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  • Perl regex which grabs ALL double letter occurances in a line

    - by phileas fogg
    Hi all, still plugging away at teaching myself Perl. I'm trying to write some code that will count the lines of a file that contain double letters and then place parentheses around those double letters. Now what I've come up with will find the first ocurrance of double letters, but not any other ones. For instance, if the line is: Amp, James Watt, Bob Transformer, etc. These pioneers conducted many My code will render this: 19 Amp, James Wa(tt), Bob Transformer, etc. These pioneers conducted many The "19" is the count (of lines containing double letters) and it gets the "tt" of "Watt" but misses the "ee" in "pioneers". Below is my code: $file = '/path/to/file/electricity.txt'; open(FH, $file) || die "Cannot open the file\n"; my $counter=0; while (<FH>) { chomp(); if (/(\w)\1/) { $counter += 1; s/$&/\($&\)/g; print "\n\n$counter $_\n\n"; } else { print "$_\n"; } } close(FH); What am I overlooking? TIA!

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  • Fancy Box to Popup an HTML Page from One List Item in an Unordered List

    - by nicorellius
    I have an unordered list: <ul> <li><a id="fancy_popup" href="popup.html" class="fancybox"> Popup HTML Link</a></li> <li><a href="other.html">Other HTML Link</a></li> <li><a href="other.html">Other HTML Link</a></li> </ul> And I have a jQuery script: <script type="text/javascript"> $(document).ready(function() { $("#fancy_popup").fancybox({ transitionIn : 'elastic', transitionOut : 'elastic', easingIn : 'easeInSine', easingOut : 'easeOutSine', speedIn : 400, speedOut : 200, titlePosition : 'inside', titleFormat : 'document.write("Fancy Box Title");', cyclic : true }); }); </script> This jQuery Fancy Box script works elsewhere, with a div that has the id="fancy_popup" so I thought why not add it to the anchor directly in this case... I'm trying to figure out how to apply Fancy Box so that when someone clicks the Popup HTML link above, a Fancy Box window pops up, according to the script. I've tried variations with placing the id on the li, on the ul and manipulating the script for these selectors to no avail. Any help is appreciated.

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  • .Net regex: what is the word character \w?

    - by tanascius
    Simple question: What is the pattern for the word character \w in c#, .net? My first thought was that it matches [A-Za-z0-9_] and the documentation tells me: Character class Description Pattern Matches \w Matches any \w "I", "D", "A", "1", "3" word character. in "ID A1.3" which is not very helpful. And \w seems to match äöü, too. What else? Is there a better (exact) definition available?

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  • ColdFusion - pass regex backreference to function call

    - by stubotnik
    Hi, I'm using ColdFusion's reReplace() function for regular expression pattern replacement. I'd like to use a function call for the replacement string, and pass a matched backreference to it. Something like this: <cfset s = "STARTDATE_2010-05-07 00:05:00.0_ENDDATE" /> <cfset s = reReplace(s, "STARTDATE_([\s-.:0-9]*)_ENDDATE", dateAdd("h", 1, "\1")) /> But that fails because "The value of parameter 3, which is currently \1, must be a class java.util.Date value." Is there any other way to achieve this? Thanks, Stu

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  • need a regex for matching repeating lines of symbols (example: ------------- or *****************)

    - by Haroldo
    I want to be able to remove linebreaks etc that people make by using recurring characters, for example: **************************************************** ---------------------------------------------------- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ etc i'd like to not have to specify which characters it will match, maybe all that are NOT \w characters? also note they will not always start/end on a new line.. is this possible?

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  • Using regex to add leading zeroes

    - by hgpc
    I would like to add a certain number of leading zeroes (say up to 3) to all numbers of a string. For example: Input: /2009/5/song 01 of 3 Output: /2009/0005/song 0001 of 0003 What's the best way to do this with regular expressions?

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  • Matlab regex if statement

    - by Dan
    I want to have matlab take user input but accept both cases of a letter. For example I have: function nothing = checkGC(gcfile) if exist(gcfile) reply = input('file exists, would you like to overwrite? [Y/N]: ', 's'); if (reply == [Yy]) display('You have chosen to overwrite!') else $ Do nothing end end The if statement obviously doesn't work, but basically I want to accept a lowercase or uppcase Y. Whats the best way to do this?

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  • How to write this regex in PHP?

    - by user198729
    $url = "http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jspHUAWEI"; preg_match('/http:\/\/.*?\.jsp/', $url, $match); I want to retrieve http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp from $url,but the above returns more than I want: http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp How to do it properly?

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  • Replace URL with a link using regex in python

    - by user122750
    how do I convert some text to a link? Back in PHP, I used this piece of code that worked well for my purpose: $text = preg_replace("#(^|[\n ])(([\w]+?://[\w\#$%&~.\-;:=,?@\[\]+]*)(/[\w\#$%&~/.\-;:=,?@\[\]+]*)?)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\3</a>", $text); $text = preg_replace("#(^|[\n ])(((www|ftp)\.[\w\#$%&~.\-;:=,?@\[\]+]*)(/[\w\#$%&~/.\-;:=,?@\[\]+]*)?)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\3</a>", $text); I tried around in Python, but was unable to get it to work.. Would be very nice if someone could translate this to Python :)..

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  • Poor performance / speed of regex with lookahead

    - by Hugo Zaragoza
    I have been observing extremely slow execution times with expressions with several lookaheads. I suppose that this is due to underlying data structures, but it seems pretty extreme and I wonder if I do something wrong or if there are known work-arounds. The problem is determining if a set of words are present in a string, in any order. For example we want to find out if two terms "term1" AND "term2" are somewhere in a string. I do this with the expresion: (?=.*\bterm1\b)(?=.*\bterm2\b) But what I observe is that this is an order of magnitude slower than checking first just \bterm1\b and just then \bterm2\b This seems to indicate that I should use an array of patterns instead of a single pattern with lookaheads... is this right? it seems wrong... Here is an example test code and resulting times: public static void speedLookAhead() { Matcher m, m1, m2; boolean find; int its = 1000000; // create long non-matching string char[] str = new char[2000]; for (int i = 0; i < str.length; i++) { str[i] = 'x'; } String test = str.toString(); // First method: use one expression with lookaheads m = Pattern.compile("(?=.*\\bterm1\\b)(?=.*\\bterm2\\b)").matcher(test); long time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m.reset(test); find = m.find(); } time = System.currentTimeMillis() - time; System.out.println(time); // Second method: use two expressions and AND the results m1 = Pattern.compile("\\bterm1\\b").matcher(test); m2 = Pattern.compile("\\bterm2\\b").matcher(test); time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m1.reset(test); m2.reset(test); find = m1.find() && m2.find(); } time = System.currentTimeMillis() - time; System.out.println(time); } This outputs in my computer: 1754 150

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  • RegEx: difference between "(?:...) and normal parentheses

    - by N0thing
    >>> re.findall(r"(?:do|re|mi)+", "mimi") ['mimi'] >>> re.findall(r"(do|re|mi)+", "mimi") ['mi'] According to my understanding of the definitions, it should produce the same answer. The only difference between (...) and (?:...) should be whether or not we can use back-references later. Am I missing something? (...) Matches whatever regular expression is inside the parentheses, and indicates the start and end of a group; the contents of a group can be retrieved after a match has been performed, and can be matched later in the string with the \number special sequence, described below. To match the literals '(' or ')', use ( or ), or enclose them inside a character class: [(] [)]. (?:...) A non-capturing version of regular parentheses. Matches whatever regular expression is inside the parentheses, but the substring matched by the group cannot be retrieved after performing a match or referenced later in the pattern.

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  • Help with regex pulling XML data from response body in PHP

    - by spdaly
    I am working on a project that pulls data from JMS queue using PHP and Zend Framework. The HTTP client response is below. All I need is the XML string. I came up with /(.*)<\/RequestDetails/gs which tests ok on http://gskinner.com/RegExr/ but the preg_match call is returning an empty matches array. I'm going to continue to hunt around for a pattern, but thought I would post here as well. Thanks to all who read, etc... Steve UPDATE: I can't get the code to paste correctly. Here's a link to a pastbin: http://pastebin.com/rQxzcfSg

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  • Regex: Match words in sentence PHP

    - by Granit Luzhnica
    Hi, I have an array with words like $arr = arra("go", "walk", ...) I would like to replace these words with links f they are matched in sentences. But it should be only if they match exactly (for example "walk" should match "Walk" or "walk!" but not also "walking") And the replacement should be a simple link like: < a href='#walk' walk< /a Anybody Any idea?

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  • Java - Regex problem

    - by Yatendra Goel
    I have a list of urls of type http://www.abc.com/pk/ca and http://www.abc.com/pk Now, I want to find out only those urls that ends with /pk or /pk/ and don't have anything in between .com and /pk

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  • Java - Regex problem

    - by Yatendra Goel
    I have list of urls of types: http://www.abc.com/pk/etc http://www.abc.com/pk/etc/ http://www.abc.com/pk/etc/etc where etc can be anything. So I want to search only those urls that contains www.abc.com/pk/etc or www.abc.com/pk/etc/

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  • Converting paragraph tags with RegEx

    - by Joel
    I need to replace all <p> tags with <br /> tags within a string. The problem is that the <p> tag can have attributes in it , such as <p align="center"> so I want to delete all occurrences of an opening tag of a paragraph, no matter what attributes are in it, and replace them with <br />. I am using PHP and had no success getting to the right expression with the preg_replace function. Any help would be appreciated! Joel

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  • Regex replace using a repetitive capture

    - by Zac
    I have a table like: A | 1 A | 2 B | 1 B | 2 B | 3 I'm trying to transform it to look like this: A { 1 | 2 } B { 1 | 2 | 3 } I've come up with this which will match correctly I just can't figure out how to get the repeated capture out. (A|B)|(\d)(\r\n\1|(\d))*

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  • Simple Regex Question

    - by Jim B
    Hey Everyone, I need to search a bunch of files for anything that contains either "tblPayment" or "tblInvoice" I also want to match any tables named "tblPaymentMethod", "tblInvoiceItem", "tblInvoicePayment" Anybody care to help me out with how to write a regular expression for this? Thanks again!

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  • Regex in javascript for enum datatype of mysql

    - by himadri
    Hello, I am working with php and mysql. I have one dropdown box where I am asking datatype of mysql field. Now, I want to put javascript validation for it. I am confused with the enum datatype. I am using regular expression /^[']{1}[^',^\\]+[']{1}$/. This is for one single value of enum values. It is working fine but issue is when I put single quote or backslash with backslash, it is valid but this regular expression shows it as invalid. For eg, 'a'b' is invalid but 'a\'b' is valid.

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  • Passing values into regex match function

    - by Tim
    In python (it's a Django filter), I'm doing this: lReturn = re.sub(r'\[usecase:([ \w]+)]', r'EXTEND WITH <a href="/usecase/%s/\1/">\1</a>' % pCurrentProjectName, lReturn) I'd like to use a function instead of a string (so I can check that the usercase is a valid name), so it would change to this: def _match_function(matchobj): lMatch = matchobj.group(1) return "EXTEND WITH <a href='/usecase/%s/%s/'>%s</a>" % (pCurrentProjectName, lMatch, lMatch) lReturn = re.sub(r'\[usecase:([ \w]+)]', _match_function, lReturn) How do I get pCurrentProjectName into the _match_function() function?

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