Search Results

Search found 310835 results on 12434 pages for 'stack user 1'.

Page 51/12434 | < Previous Page | 47 48 49 50 51 52 53 54 55 56 57 58  | Next Page >

  • how can I parse and group/do stats on user agent strings?

    - by user151841
    I have a database that has the various user-agent strings of visitors to our site. I'd like to do a 'survey' of them to see what browsers our users are using, so that I can know what features I can use in future development. Is there a tool to parse and run statistics on user-agent strings, or a bunch of strings like this? Ideally, I'd like to see a hierarchical grouping of the stats. For instance: Opera/9.80 (Windows Mobile; WCE; Opera Mobi/WMD-50301; U; en) Presto/2.4.13 Version/10.00 Opera/9.80 (J2ME/MIDP; Opera Mini/4.2.14912/1280; U; en) Presto/2.2.0 Opera/9.80 (J2ME/MIDP; Opera Mini/4.2.13918/812; U; en) Presto/2.2.0 Opera/9.64 (Macintosh; Intel Mac OS X; U; en) Presto/2.1.1 Opera/9.60 (J2ME/MIDP; Opera Mini/4.2.13918/786; U; en) Presto/2.2.0 Opera/9.60 (J2ME/MIDP; Opera Mini/4.0.10992/432; U; en) Presto/2.2.0 I'd like to see 6 entries for Opera, broken down into 3 for 9.80, 1 for 9.64 and 2 for 9.60, and so forth for all browsers. Other dimensions, such as OS, would cross the boundaries of the browser version hierarchy, but it might be nice to see also.

    Read the article

  • Is it possible to have WAMP run httpd.exe as user [myself] instead of local SYSTEM?

    - by Olivier H
    Hello! I run a django application over apache with mod_wsgi, using WAMP. A certain URL allows me to stream the content of image files, the paths of which are stored in database. The files can be located whether on local machine or under network drive (\my\network\folder). With the development server (manage.py runserver), I have no trouble at all reading and streaming the files. With WAMP, and with network drive files, I get a IOError : obviously because the httpd instance does not have read permission on said drive. In the task manager, I see that httpd.exe is run by SYSTEM. I would like to tell WAMP to run the server as [myself] as I have read and write permissions on the shared folder. (eventually, the production server should be run by a 'www-admin' user having the permissions) Mapping the network shared folder on a drive letter (Z: for instance) does not solve this at all. The User/Group directives in httpd.conf do not seem to have any kind of influence on Apache's behaviour. I've also regedited : I tried to duplicate the HKLM[...]\wampapache registry key under HK_CURRENT_USER\ and rename the original key, but then the new key does not seem to be found when I cmd this > httpd.exe -n wampapache -k start or when I run WAMP. I've run out of ideas :) Has anybody ever had the same issue?

    Read the article

  • nhibernate says 'mapping exception was unhandled' no persister for: MyNH.Domain.User

    - by mrblah
    Hi, I am using nHibernate and fluent. I created a User.cs: public class User { public virtual int Id { get; set; } public virtual string Username { get; set; } public virtual string Password { get; set; } public virtual string Email { get; set; } public virtual DateTime DateCreated { get; set; } public virtual DateTime DateModified { get; set; } } Then in my mappinds folder: public class UserMapping : ClassMap<User> { public UserMapping() { WithTable("ay_users"); Not.LazyLoad(); Id(x => x.Id).GeneratedBy.Identity(); Map(x => x.Username).Not.Nullable().WithLengthOf(256); Map(x => x.Password).Not.Nullable().WithLengthOf(256); Map(x => x.Email).Not.Nullable().WithLengthOf(100); Map(x => x.DateCreated).Not.Nullable(); Map(x => x.DateModified).Not.Nullable(); } } Using the repository pattern for the nhibernate blog: public class UserRepository : Repository<User> { } public class Repository<T> : IRepository<T> { public ISession Session { get { return SessionProvider.GetSession(); } } public T GetById(int id) { return Session.Get<T>(id); } public ICollection<T> FindAll() { return Session.CreateCriteria(typeof(T)).List<T>(); } public void Add(T product) { Session.Save(product); } public void Remove(T product) { Session.Delete(product); } } public interface IRepository<T> { T GetById(int id); ICollection<T> FindAll(); void Add(T entity); void Remove(T entity); } public class SessionProvider { private static Configuration configuration; private static ISessionFactory sessionFactory; public static Configuration Configuration { get { if (configuration == null) { configuration = new Configuration(); configuration.Configure(); configuration.AddAssembly(typeof(User).Assembly); } return configuration; } } public static ISessionFactory SessionFactory { get { if (sessionFactory == null) sessionFactory = Configuration.BuildSessionFactory(); return sessionFactory; } } private SessionProvider() { } public static ISession GetSession() { return SessionFactory.OpenSession(); } } My config: <?xml version="1.0" encoding="utf-8" ?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2"> <session-factory> <property name="connection.provider">NHibernate.Connection.DriverConnectionProvider</property> <property name="dialect">NHibernate.Dialect.MsSql2005Dialect</property> <property name="connection.driver_class">NHibernate.Driver.SqlClientDriver</property> <property name="connection.connection_string">Server=.\SqlExpress;Initial Catalog=TestNH;User Id=dev;Password=123</property> <property name="show_sql">true</property> </session-factory> </hibernate-configuration> I created a console application to test the output: static void Main(string[] args) { Console.WriteLine("starting..."); UserRepository users = new UserRepository(); User user = users.GetById(1); Console.WriteLine("user is null: " + (null == user)); if(null != user) Console.WriteLine("User: " + user.Username); Console.WriteLine("ending..."); Console.ReadLine(); } Error: nhibernate says 'mapping exception was unhandled' no persister for: MyNH.Domain.User What could be the issue, I did do the mapping?

    Read the article

  • Refactoring a custom User model to user UserProfile: Should I create a custom UserManager or add use

    - by BryanWheelock
    I have been refactoring an app that had customized the standard User model from django.contrib.auth.models by creating a UserProfile and defining it with AUTH_PROFILE_MODULE. The problem is the attributes in UserProfile are used throughout the project to determine the User sees. I had been creating tests and putting in this type of statement repeatedly: user = User.objects.get(pk=1) user_profile = user.get_profile() if user_profile.karma > 10: do_some_stuff() This is tedious and I'm now wondering if I'm violating the DRY principle. Would it make more sense to create a custom UserManager that automatically loads the UserProfile data when the user is requested. I could even iterate over the UserProfile attributes and append them to the User model. This would save me having to update all the references to the custom model attributes that litter the code. Of course, I'd have to reverse to process for to allow the User and UserProfile models to be updated correctly. Which approach is more Django-esque?

    Read the article

  • Django User model, adding function

    - by Hellnar
    Hello, I want to add a new function to the default User model of Django for retrieveing a related list of Model type. Such Foo model: class Foo(models.Model): owner = models.ForeignKey(User, related_name="owner") likes = models.ForeignKey(User, related_name="likes") ........ #at some view user = request.user foos= user.get_related_foo_models() Hwo can this be achieved ?

    Read the article

  • User Profile objects are empty, even user logged-in properly?

    - by Ahmed
    I use asp:Login control, user can login properly, but while checking user Profile information within LoggedIn event of Login control, all of the fields in the Profile objects are empty. Also, User.Identity.IsAuthenticated always returns false. But, all of these issue solved while navigating to another page. Why User.Identity.IsAuthenticated returns false, even user logged-in properly? And, is there any way to get user's profile information within LoggedIn event of Login control?

    Read the article

  • user creating/saving

    - by Xaver
    i want to write 2 program: 1) programm saves all local users to the file. 2) loads file find that users not found on local machine and create user. for searching all users which create on local machine i use next code: foreach (ManagementObject user in userSearcher.Get()) { if ((bool)user["LocalAccount"]) { string UserName = (string)user["FullName"]; } } How can i save the settings of user by name and create user?

    Read the article

  • CDI SessionScoped Bean instance remains unchanged when login with different user

    - by Jason Yang
    I've been looking for the workaround of this problem for rather plenty of time and no result, so I ask question here. Simply speaking, I'm using a CDI SessionScoped Bean User in my project to manage user information and display them on jsf pages. Also container-managed j_security_check is used to resolve authentication issue. Everything is fine if first logout with session.invalidate() and then login in the same browser tab with a different user. But when I tried to directly login (through login.jsf) with a new user without logout beforehand, I found the user information remaining unchanged. I debugged and found the User bean, as well as the HttpSession instance, always remaining the same if login with different users in the same browser, as long as session.invalidate() not invoked. But oddly, the session id did modified, and I've both checked in Java code and Firebug. org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c69a71d19f369d08b5dddbea2ef0] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue=org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 org.apache.catalina.session.StandardSessionFacade@5d7b4092 StandardSession[c6ab4b0c51ee0a649ef696faef75] attrName = org.jboss.weld.context.conversation.ConversationIdGenerator : attrValue = org.jboss.weld.context.conversation.ConversationIdGenerator@583c9dd8 attrName = com.sun.faces.renderkit.ServerSideStateHelper.LogicalViewMap : attrValue = {-4968076393130137442={-7694826198761889564=[Ljava.lang.Object;@43ff5d6c}} attrName = org.jboss.weld.context.ConversationContext.conversations : attrValue = {} attrName = org.jboss.weld.context.http.HttpSessionContext#org.jboss.weld.bean-Discipline-ManagedBean-class com.netease.qa.discipline.profile.User : attrValue = Bean: Managed Bean [class com.netease.qa.discipline.profile.User] with qualifiers [@Any @Default @Named]; Instance: com.netease.qa.discipline.profile.User@c497c7c; CreationalContext: org.jboss.weld.context.CreationalContextImpl@739efd29 attrName = javax.faces.request.charset : attrValue = UTF-8 Above block contains two successive logins and their Session info. We can see that the instance(1st row) the same while session id(2nd row) different. Seems that session object is reused to contain different session id and CDI framework manages session bean life cycle in accordance with the session object only(?). I'm wondering whether there could be only one server-side session object within the same browser unless invalidated? Since I'm adopting j_security_check I fancy intercepting it and invalidating old session is not so easy. So is it possible to accomplish the goal without altering the CDI+JSF+j_security_check design that one can relogin with different account in the same or different tab within the same browser? Really look forward for your response. More info: Glassfish v3.1 is my appserver.

    Read the article

  • Authenticated user cannot log in, "The user does not exist or is not unique."

    - by Aquinas
    This is a weird one. I have a WSS3 site, no MOSS, with a custom membership and role provider that authenticates against CRM. All the users have also been added to the site user list so once logged in they have correct display names. On dev and stage everything works fine, but on UAT the users can't get past the login screen. The login screen is working, in that if you type an incorrect password for a user it comes back with the right message, meaning the custom provider is working fine. If you fill the login form in correctly you are immediately redirected straight back to the login screen, with the IIS logs showing that the login screen sent the authenticated user to the site and then was sent back. Setting the site to allow anonymous access shows that the user is not logged in on the site side after authenticating correctly. The ULS logs show: The user does not exist or is not unique. Found 1 trusted forests nzct.local. Found 0 trusted domains Adding logging code to the site I have verified that the membership provider is correctly set, and can find the user when asked. Also, when accessing the site user list, I can find the SP user with the right name. It just refuses to set the current user to be the authenticated user. Weird.

    Read the article

  • Instagram API how to get user ID?

    - by user1355300
    How can I get the user ID with the user name with instagram API without user authentication? If I try users/search, it returns multiple research results, so how can I be sure that I get the result of exact user name only? For example, following requests return multiple users having their usernames similiar to aliciakeys, I want to get only the data of the user with exact user name. https://api.instagram.com/v1/users/search?q=aliciakeys&access_token=232967857.f59def8.c44c9e739efb4c52ab858bc84f420d00

    Read the article

  • can not login to windows

    - by LoRdiE
    Dear, When i login to windows using domain user account, it take a min show welcome and then automatically logoff. I think user profile error, so login with the administrator account and create new local account. When i login using the local user account, it happened the same as domain user account. Only Administrator Level can login to windows. Any know how can i fix this case? Thanks

    Read the article

  • Group / User based security. Table / SQL question

    - by Brett
    Hi, I'm setting up a group / user based security system. I have 4 tables as follows: user groups group_user_mappings acl where acl is the mapping between an item_id and either a group or a user. The way I've done the acl table, I have 3 columns of note (actually 4th one as an auto-id, but that is irrelevant) col 1 item_id (item to access) col 3 user_id (user that is allowed to access) col 3 group_id (group that is allowed to access) So for example item1, peter, , item2, , group1 item3, jane, , so either the acl will give access to a user or a group. Any one line in the ACL table with either have an item - user mapping, or an item group. If I want to have a query that returns all objects a user has access to, I think I need to have a SQL query with a UNION, because I need 2 separate queries that join like.. item - acl - group - user AND item - acl - user This I guess will work OK. Is this how its normally done? Am I doing this the right way? Seems a little messy. I was thinking I could get around it by creating a single user group for each person, so I only ever deal with groups in my SQL, but this seems a little messy as well..

    Read the article

  • How to limit the number of the same Activity on the stack for an Android application

    - by johnrock
    Is this possible in an Android app? I want to make it so that no matter how many times a user starts activityA, when they hit the back button they will never get more than one occurence of activityA. What I am finding in my current code is that I have only two options: 1. I can call finish() in activityA which will prevent it from being accessible via the back button completely, or 2. I do not call finish(), and then if the user starts activityA (n) times during their usage, there will be (n) instances when hitting the back button. Again, I want to have activityA accessible by hitting the back button, but there is no reason to keep multiple instances of the same activity on the stack. Is there a way to limit the number of instances of an activity in the queue to only 1?

    Read the article

  • Control Menu Items based on Privileges of Logged In User with spring security

    - by Nirmal
    Hi All... Based on this link I have incorporated the spring security core module with my grails project... I am using the Requestmap concept by storing each role, user and requestmap inside the database only... Now my requirement is to provide the menu items based on the users assigned roles... For e.g.: If my "User" Main Menu have following Items : Dashboard Import User Manage User And if I have assigned a roles of Dashboard and Import User to the user with a username "auditor" then, only following Menu items should be displayed on the screen : User (Main Menu) - Dashboard (sub menu) - Import User (sub menu) I have explored the Spring Security ACL plugin for the same, but it's using the Domain classes to get it working... So, wanted to know the convenient way to do so... Thanks in advance...

    Read the article

  • Django form and User data

    - by Dean
    I have a model that looks like this: class Client(models.Model): name = models.CharField(max_length=100, primary_key=True) user = models.ForeignKey(User) class Contract(models.Model): title = models.CharField(max_length=100, primary_key=True) start_date = models.DateField() end_date = models.DateField() description = models.TextField() client = models.ForeignKey(Client) user = models.ForeignKey(User) How can i configure a django form so that only clients associated with that user show in the field in the form? My initial thought was this in my forms.py: client = forms.ModelChoiceField(queryset=Client.objects.filter(user__username = User.username)) But it didn't work. So how else would I go about it?

    Read the article

  • ModelName(django.contrib.auth.models.User) vs ModelName(models.Model)

    - by amr.negm
    I am developing a django project. I created some apps, some of those are related to User model, for instance, I have a feeds app that handles user feeds, and another app that deals with extra user data like age, contacts, and friends. for each of these, I created a table that should be connected to the User model, which I using for storing and authenticating users. I found two ways to deal with this issue. One, is through extending User model to be like this: ModelName(User): friends = models.ManyToMany('self') ..... Two, is through adding a foreign key to the new table like this: ModelName(models.Model): user = models.ForeignKey(User, unique=True) friends = friends = models.ManyToMany('self') ...... I can't decide which to use in which case. in other words, what are the core differences between both?

    Read the article

  • How do I stack Plack authentication handlers?

    - by Schwern
    I would like to have my Plack app try several different means of authorizing the user. Specifically, check if the user is already authorized via a session cookie, then check for Digest authentication and then fall back to Basic. I figured I could just enable a bunch of Auth handlers in the order I wanted them to be checked (Session, Digest, Basic). Unfortunately, the way that Plack::Middleware::Auth::Digest and Plack::Middleware::Auth::Basic are written they both return 401 if digest or basic auth doesn't exist, respectively. How is this normally dealt with in Plack?

    Read the article

  • declerative_authorization on User problem

    - by Webpain
    I am trying to block all default methods except create and update in my users controller using declerative_authorization. But at the time I add filter_resource_access or filter_access_to into my usersController i always get "Couldn't find User without an ID". Anyone care to explain why this could be happening? class UsersController :new end end def show @user = @current_user end def edit @user = @current_user end def update @user = @current_user # makes our views "cleaner" and more consistent if @user.update_attributes(params[:user]) flash[:notice] = "Account updated!" redirect_to account_url else render :action = :edit end end end

    Read the article

  • Rails associations of user/post/comment

    - by garthcn
    Hi, I'm trying to create an app like a blog, with 3 models: user, post and comment. As expected, a comment belongs to both a user and a post. I used the following associations: User.rb has_many :comments has_many :posts Post.rb has_many :comments belongs_to :user Comment.rb belongs_to :user belongs_to :post And I tried to create comments using: @user.comments.create However, this will relate the comment with user, but not with post. I want the comment to be associated wit BOTH user and post. Is there a way to do so? Or did I use the wrong associations? I think it might be a bad practice to set the user_id or post_id by hand, so both ids are not in attr_accessible. I'm not sure if it is correct. Thank you!

    Read the article

  • How to restrict other user group members to view the Documents

    - by MKD
    I have created an Organization which has four user groups. I want to restrict the user group to view the file uploaded by the other user group. i.e Organization 1 User Group 1 A B User Group 2 C D User Group 3 E F User Group 4 G H I am using CustomLanding hook to land on the organization page. From above, If A uploads a document, it can be viewed only by B in user group 1. Like the same I want to restrict the viewable condition to other groups also. Please guide me to achieve this. Regards, Dinesh.

    Read the article

  • OSX root user keeps re-enabling itself on reboot

    - by geodave
    Running Snow Leopard. Completely inexplicably, I seem to have enabled the OSX root user by accident. I honestly have no idea how it happened, but if memory serves I was looking at the login pane (with my two user accounts) when I must have hit something, and suddenly the two accounts were replaced by one that just said "Other..." Clicking the "Other..." account allows me to type a username and password, but neither of the normal two accounts would work. Since I never set a root password, it wouldn't let me in that way either. So I booted into Single User mode and ran these commands: /sbin/mount -uw / fsck -fy launchctl load /System/Library/LaunchDaemons/com.apple.DirectoryServices.plist dscl . -passwd /Users/root newpassword and that let me login as root. Then, I went to System Preferences, Accounts, Login Options, clicked Join, Open Directory Utility, and lastly in the Edit menu I clicked "Disable Root User" Great, I thought, back to normal. Except rebooting, I still only have the Other... account visible, and the root password I set beforehand doesn't work anymore! I have to reboot into Single User Mode and go through the whole process again just to get back into the system (as root) How on Earth did I accidentally enable this? I didn't even know about the Directory Utility before now. And most importantly, why the heck would it be re-enabling the root user on boot? Thanks in advance to any help!

    Read the article

  • How to reset the postgres super user password on mac os x

    - by Andrew Barinov
    I installed postgres on my mac running 10.6.8 and I would like to reset the password for the postgres user (I believe this is the super user password) and then restart it. All the directions I found do not work because I think my user name is not recognized by pg as having authority to change the password. (I am on the admin account of my mac) Here is what I tried: Larson-2:~ larson$ psql -U postgres Password for user postgres: psql (9.0.4, server 9.1.2) WARNING: psql version 9.0, server version 9.1. Some psql features might not work. Type "help" for help. postgres=# ALTER USER postgres with password 'mypassword' postgres-# \q and for restart I did: Larson-2:~ larson$ su postgres -c 'pg_ctl -D /opt/local/var/db/postgresql84/defaultdb/ restart > Which didn't work, as the password remained the same as it was before. Can someone provide directions for doing this and for making sure it's recognized by PG? Update I went ahead and edited the pg_hba.conf file located in /Library/PostgreSQL/9.1/data and set the settings as follows: # TYPE DATABASE USER ADDRESS METHOD # "local" is for Unix domain socket connections only local all all trust # IPv4 local connections: host all all 127.0.0.1/32 trust # IPv6 local connections: host all all ::1/128 trust However, like before, the password stayed the same after I changed it. I am not sure what further steps I can take from here.

    Read the article

  • chrooted sftp user with write permissions to /var/www

    - by matthew
    I am getting confused about this setup that I am trying to deploy. I hope someone of you folks can lend me a hand: much much appreciated. Background info Server is Debian 6.0, ext3, with Apache2/SSL and Nginx at the front as reverse proxy. I need to provide sftp access to the Apache root directory (/var/www), making sure that the sftp user is chrooted to that path with RWX permissions. All this without modifying any default permission in /var/www. drwxr-xr-x 9 root root 4096 Nov 4 22:46 www Inside /var/www -rw-r----- 1 www-data www-data 177 Mar 11 2012 file1 drwxr-x--- 6 www-data www-data 4096 Sep 10 2012 dir1 drwxr-xr-x 7 www-data www-data 4096 Sep 28 2012 dir2 -rw------- 1 root root 19 Apr 6 2012 file2 -rw------- 1 root root 3548528 Sep 28 2012 file3 drwxr-x--- 6 www-data www-data 4096 Aug 22 00:11 dir3 drwxr-x--- 5 www-data www-data 4096 Jul 15 2012 dir4 drwxr-x--- 2 www-data www-data 536576 Nov 24 2012 dir5 drwxr-x--- 2 www-data www-data 4096 Nov 5 00:00 dir6 drwxr-x--- 2 www-data www-data 4096 Nov 4 13:24 dir7 What I have tried created a new group secureftp created a new sftp user, joined to secureftp and www-data groups also with nologin shell. Homedir is / edited sshd_config with Subsystem sftp internal-sftp AllowTcpForwarding no Match Group <secureftp> ChrootDirectory /var/www ForceCommand internal-sftp I can login with the sftp user, list files but no write action is allowed. Sftp user is in the www-data group but permissions in /var/www are read/read+x for the group bit so... It doesn't work. I've also tried with ACL, but as I apply ACL RWX permissions for the sftp user to /var/www (dirs and files recursively), it will change the unix permissions as well which is what I don't want. What can I do here? I was thinking I could enable the user www-data to login as sftp, so that it'll be able to modify files/dirs that www-data owns in /var/www. But for some reason I think this would be a stupid move securitywise.

    Read the article

  • Managing arbitrary user permissions under PureFTPd

    - by Sebastián Grignoli
    I need to provide an FTP service that needs to be web-managed in the simplest way possible. My customer wants to create folders and users, and give them read only or read/write access arbitrarily. For example: The folder 'Documents' should be read only for several users, writable for internal users, and invisible for the rest. The folder 'Pictures' should be read only for journalists, writable for associates, and invisible for the rest. The folder 'Media' should be read only, writable or invisible for arbitrary users specified on the admin. There could be a large number of users and folders. I can't find a good way to accomplish that. I thought that I could give each user a home folder and put symlinks for the folders he has read access to, and make the user part of the folder's group when he has write access too, but now I think that this wouldn't work, because with PureFTPd (or ProFTPd) I can only specify the virtual user's mapping to a system user, and only one GUID for each virtual user. My approach requires that I could specify several GUIDs for each user (one by each folder he has write access to). I need to start programming this admin and I still don't know wich approach would work, if any. ¿Any ideas?

    Read the article

< Previous Page | 47 48 49 50 51 52 53 54 55 56 57 58  | Next Page >