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  • [Zend Debugger] Cannot receive start command

    - by tharkun
    Hi I have a WAMP install (Apache 2.2.3, PHP 5.2.8) with a working Zend Optimizer. As soon as I add the php.ini lines for Zend Debugger: [Zend Debugger] zend_extension_manager.debug_server_ts="C:\zenddebugger" zend_debugger.allow_hosts=127.0.0.1/32, 192.168.0.0/16, 192.168.1.0/255 zend_debugger.expose_remotely=always and restart apache, I get a blank page and the following entry in the apache error log. [Zend Debugger] Cannot receive start command [Zend Debugger] Cannot send message Now the incredible thing is that I had it working this morning and now, after reinstalling WAMP there is no way I can get it work again. php.ini is exactly the same as it was before. I would be extremely glad to get help, I'm trying to get a working server environment going for over a month, can you believe that? I tried XAMPP, Zend Server and now WAMP and I'm going crazy slowly but surely.

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  • apache server not working after installing zend server

    - by kamal
    i have apache installed in my redhat 5.3 server machine. and i was trying to install zend server. i installed zend server with install.sh file in directory /var/zend. in my windows machine after installling zend server community edition i was able to access apache server as well as zend server. but in my linux machine localhost displays nothing and localhost:10081 shows zend server. what can i do to run my localhost? or should i seperately install apache?

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  • Zend hostname route doesn't match when it has child routes

    - by talisker
    I am implementing an Admin module, which contains the following routes: 'router' => array( 'routes' => array( 'admin' => array( 'type' => 'Zend\Mvc\Router\Http\Hostname', 'options' => array( 'route' => ':subdomain.mydomain.local', 'constraints' => array( 'subdomain' => 'admin', ), 'defaults' => array( 'module' => '__NAMESPACE__', 'controller' => 'Admin\Controller\Index', 'action' => 'index', ), ), 'priority' => 9000, 'may_terminate' => true, 'child_routes' => array( 'users' => array( 'type' => 'Zend\Mvc\Router\Http\Literal', 'options' => array( 'route' => '/users', 'defaults' => array( 'module' => '__NAMESPACE__', 'controller' => 'Admin\Controller\Users', 'action' => 'index', ), ), ), ) ), ), ), And this is the home route configuration: 'home' => array( 'type' => 'Zend\Mvc\Router\Http\Literal', 'options' => array( 'route' => '/', 'defaults' => array( 'controller' => 'Application\Controller\Index', 'action' => 'index', ), ), ), When I try to access to http://admin.mydomain.com, the route match always with the homeroute, but if I remove all the child routes from the admin route, the behavior is correct and a http://admin.mydomain.com matches with the adminroute. Any idea?

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  • How to switch from Apache 2.0 Handler to FastCGI on Ubuntu Zend Server?

    - by amoooc
    I can't deploy/manage my Joomla websites On Ubuntu 12.04 Zend Server PHP 5.3.14 due to permissions during Joomla installation/J! extensions installation. All files are unwriteable. Only CHMOD 777 will help but of course it's not resolving the problem due to security issues. I think it's because cgi-fcgi is not shipped with Zend Server (only with Zend Server for Windows) Or maybe there is different solution how to make it work? PHP info on Ubuntu Zend Server Server API: Apache 2.0 Handler PHP Version 5.3.14 Zend Server Community Edition 5.6.0 Server Software Apache/2.2.22 (Ubuntu) Zend Framework 1.12.0 I'm already asked similar question here, but unfortunately without solution yet so Ubuntu Community please advice. I would be grateful for any help. Cheers

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  • zend framework controller not found ?

    - by user284503
    I downloaded the latest version of Zend framework, added a controller and I can not get it to load.. Here is what I did: C:\zend\Apache2\htdocs>zf create project myproject Creating project at C:/zend/Apache2/htdocs/myproject Note: This command created a web project, for more information setting up your V HOST, please see docs/README C:\zend\Apache2\htdocs>cd myproject C:\zend\Apache2\htdocs\myproject>zf create controller mycontroller Note: The canonical controller name that is used with other providers is "Mycont roller"; not "mycontroller" as supplied Creating a controller at C:\zend\Apache2\htdocs\myproject/application/controller s/MycontrollerController.php Creating an index action method in controller Mycontroller Creating a view script for the index action method at C:\zend\Apache2\htdocs\myp roject/application/views/scripts/mycontroller/index.phtml Creating a controller test file at C:\zend\Apache2\htdocs\myproject/tests/applic ation/controllers/MycontrollerControllerTest.php Updating project profile 'C:\zend\Apache2\htdocs\myproject/.zfproject.xml' C:\zend\Apache2\htdocs\myproject> Then I tried to hit the controller from the browser.. http://localhost/myproject/public/mycontroller/ and I get the error: Not Found The requested URL /myproject/public/mycontroller/ was not found on this server. I have no idea how to resolve this, and I'm sort of shocked I'm having problems with the Zend Server.

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  • zf2 \Zend\Db\Sql\Sql using predicate in where condition

    - by RomanKonz
    i really don't get the point how to use predicates in zend framework 2. this is what i got: $sql->select() ->columns(array('GroupedColum' ,'minValue' => new Expression('min(ValueColumn)'))) ->from('ValueTable') ->group('GroupedColum') ->order('minValue') ->order('GroupedColum') ->limit(10); this is working fine now i want to apply somethin like that: $predicate = new Zend\Db\Sql\Predicate\Predicate(); $sql->where($predicate->greaterThan('filterColumn','20); this is what i tried, it throws no error, but it is not working :-( This is what i expect as SQL: select GroupedColum , min(ValueColumn) as minValue from ValueTable where filterColumn > 20 group by GroupedColum order by minValue GroupedColum limit 10;

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  • Problem in implementing the Url Rewritting for a Zend Application

    - by Nishant
    Hello everyone, I am doing my first Zend Applicaition and I am finally done with the coding side. But the problem which I have is Client has asked to rewrite the Url's which follows the SEO and as I don't have much knowledge of the Zend Router,I am finding myself helpless this time. Please helo me out.The current Url which I have is... http://localhost.ZendProject.com/keywords/ball and Client needs it like http://localhost.ZendProject.com/keywords/ball and another Url (the search Url) http://localhost.ZendProject.com/search/trends?q=nishant+shrivastava&select=All&Search=Search and the Client wants is http://localhost.ZendProject.com/nishant-shrivastava Please help me out of this problem,because I am totally freaked out thinking of any solution and my mind is also not helping me out.

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  • Salting example in Zend Framework

    - by Geoffrey
    Hello all, I am pretty new to the Zend framework and looking to build an application with pretty tight password security. I have been trying to follow the user guides in relation to password salting but haven't had any luck so far. I have setup my database and table adapter (As described in the documentation on the Zend Framework site but it didn't seem to finish the example (or I am not following well enough!) I have started with: $authAdapter = new Zend_Auth_Adapter_DbTable($dbAdapter, 'users', 'username', 'password', "MD5(CONCAT('".Zend_Registry::get('staticSalt')."', ?, password_salt))" ); But from here, what is done with the password salt? I just need an example and I'll be away! Does anyone have an example or point me in the right direction?? Many thanks!

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  • How to call a Zend lucene search function?

    - by stef
    I inherited a Zend project devoid of comments and I didn't get to talk to the previous developer. Since I have no Zend experience I'm having some issues :) I'd like to print out some variables inside an function that indexes items from the site using Zend_Search_Lucene because I think something is going wrong here. From what I've read, ::create creates a new index and ::open updates it. So it's in this ::open function I'd like to print out some variables. The name and params of the function are below. Does anyone have any idea how this function can be called so I can run some tests? private function search($category,$string,$page = 1,$itemsByPage = 5) EDIT: OR, is there a way I can nuke the existing index and force it to be rebuilt completely, for example by deleting the index files on the FS and then performing some searches?

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  • Apache htaccess Zend redirecting excepting some fodlers

    - by Frederick Marcoux
    Last week, I remade all of my website using the famous Zend Framework and now, I'm starting worrying about it... I'm trying to make an administration zone within a subfolder (also ZF) and a API Zend Application for my mobile Android application. The problem is: I rewrited all routes im my principal website, so now it always search for a route when I go to a subfolder. There's my root folder .htaccess: RewriteEngine On RewriteRule ^.htaccess$ - [F] RewriteCond %{REQUEST_URI}!^/api/ RewriteCond %{REQUEST_URI}!^/admin/ RewriteRule ^public/.*$ /public/index.php [NC,L] RewriteRule ^(.*)$ /public/$1 [NC,L] The way I want it is that: URL: {domain}/ => ./public/index.php (where's my current ZF app) URL: {domain}/[admin|api] => ./[admin/|api]/public/index.php (the others app) {domain} = my TLD; [admin|api] the requested folder So, in simple: Request = /api => /api Request = /admin => /admin Request = {anything else} => /public/index.php I searched a lot on SO and also on Google but I didn't find anything working -_-

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  • Zend Framwork scaffolding capabilities

    - by rockstarz
    Are there any open source projects any of you would recommend to follow or contribute toward, including those already documented among the zf contributors, to add zend framework scaffolding of crud functionality for rapid development as found in many competitors frameworks (Yii, Symfony, Rails, Django, etc.)? As a user of zf on a daily basis on enterprise implementations, I know this is a topic of interest and I feel professional developers like you would find here would have something to contribute toward my question and finding a library that is underway that can be contributed to.

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  • Xdebug 2.0.5 with Zend Server CE PHP5.2.12 possible?

    - by notbrain
    I'm using Zend Server CE with PHP 5.2.12 on OSX Snow Leopard and want to use Xdebug. I've turned off Zend Data Cache, Zend Optimizer+, and Zend Debugger in the console. When I run $ cd ~/Downloads/xdebug-2.0.5 $ /usr/local/zend/bin/phpize I get Configuring for: PHP Api Version: 20041225 Zend Module Api No: 20060613 Zend Extension Api No: 220060519 The PHP API Version, 20041225, seems to be off from the documentation (aka wrong). When I continue installation with $ ./configure ---with-php-config=/usr/local/zend/bin/php-config $ make $ sudo make install The installed xdebug.so seems to be the wrong one. Which version of xdebug do I need for this PHP API version? The Zend API numbers are ok. I'm just confused at why the PHP API Version doesn't match. PHP Warning: PHP Startup: Unable to load dynamic library '/usr/local/zend/lib/php_extensions/xdebug.so' - (null) in Unknown on line 0 PHP 5.2.12 (cli) (built: Feb 17 2010 13:39:36)

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  • Zend_Form : Adding fields in sub-forms on user's click

    - by anu iyer
    I'm having a zend form - comprised of a number of zend - sub forms, where the user is creating a new question (its a content management system). In one of the subforms, the user can click on a button to add more textfields, like this: [----------] [----------] [click to add more] which should give [----------] [----------] [----------] [click to add more] I'm trying to set a flag in the sub form in question - or set a count on how many times the button has been clicked, to add that many total fields to the subform - but its simply not working. I tried using a static count variable - but the value doesnt get incremented at all. Any thoughts on how to do this in a Zend-subform within a zend form? I'll definitely update if I hit a solution. Thanks!

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  • Google Spreadsheet API problem: memory exceeded

    - by Robbert
    Hi guys, Don't know if anyone has experience with the Google Spreadsheets API or the Zend_GData classes but it's worth a go: When I try to insert a value in a 750 row spreadsheet, it takes ages and then throws an error that my memory limit (which is 128 MB!) was exceeded. I also got this when querying all records of this spreadsheet but this I can imaging because it's quite a lot of data. But why does this happen when inserting a row? That's not too complex, is it? Here's the code I used: public function insertIntoSpreadsheet($username, $password, $spreadSheetId, $data = array()) { $service = Zend_Gdata_Spreadsheets::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($username, $password, $service); $client->setConfig(array( 'timeout' => 240 )); $service = new Zend_Gdata_Spreadsheets($client); if (count($data) == 0) { die("No valid data"); } try { $newEntry = $service->insertRow($data, $spreadSheetId); return true; } catch (Exception $e) { return false; } }

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  • Zend Server Cannot restart PHP: permission denied for user

    - by user30115
    When I click "Restart PHP" in Zend Server web interface, I get this error in the logs: PHP Warning: Cannot restart PHP: permission denied for user IIS APPPOOL\DefaultAppPool. in C:\Program Files (x86)\Zend\ZendServer\GUI\application\CE\models\ZwasComponents\Util\Api\UserServer.php on line 86 Based on http://kb.zend.com/index.php?View=entry&EntryID=426 I tried to give permissions to user IIS APPPOOL\DefaultAppPool to the folder C:\Program Files (x86)\Zend\ZendServer\, however it still gives the same error. Do you know to what resources the application pool does not have permissions to?

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  • Access denied error on select into outfile using Zend

    - by Peter
    Hi, I'm trying to make a dump of a MySQL table on the server and I'm trying to do this in Zend. I have a model/mapper/dbtable structure for all my connections to my tables and I'm adding the following code to the mappers: public function dumpTable() { $db = $this->getDbTable()->getAdapter(); $name = $this->getDbTable()->info('name'); $backupFile = APPLICATION_PATH . '/backup/' . date('U') . '_' . $name . '.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $name"; $db->query( $query ); } This should work peachy, I thought, but Message: Mysqli prepare error: Access denied for user 'someUser'@'localhost' (using password: YES) is what this results in. I checked the user rights for someUser and he has all the rights to the database and table in question. I've been looking around here and on the net in general and usually turning on "all" the rights for the user seems to be the solution, but not in my case (unless I'm overlooking something right now with my tired eyes + I don't want to turn on "all" on my production server). What am I doing wrong here? Or, does anybody know a more elegant way to get this done in Zend?

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  • Zend Framework cleaning default routes when adding other

    - by Renato Aquino
    I have the following problem with Zend Framework. My project has several controllers like Video,Category and Post. The VideoController has an Action called categorylist, so the default URL/Route becomes /video/categorylist Since the action requires 3 parameters I whant to add one simple route: $router->addRoute( 'categorylist', new Zend_Controller_Router_Route('categorylist/:category/:page/:per_page', array('controller' => 'video', 'action' => 'categorylist','page'=>1,'per_page'=>6,'category'=>1)) ); With this I got my URL like www.siteurl.com/categorylist/42/1/6 but, the View Helper URL got crazy, and every url for the other controllers I try to echo it´s redirected to the categorylist route. So when I try this: <?= $this->url(array("controller"=> "video", "action" =>"view",'category'=>1),null,true)?> The expected result its /video/view/category/1, but I got /categorylit only. I tryied to debug the default routes but I got an empty array. print_r($ctrl->getRouter()->getRoutes()); Does anyone have some clue about this wierd behavior? I´m using Zend Framework Version 1.9.7

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  • SyntaxError using gdata-python-client to access Google Book Search Data API

    - by isbadawi
    >>> import gdata.books.service >>> service = gdata.books.service.BookService() >>> results = service.search_by_keyword(isbn='0434003484') Traceback (most recent call last): File "<pyshell#4>", line 1, in <module> results = service.search_by_keyword(isbn='0434003484') ... snip ... File "C:\Python26\lib\site-packages\atom\__init__.py", line 127, in CreateClassFromXMLString tree = ElementTree.fromstring(xml_string) File "<string>", line 85, in XML SyntaxError: syntax error: line 1, column 0 This is a minimal example -- in particular, the book service unit tests included in the package also fail with the exact same error. I've looked at the wiki and open issue tickets on Google Code to no avail (and this seems to me more apt to be a silly error on my end rather than a problem with the library). I'm not sure how to interpret the error message. If it matters, I'm using python 2.6.5.

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  • Why does Zend discourage "floating functions"?

    - by kojiro
    Zend's Coding Standard Naming Convention says Functions in the global scope (a.k.a "floating functions") are permitted but discouraged in most cases. Consider wrapping these functions in a static class. The common wisdom in Python says practically the opposite: Finally, use staticmethod sparingly! There are very few situations where static-methods are necessary in Python, and I've seen them used many times where a separate "top-level" function would have been clearer. (Not only does the above StackOverflow answer warn against overuse of static methods, but more than one Python linter will warn the same.) Is this something that can be generalized across programming languages, and if so, why does Python differ so from PHP? If it's not something that can be generalized, what is the basis for one approach or the other, and is there a way to immediately recognize in a language whether you should prefer bare functions or static methods?

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  • Why should I use Zend_Application?

    - by Billy ONeal
    I've been working on a Zend Framework application which currently does a bunch of things through Zend Application and a few resource plugins written for it. However, looking at this codebase now, it seems to me that using Zend_Application just makes things more complicated; and a plain, more "traditional" bootstrap file would do a better job of being transparent. This is even more the case because the individual components of Zend -- Zend_Controller, Zend_Navigation, etc. -- don't reference Zend_Application at all. Therefore they do things like "Well just call setRoute and be on your way," and the user is left scratching their head as to how to implement that in terms of the application.ini configuration file. This is not to say that one can't figure out what's going on by doing spelunking through the ZF source code. My problem with that approach is that it's to easy to depend on something that's an implementation detail, rather than a contract, and that all it seems to do is add an extra layer of indirection that one must wade through to understand an application. I look at pre ZF 1.8 example code, before Zend_Application existed, and everywhere I see plain bootstrap files that setup the MVC framework and get on their way. The code is clear and easy to understand, even if it is a bit repetitive. I like the DRY concept that Application gets you, but particularly when I'm assuming first people looking at the app's code aren't really familiar with Zend at all, I'm considering blowing away any dependence I have on Zend_Application and returning to a traditional bootstrap file. Now, my concern here is that I don't have much experience doing this, and I don't want to get rid of Zend_Application if it does something particularly important of which I am unaware, or something of that nature. Is there a really good reason I should keep it around?

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