Search Results

Search found 32007 results on 1281 pages for 'php openid'.

Page 505/1281 | < Previous Page | 501 502 503 504 505 506 507 508 509 510 511 512  | Next Page >

  • Display username to logged in user only?

    - by RodeoRamsey
    I have a Wordpress blog set up to display comments as "Anonymous User" by hard coding it into the comments.php file. I would like to have it say the user's Username next to their comment and ONLY display that Username to THEM. In other words, if they're a guest, they'll see "Anonymous User" and if they're a registered/logged in DIFFERENT user, they'll still see "Anonymous User", but if it's THEIR comment it'll say "Your Comment" or their own username. Any clue on a snippet of code? Here's what I have so far: Anonymous User: <div class="post-txt" id="<?php comment_ID() ?>"><?php comment_text() ?></div> Thanks!

    Read the article

  • openoffice document (odt) to PDF with commad line on Linux?

    - by Data-Base
    Hi, we are building a PHP script that we need at work to create reports in PDFs the reports will be created by using templates from postgrSQL. so far I found that it can be done with the use of php and odt (openoffice) files [http://www.odtphp.com/] (do you have any other suggestions?) now how I can convert the results to PDF so teachers will get the final reports as PDF any tips? the server has no GUI and I want to make it as simple as possible we tried using PHP to PDF directly with FPDF [http://www.fpdf.org/] but it is really a CPU killer! cheers

    Read the article

  • How I can use X-editable pass value to backend and get response

    - by leonlong
    I am new to jquery, recently I tried to use X-editable to edit a table. after I edited it , I want to pass value to PHP for process, but when I want to return something else back with value, it will get an error. What I mean is usually we can get several response from PHP, but I can get it like that through this. $('#example').editable({ type: 'text', name: 'example', url: 'exprediction.php', ajaxOptions: { dataType: 'json' }, success: function(newValue) { var response = newValue.split("|"); value1 = response[0]; value2 = response[1]; //it did not work } });

    Read the article

  • work question how to start working as a programmer what do i need!

    - by giorgo
    Hi i am learning java and php i have some projects from uni.(Gui,s in java with mysql and a web application in php with mysql ++ more things like this.) i have started learning mvc struts spring and i also lerning php +zend +++++ more stuff etc....you can't learn everything!!!!!!!!!!!!!!!!!!!!!!! I would like to ask how can i find a job as a programmer-software eng because i have send my cv in many companys but all of them said me that i need work expirience. How All of you started your programming expirience. Did you make some projects and send them did you you have somebody that help you ...??? i am totaly alone i do everything by my self. can anyone answer this?everybody starts from somewhere but what if this somewhere don't come?what to do ?? how to start !!!!!!! Thanks

    Read the article

  • How do I extend the code igniter controller class?

    - by ChronoFish
    Hello, In my CI system\libraries directory I have a new class named DD_Controller.php. This file looks like this: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class DD_Controller extends Controller { protected $ddauthentication; function __construct() { parent::Controller(); $this->ddauthentication = "Authenticated"; } } ?> My application controller is defined like this: class Inquiry extends DD_Controller {...} The Inquiry class works fine when I extend Controller, but I get a Fatal error: Class 'DD_Controller' not found in C:\development\localhost\applications\inquiry\controllers\inquiry.php on line 4 When I extend DD_Controller. In the config file I have the prefix defined as such: $config['subclass_prefix'] = 'DD_'; Any idea of what I'm missing? TIA

    Read the article

  • .htaccess for multiple application in Kohana V3

    - by khairil
    Hi I have setup multiple application in Kohana v3, it works normally without enabling .htaccess (to remove index.php or admin.php) my setup + system/ + modules/ + applications/ + public/ + bootstrap.php + ... + admin/ + bootstrap.php + ... + index.php (for 'public' application) + admin.php (for 'admin' application) so to access the frontend sample url will be; http://mydomain.com/index.php/(controller_name)/... and to access administration site; http://mydomain.com/admin.php/(controller_name)/... The task is, I want to remove and replace index.php (default url) and admin.php with /admin/ using .htaccess (mod_rewrite) so it can be http://mydomain.com/(controller_name) <- 'public' application http://mydomain.com/admin/(controller_name) <- 'admin' application my current .htaccess (not working) is; # Turn on URL rewriting RewriteEngine On # Installation directory RewriteBase /ko3/ # Protect hidden files from being viewed Order Deny,Allow Deny From All # Protect application and system files from being viewed RewriteRule ^(?:web-apps|modules|core)\b.* index.php/$0 [L] # Allow any files or directories that exist to be displayed directly RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d # TODO: rewrite admin URL to admin.php/URL #RewriteRule ^admin/(.*) admin.php/$0 [L] # Rewrite all other URLs to index.php/URL RewriteRule .* index.php/$0 [PT]

    Read the article

  • Defautlt Contoller in CodeIgniter

    - by gregavola
    Hello everyone, I am wondering if there is any other configuration options for a default controller. For example - if I have a controller called "site" and I set the default controller in the following file: application/config/routes.php to: $route['default_controller'] = "site"; I should be able to go to http://localhost and that brings up the index(); function in the site controller. However, if I try to do go to http://localhost/index.php/index2 to load the index2(); function I get a 404 error. If i change the URL to http://localhost/index.php/site/index2 it works fine - but I thought already set the default controller. Is there any way around this? Any thoughts?

    Read the article

  • why include() don't allow to work setcookie?

    - by Syom
    i need to set cookies in my page, but it returns Warning: Cannot modify header information - headers already sent by (output started at /home1/bsam/public_html/24kadr/index.php:1) in /home1/bsam/public_html/24kadr/basic_login.php on line 35 on line 1 i have include 'basic_login.php'; but even if i remoove include, ir returns the same warning on session_start, or mysql_connect. so i think these all functions use header when calling, but what can i do? at least i need to connect to database, and just after it i need to use setcookie(). so what can i do? thanks

    Read the article

  • .htacces to create friendly URLs. Help needed....

    - by Jonathan
    Hi, I'm having a hard time with .htacces. I want to create friendly URLs for a site I'm working on... Basically I want to convert this: http://website.com/index.php?ctrl=pelicula&id=0221889 http://website.com/index.php?ctrl=pelicula&id=0160399&tab=posters Into this: http://website.com/pelicula/0221889/ http://website.com/pelicula/0221889/posters/ In case I need it later I would also want to know how to add the article title to the end of the URL like this (I'm using PHP): http://website.com/pelicula/0221889/the-article-name/ http://website.com/pelicula/0221889/the-article-name/posters/ Note: Stackoverflow method is also good for me, for example the url of this question is: http://stackoverflow.com/questions/3033407/htacces-to-create-friendly-urls-help-needed But you can put anything after the id and it will also work. like this: http://stackoverflow.com/questions/3033407/just-anything-i-want I have used some automatic web tools for creating the .htacces file, but its not working correctly. So I ask for your help. I will also be glad if you can recommend .htacces best practices and recommendations.. Thanks!

    Read the article

  • Problem while redirecting user after registration

    - by Eternal Learner
    I am creating a simple website . My situation is like this. After registering an user, I want to redirect the user after say 3 seconds to a main page(if the registration succeeds) . The code I have now is as below $query = "INSERT INTO Privileges VALUES('$user','$password1','$role')"; $result = mysql_query($query, $dbcon) or die('Registration Failed: ' . mysql_error()); print 'Thanks for Registering , You will be redirected shortly'; ob_start(); echo "Test"; header("Location: http://www.php.net"); ob_flush() I get the error message Warning: Cannot modify header information - headers already sent by (output started at/home/srinivasa/public_html/ThanksForRegistering.php:27) in /home/srinivasa /public_html/ThanksForRegistering.php on line 35. What do I need to do now ?

    Read the article

  • $_SERVER['HTTP_HOST'] not setted

    - by yes123
    Hi guys, I am getting lot of traffic to my php pages but without the variable $_SERVER['HTTP_HOST'] setted. This traffic is like 1 hit per second. I don't know what it could be, but for reducing server load i am doing this at the top of every php pages: if (!isset($_SERVER['HTTP_HOST'])) exit; Do u know what could cause this? Is it safe to exit whenever http_host is not setted? Can a normal user visit my pages without setting http_host? PHP version: 5.2.0-8, Apache: 2.2.3 Thanks

    Read the article

  • Where the probem in this code (javaScript).........?????

    - by user318068
    Hi Ihave a problem in my code. can anybody help me ... <html> <body> <script type="text/javascript"> <?php $conn = mysql_connect("localhost","root"); mysql_select_db("tr", $conn); $q = mysql_query("SELECT message FROM messages WHERE to_viewed = '0' "); if (mysql_num_rows($q)) { require('pm.php'); ?> var answer = confirm("you have new message "); <?php } ?> if (answer) { window.location = "http:>>>/"; } else { } //--> </script> </body> </html> Thanks ....

    Read the article

  • Java REST Interface

    - by Vikram
    I have a PHP web application environment. I am using Slim Framework as REST interface for my application. My application front-end is written using Backbone.js and jQuery. There is a utility (.jar file) which when I use command line makes a remote call (I guess this is a Web Service) which returns me the data. how do I best incorporate this into my webapplication described on top? My application front end will have a Button that should make an AJAX call to the REST Interface and fetch the data as JSON. My approach: PHP-REST interface url is: /api/phprestapi.php exists Add a JAVA-REST interface at url: /api/javarestapi.java (Perhaps) to separate these two Existing Environment: LAMP Stack on Ubuntu How do I achieve this? What is the kind of effort involved? Thanks for your pointers

    Read the article

  • Best practice: Define form field name in backend or the template

    - by AbcAeffchen
    If you designing a webpage you should separate the backend from the frontend. But if you use forms you have to name them. But where should you set this name? e.g. PHP: $fieldName = 'email'; $template->setVar('field_name', $fieldName) ... if(!empty($_POST)) validate($_POST[$fieldName]); Template: <input type="text" name="{$field_name}"> Or just PHP: if(!empty($_POST)) validate($_POST['email']); Template: <input type="text" name="email"> Or should I write a function that can be called from the template an converts an array of field data (name, type, value, id, class, ...) into html code? Is there a best practice where to define fieldnames (types,etc.)? Notice: I used php and smarty like pseudocode (and tags), but its a general question.

    Read the article

  • DateTime object is blank

    - by user522962
    I am trying to convert a date to a DateTime Object. My code works fine on my localhost (php version 5.3) but returns a blank DateTime object on my remote server (php version 5.2.14). Am I missing something really obvious? <?php $d = '2010-01-01'; $n = new DateTime ( $d ); print_r($n); ?> // result on localhost: DateTime Object ( [date] => 2010-01-01 00:00:00 [timezone_type] => 3 [timezone] => UTC ) // result on remotehost: DateTime Object ( ) // is blank

    Read the article

  • Apply a class to a <h1> based on the site url

    - by user1870639
    I'm new to PHP and want to apply a specific class to the title of my page depending on what part of the site the viewer is browsing. For instance, I want to apply the class "blog" to the if the viewer is at domain.com/blog OR domain.com/blog/post-1 so on and so forth BUT apply the class "pics" if they're viewing domain.com/pics or domain.com/pics/gallery-1 etc etc. I found something that could be modified to serve my needs using javascript here but I figured seeing as I'm using PHP already, it'd make more sense to keep this sort of thing server side. As I say, I'm new to PHP. I've experimented with some regular expressions, but to no avail.

    Read the article

  • Theme the node-create and node-edit template

    - by Toxid
    I'm using drupal 6. I've managed to make a .tpl file for one content type, that is for images in my image gallery. I did that by adding this code in template.php: function artbasic_theme($existing, $type, $theme, $path) { return array( 'galleryimage_node_form' => array( 'arguments' => array('form' => NULL), 'template' => 'galleryimage_node_form' ) ); } And then I created galleryimage_node_form.tpl.php, and was good to go. Now it happens so that I want to have other template files for the forms of other content types, for example link_contrib_node_form.tpl.php. I've tried a couple of ways to change this function to include more content types, but I can't figure it out. Can anyone help?

    Read the article

  • Creating a file/folder structure and zipping it up?

    - by makeee
    I have a directory of image files and I need a php script or shell script that will rename them, create a structure of nested directories, and then insert each image into a specified place in the directory hierarchy. Ideally I would just specify a parent directory for each file and a parent directory for each directory and it would build it. And then finally, I need the script to zip up the whole thing. There's probably not an existing php class that will do all this for me, but if anyone knows of a php class or other script available online that would handle a lot of this logic that would be great.

    Read the article

  • Connecting to the database in a Created Library - CodeIgniter

    - by Brogrammer
    I have a little issue right now and its bugging me, hopefully one of you guys will be able to help me out. Basically I'm creating a library to use in CodeIgniter and I'm getting this error: A PHP Error was encountered Severity: Notice Message: Undefined property: Functions::$db Filename: libraries/Functions.php Line Number: 11 The Database library is already on autoload aswell as my functions library: $autoload['libraries'] = array('database','session','encrypt','functions'); The Functions.php file is located in the application/libraries folder accordingly. Line number 11 consists of this: $this->db->where('username', $data); Not sure as to why the db is an undefined property?

    Read the article

  • .htacess windows problem

    - by pistacchio
    Hi, In the root directory of a small site i'm developing i have the following .htacess file: Options +FollowSymLinks RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-F RewriteRule .$ index.php that basically allows me to have pretty urls as it remaps every path that does not exists on the server (eg : /user/details/145 ) as a call to index.php where I handle it MVC-style. While this works ok on MacOs, this morning I have to work on another machine that has Windows (the apache server is run by xampp) and it does not work as it seems to redirect all the calls (eg those to static files like images) to index.php Any help?

    Read the article

  • Form Input Gets 1 Word

    - by 01010011
    Hi Using Codeigniter, how do I get and display, from my controller, all of the text a user entered into a text field on a view? I only get the first word, and nothing after the spaces. Here are my form_validation rules $this->form_validation->set_rules( 'field_name','Field Name','trim|required|alpha_numeric|tolower|xss_clean'); And here is my controller public function my_method() { if ($this->input->post()) { $name = $this->input->post('search'); echo $name; } } and my view ?php echo form_open('my_controller/my_method'); ?> <?php echo form_input('search'); ?> <?php echo form_submit('submit', 'Search'); ?>

    Read the article

  • jQuery: Load body of page into variable

    - by Nathan G.
    I'm using jQuery to load the result of a PHP script into a variable. The script is passed something that the user typed with a GET request. I want to take just what the script spit out into its <body> tag. Here's what I've tried: JS: function loader() { var typed = $('#i').val(); //get what user typed in $.get("script.php", {i: typed}, function(loaded) {dataloaded = loaded;}); alert($(dataloaded).find('body')) } But it just displays [Objec object]. How can I get a useful value that is just the contents of the body of a loaded page? I know the PHP works, I just need the JS. The script echos something like 1!!2 (two numbers separated by two exclamation points). Thanks!

    Read the article

  • undefined index mode, which is the variable that case statement is looking for

    - by Brad
    receiving error: PHP Notice: Undefined index: mode in /web/ee_web/include/form-modal.php on line 51 line 51 switch($_GET["mode"]) { block of code it is in: switch($_GET["mode"]) { case "login": login_user(); break; case "logout": session_destroy(); print "<p>You are now logged out.</p>"; print "<p><input type=\"submit\" id=\"closeButton\" name=\"closeButton\" value=\"Close\" onclick=\"self.parent.tb_remove(); parent.location.reload(1);\" /></p>"; break; default: login_user(); //print "<p>How'd you end up here?</p>"; break; } The URL for the page is index.php?mode=logout, that is how I am passing the value into mode. Any way I could resolve this error message?

    Read the article

  • How can i check if user entering correct form of email

    - by deerox
    Well i am not using email verification so i am facing problem in checking correct form of email address suppose if user enter support or support@ it accept it as well. So i atleast want them to enter there email or at least they enter email form correctly Here is my code: <?php require_once 'global.php'; if (!isset($_SESSION['logged_in'])) { header("Location: login.php"); } $user = unserialize($_SESSION['user']); $email = $user->email; $message = ""; if (isset($_POST['submit-settings'])) { $email = $_POST['email']; $user->email = $email; $user->save(); $msg = "Done!<br/>"; } ?>

    Read the article

  • Mod_rewrite trouble: Want to direct from ?= to a flat link, nothing seems to work.

    - by Davezatch
    I have a site that currently serves results as example.com/index.php?show=foo and I'd like it to read example.com/show/foo. My understanding is this would make them visible to search engine robots, and it seems a much simpler way to do this than to create a couple hundred html files... I've tried the following .htaccess code: Options +FollowSymLinks RewriteEngine on RewriteRule ^show/(.*)$ index.php?show=$1 [NC,L] No dice. Also tried this, which I found on another stack overflow question: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([0-9A-Za-z]+)/?$ /index.php?show=$1 [L] </IfModule> Any ideas on what I'm missing here?

    Read the article

< Previous Page | 501 502 503 504 505 506 507 508 509 510 511 512  | Next Page >