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  • Regexp for handling recursive arguments

    - by Matt
    Hi all, I'm a regexp novice, so I'm wondering what the regexp for the following: function {function arg1, arg2}, arg3 I'm looking to be able to just select the top-level arguments: {function arg1, arg2} & arg3 Ideally the response would be using preg_match in PHP, but almost any regexp would work fine. Thanks! Matt

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  • Help me understand this "Programming pearls" bitsort program

    - by ardsrk
    Jon Bentley in Column 1 of his book programming pearls introduces a technique for sorting a sequence of non-zero positive integers using bit vectors. I have taken the program bitsort.c from here and pasted it below: /* Copyright (C) 1999 Lucent Technologies */ /* From 'Programming Pearls' by Jon Bentley */ /* bitsort.c -- bitmap sort from Column 1 * Sort distinct integers in the range [0..N-1] */ #include <stdio.h> #define BITSPERWORD 32 #define SHIFT 5 #define MASK 0x1F #define N 10000000 int a[1 + N/BITSPERWORD]; void set(int i) { int sh = i>>SHIFT; a[i>>SHIFT] |= (1<<(i & MASK)); } void clr(int i) { a[i>>SHIFT] &= ~(1<<(i & MASK)); } int test(int i){ return a[i>>SHIFT] & (1<<(i & MASK)); } int main() { int i; for (i = 0; i < N; i++) clr(i); /*Replace above 2 lines with below 3 for word-parallel init int top = 1 + N/BITSPERWORD; for (i = 0; i < top; i++) a[i] = 0; */ while (scanf("%d", &i) != EOF) set(i); for (i = 0; i < N; i++) if (test(i)) printf("%d\n", i); return 0; } I understand what the functions clr, set and test are doing and explain them below: ( please correct me if I am wrong here ). clr clears the ith bit set sets the ith bit test returns the value at the ith bit Now, I don't understand how the functions do what they do. I am unable to figure out all the bit manipulation happening in those three functions. Please help.

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  • Recursion Question : Revision

    - by stan
    My slides say that: A recursive call should always be on a smaller data structure than the current one There must be a non recursive option if the data structure is too small You need a wrapper method to make the recursive method accessible Just reading this from the slides makes no sense, especially seeing as it was a topic from before christmas! Could anyone try and clear up what it means please? Thank you

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  • Handling touches during animation on iPhone

    - by SalvoMaltese
    I have a view with multiple controls inside (a picker, a switch, a slider...). I use an animation to move this view; it appears from bottom and goes up until it disappear by the top. I can't get the inside controls respond to touches while the view is moving. How can I catch those touches?

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  • [IE] Remove the complete styling of an HTML button/submit

    - by Saif Bechan
    Is there a way of completely removing the styling of a button in Internet Explorer? I use a css sprite for my button, and everything looks ok. But when I click the button, it moves to the top a little, it makes it look out of shape. Is there a css click state, or mousedown? I don't know what triggers that state. I know it's not a really big deal, but sometimes it's the small things that matter.

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  • A two way minimum spanning tree of a directed graph

    - by mvid
    Given a directed graph with weighted edges, what algorithm can be used to give a sub-graph that has minimum weight, but allows movement from any vertex to any other vertex in the graph (under the assumption that paths between any two vertices always exist). Does such an algorithm exist?

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  • Svn auto updater

    - by uzay95
    I am writing my code in my virtual machine and always committing the folder that contains published web site to the free svn server. There is also another remote machine which is test server. I would like to make auto update in the remote machine. Is there any program can make auto update in every 30 seconds?

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  • Curvey Redraw tabs working fine on Firefox , problem with IE

    - by Rohit
    Hi, I have used curvey redraw library from google code(http://code.google.com/p/curvycorners/) & it has solved my purpose, though now as per new req i am struggling with IE. I want to have two tab rows each containing 2 tabs. <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>curvyCorners - Tab demo</title> <style type="text/css">/*<![CDATA[*/ /* tab styles */ #tabrow { margin:0; padding-left:1ex; min-width:800px; font-size:small; letter-spacing:0.3pt; line-height:1; height:24px; } #tabrow ul { margin:0; padding:0; list-style:none; position:absolute; z-index:2; } #tabrow li { float:left; background-color:#E0DFE3; color:#000; margin-right:5px; padding:5px; -webkit-border-top-left-radius:5px; -webkit-border-top-right-radius:5px; -moz-border-radius-topleft:5px; -moz-border-radius-topright:5px; border-top:solid #9B9B9B 1px; border-left:solid #9B9B9B 1px; border-right:solid #9B9B9B 1px; border-bottom-width:0; border-bottom-color:transparent; cursor:pointer; font-family:verdana;font-weight:bold;font-style:italic } #tabrow li.select { background-color:#ffffff; color:#2470c4; height:14px; } /* page styles */ #midbox { width:220px; height:305px; -webkit-border-radius: 5px; -moz-border-radius: 5px; } #midbox { border: solid #9b9b9b 1px; background-color:#ffffff; } #midbox p { margin:0; padding-bottom:1ex; } h1, #topbox h2 { margin:0 15pt; padding: 5pt 0; } div.subpage { padding:1em; } /*]]>*/ </style> <script type="text/javascript" src="curvs.js"> </script> <script type="text/javascript">//<![CDATA[ var selectedTab = 0; function tabclick(n) { if (n === selectedTab) return; // nothing to do. var li = document.getElementById('tab' + selectedTab); curvyCorners.adjust(li, 'className', ''); // Remove the 'select' style li = document.getElementById('page' + selectedTab); li.style.display = 'none'; // hide the currently selected sub-page li = document.getElementById('page' + n); li.style.display = 'block'; // show the new sub-page li = document.getElementById('tab' + n); // get the new (clicked) tab curvyCorners.adjust(li, 'className', 'select'); // and update its style curvyCorners.redraw(); // Redraw all elements with className curvyRedraw selectedTab = n; // store for future reference } var selectedTab1 = 2; function tabclick1(n) { if (n === selectedTab1) return; // nothing to do. var li = document.getElementById('tab' + selectedTab1); curvyCorners.adjust(li, 'className', ''); // Remove the 'select' style li = document.getElementById('page' + selectedTab1); li.style.display = 'none'; // hide the currently selected sub-page li = document.getElementById('page' + n); li.style.display = 'block'; // show the new sub-page li = document.getElementById('tab' + n); // get the new (clicked) tab curvyCorners.adjust(li, 'className', 'select'); // and update its style curvyCorners.redraw(); // Redraw all elements with className curvyRedraw selectedTab1 = n; // store for future reference } //]]> </script> </head> <body> <div id="tabrow"> <ul> <li id="tab0" onclick="tabclick(0);" class="select curvyRedraw">Categories</li> <li id="tab1" onclick="tabclick(1);" class="curvyRedraw">Services</li> </ul> </div> <div id="midbox" class="curvyRedraw"> <div id="page0" class="subpage"> Category details </div> <div id="page1" class="subpage" style="display:none"> Service details </div> </div> <br/><br/> <div id="tabrow"> <ul> <li id="tab2" onclick="tabclick1(2);" class="select curvyRedraw">Recent Activiites</li> <li id="tab3" onclick="tabclick1(3);" class="curvyRedraw">News</li> </ul> </div> <div id="midbox" class="curvyRedraw"> <div id="page2" class="subpage"> Activities </div> <div id="page3" class="subpage" style="display:none"> News </div> </div> </body> </html> Can you please help me out in this? Thanks, Rohit.

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  • Grid overlayed on image using javascript, need help getting grid coordinates.

    - by Alos
    Hi I am fairly new to javascript and could use some help, I am trying to overlay a grid on top of an image and then be able to have the user click on the grid and get the grid coordinate from the box that the user clicked. I have been working with the code from the following stackoverflow question: Creating a grid overlay over image. link text Here is the code that I have so far: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> </script> <script type="text/javascript"> var SetGrid = function(el, sz, nr, nc){ //get number of rows/columns according to the 'grid' size //numcols = el.getSize().x/sz; //numrows = el.getSize().y/sz; numcols = 48; numrows = 32; //create table element for injecting cols/rows var gridTable = new Element('table', { 'id' : 'gridTable', 'styles' : { 'width' : el.getSize().x, 'height' : el.getSize().y, 'top' : el.getCoordinates().top, 'left' : el.getCoordinates().left } }); //inject rows/cols into gridTable for (row = 1; row<=numrows; row++){ thisRow = new Element('tr', { 'id' : row, 'class' : 'gridRow' }); for(col = 1; col<=numcols; col++){ thisCol = new Element('td', { 'id' : col, 'class' : 'gridCol0' }); //each cell gets down/up over event... down starts dragging|up stops|over draws area if down was fired thisCol.addEvents({ 'mousedown' : function(){ dragFlag = true; startRow = this.getParent().get('id'); startCol = this.get('id'); }, 'mouseup' : function(){ dragFlag = false; }, 'mouseover' : function(){ if (dragFlag==true){ this.set('class', 'gridCol'+$$('#lvlSelect .on').get('value')); } }, 'click' : function(){ //this.set('class', 'gridCol'+$$('#lvlSelect .on').get('id').substr(3, 1) ); str = $$('#lvlSelect .on').get('id'); alert(str.substr(2, 3)); } }); thisCol.inject(thisRow, 'bottom'); }; thisRow.inject(gridTable, 'bottom'); }; gridTable.inject(el.getParent()); } //sens level selector func var SetSensitivitySelector = function(el, sz, nr, nc){ $$('#lvlSelect ul li').each(function(el){ el.addEvents({ 'click' : function(){ $$('#lvlSelect ul li').set('class', ''); this.set('class', 'on'); }, 'mouseover' : function(){ el.setStyle('cursor','pointer'); }, 'mouseout' : function(){ el.setStyle('cursor',''); } }); }); } //execute window.addEvent('load', function(){ SetGrid($('imagetomap'), 32); SetSensitivitySelector(); }); var gridSize = { x: 48, y: 32 }; var img = document.getElementById('imagetomap'); img.onclick = function(e) { if (!e) e = window.event; alert(Math.floor(e.offsetX/ gridSize.x) + ', ' + Math.floor(e.offsetY / gridSize.y)); } </script> <style> #imagetomapdiv { float:left; display: block; } #gridTable { border:1px solid red; border-collapse:collapse; position:absolute; z-index:5; } #gridTable td { opacity:0.2; filter:alpha(opacity=20); } #gridTable .gridCol0 { border:1px solid gray; background-color: none; } #gridTable .gridCol1 { border:1px solid gray; background-color: green; } #gridTable .gridCol2 { border:1px solid gray; background-color: blue; } #gridTable .gridCol3 { border:1px solid gray; background-color: yellow; } #gridTable .gridCol4 { border:1px solid gray; background-color: orange; } #gridTable .gridCol5 { border:1px solid gray; background-color: red; } #lvlSelect ul {float: left; display:block; position:relative; margin-left: 20px; padding: 10px; } #lvlSelect ul li { width:40px; text-align:center; display:block; border:1px solid black; position:relative; padding: 10px; list-style:none; opacity:0.2; filter:alpha(opacity=20); } #lvlSelect ul li.on { opacity:1; filter:alpha(opacity=100); } #lvlSelect ul #li0 { background-color: none; } #lvlSelect ul #li1 { background-color: green; } #lvlSelect ul #li2 { background-color: blue; } #lvlSelect ul #li3 { background-color: yellow; } #lvlSelect ul #li4 { background-color: orange; } #lvlSelect ul #li5 { background-color: red; } </style> </div> <div id="lvlSelect"> <ul> <li value="0" id="li0">0</li> <li value="1" id="li1">1</li> <li value="2" id="li2">2</li> <li value="3" id="li3">3</li> <li value="4" id="li4">4</li> <li value="5" id="li5" class="on">5</li> </ul> </div> In this example the grid box changes color when the image is grid box is clicked, but I would like to be able to have the coordinates of the box. Any help would be great. Thank you

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  • Resharper Warnings with MVVM

    - by Dan Bryant
    As I implement the MVVM pattern with WPF, I'm finding that Resharper is often warning me that certain properties are never used in my ViewModels. The problem is that they are being used, but only by the data binding system. Has anyone else encountered this annoyance and is there a way to help Resharper realize that these properties are, indeed, being used? I am glad, at least, that VS 2010 properly realizes that [Import] tagged members won't "always be null", but hopefully I can fix this issue as well.

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  • PHP code to convert a MySQL query to CSV

    - by Reilly
    What is the most efficient way to convert a MySQL query to CSV in PHP please? It would be best to avoid temp files as this reduces portability (dir paths and setting file-system permissions required). The CSV should also include one top line of field names. Cheers.

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  • iPhone: Error when using -(id)initWithNibName

    - by Nic Hubbard
    I am trying to use the following code, but I always get an error that I can find little information about: - (id)initWithNibName:@"MyRidesListView" bundle:nil { if ((self = [super initWithNibName:@"MyRidesListView" bundle:nil])) { // Custom initialization } return self; } Error: expected identifier before 'OBJC_STRING' token This seems like a simple method to be calling. This is for a UINavigationController. Ideas?

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  • Reformatting a Java String

    - by Travis
    I have a string that looks like this: CALDARI_STARSHIP_ENGINEERING and I need to edit it to look like Caldari Starship Engineering Unfortunately it's three in the morning and I cannot for the life of me figure this out. I've always had trouble with replacing stuff in strings so any help would be awesome and would help me understand how to do this in the future.

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  • Translate SQL query to LINQ

    - by ile
    PhotoAlbums table AlbumID Title Date Photos table: PhotoID Title Date AlbumID SELECT AlbumID, Title, Date, (SELECT TOP (1) PhotoID FROM Photos AS c WHERE (AlbumID = a.AlbumID)) AS PhotoID FROM PhotoAlbums AS a I need this query written in LINQ-to-SQL. Thanks in advance

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