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  • New cast exception with VS2010/.Net 4

    - by Trevor
    [ Updated 25 May 2010 ] I've recently upgraded from VS2008 to VS2010, and at the same time upgraded to .Net 4. I've recompiled an existing solution of mine and I'm encountering a Cast exception I did not have before. The structure of the code is simple (although the actual implementation somewhat more complicated). Basically I have: public class SomeClass : ISomeClass { // Stuff } public static class ClassFactory { public static IInterface GetClassInstance<IInterface>(Type classType) { return (IInterface)Activator.CreateInstance(classType); // This throws a cast exception } } // Call the factory with: ISomeClass anInstance = ClassFactory.GetClassInstance<ISomeClass>(typeof(SomeClass)); Ignore the 'sensibleness' of the above - its provides just a representation of the issue rather than the specifics of what I'm doing (e.g. constructor parameters have been removed). The marked line throws the exception: Unable to cast object of type 'Namespace.SomeClass' to type 'Namespace.ISomeClass'. I suspect it may have something to do with the additional DotNet security (and in particular, explicit loading of assemblies, as this is something my app does). The reason I suspect this is that I have had to add to the config file the setting: <runtime> <loadFromRemoteSources enabled="true" /> </runtime> .. but I'm unsure if this is related. Update I see (from comments) that my basic code does not reproduce the issue by itself. Not surprising I suppose. It's going to be tricky to identify which part of a largish 3-tier CQS system is relevant to this problem. One issue might be that there are multiple assemblies involved. My static class is actually a factory provider, and the 'SomeClass' is a class factory (relevant in that the factories are 'registered' within the app via explicit assembly/type loading - see below) . Upfront I use reflection to 'register' all factories (i.e. classes that implement a particular interface) and that I do this when the app starts by identifying the relevant assemblies, loading them and adding them to a cache using (in essence): Loop over (file in files) { Assembly assembly = Assembly.LoadFile(file); baseAssemblyList.Add(assembly); } Then I cache the available types in these assemblies with: foreach (Assembly assembly in _loadedAssemblyList) { Type[] assemblyTypes = assembly.GetTypes(); _loadedTypesCache.AddRange(assemblyTypes); } And then I use this cache to do a variety of reflection operations, including 'registering' of factories, which involves looping through all loaded (cached) types and finding those that implement the (base) Factory interface. I've experienced what may be a similar problem in the past (.Net 3.5, so not exactly the same) with an architecture that involved dynamically creating classes on the server and streaming the compiled binary of those classes to the client app. The problem came when trying to deserialize an instance of the dynamic class on the client from a remote call: the exception said the class type was not know, even though the source and destination types were exactly the same name (including namespace). Basically the cross boundry versions of the class were not recognised as being the same. I solved that by intercepting the deserialization process and explicitly defining the deseriazation class type in the context of the local assemblies. This experience is what makes me think the types are considered mismatched because (somehow) the interface of the actual SomeClass object, and the interface of passed into the Generic method are not considered the same type. So (possibly) my question for those more knowledgable about C#/DotNet is: How does the class loading work that somehow my app thinks there are two versions/types of the interface type and how can I fit that? [ whew ... anyone who got here is quite patient .. thanks ]

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  • Tomcat does save logged users during restart

    - by mabuzer
    How to force Tomcat to save logged users, so that the they kept logged in even after Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.26 Update I managed to solve it like this: 1) Make my own extended version of FormAuthentication class: package com.alz.tomcat; import java.io.IOException; import java.security.Principal; import org.apache.catalina.Session; import org.apache.catalina.deploy.LoginConfig; import org.apache.catalina.connector.Request; import org.apache.catalina.connector.Response; import org.apache.catalina.authenticator.Constants; import org.apache.catalina.authenticator.FormAuthenticator; /** * * @author mabuzer */ public class Authenticator extends FormAuthenticator { @Override public boolean authenticate(Request request, Response response, LoginConfig config) throws IOException { String username = (String) request.getSession().getAttribute("USERNAME"); String password = (String) request.getSession().getAttribute("PASSWORD"); Principal principal = request.getUserPrincipal(); Session session = request.getSessionInternal(true); if (request.getUserPrincipal() == null && !isNull(username) && !isNull(password)) { principal = context.getRealm().authenticate(username, password); if (principal != null) { session.setNote(Constants.FORM_PRINCIPAL_NOTE, principal); if (!matchRequest(request)) { register(request, response, principal, Constants.FORM_METHOD, username, password); return (true); } } return super.authenticate(request, response, config); } else { return super.authenticate(request, response, config); } } private boolean isNull(String str) { if (str == null || "".equals(str)) { return true; } else { return false; } } } 2) Have your own ContextConfig class: package com.alz.tomcat; import java.util.HashMap; import org.apache.catalina.Valve; /** * * @author [email protected] */ public class ContextConfig extends org.apache.catalina.startup.ContextConfig { public ContextConfig() { super(); // we need to append our authenticator setCustomAuthenticators(customAuthenticators); customAuthenticators = new HashMap(); customAuthenticators.put("Authenticator" , new Authenticator()); } } 3) Have a class extends LifeCycleListener to set replace default ContextConfig the one you made: package com.alz.tomcat; import org.apache.catalina.Lifecycle; import org.apache.catalina.LifecycleEvent; import org.apache.catalina.core.StandardHost; /** * * @author [email protected] */ public class LifeCycleListener implements org.apache.catalina.LifecycleListener { public void lifecycleEvent(LifecycleEvent lifeCycleEvent) { if (Lifecycle.BEFORE_START_EVENT.equals(lifeCycleEvent.getType())) { StandardHost aStandardHost = (StandardHost) lifeCycleEvent.getLifecycle(); aStandardHost.setConfigClass("com.alz.tomcat.ContextConfig"); } } } 4) Final step which is to add your LifeCycleListener to server.xml in Host tag like this: <Host appBase="webapps" autoDeploy="true" name="localhost" unpackWARs="true" xmlNamespaceAware="false" xmlValidation="false"> <Listener className="com.alz.tomcat.LifeCycleListener"/> </Host>

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  • Why doesn't JSF 2.0 RI (Mojarra) scan my class' annotations?

    - by DWoldrich
    I have a War and Jar project in my Eclipse-based JSF project. I have decided to use annotations to declare my FacesConverter, (among a myriad other things), rather than declare it using my faces-config.xml. @FacesConverter(value="passwordFieldStringConverter") public class PasswordFieldStringConverter implements Converter { public Object getAsObject(FacesContext arg0, UIComponent arg1, String arg2) throws ConverterException { try { return arg2.getBytes("UTF-16BE"); } catch(UnsupportedEncodingException uee) { Assert.impossibleException(uee); } return(null); } public String getAsString(FacesContext arg0, UIComponent arg1, Object arg2) throws ConverterException { try { return new String((byte[]) arg2, "UTF-16BE"); } catch(UnsupportedEncodingException uee) { Assert.impossibleException(uee); } return(null); } } And then I use passwordFieldStringConverter directly in my .xhtml: <?xml version="1.0" encoding="UTF-8" ?> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:sec="http://www.springframework.org/security/facelets/tags"> <ui:composition> <f:view> <f:loadBundle basename="landingPage.bundle" var="bundle" /> <ui:decorate template="/WEB-INF/jsf_helpers/htmlShell.xhtml"> <ui:param name="PageTitleParam" value="#{bundle.pageTitle}" /> <h:form> <h:dataTable var="rowVar" value="#{userListContainer.users}"> <f:facet name="header"><h:outputText value="Users you are currently managing:" /></f:facet> <h:column> <f:facet name="header"> <h:outputText value="Screen Name" /> </f:facet> <h:outputText value="#{rowVar.screenName}" /> </h:column> <h:column> <f:facet name="header"> <h:outputText value="Password" /> </f:facet> <h:outputText value="#{rowVar.password}"> <f:converter converterId="passwordFieldStringConverter" /> </h:outputText> </h:column> </h:dataTable> </h:form> </ui:decorate> </f:view> </ui:composition> </html> JSF is supposed to scan the jars in my War at deployment-time and detect which classes have annotations on them (and auto-configure the application accordingly). My problem is that JSF is apparently not detecting the classes I have which sport annotations. The War project has all of my .xhtml files as well as the project's faces-config.xml, my Jar project has all of my faces related Java code (action beans, managed beans, custom converters, etc.)

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  • AES encryption/decryption java bouncy castle explanation?

    - by Programmer0
    Can someone please explain what this program is doing pointing out some of the major points? I'm looking at the code and I'm completely lost. I just need explanation on the encryption/decryption phases. I think it generates an AES 192 key at one point but I'm not 100% sure. I'm not sure what the byte/ivBytes are used for either. import java.security.Key; import javax.crypto.Cipher; import javax.crypto.KeyGenerator; import javax.crypto.spec.IvParameterSpec; public class RandomKey { public static void main(String[] args) throws Exception { byte[] input = new byte[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f, 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07 }; byte[] ivBytes = new byte[] { 0x00, 0x00, 0x00, 0x01, 0x04, 0x05, 0x06, 0x07, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x01 }; //initializing a new initialization vector IvParameterSpec ivSpec = new IvParameterSpec(ivBytes); //what does this actually do? Cipher cipher = Cipher.getInstance("AES/CTR/NoPadding", "BC"); //what does this do? KeyGenerator generator = KeyGenerator.getInstance("AES","BC"); //I assume this generates a key size of 192 bits generator.init(192); //does this generate a random key? Key encryptKey = generator.generateKey(); System.out.println("input: " +toHex(input)); //encryption phase cipher.init(Cipher.ENCRYPT_MODE, encryptKey, ivSpec); //what is this doing? byte[] cipherText = new byte[cipher.getOutputSize(input.length)]; //what is this doing? int ctLength = cipher.update(input, 0, input.length, cipherText,0); //getting the cipher text length i assume? ctLength += cipher.doFinal (cipherText, ctLength ); System.out.println ("Cipher: " +toHex(cipherText) + " bytes: " + ctLength); //decryption phase cipher.init(Cipher.DECRYPT_MODE, encryptKey, ivSpec); //storing the ciphertext in plaintext i'm assuming? byte[] plainText = new byte[cipher.getOutputSize(ctLength)]; int ptLength = cipher.update(cipherText, 0, ctLength, plainText, 0); //getting plaintextLength i think? ptLength= cipher.doFinal (plainText, ptLength); System.out.println("plain: " + toHex(plainText, ptLength)); } private static String digits = "0123456789abcdef"; public static String toHex(byte[] data, int length) { StringBuffer buf = new StringBuffer(); for (int i=0; i!= length; i++) { int v = data[i] & 0xff; buf.append(digits.charAt(v >>4)); buf.append(digits.charAt(v & 0xf)); } return buf.toString(); } public static String toHex(byte[] data) { return toHex(data, data.length); } }

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  • Expanding Rows for Unique Checkboxes

    - by Marc Morgan
    I was just recently given a project for my job to write a script that compares two mysql databases and print out information into an html table. Currently, I am trying to insert a checkbox by each individual's name and when selected, rows pertaining to that individual will expand underneath the person's name. I am combining javascript into my script to do this, although I really have no experience is it. The problem I am having is that when any checkbox is selected, all the rows for each individual is expanding instead of the rows pertaining only to the one individual selected. Here is the coding so far: <?php $link = mysql_connect ($server = "harris.lib.fit.edu", $username = "", $password = "") or die(mysql_error()); $db = mysql_select_db ("library-test") or die(mysql_error()); $ids = mysql_query("SELECT * FROM `ifc_studylog`") or die(mysql_error()); //not single quotes (tilda apostrophy) $x=0; $n=0; while($row = mysql_fetch_array( $ids )) { $tracksid1[$x] = $row['fitID']; $checkin[$x] = $row['checkin']; $checkout[$x] = $row['checkout']; $n++; $x++; } $names = mysql_query("SELECT * FROM `ifc_users`") or die(mysql_error()); //not single quotes (tilda apostrophy) $x=0; while($row = mysql_fetch_array( $names )) { $tracksnamefirst[$x] = $row['firstName']; $tracksnamesecond[$x] = $row['lastname']; $tracksid2[$x] = $row['fitID']; $tracksuser[$x] = $row['tracks']; $x++; } $x=0; foreach($tracksid2 as $comparename) { $chk = strval($x); ?> <script type='text/javascript' src='http://code.jquery.com/jquery-1.4.2.js'></script> <script type='text/javascript'> $(window).load(function () { $('.varx').click(function () { $('.text').toggle(this.checked); });}); </script> <?php echo '<td><input id = "<?=$chk?>" type="checkbox" class="varx" /></td>'; echo '<td align="center">'.$comparename.'</td>'; echo'<td align="center">'.$tracksnamefirst[$x].'</td>'; echo'<td align="center">'.$tracksnamesecond[$x].'</td>'; $z=0; foreach($tracksid1 as $compareid) { $HH=0; $MM =0; $SS =0; if($compareid == $comparename)// && $tracks==$tracksuser[$x]) { $SS = sprintf("%02s",(($checkout[$z]-$checkin[$z])%60)); $MM = sprintf("%02s",(($checkout[$z]-$checkin[$z])/60 %60)); $HH = sprintf("%02s",(($checkout[$z]-$checkin[$z])/3600 %24)); // echo'<td align="center">'.$HH.':'.$MM.':'.$SS.'</td>'; echo '</tr>'; echo '<tr>'; echo "<td id='txt' class='text' align='center' colspan='2' style='display:none'></td>"; echo "<td id='txt' class='text' align='center' style='display:none'>".$checkin[$z]."</td>"; echo '</tr>'; } echo '<tr>'; $z++; echo '</tr>'; } $x++; } } ?> Any Help is appreciated and sorry if I am too vague on the subject. The username and password is left off for security purposes.

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  • Using LINQ to create a simple login

    - by JDWebs
    I'm an C# ASP.NET beginner, so please excuse anything that's... not quite right! In short, I want to create a really basic login system: one which runs through a database and uses sessions so that only logged in users can access certain pages. I know how to do most of that, but I'm stuck with querying data with LINQ on the login page. On the login page, I have a DropDownList to select a username, a Textbox to type in a password and a button to login (I also have a literal for errors). The DropDownList is databound to a datatable called DT_Test. DT_Test contains three columns: UsernameID (int), Username (nchar(30)) and Password (nchar(30)). UsernameID is the primary key. I want to make the button's click event query data from the database with the DropDownList and Textbox, in order to check if the username and password match. But I don't know how to do this... Current Code (not a lot!): Front End: <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Login_Test.aspx.cs" Inherits="Login_Login_Test" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Login Test</title> </head> <body> <form id="LoginTest" runat="server"> <div> <asp:DropDownList ID="DDL_Username" runat="server" Height="20px" DataTextField="txt"> </asp:DropDownList> <br /> <asp:TextBox ID="TB_Password" runat="server" TextMode="Password"></asp:TextBox> <br /> <asp:Button ID="B_Login" runat="server" onclick="B_Login_Click" Text="Login" /> <br /> <asp:Literal ID="LI_Result" runat="server"></asp:Literal> </div> </form> </body> </html> Back End: using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; public partial class Login_Login_Test : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) { Binder(); } } private void Binder() { using (DataClassesDataContext db = new DataClassesDataContext()) { DDL_Username.DataSource = from x in db.DT_Honeys select new { x.UsernameID, txt = x.Username }; DDL_Username.DataBind(); } } protected void B_Login_Click(object sender, EventArgs e) { if (TB_Password.Text != "") { using (DataClassesDataContext db = new DataClassesDataContext()) { } } } } I have spent hours searching and trying different code, but none of it seems to fit in for this context. Anyway, help and tips appreciated, thank you very much! I am aware of security risks etc. but this is not a live website or anything, it is simply for testing purposes as a beginner. *

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  • NullPointerException in generated JSP code calling setJspId()

    - by Dobbo
    I am trying to deploy the Duke's Bank example form the J2EE 5 tutorial on JBoss 7.1.1. I have only used (unaltered) the source, and the standard XML configuration files for deployment, part of the exercise here is to see how I might structure a JSP based project of my own. The exception I get is as follows: ERROR [[jsp]] Servlet.service() for servlet jsp threw exception: java.lang.NullPointerException at javax.faces.webapp.UIComponentClassicTagBase.setJspId(UIComponentClassicTagBase.java:1858) [jboss-jsf-api_2.1_spec-2.0.1.Final.jar:2.0.1.Final] at org.apache.jsp.main_jsp._jspx_meth_f_005fview_005f0(main_jsp.java:99) at org.apache.jsp.main_jsp._jspService(main_jsp.java:76) at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) [jbossweb-7.0.13.Final.jar:] at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) [jboss-servlet-api_3.0_spec-1.0.0.Final.jar:1.0.0.Final] at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:369) [jbossweb-7.0.13.Final.jar:] at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:326) [jbossweb-7.0.13.Final.jar:] at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:253) [jbossweb-7.0.13.Final.jar:] at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) [jboss-servlet-api_3.0_spec-1.0.0.Final.jar:1.0.0.Final] at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:329) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:248) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:275) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:161) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:397) [jbossweb-7.0.13.Final.jar:] at org.jboss.as.jpa.interceptor.WebNonTxEmCloserValve.invoke(WebNonTxEmCloserValve.java:50) [jboss-as-jpa-7.1.1.Final.jar:7.1.1.Final] at org.jboss.as.web.security.SecurityContextAssociationValve.invoke(SecurityContextAssociationValve.java:153) [jboss-as-web-7.1.1.Final.jar:7.1.1.Final] at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:155) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) [jbossweb-7.0.13.Final.jar:] at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:368) [jbossweb-7.0.13.Final.jar:] at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:877) [jbossweb-7.0.13.Final.jar:] at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:671) [jbossweb-7.0.13.Final.jar:] at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:930) [jbossweb-7.0.13.Final.jar:] at java.lang.Thread.run(Thread.java:636) [rt.jar:1.6.0_18] I have not given any JBoss configuration files, the WAR's WEB-INF part looks like this: $ jar tvf build/lib/dukebank-web.war 0 Sat Dec 15 22:00:12 GMT 2012 META-INF/ 123 Sat Dec 15 22:00:10 GMT 2012 META-INF/MANIFEST.MF 0 Sat Dec 15 22:00:12 GMT 2012 WEB-INF/ 2514 Fri Dec 14 14:29:20 GMT 2012 WEB-INF/web.xml 1348 Sat Dec 15 08:19:46 GMT 2012 WEB-INF/dukesBank.tld 7245 Sat Dec 15 08:19:46 GMT 2012 WEB-INF/faces-config.xml 2153 Sat Dec 15 08:19:46 GMT 2012 WEB-INF/tutorial-template.tld 0 Sat Dec 15 22:00:12 GMT 2012 WEB-INF/classes/... The JSP file (main.jsp) that causes this problem is: <f:view> <h:form> <jsp:include page="/template/template.jsp"/> <center> <h3><h:outputText value="#{bundle.Welcome}"/></h3> </center> </h:form> </f:view> The template file it includes: <%@ taglib uri="/WEB-INF/tutorial-template.tld" prefix="tt" %> <%@ page errorPage="/template/errorpage.jsp" %> <%@ include file="/template/screendefinitions.jspf" %> <html> <head> <title> <tt:insert definition="bank" parameter="title"/> </title> <link rel="stylesheet" type="text/css" href="stylesheet.css"> </head> <body bgcolor="#ffffff"> <tt:insert definition="bank" parameter="banner"/> <tt:insert definition="bank" parameter="links"/> </body> </html> I will refrain from coping any more files because, as I said at the start I haven't altered any of the files I have used. Many thanks for your help, Steve

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  • Help passing _POST Form Data PHP

    - by Mikey1980
    I apologize in advance, I am a PHP noob! I have form with some hidden fields. I need the values to POST to "submit_rma.php" so that they're not missing from the db--I need $qty, $estmate_id and $rma_type. The rest of the fields are just displaying data for the user and are readonly. Currently I only get value from the qty text field. Is there any easier way to pass these values? URL is out of the question due to security issues. <form method="post" action="submit_rma.php";> <table> <tr> <td> Quantity </td> <td> <input type="text" name="qty" value="<?php echo $qty ?>" size="1"/><br/> </td> </tr> <tr> <td> Part # </td> <td> <input type="text" name="" value="<?php echo $model ?>" size="8" READONLY/><br/> </td> </tr> <tr> <td> Description </td> <td> <input type="text" name="" value="<?php echo $name_EN ?>" size="50" READONLY/><br/> </td> </tr> <tr> <td> Paid Date </td> <td> <input type="text" name="" value="<?php echo $sold_date ?>" size="6" READONLY/><br/> </td> </tr> <tr> <td> Amount Each </td> <td> <input type="text" name="" value="<?php echo $dealer_price ?>" size="8" READONLY/> </td> </tr> </table> <input type="hidden" name="estmate_id" value="<?php echo $estmate_id ?>"> <input type="hidden" name="rma_type" value="Short Shipped"> <input type="submit" name="submit";"> </form>

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  • Help to argue why to develop software on a physical computer rather than via a remote desktop

    - by s5804
    Remote desktops are great and many times a blessing and cost effective (instead of leasing expensive cables). I am not arguing against remote desktops, just if one have the alternative to use either remote desktop or physical computer, I would choose the later. Also note that I am not arguing for or against remote work practices. But in my case I am required to be physically present in the office when developing software. Background, I work in a company which main business is not to develop software. Therefore the company IT policies are mainly focused on security and to efficiently deploying/maintaing thousands of computer to users. Further, the typical employee runs typical Office applications, like a word processors. Because safety/stability is such a big priority, every non production system/application, shall be deployed into a physical different network, called the test network. Software development of course also belongs in the test network. To access the test network the company has created a standard policy, which dictates that access to the test network shall go only via a remote desktop client. Practically from ones production computer one would open up a remote desktop client to a virtual computer located in the test network. On the virtual computer's remote desktop one would be able to access/run/install all development tools, like Eclipse IDE. Another solution would be to have a dedicated physical computer, which is physically only connected to the test network. Both solutions are available in the company. I have tested both approaches and found running Eclipse IDE, SQL developer, in the remote desktop client to be sluggish (keyboard strokes are delayed), commands like alt-tab takes me out of the remote client, enjoying... Further, screen resolution and colors are different, just to mention a few. Therefore there is nothing technical wrong with the remote client, just not optimal and frankly de-motivating. Now with the new policies put in place, plans are to remove the physical computers connected to the test network. I am looking for help to argue for why software developers shall have a dedicated physical software development computer, to be productive and cost effective. Remember that we are physically in office. Further one can notice that we are talking about approx. 50 computers out of 2000 employees. Therefore the extra budget is relatively small. This is more about policy than cost. Please note that there are lots of similar setups in other companies that work great due to a perfectly tuned systems. However, in my case it is sluggish and it would cost more money to trouble shoot the performance and fine tune it rather than to have a few physical computers. As a business case we have argued that productivity will go down by 25%, however it's my feeling that the reality is probably closer to 50%. This business case isn't really accepted and I find it very difficult to defend it to managers that has never ever used a rich IDE in their life, never mind developed software. Further the test network and remote client has no guaranteed service level, therefore it is down for a few hours per month with the lowest priority on the fix list. Help is appreciated.

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  • Servlet response wrapper has encoding problem

    - by John O
    A servlet response wrapper is being used in a Servlet Filter. The idea is that the response is manipulated, with a 'nonce' value being injected into forms, as part of defence against CSRF attacks. The web app is using UTF-8 everywhere. When the Servlet Filter is absent, no problems. When the filter is added, encoding issues occur. (It seems as if the response is reverting to 8859-1.) The guts of the code : final class CsrfResponseWrapper extends AbstractResponseWrapper { ... byte[] modifyResponse(byte[] aInputResponse){ ... String originalInput = new String(aInputResponse, encoding); String modifiedResult = addHiddenParamToPostedForms(originalInput); result = modifiedResult.getBytes(encoding); ... } ... } As I understand it, the transition between byte-land and String-land should specify an encoding. That is done here, as you can see, in two places. The value of the 'encoding' variable is 'UTF-8'; the alteration of the String itself is standard string manipulation (with a regex), and never specifies an encoding (addHiddenParamToPostedForms). Where am I in error about the encoding? EDIT: Here is the base class (sorry it's rather long): package hirondelle.web4j.security; import javax.servlet.ServletOutputStream; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletResponse; import javax.servlet.http.HttpServletResponseWrapper; import java.io.ByteArrayOutputStream; import java.io.IOException; import java.io.PrintWriter; /** Abstract Base Class for altering response content. (May be useful in future contexts as well. For now, keep package-private.) */ abstract class AbstractResponseWrapper extends HttpServletResponseWrapper { AbstractResponseWrapper(ServletResponse aServletResponse) throws IOException { super((HttpServletResponse)aServletResponse); fOutputStream = new ModifiedOutputStream(aServletResponse.getOutputStream()); fWriter = new PrintWriter(fOutputStream); } /** Return the modified response. */ abstract byte[] modifyResponse(byte[] aInputResponse); /** Standard servlet method. */ public final ServletOutputStream getOutputStream() { //fLogger.fine("Modified Response : Getting output stream."); if ( fWriterReturned ) { throw new IllegalStateException(); } fOutputStreamReturned = true; return fOutputStream; } /** Standard servlet method. */ public final PrintWriter getWriter() { //fLogger.fine("Modified Response : Getting writer."); if ( fOutputStreamReturned ) { throw new IllegalStateException(); } fWriterReturned = true; return fWriter; } // PRIVATE /* Well-behaved servlets return either an OutputStream or a PrintWriter, but not both. */ private PrintWriter fWriter; private ModifiedOutputStream fOutputStream; /* These items are used to implement conformance to the javadoc for ServletResponse, regarding exceptions being thrown. */ private boolean fWriterReturned; private boolean fOutputStreamReturned; /** Modified low level output stream. */ private class ModifiedOutputStream extends ServletOutputStream { public ModifiedOutputStream(ServletOutputStream aOutputStream) { fServletOutputStream = aOutputStream; fBuffer = new ByteArrayOutputStream(); } /** Must be implemented to make this class concrete. */ public void write(int aByte) { fBuffer.write(aByte); } public void close() throws IOException { if ( !fIsClosed ){ processStream(); fServletOutputStream.close(); fIsClosed = true; } } public void flush() throws IOException { if ( fBuffer.size() != 0 ){ if ( !fIsClosed ) { processStream(); fBuffer = new ByteArrayOutputStream(); } } } /** Perform the core processing, by calling the abstract method. */ public void processStream() throws IOException { fServletOutputStream.write(modifyResponse(fBuffer.toByteArray())); fServletOutputStream.flush(); } // PRIVATE // private ServletOutputStream fServletOutputStream; private ByteArrayOutputStream fBuffer; /** Tracks if this stream has been closed. */ private boolean fIsClosed = false; } }

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  • php soapclient returns null but getPreviousResults has proper results

    - by Joseph.Chambers
    I've ran into trouble with SOAP, I've never had this issue before and can't find any information on line that helps me solve it. The following code $wsdl = "path/to/my/wsdl"; $client = new SoapClient($wsdl, array('trace' => true)); //$$textinput is passed in and is a very large string with rows in <item></item> tags $soapInput = new SoapVar($textinput, XSD_ANYXML); $res = $client->dataprofilingservice(array("contents" => $soapInput)); $response = $client->__getLastResponse(); var_dump($res);//outputs null var_dump($response);//provides the proper response as I would expect. I've tried passing params into the SoapClient constructor to define soap version but that didnt' help. I've also tried it with the trace param set to false and not present which as expected made $response null but $res was still null. I've tried the code on both a linux and windows install running Apache. The function definition in the WSDL is (xxxx is for security reasons) <portType name="xxxxServiceSoap"> <operation name="dataprofilingservice"> <input message="tns:dataprofilingserviceSoapIn"/> <output message="tns:dataprofilingserviceSoapOut"/> </operation> </portType> I have it working using the __getLastResponse() but its annoying me it will not work properly. I've put together a small testing script, does anyone see any issues here. //very simplifed dataset that would normally be //read in from a CSV file of about 1mb $soapInput = getSoapInput("asdf,qwer\r\nzzxvc,ewrwe\r\n23424,2113"); $wsdl = "path to wsdl"; try { $client = new SoapClient($wsdl,array('trace' => true,'exceptions' => true)); } catch (SoapFault $fault) { $error = 1; var_dump($fault); } try { $res = $client->dataprofilingservice(array("contents" => $soapInput)); $response = $client->__getLastResponse(); echo htmlentities($client->__getLastRequest()); echo '<hr>'; var_dump($res); echo "<hr>"; echo(htmlentities($response)); } catch (SoapFault $fault) { $error = 1; var_dump($fault); } function getSoapInput($input){ $rows = array(); $userInputs = explode("\r\n", $input); $userInputs = array_filter($userInputs); // $inputTemplate = " <contents>%s</contents>"; $rowTemplate = "<Item>%s</Item>"; // $soapString = ""; foreach ($userInputs as $row) { // sanitize $row = htmlspecialchars(addslashes($row)); $xmlStr = sprintf($rowTemplate, $row); $rows[] = $xmlStr; } $textinput = sprintf($inputTemplate, implode(PHP_EOL, $rows)); $soapInput = new SoapVar($textinput, XSD_ANYXML); return $soapInput; }

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  • Infinite sharing system (PHP/MySQLi)

    - by Toine Lille
    I'm working on a discount system for whichever customer shares a product and brings in new customers. Each unique visit = $0.05 off, each new customer = $0.50 off (it's a cheap product so yeah, no big numbers). When a new customer shares the site, the customer initially responsible for the new customer (if any) will get half of the new customer's discount as well. The initial customer would get a fourth for the next level and the new customer half of that, etc, creating a tree or pyramid that way that could be infinite. Initial customer ($1.35 discount: 2 new+3 visits + half of 1 new+2 visits) Visitor ($0) Visitor ($0) New customer ($0.60) Visitor ($0) Visitor ($0) Newer customer ($0) New customer ($0) Visitor ($0) The customers are saved along with their IP addresses (bin2hex(inet_pton)) in a database table (customers) with info like a unique id, e-mail address and first date/time the purchased a product (= time of registration). The shares are saved in a separate table within the same database (sharing). Each unique IP addresses that visits the site creates a new row featuring the IP address (also saved as bin2hex(inet_pton)), the id of the customer who shared it and the date/time of the visit. Sharing goes via URL, featuring a GET element containing the customer's id. Visits and new customers overlap, as visits will always occur before the new customer does. That's fine. The date/times are used just to make it a little more secure (I also use the IP along with cookies to see if people cheat the system). If an IP is already in the sharing or customer tables, it does not count and will not create a new entry. Now the problem is, how to make the infinity happen and apply the different values to it? That's all I'd need to know. It needs to calculate the discount for each customer separately, but also allow for monitoring altogether (though that's just a matter of passing all ID's through it). I figured I'd start (after the database connection) with $stmt = $con->prepare('SELECT ip,datetime FROM sharing WHERE sender=?'); $stmt->bind_param('i',$customerid); $stmt->execute(); $stmt->store_result(); $discount = $discount + ($stmt->num_rows * 0.05); $stmt->bind_result($ip,$timeofsharing); to translate all the visits to $0.05 of discount each. To check for the new customers that came from these visits, I wrote the following: while ($sql->fetch()) { $stmt2 = $con->prepare("SELECT datetime FROM users WHERE ip=?"); $stmt2->bind_param('s',$ip); $stmt2->execute(); $stmt2->store_result(); $stmt2->bind_result($timeofpurchase); Followed by a little more security comparing the datetimes: while ($stmt2->fetch()) { if (strtotime($timeofpurchase) < strtotime($timeofsharing)) { $discount = $discount + $0.50; } But this is just for the initial customer's direct results. If I'd want to check for the next level, I'd basically have to put the exact same check and loop in itself, checking each new customer the initial customer they brought to the site, and then for the next level again to check all of the newer customers, etc, etc. What to do? / Where to go? / What would be the correct practice for this? Thanks!

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  • C# Object Problem - Can't Solve It

    - by user612041
    I'm getting the error 'Object reference not set to an instance of an object'. I've tried looking at similar problems but genuinely cannot see what the problem is with my program. The line of code that I am having an error with is: labelQuestion.Text = table.Rows[0]["Question"].ToString(); Here is my code in its entirety: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Data.OleDb; using System.Data.Sql; using System.Data.SqlClient; namespace Quiz_Test { public partial class Form1 : Form { public Form1() { InitializeComponent(); } String chosenAnswer, correctAnswer; DataTable table; private void Form1_Load(object sender, EventArgs e) { //declare connection string using windows security string cnString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\\Users\\Hannah\\Desktop\\QuizQuestions.accdb"; //declare Connection, command and other related objects OleDbConnection conGet = new OleDbConnection(cnString); OleDbCommand cmdGet = new OleDbCommand(); //try //{ //open connection conGet.Open(); //String correctAnswer; cmdGet.CommandType = CommandType.Text; cmdGet.Connection = conGet; cmdGet.CommandText = "SELECT * FROM QuizQuestions ORDER BY rnd()"; OleDbDataReader reader = cmdGet.ExecuteReader(); reader.Read(); labelQuestion.Text = table.Rows[0]["Question"].ToString(); radioButton1.Text = table.Rows[0]["Answer 1"].ToString(); radioButton2.Text = table.Rows[0]["Answer 2"].ToString(); radioButton3.Text = table.Rows[0]["Answer 3"].ToString(); radioButton4.Text = table.Rows[0]["Answer 4"].ToString(); correctAnswer = table.Rows[0]["Correct Answer"].ToString(); ; conGet.Close(); } private void btnSelect_Click(object sender, EventArgs e) { String cnString = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\\Users\\Hannah\\Desktop\\QuizQuestions.accdb"; //declare Connection, command and other related objects OleDbConnection conGet = new OleDbConnection(cnString); OleDbCommand cmdGet = new OleDbCommand(); //try { //open connection conGet.Open(); cmdGet.CommandType = CommandType.Text; cmdGet.Connection = conGet; cmdGet.CommandText = "SELECT * FROM QuizQuestions ORDER BY rnd()"; // select all columns in all rows OleDbDataReader reader = cmdGet.ExecuteReader(); reader.Read(); if (radioButton1.Checked) { chosenAnswer = reader["Answer 1"].ToString(); } else if (radioButton2.Checked) { chosenAnswer = reader["Answer 2"].ToString(); } else if (radioButton3.Checked) { chosenAnswer = reader["Answer 3"].ToString(); } else { chosenAnswer = reader["Answer 4"].ToString(); } if (chosenAnswer == reader["Correct Answer"].ToString()) { //chosenCorrectly++; MessageBox.Show("You have got this answer correct"); //label2.Text = "You have got " + chosenCorrectly + " answers correct"; } else { MessageBox.Show("That is not the correct answer"); } } } } } I realise the problem isn't too big but I can't see how my declaration timings are wrong

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  • Adding picture in symfony 2 from symfony form?

    - by user2833510
    How do I add a picture in symfony2 from form to a database. I want to make a logo as a picture field and store project picture in database from form. How do I do this? Here is my form: <?php namespace Projects\ProjectsBundle\Form; use Symfony\Component\Form\AbstractType; use Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class ProjectsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('name') ->add('description') ->add('priority','choice', array( 'choices' => array('high' => 'high', 'low' => 'low', 'medium' => 'medium'))) ->add('logo') ->add('startedAt','datetime',array('label' => false,'data'=>new \DateTime(),'attr'=>array('style'=>'display:none;'))) ->add('completedOn','datetime',array('label' => false,'data'=>new \DateTime(),'attr'=>array('style'=>'display:none;'))) ->add('createdDatetime','datetime',array('label' => false,'data'=>new \DateTime(),'attr'=>array('style'=>'display:none;'))) ->add('updatedDatetime','datetime',array('label' => false,'data'=>new \DateTime(),'attr'=>array('style'=>'display:none;'))) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'Projects\ProjectsBundle\Entity\Projects' )); } public function getName() { return 'projects_projectsbundle_projectstype'; } } and here is my controller: public function createAction(Request $request) { $user = $this->get('security.context')->getToken()->getUser(); $userId = $user->getId(); $entity = new Projects(); $form = $this->createForm(new ProjectsType(), $entity); $form->bind($request); $entity->setCreatedBy($userId); $entity->setUpdatedBy($userId); $entity->setCompletedBy($userId); if ($form->isValid()) { $em = $this->getDoctrine()->getManager(); $em->persist($entity); $em->flush(); $_SESSION['projectid'] =$entity->getId(); if($request->isXmlHttpRequest()) { $response = new Response(); $output = array('success' => true, 'description' => $entity->getdescription(), 'id' => $entity->getId(), 'name' => $entity->getname(), 'priority' => $entity->getpriority(), 'logo' => $entity->getlogo(), 'startedat' => $entity->getstartedat(),'completedon' => $entity->getcompletedon(),'completedby' => $entity->getCompletedBy(), 'createdby' => $entity->getcreatedby(), 'updatedby' => $entity->getupdatedby(), 'createddatetime' => $entity->getcreateddatetime(), 'updateddatetime' => $entity->getupdateddatetime()); $response->headers->set('Content-Type', 'application/json'); $response->setContent(json_encode($output)); return $response; } return $this->redirect($this->generateUrl('projects_show', array('id' => $entity->getId()))); } return $this->render('ProjectsProjectsBundle:Projects:new.html.twig', array( 'entity' => $entity, 'form' => $form->createView(), )); }

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  • Update transaction in SQL Server 2008 R2 from ASP.Net not working

    - by Amarus
    Hello! Even though I've been a stalker here for ages, this is the first post I'm making. Hopefully, it won't end here and more optimistically future posts might actually be me trying to give a hand to someone else, I do owe this community that much and more. Now, what I'm trying to do is simple and most probably the reason behind it not working is my own stupidity. However, I'm stumped here. I'm working on an ASP.Net website that interacts with an SQL Server 2008 R2 database. So far everything has been going okay but updating a row (or more) just won't work. I even tried copying and pasting code from this site and others but it's always the same thing. In short: No exception or errors are shown when the update command executes (it even gives the correct count of affected rows) but no changes are actually made on the database. Here's a simplified version of my code (the original had more commands and tons of parameters each, but even when it's like this it doesn't work): protected void btSubmit_Click(object sender, EventArgs e) { using (SqlConnection connection = new SqlConnection(System.Configuration.ConfigurationManager.ConnectionStrings["ApplicationServices"].ConnectionString)) { string commandString = "UPDATE [impoundLotAlpha].[dbo].[Vehicle]" + "SET [VehicleMake] = @VehicleMake" + " WHERE [ComplaintID] = @ComplaintID"; using (SqlCommand command = new SqlCommand(commandString, connection)) { SqlTransaction transaction = null; try { command.Connection.Open(); transaction = connection.BeginTransaction(IsolationLevel.Serializable); command.Transaction = transaction; SqlParameter complaintID = new SqlParameter("@complaintID", SqlDbType.Int); complaintID.Value = HttpContext.Current.Request.QueryString["complaintID"]; command.Parameters.Add(complaintID); SqlParameter VehicleMake = new SqlParameter("@VehicleMake", SqlDbType.VarChar, 20); VehicleMake.Value = tbVehicleMake.Text; command.Parameters.Add(VehicleMake); command.ExecuteNonQuery(); transaction.Commit(); } catch { transaction.Rollback(); throw; } finally { connection.Close(); } } } } I've tried this with the "SqlTransaction" stuff and without it and nothing changes. Also, since I'm doing multiple updates at once, I want to have them act as a single transaction. I've found that it can be either done like this or by use of the classes included in the System.Transactions namespace (CommittableTransaction, TransactionScope...). I tried all I could find but didn't get any different results. The connection string in web.config is as follows: <connectionStrings> <add name="ApplicationServices" connectionString="Data Source=localhost;Initial Catalog=ImpoundLotAlpha;Integrated Security=True" providerName="System.Data.SqlClient"/> </connectionStrings> So, tldr; version: What is the mistake that I did with that record update attempt? (Figured it out, check below if you're having a similar issue.) What is the best method to gather multiple update commands as a single transaction? Thanks in advance for any kind of help and/or suggestions! Edit: It seems that I was lacking some sleep yesterday cause this time it only took me 5 minutes to figure out my mistake. Apparently the update was working properly but I failed to notice that the textbox values were being overwritten in Page_Load. For some reason I had this part commented: if (IsPostBack) return; The second part of the question still stands. But should I post this as an answer to my own question or keep it like this?

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  • How to use value from primary accessdatasource control as parameter in select query for secondary ac

    - by weedave
    Hi, I'm trying to display all orders placed and I have a primary accessdatasource control that has a select query to get the customer information and the orderID. I want to use the orderID value from this first query as a parameter for the secondary accessdatasource control that selects the product information of the products in the order. In plain english, I want to:- select product info from product table where orderID = ? (where ? is the orderID value from the first query) I have tried the <%#Eval("OrderID")% but I get a "server tag not well formed" error, but I do get results returned when I just type the order ID in, but obviously every result (order) just contains the same product info... <asp:Repeater ID="Repeater1" runat="server" DataSourceID="AccessDataSource1"> <ItemTemplate> <asp:AccessDataSource ID="AccessDataSource2" runat="server" DataFile="~/App_Data/project.mdb" SelectCommand="SELECT orderDetails.OrderID, album.Artist, album.Album, album.Cost, album.ImageURL, orderDetails.Quantity, orderDetails.Total FROM (album INNER JOIN orderDetails ON album.AlbumID = orderDetails.AlbumID) WHERE (orderDetails.OrderID = ? )"> <SelectParameters> // Error is on this line <asp:Parameter Name="OrderID" DefaultValue="<%#Eval ("OrderID")%>" /> </SelectParameters> </asp:AccessDataSource> <div class="viewAllOrdersOrderArea"> <div class="viewAllOrdersOrderSummary"> <p><b>Order ID: </b><%#Eval("OrderID")%></p> <h4>Shipping Details</h4> <p><b>Shipping Address: </b><%#Eval("ShippingName")%>, <%#Eval("ShippingAddress")%>, <%#Eval("ShippingTown")%>, <%#Eval("ShippingPostcode")%></p> <h4>Payment Details</h4> <p><b>Cardholder's Address: </b><%#Eval("CardHolder")%>, <%#Eval("BillingAddress")%>, <%#Eval("BillingTown")%>, <%#Eval("BillingPostcode")%></p> <p><b>Payment Method: </b><%#Eval("CardType")%></p> <p><b>Card Number: </b><%#Eval("CardNumber")%></p> <p><b>Start Date: </b><%#Eval("StartDate")%>, Expiry Date: <%#Eval("ExpiryDate")%></p> <p><b>Security Digits: </b><%#Eval("SecurityDigits")%></p> <h4>Ordered items:</h4> <asp:Repeater ID="Repeater2" runat="server" DataSourceID="AccessDataSource2"> <ItemTemplate> <div style="display: block; float: left;"> <div class="viewAllOrdersProductImage"> <img width="70px" height="70px" alt="<%# Eval("Artist") %> - <%# Eval("Album") %>" src="assets/images/thumbs/<%# Eval("ImageURL") %>" /> </div> <div style="display:block; float:left; padding-top:15px; padding-right:20px;"><p><b><%# Eval("Artist") %> - <%# Eval("Album") %></b></p> <p>£<%# Eval("Cost") %> x <%# Eval("Quantity") %> = £<%#Eval("Total")%></p></div> </div> </ItemTemplate> </asp:Repeater> </div> </div> </ItemTemplate> </asp:Repeater>

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  • Double Linked List header node keeps returning first value as 0

    - by Craig
    I will preface to say that this is my first question. I am currently getting my Masters degree in Information Security and I had to take C++ programming this semester. So this is homework related. I am not looking for you to answer my homework but I am running into a peculiar situation. I have created the program to work with a doubly linked list and everything works fine. However when I have the user create a list of values the first node keeps returning 0. I have tried finding some reading on this and I cannot locate any reference to it. My question is then is the header node(first node) always going to be zero? Or am I doing something wrong. case: 'C': cout<<"Please enter a list:"<<endl; while(n!=-999){ myList.insert(n); cin>> n;} break; I now enter: 12321, 1234,64564,346346. The results in 0, 12321, 1234, 64564,346346. Is this what should happen or am I doing something wrong? Also as this is my first post please feel free to criticize or teach me how to color code the keywords. Anyway this is a homework assignment so I am only looking for guidance and constructive criticism. Thank you all in advance So I cannot figure out the comment sections on this forum so I will edit the original post The first section is the constructor code: template <class Type> doublyLinkedList<Type>::doublyLinkedList() { first= NULL; last = NULL; count = 0; } Then there is my insert function : template <class Type> void doublyLinkedList<Type>::insert(const Type& insertItem) { nodeType<Type> *current; //pointer to traverse the list nodeType<Type> *trailCurrent; //pointer just before current nodeType<Type> *newNode; //pointer to create a node bool found; newNode = new nodeType<Type>; //create the node newNode->info = insertItem; //store the new item in the node newNode->next = NULL; newNode->back = NULL; if(first == NULL) //if the list is empty, newNode is //the only node { first = newNode; last = newNode; count++; } else { found = false; current = first; while (current != NULL && !found) //search the list if (current->info >= insertItem) found = true; else { trailCurrent = current; current = current->next; } if (current == first) //insert newNode before first { first->back = newNode; newNode->next = first; first = newNode; count++; } else { //insert newNode between trailCurrent and current if (current != NULL) { trailCurrent->next = newNode; newNode->back = trailCurrent; newNode->next = current; current->back = newNode; } else { trailCurrent->next = newNode; newNode->back = trailCurrent; last = newNode; } count++; }//end else }//end else }//end Then I have an initialization function too: template <class Type> void doublyLinkedList<Type>::initializeList() { destroy(); } Did I miss anything?

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  • Reflector error or optimisation?

    - by David_001
    Long story short: I used reflector on the System.Security.Util.Tokenizer class, and there's loads of goto statements in there. Here's a brief example snippet: Label_0026: if (this._inSavedCharacter != -1) { num = this._inSavedCharacter; this._inSavedCharacter = -1; } else { switch (this._inTokenSource) { case TokenSource.UnicodeByteArray: if ((this._inIndex + 1) < this._inSize) { break; } stream.AddToken(-1); return; case TokenSource.UTF8ByteArray: if (this._inIndex < this._inSize) { goto Label_00CF; } stream.AddToken(-1); return; case TokenSource.ASCIIByteArray: if (this._inIndex < this._inSize) { goto Label_023C; } stream.AddToken(-1); return; case TokenSource.CharArray: if (this._inIndex < this._inSize) { goto Label_0272; } stream.AddToken(-1); return; case TokenSource.String: if (this._inIndex < this._inSize) { goto Label_02A8; } stream.AddToken(-1); return; case TokenSource.NestedStrings: if (this._inNestedSize == 0) { goto Label_030D; } if (this._inNestedIndex >= this._inNestedSize) { goto Label_0306; } num = this._inNestedString[this._inNestedIndex++]; goto Label_0402; default: num = this._inTokenReader.Read(); if (num == -1) { stream.AddToken(-1); return; } goto Label_0402; } num = (this._inBytes[this._inIndex + 1] << 8) + this._inBytes[this._inIndex]; this._inIndex += 2; } goto Label_0402; Label_00CF: num = this._inBytes[this._inIndex++]; if ((num & 0x80) != 0) { switch (((num & 240) >> 4)) { case 8: case 9: case 10: case 11: throw new XmlSyntaxException(this.LineNo); case 12: case 13: num &= 0x1f; num3 = 2; break; case 14: num &= 15; num3 = 3; break; case 15: throw new XmlSyntaxException(this.LineNo); } if (this._inIndex >= this._inSize) { throw new XmlSyntaxException(this.LineNo, Environment.GetResourceString("XMLSyntax_UnexpectedEndOfFile")); } byte num2 = this._inBytes[this._inIndex++]; if ((num2 & 0xc0) != 0x80) { throw new XmlSyntaxException(this.LineNo); } num = (num << 6) | (num2 & 0x3f); if (num3 != 2) { if (this._inIndex >= this._inSize) { throw new XmlSyntaxException(this.LineNo, Environment.GetResourceString("XMLSyntax_UnexpectedEndOfFile")); } num2 = this._inBytes[this._inIndex++]; if ((num2 & 0xc0) != 0x80) { throw new XmlSyntaxException(this.LineNo); } num = (num << 6) | (num2 & 0x3f); } } goto Label_0402; Label_023C: num = this._inBytes[this._inIndex++]; goto Label_0402; Label_0272: num = this._inChars[this._inIndex++]; goto Label_0402; Label_02A8: num = this._inString[this._inIndex++]; goto Label_0402; Label_0306: this._inNestedSize = 0; I essentially wanted to know how the class worked, but the number of goto's makes it impossible. Arguably something like a Tokenizer class needs to be heavily optimised, so my question is: is Reflector getting it wrong, or is goto an optimisation for this class?

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  • Persisting objects to a database using a loop

    - by ChaoticLoki
    I have a form that returns multiple values and each value I would like to store in a database, I created a test form for this purpose <form method="post" action="{{ path('submit_exercise', {'page': 1}) }}"> <input type="hidden" name="answers[]" value="Answer 1" "/> <input type="hidden" name="answers[]" value="Answer 2" "/> <input type="hidden" name="answers[]" value="Answer 3" "/> <input type="hidden" name="answers[]" value="Answer 4" "/> <input type="hidden" name="answers[]" value="Answer 5" "/> <input type="hidden" name="answers[]" value="Answer 6" "/> <input type="hidden" name="answers[]" value="Answer 7" "/> <input type="submit" name="submit" /> </form> </body> </html> My submit answers Action is currently written like so. public function submitAnswersAction($page) { //get submitted data $data = $this->get('request')->request->all(); $answers = $data['answers']; //get student ID $user = $this->get('security.context')->getToken()->getUser(); $studentID = $user->getId(); //Get Current time $currentTime = new \DateTime(date("Y-m-d H:m:s")); //var_dump($answers); //var_dump($studentID); //var_dump($currentTime); for($index = 0; $index < count($answers); $index++) { /*echo "Question ". ($index + 1) ."<br />"; echo "Student ID: ". $studentID."<br />"; echo "Page Number: $page <br />"; echo "Answer: $answers[$index]"."<br />"; echo "<br />";*/ $studentAnswer = new StudentAnswer(); $studentAnswer->setStudentID($studentID); $studentAnswer->setPageID($page); $studentAnswer->setQuestionID($index+1); $studentAnswer->setAnswer($answers[$index]); $studentAnswer->setDateCreated($currentTime); $studentAnswer->setReadStatus(0); $database = $this->getDoctrine()->getManager(); $database->persist($studentAnswer); $database->flush(); } return new Response('Answers saved for Student: '.$user->getFullName().' for page: '.$page); When I do a var_dump everything seems to be associated correctly, meaning that the answers array is populated with the right data and so is every other variable, my problem is actually persisting it to the database. when run it returns with this error which seems to me like it doesn't know what variables to put into the row. An exception occurred while executing 'INSERT INTO Student_Answer (student_id, page_id, question_id, answer, read, date_created) VALUES (?, ?, ?, ?, ?, ?)' with params {"1":2,"2":"1","3":1,"4":"Answer 1","5":0,"6":"2012-12-11 12:12:20"}: Any help would be greatly appreciated as this is a personal project to help me try and understand web development a bit more.

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  • Remotely Schedule and Stream Recorded TV in Windows 7 Media Center

    - by DigitalGeekery
    Have you ever been away from home and suddenly realized you forgot to record your favorite program? Now Windows 7 Media Center, users can schedule recordings remotely from their phones or mobile devices with Remote Potato. How it Works Remote Potato installs server software on the host computer running Windows 7 Media Center. Once the software is installed, we’ll need to do some port forwarding on the router and setup an optional dynamic DNS address. When setup is completed, we will access the application through a web based interface. Silverlight is required for Streaming recorded TV, but scheduling recordings can be done through an HTML interface. Installing Remote Potato Download and install Remote Potato on the Media Center PC. (See download link below) If you plan to stream any Recorded TV, you’ll also want to install the streaming pack located on the same page. It isn’t required to stream all shows, only shows that require the AC3 audio codec. Click Yes to allow Remote Potato to add rules to the Windows Firewall for remote access. You’ll likely need to accept a few UAC prompts. When notified that the rules were added, click OK. Remote Potato will then prompt you to allow administrator privileges to reserve a URL for it’s web server. Click Yes. Remote Potato server will start. Click on the configuration button at the right to to reveal the settings tabs.   One the General tab, you’ll have the option to run Remote Potato on startup and minimized in the System Tray. If you’re running Media Center on a dedicated HTPC, you’ll probably want to enable both startup options. Forwarding Ports on Your Router You’ll need to forward a couple ports on your router. By default, these will be ports 9080 and 9081. In this example we’re using a Linksys WRT54GL router, however, the steps for port forwarding will vary from router to router. On the Linksys configuration page, click on the Applications & Gaming Tab, and then the Port Range Forward tab. Under Application, type in a name of your choosing. In both the Start and End boxes, type the port number 9080. Enter the local IP address of your Media Center computer in the IP address column. Click the check box under Enable. Repeat the process on the next line, but this time use port 9081. When finished, click the Save Settings button. Note: It’s highly recommended that you configure the home computer running Media Center & Remote Potato with a static IP address.   Find your IP Address You’ll need to find the IP address assigned to your router from your ISP. There are many ways to do this but a quick and easy way is to visit a site like checkip.dyndns.org (link available below) The current external IP address of your router will be displayed in the browser.   Dynamic DNS This is an optional step, but  it’s highly recommended. Many routers, such as the Linksys WRT54GL we are using, support Dynamic DNS (DDNS). What Dynamic DNS allows you to do is affiliate your home router’s external IP address to a domain name. Every time your home router is assigned a a new IP address by your ISP, the domain name is updated to point to your new IP address. Remote Potato’s user interface is accessed over the Internet is by connecting to your router’s IP address followed by a colon and the port number. (Ex: XXX.XXX.XXX.XXX:9080) Instead of constantly having to look up and remember an IP address, you can use DDNS along with a 3rd party provider like DynDNS.com, to sign up for a free domain name and configure it to be updated each time your router is assigned a new IP address. Go to the DynDNS.com website (See link at the end of the article) and sign up for a free Domain name. You’ll need to register and confirm by email.   Once you’ve signed in and selected your domain name click Activate Services. You’ll get a confirmation message that your domain name has been activated.    On the Linksys WRT54GL click on the Setup tab an then DDNS. Select DynDNS.org, or TZO.com if you prefer to use their service, from the drop down list.   With DynDNS, you’ll need to fill in your username and password you signed up with at the DynDNS website and the hostname you chose. Note: You can connect over your local network with the IP Address of the computer running Remote Potato followed by a colon and the port number. Ex: 192.168.1.2:9080 Logging in Remote Potato and Recording a Show Once you connect, you’ll see the start page. To view the TV listings, click on TV Guide. You’ll then see your guide listings. There are a few ways to navigate the listings. At the top left, you can click on any of the preset time buttons to jump to  the listings at that time of the day.  Click on the arrows to the right and left of the day and date at the top center to proceed to the previous or next day. Or, jump to a specific day with the date and date buttons at the top right.   To setup a recording, click on a program.   You can choose to record the individual show or the entire series by clicking on Record Show or Record Series.   Remote Potato on Mobile Devices Perhaps the coolest feature of Remote Potato is the ability to schedule recording from your phone or mobile device. Note: For any devices or computers without Silverlight, you will be prompted to view the HTML page. Select Browse Listings. Select your program to record. In the Program Details, select Record Show to record the single episode or Record Series to record all instances of the series. You will then see a red dot on the program listing to indicate that the show is scheduled for recording.   Streaming Recorded TV Click on Recorded TV from the home screen to access your previously recorded TV programs. Click on the selection you wish to stream. Click on Play. If you receive this error message, you’ll need to install the streaming pack for Remote Potato. This is found on the same download page as installation files. (See link below) The Begin from slider allows you to start playback from the start (by default) or a different time of the program by moving the slider. The Quality (bitrate) setting  allows you to choose the quality of the playback. We found the video quality on the Normal setting to be pretty lousy, and Low was just pointless. High was the best overall viewing experience as it provided smooth quality video playback. We experienced significant stuttering during playback using the Ultra High setting.   Click Start when you are ready to begin. When playback begins you’ll see a slider at the top right.   Move the slider left or right to increase or decrease the size of the video. There’s also a button to switch to full screen.   Media Center users who travel frequently or are always on the go will likely find Remote Potato to be a blessing. Since being released earlier this year, updates for Remote Potato have come fast and furious. The latest beta release includes support for streaming music and photos. If you like those nice network TV logos, check out our article on adding TV channel logos to Windows Media Center. Downloads and Links Download Remote Potato and Streaming Pack Find your IP address Sign Up for a Domain Name at DynDNS.com Similar Articles Productive Geek Tips Schedule Updates for Windows Media CenterUsing Netflix Watchnow in Windows Vista Media Center (Gmedia)Add a Sleep Timer to Windows 7 Media CenterStartup Customizations for Media Center in Windows 7Enable Media Streaming in Windows Home Server to Windows Media Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 FoxClocks adds World Times in your Statusbar (Firefox) Have Fun Editing Photo Editing with Citrify Outlook Connector Upgrade Error Gadfly is a cool Twitter/Silverlight app Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • Installing UCMA 3.0 and Creating a Communications Server "14"Trusted Application Pool

    A lot of setup and administration tasks have gotten a lot easier in Communications Server 14; one of them is building an application server to develop and run your UCMA 3.0 applications on. In this post, Ill walk you through installing the UCMA 3.0 Core SDK and creating a Trusted Application Pool on the server, thus adding it to the Communications Server 14 topology and allowing you to host and run UCMA 3.0 applications on it. Note: These instructions will change slightly as the bits get updated for the eventual Beta release I will update this post as soon as I get a chance to run this setup on a more recent build. Im doing the install on a simple Communications Server 14 topology consisting of the following Windows Server 2008 R2 Hyper-V images: DC Domain Controller ExchangeUM Exchange Server 2010 CS-SE Microsoft Communications Server 2010 Standard Edition TS Development machine Ill walk through setting up UCMA 3.0 on the TS VM, which is a fully patched Windows Server 2008 R2 machine that is joined to the Fabrikam domain.   Im also running Visual Studio 2010 on this VM because I intend to use it as a development machine.  In a future post, Ill walk through installing just the UCMA 3.0 run time to build a true production UCMA application server. Im making a couple of assumptions here: You have an existing CS 2010 site and cluster configured(well look at this in a future post) Youre starting with a fully patched Windows Server 2008 R2 machine The machine is joined to your domain This walkthrough was done in my Fabrikam VM environment but can easily be modified for your own environment. Installing the UCMA 3.0 SDK Lets start by installing the UCMA 3.0 SDK.  Run UcmaSdkWebDownload.msi to kick off the SDK installer package extract process. The installed package is extracted to C: >> Program Files >> Microsoft UCMA 3.0 >> SDK Installer Package.  Browse there and run setup.exe. Click Install to install the UCMA 3.0 Core SDK and Workflow SDK. Install Communications Server Core Components UCMA 3.0 introduces a new concept called Auto-provisioning, which is most easily explained from the developer point of view.  Remember what your app.config looked it in UCMA 2.0?  You had to store the application GRUU, the trusted contact SIP Uri, the port for your application, and the name of the certificate authority. Thats all gone with auto-provisioning all you need in your app.config is your ApplicationId, e.g.: urn:application:MyApplication. How does CS 2010 do this? All of the applications configuration data is associated with the applications id.  UCMA also queries a replicated copy of the Central Management Database to retrieve the applications configuration data and also the configuration data for any endpoints. In this step, well run Bootstrapper.exe to install the CS Core components, this checked for the following components and installs them if they are not already present: VcRedist Sqlexpress Sqlnativeclient Sqlbackcompat Ucmaredist OcsCore.msi Open a command window at C: >> Program Files >> Microsoft Communications Server 2010 >> Deployment and run the following command: Bootstrapper.exe /BootstrapReplica /MinCache /SourceDirectory:"%ProgramFiles%\Microsoft UCMA 3.0\SDK Installer Package\Prereq\BootstrapperCache" Create a New Trusted Application Pool The next step is to create a new trusted application pool for the new server.  Fire up the Communications Server Management Shell from Start >> Microsoft Communications Server 2010 >> Communications Server Management Shell and enter the following PowerShell command: New-CsTrustedApplicationPool -Identity <FQDN of Server> -Registrar <FQDN of CS Server> -Site <CS Site Name> Verify that the new server was added to the CS topology by running the following PowerShell command: (Get-CsTopology -AsXml).ToString() > Topology.xml This created a file called Topology.xml in the directory that you ran the command from.  Open the file and find the Clusters section and look for a node for the new server. The Cluster Fqdn is the name of your server, and note the name of the Site that this Cluster is a part of. <Cluster Fqdn="appsrv.fabrikam.com" RequiresReplication="true" RequiresSetup="true"> <ClusterId SiteId="UcMarketing2" Number="5" /> <Machine OrdinalInCluster="1" Fqdn="appsrv.fabrikam.com"> <NetInterface InterfaceSide="Primary" InterfaceNumber="1" IPAddress="0.0.0.0" /> </Machine> </Cluster> Configure CS Management Store Replication At this point, we have the CS Core components installed and the server configured as a trusted application pool.  We now need to set up replication so that the Central Management Store replicates down to the new server. From the Communications Server Management Shell, run the following PowerShell command to enable the Replica service on the new server: Enable-CSReplica The Replica service is enabled, but hasn't done anything yet. This can be verified by running the following PowerShell command to check the replication status for the various servers in the topology: Get-CSManagementStoreReplicationStatus You can see in the screenshot below that the UpToDate property of the new server is still False Run the following PowerShell command to force the replication to run: Invoke-CSManagementStoreReplicationStatus Run Get-CSManagementStoreReplicationStatus again to verify that the new service is now up to date Request and Set a New Certificate The last step in the process is to request a new certificate from the certificate authority on the domain and assign it to the new server. From the Communications Server Management Shell, run the following PowerShell command to request a new certificate: Request-CSCertificate -Action new -Type default -CA <Domain Controller FQDN>\<Certificate Authority> Setting the -Verbose switch on the cmdlet creates an Xml file with its output. Open the Xml file and copy the thumbprint of the generated certificate. <?xml version="1.0" encoding="utf-8"?> <Action Name="Request-CsCertificate" Time="20100512T212258"> <Action Name="Request-CsCertificate" Time="20100512T212258"> <Info Title="Connection" Time="20100512T212258">Data Source=(local)\rtclocal;Initial Catalog=xds;Integrated Security=True</Info> <Action Time="20100512T212258"> <Info Title="Certificate use" Time="20100512T212258">urn:certref:default</Info> <Info Title="Subject distinguished name" Time="20100512T212258">CN="appsrv2.fabrikam.com"</Info> <Info Time="20100512T212259">The certificate request is submitted to the Certification Authority dc.fabrikam.com\FabrikamCA.</Info> <Info Time="20100512T212259">The certificate was issued.</Info> <Info Time="20100512T212259">The certificate was imported with thumbprint AFC3C46E459C1A39AD06247676F3555826DBF705.</Info> <Complete Time="20100512T212259" /> </Action> <Info Title="command status" Time="20100512T212259">Command execution processing completed</Info> <Action Name="DeploymentXdsCmdlet.SaveCachedItems" Time="20100512T212259"> <Info Time="20100512T212259">0 updates</Info> <Complete Time="20100512T212259" /> </Action> <Info Title="command status" Time="20100512T212259">Command has completed</Info> </Action> </Action> Run the following PowerShell command to set the certificate: Set-CsCertificate -Type Default -Thumbprint <Thumbprint> Wrapping Up You now have a new UCMA 3.0 application server in your Communications Server 2010 server topology.  You can provision trusted applications and trusted application endpoints on the new server using the Communications Server 2010 Management Shell.  Well take a look at how to do that in another post. Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Preventing duplicate Data with ASP.NET AJAX

    - by Yousef_Jadallah
      Some times you need to prevent  User names ,E-mail ID's or other values from being duplicated by a new user during Registration or any other cases,So I will add a simple approach to make the page more user-friendly. Instead the user filled all the Registration fields then press submit after that received a message as a result of PostBack that "THIS USERNAME IS EXIST", Ajax tidies this up by allowing asynchronous querying while the user is still completing the registration form.   ASP.NET enables you to create Web services can be accessed from client script in Web pages by using AJAX technology to make Web service calls. Data is exchanged asynchronously between client and server, typically in JSON format. I’ve added an article to show you step by step  how to use ASP.NET AJAX with Web Services , you can find it here .   Lets go a head with the steps :   1-Create a new project , if you are using VS 2005 you have to create ASP.NET Ajax Enabled Web site.   2-Create your own Database which contain user table that have User_Name field. for Testing I’ve added SQL Server Database that come with Dot Net 2008: Then I’ve created tblUsers:   This table and this structure just for our example, you can use your own table to implement this approach.   3-Add new Item to your project or website, Choose Web Service file, lets say  WebService.cs  .In this Web Service file import System.Data.SqlClient Namespace, Then Add your web method that contain string parameter which received the Username parameter from the Script , Finally don’t forget to qualified the Web Service Class with the ScriptServiceAttribute attribute ([System.Web.Script.Services.ScriptService])     using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Services; using System.Data.SqlClient;     [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.Web.Script.Services.ScriptService] public class WebService : System.Web.Services.WebService {     [WebMethod] public int CheckDuplicate(string User_Name) { string strConn = @"Data Source=.\SQLEXPRESS;AttachDbFilename=|DataDirectory|\TestDB.mdf;Integrated Security=True;User Instance=True"; string strQuery = "SELECT COUNT(*) FROM tblUsers WHERE User_Name = @User_Name"; SqlConnection con = new SqlConnection(strConn); SqlCommand cmd = new SqlCommand(strQuery, con); cmd.Parameters.Add("User_Name", User_Name); con.Open(); int RetVal= (int)cmd.ExecuteScalar(); con.Close(); return RetVal; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   Our Web Method here is CheckDuplicate Which accept User_Name String as a parameter and return number of the rows , if the name will found in the database this method will return 1 else it will return 0. I’ve applied  [WebMethod] Attribute to our method CheckDuplicate, And applied the ScriptService attribute to a Web Service class named WebService.   4-Add this simple Registration form : <fieldset> <table id="TblRegistratoin" cellpadding="0" cellspacing="0"> <tr> <td> User Name </td> <td> <asp:TextBox ID="txtUserName" onblur="CallWebMethod();" runat="server"></asp:TextBox> </td> <td> <asp:Label ID="lblDuplicate" runat="server" ForeColor="Red" Text=""></asp:Label> </td> </tr> <tr> <td colspan="3"> <asp:Button ID="btnRegistration" runat="server" Text="Registration" /> </td> </tr> </table> </fieldset> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   onblur event is added to the Textbox txtUserName, This event Fires when the Textbox loses the input focus, That mean after the user get focus out from the Textbox CallWebMethod function will be fired. CallWebMethod will be implemented in step 6.   5-Add ScriptManager Control to your aspx file then reference the Web service by adding an asp:ServiceReference child element to the ScriptManager control and setting its path attribute to point to the Web service, That generate a JavaScript proxy class for calling the specified Web service from client script.   <asp:ScriptManager runat="server" ID="scriptManager"> <Services> <asp:ServiceReference Path="WebService.asmx" /> </Services> </asp:ScriptManager> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }     6-Define the JavaScript code to call the Web Service :   <script language="javascript" type="text/javascript">   // This function calls the Web service method // passing simple type parameters and the // callback function function CallWebMethod() { var User_Name = document.getElementById('<%=txtUserName.ClientID %>').value; WebService.CheckDuplicate(User_Name, OnSucceeded, OnError); }   // This is the callback function invoked if the Web service // succeeded function OnSucceeded(result) { var rsltElement = document.getElementById("lblDuplicate"); if (result == 1) rsltElement.innerHTML = "This User Name is exist"; else rsltElement.innerHTML = "";   }   function OnError(error) { // Display the error. alert("Service Error: " + error.get_message()); } </script> .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   This call references the WebService Class and CheckDuplicate Web Method defined in the service. It passes a User_Name value obtained from a textbox as well as a callback function named OnSucceeded that should be invoked when the asynchronous Web Service call returns. If the Web Service in different Namespace you can refer it before the class name this Main formula may help you :  NameSpaceName.ClassName.WebMethdName(Parameters , Success callback function, Error callback function); Parameters: you can pass one or many parameters. Success callback function :handles returned data from the service . Error callback function :Any errors that occur when the Web Service is called will trigger in this function. Using Error Callback function is optional.   Hope these steps help you to understand this approach.

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  • Making Sense of ASP.NET Paths

    - by Rick Strahl
    ASP.Net includes quite a plethora of properties to retrieve path information about the current request, control and application. There's a ton of information available about paths on the Request object, some of it appearing to overlap and some of it buried several levels down, and it can be confusing to find just the right path that you are looking for. To keep things straight I thought it a good idea to summarize the path options along with descriptions and example paths. I wrote a post about this a long time ago in 2004 and I find myself frequently going back to that page to quickly figure out which path I’m looking for in processing the current URL. Apparently a lot of people must be doing the same, because the original post is the second most visited even to this date on this blog to the tune of nearly 500 hits per day. So, I decided to update and expand a bit on the original post with a little more information and clarification based on the original comments. Request Object Paths Available Here's a list of the Path related properties on the Request object (and the Page object). Assume a path like http://www.west-wind.com/webstore/admin/paths.aspx for the paths below where webstore is the name of the virtual. .blackborder td { border-bottom: solid 1px silver; border-left: solid 1px silver; } Request Property Description and Value ApplicationPath Returns the web root-relative logical path to the virtual root of this app. /webstore/ PhysicalApplicationPath Returns local file system path of the virtual root for this app. c:\inetpub\wwwroot\webstore PhysicalPath Returns the local file system path to the current script or path. c:\inetpub\wwwroot\webstore\admin\paths.aspx Path FilePath CurrentExecutionFilePath All of these return the full root relative logical path to the script page including path and scriptname. CurrentExcecutionFilePath will return the ‘current’ request path after a Transfer/Execute call while FilePath will always return the original request’s path. /webstore/admin/paths.aspx AppRelativeCurrentExecutionFilePath Returns an ASP.NET root relative virtual path to the script or path for the current request. If in  a Transfer/Execute call the transferred Path is returned. ~/admin/paths.aspx PathInfo Returns any extra path following the script name. If no extra path is provided returns the root-relative path (returns text in red below). string.Empty if no PathInfo is available. /webstore/admin/paths.aspx/ExtraPathInfo RawUrl Returns the full root relative URL including querystring and extra path as a string. /webstore/admin/paths.aspx?sku=wwhelp40 Url Returns a fully qualified URL including querystring and extra path. Note this is a Uri instance rather than string. http://www.west-wind.com/webstore/admin/paths.aspx?sku=wwhelp40 UrlReferrer The fully qualified URL of the page that sent the request. This is also a Uri instance and this value is null if the page was directly accessed by typing into the address bar or using an HttpClient based Referrer client Http header. http://www.west-wind.com/webstore/default.aspx?Info Control.TemplateSourceDirectory Returns the logical path to the folder of the page, master or user control on which it is called. This is useful if you need to know the path only to a Page or control from within the control. For non-file controls this returns the Page path. /webstore/admin/ As you can see there’s a ton of information available there for each of the three common path formats: Physical Path is an OS type path that points to a path or file on disk. Logical Path is a Web path that is relative to the Web server’s root. It includes the virtual plus the application relative path. ~/ (Root-relative) Path is an ASP.NET specific path that includes ~/ to indicate the virtual root Web path. ASP.NET can convert virtual paths into either logical paths using Control.ResolveUrl(), or physical paths using Server.MapPath(). Root relative paths are useful for specifying portable URLs that don’t rely on relative directory structures and very useful from within control or component code. You should be able to get any necessary format from ASP.NET from just about any path or script using these mechanisms. ~/ Root Relative Paths and ResolveUrl() and ResolveClientUrl() ASP.NET supports root-relative virtual path syntax in most of its URL properties in Web Forms. So you can easily specify a root relative path in a control rather than a location relative path: <asp:Image runat="server" ID="imgHelp" ImageUrl="~/images/help.gif" /> ASP.NET internally resolves this URL by using ResolveUrl("~/images/help.gif") to arrive at the root-relative URL of /webstore/images/help.gif which uses the Request.ApplicationPath as the basepath to replace the ~. By convention any custom Web controls also should use ResolveUrl() on URL properties to provide the same functionality. In your own code you can use Page.ResolveUrl() or Control.ResolveUrl() to accomplish the same thing: string imgPath = this.ResolveUrl("~/images/help.gif"); imgHelp.ImageUrl = imgPath; Unfortunately ResolveUrl() is limited to WebForm pages, so if you’re in an HttpHandler or Module it’s not available. ASP.NET Mvc also has it’s own more generic version of ResolveUrl in Url.Decode: <script src="<%= Url.Content("~/scripts/new.js") %>" type="text/javascript"></script> which is part of the UrlHelper class. In ASP.NET MVC the above sort of syntax is actually even more crucial than in WebForms due to the fact that views are not referencing specific pages but rather are often path based which can lead to various variations on how a particular view is referenced. In a Module or Handler code Control.ResolveUrl() unfortunately is not available which in retrospect seems like an odd design choice – URL resolution really should happen on a Request basis not as part of the Page framework. Luckily you can also rely on the static VirtualPathUtility class: string path = VirtualPathUtility.ToAbsolute("~/admin/paths.aspx"); VirtualPathUtility also many other quite useful methods for dealing with paths and converting between the various kinds of paths supported. One thing to watch out for is that ToAbsolute() will throw an exception if a query string is provided and doesn’t work on fully qualified URLs. I wrote about this topic with a custom solution that works fully qualified URLs and query strings here (check comments for some interesting discussions too). Similar to ResolveUrl() is ResolveClientUrl() which creates a fully qualified HTTP path that includes the protocol and domain name. It’s rare that this full resolution is needed but can be useful in some scenarios. Mapping Virtual Paths to Physical Paths with Server.MapPath() If you need to map root relative or current folder relative URLs to physical URLs or you can use HttpContext.Current.Server.MapPath(). Inside of a Page you can do the following: string physicalPath = Server.MapPath("~/scripts/ww.jquery.js")); MapPath is pretty flexible and it understands both ASP.NET style virtual paths as well as plain relative paths, so the following also works. string physicalPath = Server.MapPath("scripts/silverlight.js"); as well as dot relative syntax: string physicalPath = Server.MapPath("../scripts/jquery.js"); Once you have the physical path you can perform standard System.IO Path and File operations on the file. Remember with physical paths and IO or copy operations you need to make sure you have permissions to access files and folders based on the Web server user account that is active (NETWORK SERVICE, ASPNET typically). Note the Server.MapPath will not map up beyond the virtual root of the application for security reasons. Server and Host Information Between these settings you can get all the information you may need to figure out where you are at and to build new Url if necessary. If you need to build a URL completely from scratch you can get access to information about the server you are accessing: Server Variable Function and Example SERVER_NAME The of the domain or IP Address wwww.west-wind.com or 127.0.0.1 SERVER_PORT The port that the request runs under. 80 SERVER_PORT_SECURE Determines whether https: was used. 0 or 1 APPL_MD_PATH ADSI DirectoryServices path to the virtual root directory. Note that LM typically doesn’t work for ADSI access so you should replace that with LOCALHOST or the machine’s NetBios name. /LM/W3SVC/1/ROOT/webstore Request.Url and Uri Parsing If you still need more control over the current request URL or  you need to create new URLs from an existing one, the current Request.Url Uri property offers a lot of control. Using the Uri class and UriBuilder makes it easy to retrieve parts of a URL and create new URLs based on existing URL. The UriBuilder class is the preferred way to create URLs – much preferable over creating URIs via string concatenation. Uri Property Function Scheme The URL scheme or protocol prefix. http or https Port The port if specifically specified. DnsSafeHost The domain name or local host NetBios machine name www.west-wind.com or rasnote LocalPath The full path of the URL including script name and extra PathInfo. /webstore/admin/paths.aspx Query The query string if any ?id=1 The Uri class itself is great for retrieving Uri parts, but most of the properties are read only if you need to modify a URL in order to change it you can use the UriBuilder class to load up an existing URL and modify it to create a new one. Here are a few common operations I’ve needed to do to get specific URLs: Convert the Request URL to an SSL/HTTPS link For example to take the current request URL and converted  it to a secure URL can be done like this: UriBuilder build = new UriBuilder(Request.Url); build.Scheme = "https"; build.Port = -1; // don't inject port Uri newUri = build.Uri; string newUrl = build.ToString(); Retrieve the fully qualified URL without a QueryString AFAIK, there’s no native routine to retrieve the current request URL without the query string. It’s easy to do with UriBuilder however: UriBuilder builder = newUriBuilder(Request.Url); builder.Query = ""; stringlogicalPathWithoutQuery = builder.ToString(); What else? I took a look through the old post’s comments and addressed as many of the questions and comments that came up in there. With a few small and silly exceptions this update post handles most of these. But I’m sure there are a more things that go in here. What else would be useful to put onto this post so it serves as a nice all in one place to go for path references? If you think of something leave a comment and I’ll try to update the post with it in the future.© Rick Strahl, West Wind Technologies, 2005-2010Posted in ASP.NET  

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