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  • how to get the real bounds with google maps when fully zoomed out

    - by brad
    I have a map that shows location points based on the gbounds of the map. For example, any time the map is moved/zoomed, i find the bounds and query for locations that fall within those bounds. Unfortunately I'm unable to display all my locations when fully zoomed out. Reason being, gmaps reports the min/max long as whatever is at the edge of the map, but if you zoom out enough, you can get a longitudinal range that excludes visible locations. For instance, if you zoom your map so that you see NorthAmerica twice, on the far left and far right. The min/max long are around: -36.5625 to 170.15625. But this almost completely excludes NorthAmerica which lies in the -180 to -60 range. Obviously this is bothersome as you can actually see the continent NorthAmerica (twice), but when I query my for locations in the range from google maps, NorthAmerica isn't returned. My code for finding the min/max long is: bounds = gmap.getBounds(); min_lat = bounds.getSouthWest().lat() max_lat = bounds.getNorthEast().lat() Has anyone encountered this and can anyone suggest a workaround? Off the top of my head I can only thing of a hack: to check the zoom level and hardcode the min/max lats to -180/180 if necessary, which is definitely unacceptable.

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  • PHP form validation question?

    - by GeNx
    Is it necessary to validate a name or street address? when I have it coded in the following format. And if so why? $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $name = mysqli_real_escape_string($mysqli, htmlentities($_POST['name']));

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  • Mysql php error insert statement not working

    - by DAFFODIL
    I created database using mysql but now,i am unable to insert data,I am getting this error. Notice: Undefined index: Name in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Address in C:\wamp\www\customer.php on line 12 Notice: Undefined index: City in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Pincode in C:\wamp\www\customer.php on line 12 Notice: Undefined index: State in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Country in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Phone in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Mobile in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Fax in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Email in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Website in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Notes in C:\wamp\www\customer.php on line 12 Error: Table 'form.customer' doesn't exist

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  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

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  • How to simplify my country select menu PHP/mysql

    - by user342391
    I have a select menu that displays countries. It looks at the DB and judging by the value in the db shows the option as selected. Is there a simpler way off doing this than: if ($country == 'AG') {echo '<option value="AG" selected="selected">Antigua</option>';} else {echo '<option value="AG">Antigua</option>';}; if ($country == 'AR') {echo '<option value="AR" selected="selected">Argentina</option>';} else {echo '<option value="AR">Argentina</option>';}; if ($country == 'AM') {echo '<option value="AM" selected="selected">Armenia</option>';} else {echo '<option value="AM">Armenia</option>';}; if ($country == 'AW') {echo '<option value="AW" selected="selected">Aruba</option>';} else {echo '<option value="AW">Aruba</option>';}; if ($country == 'AU') {echo '<option value="AU" selected="selected">Australia</option>';} else {echo '<option value="AU">Australia</option >';}; if ($country == 'AT') {echo '<option value="AT" selected="selected">Austria</option>';} else {echo '<option value="AT">Austria</option>';}; if ($country == 'AZ') {echo '<option value="AZ" selected="selected">Azerbaijan</option>';} else {echo '<option value="AZ">Azerbaijan</option>';}; if ($country == 'BS') {echo '<option value="BS" selected="selected">Bahamas</option>';} else {echo '<option value="BS">Bahamas</option>';}; if ($country == 'BH') {echo '<option value="BH" selected="selected">Bahrain</option>';} else {echo '<option value="BH">Bahrain</option>';}; There are a lot of countries and doing this would be madness wouldn't it????

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  • [PHP] Invalid argument supplied for foreach()

    - by Roberto Aloi
    It often happens to me to handle data that can be either an array or a null variable and to feed some foreach with these data. $values = get_values(); foreach ($values as $value){ ... } When you feed a foreach with data that are not an array, you get a warning: Warning: Invalid argument supplied for foreach() in [...] Assuming it's not possible to refactor the get_values() function to always return an array (backward compatibility, not available source code, whatever other reason), I'm wondering which is the cleanest and most efficient way to avoid these warnings: Casting $values to array Initializing $values to array Wrapping the foreach with an if Other (please suggest)

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  • how to find the directory already is there or not in php

    - by zahir hussain
    hi i want know find the directory is already there or not... if not i would like to create the directory... my coding is below... $da = getdate(); $dat = $da["year"]."-".$da["mon"]."-".$da["mday"]; $m = md5($url)."xml"; if(is_dir($dat)) { chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "yes"; } else { mkdir($dat,0777,true); chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "not"; } thanks and advance

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  • Debugging 500 Internal Server Error on PHP running on IIS7 cluster

    - by Matthijs P
    Recently my ISP switched our website to an IIS7.0 high availibility cluster. The website is running on PHP5.2.1 and I can only upload files (so no registry tweaks). I had tested the website before and everything seemed to be working, but now the checkout page fails with: 500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed. As error messages go, this isn't very informative. I've tried: ini_set('display_errors', 1); ini_set('error_log', $file_php_can_write_to ); but both don't seem to do anything. Anyone know how to get better debugging output?

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  • PHP IP Validation Help

    - by Zubair1
    Hello, I am using this IP Validation Function that i came across while browsing, it has been working well until today i ran into a problem. For some reason the function won't validate this IP as valid: 203.81.192.26 I'm not too great with regular expressions, so would appreciate any help on what could be wrong. If you have another function, i would appreciate if you could post that for me. |--------------------------------------------| The code for the function is below: |--------------------------------------------| public static function validateIpAddress($ip_addr) { global $errors; $preg = '#^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}' . '(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$#'; if(preg_match($preg, $ip_addr)) { //now all the intger values are separated $parts = explode(".", $ip_addr); //now we need to check each part can range from 0-255 foreach($parts as $ip_parts) { if(intval($ip_parts) > 255 || intval($ip_parts) < 0) { $errors[] = "ip address is not valid."; return false; } return true; } return true; } else { $errors[] = "please double check the ip address."; return false; } }

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  • Browser: Cookie lost on refresh

    - by Nirmal
    I am experiencing a strange behaviour of my application in Chrome browser (No problem with other browsers). When I refresh a page, the cookie is being sent properly, but intermittently the browser doesn't seem to pass the cookie on some refreshes. This is how I set my cookie: $identifier = / some weird string /; $key = md5(uniqid(rand(), true)); $timeout = number_format(time(), 0, '.', '') + 43200; setcookie('fboxauth', $identifier . ":" . $key, $timeout, "/", "fbox.mysite.com", 0); This is what I am using for page headers: header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1 header("Expires: Thu, 25 Nov 1982 08:24:00 GMT"); // Date in the past Do you see any issue here that might affect the cookie handling? Thank you for any suggestion. EDIT-01: It seems that the cookie is not being sent with some requests. This happens intermittently and I am seeing this behaviour for ALL the browsers now. Has anyone come across such situation? Is there any situation where a cookie will not be sent with the request? Thanks again, for any guideline.

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  • find and replace values in a flat-file using PHP

    - by peirix
    I'd think there was a question on this already, but I can't find one. Maybe the solution is too easy... Anyway, I have a flat-file and want to let the user change the values based on a name. I've already sorted out creating new name+value-pairs using the fopen('a') mode, using jQuery to send the AJAX call with newValue and newName. But say the content looks like this: host|http:www.stackoverflow.com folder|/questions/ folder2|/users/ And now I want to change the folder value. So I'll send in folder as oldName and /tags/ as newValue. What's the best way to overwrite the value? The order in the list doesn't matter, and the name will always be on the left, followed by a |(pipe), the value and then a new-line. My first thought was to read the list, store it in an array, search all the [0]'s for oldName, then change the [1] that belongs to it, and then write it back to a file. But I feel there is a better way around this? Any ideas? Maybe regex?

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  • PHP: Strange Date Problem

    - by Me-and-Coding
    Hi, I have two users in my database whose birth date is set to: 1985-01-26 And then i have function which when provided the users' date, tells how many days are left in the birthday. Here is the function: function retage($iy,$im,$id) { if(!empty($iy)>0 && intval($im)>0 && intval($id)>0) { $tdo=$iy.'-'.$im.'-'.$id; $tdc=date('Y').'-'.$im.'-'.$id; /*echo "<br/>";*/ $cd=date('Y-n-j'); /*echo "<br/>";*/ if(strtotime($tdc)>strtotime($cd))//coming { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } elseif(strtotime($tdc)<strtotime($cd))//past { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { //$td='gone '.floor((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ndays=floor((strtotime($cd)-strtotime($tdc))/(24*3600)); if($ndays==1) $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' day ago'; else $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ty='<font color="#C7C5C5">had turned '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'had turned '.$ty.' on '.$tdc; } else { $tdc=(date('Y')+1).'-'.$im.'-'.$id; $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); //$td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } } else//today { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { $td='today'; $ty='<font color="#C7C5C5">has turned <br>'.$ty.' on today </font>'; //return 'has turned '.$ty.' on today'; } else { $ty='<font color="#C7C5C5">today</font>';$td=''; //return ''; } } } else { $ty='';$td=''; //return ''; } $ta[0]=$ty; $ta[1]=$td ; return $ta; } I use below code to show the days remaining: while($rs=mysql_fetch_array($result)) { if (isset($rs['byear'],$rs['bmonth'],$rs['bdate'])) { $tmptxt = retage($rs['byear'],$rs['bmonth'],$rs['bdate']); echo $tmptxt[1]; } } The strange thing is that for one user, the days remaining is shown correctly eg: gone 120 days ago And for other user having same birth date, this is shown: Jan 1st 1970 -14755 days to go Strange: When I use the same function outside of the loop and test with date 1985-01-26, the correct result is shown. Note: You can check out the function for yourself. Could you please tell what could be wrong there, your help will be highly appreciated. Thanks.

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  • One-to-many relationship with JDO in Google App Engine

    - by Marvin
    I've followed the GAE docs on setting up one-to-many relationship in JDO but I'm still having trouble in retrieving the collection data back. I have no problem getting the other non-collection fields back. Here are my classes: @PersistenceCapable public class User{ @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Key key; @Persistent private String uniqueId; @Persistent private String email; @Persistent private List<Address> addresses = new ArrayList<Address>() ; ... } @PersistenceCapable public class Phone{ @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Key key; @Persistent private String number; ... } public class UserDaoImpl implements UserDao { public void insertUser(User user) { if(user.getKey() == null) { com.google.appengine.api.datastore.Key key = KeyFactory.createKey(User.class.getSimpleName(), user.getEmail()); user.setKey(key); } PersistenceManager pm = PersistenceManagerWrapper.getPersistenceManager(); notNull(user); try { pm.makePersistent(user); } finally { pm.close(); } } @SuppressWarnings("unchecked") public User getUser(String uniqueId) { PersistenceManager pm = PersistenceManagerWrapper.getPersistenceManager(); Query query = pm.newQuery(User.class); query.setFilter("uniqueId == uniqueIdParam"); query.declareParameters("String uniqueIdParam"); User user = null; try { List<User> users = (List<User>)(query.execute(uniqueId)); //TODO abstract this if(users.size() > 0) user = users.get(0); } finally { pm.close(); } return user; } } public class UserDaoImplTest { @Test public void getUserTest() { User user = createTestUser(); assertNotNull("The user object should not be null", user); userDao.insertUser(user); User returnedUser = userDao.getUser(TEST_USER_ID); assertNotNull("The returnedUser object should not be null", returnedUser); Assert.assertPropertyEqualsExcludeProperties("User Object", user, returnedUser, ""); } } When I run the test, all the properties for User is populated but the list of Phone if I get is empty.

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  • How can I execute CGI files from PHP?

    - by Henri W
    I'm trying to make a web app that will manage my Mercurial repositories for me. I want it so that when I tell it to load repository X: Connect to a MySQL server and make sure X exists. Check if the user is allowed to access the repository. If above is true, get the location of X from a mysql server. Run a hgweb cgi script (python) containing the path of the repository. Here is the problem, I want to: take the hgweb script, modify it, and run it. But I do not want to: take the hgweb script, modify it, write it to a file and redirect there. I am using Apache to run the httpd process.

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  • PHP Associative Array Duplicate Key?

    - by Steven
    Hello, I have an associative array, however when I add values to it using the below function it seems to overwrite the same keys. Is there a way to have multiple of the same keys with different values? Or is there another form of array that has the same format? I want to have 42=56 42=86 42=97 51=64 51=52 etc etc function array_push_associative(&$arr) { $args = func_get_args(); foreach ($args as $arg) { if (is_array($arg)) { foreach ($arg as $key => $value) { $arr[$key] = $value; $ret++; } }else{ $arr[$arg] = ""; } } return $ret; }

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  • PHP Application check name is unique if not append

    - by user270797
    My application requires the user to enter their business name, which the application will automatically create into a unique identifier to be used in URLs, ie "Bob's Cafe" will become "bobs-cafe" But if there are duplicate names I would like the application to add a number so if there is already a "bobs-cafe" we will use "bobs-cafe-1" and likewise if there is already a "bobs-cafe-1" we will use "bobs-cafe-2" Ive used explode and also looked at a regular expressions but I dont know the best way to approach this. Im stuck in being able to grab the number and incrementing it and returning the string

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  • Redefining PHP function?

    - by Michael
    If I have a function: function this($a){ return $a; } If I wanted to redefine the function, would it be as simple as rewriting it? function this($a, $b){ //New this function return $a * $b; }

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  • Multiple table relationships in Zend Help

    - by Zogi
    Hi Guys I have been doing some DB mapping to link two tables to no avail. Everytime I run the code I get the following error: Message: File "Role.php" does not exist or class "Role" was not found in the file Stack trace: #0 C:\wamp\www\zend\library\Zend\Db\Table\Row\Abstract.php(867): Zend_Db_Table_Row_Abstract->_getTableFromString('Role') #1 C:\wamp\www\uw\application\models\admin\User.php(56): Zend_Db_Table_Row_Abstract->findDependentRowset('Role') #2 C:\wamp\www\uw\application\controllers\AdminController.php(110): Application_Model_Admin_User->getUsers() #3 C:\wamp\www\zend\library\Zend\Controller\Action.php(513): AdminController->usersAction() #4 C:\wamp\www\zend\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action->dispatch('usersAction') #5 C:\wamp\www\zend\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #6 C:\wamp\www\zend\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch() #7 C:\wamp\www\zend\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #8 C:\wamp\www\uwi\public\index.php(26): Zend_Application->run() #9 {main} Code & DB below: application/models/admin/User.php class Application_Model_Admin_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; protected $_dependentTables = array('Role'); public function getUsers() { $rows = $this->fetchAll($this->select()->where('active = ?', 1)); $rows1 = $rows->current(); $rows2 = $rows1->findDependentRowset('Role'); return $rows2; } } application/models/admin/Role.php class Application_Model_Admin_Role extends Zend_Db_Table_Abstract { protected $_name = 'role'; protected $_referenceMap = array ( 'Role' => array( 'columns' => array('id'), 'refTableClass' => 'User', 'refColumns' => array('role_id') ); } DB tables CREATE TABLE role ( id integer auto_increment NOT NULL, name varchar(120), PRIMARY KEY(id) ); CREATE TABLE user ( id integer auto_increment NOT NULL, username varchar(120), PRIMARY KEY(id), FOREIGN KEY(role_id) REFERENCES role(id) );

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