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  • updating a table conditionally with values from a group by sub query in oracle

    - by user333147
    the problem is Update the salary of all the employees by 50% who had worked on 5 or more than 5 projects, by 30% (= 3 projects), by 20 % (= 1 projects) the number of project is got by performing a group by query on the EMPLOYEE_PROJECT_HISTORY; i have tried these queries 1) update emp set emp.sal= case when jemp.pcount >=5 then emp.sal+ (emp.sal*50)/100 when jemp.pcount >=3 then emp.sal+ (emp.sal*30)/100 when jemp.pcount >=1 then emp.sal+ (emp.sal*20)/100 else emp.sal+ (emp.sal*20)/100 end from employee emp join (select empno as jempno,count(projectno) as pcount from EMPLOYEE_PROJECT_HISTORY by empno) jemp on emp.empno=jemp.jempno ; 2)update employee a set a.sal= case (select count(b.projectno) as pcount from EMPLOYEE_PROJECT_HISTORY b group by b.empno ) when b.pcount >5 then a.sal = a.sal+ (a.sal*50)/100 when pcount >3 then a.sal = a.sal+ (a.sal*30)/100 when pcount >1 then a.sal = a.sal+ (a.sal*20)/100 end;

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  • Aggregate Functions and Group By Problems

    - by David Stein
    If we start with the following simple SQL statement which works. SELECT sor.FPARTNO, sum(sor.FUNETPRICE) FROM sorels sor GROUP BY sor.FPARTNO FPartNo is the part number and the Funetprice is obviously the net price. The user also wants the description and this causes a problem. If I follow up with this: SELECT sor.FPARTNO, sor.fdesc, sum(sor.FUNETPRICE) FROM sorels sor GROUP BY sor.FPARTNO, sor.fdesc If there are multiple variations of the description for that part number, typically very small variations in the text, then I don't actually aggregate on the part number. Make sense? I'm sure this must be simple. How can I return the first fdesc that corresponds to the part number? Any of the description variations would suffice as they are almost entirely identical. Edit: The description is a text field.

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  • Group MySQL Data into Arbitrarily Sized Time Buckets

    - by Eric J.
    How do I count the number of records in a MySQL table based on a timestamp column per unit of time where the unit of time is arbitrary? Specifically, I want to count how many record's timestamps fell into 15 minute buckets during a given interval. I understand how to do this in buckets of 1 second, 1 minute, 1 hour, 1 day etc. using MySQL date functions, e.g. SELECT YEAR(datefield) Y, MONTH(datefield) M, DAY(datefield) D, COUNT(*) Cnt FROM mytable GROUP BY YEAR(datefield), MONTH(datefield), DAY(datefield) but how can I group by 15 minute buckets?

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  • SQL Group By equivalent

    - by MikeB
    Pretend I have a cupcake_rating table: id | cupcake | delicious_rating -------------------------------------------- 1 | Strawberry | Super Delicious 2 | Strawberry | Mouth Heaven 3 | Blueberry | Godly 4 | Blueberry | Super Delicious I want to find all the cupcakes that have a 'Super Delicious' AND 'Mouth Heaven' rating. I feel like this is easily achievable using a group by clause and maybe a having. I was thinking: select distinct(cupcake) from cupcake_rating group by cupcake having delicious_rating in ('Super Delicious', 'Mouth Heaven') I know I can't have two separate AND statements. I was able to achieve my goal using: select distinct(cupcake) from cupcake_rating where cupcake in ( select cupcake from cupcake_rating where delicious_rating = 'Super Delicious' ) and cupcake in ( select cupcake from cupcake_rating where delicious_rating = 'Mouth Heaven' ) This will not be satisfactory because once I add a third type of rating I am looking for, the query will take hours (there are a lot of cupcake ratings).

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  • LINQ to sql return group by results from method

    - by petebob796
    How do I create a method to return the results of a group by in LINQ to sql such as the one below: internal SomeTypeIDontKnow GetDivisionsList(string year) { var divisions = from p in db.cm_SDPs where p.acad_period == year group p by new { p.Division } into g select new { g.Key.Division }; return divisions; } I can't seem to define a correct return type. I think it is because it's an anonymous type but haven't got my head around it yet. Do I need to convert it to a list or something? The results would just be used for filling a combo box.

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  • xcodeproj merge fails when adding new group

    - by user1473113
    I'm currently using Xcode with Git, and I'm experiencing some troubles during the merge process of my xcodeproj. Developer1 create a new group in Xcode file arborescence the commit and push. Developer2 on an other computer do the same with an other group name, commit and pull(with merge). The xcodeproj of Developer 2 become unreadable with Xcode. But when I create a new file or just drag and drop files from finder to repository, the merge succeed. Did someone has experienced that kind of trouble? I'm using in .gitattributes: *.pbxproj -crlf -diff merge=union # Better to treat them as binary files. *.pbxuser -crlf -diff -merge *.xib -crlf -diff -merge and in my .gitignore # Mac OS X *.DS_Store *~ # Xcode *.mode1v3 *.mode2v3 *.perspectivev3 *.xcuserstate project.xcworkspace/ xcuserdata/ *.xcodeproj/* !*.xcodeproj/project.pbxproj !*.xcodeproj/*.pbxuser # Generated files *.o *.pyc *.hi #Python modules MANIFEST dist/ build/ # Backup files *~.nib \#*# .#*

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  • Elegant PostgreSQL Group by for Ruby on Rails / ActiveRecord

    - by digitalfrost
    Trying to retrieve an array of ActiveRecord Objects grouped by date with PostgreSQL. More specifically I'm trying to translate the following MySQL querry: @posts = Post.all(:group => "date(date)", :conditions => ["location_id = ? and published = ?", @location.id, true], :order => "created_at DESC") I am aware that PostgreSQL interpretation of the SQL standard is stricter than MySQL and that consequently this type of query won't work...and have read a number of posts on StackOverflow and elsewhere on the subject - but none of them seem to be the definitive answer on this subject I've tried various combinations of queries with group by and distinct clauses without much joy - and for the moment I have a rather inelegant hack which although works makes me blush when I look at it. What is the proper way to make such a querry with Rails and PostgreSQL ? (Ignoring the fact that surely this should be abstracted away at the ActiveRecord Level)

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  • group by with 3 diffrent

    - by NN
    I have 2 table and I wanna a query with 3 column result in on of them 2 column with view count and title name and in the other 1 column with type_ and i wanna to grouping type_ with max(view count) and show the them title but i didn't have any idea about grouping expression. i think we can solve in by using sub query but i don't know which column use in group by. 2 table join with this expression class pk=resource key i exam this query: SELECT t.title,j.type_ FROM tags asset t,journal article j where type_ in (select type_ from journal article,tags asset where class pk=resource key group by type_) but the answer was wrong

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  • Get the checked value of 2 sets of radiobuttons using jQuery

    - by Hans Wassink
    Im having a weird issue here. Its probably just something stupid but I dont see it. I have two sets of radiobuttons, group1 and group2, and I want to get their values in a function. I have 1 clickevent on all radiobuttons in that div and when I click them I want to display the check-values of both groups. But he only reads the value of the first group. and so it always displays 1-1 2-2 3-3 4-4 instead of possibly 1-2 3-1 etc.... There is a jsfiddle here what am I missing??

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  • MySQL LEFT JOIN, GROUP BY and ORDER BY not working as required

    - by Simon
    I have a table 'products' => ('product_id', 'name', 'description') and a table 'product_price' => ('product_price_id', 'product_id', 'price', 'date_updated') I want to perform a query something like SELECT `p`.*, `pp`.`price` FROM `products` `p` LEFT JOIN `product_price` `pp` ON `pp`.`product_id` = `p`.`product_id` GROUP BY `p`.`product_id` ORDER BY `pp`.`date_updated` DESC As you can probably guess the price changes often and I need to pull out the latest one. The trouble is I cannot work out how to order the LEFT JOINed table. I tried using some of the GROUP BY functions like MAX() but that would only pull out the column not the row. Thanks.

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  • How do I use SPMemember.ID property to get User or Group

    - by Jason
    I have to write a utility to enumerate and manage the owners of groups within a SharePoint site. I know I can use the Groups property of the SPWeb object to retrieve a collection of groups. And I know I can use the Owner property of the group to get back the owner. My problem is that I do not know what to do next. The SPGroup.Owner property returns a SPMember object. The member object has one property called ID that returns the unique ID (an integer) of the member. What I cannot seem to find information on is how to use that integer value to determine if the member is a User or a Group and how to get back additional details (say the name). Any ideas? Thanks.

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  • GROUP BY and SUM distinct date across 2 tables

    - by kenitech
    I'm not sure if this is possible in one mysql query so I might just combine the results via php. I have 2 tables: 'users' and 'billing' I'm trying to group summed activity for every date that is available in these two tables. 'users' is not historical data but 'billing' contains a record for each transaction. In this example I am showing a user's status which I'd like to sum for created date and deposit amounts that I would also like to sum by created date. I realize there is a bit of a disconnect between the data but I'd like to some all of it together and display it as seen below. This will show me an overview of all of the users by when they were created and what the current statuses are next to total transactions. I've tried UNION as well as LEFT JOIN but I can't seem to get either to work. Union example is pretty close but doesn't combine the dates into one row. ( SELECT created, SUM(status) as totalActive, NULL as totalDeposit FROM users GROUP BY created ) UNION ( SELECT created, NULL as totalActive, SUM(transactionAmount) as totalDeposit FROM billing GROUP BY created ) I've also tried using a date lookup table and joining on the dates but the SUM values are being added multiple times. note: I don't care about the userIds at all but have it in here for the example. users table (where status of '1' denotes "active") (one record for each user) created | userId | status 2010-03-01 | 10 | 0 2010-03-01 | 11 | 1 2010-03-01 | 12 | 1 2010-03-10 | 13 | 0 2010-03-12 | 14 | 1 2010-03-12 | 15 | 1 2010-03-13 | 16 | 0 2010-03-15 | 17 | 1 billing table (record created for every instance of a billing "transaction" created | userId | transactionAmount 2010-03-01 | 10 | 50 2010-03-01 | 18 | 50 2010-03-01 | 19 | 100 2010-03-10 | 89 | 55 2010-03-15 | 16 | 50 2010-03-15 | 12 | 90 2010-03-22 | 99 | 150 desired result: created | sumStatusActive | sumStatusInactive | sumTransactions 2010-03-01 | 2 | 1 | 200 2010-03-10 | 0 | 1 | 55 2010-03-12 | 2 | 0 | 0 2010-03-13 | 0 | 0 | 0 2010-03-15 | 1 | 0 | 140 2010-03-22 | 0 | 0 | 150 Table dump: CREATE TABLE IF NOT EXISTS `users` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `status` smallint(6) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `users` (`created`, `userId`, `status`) VALUES ('2010-03-01', 10, 0), ('2010-03-01', 11, 1), ('2010-03-01', 12, 1), ('2010-03-10', 13, 0), ('2010-03-12', 14, 1), ('2010-03-12', 15, 1), ('2010-03-13', 16, 0), ('2010-03-15', 17, 1); CREATE TABLE IF NOT EXISTS `billing` ( `created` date NOT NULL, `userId` int(11) NOT NULL, `transactionAmount` int(11) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `billing` (`created`, `userId`, `transactionAmount`) VALUES ('2010-03-01', 10, 50), ('2010-03-01', 18, 50), ('2010-03-01', 19, 100), ('2010-03-10', 89, 55), ('2010-03-15', 16, 50), ('2010-03-15', 12, 90), ('2010-03-22', 99, 150);

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  • MySQL returns fewer rows with GROUP BY statement

    - by bschaeffer
    I've got a MySQL database that stores image information. Right now it only has three rows stored in the database, and each row is associated with something like, for instance, a unique blog post via a key column. As of right now, one "blog post key" has one image, and one has two images in the database. When I run this query, MySQL returns all three rows. SELECT `id`, `key`, `url` FROM (`images`) WHERE `key` = 'TpaS4G5h' OR `key` = '78855e44' However, when i add the GROUP BY statement I only get two rows... one for each key. SELECT `id`, `key`, `url` FROM (`images`) WHERE `key` = 'TpaS4G5h' OR `key` = '78855e44' GROUP BY `key` I'm sure there is a simple solution, but I don't know what it is... so any help would be really appreciated. Thanks in advance!

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  • Query returning an ascending group number

    - by Dougman
    I have a query like below that has groups (COL1) and that group's values (COL2). select col1, col2 from (select 'A' col1, 1 col2 from dual union all select 'A' col1, 2 col2 from dual union all select 'B' col1, 1 col2 from dual union all select 'B' col1, 2 col2 from dual union all select 'C' col1, 1 col2 from dual union all select 'C' col1, 2 col2 from dual ) order by col1, col2; The output of this query looks like: COL1 COL2 ---- ---- A 1 A 2 B 1 B 2 C 1 C 2 What I need is a query that will return an ordered number increasing for each different group (COL1). It seems like there would be a simple way to accomplish this (maybe with analytics) but for some reason it is escaping me. GRPNUM COL1 COL2 ------ ---- ---- 1 A 1 1 A 2 2 B 1 2 B 2 3 C 1 3 C 2 I am running Oracle 10gR2.

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  • MySQL, PHP, How Many in GROUP

    - by 0Neji
    I'm trying to create a table which outputs a list of users and how many times they've logged in. A new row in the table is created every time that someone logs in so there is multiple rows for one user. Now, I'm trying using the following statement to pull the data out: SELECT * FROM logins GROUP BY user ORDER BY timestamp DESC Which is working fine but now there is a column in my HTML table which should show how many times the user has logged in. How do I go about counting the amount of rows in each group?

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  • How can I disable the "Do you want to allow this website to open a program on your computer?" warnin

    - by serialhobbyist
    I've been playing with new URL monikers in Windows for a utility I'm working on. When I run the new URL from Start Run, it just runs. If I send the URL to myself via Notes or enter it into the IE address bar, I get a window which says: "Do you want to allow this website to open a program on your computer?" Program: UrlMonikerTest1 Address: urltest://ticket?param1=42&param2=Derf [CheckBox] Always ask before opening this type of address [Button] Allow [Button] Cancel Allowing web content to open a program can be useful, but it can potentially harm your computer. Do not allow it unless you trust the source of the content. What's the risk? Given that the utility will only run on internal machines to which it will be deployed using SCCM and to which I can apply Group Policy, can I disable this message for this application/URL moniker alone? The clients are currently XP. They will be Win7 at some point. We don't have to consider Vista.

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  • Enabling WinRM by Group Policy

    - by SaintNick
    I'm having partial success enabling WinRM through Active Directory GPO's on our Server 2008 R2 environment. I've created a GPO that enables "Allow automatic configuration of listeners" and also enables all the necessary predefined WinRM Firewall rules. This GPO works fine for our webservers. Indeed, this is reflected by the "Server Manager Remote Management" nicely flipping to "enabled" in Server Manager Server Summary. However, the same GPO applied to both our Management servers, which are Domain Controllers, does not give the same result. I see the GPO settings being applied, including the listener as confirmed by C:\Windows\system32>winrm e winrm/config/listener Listener [Source="GPO"] Address = * Transport = HTTP Port = 5985 Hostname Enabled = true URLPrefix = wsman CertificateThumbprint ListeningOn = 10.32.40.210, 10.32.40.211, 10.32.40.212 But in Server Manager, Server Summary, Remote Management remains on "disabled" and indeed when trying to connect to one of these machines Server Manager gives an "Access Denied". Manually enabling WinRM locally via Server Manager "Configure Server Manager Remote Management" on either of these machines works fine. What can be the cause? Can it have something to do with theses machines being DC's and needing extra settings in the GPO? Nick Reid

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  • Windows 7 Group Policy to display message for login tries left before account lock

    - by Vivek
    My requirement is to display the the remaining count left on the login screen when user trying to login using Windows 7 OS before account lock in case user enter invalid password. I am having Active Directory on Windows 2008 R2 server. I set the maximum Lockout count = 5 in GPO policy. Example: If user try login first 1 attempt is failed, next time enter password and login shold show message for remaining attemps left.( my case count 4 left) Please let me know as this is urgent for me.

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  • Email attachments sent to a group don't show up for some

    - by blsub6
    My boss sent out an email from my Exchange 2010 org and attached a PDF and a Word doc to it. He came back the next day and told me that some of the 8 or 10 people that received this email could open up the attachments no problem. The other 2 or 3 people, could not. One of these people who could not open the attachment, went so far as to call Comcast (his email service provider) and ask them where his attachments went. Comcast told this person that when they received the email, the attachment was 0 bytes in size. This may sound like more of a rant than a question but I'm genuinely concerned. Is there any possible way that something could have gone wrong on my end that sent out the email to some with the attachment and to some without?

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  • Plone Active Directory group filter

    - by Jason Weber
    I am currently trying to configure the Plone LDAP plugin for Active directory. Thus far all is good and I’m getting users and groups through. The usage is for Cyn.In However the problem I’m facing is thus: The users search has the ability to filter, which is great. I can use the memberOf or department filter to just grab the users I want. However all our groups simply live in one OU, which means I’m getting over 30 pages of groups of which 99% are just not necessary. Sadly I don’t have control over our AD, so can’t just shift the ones I want into their own OU. Is there any way you can think of to also filter groups based on some kind of LDAP criteria?

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  • The Cindy Shearin Group: New Scam Targets Renters in the Area

    - by user226089
    MONROE - Craigslist is a popular site when trying to find that perfect deal on a rental home or apartment. Experts warn some of these rental ads aren't what they seem. We decided to take a look. On our Craigslist search we found this house for rent. The problem is this home’s not for rent - it's for sale. “I think it’s a huge deal,” said Shane Wooten, the realtor for this home in Monroe. His properties have become the target of a common scam, aimed at taking your money. "It looks like they're trying to scam them out of their deposit and first months rent," adds Wooten. He says scammers copy and paste the sale ad's from legitimate realtor sites to Craigslist as rental ads. "I can usually tell when one hits craigslist because I’ll usually get 20 to 30 phone calls that day." They then pretend to be out of town on business or personal matters, and give only an email address as a point of contact. Usually they'll ask for money up front on a deal too good to miss. "You'll have a house that's supposed to rent for $950-1000 a month, and they'll have it renting for $600 a month,” says Wooten During our conversation, he shows us text messages from one scammer who says he'll mail the keys to this house if Wooten wires money for a deposit and first months rent. Jo Ann Deal of the Better Business Bureau says scammers are getting better at making themselves out to be realtors. "We’re really concerned for our real estate agents with this scam," says Deal. She says that realtors have to be more on top of their vacant homes in order to protect their businesses. So how can you tell if the house you want is really for rent? She says if the home owner lives out of the country, can't meet face to face or asks for a payment through a money wire it's probably a scam. “There are some catch-lines you watch for,” says Deal. “If the marketing is really good but there's no phone number, no physical address and they will communicate with you only by email and you can do it today, then it's probably a scam." You should always report fishy ad's to Craigslist or the BBB and never send money through a wire transfer.

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