Search Results

Search found 14175 results on 567 pages for 'home entertainment'.

Page 504/567 | < Previous Page | 500 501 502 503 504 505 506 507 508 509 510 511  | Next Page >

  • Bash script to insert code from one file at a specific location in another file?

    - by Kurtosis
    I have a fileA with a snippet of code, and I need a script to insert that snippet into fileB on the line after a specific pattern. I'm trying to make the accepted answer in this thread work, but it's not, and is not giving an error so not sure why not: sed -e '/pattern/r text2insert' filewithpattern Any suggestions? pattern (insert snippet on line after): def boot { also tried escaped pattern but no luck: def\ boot\ { def\ boot\ \{ fileA snippet: LiftRules.htmlProperties.default.set((r: Req) => new Html5Properties(r.userAgent)) fileB (Boot.scala): package bootstrap.liftweb import net.liftweb._ import util._ import Helpers._ import common._ import http._ import sitemap._ import Loc._ /** * A class that's instantiated early and run. It allows the application * to modify lift's environment */ class Boot { def boot { // where to search snippet LiftRules.addToPackages("code") // Build SiteMap val entries = List( Menu.i("Home") / "index", // the simple way to declare a menu // more complex because this menu allows anything in the // /static path to be visible Menu(Loc("Static", Link(List("static"), true, "/static/index"), "Static Content"))) // set the sitemap. Note if you don't want access control for // each page, just comment this line out. LiftRules.setSiteMap(SiteMap(entries:_*)) // Use jQuery 1.4 LiftRules.jsArtifacts = net.liftweb.http.js.jquery.JQuery14Artifacts //Show the spinny image when an Ajax call starts LiftRules.ajaxStart = Full(() => LiftRules.jsArtifacts.show("ajax-loader").cmd) // Make the spinny image go away when it ends LiftRules.ajaxEnd = Full(() => LiftRules.jsArtifacts.hide("ajax-loader").cmd) // Force the request to be UTF-8 LiftRules.early.append(_.setCharacterEncoding("UTF-8")) } }

    Read the article

  • Why is Firefox prompting to download a file that is POST'd to?

    - by alex
    This is the most peculiar thing. It is from an old in house CMS. When I attempt to submit my changes, it prompts to save the file linked in the action attribute of the form. Headers Request POST /~site/edit/articles/article_save.php?id=54 HTTP/1.1 Host: example.com User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://example.com Content-Type: multipart/form-data; boundary=---------------------------10102754414578508781458777923 Content-Length: 940 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="title" Home Content -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="catid" 18 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="activecheck" 1 -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="image" -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgToolbarSelectBlock" <p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="content" <p>Edit your article in this text box.</p> -----------------------------10102754414578508781458777923 Content-Disposition: form-data; name="contentWidgEditor" true -----------------------------10102754414578508781458777923-- Response HTTP/0.9 200 OK And then Firefox shows.... I can't determine from the response headers as to why this is prompting to open/save. It has always worked. All other PHP files on the site work fine. Anyone have a clue? Thanks Update Apparently, it just crashes Safari.

    Read the article

  • Show wordpress posts outside of the blog

    - by way2project
    I have two wordpress blogs on my site and now I want to show the posts of categories of both blogs on the home page. I am using the following code. <?php require($_SERVER['DOCUMENT_ROOT'] . '/projects/wp-load.php'); query_posts('cat=9& showposts=8'); if (have_posts()) : while (have_posts()) : the_post(); ?> <ul><li> <a href="<?php the_permalink(); ?>" title="<?php the_title(); ?>"><?php $shorttitle4 = substr(the_title('','',FALSE),0,25)."..."; echo $shorttitle4; ?></a> </li></ul> <?php endwhile; else: echo "no posts"; endif; ?> <?php wp_reset_query(); ?> One of my blogs is placed in the "projects" folder and another one is placed in "technology folder". but this code is showing the posts only from projects blogs if I changed the folder in as "technology" in the above code. I think this is because of wp-load.php file. Can you help me? Thanks

    Read the article

  • Understanding the workflow of the messages in a generic server implementation in Erlang

    - by Chiron
    The following code is from "Programming Erlang, 2nd Edition". It is an example of how to implement a generic server in Erlang. -module(server1). -export([start/2, rpc/2]). start(Name, Mod) -> register(Name, spawn(fun() -> loop(Name, Mod, Mod:init()) end)). rpc(Name, Request) -> Name ! {self(), Request}, receive {Name, Response} -> Response end. loop(Name, Mod, State) -> receive {From, Request} -> {Response, State1} = Mod:handle(Request, State), From ! {Name, Response}, loop(Name, Mod, State1) end. -module(name_server). -export([init/0, add/2, find/1, handle/2]). -import(server1, [rpc/2]). %% client routines add(Name, Place) -> rpc(name_server, {add, Name, Place}). find(Name) -> rpc(name_server, {find, Name}). %% callback routines init() -> dict:new(). handle({add, Name, Place}, Dict) -> {ok, dict:store(Name, Place, Dict)}; handle({find, Name}, Dict) -> {dict:find(Name, Dict), Dict}. server1:start(name_server, name_server). name_server:add(joe, "at home"). name_server:find(joe). I tried so hard to understand the workflow of the messages. Would you please help me to understand the workflow of this server implementation during the executing of the functions: server1:start, name_server:add and name_server:find?

    Read the article

  • How do I enable mod_deflate for PHP files?

    - by DM.
    I have a Liquid Web VPS account, I've made sure that mod_deflate is installed and running/active. I used to gzip my css and js files via PHP, as well as my PHP files themselves... However, I'm now trying to do this via mod_deflate, and it seems to work fine for all files except for PHP files. (Txt files work fine, css, js, static HTML files, just nothing that is generated via a PHP file.) How do I fix this? (I used the "Compress all content" option under "Optimize Website" in cPanel, which creates an .htaccess file in the home directory (not public_html, one level higher than that) with exactly the same text as the "compress everything except images" example on http://httpd.apache.org/docs/2.0/mod/mod_deflate.html) .htaccess file: <IfModule mod_deflate.c> SetOutputFilter DEFLATE <IfModule mod_setenvif.c> # Netscape 4.x has some problems... BrowserMatch ^Mozilla/4 gzip-only-text/html # Netscape 4.06-4.08 have some more problems BrowserMatch ^Mozilla/4\.0[678] no-gzip # MSIE masquerades as Netscape, but it is fine # BrowserMatch \bMSIE !no-gzip !gzip-only-text/html # NOTE: Due to a bug in mod_setenvif up to Apache 2.0.48 # the above regex won't work. You can use the following # workaround to get the desired effect: BrowserMatch \bMSI[E] !no-gzip !gzip-only-text/html # Don't compress images SetEnvIfNoCase Request_URI .(?:gif|jpe?g|png)$ no-gzip dont-vary </IfModule> <IfModule mod_headers.c> # Make sure proxies don't deliver the wrong content Header append Vary User-Agent env=!dont-vary </IfModule> </IfModule>

    Read the article

  • LINQ thinks I need an extra INNER JOIN, but why?

    - by Saurabh Kumar
    I have a LINQ query, which for some reason is generating an extra/duplicatre INNER JOIN. This is causing the query to not return the expected output. If I manually comment that extra JOIN from the generated SQL, then I get seemingly correct output. Can you detect what I might have done i nthis LINQ to have cuased this extra JOIN? Thanks. Here is my approx LINQ var ids = context.Code.Where(predicate); var rs = from r in ids group r by new { r.phonenumbers.person.PersonID} into g let matchcount=g.Select(p => p.phonenumbers.PhoneNum).Distinct().Count() where matchcount ==2 select new { personid = g.Key }; and here is the generated SQL (the duplicate join is [t7]) Declare @p1 VarChar(10)='Home' Declare @p2 VarChar(10)='111' Declare @p3 VarChar(10)='Office' Declare @p4 VarChar(10)='222' Declare @p5 int=2 SELECT [t9].[PersonID] AS [pid] FROM ( SELECT [t3].[PersonID], ( SELECT COUNT(*) FROM ( SELECT DISTINCT [t7].[PhoneValue] FROM [dbo].[Person] AS [t4] INNER JOIN [dbo].[PersonPhoneNumber] AS [t5] ON [t5].[PersonID] = [t4].[PersonID] INNER JOIN [dbo].[CodeMaster] AS [t6] ON [t6].[Code] = [t5].[PhoneType] INNER JOIN [dbo].[PersonPhoneNumber] AS [t7] ON [t7].[PersonID] = [t4].[PersonID] WHERE ([t3].[PersonID] = [t4].[PersonID]) AND ([t6].[Enumeration] = @p0) AND ((([t6].[CodeDescription] = @p1) AND ([t5].[PhoneValue] = @p2)) OR (([t6].[CodeDescription] = @p3) AND ([t5].[PhoneValue] = @p4))) ) AS [t8] ) AS [value] FROM ( SELECT [t0].[PersonID] FROM [dbo].[Person] AS [t0] INNER JOIN [dbo].[PersonPhoneNumber] AS [t1] ON [t1].[PersonID] = [t0].[PersonID] INNER JOIN [dbo].[CodeMaster] AS [t2] ON [t2].[Code] = [t1].[PhoneType] WHERE ([t2].[Enumeration] = @p0) AND ((([t2].[CodeDescription] = @p1) AND ([t1].[PhoneValue] = @p2)) OR (([t2].[CodeDescription] = @p3) AND ([t1].[PhoneValue] = @p4))) GROUP BY [t0].[PersonID] ) AS [t3] ) AS [t9] WHERE [t9].[value] = @p5

    Read the article

  • How to add deploy.jar to classpath?

    - by dma_k
    I am facing the problem: I need to add ${java.home}/lib/deploy.jar JAR file to classpath in the runtime (dynamically from java). The solution with Thread#setContextClassLoader(ClassLoader) (mentioned here) does not work because of this bug (if somebody can explain what is really a problem – you are welcome). The solution with -Xbootclasspath/a:"%JAVA_HOME%/jre/lib/deploy.jar" does not work well for me, because I want to have "pure executable jar" as a deliverable: no wrapping scripts please (more over %JAVA_HOME% may not be defined in user's environment in Windows for example, plus I need to write a script per platform) The solution with merging deploy.jar file into my deliverable works only if I make a build on Windows platform. Unfortunately, when the deliverable is produced on build server running on Linux, I got Linux-dependant JAR, which does not execute on Windows – it fails with the trace below. I have read How the Java Launcher Finds Classes and Java programming dynamics: Java classes and class loading articles but I've got no extra ideas, how to correctly handle this situation. Any advices or solutions are very welcomed. Trace: java.lang.NoClassDefFoundError: Could not initialize class com.sun.deploy.config.Config at com.sun.deploy.net.proxy.UserDefinedProxyConfig.getBrowserProxyInfo(UserDefinedProxyConfig.java:43) at com.sun.deploy.net.proxy.DynamicProxyManager.reset(DynamicProxyManager.java:235) at com.sun.deploy.net.proxy.DeployProxySelector.reset(DeployProxySelector.java:59) ... java.lang.NullPointerException at com.sun.deploy.net.proxy.DynamicProxyManager.getProxyList(DynamicProxyManager.java:63) at com.sun.deploy.net.proxy.DeployProxySelector.select(DeployProxySelector.java:166)

    Read the article

  • How do I use Perl's LWP to log in to a web application?

    - by maxjackie
    I would like to write a script to login to a web application and then move to other parts of the application: use HTTP::Request::Common qw(POST); use LWP::UserAgent; use Data::Dumper; $ua = LWP::UserAgent->new(keep_alive=>1); my $req = POST "http://example.com:5002/index.php", [ user_name => 'username', user_password => "password", module => 'Users', action => 'Authenticate', return_module => 'Users', return_action => 'Login', ]; my $res = $ua->request($req); print Dumper(\$res); if ( $res->is_success ) { print $res->as_string; } When I try this code I am not able to login to the application. The HTTP status code returned is 302 that is found, but with no data. If I post username/password with all required things then it should return the home page of the application and keep the connection live to move other parts of the application.

    Read the article

  • committing to a branch that's not checked out

    - by intuited
    I'm using git to version my home directories on a couple different machines. I'd like for them to each use separate branches and both pull from a common branch. So most commits should be made to that common branch, unless something specific to that machine is being committed, in which case the commit should go to the checked out, machine-specific branch. Switching branches is clearly not a very good option in this case. It's mentioned in this post that what I want to do is impossible, but I found that answer to be rather blunt and to perhaps not take into account the possibility of using the plumbing commands. Unfortunately I don't have enough reputation to comment on that thread. I rather suspect that there is some way to do this and am hoping to save myself an hour or few of questing for the answer by just asking you good folk. So is it possible to commit to a different branch without checking that branch out first? Ideally I'd like to use the index in the same way that git commit normally does.

    Read the article

  • Symfony: joining two forms in the same page

    - by user248959
    Hi, i'm trying to join in the same action the login and the register forms. This is what i'm trying: modules/miembros/actions.class.php public function executeAux(sfWebRequest $request) { // I execute this action } modules/miembros/templates/auxSuccess.php <?php include_component('sfGuardRegister', 'register'); ?> <?php include_component('sfGuardAuth', 'signin'); ?> modules/miembros/components.class.php public function executeSignin($request) { if ( $request->isMethod( 'post' ) && ($request- >getParameter('submit')=='signin') ){ $this->form->bind( $request->getParameter( 'login' ) ); if ( $this->form->isValid() ){ $this->getController()->getActionStack()->getLastEntry()->getActionInstance()->redirect( '@home' ); } } } modules/miembros/templates/_signin.php <form action="<?php echo url_for('miembros/aux?submit=signin') ?>" method="post"> <?php echo $form['email_address']->renderLabel() ?> <?php echo $form['email_address'] ?> ... It's working ok, but i would to know if you have other alternatives. Regards Javi

    Read the article

  • Python 3.3 Webserver restarting problems

    - by IPDGino
    I have made a simple webserver in python, and had some problems with it before as described here: Python (3.3) Webserver script with an interesting error In that question, the answer was to use a While True: loop so that any crashes or errors would be resolved instantly, because it would just start itself again. I've used this for a while, and still want to make the server restart itself every few minutes, but on Linux for some reason it won't work for me. On windows the code below works fine, but on linux it keeps saying Handler class up here ... ... class Server: def __init__(self): self.server_class = HTTPServer self.server_adress = ('MY IP GOES HERE, or localhost', 8080) global httpd httpd = self.server_class(self.server_adress, Handler) self.main() def main(self): if count > 1: global SERVER_UP_SINCE HOUR_CHECK = int(((count - 1) * RESTART_INTERVAL) / 60) SERVER_UPTIME = str(HOUR_CHECK) + " MINUTES" if HOUR_CHECK > 60: minutes = int(HOUR_CHECK % 60) hours = int(HOUR_CHECK // 60) SERVER_UPTIME = ("%s HOURS, %s MINUTES" % (str(hours), str(minutes))) SERVING_ON_ADDR = self.server_adress SERVER_UP_SINCE = str(SERVER_UP_SINCE) SERVER_RESTART_NUMBER = count - 1 print(""" SERVER INFO ------------------------------------- SERVER_UPTIME: %s SERVER_UP_SINCE: %s TOTAL_FILES_SERVED: %d SERVING_ON_ADDR: %s SERVER_RESTART_NUMBER: %s \n\nSERVER HAS RESTARTED """ % (SERVER_UPTIME, SERVER_UP_SINCE, TOTAL_FILES, SERVING_ON_ADDR, SERVER_RESTART_NUMBER)) else: print("SERVER_BOOT=1\nSERVER_ONLINE=TRUE\nRESTART_LOOP=TRUE\nSERVING_ON_ADDR:%s" % str(self.server_adress)) while True: try: httpd.serve_forever() except KeyboardInterrupt: print("Shutting down...") break httpd.shutdown() httpd.socket.close() raise(SystemExit) return def server_restart(): """If you want the restart timer to be longer, replace the number after the RESTART_INTERVAL variable""" global RESTART_INTERVAL RESTART_INTERVAL = 10 threading.Timer(RESTART_INTERVAL, server_restart).start() global count count = count + 1 instance = Server() if __name__ == "__main__": global SERVER_UP_SINCE SERVER_UP_SINCE = strftime("%d-%m-%Y %H:%M:%S", gmtime()) server_restart() Basically, I make a thread to restart it every 10 seconds (For testing purposes) and start the server. After ten seconds it will say File "/home/username/Desktop/Webserver/server.py", line 199, in __init__ httpd = self.server_class(self.server_adress, Handler) File "/usr/lib/python3.3/socketserver.py", line 430, in __init__ self.server_bind() File "/usr/lib/python3.3/http/server.py", line 135, in server_bind socketserver.TCPServer.server_bind(self) File "/usr/lib/python3.3/socketserver.py", line 441, in server_bind self.socket.bind(self.server_address) OSError: [Errno 98] Address already in use As you can see in the except KeyboardInterruption line, I tried everything to make the server stop, and the program stop, but it will NOT stop. But the thing I really want to know is how to make this server able to restart, without giving some wonky errors.

    Read the article

  • MySQL PHP SELECT throwing up an error?

    - by user1909695
    I am trying to make a comment section on my hand made site, using PHP and MySQL. I have got the comments stored in my database, but when I try to SELECT them my site throws up this error, mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 9 in /home/a9210109/public_html/comments.php on line 16 My code so far is below <?php $comment = $_POST['comment']; $mysql_host = ""; $mysql_database = ""; $mysql_user = ""; $mysql_password = ""; mysql_connect($mysql_host,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die( "Unable to select database"); $CreateTable = "CREATE TABLE comments (comment VARCHAR(255), time VARCHAR(255));"; mysql_query($CreateTable); $UseComment = "INSERT INTO comments VALUES ('$comment')"; mysql_query($UseComment); $SelectComments = "SELECT * FROM comments"; $comments = mysql_query($SelectComments); $num=mysql_numrows($comments); $variable=mysql_result($comments,$i,"comment"); mysql_close(); ?> <a href="#" onclick="toggle_visibility('hidden');">Show/Hide Comments</a> <?php $i=0; while ($i < $num) { $comment=mysql_result($comments,$i,"comment"); echo "<div id='hidden' style='display:none'><h3>$comment</h3></div>"; $i++; } ?>

    Read the article

  • php error reporting - having trouble matching local & web server settings

    - by Andrew Heath
    I'm trying to add a custom error handler to my site, but in doing so have discovered that my webhost's PHP error reporting settings and those of my localhost (default XAMPP) vary considerably. While I thought I was programming to E_STRICT like a good little boy, adding the error handler to my webhost revealed craploads of Runtime Notices. Example: Runtime notice strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Chicago' for 'CST/-6.0/no DST' instead In /home/... Clearly this isn't a red-alert, showstopping error. But what bothers me is that it doesn't show up on my localhost. I'd certainly like to improve my code by addressing these sorts of issues if I could see them! I've looked through both php.ini files, and my webhost's setting is error_reporting = E_ALL & ~E_NOTICE whereas mine was error_reporting = E_STRICT, which I had thought was better. However, changing mine to match and rebooting the server doesn't seem to have accomplished anything. Could someone please point me in the right direction?

    Read the article

  • Codeigniter: Library function--I'm stuck

    - by Kevin Brown
    I have a library function that sets up my forms, and submits data. They're long, and they work, so I'll spare you reading my code. :) I simply need a way for my functions to determine how to handle the data. Until now, the function did one thing: Submit a report for the current user. NOW, the client has requested that an administrator also be able to complete a form--this means that the form would be filled out, and it would CREATE a user at the same time, whereas the current function EDITS and is accessed by an EXISTING user. Do I need a separate function to do essentially the same thing? How do I make one function perform two tasks? One to update a user, and if there is no user, create one. Current controller: function survey() { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); //Convert the db Object to a row array $data['manager'] = $data['member']->row(); $manager_id = $data['manager']->manager_id; $data['manager'] = $this->home_model->getUser($manager_id); $data['manager'] = $data['manager']->row(); $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data, $method); } Current Library: function survey_form($container) { //Lots of validation stuff $this->CI->validation->set_rules($rules); if ( $this->CI->validation->run() === FALSE ) { // Output any errors $this->CI->validation->output_errors(); } else { // Submit form $this->_submit(); } $this->CI->load->view($container,$data); The submit function is huge too. Basically says, "Update table with data where user_id=current user" I hope this wasn't too confusing. I'll create two functions if need be, but I'd like to keep redundancy down! }

    Read the article

  • ASP.NET MVC 2.0 + Implementation of a IRouteHandler goes not fire

    - by Peter
    Can anybody please help me with this as I have no idea why public IHttpHandler GetHttpHandler(RequestContext requestContext) is not executing. In my Global.asax.cs I have public class MvcApplication : System.Web.HttpApplication { public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); routes.Add("ImageRoutes", new Route("Images/{filename}", new CustomRouteHandler())); } protected void Application_Start() { RegisterRoutes(RouteTable.Routes); } } //CustomRouteHandler implementation is below public class CustomRouteHandler : IRouteHandler { public IHttpHandler GetHttpHandler(RequestContext requestContext) { // IF I SET A BREAK POINT HERE IT DOES NOT HIT FOR SOME REASON. string filename = requestContext.RouteData.Values["filename"] as string; if (string.IsNullOrEmpty(filename)) { // return a 404 HttpHandler here } else { requestContext.HttpContext.Response.Clear(); requestContext.HttpContext.Response.ContentType = GetContentType(requestContext.HttpContext.Request.Url.ToString()); // find physical path to image here. string filepath = requestContext.HttpContext.Server.MapPath("~/logo.jpg"); requestContext.HttpContext.Response.WriteFile(filepath); requestContext.HttpContext.Response.End(); } return null; } } Can any body tell me what I'm missing here. Simply public IHttpHandler GetHttpHandler(RequestContext requestContext) does not fire. I havn't change anything in the web.config either. What I'm missing here? Please help.

    Read the article

  • Bizarre Bug with our Rails app in IE

    - by Callmeed
    We're experiencing a really bizarre bug in our Rails 2.3.4 app. This bug only happens in Internet Explorer (7 and 8). Here's what happens: A new customer creates an account at https://domain.com/signup/free (notice no subdomain) Their account is identified by a subdomain like "example.domain.com" After signing up, they get a welcome screen with a link to their account's home page They follow the link, then click the "log in" button and attempt to login Even though they provide valid credentials, the app redirects back to their account's root url ... they can never reach their admin area The only way they can login (on IE) is by quitting and re-opening IE ... then it works fine ... Something with their initial session is preventing them from logging in. If it matters, we are using restful_authentication and the ssl_requirement plugin ... I'm not sure if one or both of those has a problem with IE but we are stumped here. Also, I've read IE has an issue with subdomains that contain underscores ... this isn't what's going on.

    Read the article

  • Doubt about instance creation by using Spring framework ???

    - by Arthur Ronald F D Garcia
    Here goes a command object which needs to be populated from a Spring form public class Person { private String name; private Integer age; /** * on-demand initialized */ private Address address; // getter's and setter's } And Address public class Address { private String street; // getter's and setter's } Now suppose the following MultiActionController @Component public class PersonController extends MultiActionController { @Autowired @Qualifier("personRepository") private Repository<Person, Integer> personRepository; /** * mapped To /person/add */ public ModelAndView add(HttpServletRequest request, HttpServletResponse response, Person person) throws Exception { personRepository.add(person); return new ModelAndView("redirect:/home.htm"); } } Because Address attribute of Person needs to be initialized on-demand, i need to override newCommandObject to create an instance of Person to initiaze address property. Otherwise, i will get NullPointerException @Component public class PersonController extends MultiActionController { /** * code as shown above */ @Override public Object newCommandObject(Class clazz) thorws Exception { if(clazz.isAssignableFrom(Person.class)) { Person person = new Person(); person.setAddress(new Address()); return person; } } } Ok, Expert Spring MVC and Web Flow says Options for alternate object creation include pulling an instance from a BeanFactory or using method injection to transparently return a new instance. First option pulling an instance from a BeanFactory can be written as @Override public Object newCommandObject(Class clazz) thorws Exception { /** * Will retrieve a prototype instance from ApplicationContext whose name matchs its clazz.getSimpleName() */ getApplicationContext().getBean(clazz.getSimpleName()); } But what does he want to say by using method injection to transparently return a new instance ??? Can you show how i implement what he said ??? ATT: I know this funcionality can be filled by a SimpleFormController instead of MultiActionController. But it is shown just as an example, nothing else

    Read the article

  • Paging not working in my wordpress installation

    - by Bootcamp
    I recently started a blog site and wanted to give it a magazine look. I used Wordpress for my blog and used the Arthemia theme with it. I also changed the permalink structure to point to /%year%/%monthnum%/%day%/%postname%/ structure. Now the problem that i have is that the paging has stopped working on my home page. When i click on the next page link i get a 404 error. My /page/2 url does not show the next page. I check on google and found out that it was due to the redirection that is being performed due to the permalink change. The solution given was that i need to skip the url rewriting for the /page/* urls. This is the link to an article which said this http://www.yoursearchadvisor.com/blog/wordpress-next_posts_link-broken/ . I was not able to follow this article and solve my problem, as i could not find the permanent redirect manager under the settings section as said in this article. Can somebody please guide me how to solve this problem. I am using the latest Wordpress version and Arthemia theme with it. Thanks.

    Read the article

  • jeditable table cell

    - by user666262
    Hi all, I am having an issue when using jeditable to edit a cell in a table. The project is the MVC 2 web application and the table has been put on the standard about page. How do i tell the script to call a specific method in the controller ? because it is currently just loading the entire page into the cell. This is the javascript: $(document).ready(function () { $('.editable').editable('http://localhost:2196/Home/About', { type: 'text', cancel: 'Cancel', event: 'dblclick', submit: 'OK', tooltip: 'double Click to edit...' }); }); This is the table : <% foreach (DataTableEditable.Models.Company item in (IEnumerable<DataTableEditable.Models.Company>)Model) {%> <tr id="<%= Html.Encode(item.ID) %>"> <td class="editable"><%= Html.Encode(item.Name) %> </td> <td><%= Html.Encode(item.Address) %> </td> <td><%= Html.Encode(item.Town) %> </td> </tr> <% }%> Thanks lots John

    Read the article

  • Apache Content negotiation returns wrong Content-Type with Mulitviews :(

    - by edbras
    I am using Apache webserver 2.2 with Content Negotiation through Multiviews. I have: <Directory /home/develop/web/prodBuild> Options +MultiViews AddEncoding x-gzip .gz </Directory> This directory contains the gzip files. So if a browser requests the file bla.js, the server will return the file bla.js.gz as the file bla.js doesn't exists. However, the Content-Type on my Ubuntu server is set to be "application/x-gzip" which is wrong as it's a javascript file, so is has be "application/javascript" I have this working on my local Windows Apache server, but don't seem to get it working on the remote Ubuntu server. :(... NO idea why... Who/why is it setting this wrong Content-Type ? BTW: I don't have this line "AddType application/x-gzip .gz .tgz" somwhere in my config, as then I understand why it goes wrong. My workaround: add the following line under the above "AddEncoding": AddType "" .gz It will then set an empty string as Content-Type and then it works.. I think that the browser will try to discover the content type itself... I hope somebody can explain to me why this is not working and why this content type is set ? :(

    Read the article

  • Java applet loading images from external jars

    - by Mathias
    I have a jar on a server, and users should be able to develop extensions for it. Therefore the jars main class should be extended and some resources should be added to a second user created jar which will be loaded from another server or locally. Now I have problems accessing the resources (images) from the user loaded jars. Heres is the structure: My Server: game.jar containing game.class images.class ... image1.png (...) Local: user.jar containing: user.class extends game userimage.png The extension is loaded via Greasemonkey, it modifies the "archive" attribute to "/home/username/user.jar, game.jar" and the "code" attribute to "user.class". The user should be able to overwrite already defined images. If the image does not exist in game.jar, it is loaded correctly from user.jar. But the images loaded early in the game are always loaded from the game.jar, others seem to be overwritten correctly by the user. Is there a way to make sure they are always loaded in the correct order? This might be because of some caching mechanism. Because Greasemonkey removes the game from the page, changes the archive and code and reinsert it, the game is loaded without a mod for a brief second. In that time, images are loaded as expected from game jar, but those are the ones not being overwritable by the user. But how to avoid it? Another thing: If I overwrite the "run" method in user.class, the game is unable to load any image at all. Not from the user.jar and not from the game.jar. Java doesn't find the image, as the URL object "getClass().getResource(imagename)" returns with null. I tried to overwrite the image.class, but that doesn't fix the problem, unless I overwrite every class from game.class involved into calling the image.class

    Read the article

  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

    Read the article

  • Parse error: syntax error, unexpected ';'

    - by sufoid
    Hallo I have this script: <? require("lib2/config.inc.php"); require("lib2/tpl.class.php"); require("lib2/db.class.php"); require("lib2/um.class.php"); $tpl = new template("templates", "tpl"); $db = new db($db['location'], $db['username'], $db['passwort'], $db['database']); $um = new usermanagment(); /** User login **/ $checklogin = $um->check_login(); $userdata = $um->getuserdata(); if(!$checklogin && !$guest) { header("LOCATION: ./index2.php"); } eval("\$header .= \" ".$tpl->get("header")."\";"); eval("\$footer .= \" ".$tpl->get("footer")."\";"); $time = time(); $db->Query("UPDATE userdaten SET lastaction = '$time' WHERE userid = '".$userdata['userid']."'"); ?> And get this error: Parse error: syntax error, unexpected ';' in /home/httpd/html/login/global.php(22) : eval()'d code on line 96 Any ideas?

    Read the article

  • asp.net on linux/mono broken? weird load then 404/resource error

    - by acidzombie24
    I am testing out my asp.net on mono's VM Ware Image using opensuse From the home page it says Trying out your own code You can test your own applications by connecting with the file manager on this machine to the machine hosting your application, and copying over the directory containing application and its associated files. To test your ASP.NET applications, copy your code to a new directory in /srv/www/htdocs , then visit the following url: http://localhost/directoryname/page.aspx Where directoryname is the directory where you deployed your application, and page.aspx is the initial page for your software, typically Default.aspx. Mirror: http://tortillaflatscafe.com/ I saw my app had errors. After i restarted the VM i can no longer run my app. Instead of getting error messages or anything i get this error instead. Server Error in '/myfoldername' Application The resource cannot be found. Description: HTTP 404. The resource you are looking for (or one of its dependencies) could have been removed, had its name changed, or is temporarily unavailable. Please review the following URL and make sure that it is spelled correctly. Requested URL: /Default.aspx I tried /default.aspx, using sudo to set permissions to 777 recursively, restarting apache via terminal i could not get this error to go away. How do i fix this?

    Read the article

  • tracd server problems

    - by deddihp
    Hello, I got the following error while accessing tracd server, what's going on ? Thanks. [oke@localhost Trac-0.11.7]$ sudo tracd -p 8000 /home/deddihp/trac/ Server starting in PID 5082. Serving on 0.0.0.0:8000 view at http://127.0.0.1:8000/ ---------------------------------------- Exception happened during processing of request from ('127.0.0.1', 47804) Traceback (most recent call last): File "/usr/lib/python2.6/SocketServer.py", line 558, in process_request_thread self.finish_request(request, client_address) File "/usr/lib/python2.6/SocketServer.py", line 320, in finish_request self.RequestHandlerClass(request, client_address, self) File "/usr/lib/python2.6/SocketServer.py", line 615, in __init__ self.handle() File "/usr/lib/python2.6/BaseHTTPServer.py", line 329, in handle self.handle_one_request() File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 194, in handle_one_request gateway.run(self.server.application) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 94, in run response = application(self.environ, self._start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/standalone.py", line 100, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/main.py", line 346, in dispatch_request locale.setlocale(locale.LC_ALL, environ['trac.locale']) File "/usr/lib/python2.6/locale.py", line 513, in setlocale return _setlocale(category, locale) Error: unsupported locale setting ----------------------------------------

    Read the article

< Previous Page | 500 501 502 503 504 505 506 507 508 509 510 511  | Next Page >