turning text into image - PHP/GD - save image

  - by Phil Jackson

  Hi, I'm using this script to simply create an image from text. What I would like to know is how to save the image instead of printing straight to browser; // an email address in a string $string = $post[$key]; // some variables to set $font = 4; $width = ImageFontWidth($font) * strlen($string); $height = ImageFontHeight($font); // lets begin by creating an image $im = @imagecreatetruecolor ($width,$height); //white background $background_color = imagecolorallocate ($im, 255, 255, 255); //black text $text_color = imagecolorallocate ($im, 0, 0, 0); // put it all together $image = imagestring ($im, $font, 0, 0, $string, $text_color); I know its probably just one line of code at the end but im not sure which GD function to use. Any help would be much appreciated, Regards, Phil.

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• Mac OS X 10.5+ and POSIX

  - by Phil

  Hello, I need to program an authentication module that has to work with Mac OS X 10.6 Snow Leopard and at the same time needs to be POSIX-compliant. I read here: developer.apple.com/leopard/overview/osfoundations.html that since Mac OS X 10.5 Leopard, Mac OS X is POSIX-compliant (to POSIX 1003.1), but working under MAC OS X 10.5 Leopard myself, I can't find any trace of my user name neither in /etc/passwd nor in its successor /etc/master.passwd, which is mentioned here: developer.apple.com/mac/library/DOCUMENTATION/Darwin/Reference/ManPages/man5/passwd.5.html Instead it says in both files OpenDirectory Service is used, which should be OpenLDAP according to the OpenDirectoryService man-page. Is this still POSIX-compliant ? I guess not. I wonder how Mac OS X would handle my 100% POSIX-compliant code which depends on /etc/passwd ? I would be gratefull if someone could explain the way this works to me. Thank you for your time and trouble. Best regards Phil.

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• PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

  - by Phil Jackson

  Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

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• stumped on jquery call inside chrome extension

  - by phil swenson

  In my chrome extension I call this: jsonPost = { email:"[email protected]", password:"demo", content: $('#selected_text').val(), notification_type: $('#notification_type').val(), name:$('#notification_name').val() } $.post('http://localhost:3000/api/create.json', jsonPost, function (data) { console.log("type of data = " + typeof(data)); console.log("data in function = " + data); } The data makes it to the server. But the response is lost, in the console ---type of data = String ---data in function = So for some reason I am not getting the response back. Works from the browser. I even tried doing a get against cnn.com and got no response. any ideas? thanks

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• PHP/MySQL - updateing 2 tables in one request

  - by Phil Jackson

  Morning, I want to learn more about sql and I'm wanting to update to tables; $query3 = "INSERT INTO `$table1`, `$table2` ($table1.DISPLAY_NAME, $table1.EMAIL_ACCOUNT, $table2.DISPLAY_NAME, $table2.EMAIL_ACCOUNT) values ('" . DISPLAY_NAME . "', '" . EMAIL_ADDRESS . "', '" . $get['rn'] . "', '" . $email . "')"; could some one point me in the right direction on how I would go about this? current error is You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' contacts_ACT_Web_Designs (contacts_E_Jackson.DISPLAY_NAME, contacts_E_Jackson' at line 1 regards, phil

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• custom Progress Dialog in android?

  - by androidbase Praveen

  i follow the step in the customdialog example in the documentation. but get htis exception . any idea? 04-03 18:50:28.787: VERBOSE/Bru_Press_Tab(750): Exception in Tabsjava.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.brown/com.example.brown.Bru_Press_MostRecent}: android.util.AndroidRuntimeException: requestFeature() must be called before adding content

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• Flex: replace all spaces with comma

  - by Treby

  im new with regexp, so can i ask for some assistance Using string.replace function what code that can replace spaces with comma Input:The quick brown fox jumps over the lazy dog. Output:The,quick,brown,fox,jumps,over,the,lazy dog. Thanks

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• Create array of objects based on another array?

  - by xckpd7

  I want to take an array like this: var food = [ { name: 'strawberry', type: 'fruit', color: 'red', id: 3483 }, { name: 'apple', type: 'fruit', color: 'red', id: 3418 }, { name: 'banana', type: 'fruit', color: 'yellow', id: 3458 }, { name: 'brocolli', type: 'vegetable', color: 'green', id: 1458 }, { name: 'steak', type: 'meat', color: 'brown', id: 2458 }, ] And I want to create something like this dynamically: var foodCategories = [ { name: 'fruit', items: [ { name: 'apple', type: 'fruit', color: 'red', id: 3418 }, { name: 'banana', type: 'fruit', color: 'yellow', id: 3458 } ] }, { name: 'vegetable', items: [ { name: 'brocolli', type: 'vegetable', color: 'green', id: 1458 }, ] }, { name: 'meat', items: [ { name: 'steak', type: 'meat', color: 'brown', id: 2458 } ] } ] What's the best way to go about doing this?

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• excel change 4 rows / 48 col to 48 rows / 4 col

  - by GoodOlPete

  Hi, I've selected 4 database records of 48 fields into excel as below: FirstName LastName Age Address1 ....................... Andy smith 23 53 high st billy ball 43 23 the avenue charles brown 76 rose cottage dave green 43 station rd I want to display them as firstname andy billy charles dave lastname smith ball brown green age 23 43 76 43 address1.............................. Can anyone suggest how to do this?

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• How to search for alphanumeric word before or after a keyword in perl?

  - by aliocee

  I have sentences as shown in the below examples: $sen1 = "The quick brown fox jump KEYWORD over123 the3 lazy dog, fox is quick"; $sen2 = "The quick brown fox jump123 KEYWORD over the lazy dog, fox is quick"; i want to use the keyword 'KEYWORD' as my search string to extract the alphanumeric words before and after the search string using Perl regular expression. sample output: over123 jump123 NB: The word 'the3' is left out because i'm only searching for alphanumeric words exactly before or after the 'KEYWORD'. Thanks

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• How do I keep this from pushing down?

  - by Doug

  http://dougymak.com/jquery/test.html Playing with jQuery and upon pressing "More" on the top left, it pushes down the "Brown" layer. How can I keep the brown layer steady? It happens in Chrome, but not Firefox.

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• SQL Reset Identity ID in already populated table

  - by rockinthesixstring

  hey all. I have a table in my DB that has about a thousand records in it. I would like to reset the identity column so that all of the ID's are sequential again. I was looking at this but I'm ASSuming that it only works on an empty table Current Table ID | Name 1 Joe 2 Phil 5 Jan 88 Rob Desired Table ID | Name 1 Joe 2 Phil 3 Jan 4 Rob Thanks in advance

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• Advanced SQL query with lots of joins

  - by lund.mikkel

  Hey fellow programmers Okay, first let me say that this is a hard one. I know the presentation may be a little long. But I how you'll bare with me and help me through anyway :D So I'm developing on an advanced search for bicycles. I've got a lot of tables I need to join to find all, let's say, red and brown bikes. One bike may come in more then one color! I've made this query for now: SELECT DISTINCT p.products_id, #simple product id products_name, #product name products_attributes_id, #color id pov.products_options_values_name #color name FROM products p LEFT JOIN products_description pd ON p.products_id = pd.products_id INNER JOIN products_attributes pa ON pa.products_id = p.products_id LEFT JOIN products_options_values pov ON pov.products_options_values_id = pa.options_values_id LEFT JOIN products_options_search pos ON pov.products_options_values_id = pos.products_options_values_id WHERE pos.products_options_search_id = 4 #code for red OR pos.products_options_search_id = 5 #code for brown My first concern is the many joins. The Products table mainly holds product id and it's image and the Products Description table holds more descriptive info such as name (and product ID of course). I then have the Products Options Values table which holds all the colors and their IDs. Products Options Search is containing the color IDs along with a color group ID (products_options_search_id). Red has the color group code 4 (brown is 5). The products and colors have a many-to-many relationship managed inside Products Attributes. So my question is first of all: Is it okay to make so many joins? Is i hurting the performance? Second: If a bike comes in both red and brown, it'll show up twice even though I use SELECT DISTINCT. Think this is because of the INNER JOIN. Is this possible to avoid and do I have to remove the doubles in my PHP code? Third: Bikes can be double colored (i.e. black and blue). This means that there are two rows for that bike. One where it says the color is black and one where is says its blue. (See second question). But if I replace the OR in the WHERE clause it removes both rows, because none of them fulfill the conditions - only the product. What is the workaround for that? I really hope you will and can help me. I'm a little desperate right now :D Regards Mikkel Lund

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• How to store array data in MySQL database using PHP & MySQL?

  - by Cyn

  I'm new to php and mysql and I'm trying to learn how to store the following array data from three different arrays friend[], hair_type[], hair_color[] using MySQL and PHP an example would be nice. Thanks Here is the HTML code. <input type="text" name="friend[]" id="friend[]" /> <select id="hair_type[]" name="hair_type[]"> <option value="Hair Type" selected="selected">Hair Type</option> <option value="Straight">Straight</option> <option value="Curly">Curly</option> <option value="Wavey">Wavey</option> <option value="Bald">Bald</option> </select> <select id="hair_color[]" name="hair_color[]"> <option value="Hair Color" selected="selected">Hair Color</option> <option value="Brown">Brown</option> <option value="Black">Black</option> <option value="Red">Red</option> <option value="Blonde">Blonde</option> </select> <input type="text" name="friend[]" id="friend[]" /> <select id="hair_type[]" name="hair_type[]"> <option value="Hair Type" selected="selected">Hair Type</option> <option value="Straight">Straight</option> <option value="Curly">Curly</option> <option value="Wavey">Wavey</option> <option value="Bald">Bald</option> </select> <select id="hair_color[]" name="hair_color[]"> <option value="Hair Color" selected="selected">Hair Color</option> <option value="Brown">Brown</option> <option value="Black">Black</option> <option value="Red">Red</option> <option value="Blonde">Blonde</option> </select> Here is the MySQL tables below. CREATE TABLE friends_hair ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, hair_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) ); CREATE TABLE hair_types ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, friend TEXT NOT NULL, hair_type TEXT NOT NULL, hair_color TEXT NOT NULL, PRIMARY KEY (id) );

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• (Python) Converting a dictionary to a list?

  - by Daria Egelhoff

  So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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• MVC2 Apps (and others) sharing WCF services and authentication

  - by stupid-phil

  Hi, I've seen several similar scenarios explained here but not my particular one. I wonder if someone could tell me which direction to go in? I am developing two (and more later) MVC2 apps. There will also be another (thicker) client later on (WPF or Silverlight, TBD). These all need to share the same authentication. For the MVC2 apps they (preferably) need to be single log on - ie if a user logs in to one MVC2 app, they should be authorised on the other, as long as the cookie hasn't timed out. Forms authentication is to be used. All the apps need to use common business functionality and perform db access via a common WCF Service App. It would be nice (I think) if the WCF is not publicly accessible (ie blocked behind FW). The thicker client could use an additional service layer to access the Common WCF App. What this should look like is: MVCApp1 - WCFAppCommon MVCApp2 - WCFAppCommon ThickClient - WCFApp2 - WCFAppCommon Is it possible to carry out all the authentication/authorization in the WCFAppCommon? Otherwise I think I'll have to repeat all the security logic in the MVCApps and WCFApp2, whereas, to me, it seems to sit naturally in WCFAppCommon. On the otherhand, it seems if I authenticate/authorize in WCFAppCommon, I wouldn't be able to use Forms Authentication. Where I've seen possible solutions (that I haven't tried yet) they seem much more complex than Forms Authentication and a single DB. Any help appreciated, Phil

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• dynamically create class in scala, should I use interpreter?

  - by Phil

  Hi, I want to create a class at run-time in Scala. For now, just consider a simple case where I want to make the equivalent of a java bean with some attributes, I only know these attributes at run time. How can I create the scala class? I am willing to create from scala source file if there is a way to compile it and load it at run time, I may want to as I sometimes have some complex function I want to add to the class. How can I do it? I worry that the scala interpreter which I read about is sandboxing the interpreted code that it loads so that it won't be available to the general application hosting the interpreter? If this is the case, then I wouldn't be able to use the dynamically loaded scala class. Anyway, the question is, how can I dynamically create a scala class at run time and use it in my application, best case is to load it from a scala source file at run time, something like interpreterSource("file.scala") and its loaded into my current runtime, second best case is some creation by calling methods ie. createClass(...) to create it at runtime. Thanks, Phil

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• Opening href in jQuery Dialog

  - by Phil

  Okay, so I've got the following code to create a dialog of a div within a page: $('#modal').dialog({ autoOpen: false, width: 600, height: 450, modal: true, resizable: false, draggable: false, title: 'Enter Data', close: function() { $("#modal .entry_date").datepicker('hide'); } }); $('.modal').click(function() { $('#modal').dialog('open'); }); All working fine. But what I want is to also be able to open a link in a dialog window, kinda like... <a href="/path/to/file.html" class="modal">Open Me!!</a> I've done this before by hardcoding the path: $('#modal').load('/path/to/file.html').dialog('open'); but we can't hardcode the path in the javascript (as there will be multiple coming from the database) and I'm struggling to understand how to get this to work. I'm also pretty sure that the answer is really obvious, and I'm merely setting myself up to be humbled by the clever folk here at StackOverflow, but I've scratched my head for long enough this afternoon, so my ego has been put away, and hopefully someone can point me in the right direction... Thanks Phil

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• PHP - post data ends when '&' is in data.

  - by Phil Jackson

  Hi all, im posting data using jquery/ajax and PHP at the backend. Problem being, when I input something like 'Jack & Jill went up the hill' im only recieving 'Jack' when it gets to the backend. I have thrown an error at the frontend before that data is sent which alerts 'Jack & Jill went up the hill'. When I put die(print_r($_POST)); at the very top of my index page im only getting [key] => Jack how can I be loosing the data? I thought It may have been my filter; <?php function filter( $data ) { $data = trim( htmlentities( strip_tags( mb_convert_encoding( $data, 'HTML-ENTITIES', "UTF-8") ) ) ); if ( get_magic_quotes_gpc() ) { $data = stripslashes( $data ); } //$data = mysql_real_escape_string( $data ); return $data; } echo "<xmp>" . filter("you & me") . "</xmp>"; ?> but that returns fine in the test above you &amp; me which is in place after I added die(print_r($_POST));. Can anyone think of how and why this is happening? Any help much appreciated. Regards, Phil.

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• paypal sadbox IPN

  - by Phil Jackson

  Morning all. I am trying to test a SIMPLE php script to deal with the IPN response from paypal sandbox. <?php // read the post from PayPal system and add 'cmd' $req = 'cmd=_notify-validate'; foreach ($post as $key => $value) { $value = urlencode(stripslashes($value)); $req .= "&$key=$value"; } // post back to PayPal system to validate $header = "POST /cgi-bin/webscr HTTP/1.0\r\n"; $header .= "Content-Type: application/x-www-form-urlencoded\r\n"; $header .= "Content-Length: " . strlen($req) . "\r\n\r\n"; $fp = fsockopen ('ssl://www.sandbox.paypal.com/', 443, $errno, $errstr, 30); if ( !$fp ) { // HTTP ERROR $fp = fopen('thinbg.txt', 'a'); fwrite($fp, "false !fp - " . implode(" ", $post) ); fclose($fp); } else { fputs ($fp, $header . $req); while (!feof($fp)) { $res = fgets ($fp, 1024); if (strcmp ($res, "VERIFIED") == 0) { // PAYMENT VALIDATED & VERIFIED! $fp2 = fopen('thinbg.txt', 'a'); fwrite($fp2, "true - " . implode(" ", $post) ); fclose($fp2); } else if (strcmp ($res, "INVALID") == 0) { // PAYMENT INVALID & INVESTIGATE MANUALY! $fp2 = fopen('thinbg.txt', 'a'); fwrite($fp2, "false - " . implode(" ", $post) ); fclose($fp2); } } fclose ($fp); } ?> When I click on "send IPN" in the test ac"IPN successfully sent". when I look at the file that I created to check the vars it begins with "false !fp" yet still displays all the vars. Can anyone see whats happening and how I go about fixing. Regards, Phil

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