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  • Converting a certain SQL query into relational algebra

    - by Fumler
    Just doing an assignment for my database course and I just want to double check that I've correctly wrapped my head around relational algebra. The SQL query: SELECT dato, SUM(pris*antall) AS total FROM produkt, ordre WHERE ordre.varenr = produkt.varenr GROUP BY dato HAVING total >= 10000 The relational algebra: stotal >= 10000( ?R(dato, total)( sordre.varenr = produkt.varenr( datoISUM(pris*antall(produkt x ordre)))) Is this the correct way of doing it?

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  • Which is faster??

    - by kaki
    is opening a large file once reading it completely once to list faster (or) opening smaller files whose total sum of size is equal to large file and loading smaller file into list manupalating one by one faster? which is faster?? is the difference is time large enough to impact my program?? total time difference of lesser then of 30 sec is negligible for me

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  • Parameter has no walue

    - by Simon
    string queryString = "SELECT SUM(skupaj_kalorij)as Skupaj_Kalorij " + "FROM (obroki_save LEFT JOIN users ON obroki_save.ID_uporabnika=users.ID)" + "WHERE users.ID= " + a.ToString() + " AND obroki_save.datum =?"; using (OleDbCommand cmd = new OleDbCommand(queryString,database)) { cmd.Parameters.Add("@datum", OleDbType.Char).Value = DateTime.Now.ToShortDateString(); } Why doesn't the parametr datum get the date value? (the value of at least one complex parameter has not been determined )

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  • libXcodeDebuggerSupport.dylib is missing in iOS 4.2.1 development SDK

    - by Kalle
    Note: creating a symbolic link to use the 4.2 lib seems to work fine -- maybe cd /Developer/Platforms/iPhoneOS.platform/DeviceSupport/4.2.1\ \(8C148\)/Symbols/ sudo ln -s ../../4.2 (8C134)/Symbols/Developer Request: See end of this question! After upgrading from 4.2.0 (beta, I believe) to 4.2.1, the libXcodeDebuggerSupport.dylib file is missing, which results in: warning: Unable to read symbols for /Developer/Platforms/iPhoneOS.platform/DeviceSupport/4.2.1 (8C148)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib (file not found). which I guess isn't good. Looking at the directory in question I note: .../DeviceSupport/4.2 (8C134)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib but .../DeviceSupport/4.2.1 (8C148)/Symbols/System/ .../DeviceSupport/4.2.1 (8C148)/Symbols/usr/ the above two dirs make up all the content in the 4.2.1 folder. No "Developer" folder. Checking the /usr/ dir there, I find no libXcodeDebuggerSupport.dylib file in the lib dir either, so ln -s'ing isn't an option. Worth mentioning: after the upgrade, I plugged the iPad in and had to click "Use for development" in Xcode organizer. Doing so, I got a message about symbols missing for that version, and Xcode proceeded to generate such, then failed. I restored the iPad and did "Use for development" again, and nothing about missing symbols appeared... Update: deletion of /Developer and reinstallation of Xcode from scratch does not fix this issue. Update 2: I just realized that after the reinstall of Xcode, .../DeviceSupport/4.2 (8C134)/Symbols is now a symbolic link, lrwxr-xr-x 1 root admin 36 Dec 3 17:17 Symbols -> ../../Developer/SDKs/iPhoneOS4.2.sdk And the directory in question has the appropriate files. Maybe this is simply a matter of linking the 4.2.1 dir in the same fashion? I'll try that and see if Xcode freaks out. If someone who has this file could provide a md5 sum that would be splendid. This is what it says for me: $ md5 /Developer/Platforms/iPhoneOS.platform/DeviceSupport/4.2\ \(8C134\)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib MD5 (/Developer/Platforms/iPhoneOS.platform/DeviceSupport/4.2 (8C134)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib) = 08f93a0a2e3b03feaae732691f112688 If the MD5 sum is identical to the output of $ md5 /Developer/Platforms/iPhoneOS.platform/DeviceSupport/4.2.1\ \(8C148\)/Symbols/Developer/usr/lib/libXcodeDebuggerSupport.dylib then we're all set.

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  • SEC_TO_TIME() convert to java.sql.Time error

    - by chun
    hi I have a aggregate column present the microsecond, a report(with jasper) have to show HH:mm:ss of this indicator What I did is using SEC_TO_TIME(sum(col)/1000) , but when mapping to java.sql.Time, i doesn't work when the value of hour in result pass over 24(ex:36:33:33) Then I think another way, not using sec_to_time, just mapping the microsecond as Bigdecimal, but dunno what java class shoud i use to format date as the default format of hh:mm:ss is limit to 24...?

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  • Group By Multiple Columns - LINQ

    - by Nev_Rahd
    How can I do GroupBy Multiple Columns in LINQ Something as in SQL : SELECT * FROM <TableName> GROUP BY <Column1>,<Column2> How Can i convert below to LINQ QuantityBreakdown ( MaterialID int, ProductID int, Quantity float ) INSERT INTO @QuantityBreakdown (MaterialID, ProductID, Quantity) SELECT MaterialID, ProductID, SUM(Quantity) FROM @Transactions GROUP BY MaterialID, ProductID Thanks

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  • Is there any way to achieve multiple inheritance in php?

    - by Starx
    Lets say I have a parent class class parent { } ..... This parent has three sub class class child1 { } class child2 { } class child3 { } and these child classes have further smaller parts like class child1subpar1 { } class child1subpar2 { public function foo() { echo "hi"; } } class child2subpar1 { } class child2subpar2 { } Now, how to sum this whole up like class child1 extends child1subpar1, child1subpar2 { } class child2 extends child2subpar1, childsubpar1 { } class parent extends child1,child2,child3 { } I need to execute the methods in its inherited classes and do something like this $objparent = new parent; $objparent - foo();

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  • MySQL subqueries

    - by swamprunner7
    Can we do this query without subqueries? SELECT login, post_n, (SELECT SUM(vote) FROM votes WHERE votes.post_n=posts.post_n)AS votes, (SELECT COUNT(comments.post_n) FROM comments WHERE comments.post_n=posts.post_n)AS comments_count FROM users, posts WHERE posts.id=users.id AND (visibility=2 OR visibility=3) ORDER BY date DESC LIMIT 0, 15 tables: Users: id, login Posts: post_n, id, visibility Votes: post_n, vote id — it`s user id, Users the main table.

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  • How to maintain decimal percision in calculations

    - by Blankman
    I need to sum 2 decimal values together, then divide by 2 and convert to string. My calculation currently is trimming to 2 decimal places, but I want to keep as many decimals as I can. city.Latitude = ( (lat.North + lat.South) / 2 ).ToString(); the values for lat.North and lat.Souch are like: 55.32342322

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  • How to maintain decimal precision in calculations

    - by Blankman
    I need to sum 2 decimal values together, then divide by 2 and convert to string. My calculation currently is trimming to 2 decimal places, but I want to keep as many decimals as I can. city.Latitude = ( (lat.North + lat.South) / 2 ).ToString(); the values for lat.North and lat.Souch are like: 55.32342322

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  • DB2 Query to Hibernate Criteria

    - by Fortega
    Hi, I have a specific DB2 query, and I would like to execute this query using criteria. The query: SELECT sum(units) as volume, location_id, aged FROM ( SELECT units, location_id, CASE WHEN daysinstock < 61 THEN 'NOT_AGED' WHEN daysinstock < 91 THEN 'AGED' ELSE 'OVER_AGED' END AS AGED FROM STOCK_TABLE ) x group by location_id, aged the STOCK_TABLE contains the following fields: units, location_id, daysinstock. This table is matched by a StockDataSource object, with the same fields.

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  • Django - Can you use property as the field in an aggregation function?

    - by orokusaki
    I know the short answer because I tried it. Is there any way to accomplish this though (even if only on account of a hack)? class Ticket(models.Model): account = modelfields.AccountField() uuid = models.CharField(max_length=36, unique=True) created = models.DateTimeField(auto_now_add=True) class Meta: ordering = ['created'] @property def repair_cost(self): # cost is a @property of LineItem(models.Model) return self.lineitem_set.aggregate(models.Sum('cost'))

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  • Mysql timestamp query

    - by Hulk
    In mysql a result of a query is say select timestamp from newbie; | 2010-03-12 14:50:46 | | 2010-03-12 14:50:46 | | 2010-03-12 14:50:51 | | 2010-03-12 14:50:52 | | 2010-03-12 14:50:54 | | 2010-03-12 14:51:04 | | 2010-03-12 14:51:07 | | 2010-03-12 14:51:08 | Is there a way to subquery the above and sum up the i.e, the final result should be the delta of each row in hh:mm:ss format

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  • Values of generated column not appearing in table

    - by msh210
    I'm using mysql version 5.1.41-3ubuntu12.10 (Ubuntu). mysql> show create table tt\G *************************** 1. row *************************** Table: tt Create Table: CREATE TABLE `tt` ( `pz` int(8) DEFAULT NULL, `os` varchar(8) DEFAULT NULL, `uz` int(11) NOT NULL, `p` bigint(21) NOT NULL DEFAULT '0', `c` decimal(23,0) DEFAULT NULL, KEY `pz` (`pz`), KEY `uz` (`uz`), KEY `os` (`os`), KEY `pz_2` (`pz`,`uz`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 1 row in set (0.00 sec) mysql> select pz,uz,pz*uz, -> if(pz*uz,1,.5), -> left(pz,2) pl,left(lpad(uz,5,0),2) ul, -> p from tt limit 10; +-------+----+-------+----------------+--------+----+--------+ | pz | uz | pz*uz | if(pz*uz,1,.5) | pl | ul | p | +-------+----+-------+----------------+--------+----+--------+ | NULL | 0 | NULL | 0.5 | NULL | 00 | 4080 | | NULL | 0 | NULL | 0.5 | NULL | 00 | 323754 | | 89101 | 0 | 0 | 0.5 | 89 | 00 | 6880 | | 0 | 0 | 0 | 0.5 | 0 | 00 | 11591 | | 89110 | 0 | 0 | 0.5 | 89 | 00 | 72 | | 78247 | 0 | 0 | 0.5 | 78 | 00 | 27 | | 90062 | 0 | 0 | 0.5 | 90 | 00 | 5 | | 63107 | 0 | 0 | 0.5 | 63 | 00 | 4 | | NULL | 0 | NULL | 0.5 | NULL | 00 | 54561 | | 94102 | 0 | 0 | 0.5 | 94 | 00 | 12499 | +-------+----+-------+----------------+--------+----+--------+ So far so good. As you see, 0.5 appears as a value of if(pz*uz,1,.5). The problem is: mysql> select os, -> if(pz*uz,left(pz,2)<=>left(lpad(uz,5,0),2),.5) uptwo, -> if(pz*uz,left(pz,3)<=>left(lpad(uz,5,0),3),.5) upthree, -> sum(p) p,sum(c) c -> from tt t -> group by os,uptwo,upthree order by null; +----+-------+---------+---------+-------+ | os | uptwo | upthree | p | c | +----+-------+---------+---------+-------+ | u | 1 | 1 | 52852 | 318 | | i | 1 | 1 | 7046563 | 21716 | | m | 1 | 1 | 1252166 | 7337 | | i | 0 | 0 | 1830284 | 4033 | | m | 0 | 0 | 294612 | 1714 | | i | 1 | 0 | 911486 | 3560 | | m | 1 | 0 | 145182 | 1136 | | u | 0 | 0 | 12144 | 23 | | u | 1 | 0 | 1571 | 8 | +----+-------+---------+---------+-------+ Although I group by uptwo, 0.5 doesn't appear in that column. What happened to the 0.5 values? Edit: As noted in the comments to Todd Gibson's answer, I also tried it with if(pz*uz,cast(left(pz,2)<=>left(lpad(uz,5,0),2) as decimal),.5) instead of if(pz*uz,left(pz,2)<=>left(lpad(uz,5,0),2),.5), but it, too, didn't work.

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  • Subband decomposition using Daubechies filter

    - by misha
    I have the following two 8-tap filters: h0 ['-0.010597', '0.032883', '0.030841', '-0.187035', '-0.027984', '0.630881', '0.714847', '0.230378'] h1 ['-0.230378', '0.714847', '-0.630881', '-0.027984', '0.187035', '0.030841', '-0.032883', '-0.010597'] Here they are on a graph: I'm using it to obtain the approximation (lower subband of an image). This is a(m,n) in the following diagram: I got the coefficients and diagram from the book Digital Image Processing, 3rd Edition, so I trust that they are correct. The star symbol denotes one dimensional convolution (either over rows or over columns). The down arrow denotes downsampling in one dimension (either over rows, or columns). My problem is that the filter coefficients for h0 and h1 sum to greater than 1 (approximately 1.4 or sqrt(2) to be exact). Naturally, if I convolve any image with the filter, the image will get brighter. Indeed, here's what I get (expected result on right): Can somebody suggest what the problem is here? Why should it work if the convolution filter coefficients sum to greater than 1? I have the source code, but it's quite long so I'm hoping to avoid posting it here. If it's absolutely necessary, I'll put it up later. EDIT What I'm doing is: Decompose into subbands Filter one of the subbands Recompose subbands into original image Note that the point isn't just to have a displayable subband-decomposed image -- I have to be able to perfectly reconstruct the original image from the subbands as well. So if I scale the filtered image in order to compensate for my decomposition filter making the image brighter, this is what I will have to do: Decompose into subbands Apply intensity scaling Filter one of the subbands Apply inverse intensity scaling Recompose subbands into original image Step 2 performs the scaling. This is what @Benjamin is suggesting. The problem is that then step 4 becomes necessary, or the original image will not be properly reconstructed. This longer method will work. However, the textbook explicitly says that no scaling is performed on the approximation subband. Of course, it's possible that the textbook is wrong. However, what's more possible is I'm misunderstanding something about the way this all works -- this is why I'm asking this question.

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  • onchange event is not woking

    - by Jim
    Hello guys, Whats wrong with this code? My first function working fine but second function is not working. Please help me. Thanks function bag1() { var sum = 0; var qty = document.form1.qty.value; var pack = document.form1.pack.value; document.form1.bag.value = (qty*pack)/100; } function bag2() { var sum = 0; var qty = document.form1.qty.value; var pack1 = document.form1.pack1.value; document.form1.bag1.value = (qty*pack1)/100; } Here is HTML code <input id="item1" name="item1" type="text" maxlength="255" value=""/> <input type="text" maxlength="255" value=""/> <input id="weight" name="weight" type="text" maxlength="255" value=""/> <input id="pack" name="pack" type="text" maxlength="255" onchange="bag1();" value=""/> <input id="bag" name="bag" type="text" maxlength="255" value=""/> <input id="rate" name="rate" type="text" maxlength="255" value=""/> <input id="amount" name="amount" type="text" maxlength="255" value=""/> <input id="element_12" name="type" type="text" maxlength="255" value=""/> <input id="element_13" name="brand" type="text" maxlength="255" value=""/> <!-------------------------- Caculating 2th Row ---------------------------------------------------------------> <input type="text" maxlength="255" value=""/> <input type="text" maxlength="255" value=""/> <input id="weight2" name="weight2" type="text" maxlength="255" value=""/> <input id="pack2" name="pack2" type="text" maxlength="255" value=""/> <input id="bag2" name="bag2" type="text" maxlength="255" onchange="bag2();" value=""/> <input id="rate2" name="rate2" type="text" maxlength="255" value=""/> <input id="amount2" name="amount2" type="text" maxlength="255" value=""/> <input id="element_12" name="type" type="text" maxlength="255" value=""/> <input id="element_13" name="brand" type="text" maxlength="255" value=""/> </form type="submit" value="calculator2">

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  • Django Include Aggregate Sums of Zero

    - by tomas
    I'm working on a Django timesheet application and am having trouble figuring out how to include aggregate sums that equal zero. If I do something like: entries = TimeEntry.objects.all().values("user__username").annotate(Sum("hours")) I get all users that have time entries and their sums. [{'username': u'bob' 'hours__sum':49}, {'username': u'jane' 'hours__sum':10}] When I filter that by a given day: filtered_entries = entries.filter(date="2010-05-17") Anyone who didn't enter time for that day is excluded. Is there a way to include those users who's sums are 0? Thanks

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  • what to do with a flawed C++ skills test

    - by Mike Landis
    In the following gcc.gnu.org post, Nathan Myers says that a C++ skills test at SANS Consulting Services contained three errors in nine questions: Looking around, one of fthe first on-line C++ skills tests I ran across was: http://www.geekinterview.com/question_details/13090 I looked at question 1... find(int x,int y) { return ((x<y)?0:(x-y)):} call find(a,find(a,b)) use to find (a) maximum of a,b (b) minimum of a,b (c) positive difference of a,b (d) sum of a,b ... immediately wondering why would anyone write anything so obtuse. Getting past the absurdity, I didn't really like any of the answers, immediately eliminating (a) and (b) because you can get back zero (which is neither a nor b) in a variety of circumstances. Sum or difference seemed more likely, except that you could also get zero regardless of the magnitudes of a and b. So... I put Matlab to work (code below) and found: when either a or b is negative you get zero; when b a you get a; otherwise you get b, so the answer is (b) min(a,b), if a and b are positive, though strictly speaking the answer should be none of the above because there are no range restrictions on either variable. That forces test takers into a dilemma - choose the best available answer and be wrong in 3 of 4 quadrants, or don't answer, leaving the door open to the conclusion that the grader thinks you couldn't figure it out. The solution for test givers is to fix the test, but in the interim, what's the right course of action for test takers? Complain about the questions? function z = findfunc(x,y) for i=1:length(x) if x(i) < y(i) z(i) = 0; else z(i) = x(i) - y(i); end end end function [b,d1,z] = plotstuff() k = 50; a = [-k:1:k]; b = (2*k+1) * rand(length(a),1) - k; d1 = findfunc(a,b); z = findfunc(a,d1); plot( a, b, 'r.', a, d1, 'g-', a, z, 'b-'); end

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  • CRC function without order dependency

    - by Pirks
    I need a CRC mechanism to calculate the CRC of a number of strings, such that, given two strings, A and B, the sum crc(A) + crc(B) == crc(A+B). P.S. XOR is too weak---the algorithm should be not trivial for reverse engineering.

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