Search Results

Search found 15376 results on 616 pages for 'mysql triggers'.

Page 50/616 | < Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >

  • Setting the mysql root user password on mac

    - by madaura
    I just Install MySQL on Mac OS X. The next step was setting the root user password, do I did the next: 1-Launch the terminal app to access the unix command line. 2-Under the unix prompt I executed the next commands: madaura$ cd /usr/local/mysql/bin madaura$ ./mysqladmin -u root password 'password' But, when I execute the command madaura$ ./mysql -u root, this is the answer: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 224 Server version: 5.5.13 MySQL Community Server (GPL) Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved. Oracle is a registered trademark of Oracle Corporation and/or its affiliates. Other names may be trademarks of their respective owners. Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> I can get in to the mysql command line without password! Any ideas? Thanks a lot!

    Read the article

  • Preview result of update/insert query whithout comitting changes to database in MySQL?

    - by Camsoft
    I am writing a script to import CSV files into existing tables within my database. I decided to do the insert/update operations myself using PHP and INSERT/UPDATE statements, and not use MySQL's LOAD INFILE command, I have good reasons for this. What I would like to do is emulate the insert/update operations and display the results to the user, and then give them the option of confirming that this is OK, and then committing the changes to the database. I'm using InnoDB database engine with support for transactions. Not sure if this helps but was thinking down the line of insert/update, query data, display to user, then either commit or rollback transaction? Any advise would be appreciated.

    Read the article

  • How do I increase Relevance value in an advanced MySQL query?

    - by morgant
    I've got a MySQL query similar to the following: SELECT *, MATCH (`Description`) AGAINST ('+ipod +touch ' IN BOOLEAN MODE) * 8 + MATCH(`Description`) AGAINST ('ipod touch' IN BOOLEAN MODE) AS Relevance FROM products WHERE ( MATCH (`Description`) AGAINST ('+ipod +touch' IN BOOLEAN MODE) OR MATCH(`LongDescription`) AGAINST ('+ipod +touch' IN BOOLEAN MODE) ) HAVING Relevance > 1 ORDER BY Relevance DESC Now, I've made the query more advanced by also searching for UPC: SELECT *, MATCH (`Description`) AGAINST ('+ipod +touch ' IN BOOLEAN MODE) * 8 + MATCH(`Description`) AGAINST ('ipod touch' IN BOOLEAN MODE) + `UPC` = '123456789012' * 16 AS Relevance FROM products WHERE ( MATCH (`Description`) AGAINST ('+ipod +touch' IN BOOLEAN MODE) OR MATCH(`LongDescription`) AGAINST ('+ipod +touch' IN BOOLEAN MODE) ) AND `UPC` = '123456789012' HAVING Relevance > 1 ORDER BY Relevance DESC That'll return results, but the fact that I had a successful match on the UPC does not increase the value of Relevance. Can I only do that kind of calculation w/full text searches like MATCH() AGAINST()? Clarification: Okay, so my real question is, why does the following not have a Relevance = 16? SELECT `UPC`, `UPC` = '123456789012' * 16 AS Relevance FROM products WHERE `UPC` = '123456789012' HAVING Relevance > 1 ORDER BY Relevance DESC

    Read the article

  • How to Check for record existence and do Insert in MYSQL ?

    - by karthik
    How to Check for record existence and do Insert or Update in MYSQL ? I have a script, which has set of Insert statements for multiple tables. Now when i try to execute the Insert statement, i want to do the following.. Check for the record existence and then do Insert or Update. If the Record is not exist do Insert. If the Record is already do not do anything. How to accomplish this ? Note : The script with Insert Statements are generated programmaticaly using SP

    Read the article

  • Checking for reciprocal relationships in mysql. A trivial one table problem.

    - by calumbrodie
    I have a mysql table that stores relationships. Items can be related to another item in one direction, or both items can be related to each other. I want to return all items related to my primary item - but I also want to check to see if the related item has a 'reverse relationship' to the current item and show this as a boolean |--------------|---------------| | SKU | related_SKU | |--------------|---------------| | 0001 | 0099 | | 0002 | 0099 | | 0099 | 0001 | |--------------|---------------| If I want to get all relationships for SKU=0001 SELECT related_SKU from relationships where SKU='0001' returns |--------------| | related_SKU | |--------------| | 0099 | |--------------| but what I want is |--------------|---------------| | related_SKU | reciprocal | |--------------|---------------| | 0099 | 1 | |--------------|---------------| or SELECT related_SKU from relationships where SKU='0002' |--------------|---------------| | related_SKU | reciprocal | |--------------|---------------| | 0099 | 0 | |--------------|---------------| What's the best way to do this?

    Read the article

  • How to retrieve MYSQL records as an INSERT statement.

    - by Aglystas
    I'm trying come up with the best method of synchronizing particular rows of 2 different database tables. So, for example there's 2 product tables in different databases as such... Origin Database product{ merchant_id, product_id, ... additional fields } Destination Database product{ merchant_id product_id ... additional fields } So, the database schema is the same for both. However I'm looking to select records with a particular merchant_id, remove all records from the destination table that have that merchant_id and replace those records with records from the origin database of the same merchant_id. My first thought was using mysqldump, parsing out the create table statements, and only running the Insert Statements. Seems like a pain though. So I was wondering if there is a better technique to do this. I would think mysql has some method of creating INSERT statements as output from a SELECT statement, so you can define how to insert specific record information into a new db. Any help would be appreciated, thank you much.

    Read the article

  • MySQL InnoDB Cascade Rule that looks at 2 columns?

    - by Travis
    I have the following MySQL InnoDB tables... TABLE foldersA ( ID title ) TABLE foldersB ( ID title ) TABLE records ( ID folderID folderType title ) folderID in table "records" can point to ID in either "foldersA" or "foldersB" depending on the value of folderType. (0 or 1). I am wondering: Is there a way to create a CASCADE rule such that the appropriate rows in table records are automatically deleted when a row in either foldersA or folderB is deleted? Or in this situation, am I forced to have to delete the rows in table "records" programatically? Thanks for you help!

    Read the article

  • Preview result of update/insert query without comitting changes to database in MySQL?

    - by Camsoft
    I am writing a script to import CSV files into existing tables within my database. I decided to do the insert/update operations myself using PHP and INSERT/UPDATE statements, and not use MySQL's LOAD INFILE command, I have good reasons for this. What I would like to do is emulate the insert/update operations and display the results to the user, and then give them the option of confirming that this is OK, and then committing the changes to the database. I'm using InnoDB database engine with support for transactions. Not sure if this helps but was thinking down the line of insert/update, query data, display to user, then either commit or rollback transaction? Any advise would be appreciated.

    Read the article

  • Bringing specific results to the front using one MySQL query.

    - by animuson
    I'm setting up my geolocation feature which lists out all the countries in order of name. However, most websites have it set up where the popular countries (such as United States, United Kingdom, Canada, Australia) are at the front of the list (are shown first rather than in their assigned places). Is it possible to achieve this using the same MySQL query that I am already running to select them? SELECT * FROM `global_flags` ORDER BY `country` Is there a better alternative somewhere? Perhaps something that can reorganize the results after the database has already been queried? I don't want to exclude those results and then manually type them at the beginning because that would waste more space in the file.

    Read the article

  • In mySQL, Is it possible to SELECT from two tables and merge the columns?

    - by Travis
    If I have two tables in mysql that have similar columns... TABLEA id name somefield1 TABLEB id name somefield1 somefield2 How do I structure a SELECT statement so that I can SELECT from both tables simultaneously, and have the result sets merged for the columns that are the same? So for example, I am hoping to do something like... SELECT name, somefield1 FROM TABLEA, TABLEB WHERE name="mooseburgers"; ...and have the name, and somefield1 columns from both tables merged together in the result set. Thank-you for your help!

    Read the article

  • MySQL, return only rows where there are duplicates among two columns.

    - by Richard Waite
    I have a table in MySQL of contact information ; first name, last name, address, etc. I would like to run a query on this table that will return only rows with first and last name combinations which appear in the table more than once. I do not want to group the "duplicates" (which may only be duplicates of the first and last name, but not other information like address or birthdate) - I want to return all the "duplicate" rows so I can look over the results and determine if they are dupes or not. This seemed like it would be a simple thing to do, but it has not been. Every solution I can find either groups the dupes and gives me a count only (which is not useful for what I need to do with the results) or doesn't work at all. Is this kind of logic even possible in a query ? Should I try and do this in Python or something?

    Read the article

  • Multiple connections to a MySQL database in a single PHP script.

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

    Read the article

  • MySQL - Counting rows in preparation for greatest-n-per-group not working?

    - by John M
    Referring to SO and other sites have given me examples of how to use MySQL to create a 'greatest-n-per-group' query. My variant on this would be to have a query that returns the first 3 rows of each category. As the basis for this I need to sort my data into a usable sequence and that is where my problems start. Running just the sequence query with row numbering shows that changes in category are mostly ignored. I should have 35 categories returning rows but only 5 do so. My query: set @c:=0; set @a:=0; SELECT IF(@c = tdg, @a:=@a+1, @a:=1) AS rownum, (@c:=tdg) , julian_day, sequence, complete, year, tdg FROM tsd WHERE complete = 0 order by tdg, year, julian_day, sequence Do I have a syntax mistake with this query?

    Read the article

  • Can't use MySQL extract() function in the WHERE clause.

    - by UkraineTrain
    I've run the following query: UPDATE main_table, reference_table SET main_table.calc_column = (CASE WHEN main_table.incr = "6AM" THEN reference_table.col1+reference_table.col2+... WHEN main_table.incr = "12AM" THEN reference_table.col7+reference_table.col8+... WHEN main_table.incr = "6PM" THEN reference_table.col13+reference_table.col14+... ELSE reference_table.col19+reference_table.col20+...) WHERE main_table.month = extract(month from reference_table.thedate) AND main_table.day = extract(day from reference_table.thedate) I've used extract() function since my reference_table doesn't have month and day columns but has the date column named thedate. I've used the extract() function on the reference_table many times before successfully, so, I know that there's nothing wrong with my extract function syntax. However, in this instance, MySQL complains. It probably has to do with the fact that I've used in the WHERE clause. I know that this issue could get fixed if I added the month and day columns to the reference_table to avoid using the extract() function. However, I'm very reluctant to do that and would like to avoid it. How can I make it work?`

    Read the article

  • Installing Rails, MySQL, etc. everything goes wrong

    - by Rits
    I've been struggling with this for a few hours. Everything just stopped working and I can't get it to work anymore. I'm a noob at Ruby, Ruby on Rails and the Terminal in general. This is really frustrating me so I just try to describe my problem as detailed as possible hoping someone can give me a solution. I'm on Mac OS X Snow Leopard. I couldn't get Rails working at all just now: Could not find gem 'rails' headaches But after some tries of reinstalling it, it suddenly worked again. But now I just can't get MySQL to work, and it sometimes even breaks the Rails installation again. This is what I do: sudo gem uninstall rails sudo gem uninstall mysql sudo gem uninstall mysql2 After these commands, I check the installed gems with gem list. No MySQL gem is listed anymore, but I can still see rails (2.3.5, 2.2.2, 1.2.6) . Is this normal? Does this mean I have 3 Rails installations? It doesn't make sense to me. Anyway, then I do this: sudo gem clean Which fails completely. I get a bunch of errors like this: Attempting to uninstall fcgi-0.8.7 Unable to uninstall fcgi-0.8.7: Gem::InstallError: cannot uninstall, check gem list -d fcgi It doesn't uninstall anything. At this point, I try to install everything again. I start with: sudo gem install rails Which succeeds (I think): Successfully installed rails-3.0.3 Successfully installed builder-2.1.2 2 gems installed Installing ri documentation for rails-3.0.3... File not found: lib Then, I update RubyGems: sudo gem update --system sudo gem install rubygems-update sudo update_rubygems Then it says I have 1.3.7 installed, so it succeeded, I think. So now I proceed with installing MySQL. I already got MySQL 5.5.8 installed on my machine. I did some research about installing MySQL on Snow Leopard, and it seems I have to use this command: sudo env ARCHFLAGS="-arch x86_64" gem install mysql -- --with-mysql-config=/usr/local/mysql/bin/mysql_config I get a bunch of errors like this: No definition for time_set_neg No definition for time_set_second_part No definition for time_equal No definition for error_errno At this point, I assume I got both Rails and the MySQL gem installed, so I try to start a new project. rails new user_group -d mysql It works! Rails is installed correctly. Now, I try generating a model. cd user_group rails generate model User It fails with this error: Could not find gem 'mysql2 (= 0, runtime)' in any of the gem sources listed in your Gemfile. Try running bundle install. So I try running bundle install. It installs a lot of gems. Then I try to generate my model again. I get this error: Library/Ruby/Gems/1.8/gems/mysql2-0.2.6/lib/mysql2/mysql2.bundle: dlopen(/Library/Ruby/Gems/1.8/gems/mysql2-0.2.6/lib/mysql2/mysql2.bundle, 9): Library not loaded: libmysqlclient.16.dylib (LoadError) Referenced from: /Library/Ruby/Gems/1.8/gems/mysql2-0.2.6/lib/mysql2/mysql2.bundle Reason: image not found - /Library/Ruby/Gems/1.8/gems/mysql2-0.2.6/lib/mysql2/mysql2.bundle This is as far as I can get. What should I do? And why should this be so hard...

    Read the article

  • NHibernate MySQL Composite-Key

    - by LnDCobra
    I am trying to create a composite key that mimicks the set of PrimaryKeys in the built in MySQL.DB table. The Db primary key is as follows: Field | Type | Null | ---------------------------------- Host | char(60) | No | Db | char(64) | No | User | char(16) | No | This is my DataBasePrivilege.hbm.xml file <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="TGS.MySQL.DataBaseObjects" namespace="TGS.MySQL.DataBaseObjects"> <class name="TGS.MySQL.DataBaseObjects.DataBasePrivilege,TGS.MySQL.DataBaseObjects" table="db"> <composite-id name="CompositeKey" class="TGS.MySQL.DataBaseObjects.DataBasePrivilegePrimaryKey, TGS.MySQL.DataBaseObjects"> <key-property name="Host" column="Host" type="char" length="60" /> <key-property name="DataBase" column="Db" type="char" length="64" /> <key-property name="User" column="User" type="char" length="16" /> </composite-id> </class> </hibernate-mapping> The following are my 2 classes for my composite key: namespace TGS.MySQL.DataBaseObjects { public class DataBasePrivilege { public virtual DataBasePrivilegePrimaryKey CompositeKey { get; set; } } public class DataBasePrivilegePrimaryKey { public string Host { get; set; } public string DataBase { get; set; } public string User { get; set; } public override bool Equals(object obj) { if (ReferenceEquals(null, obj)) return false; if (ReferenceEquals(this, obj)) return true; if (obj.GetType() != typeof (DataBasePrivilegePrimaryKey)) return false; return Equals((DataBasePrivilegePrimaryKey) obj); } public bool Equals(DataBasePrivilegePrimaryKey other) { if (ReferenceEquals(null, other)) return false; if (ReferenceEquals(this, other)) return true; return Equals(other.Host, Host) && Equals(other.DataBase, DataBase) && Equals(other.User, User); } public override int GetHashCode() { unchecked { int result = (Host != null ? Host.GetHashCode() : 0); result = (result*397) ^ (DataBase != null ? DataBase.GetHashCode() : 0); result = (result*397) ^ (User != null ? User.GetHashCode() : 0); return result; } } } } And the following is the exception I am getting: Execute System.InvalidCastException: Unable to cast object of type 'System.Object[]' to type 'TGS.MySQL.DataBaseObjects.DataBasePrivilegePrimaryKey'. at (Object , GetterCallback ) at NHibernate.Bytecode.Lightweight.AccessOptimizer.GetPropertyValues(Object target) at NHibernate.Tuple.Component.PocoComponentTuplizer.GetPropertyValues(Object component) at NHibernate.Type.ComponentType.GetPropertyValues(Object component, EntityMode entityMode) at NHibernate.Type.ComponentType.GetHashCode(Object x, EntityMode entityMode) at NHibernate.Type.ComponentType.GetHashCode(Object x, EntityMode entityMode, ISessionFactoryImplementor factory) at NHibernate.Engine.EntityKey.GenerateHashCode() at NHibernate.Engine.EntityKey..ctor(Object identifier, String rootEntityName, String entityName, IType identifierType, Boolean batchLoadable, ISessionFactoryImplementor factory, EntityMode entityMode) at NHibernate.Engine.EntityKey..ctor(Object id, IEntityPersister persister, EntityMode entityMode) at NHibernate.Event.Default.DefaultLoadEventListener.OnLoad(LoadEvent event, LoadType loadType) at NHibernate.Impl.SessionImpl.FireLoad(LoadEvent event, LoadType loadType) at NHibernate.Impl.SessionImpl.Get(String entityName, Object id) at NHibernate.Impl.SessionImpl.Get(Type entityClass, Object id) at NHibernate.Impl.SessionImpl.Get[T](Object id) at TGS.MySQL.DataBase.DataProvider.GetDatabasePrivilegeByHostDbUser(String host, String db, String user) in C:\Documents and Settings\Michal\My Documents\Visual Studio 2008\Projects\TGS\TGS.MySQL.DataBase\DataProvider.cs:line 20 at TGS.UserAccountControl.UserAccountManager.GetDatabasePrivilegeByHostDbUser(String host, String db, String user) in C:\Documents and Settings\Michal\My Documents\Visual Studio 2008\Projects\TGS\TGS.UserAccountControl\UserAccountManager.cs:line 10 at TGS.UserAccountControlTest.UserAccountManagerTest.CanGetDataBasePrivilegeByHostDbUser() in C:\Documents and Settings\Michal\My Documents\Visual Studio 2008\Projects\TGS\TGS.UserAccountControlTest\UserAccountManagerTest.cs:line 12 I am new to NHibernate and any help would be appreciated. I just can't see where it is getting the object[] from? Is the composite key supposed to be object[]?

    Read the article

  • SQL queries break our game! (Back-end server is at capacity)

    - by TimH
    We have a Facebook game that stores all persistent data in a MySQL database that is running on a large Amazon RDS instance. One of our tables is 2GB in size. If I run any queries on that table that take more than a couple of seconds, any SQL actions performed by our game will fail with the error: HTTP/1.1 503 Service Unavailable: Back-end server is at capacity This obviously brings down our game! I've monitored CPU usage on the RDS instance during these periods, and though it does spike, it doesn't go much over 50%. Previously we were on a smaller instance size and it did hit 100%, so I'd hoped just throwing more CPU capacity at the problem would solve it. I now think it's an issue with the number of open connections. However, I've only been working with SQL for 8 months or so, so I'm no expert on MySQL configuration. Is there perhaps some configuration setting I can change to prevent these queries from overloading the server, or should I just not be running them whilst our game is up? I'm using MySQL Workbench to run the queries. Here's an example.... SELECT * FROM BlueBoxEngineDB.Transfer WHERE Amount = 1000 AND FromUserId = 4 AND Status='Complete'; As you can see, it's not overly complex. There are only 5 columns in the table. Any help would be very much appreciated - Thanks!

    Read the article

  • Using Teleriks new LINQ implementation to connect to MySQL

    Last week Telerik released a new LINQ implementation that is simple to use and produces domain models very fast. Built on top of the enterprise grade OpenAccess ORM, you can connect to any database that OpenAccess can connect to such as: SQL Server, MySQL, Oracle, SQL Azure, VistaDB, etc. Today I will show you how to build a domain model using MySQL as your back end. To get started, you have to download MySQL 5.x and the MySQL Workbench and also, as my colleague Alexander Filipov at Telerik reminded me, make sure you install the MySQL .NET Connector, which is available here.  I like to use Northwind, ok it gives me the warm and fuzzies, so I ran a script to produce Northwind on my MySQL server. There are many ways you can get Northwind on your MySQL database, here is a helpful blog to get your started. I also manipulated the first record to indicate that I am in MySQL and gave a look via the MySQL Workbench. Ok, time to build our model! Start up the Domain Model wizard by right clicking on the project in Visual Studio (I have a Web project) and select Add|New Item and choose Telerik OpenAccess Domain Model from the new item list. When the wizard comes up, choose MySQL as your back end and enter in the name of your saved MySQL connection. If you dont have a saved MySQL connection set up in Visual Studio, click on New Connection and enter in the proper connection information. *Note, this is where you need to have the MySQL .NET connector installed. After you set your connection to the MySQL database server, you have to choose which tables to include in your model. Just for fun, I will choose all of them. Give your model a name, like NorthwindEntities and click finish. That is it. Now lets consume the model with ASP .net. I created a simple page that also has a GridView on it. On my page load I wrote this code, by now it should look very familiar, a simple LINQ query filtering customers by country (Germany) and binding the results to the grid.  1: protected void Page_Load(object sender, EventArgs e) 2: { 3: if (!IsPostBack) 4: { 5: //a reference to the data context 6: NorthwindEntities dat = new NorthwindEntities(); 7: //LINQ Statement 8: var result = from c in dat.Customers 9: where c.Country == "Germany" 10: select c; 11: //Databinding to the Gridview 12: GridView1.DataSource = result; 13: GridView1.DataBind(); 14: } 15: } .csharpcode, .csharpcode pre{ font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/}.csharpcode pre { margin: 0em; }.csharpcode .rem { color: #008000; }.csharpcode .kwrd { color: #0000ff; }.csharpcode .str { color: #006080; }.csharpcode .op { color: #0000c0; }.csharpcode .preproc { color: #cc6633; }.csharpcode .asp { background-color: #ffff00; }.csharpcode .html { color: #800000; }.csharpcode .attr { color: #ff0000; }.csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em;}.csharpcode .lnum { color: #606060; } F5 produces the following. Tomorrow Ill show how to take the same model and create an Astoria/OData data feed. Technorati Tags: MySQL Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • MySQL error: Can't find symbol '_mysql_plugin_interface_version_' in library

    - by Josh Smith
    The boring, necessary details: I'm on Snow Leopard running MySQL locally. I'm trying to install the Sphinx engine for MySQL like so: mysql> install plugin sphinx soname 'sphinx.so'; ERROR 1127 (HY000): Can't find symbol '_mysql_plugin_interface_version_' in library I've Googled everywhere and can't seem to find an actual solution to this problem. For example this issue on the Sphinx forums seems unresolved. Someone else also raised this issue with similar results. The first post linked to an O'Reilly article which says: There is a common problem that might occur at this point: ERROR 1127 (HY000): Can't find symbol '_mysql_plugin_interface_version_' in library If you see a message like this, it is likely that you forgot to include the -DMYSQL_DYNAMIC_PLUGIN option when compiling the plugin. Adding this option to the g++ compile line is required to create a dynamically loadable plug-in. But the article ends on that point; I have no idea what this means or how to resolve the issue.

    Read the article

  • MySQL Daemon failed to start.

    - by matthewsteiner
    There were no updates when I ran yum update. I was trying to install php-soap (which was failing), and online I found I should run this: wget -q -O - http://www.atomicorp.com/installers/atomic.sh |sh After running that, then "yum install php-soap" ran successfuly. Then I ran yum update just to check for updates and said yes for some packages. I noticed there were some mysql ones and such. Now mysql isn't running anymore and it won't let me start it (I get "MySQL Daemon failed to start") Ideas?

    Read the article

  • mysql UDF : fopen = permission denied

    - by lindenb
    Hi All, this is question I already asked on SO but I wonder if this could be a SysAdmin problem. I'm trying to create a mysql UDF function , this function calls "fopen/fclose" to read a flat file stored in /data. But using errno (yes, I know it is bad in a MT program...) I can see that the function cannot open my file: "Permission denied" I tried to do a chmod -R 755 /data (as well as 777, chown -R mysql:mysql /data etc...) but it didn't change anything. when I copied the flat file to /tmp : OK, my UDF was able to 'fopen' the file. I'm puzzled. currently , I've got: drwxrwxrwx 4 pierre root 4096 2010-05-26 16:51 /data drwxrwxrwx 3 pierre root 4096 2010-05-18 09:41 /data/dir1 drwxrwxrwx 3 pierre root 4096 2010-05-18 09:41 /data/dir1/dir2 drwxrwxrwx 4 pierre root 4096 2010-05-18 10:27 /data/dir1/dir2/dir3 -rw-r--r-- 1 pierre root 50685268 2005-12-10 00:01 /data/dir1/dir2/dir3/myfile.txt Any idea ?

    Read the article

  • Mysql out of disk space

    - by Paddy
    I have just finished developing a rails app which has a mysql db as a backend. The app is meant for high traffic and will store lots of information. I am planning to set up my own web server and host the site from it. If in future my disk space runs out i would want to expand by adding more space. But say if my mysql database is housed in my /disk0s1 and by adding a new drive i have more partitions (and hence more disk space), how then would i extend my database to store information on those partitions too, and at the same time prevent any information from being written on the original partition. Should i go for multiple databases? if so how? If i went for a hosting solution i wouldn't be bothering about this as i would just have to worry about making payments for the extra space :) I always wondered how space is added on-the-go by these webhosts. Is there any specific mysql configuration that i have to make?

    Read the article

  • Giving a normal user and Mysql access to a common directory

    - by James R
    We need a common directory where Mysql can do a SELECT INTO OUTFILE and then the file can be picked up by a virtual server user in /home/theuser and worked on. I can perform the SELECT INTO OUTFILE into the /tmp/ dir but theuser does not have access here. Would it be ok to grant the user access to tmp or is that bad practice? The other option I looked at was creating a group 'theusermysql' containing the mysql user and theuser. I set the group on the tree /home/theuser/thedumpfolder and gave write permissions on thedumpfolder, but for some reason mysql still complains that it cannot write here. I'm completely stumped! What would be the best practice way to have a common folder for these two users?

    Read the article

  • How to setup separate MySQL and PHP VPS servers

    - by Fazal
    Someone recommended I should have my MySQL server separate from my Apache/PHP server in case of hacking and such. By visiting linode, slicehost and various articles here on serverfault I've managed to cobble together a decent set of instructions on how to do the Apache/PHP bit. I'm using Rackspace VPS and they provide an internal IP for each server. If I setup a MySQL VPS, should I assume that I would just add the internal IP for the database host? And I guess that I would only need to open up my default ssh port and mysql ports and install phpmyadmin on there? Ideally I would have webserver.mydomain.com and dbserver.mydomain.com (two 256mb VPS's) with servermin on webserver.mydomain.com and phpmyadmin on dbserver.mydomain.com. If anyone has any guides or advice on how to setup this type of solution I'd be more then grateful!

    Read the article

  • What are some hosted MySQL solutions?

    - by bigmac
    I would like to host a MySQL database somewhere. The basic solution would be to get a VPS, but then I am stuck doing all the sysadmin stuff. It's not terribly difficult if you are not doing anything fancy, but if something goes wrong (like a security breach), it may be hard to resolve or even diagnose in the first place. On the other end of the spectrum, I found Xeround and Amazon RDS. Xeround is not exactly standard MySQL. Amazon seems a bit complex to get started (which is weird because they specifically say it is "simple to deploy"). Why is there nothing in the middle? Is there no demand for a basic hosted MySQL solution?

    Read the article

< Previous Page | 46 47 48 49 50 51 52 53 54 55 56 57  | Next Page >