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  • How can I extract the nth occurrence of a match in a Perl regex?

    - by Zaid
    Is it possible to extract the n'th match in a string of single-quoted words? use strict; use warnings; my $string1 = '\'I want to\' \'extract the word\' \'Perl\',\'from this string\''; my $string2 = '\'What about\',\'getting\',\'Perl\',\'from\',\'here\',\'?\''; sub extract_quoted { my ($string, $index) = @_; my ($wanted) = $string =~ /some_regex_using _$index/; return $wanted; } extract_wanted ($string1, 3); # Should return 'Perl', with quotes extract_wanted ($string2, 3); # Should return 'Perl', with quotes

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  • Regex for retrieving the parameter of the css url function...

    - by Kieron
    Hi, I'm trying to get the url portion of the following string: url(images/ui-bg_highlight-soft_75_cccccc_1x100.png) So the required part if images/ui-bg_highlight-soft_75_cccccc_1x100.png. Currently I've got this: url\((?<url>.*)\) But it seems to be choking on the following example: url(images/ui-bg_flat_0_aaaaaa_40x100.png) 50% 50% repeat-x; opacity: .30;filter:Alpha(Opacity=30) Which results in images/ui-bg_flat_0_aaaaaa_40x100.png) 50% 50% repeat-x; opacity: .30;filter:Alpha(Opacity=30... I'd like to make sure that it supports as many variations as possible (additional whitespace etc). Thanks! Kieron

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  • PHP-REGEX: accented letters matches non-accented ones, and visceversa. How to achive it?

    - by Lightworker
    I want to do the typical higlight code. So I have something like: $valor = preg_replace("/(".$_REQUEST['txt_search'].")/iu", "<span style='background-color:yellow; font-weight:bold;'>\\1</span>", $valor); Now, the request word could be something like "josé". And with it, I want "jose" or "JOSÉ" or "José" or ... highlighted too. With this expression, if I write "josé", it matches "josé" and "JOSÉ" (and all the case variants). It always matches the accented variants only. If I search "jose", it matches "JOSE", "jose", "Jose"... but not the accented ones. So I've partially what I want, cause I have case insensitive on accented and non-accented separately. I need it fully combined, wich means accent (unicode) insensitive, so I can search "jose", and highlight "josé", "josÉ", "José", "JOSE", "JOSÉ", "JoSé", ... I don't want to do a replace of accents on the word, cause when I print it on screen I need to see the real word as it comes. Any ideas? Thanks!

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  • What is wrong with this really really simple RegEx expression?

    - by Pure.Krome
    Hi folks, this one is really easy. I'm trying to create a Regular Expression that will result in a Successful Match when against the following text /default.aspx? So i tried the following... ^/default.aspx$ and it's failing to match it. Can someone help, please? (i'm guessing i'm screwing up becuase of the \ and the ? in the input expression).

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  • Regex to identify rows that do not contain exact number of occurences of quotemark character using Notepad++

    - by SamAspin
    I would like to be able to jump to rows that dont contain 6 quotemarks in a quoted-CSV file as it feels like a good way to identify broken rows. I think using a regular expression with Notepad++'s find features would be a sensible approach but I'm not sure how to pick the rows up. 6 quotemarks (") would suggest a complete row so I want to skip to any row that does not contain 6. Here is some sample data to play with, in this example its the 4th line I'd like to jump to "sam","mark","dave" "sam","mark","dave" "sam","mark","dave" "sam","mark"," dave" "sam","mark","dave" "sam","mark","dave"

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  • How to regex match a string of alnums and hyphens, but which doesn't begin or end with a hyphen?

    - by Shahar Evron
    I have some code validating a string of 1 to 32 characters, which may contain only alpha-numerics and hyphens ('-') but may not begin or end with a hyphen. I'm using PCRE regular expressions & PHP (albeit the PHP part is not really important in this case). Right now the pseudo-code looks like this: if (match("/^[\p{L}0-9][\p{L}0-9-]{0,31}$/u", string) and not match("/-$/", string)) print "success!" That is, I'm checking first that the string is of right contents, doesn't being with a '-' and is of the right length, and then I'm running another test to see that it doesn't end with a '-'. Any suggestions on merging this into a single PCRE regular expression? I've tried using look-ahead / look-behind assertions but couldn't get it to work.

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  • How to do regex HTML tag replace in MS SQL?

    - by timmerk
    I have a table in SQL Server 2005 with hundreds of rows with HTML content. Some of the content has HTML like: <span class=heading-2>Directions</span> where "Directions" changes depending on page name. I need to change all the <span class=heading-2> and </span> tags to <h2> and </h2> tags. I wrote this query to do content changes in the past, but it doesn't work for my current problem because of the ending HTML tag: Update ContentManager Set ContentManager.Content = replace(Cast(ContentManager.Content AS NVARCHAR(Max)), 'old text', 'new text') Does anyone know how I could accomplish the span to h2 replacing purely in T-SQL? Everything I found showed I would have to do CLR integration. Thanks!

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  • Regex for Matching First Alphanumeric Character skipping (The |An? )

    - by TheLizardKing
    I have a list of artists, albums and tracks that I want to sort using the first letter of their respective name. The issue arrives when I want to ignore "The ", "A ", "An " and other various non-alphanumeric characters (Talking to you "Weird Al" Yankovic and [dialog]). Django has a nice start '^(An?|The) +' but I want to ignore those and a few others of my choice. I am doing this in Django, using a MySQL db with utf8_bin collation.

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  • How can I match at the beginning of any line, including the first, with a Perl regex?

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)? EDIT: OK, it seems that the file has BOM information (3 chars) at the beginning and that's what's messing me up. Any way to get ^ to match anyway? EDIT: So in the end it works (as long as there's no BOM), but now it seems that the Perl documentation is wrong, since it says "after any newline"

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  • Help with Perl Regex Recursive Replace One Liner? Replace MySQL comments '--' with '#'

    - by NJTechie
    I have various SQL files with '--' comments and we migrated to the latest version of MySQL and it hates these comments. I want to replace -- with #. I am looking for a recursive, inplace replace one-liner. This is what I have : perl -p -i -e 's/--/# /g' `fgrep -- -- * ` A sample .sql file : use myDB; --did you get an error I get the following error : Unrecognized switch: --did (-h will show valid options). p.s : fgrep skipping 2 dashes was just discussed here if you are interested. Any help is appreciated.

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  • How to validate a domain name using Regex & Php?

    - by David
    Hi, I want a solution to validate only domain names not full urls, The following example is what i'm looking for: domain.com -> true domain.net/org/biz... -> true domain.co.uk -> true sub.domain.com -> true domain.com/folder -> false domµ*$ain.com -> false Thank you

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  • Can I improve this regex check for valid domain names?

    - by Josh
    So, I have been working on this domain name regular expression. So far, it seems to pick up domain names with SLDs and TLDs (with the optional ccTLD), but there is duplication of the TLD listing. Can this be refactored any further? params[:domain_name].downcase.strip.match(/^[a-z0-9\-]{2,63} \.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| (m[acdghklmnopqrstuvwxyz]|me|mil|mobi|museum)|(n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]) (\.((a[cdefgilmnoqrstuwxz]|aero|arpa)|(b[abdefghijmnorstvwyz]|biz)| (c[acdfghiklmnorsuvxyz]|cat|com|coop)|d[ejkmoz]|(e[ceghrstu]|edu)|f[ijkmor]| (g[abdefghilmnpqrstuwy]|gov)|h[kmnrtu]|(i[delmnoqrst]|info|int)| (j[emop]|jobs)|k[eghimnprwyz]|l[abcikrstuvy]| m[acdghklmnopqrstuvwxyz]|mil|mobi|museum)| (n[acefgilopruz]|name|net)|(om|org)| (p[aefghklmnrstwy]|pro)|qa|r[eouw]|s[abcdeghijklmnortvyz]| (t[cdfghjklmnoprtvwz]|travel)|u[agkmsyz]|v[aceginu]|w[fs]|y[etu]|z[amw]))?$/)

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  • .NET Regex - Replace multiple characters at once without overwriting?

    - by Everaldo Aguiar
    I'm implementing a c# program that should automatize a Mono-alphabetic substitution cipher. The functionality i'm working on at the moment is the simplest one: The user will provide a plain text and a cipher alphabet, for example: Plain text(input): THIS IS A TEST Cipher alphabet: A - Y, H - Z, I - K, S - L, E - J, T - Q Cipher Text(output): QZKL KL QJLQ I thought of using regular expressions since I've been programming in perl for a while, but I'm encountering some problems on c#. First I would like to know if someone would have a suggestion for a regular expression that would replace all occurrence of each letter by its corresponding cipher letter (provided by user) at once and without overwriting anything. Example: In this case, user provides plaintext "TEST", and on his cipher alphabet, he wishes to have all his T's replaced with E's, E's replaced with Y and S replaced with J. My first thought was to substitute each occurrence of a letter with an individual character and then replace that character by the cipherletter corresponding to the plaintext letter provided. Using the same example word "TEST", the steps taken by the program to provide an answer would be: 1 - replace T's with (lets say) @ 2 - replace E's with # 3 - replace S's with & 4 - Replace @ with E, # with Y, & with j 5 - Output = EYJE This solution doesn't seem to work for large texts. I would like to know if anyone can think of a single regular expression that would allow me to replace each letter in a given text by its corresponding letter in a 26-letter cipher alphabet without the need of splitting the task in an intermediate step as I mentioned. If it helps visualize the process, this is a print screen of my GUI for the program:

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  • How to extract part of the path and the ending file name with Regex?

    - by brasofilo
    I need to build an associative array with the plugin name and the language file it uses in the following sequence: /whatever/path/length/public_html/wp-content/plugins/adminimize/languages/adminimize-en_US.mo /whatever/path/length/public_html/wp-content/plugins/audio-tube/lang/atp-en_US.mo /whatever/path/length/public_html/wp-content/languages/en_US.mo /whatever/path/length/public_html/wp-content/themes/twentyeleven/languages/en_US.mo Those are the language files WordPress is loading. They are all inside /wp-content/, but with variable server paths. I'm looking only for those inside the plugins folder, grab the plugin folder name and the filename. Hipothetical case in PHP, where reg_extract_* functions are the parts I'm missing: $plugins = array(); foreach( $big_array as $item ) { $folder = reg_extract_folder( $item ); if( 'plugin' == $folder ) { // "folder-name-after-plugins-folder" $plugin_name = reg_extract_pname( $item ); // "ending-mo-file.mo" $file_name = reg_extract_fname( $item ); $plugins[] = array( 'name' => $plugin_name, 'file' => $file_name ); } } [update] Ok, so I was missing quite a basic function, pathinfo... :/ No problem to detect if /plugins/ is contained in the array. But what about the plugin folder name?

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  • How does this RegEx for parsing emails work in PHP?

    - by George Edison
    Okay, I have the following PHP code to extract an email address of the following two forms: Random Stranger <[email protected]> [email protected] Here is the PHP code: // The first example $sender = "Random Stranger <[email protected]>"; $pattern = '/([\w_-]*@[\w-\.]*)|.*<([\w_-]*@[\w-\.]*)>/'; preg_match($pattern,$sender,$matches,PREG_OFFSET_CAPTURE); echo "<pre>"; print_r($matches); echo "</pre><hr>"; // The second example $sender = "[email protected]"; preg_match($pattern,$sender,$matches,PREG_OFFSET_CAPTURE); echo "<pre>"; print_r($matches); echo "</pre>"; My question is... what is in $matches? It seems to be a strange collection of arrays. Which index holds the match from the parenthesis? How can I be sure I'm getting the email address and only the email address? Update: Here is the output: Array ( [0] => Array ( [0] => Random Stranger [1] => 0 ) [1] => Array ( [0] => [1] => -1 ) [2] => Array ( [0] => [email protected] [1] => 5 ) ) Array ( [0] => Array ( [0] => [email protected] [1] => 0 ) [1] => Array ( [0] => [email protected] [1] => 0 ) )

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • How do you replace many characters in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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