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  • Get the last N rows in the database in order?

    - by Kristopher
    Let's say I have the following database table: record_id | record_date | record_value -----------+-------------+-------------- 1 | 2010-05-01 | 195.00 2 | 2010-07-01 | 185.00 3 | 2010-09-01 | 175.00 4 | 2010-05-01 | 189.00 5 | 2010-06-01 | 185.00 6 | 2010-07-01 | 180.00 7 | 2010-08-01 | 175.00 8 | 2010-09-01 | 170.00 9 | 2010-10-01 | 165.00 I want to grab the last 5 rows with the data ordered by record_date ASC. This is easy to do with: SELECT * FROM mytable ORDER BY record_date ASC LIMIT 5 OFFSET 4 Which would give me: record_id | record_date | record_value -----------+-------------+-------------- 6 | 2010-07-01 | 180.00 7 | 2010-08-01 | 175.00 3 | 2010-09-01 | 175.00 8 | 2010-09-01 | 170.00 9 | 2010-10-01 | 165.00 But how do I do this when I don't know how many records there are and can't compute the magic number of 4? I've tried this query, but if there are less than 5 records, it results in a negative OFFSET, which is invalid: SELECT * FROM mytable ORDER BY record_date ASC LIMIT 5 OFFSET (SELECT COUNT(*) FROM mytable) - 5; So how do I accomplish this?

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  • Is there a way to enforce/preserve order of XML elements in an XML Schema?

    - by MarcoS
    Let's consider the following XML Schema: <?xml version="1.0" encoding="UTF-8"?> <schema targetNamespace="http://www.example.org/library" elementFormDefault="qualified" xmlns="http://www.w3.org/2001/XMLSchema" xmlns:lib="http://www.example.org/library"> <element name="library" type="lib:libraryType"></element> <complexType name="libraryType"> <sequence> <element name="books" type="lib:booksType"></element> </sequence> </complexType> <complexType name="booksType"> <sequence> <element name="book" type="lib:bookType" maxOccurs="unbounded" minOccurs="1"></element> </sequence> </complexType> <complexType name="bookType"> <attribute name="title" type="string"></attribute> </complexType> </schema> and a corresponding XML example: <?xml version="1.0" encoding="UTF-8"?> <lib:library xmlns:lib="http://www.example.org/library" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.org/library src/library.xsd "> <lib:books> <lib:book title="t1"/> <lib:book title="t2"/> <lib:book title="t3"/> </lib:books> </lib:library> Is there a way to guarantee that the order of <lib:book .../> elements is preserved? I want to be sure that any parser reading the XML will return books in the specified oder, that is first the book with title="t1", then the book with title="t2", and finally the book with title="t3". As far as I know XML parsers are not required to preserve order. I wonder whether one can enforce this through XML Schema? One quick solution for me would be adding an index attribute to the <lib:book .../> element, and delegate order preservation to the application reading the XML. Comments? Suggestions?

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  • zfdatagrid : how to set the relative order of columns?

    - by user522350
    To those of you who are familiar with zfdatagrid for the Zend framework: I got a recordset by a JOIN query, say from tables s and t, now I want to set the order in which the columns appear in the deployed table. For example, 5th column of table t to appear at the leftmost side, then 3rd column of table s, then 2nd column of table t, then 4th column of table s. How do I do this? Whatever I tried, it always shows first the columns of the left table of the JOIN, then the columns of the right table of the JOIN. I only know how to tell it which columns to show, but not their order. Thanks!

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  • Proper Install Order For Visual Studio 2010 with SQL Server 2008 and Office 2007?

    - by Optimal Solutions
    I want to create a Windows 7 64-bit (Ultimate) virtual machine with: Visual Studio 2010 (Ultimate) Office 2007 Enterprise (with Visio 2007) SQL Server 2008 (with SSIS and SSRS) but I am not sure if there is a correct order to install those items such that there will not be a loss of "awareness" of one application from another on that list? For example, I want to make sure Visual Studio knows that Office exists but also that Visual Studio knows that SQL Server exists but if I install SQL Server before Office will that wipe out any data access drivers that are needed by VS 2010 if Office is installed after SQL Server? There are a lot of components and I never gave it a thought that install order would matter but I have a feeling it does. Ultimately I want to create a VM that I can save and use a base development VM from which to create additional VMs from.

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  • How to order by results from 2 seperate tables in PHP and MySQL.

    - by Vafello
    I am trying to output results of 2 sql queries to one JSON file. The problem is that I would like to order them ascending by distance which is the result of equation that takes homelat and homelon from the users table and lat, lng from locations table.(basically it takes lattitude and longitude of one point and another and computes the distance between these points). Is it possible to take some parameters from both select queries, compute it and output the result in ascending order? $wynik = mysql_query("SELECT homelat, homelon FROM users WHERE guid='2'") or die(mysql_error()); ; $query = "SELECT * FROM locations WHERE timestamp"; $result = map_query($query); $points = array(); while ($aaa = mysql_fetch_assoc($wynik)) { while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { array_push($points, array('name'=>$row['name'], 'lat'=>$row['lat'], 'lng'=>$row['lng'], 'description'=>$row['description'], 'eventType'=>$row['eventType'], 'date'=>$row['date'], 'isotime'=>date('c', ($row['timestamp'])), 'homelat'=>$aaa['homelat'], 'homelon'=>$aaa['homelon'])); } echo json_encode(array("Locations"=>$points));

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  • PHP, MySQL - would results-array shuffle be quicker than "select... order by rand()"?

    - by sombe
    I've been reading a lot about the disadvantages of using "order by rand" so I don't need update on that. I was thinking, since I only need a limited amount of rows retrieved from the db to be randomized, maybe I should do: $r = $db->query("select * from table limit 500"); for($i;$i<500;$i++) $arr[$i]=mysqli_fetch_assoc($r); shuffle($arr); (i know this only randomizes the 500 first rows, be it). would that be faster than $r = $db->("select * from table order by rand() limit 500"); let me just mention, say the db tables were packed with more than...10,000 rows. why don't you do it yourself?!? - well, i have, but i'm looking for your experienced opinion. thanks!

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  • Split a string and join it back together in a different order?

    - by Xaisoft
    What is the most concise, yet readable way to split a string and put join it back together in a different order. For example, I want to split the following string: 10-20-30-4000-50000 and I would do this via: string[] tokens = original.Split('-'); and now I want to put it back together in this order: 30-20-10-4000-50000 I know I can use Join to put it back together in it's original form, but I don't want that. The only thing I can think of right now is: string modified = string.Format("{0}{1}{2}{3}{4}",tokens[2],tokens[1],tokens[0],tokens[3], tokens[4]); I realized that if I do: string modified = string.Format("{2}{1}{0}{3}{4}", tokens); it does not keep the dashes which is what I want so is to do that, should I just do: string modified = string.Format("{2}-{1}-{0}-{3}-{4}", tokens);

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  • Is it possible to have a composite index with a list property and a sort order?

    - by npdoty
    And if not, why not? The following index always fails for me, even though I had thought I could have a sort order with a list property as long as the index didn't sort or match against any other properties. - kind: Foo properties: - name: location_geocells - name: time direction: desc If such a composite index is allowed, are there any reasons that this might be failing for me? Do the existence of other indices on the same model increase the likelihood of this failure? Does the combination of a sort order with a list property require more than N entries, where N is the number of values in the list property? (If so, how many does it require?)

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  • Creating a JSONRepresentation of my NSDictionary messes up the order?

    - by Lewion
    Hi all, To pass data to my webservice, I create an NSDictionary with the objects and keys I need, and use JSONRepresentation to format it nicely so I can post it to my service. It all worked fine with the previous version where only 2 parameters were required. An array with listitems, and a UDID. No I also need to pass a version number because we need to provide more data for people with the application at this new version. Only problem is when I create my JSONRepresentation now, the order of things are all messed up. NSMutableDictionary *rowDict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:arrayDict,@"basketListV2",sharedData.udid,@"UDID",@"1.4",@"version",nil]; It prints out version first, then UDID and then basketListV2. Anyone know what I can do to maintain the order of my NSDict? I tried both NSDictionary and NSMutableDictionary (Probably doesn't have to do anything with it but for testing purposes I had to try it.) Thanks in advance. Lewion

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  • Windows can see Ubuntu Server printer, but can't print to it

    - by Mike
    I have an old desktop that I'm trying to set up as a home backup/print server. Backup was trivial, but am having issues getting the printing to work. The printer is connected to the server running Ubuntu Server 9.10 (no gui). If I access the printer via http://hostname:631/printers/, I am able to print a test page, so I know the printer is working; however, I am having no luck from Windows. Windows can see the printer when browsed via \hostname\, but I am unable to connect. Windows says "Windows cannot connect to the printer" without indicating why. Any suggestions? From /etc/samba/smb.conf: [global] workgroup = WORKGROUP dns proxy = no security = user username map = /etc/samba/smbusers encrypt passwords = true passdb backend = tdbsam obey pam restrictions = yes unix password sync = yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . pam password change = yes map to guest = bad user load printers = yes printing = cups printcap name = cups [printers] comment = All Printers browseable = no path = /var/spool/samba writable = no printable = yes guest ok = yes read only = yes create mask = 0700 [print$] comment = Printer Drivers path = /var/lib/samba/printers browseable = yes read only = yes guest ok = yes From /etc/cups/cupsd.conf: LogLevel warn SystemGroup lpadmin Port 631 Listen /var/run/cups/cups.sock Browsing On BrowseOrder allow,deny BrowseAllow all BrowseRemoteProtocols CUPS BrowseAddress @LOCAL BrowseLocalProtocols CUPS dnssd DefaultAuthType Basic <Location /> Order allow,deny Allow all </Location> <Location /admin> Order allow,deny Allow all </Location> <Location /admin/conf> AuthType Default Require user @SYSTEM Order allow,deny Allow all </Location> <Policy default> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job CUPS-Move-Job CUPS-Get-Document> Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default CUPS-Get-Devices> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit CUPS-Authenticate-Job> Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy> <Policy authenticated> <Limit Create-Job Print-Job Print-URI> AuthType Default Order deny,allow </Limit> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job CUPS-Move-Job CUPS-Get-Document> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> <Limit Cancel-Job CUPS-Authenticate-Job> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy>

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  • How do you write a "nested IF formula" in Excel?

    - by Mike
    I manually enter numbers on one cell according to text values in the cell adjacent to it. Is there a way to use the IF function to help me manage this? The text is automatically generated with a report but I put the numbers in manually in Excel. Example of my weekly boredom below: number Text in Cell 3 Order A 3 Order A 1 Order C 2 Order B 3 Order A 1 Order C 2 Order B 2 Order B HELP! My eyes and soul hurt each time I need to do this. Thanks Mike

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  • Excel: VLookUp solves a potential Nested IF problem.

    - by Mike
    I manually enter numbers on one cell according to text values in the cell adjacent to it. Is there a way to use the IF function to help me manage this? The text is automatically generated with a report but I put the numbers in manually in Excel. Example of my weekly boredom below: number Text in Cell 3 Order A 3 Order A 1 Order C 2 Order B 3 Order A 1 Order C 2 Order B 2 Order B HELP! My eyes and soul hurt each time I need to do this. Thanks Mike

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  • How to write a "nested IF formula" in Excel?

    - by Mike
    I manually enter numbers on one cell according to text values in the cell adjacent to it. Is there a way to use the IF function to help me manage this? The text is automatically generated with a report but I put the numbers in manually in Excel. Example of my weekly boredom below: number Text in Cell 3 Order A 3 Order A 1 Order C 2 Order B 3 Order A 1 Order C 2 Order B 2 Order B HELP! My eyes and soul hurt each time I need to do this. Thanks Mike

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  • Greiner-Hormann clipping problem

    - by Belgin
    I have a set of planar polygons in 3D space defined by their vertices in counterclockwise order. Let's define the 'positive face' as being the face of the 3D polygon such as when observed, the vertices appear in counterclockwise order, and the 'negative face', the face which when observed, the vertices appear in clockwise order. I'm doing perspective projection of the set of polygons onto a projection polygon defined by the points in this order: (0, h, 0), (0, 0, 0), (w, 0, 0), and (w, h, 0), where w and h are strictly positive integers. The positive face of this projection polygon is oriented towards positive Z, and the camera point is somewhere at (0, 0, d), where d is a strictly negative number. In order to 'clip' the projected polygons into the projection polygon, I'm applying the Greiner-Hormann (PDF) clipping algorithm, which requires that the clipper and the to-be-clipped polygons be in the same order (i.e. clockwise or counterclockwise). My question is the following: How can I determine whether the projected face of the 3D polygon is the negative or the positive one? Meaning, how do I find out if I have to work with the vertices in normal or inverted order for the algorithm to work? I noticed that only if the 3D polygon is facing the projection polygon with its negative face, both of them are in the same order (counterclockwise), otherwise, a modification needs to be done. Here is a picture (PNG) that illustrates this. Note that the planes described by the polygon from the set and the projection polygon may not always be parallel.

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  • Information Spilling Across Object Boundaries

    - by Winston Ewert
    Many times my business objects tend to have situations where information needs to cross object boundaries too often. When doing OO, we want information to be in one object and as much as possible all code dealing with that information should be in that object. However, business rules do not follow this principle giving me trouble. As an example suppose that we have an Order which has a number of OrderItems which refers to an InventoryItem which has a price. I invoke Order.GetTotal() which sums the result of OrderItem.GetPrice() which multiples a quantity by InventoryItem.GetPrice(). So far so good. But then we find out that some items are sold with a two for one deal. We can handle this by having OrderItem.GetPrice() do something like InventoryItem.GetPrice( quantity ) and letting InventoryItem deal with this. However, then we find out that the two-for-one deal only lasts for a particular time period. This time period needs to be based on the date of the order. Now we change OrderItem.GetPrice() to be InventoryItem.GetPrice( quatity, order.GetDate() ) But then we need to support different prices depending on how long the customer has been in the system: InventoryItem.GetPrice( quantity, order.GetDate(), order.GetCustomer() ) But then it turns out that the two-for-one deals apply not just to buying multiple of the same inventory item but multiple for any item in a InventoryCategory. At this point we throw up our hands and just give the InventoryItem the order item and allow it to travel over the object reference graph via accessors to get the information its needs: InventoryItem.GetPrice( this ) TL;DR I want to have coupling in objects, but business rules often force me to access information from all over the place in order to make particular decisions. Are there good techniques for dealing with this? Do others find the same problem?

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  • Change the order of IP addresses returned by ifconfig?

    - by erikcw
    I have an Ubuntu server with several IP addresses attached to it. 127.0.0.1 is listed as venet0 by ifconfig. I'm using Chef to configure the server. The problem is that chef is listing 127.0.0.1 as the IP address for the server instead of one of the server's "real" IPs. (apparent "ohai ipaddress" uses the first IP listed by ifconfig to determine the server's IP). How can I change the order so the servers main IP is listed first instead of the 127.0.0.1? Can venet0 be deleted and venet0:0 be "promoted" to take its place since 127.0.0.1 is already listed in the "lo" interface? lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:334 errors:0 dropped:0 overruns:0 frame:0 TX packets:334 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:16700 (16.7 KB) TX bytes:16700 (16.7 KB) venet0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:127.0.0.1 P-t-P:127.0.0.1 Bcast:0.0.0.0 Mask:255.255.255.255 UP BROADCAST POINTOPOINT RUNNING NOARP MTU:1500 Metric:1 RX packets:7622207 errors:0 dropped:0 overruns:0 frame:0 TX packets:8183436 errors:0 dropped:1 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:2102750761 (2.1 GB) TX bytes:2795213667 (2.7 GB) venet0:0 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:XXX.XXX.XXX.XX1 P-t-P:XXX.XXX.XXX.XX1 Bcast:0.0.0.0 Mask:255.255.255.255 UP BROADCAST POINTOPOINT RUNNING NOARP MTU:1500 Metric:1 venet0:1 Link encap:UNSPEC HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00 inet addr:XXX.XXX.XXX.XX2 P-t-P:XXX.XXX.XXX.XX2 Bcast:0.0.0.0 Mask:255.255.255.255 UP BROADCAST POINTOPOINT RUNNING NOARP MTU:1500 Metric:1 route -n route -n Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 192.0.2.1 0.0.0.0 255.255.255.255 UH 0 0 0 venet0 0.0.0.0 192.0.2.1 0.0.0.0 UG 0 0 0 venet0

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  • pg_dump not working - do I need to change order of $PATH?

    - by A4J
    I'm trying to set the $PATH to pick up the latest version of pg_dump as I'm currently getting a mismatch error while doing a migrate in my Rails app (I recently changed the schema type to SQL). I have added a new file in /etc/profile.d called pg_dump.sh, and inside that put: PG_DUMP=/usr/pgsql-9.1 export PG_DUMP PATH=$PATH:$PG_DUMP/bin export PATH On looking at echo $PATH, I get: /usr/local/rvm/gems/ruby-1.9.3-p194/bin:/usr/local/rvm/gems/ruby-1.9.3-p194@global/bin:/usr/local/rvm/rubies/ruby-1.9.3-p194/bin:/usr/local/rvm/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/usr/pgsql-9.1/bin:/root/bin And I still get the error. Do I need to change the order? If so any ideas how? Output of 'ls /usr/pgsql-9.1/bin': clusterdb droplang pg_archivecleanup pg_ctl pg_standby psql createdb dropuser pg_basebackup pg_dump pg_test_fsync reindexdb createlang ecpg pgbench pg_dumpall pg_upgrade vacuumdb createuser initdb pg_config pg_resetxlog postgres vacuumlo dropdb oid2name pg_controldata pg_restore postmaster And output of 'which pg_dump': /usr/bin/pg_dump Error message on running cap 'deploy:migrate': ** [out :: 46.4.9.199] pg_dump: server version: 9.1.4; pg_dump version: 8.4.11 ** [out :: 46.4.9.199] pg_dump: aborting because of server version mismatch ** [out :: 46.4.9.199] rake aborted! ** [out :: 46.4.9.199] Error dumping database output of 'pg_dump --version': pg_dump (PostgreSQL) 8.4.11

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  • Asynchronous PHP request (not AJAX)

    - by Renjith R
    Hi I am developing an eshop application. I am using webservice to create Order in Oracle database and websvc will give a response (OrderNumber) and I will inform customer that his Order (OrderNumber) is generated My problem The creation of order is taking too much time in backend system and user is keeping refreshing the page, On each refresh user is coming back to Order create Page, so user is able to click on create Order button again In such cases multiple orders are creating for same orderlines.I can restrict user to create only one order per session in case I got order number in websvc response and I can give ordernumber to customer in next page But real problem come when I didn't get response(Ordernumber) and user is refreshing page. request is already went to Backend system and it will create order and my applicaion will not get response Is there any method in PHP where we can asyncronously check the status of order if first request is initiated by user and it doesn't matter the furthur page navigation Please help me out.. Thanks in advance

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  • Problems with :uniq => true/Distinct option in a has_many_through association w/ named scope (Rails)

    - by MikeH
    I had to make some tweaks to my app to add new functionality, and my changes seem to have broken the :uniq option that was previously working perfectly. Here's the set up: #User.rb has_many :products, :through = :seasons, :uniq = true has_many :varieties, :through = :seasons, :uniq = true #product.rb has_many :seasons has_many :users, :through = :seasons, :uniq = true has_many :varieties #season.rb belongs_to :product belongs_to :variety belongs_to :user named_scope :by_product_name, :joins = :product, :order = 'products.name' #variety.rb belongs_to :product has_many :seasons has_many :users, :through = :seasons, :uniq = true First I want to show you the previous version of the view that is now breaking, so that we have a baseline to compare. The view below is pulling up products and varieties that belong to the user. In both versions below, I've assigned the same products/varieties to the user so the logs will looking at the exact same use case. #user/show <% @user.products.each do |product| %> <%= link_to product.name, product %> <% @user.varieties.find_all_by_product_id(product.id).each do |variety| %> <%=h variety.name.capitalize %></p> <% end %> <% end %> This works. It displays only one of each product, and then displays each product's varieties. In the log below, product ID 1 has 3 associated varieties. And product ID 43 has none. Here's the log output for the code above: Product Load (11.3ms) SELECT DISTINCT `products`.* FROM `products` INNER JOIN `seasons` ON `products`.id = `seasons`.product_id WHERE ((`seasons`.user_id = 1)) ORDER BY name, products.name Product Columns (1.8ms) SHOW FIELDS FROM `products` Variety Columns (1.9ms) SHOW FIELDS FROM `varieties` Variety Load (0.7ms) SELECT DISTINCT `varieties`.* FROM `varieties` INNER JOIN `seasons` ON `varieties`.id = `seasons`.variety_id WHERE (`varieties`.`product_id` = 1) AND ((`seasons`.user_id = 1)) ORDER BY name Variety Load (0.5ms) SELECT DISTINCT `varieties`.* FROM `varieties` INNER JOIN `seasons` ON `varieties`.id = `seasons`.variety_id WHERE (`varieties`.`product_id` = 43) AND ((`seasons`.user_id = 1)) ORDER BY name Ok, so everything above is the previous version which was working great. In the new version, I added some columns to the join table called seasons, and made a bunch of custom methods that query those columns. As a result, I made the following changes to the view code that you saw above so that I could access those methods on the seasons model: <% @user.seasons.by_product_name.each do |season| %> <%= link_to season.product.name, season.product %> #Note: I couldn't get this loop to work at all, so I settled for the following: #<% @user.varieties.find_all_by_product_id(product.id).each do |variety| %> <%=h season.variety.name.capitalize %> <%end%> <%end%> Here's the log output for that: SQL (0.9ms) SELECT count(DISTINCT "products".id) AS count_products_id FROM "products" INNER JOIN "seasons" ON "products".id = "seasons".product_id WHERE (("seasons".user_id = 1)) Season Load (1.8ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name Product Load (0.7ms) SELECT * FROM "products" WHERE ("products"."id" = 43) ORDER BY products.name CACHE (0.0ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name Product Load (0.4ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 2) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 8) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name Variety Load (0.4ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 7) ORDER BY name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 43) ORDER BY products.name CACHE (0.0ms) SELECT count(DISTINCT "products".id) AS count_products_id FROM "products" INNER JOIN "seasons" ON "products".id = "seasons".product_id WHERE (("seasons".user_id = 1)) CACHE (0.0ms) SELECT "seasons".* FROM "seasons" INNER JOIN "products" ON "products".id = "seasons".product_id WHERE ("seasons".user_id = 1) AND ("seasons".user_id = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "products" WHERE ("products"."id" = 1) ORDER BY products.name CACHE (0.0ms) SELECT * FROM "varieties" WHERE ("varieties"."id" = 8) ORDER BY name I'm having two problems: (1) The :uniq option is not working for products. Three distinct versions of the same product are displaying on the page. (2) The :uniq option is not working for varieties. I don't have validation set up on this yet, and if the user enters the same variety twice, it does appear on the page. In the previous working version, this was not the case. The result I need is that only one product for any given ID displays, and all varieties associated with that ID display along with such unique product. One thing that sticks out to me is the sql call in the most recent log output. It's adding 'count' to the distinct call. I'm not sure why it's doing that or whether it might be an indication of an issue. I found this unresolved lighthouse ticket that seems like it could potentially be related, but I'm not sure if it's the same issue: https://rails.lighthouseapp.com/projects/8994/tickets/2189-count-breaks-sqlite-has_many-through-association-collection-with-named-scope I've tried a million variations on this and can't get it working. Any help is much appreciated!

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  • Set value in controller using nested resource

    - by vectran
    I have two models, product and order. Product - cost - id Order - cost - product_id Each time someone places an order, it captures the product_id through a radio button value in the "new order" form. In the controller when creating the new order it needs to set order.cost to order.product.cost. Logically I thought the code should be something like this: def create ... @order.cost == @order.product.cost ... end However I can't seem to make it work at all, hence me asking the question here. Any help is answering (or naming) the question would be greatly appreciated.

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  • Grouping and retrieving most recent entry in a table for each group

    - by Lisa
    First off, please bear with me if I don't state the SQL question correctly. I have a table that has multiple columns of data. The selection criteria for my table groups based on column 1(order #). There could be multiple items on each order, but the item #'s are not grouped together. Example: Order Customer Order Date Order Time Item Quantity 123456 45 01/02/2010 08:00 140 4 123456 45 01/02/2010 08:30 270 29 123456 45 03/03/2010 09:00 140 6 123456 45 04/02/2010 09:30 140 10 123456 45 04/02/2010 10:00 270 35 What I need is a result like: Order Customer Order Date Order Time Item Quantity 123456 45 04/02/2010 09:30 140 10 123456 45 04/02/2010 10:00 270 35 This result shows that after all the changes the final order includes 10 of Item 140 and 35 of Item 270. Is this possible. python

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  • Creating objects and referencing before saving object to db

    - by Flexo
    Sorry about the vague title, but i didnt know how to ask the question in one line :) I have an order with nested itemgroups that again have nested items. the user specify the amount of item that he would like to have in each itemgroup. I would like to create these items in the create method of the orders controller when the order itself is being created. I kinda have 2 problems here. First, how do i set the reference of the items, or better yet, put the items into the @order object so they are saved when the @order is saved? the items are being stored in the db as the code is now, but the reference is not set because the order is not stored in the db yet so it doesnt have an id yet. Second, im not sure im using the correct way to get the id from my itemgroup. @order = Order.new(params[:order]) @order.itemgroups.each do |f| f.amount.times do @item = Item.new() @item.itemgroup_id = f.id @item.save end end

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  • New records added to DataGridView aren't displayed

    - by Ross
    I have a custom Order class, groups of which are stored in List<Order> and a DataGridView. I think the problem is in my implementation so here's how I'm using it: In the form enclosing DataGridView (as OrdersDataGrid): public partial class MainForm : Form { public static List<Order> Orders; public MainForm() { // code to populate Orders with values, otherwise sets Orders to new List<Order>(); OrdersDataGrid.DataSource = Orders; } Then in another form that adds an Order: // Save event public void Save(object sender, EventArgs e) { Order order = BuildOrder(); // method that constructs an order object from form data MainForm.Orders.Add(order); } From what I can tell from the console this is added successfully. I thought the DataGrid would be updated automatically after this since Orders has changed - is there something I'm missing? The DataGrid accepts the class since it generates columns from the members.

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