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  • Visual Studio 2010 - Crash/Problems on the keyboard (Keys)

    - by Ph.E
    Camarades, My Visual Studio is in trouble in keyboard. I am working normally, when suddenly my keyboard loses its configuration, so where is the "" becomes "/". Someone can tell me what would be a possible solution? (Yes, I know something is hazy). Or has left some Pachter fix for problems like this. Grateful for any help. Success for all. Microsoft Visual Studio 2010 Version 10.0.30319.1 RTMRel

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  • Postgres: Find table foreign keys (Faster alternative)

    - by Najera
    Is there faster alternative to this: Take almost 1 minute in our server. SELECT tc.constraint_name, tc.table_name, kcu.column_name, ccu.table_name AS foreign_table_name, ccu.column_name AS foreign_column_name FROM information_schema.table_constraints AS tc JOIN information_schema.key_column_usage AS kcu ON tc.constraint_name = kcu.constraint_name JOIN information_schema.constraint_column_usage AS ccu ON ccu.constraint_name = tc.constraint_name WHERE constraint_type = 'FOREIGN KEY' AND tc.table_name='mytable'; Maybe using pg_class metadata?, thanks.

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  • MS SQL: How to get the newest date in a table with several equal keys

    - by Qohelet
    Unfortunately my knowledge related to statements like "group by" and "having" is quite limited, so hopefully you can help me: I have a view -here's an excerpt- (if we have some Europeans here - it's v021 of Winline/Mesonic): ID | Artikelbezeichnung1 | Bez2 | mesoyear _____________________________________________________________________ 1401MA70 | Marga ,Saracena grigio,1S,33,3/33,3 | Marazzi | 1344 1401MA70 | Marga ,Saracena grigio,1S,33,3/33,3 | Marazzi | 1356 1401MA70 | Marga ,Saracena grigio,1S,33,3/33,3 | Marazzi | 1356 1401MA71 | Marga ,Saracena beige,1S,33,3/33,3 | Marazzi | 1344 1401MA71 | Marga ,Saracena beige,1S,33,3/33,3 | Marazzi | 1356 1401MA71 | Marga ,Saracena beige,1S,33,3/33,3 | Marazzi | 1356 2401CR13 | Crista,Mahon rojo,1S,33,3/33,3 | Cristacer | 1332 2401CR13 | Crista,Mahon rojo,1S,33,3/33,3 | Cristacer | 1344 So the ID is not unique and I just need the one with the highest val in "mesoyear". My fist solution was: Select c015 as ID, c003 as Artikelbezeichnung1, c074 as Bez2, mesoyear from CWLDATEN_91.dbo.v021 group by c015 having mesoyear = max(mesoyear) But this doesn't work at all... Msg 8121, Level 16, State 1, Line 8 Column 'CWLDATEN_91.dbo.v021.mesoyear' is invalid in the HAVING clause because it is not contained in either an aggregate function or the GROUP BY clause. So I just removed the "having" statement and it went "better": Msg 8120, Level 16, State 1, Line 2 Column 'CWLDATEN_91.dbo.v021.c003' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. So I tried to remove the error just by adding things to the "group by". And it worked. Select c015 as ID, c003 as Artikelbezeichnung1, c074 as Bez2, max(mesoyear) from CWLDATEN_91.dbo.v021 group by c015,c003,c074 gives me exactly what I want. But the correct Select contains about 24 columns and some calculations as well. The problem can't be solved just by adding all the columns to the "group by"...? Can someone please help me to find a proper command? Thank you!

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  • xmodmap modifications aren't enough - anything else I can do?

    - by Codemonkey
    I'm using an Apple keyboard which has some annoyances compared to other keyboards. Namely, the Alt_L and Super_L keys are swapped, and the bar and less keys are swapped ("|" and "<"). I've written an Xmodmap file to swap the keys back: keycode 49 = less greater less greater onehalf threequarters keycode 64 = Super_L NoSymbol Super_L keycode 94 = bar section bar section brokenbar paragraph keycode 108 = Super_R NoSymbol Super_R keycode 133 = Alt_L Meta_L Alt_L Meta_L keycode 134 = Alt_R Meta_R Alt_R Meta_R I did this by identifying the keys using xev and the default modmap xmodmap -pke and swapping the keycodes. xev now identifies all my keys as correct, which is awesome! I can also use the correct keys to type the bar and less than symbols. (I followed this answer on askubuntu: How do I remap certain keys?) But it seems the change isn't very deep. For instance, the Super key is now broken in the Compiz Settings Manager. No shortcuts involving the Super key works (but the Alt key does). Also the settings dialog for Gnome Do doesn't heed the changes in xmodmap, and I can't open the Gnome Do window anymore if I use any of the remapped keys. So to summarize, everything broke. I would like a deeper way of telling Ubuntu (or any other Linux distro for that matter) which keys are which on the keyboard. Is there a way to edit the Keyboard Layout directly? I'm using the Norwegian Bokmål keyboard layout. Does it reside in a file somewhere I could edit? Any comments, previous experiences or relevant stray thoughts would be greatly appreciated - Thanks

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  • Erlang, SSH and authorized_keys

    - by Roberto Aloi
    Playing with the ssh and public_key application in Erlang, I've discovered a nice feature. I was trying to connect to my running Erlang SSH daemon by using a rsa key, but the authentication was failing and I was prompted for a password. After some debugging and tracing (and a couple of coffees), I've realized that, for some weird reason, a non valid key for my user was there. The authorized_keys file contained two keys. The wrong one was at some point in the file, while the correct one was appended at the end of the file. Now, the Erlang SSH application, when diffing the provided key with the ones contained in the authorized_keys, it was finding the first entry (completely ignoring the second on - the correct one). Then, it was switching to different authentication mechanism (at first it was trying dsa instead of rsa and then it was prompting for a password). The question is: Is this behavior intended or should the SSH server check for multiple entries for the same user in the *authorized_keys* file? Is this a generic SSH behaviour or it's just specific to the Erlang implementation?

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  • How to put foreign key constraints on a computed fields in sql server?

    - by Asaf R
    Table A has a computed field called Computed1. It's persisted and not null. Also, it always computes to an expression which is char(50). It's also unique and has a unique key constraint on it. Table B has a field RefersToComputed1, which should refer to a valid Computed1 value. Trying to create a foreign key constraint on B's RefersToComputed1 that references A' Computed1 leads to the following error: Error SQL01268: .Net SqlClient Data Provider: Msg 1753, Level 16, State 0, Line 1 Column 'B.RefersToComputed1' is not the same length or scale as referencing column 'A.Computed1' in foreign key 'FK_B_A'. Columns participating in a foreign key relationship must be defined with the same length and scale. Q: Why is this error created? Are there special measures needed for foreign keys for computed columns, and if so what are they? Summary: The specific problem rises from computed, char based, fields being varchar. Hence, Computed1 is varchar(50) and not char(50). It's best to have a cast surrounding a computed field's expression to force it to a specific type. Credit goes to Cade Roux for this tip.

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  • BitShifting with BigIntegers in Java

    - by ThePinkPoo
    I am implementing DES Encryption in Java with use of BigIntegers. I am left shifting binary keys with Java BigIntegers by doing the BigInteger.leftShift(int n) method. Key of N (Kn) is dependent on the result of the shift of Kn-1. The problem I am getting is that I am printing out the results after each key is generated and the shifting is not the expected out put. The key is split in 2 Cn and Dn (left and right respectively). I am specifically attempting this: "To do a left shift, move each bit one place to the left, except for the first bit, which is cycled to the end of the block. " It seems to tack on O's on the end depending on the shift. Not sure how to go about correcting this. Results: c0: 11110101010100110011000011110 d0: 11110001111001100110101010100 c1: 111101010101001100110000111100 d1: 111100011110011001101010101000 c2: 11110101010100110011000011110000 d2: 11110001111001100110101010100000 c3: 1111010101010011001100001111000000 d3: 1111000111100110011010101010000000 c4: 111101010101001100110000111100000000 d4: 111100011110011001101010101000000000 c5: 11110101010100110011000011110000000000 d5: 11110001111001100110101010100000000000 c6: 1111010101010011001100001111000000000000 d6: 1111000111100110011010101010000000000000 c7: 111101010101001100110000111100000000000000 d7: 111100011110011001101010101000000000000000 c8: 1111010101010011001100001111000000000000000 d8: 1111000111100110011010101010000000000000000 c9: 111101010101001100110000111100000000000000000 d9: 111100011110011001101010101000000000000000000 c10: 11110101010100110011000011110000000000000000000 d10: 11110001111001100110101010100000000000000000000 c11: 1111010101010011001100001111000000000000000000000 d11: 1111000111100110011010101010000000000000000000000 c12: 111101010101001100110000111100000000000000000000000 d12: 111100011110011001101010101000000000000000000000000 c13: 11110101010100110011000011110000000000000000000000000 d13: 11110001111001100110101010100000000000000000000000000 c14: 1111010101010011001100001111000000000000000000000000000 d14: 1111000111100110011010101010000000000000000000000000000 c15: 11110101010100110011000011110000000000000000000000000000 d15: 11110001111001100110101010100000000000000000000000000000

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  • how can i set up a uniqueness constraint in mysql for columns that can be null?

    - by user299689
    I know that in MySQL, UNIQUE constraits don't treat NULL values as equal. So if I have a unique constraint on ColumnX, then two separate rows can have values of NULL for ColumnX and this wouldn't violate the constraint. How can I work around this? I can't just set the value to an arbitrary constant that I can flag, because ColumnX in my case is actually a foreign key to another table. What are my options here? Please note that this table also has an "id" column that is its primary key. Since I'm using Ruby on Rails, it's important to keep this id column as the primary key. Note 2: In reality, my unique key encompasses many columns, and some of them have to be null, because they are foreign keys, and only one of them should be non-null. What I'm actually trying to do is to "simulate" a polymorphic relationship in a way that keep referential integrity in the db, but using the technique outlined in the first part of the question asked here: http://stackoverflow.com/questions/922184/why-can-you-not-have-a-foreign-key-in-a-polymorphic-association

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  • Sort queryset by a generic foreign key (django)?

    - by thornomad
    I am using Django's comment framework which utilizes generic foreign keys. Question: How do I sort a given model's queryset by their comment count using the generic foreign key lookup? Reading the django docs on the subject it says one needs to calculate them not using the aggregation API: Django's database aggregation API doesn't work with a GenericRelation. [...] For now, if you need aggregates on generic relations, you'll need to calculate them without using the aggregation API. The only way I can think of, though, would be to iterate through my queryset, generate a list with content_type and object_id's for each item, then run a second queryset on the Comment model filtering by this list of content_type and object_id ... sort the objects by the count, then re-create a new queryset in this order by pulling the content_object for each comment ... This just seems wrong and I'm not even sure how to pull it off. Ideas? Someone must have done this before. I found this post online but it requires me handwriting SQL -- is that really necessary ?

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  • Left and right keys acting crazy on Ubuntu 10.10 Netbook Remix?

    - by Stephanie
    Hi guys, I just installed Ubuntu 10.10 Netbook Remix on my HP Mini 1000. Everything worked fine right up until I tried typing - apparently the left and right arrow keys on my keyboard are uncontrollable. Everything I type ends up looking messed up because the left and right keys keep automatically inserting themselves into everything I type. This also happens when I click on, say, "File" on Firefox. It starts rotating between all the different menu options even though I'm not pressing anything on the keyboard. Does anyone have any idea what's going on? Is this a problem with the keyboard itself?

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  • Would it be practical/secure to import my GPG keys into (Open)SSH?

    - by InkBlend
    I know a bit about computer security, and well as about the concept of public and private keys. I also know that both GPG and (Open)SSH use the public/private key system. My question is, is there any reason that I would not want to use my GPG keys as authentication for SSH? Please note that, while a have a little bit more experience with Linux, GPG, and SSH than the average computer user, I am by no means an expert. Please be patient and point out any mistakes that you might see.

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  • OperationalError: foreign key mismatch

    - by Niek de Klein
    I have two tables that I'm filling, 'msrun' and 'feature'. 'feature' has a foreign key pointing to the 'msrun_name' column of the 'msrun' table. Inserting in the tables works fine. But when I try to delete from the 'feature' table I get the following error: pysqlite2.dbapi2.OperationalError: foreign key mismatch From the rules of foreign keys in the manual of SQLite: - The parent table does not exist, or - The parent key columns named in the foreign key constraint do not exist, or - The parent key columns named in the foreign key constraint are not the primary key of the parent table and are not subject to a unique constraint using collating sequence specified in the CREATE TABLE, or - The child table references the primary key of the parent without specifying the primary key columns and the number of primary key columns in the parent do not match the number of child key columns. I can see nothing that I'm violating. My create tables look like this: DROP TABLE IF EXISTS `msrun`; -- ----------------------------------------------------- -- Table `msrun` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `msrun` ( `msrun_name` VARCHAR(40) PRIMARY KEY NOT NULL , `description` VARCHAR(500) NOT NULL ); DROP TABLE IF EXISTS `feature`; -- ----------------------------------------------------- -- Table `feature` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `feature` ( `feature_id` VARCHAR(40) PRIMARY KEY NOT NULL , `intensity` DOUBLE NOT NULL , `overallquality` DOUBLE NOT NULL , `charge` INT NOT NULL , `content` VARCHAR(45) NOT NULL , `msrun_msrun_name` VARCHAR(40) NOT NULL , CONSTRAINT `fk_feature_msrun1` FOREIGN KEY (`msrun_msrun_name` ) REFERENCES `msrun` (`msrun_name` ) ON DELETE NO ACTION ON UPDATE NO ACTION); CREATE UNIQUE INDEX `id_UNIQUE` ON `feature` (`feature_id` ASC); CREATE INDEX `fk_feature_msrun1` ON `feature` (`msrun_msrun_name` ASC); As far as I can see the parent table exists, the foreign key is pointing to the right parent key, the parent key is a primary key and the foreign key specifies the primary key column. The script that produces the error: from pysqlite2 import dbapi2 as sqlite import parseFeatureXML connection = sqlite.connect('example.db') cursor = connection.cursor() cursor.execute("PRAGMA foreign_keys=ON") inputValues = ('example', 'description') cursor.execute("INSERT INTO `msrun` VALUES(?, ?)", inputValues) featureXML = parseFeatureXML.Reader('../example_scripts/example_files/input/featureXML_example.featureXML') for feature in featureXML.getSimpleFeatureInfo(): inputValues = (featureXML['id'], featureXML['intensity'], featureXML['overallquality'], featureXML['charge'], featureXML['content'], 'example') # insert the values into msrun using ? for sql injection safety cursor.execute("INSERT INTO `feature` VALUES(?,?,?,?,?,?)", inputValues) connection.commit() for feature in featureXML.getSimpleFeatureInfo(): cursor.execute("DELETE FROM `feature` WHERE feature_id = ?", (str(featureXML['id']),))

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  • Foreign Key Relationships and "belongs to many"

    - by jan
    I have the following model: S belongs to T T has many S A,B,C,D,E (etc) have 1 T each, so the T should belong to each of A,B,C,D,E (etc) At first I set up my foreign keys so that in A, fk_a_t would be the foreign key on A.t to T(id), in B it'd be fk_b_t, etc. Everything looks fine in my UML (using MySQLWorkBench), but generating the yii models results in it thinking that T has many A,B,C,D (etc) which to me is the reverse. It sounds to me like either I need to have A_T, B_T, C_T (etc) tables, but this would be a pain as there are a lot of tables that have this relationship. I've also googled that the better way to do this would be some sort of behavior, such that A,B,C,D (etc) can behave as a T, but I'm not clear on exactly how to do this (I will continue to google more on this) What do you think is the better solution? UML: Here's the DDL (auto generated). Just pretend that there is more than 3 tables referencing T. -- ----------------------------------------------------- -- Table `mydb`.`T` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `mydb`.`T` ( `id` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`S` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `mydb`.`S` ( `id` INT NOT NULL AUTO_INCREMENT , `thing` VARCHAR(45) NULL , `t` INT NOT NULL , PRIMARY KEY (`id`) , INDEX `fk_S_T` (`id` ASC) , CONSTRAINT `fk_S_T` FOREIGN KEY (`id` ) REFERENCES `mydb`.`T` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`A` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `mydb`.`A` ( `id` INT NOT NULL AUTO_INCREMENT , `T` INT NOT NULL , `stuff` VARCHAR(45) NULL , `bar` VARCHAR(45) NULL , `foo` VARCHAR(45) NULL , PRIMARY KEY (`id`) , INDEX `fk_A_T` (`T` ASC) , CONSTRAINT `fk_A_T` FOREIGN KEY (`T` ) REFERENCES `mydb`.`T` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`B` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `mydb`.`B` ( `id` INT NOT NULL AUTO_INCREMENT , `T` INT NOT NULL , `stuff2` VARCHAR(45) NULL , `foobar` VARCHAR(45) NULL , `other` VARCHAR(45) NULL , PRIMARY KEY (`id`) , INDEX `fk_A_T` (`T` ASC) , CONSTRAINT `fk_A_T` FOREIGN KEY (`T` ) REFERENCES `mydb`.`T` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`C` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `mydb`.`C` ( `id` INT NOT NULL AUTO_INCREMENT , `T` INT NOT NULL , `stuff3` VARCHAR(45) NULL , `foobar2` VARCHAR(45) NULL , `other4` VARCHAR(45) NULL , PRIMARY KEY (`id`) , INDEX `fk_A_T` (`T` ASC) , CONSTRAINT `fk_A_T` FOREIGN KEY (`T` ) REFERENCES `mydb`.`T` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB;

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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  • Cannot add repository key

    - by William Anthony
    I just installed my new laptop with ubuntu 12.04 and when I'm trying to add key, there is a "network unreachable" error. william@ubuntu:~$ gpg --keyserver hkp://keys.gnupg.net --recv-keys 1C4CBDCDCD2EFD2A gpg: requesting key CD2EFD2A from hkp server keys.gnupg.net ?: keys.gnupg.net: Network is unreachable gpgkeys: HTTP fetch error 7: couldn't connect: Network is unreachable gpg: no valid OpenPGP data found. gpg: Total number processed: 0 I'm so sure the keyserver is not down, because I tried it again at my old laptop running ubuntu 11.04 william@william:~$ gpg --keyserver hkp://keys.gnupg.net --recv-keys 1C4CBDCDCD2EFD2A gpg: requesting key CD2EFD2A from hkp server keys.gnupg.net gpg: key CD2EFD2A: "Percona MySQL Development Team <[email protected]>" not changed gpg: Total number processed: 1 gpg: unchanged: 1 Is this a bug?

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  • MySQL: Creating table with FK error (errno 150)

    - by Peter Bailey
    I've tried searching on this error and nothing I've found helps me, so I apologize in advance if this is a duplicate and I'm just too dumb to find it. I've created a model with MySQL Workbench and am now attempting to install it to a mysql server. Using File Export Forward Engineer SQL CREATE Script... it outputs a nice big file for me, with all the settings I ask for. I switch over to MySQL GUI Tools (the Query Browser specifically) and load up this script (note that I'm going form one official MySQL tool to another). However, when I try to actually execute this file, I get the same error over and over SQLSTATE[HY000]: General error: 1005 Can't create table './srs_dev/location.frm' (errno: 150) "OK", I say to myself, something is wrong with the location table. So I check out the definition in the output file. SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; -- ----------------------------------------------------- -- Table `state` -- ----------------------------------------------------- DROP TABLE IF EXISTS `state` ; CREATE TABLE IF NOT EXISTS `state` ( `state_id` INT NOT NULL AUTO_INCREMENT , `iso_3166_2_code` VARCHAR(2) NOT NULL , `name` VARCHAR(60) NOT NULL , PRIMARY KEY (`state_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `brand` -- ----------------------------------------------------- DROP TABLE IF EXISTS `brand` ; CREATE TABLE IF NOT EXISTS `brand` ( `brand_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(45) NOT NULL , `domain` VARCHAR(45) NOT NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , PRIMARY KEY (`brand_id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `location` -- ----------------------------------------------------- DROP TABLE IF EXISTS `location` ; CREATE TABLE IF NOT EXISTS `location` ( `location_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `name` VARCHAR(255) NOT NULL , `address_line_1` VARCHAR(255) NULL , `address_line_2` VARCHAR(255) NULL , `city` VARCHAR(100) NULL , `state_id` TINYINT UNSIGNED NULL DEFAULT NULL , `postal_code` VARCHAR(10) NULL , `phone_number` VARCHAR(20) NULL , `fax_number` VARCHAR(20) NULL , `lat` DECIMAL(9,6) NOT NULL , `lng` DECIMAL(9,6) NOT NULL , `contact_url` VARCHAR(255) NULL , `brand_id` TINYINT UNSIGNED NOT NULL , `summer_hours` VARCHAR(255) NULL , `winter_hours` VARCHAR(255) NULL , `after_hours_emergency` VARCHAR(255) NULL , `image_file_name` VARCHAR(100) NULL , `manager_name` VARCHAR(100) NULL , `manager_email` VARCHAR(255) NULL , `created_date` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`location_id`) , CONSTRAINT `fk_location_state` FOREIGN KEY (`state_id` ) REFERENCES `state` (`state_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION, CONSTRAINT `fk_location_brand` FOREIGN KEY (`brand_id` ) REFERENCES `brand` (`brand_id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; CREATE INDEX `fk_location_state` ON `location` (`state_id` ASC) ; CREATE INDEX `fk_location_brand` ON `location` (`brand_id` ASC) ; CREATE INDEX `idx_lat` ON `location` (`lat` ASC) ; CREATE INDEX `idx_lng` ON `location` (`lng` ASC) ; Looks ok to me. I surmise that maybe something is wrong with the Query Browser, so I put this file on the server and try to load it this way ] mysql -u admin -p -D dbname < path/to/create_file.sql And I get the same error. So I start to Google this issue and find all kinds of accounts that talk about an error with InnoDB style tables that fail with foreign keys, and the fix is to add "SET FOREIGN_KEY_CHECKS=0;" to the SQL script. Well, as you can see, that's already part of the file that MySQL Workbench spat out. So, my question is then, why is this not working when I'm doing what I think I'm supposed to be doing? Version Info: # MySQL: 5.0.45 GUI Tools: 1.2.17 Workbench: 5.0.30

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  • Is there a keyboard shortcut to toggle Tree view / Places View?

    - by zinzolin
    I find both the Tree view and the Places view useful. Changing from one view to the other is not fast because one have to go into the appearance menu. It's even slower with Oneiric because this menu can now be far away. (Before Unity, I always had the tree view on and I used my bookmarks directly from the Places menu. That was fine) Is there a keyboard shortcut to toggle from one view to the other? Or is it possible to create one oneself? Thanks a lot the help !

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  • How to map string keys to unique integer IDs?

    - by Marek
    I have some data that comes regularily as a dump from a data souce with a string natural key that is long (up to 60 characters) and not relevant to the end user. I am using this key in a url. This makes urls too long and user unfriendly. I would like to transform the string keys into integers with the following requirements: The source dataset will change over time. The ID should be: non negative integer unique and constant even if the set of input keys changes preferrably reversible back to key (not a strong requirement) The database is rebuilt from scratch every time so I can not remember the already assigned IDs and match the new data set to existing IDs and generate sequential IDs for the added keys. There are currently around 30000 distinct keys and the set is constantly growing. How to implement a function that will map string keys to integer IDs? What I have thought about: 1. Built-in string.GetHashCode: ID(key) = Math.Abs(key.GetHashCode()) is not guaranteed to be unique (not reversible) 1.1 "Re-hashing" the built-in GetHashCode until a unique ID is generated to prevent collisions. existing IDs may change if something colliding is added to the beginning of the input data set 2. a perfect hashing function I am not sure if this can generate constant IDs if the set of inputs changes (not reversible) 3. translate to base 36/64/?? does not shorten the long keys enough What are the other options?

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  • Sendto shortcuts not working on Vista

    - by tbischel
    I'm trying to customize my sendto shortcut following instructions posted on a How-To Geek article. The problem is that any shortcut I drop into the sendto folder doesn't appear as a shortcut when I right-click-sendto. If I copy the actual application (say, Notepad) into the Sendto folder, it will appear as an option but it will not run. If I create a shortcut by copying the actual application and pasting a shortcut, it doesn't appear. Anyone run into this problem before?

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  • Single use download script - Modification [on hold]

    - by Iulius
    I have this Single use download script! This contain 3 php files: page.php , generate.php and variables.php. Page.php Code: <?php include("variables.php"); $key = trim($_SERVER['QUERY_STRING']); $keys = file('keys/keys'); $match = false; foreach($keys as &$one) { if(rtrim($one)==$key) { $match = true; $one = ''; } } file_put_contents('keys/keys',$keys); if($match !== false) { $contenttype = CONTENT_TYPE; $filename = SUGGESTED_FILENAME; readfile(PROTECTED_DOWNLOAD); exit; } else { ?> <html> <head> <meta http-equiv="refresh" content="1; url=http://docs.google.com/"> <title>Loading, please wait ...</title> </head> <body> Loading, please wait ... </body> </html> <?php } ?> Generate.php Code: <?php include("variables.php"); $password = trim($_SERVER['QUERY_STRING']); if($password == ADMIN_PASSWORD) { $new = uniqid('key',TRUE); if(!is_dir('keys')) { mkdir('keys'); $file = fopen('keys/.htaccess','w'); fwrite($file,"Order allow,deny\nDeny from all"); fclose($file); } $file = fopen('keys/keys','a'); fwrite($file,"{$new}\n"); fclose($file); ?> <html> <head> <title>Page created</title> <style> nl { font-family: monospace } </style> </head> <body> <h1>Page key created</h1> Your new single-use page link:<br> <nl> <?php echo "http://" . $_SERVER['HTTP_HOST'] . DOWNLOAD_PATH . "?" . $new; ?></nl> </body> </html> <?php } else { header("HTTP/1.0 404 Not Found"); } ?> And the last one Variables.php Code: <? define('PROTECTED_DOWNLOAD','download.php'); define('DOWNLOAD_PATH','/.work/page.php'); define('SUGGESTED_FILENAME','download-doc.php'); define('ADMIN_PASSWORD','1234'); define('EXPIRATION_DATE', '+36 hours'); header("Cache-Control: no-cache, must-revalidate"); header("Expires: ".date('U', strtotime(EXPIRATION_DATE))); ?> The http://www.site.com/generate.php?1234 will generate a unique link like page.php?key1234567890. This link page.php?key1234567890 will be sent by email to my user. Now how can I generate a link like this page.php?key1234567890&[email protected] ? So I think I must access the generator page like this generate.php?1234&[email protected] . P.S. This variable will be posted on the download page by "Hello, " I tried everthing to complete this, and no luck. Thanks in advance for help.

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  • Remapping Alt + F2 in Unity

    - by Jesse
    I disabled the Alt + F2 default shortcut in unity (ubuntu 11.10) using ccsm and I set a new shortcut using the default system shortcut manager (system settings keyboard). And it works, until I execute a command like compiz --replace. After that, all shortcuts keep working normally, except for Alt + F2. It does nothing. Any suggetions to keep the custom Alt + F2 shortcut working after compiz --replace?

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  • How to append \line into RTF using RichTextBox control

    - by Steve Sheldon
    When using the Microsoft RichTextBox control it is possible to add new lines like this... richtextbox.AppendText(System.Environment.NewLine); // appends \r\n However, if you now view the generated rtf the \r\n characters are converted to \par not \line How do I insert a \line control code into the generated RTF? What does't work: Token Replacement Hacks like inserting a token at the end of the string and then replacing it after the fact, so something like this: string text = "my text"; text = text.Replace("||" "|"); // replace any '|' chars with a double '||' so they aren't confused in the output. text = text.Replace("\r\n", "_|0|_"); // replace \r\n with a placeholder of |0| richtextbox.AppendText(text); string rtf = richtextbox.Rtf; rtf.Replace("_|0|_", "\\line"); // replace placeholder with \line rtf.Replace("||", "|"); // set back any || chars to | This almost worked, it breaks down if you have to support right to left text as the right to left control sequence always ends up in the middle of the placeholder. Sending Key Messages public void AppendNewLine() { Keys[] keys = new Keys[] {Keys.Shift, Keys.Return}; SendKeys(keys); } private void SendKeys(Keys[] keys) { foreach(Keys key in keys) { SendKeyDown(key); } } private void SendKeyDown(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYDOWN, (int)key, 0); } private void SendKeyUp(Keys key) { user32.SendMessage(this.Handle, Messages.WM_KEYUP, (int)key, 0); } This also ends up being converted to a \par Is there a way to post a messaged directly to the msftedit control to insert a control character? I am totally stumped, any ideas guys? Thanks for your help!

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  • PyQt - How to connect multiple signals to the same widget

    - by Orchainu
    [ ]All1 [ ]All2 [ ]checkbox1A [ ]checkbox1B [ ]checkbox2A [ ]checkbox2B Based on the chart above, a few things need to happen: The All checkboxes only affect the on/off of the column it resides in, and checks on/off all the checkboxes in that column. All checkboxes work in pairs, so if checkbox1A is on/off, checkbox1B needs to be on/off If an All checkbox is checked on, and then the user proceeds to check off one or more checkbox in the column, the All checkbox should be unchecked, but all the checkboxes that are already checked should remain checked. So really this is more like a chain reaction setup. If checkbox All1 is on, then chieckbox1A and 2A will be on, and because they are on, checkbox1B and 2B are also on, but checkbox All2 remains off. I tried hooking up the signals based on this logic, but only the paired logic works 100%. The All checkbox logic only works 50% of the time, and not accurately, and there's no way for me to turn off the All checkbox without turning all already checked checkboxes off. Really really need help ... T-T Sample code: cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.stateChanged.connect(self.syncCB) cbTwo.stateChanged.connect(self.syncCB) def syncCB(self): pairKeys = cbPairs.keys() for keys in pairKeys: cbOne = cbPairs[keys][0][0] cbOneAllCB = cbPairs[keys][0][4] cbTwo = cbPairs[keys][1][0] cbTwoAllCB = cbPairs[keys][1][4] if self.sender() == cbOne: if cbOne.isChecked() or cbTwoAllCB.isChecked(): cbTwo.setChecked(True) else: cbTwo.setChecked(False) else: if cbTwo.isChecked() or cbOneAllCB.isChecked(): cbOne.setChecked(True) else: cbOne.setChecked(False) EDIT Thanks to user Avaris's help and patience, I was able to reduce the code down to something much cleaner and works 100% of the time on the 1st and 2nd desired behavior: #Connect checkbox pairs cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.toggled.connect(cbTwo.setChecked) cbTwo.toggled.connect(cbOne.setChecked) #Connect allCB and allRO signals cbsKeys = allCBList.keys() for keys in cbsKeys: for checkbox in allCBList[keys]: keys.toggled.connect(checkbox.setChecked) Only need help on turning off the All checkbox when the user selectively turns off the modular checkboxes now

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  • How can laptop keyboard keys be removed and replaced?

    - by Lord Torgamus
    I'm trying to fix a laptop keyboard that has issues with keys on its left side. Just by feel, it's clear that something sticky got under there. There could be something crunchy too, but that might just be the sound of the key's spring releasing itself from the sticky. I don't know the cause because it's not my computer and the owner isn't sure, but I'm guessing soda spill for now. The computer is an HP dv2500. I've removed the keyboard and blown under it but that hasn't helped. I didn't use compressed air because I just don't have any available, but I suspect it wouldn't help with sticky. So, I'd like to pop they keys off and clean with damp cotton swabs or similar. Is there a proper way to remove the keys? I've found some instructions via Google for non-laptop keyboards, but they don't seem like they'd work for me. Alternate solutions to the problem also welcome, but I've been curious about how to remove the keys for some time for other reasons.

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