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• Row level user permissions, help with design

  - by bambam

  Hi, Say I am creating a forums application, I understand how to design a forum level permission system with Groups. i.e. you create a forum to group mapping, and assign users to a group to give them access to a particular forum. How can I refine the permissions to allow for row level permissions (or in forum terms, post level).

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• Where should I store custom permissions for my web app

  - by vikp

  Hi, I'm wondering where is the ideal place to store custom permissions in my web applications. For example I have the following permissions: AdminPermission ReadPermission WritePermission At the moment I store these in the static utilities class as the constant string type objects. Thank you

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• Django - serving and managing permissions for static content

  - by kRON

  I have certain documents that I want to limit access to through Django to authorized users with permissions only. If I'm going to use Django as a proxy to serve static files in a view, what are the implications? I'm used to serving static files in Apache and configuring that my media is served without any handlers, but what happens if someone starts downloading 500mb through my Django proxy? Will my Django thread be locked for that user until he recieves the 500mb response?

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• Change permissions upon uploading with scp

  - by Florian Mayer

  I am uploading files to my shell account using scp. As I need different permissions on the server than on my computer, I'd like to have a way to easily change the permissions upon upload without needing to ssh to the account and change them manually.

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• Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

  - by Kristian

  I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

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• CharField values disappearing after save (readonly field)

  - by jamida

  I'm implementing simple "grade book" application where the teacher would be able to update the grades w/o being allowed to change the students' names (at least not on the update grade page). To do this I'm using one of the read-only tricks, the simplest one. The problem is that after the SUBMIT the view is re-displayed with 'blank' values for the students. I'd like the students' names to re-appear. Below is the simplest example that exhibits this problem. (This is poor DB design, I know, I've extracted just the relevant parts of the code to showcase the problem. In the real example, student is in its own table but the problem still exists there.) models.py class Grade1(models.Model): student = models.CharField(max_length=50, unique=True) finalGrade = models.CharField(max_length=3) class Grade1OForm(ModelForm): student = forms.CharField(max_length=50, required=False) def __init__(self, *args, **kwargs): super(Grade1OForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['student'].widget.attrs['readonly'] = True self.fields['student'].widget.attrs['disabled'] = 'disabled' def clean_student(self): instance = getattr(self,'instance',None) if instance: return instance.student else: return self.cleaned_data.get('student',None) class Meta: model=Grade1 views.py from django.forms.models import modelformset_factory def modifyAllGrades1(request): gradeFormSetFactory = modelformset_factory(Grade1, form=Grade1OForm, extra=0) studentQueryset = Grade1.objects.all() if request.method=='POST': myGradeFormSet = gradeFormSetFactory(request.POST, queryset=studentQueryset) if myGradeFormSet.is_valid(): myGradeFormSet.save() info = "successfully modified" else: myGradeFormSet = gradeFormSetFactory(queryset=studentQueryset) return render_to_response('grades/modifyAllGrades.html',locals()) template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myGradeFormSet.management_form }} {% for myform in myGradeFormSet.forms %} {# myform.as_table #} <tr> {% for field in myform %} <td> {{ field }} {{ field.errors }} </td> {% endfor %} </tr> {% endfor %} </table> <input type="submit" value="Submit"> </form>

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• Updating permissions on Amazon S3 files that were uploaded via JungleDisk

  - by Simon_Weaver

  I am starting to use Jungle Disk to upload files to an Amazon S3 bucket which corresponds to a Cloudfront distribution. i.e. I can access it via an http:// URL and I am using Amazon as a CDN. The problem I am facing is that Jungle Disk doesn't set 'read' permissions on the files so when I go to the corresponding URL in a browser I get an Amazon 'AccessDenied' error. If I use a tool like BucketExplorer to set the ACL then that URL now returns a 200. I really really like the simplicity of dragging files to a network drive. JungleDisk is the best program I've found to do this reliably without tripping over itself and getting confused. However it doesn't seem to have an option to make the files read-able. I really don't want to have to go to a different tool (especially if i have to buy it) to just change the permissions - and this seems really slow anyway because they generally seem to traverse the whole directory structure. JungleDisk provides some kind of 'web access' - but this is a paid feature and I'm not sure if it will work or not. S3 doesn't appear to propagate permissions down which is a real pain. I'm considering writing a manual tool to traverse my tree and set everything to 'read' but I'd rather not do this if this is a problem someone else has already solved.

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• Permissions on Mac OSX

  - by Linda

  I think that this is a permissions issue but I am not sure and I am not sure how to repair the problem. I have a new MacBook. I have 2 external drives that were previously used on another MacBook. I have a lot of folders and XCode projects on the external drives. When I try to work on the projects, there is a message similar to this: "This file is not writable. You may not be able to save your changes, but you will be able to Save a Copy somewhere else. Do you want to edit this file anyway?" If I make changes and try to close the project I get this error: "The project and user files project.pbxproj and macbook.pbxuser for project “thirdtry.xcodeproj” are not writeable and cannot be saved. Your changes will be lost if you close the project. You may need to SCM edit these files to gain writability." I have tried just to rename the folder but that permission is not allowed either unless I individually change permissions for every file in an XCode project. As you can imagine, this could be time consuming for tons of files and projects. I can copy the project into internal memory and can run it then after renaming the folder that contains all of the files. This defeats the purpose of having all of the projects on an external drive. Also, in XCode, there is no "Build and Run" there is only "Build and Debug" now. I don't know if this is related or not. Suggestions for how to repair all permissions to all files and folders on my external drives? What about the "Build and Debug" and no "Build and Run" choice? Thanks, Linda

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• setting write permissions on theme subdirectory?

  - by Scott B

  I've a theme which supports multiple templates, each with a header background image whose color can be set by the site owner via a colorpicker widget in my theme's options panel. This has the effect of opening the background image, recoloring it and resaving it back to the server. I've had zero issues with this routine until recently when a customer installed the theme on a web host whose default read/write permissions are apparently much more restrictive than the norm. In this case, the user was unable to alter the colors of the template images because of the permissions settings. I'm looking for a bit of understanding on what the permissions would need to be (assuming I purposefully set them via script) to allow the logged in wordpress user to write to files under my theme's styles directory. The code I'm using to write to the image file is below... $img = imagecreatefromgif("../wp-content/themes/mytheme/styles/".get_option('my_theme')."/image.gif"); $color = imagecolorallocate($img, $info["red"], $info["green"], $info["blue"]); imagecolorset($img, 0, $info["red"], $info["green"], $info["blue"]); imagegif($img, $path);

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• php lampp permissions of fopen function

  - by marmoushismail

  hi i'm programming php using: netbeans 6.8 lampp for ubuntu (xampp) apache which came with xampp $fh = fopen("testfile2.txt", 'w') or die("Failed to create file"); $text ="hello man cool good"; fwrite($fh, $text) or die("Could not write to file"); fclose($fh); echo "File 'testfile.txt' written successfully"; //i get the next error: Warning: fopen(testfile2.txt) [function.fopen]: failed to open stream: Permission denied in /home/marmoush/allprojects/phpprojects/myindex.php on line 91 Failed to create file anyway i know what this error is; it's about folder and files permissions; i looked into the folder permission tab made access available for "others" group ( to read and write) the program worked result was a file (test.txt) so i looked at the created file permission it appears to be that (php , xampp or whoever) creates file with (nobody permission) I have 2 QUESTIONS: 1- what if i need the file created by (php code and xampp ) to have the "root or user or myname" permissions ?? where to set this setting 2-also my concern (what if i send this files to actual web server will it make nobody permissions also nobody ? when they create files

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• working on lists in python

  - by owca

  I'm trying to make a small modification to django lfs project, that will allow me to deactivate products with no stocks. Unfortunatelly I'm just beginning to learn python, so I have big trouble with its syntax. That's what I'm trying to do. I'm using method 'has_variants' which returns true if product has any. Then I'm building a list from variants for this product. Next for every product in this list (I've called it 'set') I check it's stock and set bool variable 'inactive' to true if product has no stocks and to false if there are any. Finally if 'inactive' is false I'm setting self.active to 0. Code fails in line with: set[] = s How to correct it ? def deactivate(self): """If there are no stocks, deactivate the product. Used in last step of checkout. """ if self.has_variants(): for s in self.variants.filter(active=True): set[] = s for var in set: if var.get_stock_amount() == 0: inactive = True else: inactive = False else: if self.get_stock_amount() == 0: inactive = True if inactive: self.active = False return 0 error log : Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 362, in execute_manager utility.execute() File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 213, in execute translation.activate('en-us') File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 73, in activate return real_activate(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 180, in _fetch app = import_module(appname) File "/home/purplecow/rails/purpledev/site-packages/django/utils/importlib.py" , line 35, in import_module __import__(name) File "/home/purplecow/rails/purpledev/lfs/caching/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/caching/listeners.py", line 10, in < module> from lfs.cart.models import Cart File "/home/purplecow/rails/purpledev/lfs/cart/models.py", line 8, in <module> from lfs.catalog.models import Product File "/home/purplecow/rails/purpledev/lfs/catalog/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/catalog/listeners.py", line 5, in <m odule> from lfs.catalog.models import PropertyGroup File "/home/purplecow/rails/purpledev/lfs/catalog/models.py", line 589 set[] = s ^ SyntaxError: invalid syntax

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• How to prevent HTTP 304 in Django test server

  - by Augusto Men

  I have a couple of projects in Django and alternate between one and another every now and then. All of them have a /media/ path, which is served by django.views.static.serve, and they all have a /media/css/base.css file. The problem is, whenever I run one project, the requests to base.css return an HTTP 304 (not modified), probably because the timestamp hasn't changed. But when I run the other project, the same 304 is returned, making the browser use the file cached by the previous project (and therefore, using the wrong stylesheet). Just for the record, here are the middleware classes: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.transaction.TransactionMiddleware', ) I always use the default address http://localhost:8000. Is there another solution (other than using different ports - 8001, 8002, etc.)?

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• django urls.py regex isn't working

  - by Phil

  This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

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• Must See Conference Videos for Python/Django Developers

  - by Koobz

  There's lots of good conference videos online regarding Python and Django development. Instead of watching ST:TNG at the computer, I figure it'd more productive to hone my knowledge . Fire away with some of your most inspiring and educational Python, Django, or simply programming related talks. Provide an explanation of why you found the talk useful. Examples: James Bennet on Re-usable Apps - Got me to take a serious look at django apps. Put together a fairly robust site in two days afterwards with django-cms, django-photologue, django-contact-form. Good advice on when your app is crossing boundaries and why it's good to err on the site of 'make it a separate app.'

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• Trouble using South with Django and Heroku

  - by Dan

  I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

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• Making Django ignore string literals

  - by James

  UPDATE: It turns out this is a deeper question than I thought at first glance - the issue is that python is replacing the string literals before they ever get to django. I will do more investigating and update this if I find a solution. I'm using django to work with LaTeX templates for report generation, and am running into a lot of problems with the way Django replaces parts of strings. Specficially, I've run into two problems where I try to insert a variable containing latex code. The first was that it would replace HTML characters, such as the less than symbol, with their HTML codes, which are of course gibberish to a LaTeX interpreter. I fixed this by setting the context to never autoescape, like so: c = Context(inputs) c.autoescape = False However, I still have my second issue, which is that Django replaces string literals with their corresponding characers, so a double backslash becomes \, and \b becomes a backspace. How can I force Django to leave these characters in place, so inputs['variable'] = '{\bf this is code} \\' won't get mangled when I use {{variable}} to reference it in the django template?

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• Which Django 1.2.x multilingual application to use?

  - by mawimawi

  There are a couple of different applications for internationalized content in Django. As of now I only have used http://code.google.com/p/django-multilingual/ in my production environments, but I wonder if there are "better" solutions for my wishes. What my staff users need is the following: An object is being created by a staff user in any language (e.g. "de") This object should be displayed in the german version of the website. When a staff user translates the object into a different language (e.g. "fr"), then the page must be visible in the french version as well. If an object is not translated in the visitor's currently selected language (e.g. "en"), then calling the objects url shall raise a 404 Error (or even better a notice that the object is only available in the languages "de" and "fr", and the visitor might be able to select one of the languages) My staff users are working in the admin interface, so the multilingual application must support this as well. I don't really care whether the multilingual app uses a single table with many fields (like title_en, title_de, title_fr) or a foreign key to a related table (as it is implemented in django-multlingual). I only want it to have a good admin interface and no "default" language, because some content might be available just in "de", and some other just in "fr" and "en". And the most important issue of course is compatibility with Django 1.2.x. What are your experiences and preferred apps, and why?

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• What are the options for overriding Django's cascading delete behaviour?

  - by Tom

  Django models generally handle the ON DELETE CASCADE behaviour quite adequately (in a way that works on databases that don't support it natively.) However, I'm struggling to discover what is the best way to override this behaviour where it is not appropriate, in the following scenarios for example: ON DELETE RESTRICT (i.e. prevent deleting an object if it has child records) ON DELETE SET NULL (i.e. don't delete a child record, but set it's parent key to NULL instead to break the relationship) Update other related data when a record is deleted (e.g. deleting an uploaded image file) The following are the potential ways to achieve these that I am aware of: Override the model's delete() method. While this sort of works, it is sidestepped when the records are deleted via a QuerySet. Also, every model's delete() must be overridden to make sure Django's code is never called and super() can't be called as it may use a QuerySet to delete child objects. Use signals. This seems to be ideal as they are called when directly deleting the model or deleting via a QuerySet. However, there is no possibility to prevent a child object from being deleted so it is not usable to implement ON CASCADE RESTRICT or SET NULL. Use a database engine that handles this properly (what does Django do in this case?) Wait until Django supports it (and live with bugs until then...) It seems like the first option is the only viable one, but it's ugly, throws the baby out with the bath water, and risks missing something when a new model/relation is added. Am I missing something? Any recommendations?

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• why does django-registration use an "activation window" for activating accounts?

  - by bharal

  i'm using django-registration, which is a django lib that helps with users registering on a django-built website. All well and dandy, except that it insists i have an "activation email" associated with all new users. It defaults to a 7 day window, after which, if someone signed up (and we then sent an email to confirm their email address) but didn't click on the link in the sent email within the 7 days, then they cannot sign up. Instead, they need to do the whole process all over again. I'm sure this is a concept that exists generally in web design, because why would django-registration make its own arbitrary signup process up? Anyway, the question is why? What do i gain by having the peace of mind knowing that all the users of my site are the kind of go-getters that click on registration emails with 7 days of receiving them? Why should i sleep easier knowing that my database isn't filled with users who, for whatever reason, clicked through to sign up but didn't actually want to sign up? cheers!

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• PHP mkdir issue!

  - by Richard González Alberto

  Hi, I trying to create some dirs like this: @mkdir("photos/$cat/$sku", 0777, true) it creates the first directory with 0777 permissions, but when it creates the second is uses 000 as it's perms, so it fails to create the third. A workaround this please? Thanks, Richard.

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• Python-MySQLdb problem: wrong ELF class: ELFCLASS32

  - by jsalonen

  As part of trying out django CMS (http://www.django-cms.org/), I'm struggling with getting Python-MySQLdb to work (http://pypi.python.org/pypi/MySQL-python/). I have installed Django CMS and all of its dependencies (Python 2.5, Django, django-south, MySQL server) I'm trying out the example code within Django CMS code with MySQL as chosen database type When I execute python manage.py syncdb, the following error occurs: django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: /root/.python-eggs/MySQL_python-1.2.3c1-py2.5-linux-i686.egg-tmp/_mysql.so: wrong ELF class: ELFCLASS32 I have been able to trace the problem specifically to python-mySQLdb (as also visible in the stack trace). Other than that, I am completely puzzled. I don't have a clue what ELFCLASS32 means, or what ELF class is anyway. I suspect that this error could have something to do with the fact that I am running 64-bit version of Debian 5 (on a VPS). Any good ideas how to troubleshoot?

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• django app using amazon aws s3 storage in stead of DB?

  - by farble1670

  new to python here so bear with me ... i'm looking at django for a rapid prototype to a photo sharing app with an amazon aws s3 storage back end. however, as far as i can tell, django is tailored toward the typical database MVC type of pattern. is there a way to for example provide a custom django model implementation that talks to s3 in stead of a DB? a custom DB engine? would either of these be practical, or am i looking in the wrong direction? thanks.

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• Storing hierarchical (parent/child) data in Python/Django: MPTT alternative?

  - by Parand

  I'm looking for a good way to store and use hierarchical (parent/child) data in Django. I've been using django-mptt, but it seems entirely incompatible with my brain - I end up with non-obvious bugs in non-obvious places, mostly when moving things around in the tree: I end up with inconsistent state, where a node and its parent will disagree on their relationship. My needs are simple: Given a node: find its root find its ancestors find its descendants With a tree: easily move nodes (ie. change parent) My trees will be smallish (at most 10k nodes over 20 levels, generally much much smaller, say 10 nodes with 1 or 2 levels). I have to think there has to be an easier way to do trees in python/django. Are there other approaches that do a better job of maintaining consistency?

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• SQL Select Permissions

  - by Brandi

  I have a database that I need to connect to and select from. I have an SQL Login, let's call it myusername. When I use the following, no SELECT permission shows up: SELECT * FROM fn_my_permissions ('dbo.mytable', 'OBJECT') GO Several times I tried things like: USE mydatabase GO GRANT SELECT TO myusername GO GRANT SELECT ON DATABASE::mydatabase TO myusername GO GRANT SELECT ON mytable TO myusername GO It says the queries execute successfully, but there is never any difference in the first query. What simple thing am I missing to grant database level select permissions. As a note, I made double sure it was the correct user, correct database, and I have already tried granting table level select permissions. So far I keep getting the error: SELECT permission denied on object 'mytable', database 'mydatabase', schema 'dbo'. Any ideas what I'm missing? Thanks in advance.

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• iPhone filesystem permissions POSIX-compliant?

  - by Seva Alekseyev

  Hi all, I'm trying to pass some files from one app to another. I communicate the path (via a custom URL). The target application cannot read the file, citing errno 13 (permission denied). I've checked the permissions on file - they're 0644 (O+R), the permissions on directories all the way up to the root are 755 (O+RX). From a POSIX perspective, the file should be readable to any process and any user. Yet it's not. Any ideas, please? I can think of some workarounds. I could use a Web service (upload, get a cookie, communicate the cookie to the other app, other app downloads). I could also pass the actual file data in the URL - unelegant, and probably subject to length limitations. Clipboard is not supported on iPhone OS 2 IIRC.

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