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• ssh without password does not work for some users

  - by joshxdr

  I have a new RHEL4 Linux box that I am using to copy data to old Solaris 2.6 and RHEL3 Linux boxes with scp. I have found that with the same setup, it works for some users but not for others. For user jane, this works fine: jane@host1$ ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/osborjo/.ssh/identity debug1: Offering public key: /mnt/home/osborjo/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: read PEM private key done: type RSA debug1: Authentication succeeded (publickey). for user jack it does not: jack@host1 ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/oper1/.ssh/identity debug1: Offering public key: /mnt/home/oper1/.ssh/id_rsa debug1: Authentications that can continue: publickey,password,keyboard-interactive I have looked at the permissions for all the keys and files, they look the same. Since I am using home directories mounted by NFS, the keys for both the remote host and the local host are in the same directory. This is how things look for jane: jane@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jane operator 394 Jan 27 16:28 authorized_keys -rw------- 1 jane operator 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jane operator 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jane operator 1205 Jan 27 16:46 known_hosts For user jack: jack@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jack engineer 394 Jan 27 16:28 authorized_keys -rw------- 1 jack engineer 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jack engineer 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jack engineer 1205 Jan 27 16:46 known_hosts As a last ditch effort, I copied the authorized_keys, id_rsa, and id_rsa.pub from jill to jack, and changed the username in authorized_keys and id_rsa.pub with vi. It still did not work. It seems there is something different between the two users but I cannot figure out what it is.

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• Correct MySQL username/password, but getting Access Denied error when run from script

  - by Nick

  I'm currently trying to run the following command from within a shell script. /usr/bin/mysql -u username -ppassword -h localhost database It works perfectly fine when executed manually, and not from within a script. When I try to execute a script that contains that command, I get the following error: ERROR 1045 (28000) at line 3: Access denied for user 'username'@'localhost' (using password: YES) I literally copied and pasted the working command into the script. Why the error? As a sidenote: the ultimate intent is to run the script with cron. EDIT: Here is a stripped down version of my script that I'm trying to run. You can ignore most of it up until the point where it connects to MySQL around line 19. #!/bin/sh #Run download script to download product data cd /home/dir/Scripts/Linux /bin/sh script1.sh #Run import script to import product data to MySQL cd /home/dir/Mysql /bin/sh script2.sh #Download inventory stats spreadsheet and rename it cd /home/dir /usr/bin/wget http://www.url.com/file1.txt mv file1.txt sheet1.csv #Remove existing export spreadsheet rm /tmp/sheet2.csv #Run MySQL queries in "here document" format /usr/bin/mysql -u username -ppassword -h localhost database << EOF --Drop old inventory stats table truncate table table_name1; --Load new inventory stats into table Load data local infile '/home/dir/sheet1.csv' into table table_name1 fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; --MySQL queries to combine product data and inventory stats here --Export combined data in spreadsheet format group by p.value into outfile '/tmp/sheet2.csv' fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; EOF EDIT 2: After some more testing, the issue is with the << EOF that is at the end of the command. This is there for the "here document". When removed, the command works fine. The problem is that I need << EOF there so that the MySQL queries will run.

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• HP Power Manager SMTP setup doesn't have space for username & password

  - by Martha

  Is there some way to configure HP Power Manager to not assume that there's an email server running locally? We recently acquired an HP T1500 G3 UPS, which we're trying to control using HP Power Manager 4.2. The main reason we wanted to get this particular UPS is because it says it's capable of sending notifications (of the "Yo, the power's out, you may want to look into it" type) via email, as opposed to SNMP. Turns out, that's not entirely true. The server is running Windows Server 2003. It is not running an email server of any sort - we do that via two different providers. Outlook email is provided by Verizon, and our SMTP email service is provided by a small local company. When we use CDO to send auto-generated notification emails, we have to provide the SMTP server name, port, username, and password. The HP Power Manager interface only allows us to enter the server name and the username. Thus, not surprisingly, the emails never go anywhere. Help?

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• Exclamation 403 forbidden for cgi-bin/ and cannot protect site with password

  - by gasgdasdgasdg

  First problem i have is i am getting 403 forbidden error for cgi-bin/ I have created a new /var/www2/ i can access it fine. php runs fine. Second problem is I cannot password protect it. i first tried doing htpasswd, it asks for login but everytime i login it keeps asking for new one. its getting frustrating, i have tried all tricks. and doesn't seem to work. this is a virtual host config inside sites-available. httpd.conf is empty but i have apache2.conf Code: NameVirtualHost 12.12.12.12. <VirtualHost 12.12.12.12> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /var/www2/cgi-bin/ <Directory "/var/www2/cgi-bin/"> AllowOverride Options Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch AddHandler cgi-script cgi pl Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost>

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• 40k Event Log Errors an hour Unknown Username or bad password

  - by ErocM

  I am getting about 200k of these an hour: An account failed to log on. Subject: Security ID: SYSTEM Account Name: TGSERVER$ Account Domain: WORKGROUP Logon ID: 0x3e7 Logon Type: 4 Account For Which Logon Failed: Security ID: NULL SID Account Name: administrator Account Domain: TGSERVER Failure Information: Failure Reason: Unknown user name or bad password. Status: 0xc000006d Sub Status: 0xc0000064 Process Information: Caller Process ID: 0x334 Caller Process Name: C:\Windows\System32\svchost.exe Network Information: Workstation Name: TGSERVER Source Network Address: - Source Port: - Detailed Authentication Information: Logon Process: Advapi Authentication Package: Negotiate Transited Services: - Package Name (NTLM only): - Key Length: 0 This event is generated when a logon request fails. It is generated on the computer where access was attempted. The Subject fields indicate the account on the local system which requested the logon. This is most commonly a service such as the Server service, or a local process such as Winlogon.exe or Services.exe. The Logon Type field indicates the kind of logon that was requested. The most common types are 2 (interactive) and 3 (network). The Process Information fields indicate which account and process on the system requested the logon. The Network Information fields indicate where a remote logon request originated. Workstation name is not always available and may be left blank in some cases. The authentication information fields provide detailed information about this specific logon request. - Transited services indicate which intermediate services have participated in this logon request. - Package name indicates which sub-protocol was used among the NTLM protocols. - Key length indicates the length of the generated session key. This will be 0 if no session key was requested. On my server... I changed my adminstrative username to something else and since then I've been inidated with these messages. I found on http://technet.microsoft.com/en-us/library/cc787567(v=WS.10).aspx that the 4 means "Batch logon type is used by batch servers, where processes may be executing on behalf of a user without their direct intervention." which really doesn't shed any light on it for me. I checked the services and they are all logging in as local system or network service. Nothing for administrator. Anyone have any idea how I tell where these are coming from? I would assume this is a program that is crapping out... Thanks in advance!

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• X509Certificate.CreateFromCertFile - the specified network password is not correct

  - by pcampbell

  I have a .NET application that I want to use as a client to call an SSL SOAP web service. I have been supplied with a valid client certificate called foo.pfx. There is a password on the certificate itself. I've located the certificate at the following location: C:\certs\foo.pfx To call the web service, I need to attach the client certificate. Here's the code: public X509Certificate GetCertificateFromDisk(){ try{ string certPath = ConfigurationManager.AppSettings["MyCertPath"].ToString(); //this evaluates to "c:\\certs\\foo.pfx". So far so good. X509Certificate myCert = X509Certificate.CreateFromCertFile(certPath); // exception is raised here! "The specified network password is not correct" return cert; } catch (Exception ex){ throw; } } It sounds like the exception is around the .NET application trying to read the disk. The method CreateFromCertFile is a static method that should create a new instance of X509Certificate. The method isn't overridden, and has only one argument: the path. When I inspect the Exception, I find this: _COMPlusExceptionCode = -532459699 Source=mscorlib Question: does anyone know what the cause of the exception "The specified network password is not correct" ?

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• Windows server 2003 default administrator password

  - by Jason Baker

  Sorry if this is an overly simplistic question, but I'm a bit stuck here. :) I need a windows machine for me to do some programming for class. Since I have my Macbook with me everywhere I go, I figured that it would be easiest to install a vm. And since I can get a copy of Windows server 2k3 for free via dreamspark, I thought I'd try to do that. Here's what happened though: I installed windows server (disk one). When the system booted up, vmware automatically installed VMWare tools and prompted me to restart. There was also a prompt to start the installation of disc 2, but I figured it would be better to restart before doing that. When the machine came back up, I was prompted to log in as the administrator. The problem is that I wasn't prompted to make an administrator account or password. Is there a default password I can use? I've tried all the obvious ones (blank, password, etc) and googling, but I didn't come up with anything.

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• ASP.NET Membership ChangePassword control - Need to check for previous password

  - by Steve

  Hi guys, I have a new table that hold old passwords, I need to check if there is a match. If there is a match I need the ChangePassword contol to NOT change the password. I need to tell the user that this password was used and pic a new one. I can't seem to be able to interrupt the control from changing the password. Maybe I am using the wrong event. Here is a piece of my code, or how I wish it would work. I appreciate all your help. protected void ChangePassword1_ChangedPassword(object sender, EventArgs e) { MembershipUser user = Membership.GetUser(); string usrName = ""; if (user != null) { string connStr = ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString; SqlConnection mySqlConnection = new SqlConnection(connStr); SqlCommand mySqlCommand = mySqlConnection.CreateCommand(); mySqlCommand.CommandText = "Select UserName from OldPasswords where UserName = 'test'"; mySqlConnection.Open(); SqlDataReader mySqlDataReader = mySqlCommand.ExecuteReader(CommandBehavior.Default); while (mySqlDataReader.Read()) { usrName = mySqlDataReader["UserName"].ToString(); if (usrName == user.ToString()) { Label1.Text = "Match"; } else { Label1.Text = "NO Match!"; } }

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• C# Active Directory - Check username / password

  - by Michael G

  I'm using the following code on Windows Vista Ultimate SP1 to query our active directory server to check the user name and password of a user on a domain. public Object IsAuthenticated() { String domainAndUsername = strDomain + @"\" + strUser; DirectoryEntry entry = new DirectoryEntry(_path, domainAndUsername, strPass); SearchResult result; try { //Bind to the native AdsObject to force authentication. DirectorySearcher search = new DirectorySearcher(entry) { Filter = ("(SAMAccountName=" + strUser + ")") }; search.PropertiesToLoad.Add("givenName"); // First Name search.PropertiesToLoad.Add("sn"); // Last Name search.PropertiesToLoad.Add("cn"); // Last Name result = search.FindOne(); if (null == result) { return null; } //Update the new path to the user in the directory. _path = result.Path; _filterAttribute = (String)result.Properties["cn"][0]; } catch (Exception ex) { return new Exception("Error authenticating user. " + ex.Message); } return user; } the target is using .NET 3.5, and compiled with VS 2008 standard I'm logged in under a domain account that is a domain admin where the application is running. The code works perfectly on windows XP; but i get the following exception when running it on Vista: System.DirectoryServices.DirectoryServicesCOMException (0x8007052E): Logon failure: unknown user name or bad password. at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() I've tried changing the authentication types, I'm not sure what's going on. See also: http://stackoverflow.com/questions/290548/c-validate-a-username-and-password-against-active-directory

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• django: cannot import settings, cannot login to admin, cannot change admin password

  - by xpanta

  Hi, It seems that I am completely lost here. Yesterday I noticed that I cannot login to the admin panel (don't use it much, so it's been some weeks since last login). I thought that I might have changed the admin password and now I can't remember it (though I doubt it). I tried django-admin.py changepassword (using django 1.2.1) but it said that 'changepassword' is unknown command (I have all the necessary imports in my settings.py. Admin interface used to work ok). Then I gave a django-admin.py validate. Then the hell begun. django-admin.py validate gave me this error: Error: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined. I then gave a set DJANGO_SETTINGS_MODULE=myproject.settings and then again a django-admin.py validate This is what I get now: Error: Could not import settings 'myproject.settings' (Is it on sys.path? Does it have syntax errors?): No module named myproject.settings and now I am lost. I tried django console and sys.path.append('c:\workspace') or sys.append('c:\workspace\myproject') but still get the same errors. I use windows 7 and my project dir is c:\workspace. I don't use a PYTHONPATH variable (although I tried setting it temporarily to C:\workspace but I still get the same error). I don't use Apache, just the django development server. What am I doing wrong? My web page works fine. I think that the fact that I can't login as admin is related to the previous import error, no? PS: I also tried this: http://coderseye.com/2007/howto-reset-the-admin-password-in-django.html but still I couldn't change admin password for some reason. Although I could create another admin user (with which I couldn't login).

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• Outlook Interop: Password protected PST file headache

  - by Ed Manet

  Okay, I have no problem identifying the .PST file using the Outlook Interop assemblies in a C# app. But as soon as I hit a password protected file, I am prompted for a password. We are in the process of disabling the use of PSTs in our organization and one of the steps is to unload the PST files from the users' Outlook profile. I need to have this app run silently and not prompt the user. Any ideas? Is there a way to create the Outlook.Application object with no UI and then just try to catch an Exception on password protected files? // create the app and namespace Application olApp = new Application(); NameSpace olMAPI = olApp.GetNamespace("MAPI"); // get the storeID of the default inbox string rootStoreID = olMAPI.GetDefaultFolder(OlDefaultFolders.olFolderInbox).StoreID; // loop thru each of the folders foreach (MAPIFolder fo in olMAPI.Folders) { // compare the first 75 chars of the storeid // to prevent removing the Inbox folder. string s1 = rootStoreID.Substring(1, 75); string s2 = fo.StoreID.Substring(1, 75); if (s1 != s2) { // unload the folder olMAPI.RemoveStore(fo); } } olApp.Quit();

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• Python-based password tracker (or dictionary)

  - by Arrieta

  Hello: Where we work we need to remember about 10 long passwords which need to change every so often. I would like to create a utility which can potentially save these passwords in an encrypted file so that we can keep track of them. I can think of some sort of dictionary passwd = {'host1':'pass1', 'host2':'pass2'}, etc, but I don't know what to do about encryption (absolutely zero experience in the topic). So, my question is really two questions: Is there a Linux-based utility which lets you do that? If you were to program it in Python, how would you go about it? A perk of approach two, would be for the software to update the ssh public keys after the password has been changed (you know the pain of updating ~15 tokens once you change your password). As it can be expected, I have zero control over the actual network configuration and the management of scp keys. I can only hope to provide a simple utility to me an my very few coworkers so that, if we need to, we can retrieve a password on demand. Cheers.

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• Saving Email/Password to Keychain in iOS

  - by Jason

  I'm very new to iOS development so forgive me if this is a newbie question. I have a simple authentication mechanism for my app that takes a user's email address and password. I also have a switch that says 'Remember me'. If the user toggles that switch on, I'd like to preserve their email/password so those fields can be auto-populated in the future. I've gotten this to work with saving to a plist file but I know that's not the best idea since the password is unencrypted. I found some sample code for saving to the keychain, but to be honest, I'm a little lost. For the function below, I'm not sure how to call it and how to modify it to save the email address as well. I'm guessing to call it would be: saveString(@"passwordgoeshere"); Thank you for any help!!! + (void)saveString:(NSString *)inputString forKey:(NSString *)account { NSAssert(account != nil, @"Invalid account"); NSAssert(inputString != nil, @"Invalid string"); NSMutableDictionary *query = [NSMutableDictionary dictionary]; [query setObject:(id)kSecClassGenericPassword forKey:(id)kSecClass]; [query setObject:account forKey:(id)kSecAttrAccount]; [query setObject:(id)kSecAttrAccessibleWhenUnlocked forKey:(id)kSecAttrAccessible]; OSStatus error = SecItemCopyMatching((CFDictionaryRef)query, NULL); if (error == errSecSuccess) { // do update NSDictionary *attributesToUpdate = [NSDictionary dictionaryWithObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemUpdate((CFDictionaryRef)query, (CFDictionaryRef)attributesToUpdate); NSAssert1(error == errSecSuccess, @"SecItemUpdate failed: %d", error); } else if (error == errSecItemNotFound) { // do add [query setObject:[inputString dataUsingEncoding:NSUTF8StringEncoding] forKey:(id)kSecValueData]; error = SecItemAdd((CFDictionaryRef)query, NULL); NSAssert1(error == errSecSuccess, @"SecItemAdd failed: %d", error); } else { NSAssert1(NO, @"SecItemCopyMatching failed: %d", error); } }

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• get random password with puppet function

  - by ninja-2

  I have a function that allow me to generate random password. My function is working well without a puppetmaster. When i tried with a master an error appear when I called the function : Error 400 on SERVER: bad value for range Here is my function module Puppet::Parser::Functions newfunction(:get_random_password, :type => :rvalue, :doc => <<-EOS Returns a random password. EOS ) do |args| raise(Puppet::ParseError, "get_random_password(): Wrong number of arguments " + "given (#{args.size} for 1)") if args.size != 1 specials = ((33..33).to_a + (35..38).to_a + (40..47).to_a + (58..64).to_a + (91..93).to_a + (95..96).to_a + (123..125).to_a).pack('U*').chars.to_a numbers = (0..9).to_a alphal = ('a'..'z').to_a alphau = ('A'..'Z').to_a length = args[0] CHARS = (alphal + specials + numbers + alphau) pwd = CHARS.sort_by { rand }.join[0...length] return pwd end end The function is called in both case with $pwd = get_random_password(10). When I specified the length directly in the function to 10 for example. the password is well generated in master mode. Have you any idea why i can't specify the lentgth value ? Thanks for any help.

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• sudo in Debian squeeze inside linux-vserver always wants password

  - by mark

  Every since I upgraded all my linux-vserver Debian guests from Lenny to Squeeze I've the apparent problem that whenever I want to use sudo it asks me for my password. Every time. I've configured sudo to have a timeout of 30 minutes: Defaults timestamp_timeout=30 . This has been configured when it was still Lenny (note: as suggested by EightBitTony I've also tried without this setting - no change). I've a hard time figuring out what the problem here is, since I think my configuration is right. I thought about it being a problem with the file used to record the timestamp, maybe a permission issue, but was unlucky to find any hard evidence. I've compared the contents of /var/lib/sudo/ between a working and a non-working system but couldn't spot any difference. The version of sudo used in both environments is 1.7.4p4-2.squeeze.3. My non-working system(s): find /var/lib/sudo/ -ls 17319289 4 drwx------ 4 root root 4096 Jan 1 1985 /var/lib/sudo/ 17319286 4 drwx------ 2 root mark 4096 Jan 1 1985 /var/lib/sudo/mark 17319312 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/6 17319361 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/9 17319490 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/10 17319326 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/4 17319491 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/2 A working system: find /var/lib/sudo -ls 2598921 4 drwx------ 5 root root 4096 Jan 1 1985 /var/lib/sudo 1999522 4 drwx------ 2 root mark 4096 Jan 1 1985 /var/lib/sudo/mark 2000781 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/8 1998998 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/17 1999459 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/26 1998930 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/24 2000771 4 -rw------- 1 root mark 40 Jun 25 11:39 /var/lib/sudo/mark/4 2000773 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/5 1999223 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/0 1998908 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/14 2000769 4 -rw------- 1 root mark 40 Jul 9 13:30 /var/lib/sudo/mark/2 2000770 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/3 2000782 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/9 2000778 4 -rw------- 1 root mark 40 Jul 8 00:11 /var/lib/sudo/mark/7 1998892 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/19 1999264 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/23 2000789 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/12 1999093 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/25 1998880 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/18 1998853 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/20 2000790 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/15 1998878 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/16 1998874 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/13 2000774 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/6 2000786 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/11 1998893 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/22 2000783 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/10 1998949 4 -rw------- 1 root mark 40 Jan 1 1985 /var/lib/sudo/mark/1 Despite the obvious (some up2date timestamps on the working system) I don't see anything wrong here, so it could be as well be a wrong track. Here's my current /etc/sudoers: # /etc/sudoers # # This file MUST be edited with the 'visudo' command as root. # # See the man page for details on how to write a sudoers file. # Defaults env_reset # Host alias specification # User alias specification User_Alias FULLADMIN = user1, user2, user3 # Cmnd alias specification # User privilege specification root ALL=(ALL) ALL FULLADMIN ALL = (ALL) ALL # Allow members of group sudo to execute any command # (Note that later entries override this, so you might need to move # it further down) %sudo ALL=(ALL) ALL # #includedir /etc/sudoers.d #Defaults always_set_home,timestamp_timeout=30

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• I saved PuTTY password when logging in, how to unsave it?

  - by xiaolaidd

  I mistakenly saved password first time logging to the server through PuTTY. How can I unsave the password? I don't want the password to be saved, instead I want to type the password everytime when I want to log in. Sorry that the question maybe confusing. The problem is I mistakenly click "yes" when PuTTY asked me to save the password or not. When logging in, it will prompt running "my username" and "my password". Apparently it will complain command not found. Just want to know where PuTTY stores my password so that I can delete it. Thanks,

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• How can I login to lightdm with password for fingerprint-enabled user after 12.10 upgrade?

  - by jxn

  Sorry for the long question. I have a laptop with ubuntu quantal 12.10, a fingerprint scanner, and a few active user accounts. When the machine boots up to lightdm, I get a prompt toenter my password or scan my finger print. Every now and then, fingerprint scanning just doesn't seem to work. Before the 12.10 upgrade, I was always able to enter my password for this user when fingerprint failed. Now, no matter what, I have to scan my prints to login as this user. If I try to login as a different user (fingerprint is not enabled for any others), I can see the password is typed out -- asterisks show in the password input box as I type them -- and get in. Not so for the fingerprint user. Any clues on how to figure out what's gone wrong?

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• Disable Password Complexity/Expiration etc. Policy on Windows Server 2008

  - by Sahil Malik

  Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). One of the things I like to do, for development environments only is to get rid of that excessively bothersome password policies. I like to have my password as something like p@ssword1, so they are easy to remember etc. etc. Obviously never do this in production. However, Windows Server 2008 comes with a password policy that expires my passwords every 90 days, and requires me to pick complex passwords, can’t reuse passwords etc. etc. Well here is how you disable password policy on a Windows Server 2008 machine - Run Group Policy Management (gpmc.msc) Expand to your domain, look for Forest\Domains\yourdomain\default domain policy. Go to the settings tab, right click on the tab, and choose “Edit”. This will open the Group Policy Management Editor, in which - Go to Computer Configuration\Policies\Windows Settings\Security Settings\Account Policies\Password Policy, and change the policy to whatever that suits you. Close everything, and run command prompt as administrator, and issue a “gpupdate /force” command to force the group policy update on the machine. Restart, and you’re done! :) Comment on the article ....

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• PhP Login/Register system [migrated]

  - by Marian

  I found this good tutorial on creating a login/register system using PhP and MySQL. The forum is around 5 years old (edited last year) but it can still be usefull. Beginner Simple Register-Login system There seems to be an issue with both login and register pages. <?php function register_form(){ $date = date('D, M, Y'); echo "<form action='?act=register' method='post'>" ."Username: <input type='text' name='username' size='30'><br>" ."Password: <input type='password' name='password' size='30'><br>" ."Confirm your password: <input type='password' name='password_conf' size='30'><br>" ."Email: <input type='text' name='email' size='30'><br>" ."<input type='hidden' name='date' value='$date'>" ."<input type='submit' value='Register'>" ."</form>"; } function register(){ $connect = mysql_connect("host", "username", "password"); if(!$connect){ die(mysql_error()); } $select_db = mysql_select_db("database", $connect); if(!$select_db){ die(mysql_error()); } $username = $_REQUEST['username']; $password = $_REQUEST['password']; $pass_conf = $_REQUEST['password_conf']; $email = $_REQUEST['email']; $date = $_REQUEST['date']; if(empty($username)){ die("Please enter your username!<br>"); } if(empty($password)){ die("Please enter your password!<br>"); } if(empty($pass_conf)){ die("Please confirm your password!<br>"); } if(empty($email)){ die("Please enter your email!"); } $user_check = mysql_query("SELECT username FROM users WHERE username='$username'"); $do_user_check = mysql_num_rows($user_check); $email_check = mysql_query("SELECT email FROM users WHERE email='$email'"); $do_email_check = mysql_num_rows($email_check); if($do_user_check > 0){ die("Username is already in use!<br>"); } if($do_email_check > 0){ die("Email is already in use!"); } if($password != $pass_conf){ die("Passwords don't match!"); } $insert = mysql_query("INSERT INTO users (username, password, email) VALUES ('$username', '$password', '$email')"); if(!$insert){ die("There's little problem: ".mysql_error()); } echo $username.", you are now registered. Thank you!<br><a href=login.php>Login</a> | <a href=index.php>Index</a>"; } switch($act){ default; register_form(); break; case "register"; register(); break; } ?> Once pressed the register button the page does nothing, fields are erased and no data is added inside the database or error given. I tought that the problem might be the switch($act){ part so I removed it and changed the page using a require require('connect.php'); where connect.php is <?php mysql_connect("localhost","host","password"); mysql_select_db("database"); ?> Removed the function register_form(){ and echo part turning it into an HTML code: <form action='register' method='post'> Username: <input type='text' name='username' size='30'><br> Password: <input type='password' name='password' size='30'><br> Confirm your password: <input type='password' name='password_conf' size='30'><br> Email: <input type='text' name='email' size='30'><br> <input type='hidden' name='date' value='$date'> <input type='submit' name="register" value='Register'> </form> And instead of having a function register(){ I replaced it with a if($register){ So when the Register button is pressed it runs the php code, but this edit doesn't seem to work either. So what can the problem be? If needed I can re-add this code on my Domain The login page has the same issue, nothing happens when the button is pressed beside emptying the fields.

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• How do I make the PolicyKit authentication agent window not dissapear when I enter faulty password in Ubuntu 12.04?

  - by Petar

  As far as I remember in previous versions of Ubuntu, whenever authentication was required and when the PolicyKit authentication agent window was presented, it stayed there even after I would enter a faulty password. But now, whenever I make a mistake, the window is closed immediately. I find this behaviour irritating. For instance I use Synaptic rather frequently, and I prefer to start it using Synapse. I press Ctrl+Space to invoke Synapse, then I enter "syn" (s-shows SMplayer, sy- shows System Monitor) and than I press Enter so that Synaptic is invoked. Then I'm presented with the PolicyKit authentication agent window. As my password is rather complicated - using special characters and big letters, it's easy to make a mistake. If I do make a mistake while typing my password, I'm forced to redo all the previous steps. It's annoying as hell, knowing that this is not the way the PolicyKit authentication agent window behaved before. It used to warn me that the password was not correct and than wait for the correct input. I'm not sure if it allowed trying for the correct password indefinitely, or it was limited to 3 retries which is a much saner behaviour than the current one. I'm using Gnome 3, but the same thing happens in Unity too, although the window looks different.

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• After locking the screen in Ubuntu 14.04, password is not accepted, How can it be fixed?

  - by Itai Ganot

  I'm running Ubuntu 14.04 fully updated on my laptop. Since the last update every time I lock the screen (when leaving my room for example) - when I get back and input my password, it is not accepted even though it's the correct password, the error I get is: Password incorrect, please try again I found that clicking the "Switch Account" fixes the issue but it is very annoying, if you know any way to fix it, it would be nice. Thanks in advance

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• How do I include a password with SSH command? (want to make shell script)

  - by Evan

  I'm trying to SSH to a server on startup with a .sh script, but that will require me to enter the password for the account on the server that I'm SSHing to. I did some RTFMing, and I see in "-o" that it has "PasswordAuthentication" but I'm not sure how or if I could use that option. As this will be in a shell script, obviously I'd like to have the password in that file, or in any case not have to enter in the password manually every time the script runs.

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• How to enter the Default Keyring password via the command line?

  - by Jerkofalltrades

  Is there a way to enter the default keyring password using the command line? For instance: You have a remote setup of Ubuntu 10.10 thats set to auto login. You don't want to remove the keyring password. All right the system boots up and logs in automatically, then asks for the keyring password now at this point you can create ssh connections but you can't remote desktop. What can you do to enter the keyring password at this point? Also, to better clarify, this is from a remote connection using the command line.

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• is it possible to ssh into ubuntu server with keys and from another computer using password?

  - by Sandro Dzneladze

  I have ubuntu server at home, and I use SSH keys to log in via terminal from my laptop. Rarely, but mostly from work, I need to access this server, but I dont want to copy keys on my work laptop - Id rather just use plain password for that. So if I enable password log in from ssh config file, it will ask me password on my laptop too even though it contains keys, right? Is there a way to stop this behavior? Thanks.

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• ADODB Connection String: Workgroup Information file is Missing?

  - by Mohgeroth

  I have a few data sources in access that I need to connect to programatically to do things with behind the scenes and keep visibility away from users. Said datasource has a password 'pass' as I'm going to call it here. Using this connection method I get an error attempting to use the open method Dim conn as ADODB.Connection Set ROBBERS.conn = New ADODB.Connection conn.open "Provider=Microsoft.Jet.OLEDB.4.0;" _ & "Data Source=\\pep-home\projects\billing\autobilling\DPBilling2.mdb;" _ & "Jet OLEDB:Database Password=pass;", "admin", "pass" "Cannot start your application. The workgroup information file is missing or opened exclusively by another user." Due to planning to move into 2007, we are not using nor have ever used a workgroup identification file through access. The database password on the data source was set through the Set Databa Password which had to be done on an exclusive open. Ive spent a good while changing around my connection options, where to put the passwords etc and either cannot find the right format, or (why I'm asking here) I think there may be some other unknown that I must setup to do this. Anyone out there got some useful information?

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