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  • Render {embed} for each entry in {exp:weblog:entries} loop

    - by eyelidlessness
    {exp:weblog:entries [args]} [content] {embed="path/to/sub-template" [args]} {/exp:weblog:entries} The sub-template only renders for the first entry, and the {embed} template tag is swallowed for all subsequent entries. Is there a way to make it render the sub-template for each iteration? Edit: stranger yet, if caching is enabled for the sub-template, it renders for each iteration—but, of course, the arguments on the embed tag aren't passed to subsequent iterations, as the sub-template is cached.

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  • What exactly does this PHP code do?

    - by Rob
    Alright, my friend gave me this code for requesting headers and comparing them to what the header should be. It works perfectly, but I'm not sure why. Here is the code: $headers = apache_request_headers(); $customheader = "Header: 7ddb6ffab28bb675215a7d6e31cfc759"; foreach ($headers as $header => $value) { // 1 $custom .= "$header: $value"; // 2 } $mystring = $custom; // 3 $findme = $customheader; // 4 $pos = strpos($mystring, $findme); if ($pos !== false) { // Do something } else{ exit(); } //If it doesn't match, exit. I commented with some numbers relating to the following questions: 1: What exactly is happening here? Is it setting the $headers as $header AND $value? 2: Again, don't have any idea what is going on here. 3: Why set the variable to a different variable? This is the only area where the variable is getting used, so is there a reason to set it to something else? 4: Same question as 3. I'm sorry if this is a terrible question, but its been bothering me, and I really want to know WHY it works. Well, I understand why it works, I guess I just want to know more specifically. Thanks for any insight you can provide.

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  • in R, the arguments of "for loop"

    - by alex
    Could anyone please tell me what is wrong with the R code below: i = 1.001 #make SAV and STO become vector SAV = c() STO = c() #set the initial values for the vector SAV[1] = 0 STO[1] = 100 for (t in 2:1000) { if ((price[t]>9.9)&(price[t]<10.1)&(SAV[t-1]!=0)) SAV[t]=SAV[t-1]*i STO[t]=0 } for (t in 2:1000) { if ((price[t]>9.9)&(price[t]<10.1)&(SAV[t-1]=0)) STO[t] = STO [t-1] SAV[t] = 0 } SAV STO What I am trying to do is to find vector for both SAV and STO.

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  • Scala println in a for loop

    - by random459
    The following Scala code does just what I expect it to - it prints each line of some_file.txt. import scala.io.Source val lines = Source.fromPath("some_file.txt").mkString for (line <- lines) print(line) If I use println instead of print, I expect to see some_file.txt printed out with double-spacing. Instead, the program prints a newline after every character of some_file.txt. Could someone explain this to me? I'm using Scala 2.8.0 Beta 1.

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  • Improve heavy work in a loop in multithreading

    - by xjaphx
    I have a little problem with my data processing. public void ParseDetails() { for (int i = 0; i < mListAppInfo.Count; ++i) { ParseOneDetail(i); } } For 300 records, it usually takes around 13-15 minutes. I've tried to improve by using Parallel.For() but it always stop at some point. public void ParseDetails() { Parallel.For(0, mListAppInfo.Count, i => ParseOneDetail(i)); } In method ParseOneDetail(int index), I set an output log for tracking the record id which is under processing. Always hang at some point, I don't know why.. ParseOneDetail(): 89 ... ParseOneDetail(): 90 ... ParseOneDetail(): 243 ... ParseOneDetail(): 92 ... ParseOneDetail(): 244 ... ParseOneDetail(): 93 ... ParseOneDetail(): 245 ... ParseOneDetail(): 247 ... ParseOneDetail(): 94 ... ParseOneDetail(): 248 ... ParseOneDetail(): 95 ... ParseOneDetail(): 99 ... ParseOneDetail(): 249 ... ParseOneDetail(): 100 ... _ <hang at this point> Appreciate your help and suggestions to improve this. Thank you! Edit 1: update for method: private void ParseOneDetail(int index) { Console.WriteLine("ParseOneDetail(): " + index + " ... "); ApplicationInfo appInfo = mListAppInfo[index]; var htmlWeb = new HtmlWeb(); var document = htmlWeb.Load(appInfo.AppAnnieURL); // get first one only HtmlNode nodeStoreURL = document.DocumentNode.SelectSingleNode(Constants.XPATH_FIRST); appInfo.StoreURL = nodeStoreURL.Attributes[Constants.HREF].Value; } Edit 2: This is the error output after a while running as Enigmativity suggest, ParseOneDetail(): 234 ... ParseOneDetail(): 87 ... ParseOneDetail(): 235 ... ParseOneDetail(): 236 ... ParseOneDetail(): 88 ... ParseOneDetail(): 238 ... ParseOneDetail(): 89 ... ParseOneDetail(): 90 ... ParseOneDetail(): 239 ... ParseOneDetail(): 92 ... Unhandled Exception: System.AggregateException: One or more errors occurred. --- > System.Net.WebException: The operation has timed out at System.Net.HttpWebRequest.GetResponse() at HtmlAgilityPack.HtmlWeb.Get(Uri uri, String method, String path, HtmlDocum ent doc, IWebProxy proxy, ICredentials creds) in D:\Source\htmlagilitypack.new\T runk\HtmlAgilityPack\HtmlWeb.cs:line 1355 at HtmlAgilityPack.HtmlWeb.LoadUrl(Uri uri, String method, WebProxy proxy, Ne tworkCredential creds) in D:\Source\htmlagilitypack.new\Trunk\HtmlAgilityPack\Ht mlWeb.cs:line 1479 at HtmlAgilityPack.HtmlWeb.Load(String url, String method) in D:\Source\htmla gilitypack.new\Trunk\HtmlAgilityPack\HtmlWeb.cs:line 1103 at HtmlAgilityPack.HtmlWeb.Load(String url) in D:\Source\htmlagilitypack.new\ Trunk\HtmlAgilityPack\HtmlWeb.cs:line 1061 at SimpleChartParser.AppAnnieParser.ParseOneDetail(ApplicationInfo appInfo) i n c:\users\nhn60\documents\visual studio 2010\Projects\FunToolPack\SimpleChartPa rser\AppAnnieParser.cs:line 90 at SimpleChartParser.AppAnnieParser.<ParseDetails>b__0(ApplicationInfo ai) in c:\users\nhn60\documents\visual studio 2010\Projects\FunToolPack\SimpleChartPar ser\AppAnnieParser.cs:line 80 at System.Threading.Tasks.Parallel.<>c__DisplayClass21`2.<ForEachWorker>b__17 (Int32 i) at System.Threading.Tasks.Parallel.<>c__DisplayClassf`1.<ForWorker>b__c() at System.Threading.Tasks.Task.InnerInvoke() at System.Threading.Tasks.Task.InnerInvokeWithArg(Task childTask) at System.Threading.Tasks.Task.<>c__DisplayClass7.<ExecuteSelfReplicating>b__ 6(Object ) --- End of inner exception stack trace --- at System.Threading.Tasks.Task.ThrowIfExceptional(Boolean includeTaskCanceled Exceptions) at System.Threading.Tasks.Task.Wait(Int32 millisecondsTimeout, CancellationTo ken cancellationToken) at System.Threading.Tasks.Parallel.ForWorker[TLocal](Int32 fromInclusive, Int 32 toExclusive, ParallelOptions parallelOptions, Action`1 body, Action`2 bodyWit hState, Func`4 bodyWithLocal, Func`1 localInit, Action`1 localFinally) at System.Threading.Tasks.Parallel.ForEachWorker[TSource,TLocal](TSource[] ar ray, ParallelOptions parallelOptions, Action`1 body, Action`2 bodyWithState, Act ion`3 bodyWithStateAndIndex, Func`4 bodyWithStateAndLocal, Func`5 bodyWithEveryt hing, Func`1 localInit, Action`1 localFinally) at System.Threading.Tasks.Parallel.ForEachWorker[TSource,TLocal](IEnumerable` 1 source, ParallelOptions parallelOptions, Action`1 body, Action`2 bodyWithState , Action`3 bodyWithStateAndIndex, Func`4 bodyWithStateAndLocal, Func`5 bodyWithE verything, Func`1 localInit, Action`1 localFinally) at System.Threading.Tasks.Parallel.ForEach[TSource](IEnumerable`1 source, Act ion`1 body) at SimpleChartParser.AppAnnieParser.ParseDetails() in c:\users\nhn60\document s\visual studio 2010\Projects\FunToolPack\SimpleChartParser\AppAnnieParser.cs:li ne 80 at SimpleChartParser.Program.Main(String[] args) in c:\users\nhn60\documents\ visual studio 2010\Projects\FunToolPack\SimpleChartParser\Program.cs:line 15

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  • Array basics - Populating with loop

    - by madlan
    Hi, I'm looping through a zip file trying to add the file name of each file within. Is this the correct method? Dim ZipNameArray(?) Using zip As ZipFile = ZipFile.Read(ZipToUnpack) For Each file In zip ZipNameArray(?) = file .FileName Next End Using I do not know the array size until I start looping through the zip (To work out the number of files within). How do I increment the Array? file is not a number? (It's a ZipEntry)

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  • Java do while, while

    - by Pindatjuh
    Hello, what behaviour can I expect when I run this code: do while(testA) { // do stuff } while(testB); Will it behave like: do { while(testA) { // do stuff } } while(testB); Or: if(testA) { do { // do stuff } while(testA && testB); } Or something totally unexpected? I ask this question because I think this is quite ambiguous, and for other people searching on this topic, not because I am lazy to test it out.

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  • comparing indexPaths in a loop iphone

    - by Brodie4598
    I am trying to compare an index path in my didSelectRowAtIndexPath delegate method with an array of index paths. for (n=0; n < [tempMutArrray count]; n= n+1){ NSComparisonResult *result = [indexPath compare:[tempMutArray objectAtIndex:n]; //What I want to do is is write an if statement that executes a certain block of code //if the two index paths are equal, but I cant figure out how to work with an //NSComparisonResult. }

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  • Infinite loop in haskell? (newbie)

    - by Mike
    I'm just learning Haskell. I thought this would produce a factorial function... (within ghci) Prelude let ft 0 = 1 Prelude let ft n = n * ft (n - 1) Prelude ft 5 (hangs indefinitely, until ^C). Can someone point me in the right direction? Thanks!

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  • Formatting numbers in loop

    - by dave9909
    I want to list all numbers from 0000-9999 however I am having trouble holding the zero places. I tried: for(int i = 0; i <= 9999; ++i) { cout << i << "\n"; } but I get: 1,2,3,4..ect How can I make it 0001,0002,0003....0010, etc

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  • Using a function found in a different file in a loop

    - by Anders
    This question is related to BuddyPress, and a follow-up question from this question I have a .csv-file with 790 rows and 3 columns where the first column is the group name, second is the group description and last (third) the slug. As far as I've been told I can use this code: <?php $groups = array(); if (($handle = fopen("groupData.csv", "r")) !== FALSE) { while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $group = array('group_id' = 'SOME ID', 'name' = $data[0], 'description' = $data[1], 'slug' = groups_check_slug(sanitize_title(esc_attr($data[2]))), 'date_created' = gmdate( "Y-m-d H:i:s" ), 'status' = 'public' ); $groups[] = $group; } fclose($handle); } foreach ($groups as $group) { groups_create_group($group); } With http://www.nomorepasting.com/getpaste.php?pasteid=35217 which is called bp-groups.php. The thing is that I can't make it work. I've created a new file with the code written above called groupgenerator.php uploaded the .csv file to the same folder and opened groupgenerator.php in my browser. But, i get this error: Fatal error: Call to undefined function groups_check_slug() in What am I doing wrong?

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  • I cant able to remove a row from a table while running through a loop

    - by Vibin Jith
    I am iterating through the table rows . if the row row is null I just want to remove the row. it shows an error Public Sub RemoveBlankRow(ByVal MyDataTable As DataTable) Try Dim MyRowStr As String = String.Empty For Each MyRow As DataRow In MyDataTable.Rows MyRowStr = "" For Each MyCellText As Object In MyRow.ItemArray MyRowStr = MyRowStr + MyCellText.ToString Next MyRowStr = Replace(MyRowStr, "0", " ") MyRowStr = Replace(MyRowStr, ".", " ") If MyRowStr.Trim = String.Empty Then MyDataTable.Rows.Remove(MyRow) End If Next Catch ex As Exception End Try End Sub How to overcome this issue?

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  • K-nearest neighbour with closed-loop dimensions

    - by Tomas
    Hi, I've got a K-nearest neighbour problem where some of the dimensions are closed loops. For example one is 'time of day' and I'm matching for similarity so 'very early morning' is close to 'late evening', you can't just make it a linear scale from 'very early morning' at one end to 'late evening' at the other. How can I represent this in the data model? Is there an established way to handle this or a way to work around it?

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  • PHP - Nested Looping Trouble

    - by Jeremy A
    I have an HTML table that I need to populate with the values grabbed from a select statement. The table cols are populated by an array (0,1,2,3). Each of the results from the query will contain a row 'GATE' with a value of (0-3), but there will not be any predictability to those results. One query could pull 4 rows with 'GATE' values of 0,1,2,3, the next query could pull two rows with values of 1 & 2, or 1 & 3. I need to be able to populate this HTML table with values that correspond. So HTML COL 0 would have the TTL_NET_SALES of the db row which also has the GATE value of 0. <?php $gate = array(0,1,2,3); $gate_n = count($gate); /* Database = my_table.ID my_table.TT_NET_SALES my_table.GATE my_table.LOCKED */ $locked = "SELECT * FROM my_table WHERE locked = true"; $locked_n = count($locked); /* EXAMPLE RETURN Row 1: my_table['ID'] = 1 my_table['TTL_NET_SALES'] = 1000 my_table['GATE'] = 1; Row 2: my_table['ID'] = 2 my_table['TTL_NET_SALES'] = 1500 my_table['GATE'] = 3; */ print "<table border='1'>"; print "<tr><td>0</td><td>1</td><td>2</td><td>3</td>"; print "<tr>"; for ($i=0; $i<$locked_n; $i++) { for ($g=0; $g<$gate_n; $g++) { if (!is_null($locked['TTL_NET_SALES'][$i]) && $locked['GATE'][$i] == $gate[$g]) { print "<td>$".$locked['TTL_NET_SALES'][$i]."</td>"; } else { print "<td>-</td>"; } } } print "</tr>"; print "</table>"; /* What I want to see: <table border='1'> <tr> <td>0</td> <td>1</td> <td>2</td> <td>3</td> </tr> <tr> <td>-</td> <td>1000</td> <td>-</td> <td>1500</td> </tr> </table> */ ?>

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  • UIWebView comparing current and defined URL's with a loop depending on result

    - by Syleron
    I am trying to compare the current url in webView with a defined url say google.com so in theory.. NSURLRequest *currentRequest = [webView request]; NSURL *currentURL = [currentRequest URL]; would give us our current url... NSString *newurl = @"http://www.google.com"; this would give us the compared to defined url while (!currentURL == newurl) { //do whatever here because currentURL does not equal the newurl } This does not seem to work though.. solutions?

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  • Python Loop for mysql statement

    - by user552974
    Hi, I have a project that i need to compile number of cities in each state and make an insert statement for mysql database. I think the easiest way to do it is via python but since i m a complete noob i would like to reach out all the python gurus here. Here is what the input looks like. Example below is for Florida. cities = ['Boca Raton', 'Boynton Beach', 'Bradenton', 'Cape Coral', 'Deltona'] and this what the output should be. INSERT INTO `oc_locations` (`idLocation`, `name`, `idLocationParent`, `friendlyName`) VALUES (1, 'Florida', 0, 'Florida'), (2, 'Boca Raton', 1, 'Boca Raton'), (3, 'Boynton Beach', 1, 'Boynton Beach'), (4, 'Bradenton', 1, 'Bradenton'), (5, 'Cape Coral', 1, 'Cape Coral'), (6, 'Deltona', 1, 'Deltona'), If you look at carefully the "idLocationParent" for "Florida" value is "0" so which means it is a top level value. This will be done for 50 states so ability to plug the state name into the mysql statement would be icing on the cake if there is a easy way to do it. Also alphabetical order and auto increment for the idLocation would be great. Here is an example of what i m trying to achieve concatenation is the part i need to figure out. for city in cities: print (1, 'city', 0, 'city'), city

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  • calculate next line numbers

    - by osomanden
    Weird question I guess.. But I am not very math wiz - soo here goes.. I am trying to create a patterne (or variable patterns based on selection) based on x and y numbers (2 rows and 4 columns) and the direction of the counting of x numbers like: 1-2-3-4 5-6-7-8 That one is easy, when number of x-columns is reached, next line and continue x count. But with eg. this one (still 2 rows and 4 columns): 1-2-3-4 8-7-6-5 upsie.. what if it is eg. 3++ rows and still 4 columns? 1-2-3-4 8-7-6-5 9-10-11-12 what would be the formula for this - or other possible variations (teaser for variations): 9-10-11-12 8-7-6-5 1-2-3-4 or reversed

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  • from loop to Nested loops ?

    - by WM
    I have this program that returns a factorial of N. For example, when entering 4,,, it will give 1! , 2! , 3! How could I convert this to use nested loops? public class OneForLoop { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a number : "); int N = input.nextInt(); int factorial = 1; for(int i = 1; i < N; i++) { factorial *= i; System.out.println(i + "! = " + factorial); } } }

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  • Alternative to nesting for loops in Python

    - by davenz
    I've read that one of the key beliefs of Python is that flat nested. However, if I have several variables counting up, what is the alternative to multiple for loops? My code is for counting grid sums and goes as follows: def horizontal(): for x in range(20): for y in range(17): temp = grid[x][y: y + 4] sum = 1 for n in temp: sum += int(n) return sum This seems to me like it is too heavily nested. Firstly, what is considered to many nested loops in Python ( I have certainly seen 2 nested loops before). Secondly, if this is too heavily nested, what is an alternative way to write this code?

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  • help, stuck with logic variable comparison loop, javascript

    - by Jamex
    I have an input text box for search of input, the id of the text box is: id="search". if a user enters 'cat' at first and hit search. In the function, I get the value 'cat' by using the syntax: var input = document.getElementById("search").value; After that, the user enter 'dog' in the search box and hit search using the same function. The function would assign 'dog' to the input variable. How would I compare the current value (dog) to the previously entered value (cat)? I have tried to assign the original input with a statement, something like var orig = input; but that would only overwrite the original input with the new input. What is the logical approach to this problem.

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  • While loop not reading in the last item

    - by Gandalf StormCrow
    I'm trying to read in a multi line string then split it then print it .. here is the string : 1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X 4X1b1X When I split the string with ! I get this without the last line string : 1T1b5T 1T1b5T1T2b1T1b2T 1T2b1T1b2T1T1b1T2b2T 1T1b1T2b2T1T3b1T1b1T 1T3b1T1b1T3T3b1T 3T3b1T1T3b1T1b1T 1T3b1T1b1T5T1*1T 5T1*1T11X21b1X 11X21b1X Here is my code : import java.io.BufferedInputStream; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner stdin = new Scanner(new BufferedInputStream(System.in)); while (stdin.hasNext()) { for (String line : stdin.next().split("!")) { System.out.println(line); for (int i = 0; i < line.length(); i++) { System.out.print(line.charAt(i)); } } } } } Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you UPDATE : Here is how the output should look like : 1T1b5T 1T2b1T1b2T 1T1b1T2b2T 1T3b1T1b1T 3T3b1T 1T3b1T1b1T 5T1*1T 11X21b1X 4X1b1X Here is a solution in C(my friend solved it not me), but I'd stil wanted to do it in JAVA : #include <stdio.h> int main (void) { char row[134]; for (;fgets (row,134,stdin)!=NULL;) { int i,j=0; for (i=0;row[i]!='\0';i++) { if (row[i]<='9'&&row[i]>='1') j+=(row[i]-'0'); else if ((row[i]<='Z'&&row[i]>='A')||row[i]=='*') for (;j;j--) printf ("%c",row[i]); else if (row[i]=='b') for (;j;j--) printf (" "); else if (row[i]=='!'||row[i]=='\n') printf ("\n"); } } return 0; }

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  • vba Loop over a non-contiguous range

    - by Jeffrey
    I have a non-contiguous range on rows (example address of myRange: $2:$2,$4:$205,$214:$214) and I would like to access a specific row and column within the range. I have tried the following: 'Get the value of the 2nd row, 1st column within the range myRange.rows(2).Cells(, 1).Value However, this is giving me the value of the 2nd row in the WorkSheet, and NOT in the range - meaning it is giving me address $3$1 - and not $4$1 Can someone please explain how I can access the values within in my range? (It may have to do with different areas) Thank You

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