Search Results

Search found 6796 results on 272 pages for 'cakephp forms'.

Page 52/272 | < Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >

  • Is it possible to make an online registration process for a course in Google Docs with a cap on registrations?

    - by user61551
    I am trying to build an online registration form for an institute I intern at that is running a training programme with multiple courses and hundreds of applicants. I've done registration forms with Google Docs Forms before, but the tricky spot this time round is that I'm trying to put a registration cap on each of the courses. Every person needs to register for one course in every timeslot, and there are seven or so timeslots. However, as seating space in every venue is limited, we would like to cap registrations per course (venue) to 200 per course, after which either a) the applicant will be informed that they need to register for another course in that timeslot if they apply to a full course, or b) ideal case scenario, the option will be greyed out. Is this possible using Google Docs Forms at all? If not, is there a free alternative that might do the job properly?

    Read the article

  • TypeError while using django Form in editing an Entry

    - by damon
    I have an Entry model which can belong to a Category.I am providing a CategoryChoicesForm sothat the user can choose from various Categorys (from a dropdown list)when an Entry is created or edited. I am having trouble with the CategoryChoicesForm while editing the Entry.It throws a TypeError.. If somebody can make out what is happening..please advise me how to correct this. int() argument must be a string or a number, not 'QueryDict' /home/Django-1.4/django/db/models/fields/__init__.py in get_prep_value, line 537 ...views.py in edit_entry category_choices_form = CategoryChoicesForm(form_data) ... ...forms.py in __init__ self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) Here is the form class CategoryChoicesForm(forms.Form): categoryoption = forms.ModelChoiceField( queryset = Category.objects.none(), required=False,label='Category') def __init__(self, categorycreator,*args, **kwargs): super(CategoryChoicesForm, self).__init__(*args, **kwargs) self.creator=categorycreator self.fields['categoryoption'].queryset = Category.objects.filter(creator=self.creator) The edit_entry view is as follows @login_required @transaction.commit_on_success def edit_entry(request,id,template_name,page_title): form_data = get_form_data(request) entry = get_object_or_404(Entry,pk=id,author=request.user) ... category_choices_form = CategoryChoicesForm(form_data) ...

    Read the article

  • Simple animation using C#/Windows Forms

    - by clintp
    I need to knock out a quick animation in C#/Windows Forms for a Halloween display. Just some 2D shapes moving about on a solid background. Since this is just a quick one-off project I really don't want to install and learn an entire new set of tools for this. (DirectX dev kits, Silverlight, Flash, etc..) I also have to install this on multiple computers so anything beyond the basic .Net framework (2.0) would be a pain in the arse. For tools I've got VS2k8, 25 years of development experience, a wheelbarrow, holocaust cloak, and about 2 days to knock this out. I haven't done animation since using assembler on my Atari 130XE (hooray for page flipping and player/missile graphics!) Advice? Here's some of the things I'd like to know: I can draw on any empty widget (like a panel) by fiddling with it's OnPaint handler, right? That's how I'd draw a custom widget. Is there a better technique than this? Is there a page-flipping technique for this kind of thing in Windows Forms? I'm not looking for a high frame rate, just as little flicker/drawing as necessary. Thanks. Post Mortem Edit ... "a couple of coding days later" Well, the project is done. The links below came in handy although a couple of them were 404. (I wish SO would allow more than one reply to be marked "correct"). The biggest problem I had to overcome was flickering, and a persistent bug when I tried to draw on the form directly. Using the OnPaint event for the Form: bad idea. I never got that to work; lots of mysterious errors (stack overflows, or ArgumentNullExceptions). I wound up using a panel sized to fill the form and that worked fine. Using the OnPaint method is slow anyway. Somewhere online I read that building the PaintEventArgs was slow, and they weren't kidding. Lots of flickering went away when I abandoned this. Skip the OnPaint/Invalidate() and just paint it yourself. Setting all of the "double buffering" options on the form still left some flicker that had to be fixed. (And I found conflicting docs that said "set them on the control" and "set them on the form". Well controls don't have a .SetStyle() method.) I haven't tested without them, so they might be doing something (this is the form): this.SetStyle(ControlStyles.UserPaint, true); this.SetStyle(ControlStyles.OptimizedDoubleBuffer, true); this.SetStyle(ControlStyles.AllPaintingInWmPaint, true); So the workhorse of the code wound up looking like (pf is the panel control): void PaintPlayField() { Bitmap bufl = new Bitmap(pf.Width, pf.Height); using (Graphics g = Graphics.FromImage(bufl)) { g.FillRectangle(Brushes.Black, new Rectangle(0, 0, pf.Width, pf.Height)); DrawItems(g); DrawMoreItems(g); pf.CreateGraphics().DrawImageUnscaled(bufl, 0, 0); } } And I just called PaintPlayField from the inside of my Timer loop. No flicker at all.

    Read the article

  • Error in loading component property (Swing GUI Forms)

    - by Christo Du Preez
    For no apparent reason all my Swing GUI forms using components linked to org.jdesktop.beansbinding.Converter started generating errors when trying to open the Design View: Error Error in loading component property: [JPanel]-filterTextField-converter. Cannot load property type class org.jdesktop.beansbinding.Converter. The property cannot be loaded. Errors occurred in loading... I'm currently using Netbeans 6.8. I opened my project in Netbeans 6.7.1 and all was fine but after a while the same thing happened. Looking at the .form and .java files and comparing it to previous backups, everything looks fine. Even my Netbeans tutorial project no longer works. What can cause this. Any suggestions would greatly be appreciated. After further investigation this is taken from my IDE's log : INFO: msg org.openide.ErrorManager$AnnException: msg at org.openide.ErrorManager$AnnException.findOrCreate(ErrorManager.java:867) at org.openide.ErrorManager$DelegatingErrorManager.annotate(ErrorManager.java:650) at org.netbeans.modules.form.GandalfPersistenceManager.annotateException(GandalfPersistenceManager.java:230) at org.netbeans.modules.form.GandalfPersistenceManager.annotateException(GandalfPersistenceManager.java:240) at org.netbeans.modules.form.GandalfPersistenceManager.getPropertyType(GandalfPersistenceManager.java:2362) at org.netbeans.modules.form.GandalfPersistenceManager.loadProperty(GandalfPersistenceManager.java:2041) at org.netbeans.modules.form.GandalfPersistenceManager.loadBindingProperties(GandalfPersistenceManager.java:2627) at org.netbeans.modules.form.GandalfPersistenceManager.loadComponent(GandalfPersistenceManager.java:900) at org.netbeans.modules.form.GandalfPersistenceManager.restoreComponent(GandalfPersistenceManager.java:845) at org.netbeans.modules.form.GandalfPersistenceManager.loadComponent(GandalfPersistenceManager.java:979) at org.netbeans.modules.form.GandalfPersistenceManager.restoreComponent(GandalfPersistenceManager.java:845) at org.netbeans.modules.form.GandalfPersistenceManager.loadNonVisuals(GandalfPersistenceManager.java:695) at org.netbeans.modules.form.GandalfPersistenceManager.loadForm(GandalfPersistenceManager.java:529) at org.netbeans.modules.form.GandalfPersistenceManager.loadForm(GandalfPersistenceManager.java:290) at org.netbeans.modules.form.FormEditor$3.run(FormEditor.java:339) at org.netbeans.modules.form.FormLAF$2.run(FormLAF.java:287) at org.openide.util.Mutex.doEventAccess(Mutex.java:1355) at org.openide.util.Mutex.readAccess(Mutex.java:317) at org.netbeans.modules.form.FormLAF.executeWithLookAndFeel(FormLAF.java:272) at org.netbeans.modules.form.FormEditor.loadFormData(FormEditor.java:337) at org.netbeans.modules.form.FormEditor.loadForm(FormEditor.java:266) at org.netbeans.modules.form.FormEditorSupport.loadForm(FormEditorSupport.java:306) at org.netbeans.modules.form.FormEditorSupport$3.run(FormEditorSupport.java:457) at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:209) at java.awt.EventQueue.dispatchEvent(EventQueue.java:597) at org.netbeans.core.TimableEventQueue.dispatchEvent(TimableEventQueue.java:125) at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:269) at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:184) at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:174) at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:169) at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:161) at java.awt.EventDispatchThread.run(EventDispatchThread.java:122) Caused by: java.lang.ClassNotFoundException: Will not load class org.jdesktop.beansbinding.Converter arbitrarily from one of ModuleCL@738d08[org.jdesktop.beansbinding] and ModuleCL@167e3a5[javax.beans.binding] starting from SystemClassLoader[556 modules]; see http://wiki.netbeans.org/DevFaqModuleCCE at org.netbeans.ProxyClassLoader.loadClass(ProxyClassLoader.java:241) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at org.netbeans.modules.form.project.FormClassLoader.findClass(FormClassLoader.java:83) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:247) at org.netbeans.modules.form.project.ClassPathUtils.loadClass(ClassPathUtils.java:95) at org.netbeans.modules.form.FormUtils.loadClass(FormUtils.java:1445) at org.netbeans.modules.form.PersistenceObjectRegistry.loadClass(PersistenceObjectRegistry.java:95) at org.netbeans.modules.form.GandalfPersistenceManager.getClassFromString(GandalfPersistenceManager.java:5516) at org.netbeans.modules.form.GandalfPersistenceManager.getPropertyType(GandalfPersistenceManager.java:2348) ... 27 more msg Error in loading component property: Other Components-mainPanel-jTextField1-converter Cannot load property type class org.jdesktop.beansbinding.Converter. The property cannot be loaded. Can someone please help me with this issue. This is still not resolved and not being able to edit my Forms or loosing binding properties every time I need to edit a Form is a real pain and time consuming! Any help would greatly be appreciated. Thanx.

    Read the article

  • What framework would allow for the largest coverage of freelance developers in the media/digital mar

    - by optician
    This question is not about which is the best, it is about which makes the most business sense to use as a company's platform of choice for ongoing freelance development. I'm currently trying to decide what framework to move my company in regarding frameworks for web application work. Options are ASP.NET MVC Django CakePHP/Symfony etc.. Struts Pearl on Rails Please feel free to add more to the discussion. I currently work in ASP.NET MVC in my Spare time, and find it incredibly enjoyable to work with. It is my first experince with an MVC framework for the web, so I can't talk on the others. The reason for not pushing this at the company is that I feel that there are not many developers in the Media/Marketing world who would work with this, so it may be hard to extend the team, or at least cost more. I would like to move into learning and pushing Django, partly to learn python, partly to feel a bit cooler (all my geeky friends use Java/Python/c++). Microsoft is the dark side to most company's I work with (Marketing/Media focused). But again I'm worried about developers in this sector. PHP seems like the natural choice, but I'm scared by the sheer amount of possible frameworks, and also that the quality of developer may be lower. I know there are great php developers out there, but how many of them know multiple frameworks? Are they similar enough that anyone decent at php can pick them up? Just put struts in the list as an option, but personally I live with a Java developer, and considering my experience with c#, I'm just not that interested in learning Java (selfish personal geeky reasons) Final option was a joke http://www.bbc.co.uk/blogs/radiolabs/2007/11/perl_on_rails.shtml

    Read the article

  • VS2008 Windows Form Designer does not like my control.

    - by Thedric Walker
    I have a control that is created like so: public partial class MYControl : MyControlBase { public string InnerText { get { return textBox1.Text; } set { textBox1.Text = value; } } public MYControl() { InitializeComponent(); } } partial class MYControl { /// <summary> /// Required designer variable. /// </summary> private System.ComponentModel.IContainer components = null; /// <summary> /// Clean up any resources being used. /// </summary> /// <param name="disposing">true if managed resources should be disposed; otherwise, false.</param> protected override void Dispose(bool disposing) { if (disposing && (components != null)) { components.Dispose(); } base.Dispose(disposing); } #region Component Designer generated code /// <summary> /// Required method for Designer support - do not modify /// the contents of this method with the code editor. /// </summary> private void InitializeComponent() { this.textBox1 = new System.Windows.Forms.TextBox(); this.listBox1 = new System.Windows.Forms.ListBox(); this.label1 = new System.Windows.Forms.Label(); this.SuspendLayout(); // // textBox1 // this.textBox1.Location = new System.Drawing.Point(28, 61); this.textBox1.Name = "textBox1"; this.textBox1.Size = new System.Drawing.Size(100, 20); this.textBox1.TabIndex = 0; // // listBox1 // this.listBox1.FormattingEnabled = true; this.listBox1.Location = new System.Drawing.Point(7, 106); this.listBox1.Name = "listBox1"; this.listBox1.Size = new System.Drawing.Size(120, 95); this.listBox1.TabIndex = 1; // // label1 // this.label1.AutoSize = true; this.label1.Location = new System.Drawing.Point(91, 42); this.label1.Name = "label1"; this.label1.Size = new System.Drawing.Size(35, 13); this.label1.TabIndex = 2; this.label1.Text = "label1"; // // MYControl // this.AutoScaleDimensions = new System.Drawing.SizeF(6F, 13F); this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font; this.Controls.Add(this.label1); this.Controls.Add(this.listBox1); this.Controls.Add(this.textBox1); this.Name = "MYControl"; this.Size = new System.Drawing.Size(135, 214); this.ResumeLayout(false); this.PerformLayout(); } #endregion private System.Windows.Forms.Label label1; } MyControlBase contains the definition for the ListBox and TextBox. Now when I try to view this control in the Form Designer it gives me these errors: The variable 'listBox1' is either undeclared or was never assigned. The variable 'textBox1' is either undeclared or was never assigned. This is obviously wrong as they are defined in MyControlBase with public access. Is there any way to massage Form Designer into allowing me to visually edit my control?

    Read the article

  • Manually start session with specific id / transitioning session cookie between domains

    - by deceze
    My host requires me to use a different domain for SSL secured access (shared SSL), so I need to transition the user session between two domains. One part of the page lives at http://example.com, while the SSL'd part is at https://example.hosting.com. As such I can't set a domain-spanning cookie. What I'm trying to do is to transition the session id over and re-set the cookie like this: http://example.com/normal/page, user clicks link to secure area and goes to: http://example.com/secure/page, which causes a redirect to: https://example.hosting.com/secure/page?sess=ikub..., which resurrects the session and sets a new cookie valid for the domain, then redirects to: https://example.hosting.com/secure/page This works up to the point where the session should be resurrected. I'm doing: function beforeFilter() { ... $this->Session->id($_GET['sess']); $this->Session->activate(); ... } As far as I can tell this should start the session with the given ID. It actually generates a new session ID though and this session is empty, the data is not restored. This is on CakePHP 1.2.4. Do I need to do something else, or is there a better way to do what I'm trying to do?

    Read the article

  • Forms bound to updateable ADO recordsets are not updateable when the source includes a JOIN

    - by Art
    I'm developing an application in Access 2007. It uses an .accdb front end connecting to an SQL Server 2005 backend. I use forms that are bound to ADO recordsets at runtime. For the sake of efficiency, the recordsets usually contain only one record, and are queried out on the server: Public Sub SetUpFormRecordset(cn As ADODB.Connection, rstIn As ADODB.Recordset, rstSource As String) Dim cmd As ADODB.Command Dim I As Long Set cmd = New ADODB.Command cn.Errors.Clear ' Recordsets based on command object Execute method are Read Only! With cmd Set .ActiveConnection = cn .CommandType = adCmdText .CommandText = rstSource End With With rstIn .CursorType = adOpenKeyset .LockType = adLockPessimistic 'Check the locktype after opening; optimistic locking is worthless on a bound End With ' form, and ADO might open optimistically without firing an error! rstIn.Open cmd, , adOpenKeyset, adLockPessimistic 'This should run the query on the server and return an updatable recordset With cn If .Errors.Count <> 0 Then For Each errADO In .Errors Call HandleADOErrors(.Errors(I)) I = I + 1 Next errADO End If End With End Sub rstSource (the string containg the TSQL on which the recordset is based) is assembled by the calling routine, in this case from the Open event of the form being bound: Private Sub Form_Open(Cancel As Integer) Dim rst As ADODB.Recordset Dim strSource As String, DefaultSource as String Dim lngID As Long lngID = Forms!MyParent.CurrentID strSource = "SELECT TOP (100) PERCENT dbo.Customers.CustomerID, dbo.Customers.LegacyID, dbo.Customers.Active, dbo.Customers.TypeID, dbo.Customers.Category, " & _ "dbo.Customers.Source, dbo.Customers.CustomerName, dbo.Customers.CustAddrID, dbo.Customers.Email, dbo.Customers.TaxExempt, dbo.Customers.SalesTaxCode, " & _ "dbo.Customers.SalesTax2Code, dbo.Customers.CreditLimit, dbo.Customers.CreationDate, dbo.Customers.FirstOrder, dbo.Customers.LastOrder, " & _ "dbo.Customers.nOrders, dbo.Customers.Concurrency, dbo.Customers.LegacyLN, dbo.Addresses.AddrType, dbo.Addresses.AddrLine1, dbo.Addresses.AddrLine2, " & _ "dbo.Addresses.City, dbo.Addresses.State, dbo.Addresses.Country, dbo.Addresses.PostalCode, dbo.Addresses.PhoneLandline, dbo.Addresses.Concurrency " & _ "FROM dbo.Customers INNER JOIN " & _ "dbo.Addresses ON dbo.Customers.CustAddrID = dbo.Addresses.AddrID " strSource = strSource & "WHERE dbo.Customers.CustomerID= " & lngID With Me 'Default is Set up for editing one record If Not Nz(.RecordSource, vbNullString) = vbNullString Then If .Dirty Then .Dirty = False 'Save any changes on the form .RecordSource = vbNullString End If If rst Is Nothing Then 'Might not be first time through DefaultSource = .RecordSource Else rst.Close Set rst = Nothing End If End With Set rst = New ADODB.Recordset Call setupformrecordset(dbconn, rst, strSource) 'dbconn is a global variable With Me Set .Recordset = rst End With End Sub The recordset that is returned from setupformrecordset is fully updateable, and its .Supports property shows this. It can be edited and updated in code. The entire form, however, is read only, even though it's .AllowEdits and .AllowAdditions properties are both true. Even the fields from the right hand side (the 'many' side) cannot be edited. Removing the INNER JOIN clause from the TSQL (restricting strSource to one table) makes the form fully editable. I've verified that the TSQL includes priimary key fields from both tables, and each table includes a timestamp field for concurrency. I tried changing the .CursorType and .CursorLocation properties of the recordset to no avail. What am I doing wrong?

    Read the article

  • Unable to render php files in browser

    - by p1
    Hello, I am very new to php, and I am trying to develop a facebook application using php. I am using Joyent as my hosting platform. Currently, I am trying to do some simple scripts in php and then build on them. However I am unable to see any php files being rendered properly in my application. For eg: I have a simple script called phpinfo.php: If I execute this on terminal like php phpinfo.php , I can see all the configurations. However if I try to access the same file as http://xxxxxx.facebook.joyent.us/phpinfo.php, I get : Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. Even if I rename this file to index.php its still the same. However I am able to access other html files [index.html] on the same location . These are some of my php settings: These are some of the settings: [fbkusoni:~/web/public] aafhe7vh$ php phpinfo.php | grep On allow_url_fopen = On = On auto_globals_jit = On = On enable_dl = On = On file_uploads = On = On ignore_repeated_errors = On = On ignore_repeated_source = On = On implicit_flush = On = On log_errors = On = On register_argc_argv = On = On report_memleaks = On = On y2k_compliance = On = On Multibyte regex (oniguruma) backtrack check = On mysql.allow_persistent = On = On session.bug_compat_warn = On = On session.use_cookies = On = On suhosin.cookie.cryptdocroot = On = On suhosin.cookie.cryptua = On = On suhosin.mt_srand.ignore = On = On suhosin.protectkey = On = On suhosin.server.encode = On = On suhosin.server.strip = On = On suhosin.session.cryptdocroot = On = On suhosin.session.cryptua = On = On suhosin.session.encrypt = On = On suhosin.srand.ignore = On = On suhosin.stealth = On = On The answer might be very naive, but I am just trying to get started and looking for any suggestions regarding this and also using Joyent and cakephp to develop facebook applications. Thanks.

    Read the article

  • Facebook Like Meta Tags not showing Images

    - by Hooman Ahmadi
    I have implemented the Facebook Like button on all our pages and it works properly by posting to Facebook with the correct meta tags. However, the images do not show in Facebook. The image meta tags show up properly when I use the Facebook Linter, but they don't show on someone's facebook page where the Like is posted on their wall. Also, is there any way to have the info recache more often? The tags take forever to update. Our site is built with CakePHP. Below are snippets of my code, thanks: <html xmlns="http://www.w3.org/1999/xhtml" xmlns:og="http://ogp.me/ns#" xmlns:fb="http://www.facebook.com/2008/fbml"> <head> <script src="http://connect.facebook.net/en_US/all.js#xfbml=1"></script> <script type="text/javascript" src="http://use.typekit.com/wlx8xgm.js"></script> <script type="text/javascript">try{Typekit.load();}catch(e){}</script> <?php if(!isset($meta_title)) { $meta_title = $title_for_layout; } if(!isset($meta_location)) { $meta_location = null; } if(!isset($meta_image)) { $meta_image = null; } if(!isset($meta_type)) { $meta_type = null; } ?> <meta property="og:title" content="<?= $meta_title ?>"/> <meta property="og:type" content="<?= $meta_type ?>"/> <meta property="og:url" content="<?= $meta_location ?>"/> <meta property="og:image" content="<?= $meta_image ?>"/> <meta property="fb:admins" content="1004432800"/> ... echo '<br><br><fb:like href="' . $fbook_url . '" width="300" height="80" layout="standard" show_faces="true" colorscheme="light"></fb:like>';

    Read the article

  • What are good hosting companies for PHP 5.3 Mysql / CouchDb / MongoDB Dev ( Lithium / CakePHP Framew

    - by Abba Bryant
    I am looking for a quality reliable host for some lithium development. I don't mind a shared platform as long as I have some ssh access. I require php 5.3.x, Mysql 5.x, and the usual imageMagick etc. Non-relational DB support up front would be nice but if they let me set one up myself I would be okay with doing it. I don't need a lot in the way of control panel tools. Good ones are appreciated but bad ones I would prefer not to even deal with. I don't anticipate needing much in the way of email but mail support would be nice to have. Cost isn't a big issue. I don't want to pay an arm and a leg but don't mind paying for what I need. Good support and decent uptime would be nice but I don't need an SLO or anything.

    Read the article

  • Web application architecture, and application servers?

    - by seanieb
    Hi, I'm building a web application, and I need to use an architecture that allows me to run it on two servers. The application scrapes information from other sites periodically, and on input from the end user. To do this I'm using Php+curl to scrape the information, Php or python to parse it and store the results in a MySQLDB. Then I will use Python to run some algorithms on the data, this will happen both periodically and on input from the end user. I'm going to cache some of the results in the MySQL DB and sometimes if it is specific to the user, skip storing the data and serve it to the user. I'm think of using Php for the website front end on a separate web server, running the Php spider, MySQL DB and python on another server. As you can see I'm fairly clueless. I'm familiar with using Php, MySQL and the basics of Python, but bringing this all together using something more complex than a cron job is new to me. How do go about implementing this? What frame work(s) should I use? Is MVC a good architecture for this? (I'm new to MVC, architectures etc.) Is Cakephp a good solution? If so will I be able to control and monitor the Python code using it?

    Read the article

  • Trouble with Router::url() when using named parameters

    - by sibidiba
    I'm generating plain simple links with CakePHP's HtmlHelper the following way: $html->link("Newest", array( 'controller' => 'posts', 'action' => 'listView', 'page'=> 1, 'sort'=>'Question.created', 'direction'=>'desc', )); Having the following route rule: Router::connect('/foobar/*',array( 'controller' => 'posts', 'action' => 'listView' )); The link is nicely generated as /foobar/page:1/sort:Question.created/direction:desc. Just as I want, it uses my URL prefix instead of controller/action names. However, for some links I must add named parameters like this: $html->link("Newest", array( 'controller' => 'posts', 'action' => 'listView', 'page'=> 1, 'sort'=>'Question.created', 'direction'=>'desc', 'namedParameter' => 'namedParameterValue' )); The link in this case points to /posts/listView/page:1/sort:Question.created/direction:desc/namedParameter:namedParameterValue. But I do not want to have contoller/action names in my URL-s, why is Cake ignoring in this case my routers configuration?

    Read the article

  • Lost Array After Validation Error

    - by Georges Kmeid
    I'm working on a CakePHP project and I have User, Post and Location models among others. User hasMany Location and Post belongsTo User so Location is not directly related to Post. This is my code in the Post controller: public function add() { if ($this->request->is('get')) { $this->loadModel('Location'); $this->set('locations', $this->Location->find('all', array('conditions' => array('user_id' => $this->Auth->user('id'))))); } ... } And this is my code in the posts/add view: <?php $i = 0; $j = 0; foreach ($locations as $location): $location_names[$i] = $location['Location']['name']; $i++; endforeach; echo "<select name=\"location\" onchange=\"select(this.value)\">"; echo "<option value=\"\">Select a saved location</option>"; foreach ($locations as $location): echo "<option value=\"" . $location['Location']['latitude'] . "," . $location['Location']['longitude'] . "\">" . $location_names[$j] . "</option>"; $j++; endforeach; ?> </select> If I enter a wrong value in one of the post inputs that has a validation rule in Post model, it redirects to the current add view, shows what is the validation error, but then the $locations array passed from controller to view disappears and can't use it in view and I get this error: Notice (8): Undefined variable: locations [APP\View\Posts\add.ctp, line 68]

    Read the article

  • JQuery AJAX returned too much data that I had not requested

    - by kwokwai
    Hi all, I am using CakePHP 1.26 and CDN JQuery in this URL: http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js In a HTML web page, I have these lines of code: $.ajax({ type: "POST", url: "http://mywebsite.com/controllers/avail/"+curl, success: function(data) { alert(data);} }); and in the PHP page, I got another few lines of code: function avail($uname){ $result1=$this->Site1->User->findByusername($uname); if($result1){ return 1; } else{ return 0; } } As you see, the Avail function will return either zero or one. But there was some redundant data returned from the server, what I saw in the Alert box was somthing like this (rather than 0 or 1): <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Missing Method in Controller</title> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> <style type="text/css"> /* CSS Document */ /*PAGE LAYOUT*/ 0

    Read the article

  • how to create aro using dbAcl using console

    - by Praveen kalal
    hi i am using cakephp for my project but whille creating acl using command promt. when i run the following command cake schema run create DbAcl it genrate three tables in database. but after puting the following code in users_controller.php. and this command. cake acl view aro it dont create aros. function index() { $aro =& $this->Acl->Aro; //pr($aro); exit; //Here's all of our group info in an array we can iterate through $groups = array( 0 => array( 'alias' => 'admins' ), 1 => array( 'alias' => 'guests' ), 2 => array( 'alias' => 'mangers' ) ); //Iterate and create ARO groups foreach($groups as $data) { //Remember to call create() when saving in loops... $aro->create(); //Save data $aro->save($data); } }

    Read the article

  • Matching innermost braces with regex or strpos?

    - by rich97
    I have a sort of mini parsing syntax I made up to help me streamline my view code in cakephp. Basically I have created a table helper which, when given a dataset and (optionally) a set of options for how to format the data will render out a table, as opposed to me looping though the data and editing it manually. It allows the user to be as complex or as simple as they like, it can get pretty powerful. However, In order to achieve this I had to make a simple parsing syntax. As a quick example the user would do something like so: $this->Table->data = $userData; $this->Table->elements['td']['data'] = array( '{:User.username:}', '{:User.created:}' => array('Time::nice') ); echo $this->Table->render(); And when rendering the table would then generate: <table> <tbody> <tr><td>rich97</td><td>Sun 21st 02:30pm</td></tr> </tbody> </table> The problem occurs then I try to nest the braces like so: {:User.levels.iconClasses.{:User.access:}:} Is there anyway I can only get the inner most brackets on the first time round and loop though until there are no matches? Or even do it in one go? Or even better use strpos? Here is my regex as it stands: '/\{\:([^}]+)\:\}/'

    Read the article

  • Sending mail through PHP

    - by Angeline Aarthi
    I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

    Read the article

  • Cakephp ajax Autocomplete not working

    - by Vijay Kumbhar
    Hello All, I am using ajax autocomplete in my application, but it is not giving the output. Ajax request to the desired function goes but it is not giving back any response, it is blank. I am also using jquery but it is used for other effects. i added jquery no conflict to avoid the prototype & jquery conflicts. I have tried other ajax helper methods like obeserverfield, it is working fine & returning the proper response, but when i use autocomplete it fails Can anybody help me ..........

    Read the article

  • MySql stored procedure not found in PHP

    - by kaupov
    Hello, I have a trouble with MySql stored procedure that calls itself recursively using PHP (CakePHP). Calling it I receive following error: SQL Error: 1305: FUNCTION dbname.GetAdvertCounts does not exist The procedure itself is following: delimiter // DROP PROCEDURE IF EXISTS GetAdvertCounts// CREATE PROCEDURE GetAdvertCounts(IN category_id INT) BEGIN DECLARE no_more_sub_categories, advert_count INT DEFAULT 0; DECLARE sub_cat_id INT; DECLARE curr_sub_category CURSOR FOR SELECT id FROM categories WHERE parent_id = category_id; DECLARE CONTINUE HANDLER FOR NOT FOUND SET no_more_sub_categories = 1; SELECT COUNT(*) INTO advert_count FROM adverts WHERE category_id = category_id; OPEN curr_sub_category; FETCH curr_sub_category INTO sub_cat_id; REPEAT SELECT advert_count + GetAdvertCounts(sub_cat_id) INTO advert_count; FETCH curr_sub_category INTO sub_cat_id; UNTIL no_more_sub_categories = 1 END REPEAT; CLOSE curr_sub_category; SELECT advert_count; END // delimiter ; If I remove or comment out the recursive call, the procedure is working. Any idea what I'm missing here? The categories are 2 level deep.

    Read the article

  • HABTM selection seemingly ignores joinTable

    - by TheCapn
    I'm attempting to do a HABTM relationship between a Users table and Groups table. The problem is, that I when I issue this call: $this->User->Group->find('list'); The query that is issued is: SELECT [Group].[id] AS [Group__id], [Group].[name] AS [Group__name] FROM [groups] AS [Group] WHERE 1 = 1 I can only assume at this point that I have defined my relationship wrong as I would expect behavior to use the groups_users table that is defined on the database as per convention. My relationships: class User extends AppModel { var $name = 'User'; //...snip... var $hasAndBelongsToMany = array( 'Group' => array( 'className' => 'Group', 'foreignKey' => 'user_id', 'associationForeignKey' => 'group_id', 'joinTable' => 'groups_users', 'unique' => true, ) ); //...snip... } class Group extends AppModel { var $name = 'Group'; var $hasAndBelongsToMany = array ( 'User' => array( 'className' => 'User', 'foreignKey' => 'group_id', 'associationForeignKey' => 'user_id', 'joinTable' => 'groups_users', 'unique' => true, )); } Is my understanding of HABTM wrong? How would I implement this Many to Many relationship where I can use CakePHP to query the groups_users table such that a list of groups the currently authenticated user is associated with is returned?

    Read the article

  • Array values changing unexpectedly

    - by Lizard
    I am using cakephp 1.2 and I have an array that appears to have a value change even though that variable is not being manipulated. Below is the code to that is causing me trouble. PLEASE NOTE - UPDATE Changing the variable name makes no difference to the outcome, The values get changed somewhere between the two print_r calls, and I can't see why the $this-find would do this . echo "Start of findCountByString()"; print_r($myArr); $test = $this->find('count', array( 'conditions' => $conditions, 'joins' => array('LEFT JOIN `articles_entities` AS ArticleEntity ON `ArticleEntity`.`article_id` = `Article`.`id`'), 'group' => 'Article.id' )); echo "End of findCountByString()"; print_r($myArr); I am getting the following output: Start of findCountByString() Array ( [0] => 4bdb1d96-c680-4c2c-aae7-104c39d70629 [1] => 4bdb1d6a-9e38-479d-9ad4-105c39d70629 [2] => 4bdb1b55-35f0-4d22-ab38-104e39d70629 [3] => 4bdb25f4-34d4-46ea-bcb6-104f39d70629 ) End of findCountByString() Array ( [0] => 4bdb1d96-c680-4c2c-aae7-104c39d70629 [1] => 4bdb1d6a-9e38-479d-9ad4-105c39d70629 [2] => 4bdb1b55-35f0-4d22-ab38-104e39d70629 [3] => '4bdb25f4-34d4-46ea-bcb6-104f39d70629' # This is now in inverted commas ) The the value in my array have changed, and I don't know why? Any suggestions?

    Read the article

  • Cleaner HTML Markup with ASP.NET 4 Web Forms - Client IDs (VS 2010 and .NET 4.0 Series)

    - by ScottGu
    This is the sixteenth in a series of blog posts I’m doing on the upcoming VS 2010 and .NET 4 release. Today’s post is the first of a few blog posts I’ll be doing that talk about some of the important changes we’ve made to make Web Forms in ASP.NET 4 generate clean, standards-compliant, CSS-friendly markup.  Today I’ll cover the work we are doing to provide better control over the “ID” attributes rendered by server controls to the client. [In addition to blogging, I am also now using Twitter for quick updates and to share links. Follow me at: twitter.com/scottgu] Clean, Standards-Based, CSS-Friendly Markup One of the common complaints developers have often had with ASP.NET Web Forms is that when using server controls they don’t have the ability to easily generate clean, CSS-friendly output and markup.  Some of the specific complaints with previous ASP.NET releases include: Auto-generated ID attributes within HTML make it hard to write JavaScript and style with CSS Use of tables instead of semantic markup for certain controls (in particular the asp:menu control) make styling ugly Some controls render inline style properties even if no style property on the control has been set ViewState can often be bigger than ideal ASP.NET 4 provides better support for building standards-compliant pages out of the box.  The built-in <asp:> server controls with ASP.NET 4 now generate cleaner markup and support CSS styling – and help address all of the above issues.  Markup Compatibility When Upgrading Existing ASP.NET Web Forms Applications A common question people often ask when hearing about the cleaner markup coming with ASP.NET 4 is “Great - but what about my existing applications?  Will these changes/improvements break things when I upgrade?” To help ensure that we don’t break assumptions around markup and styling with existing ASP.NET Web Forms applications, we’ve enabled a configuration flag – controlRenderingCompatbilityVersion – within web.config that let’s you decide if you want to use the new cleaner markup approach that is the default with new ASP.NET 4 applications, or for compatibility reasons render the same markup that previous versions of ASP.NET used:   When the controlRenderingCompatbilityVersion flag is set to “3.5” your application and server controls will by default render output using the same markup generation used with VS 2008 and .NET 3.5.  When the controlRenderingCompatbilityVersion flag is set to “4.0” your application and server controls will strictly adhere to the XHTML 1.1 specification, have cleaner client IDs, render with semantic correctness in mind, and have extraneous inline styles removed. This flag defaults to 4.0 for all new ASP.NET Web Forms applications built using ASP.NET 4. Any previous application that is upgraded using VS 2010 will have the controlRenderingCompatbilityVersion flag automatically set to 3.5 by the upgrade wizard to ensure backwards compatibility.  You can then optionally change it (either at the application level, or scope it within the web.config file to be on a per page or directory level) if you move your pages to use CSS and take advantage of the new markup rendering. Today’s Cleaner Markup Topic: Client IDs The ability to have clean, predictable, ID attributes on rendered HTML elements is something developers have long asked for with Web Forms (ID values like “ctl00_ContentPlaceholder1_ListView1_ctrl0_Label1” are not very popular).  Having control over the ID values rendered helps make it much easier to write client-side JavaScript against the output, makes it easier to style elements using CSS, and on large pages can help reduce the overall size of the markup generated. New ClientIDMode Property on Controls ASP.NET 4 supports a new ClientIDMode property on the Control base class.  The ClientIDMode property indicates how controls should generate client ID values when they render.  The ClientIDMode property supports four possible values: AutoID—Renders the output as in .NET 3.5 (auto-generated IDs which will still render prefixes like ctrl00 for compatibility) Predictable (Default)— Trims any “ctl00” ID string and if a list/container control concatenates child ids (example: id=”ParentControl_ChildControl”) Static—Hands over full ID naming control to the developer – whatever they set as the ID of the control is what is rendered (example: id=”JustMyId”) Inherit—Tells the control to defer to the naming behavior mode of the parent container control The ClientIDMode property can be set directly on individual controls (or within container controls – in which case the controls within them will by default inherit the setting): Or it can be specified at a page or usercontrol level (using the <%@ Page %> or <%@ Control %> directives) – in which case controls within the pages/usercontrols inherit the setting (and can optionally override it): Or it can be set within the web.config file of an application – in which case pages within the application inherit the setting (and can optionally override it): This gives you the flexibility to customize/override the naming behavior however you want. Example: Using the ClientIDMode property to control the IDs of Non-List Controls Let’s take a look at how we can use the new ClientIDMode property to control the rendering of “ID” elements within a page.  To help illustrate this we can create a simple page called “SingleControlExample.aspx” that is based on a master-page called “Site.Master”, and which has a single <asp:label> control with an ID of “Message” that is contained with an <asp:content> container control called “MainContent”: Within our code-behind we’ll then add some simple code like below to dynamically populate the Label’s Text property at runtime:   If we were running this application using ASP.NET 3.5 (or had our ASP.NET 4 application configured to run using 3.5 rendering or ClientIDMode=AutoID), then the generated markup sent down to the client would look like below: This ID is unique (which is good) – but rather ugly because of the “ct100” prefix (which is bad). Markup Rendering when using ASP.NET 4 and the ClientIDMode is set to “Predictable” With ASP.NET 4, server controls by default now render their ID’s using ClientIDMode=”Predictable”.  This helps ensure that ID values are still unique and don’t conflict on a page, but at the same time it makes the IDs less verbose and more predictable.  This means that the generated markup of our <asp:label> control above will by default now look like below with ASP.NET 4: Notice that the “ct100” prefix is gone. Because the “Message” control is embedded within a “MainContent” container control, by default it’s ID will be prefixed “MainContent_Message” to avoid potential collisions with other controls elsewhere within the page. Markup Rendering when using ASP.NET 4 and the ClientIDMode is set to “Static” Sometimes you don’t want your ID values to be nested hierarchically, though, and instead just want the ID rendered to be whatever value you set it as.  To enable this you can now use ClientIDMode=static, in which case the ID rendered will be exactly the same as what you set it on the server-side on your control.  This will cause the below markup to be rendered with ASP.NET 4: This option now gives you the ability to completely control the client ID values sent down by controls. Example: Using the ClientIDMode property to control the IDs of Data-Bound List Controls Data-bound list/grid controls have historically been the hardest to use/style when it comes to working with Web Form’s automatically generated IDs.  Let’s now take a look at a scenario where we’ll customize the ID’s rendered using a ListView control with ASP.NET 4. The code snippet below is an example of a ListView control that displays the contents of a data-bound collection — in this case, airports: We can then write code like below within our code-behind to dynamically databind a list of airports to the ListView above: At runtime this will then by default generate a <ul> list of airports like below.  Note that because the <ul> and <li> elements in the ListView’s template are not server controls, no IDs are rendered in our markup: Adding Client ID’s to Each Row Item Now, let’s say that we wanted to add client-ID’s to the output so that we can programmatically access each <li> via JavaScript.  We want these ID’s to be unique, predictable, and identifiable. A first approach would be to mark each <li> element within the template as being a server control (by giving it a runat=server attribute) and by giving each one an id of “airport”: By default ASP.NET 4 will now render clean IDs like below (no ctl001-like ids are rendered):   Using the ClientIDRowSuffix Property Our template above now generates unique ID’s for each <li> element – but if we are going to access them programmatically on the client using JavaScript we might want to instead have the ID’s contain the airport code within them to make them easier to reference.  The good news is that we can easily do this by taking advantage of the new ClientIDRowSuffix property on databound controls in ASP.NET 4 to better control the ID’s of our individual row elements. To do this, we’ll set the ClientIDRowSuffix property to “Code” on our ListView control.  This tells the ListView to use the databound “Code” property from our Airport class when generating the ID: And now instead of having row suffixes like “1”, “2”, and “3”, we’ll instead have the Airport.Code value embedded within the IDs (e.g: _CLE, _CAK, _PDX, etc): You can use this ClientIDRowSuffix approach with other databound controls like the GridView as well. It is useful anytime you want to program row elements on the client – and use clean/identified IDs to easily reference them from JavaScript code. Summary ASP.NET 4 enables you to generate much cleaner HTML markup from server controls and from within your Web Forms applications.  In today’s post I covered how you can now easily control the client ID values that are rendered by server controls.  In upcoming posts I’ll cover some of the other markup improvements that are also coming with the ASP.NET 4 release. Hope this helps, Scott

    Read the article

  • VBA WinHTTPRequest and submitting forms

    - by Hazerider
    Hi. I spent all day yesterday trying to figure out how to submit a form using WinHTTPRequest. I can do it pretty easily with an InternetExplorer object, but the problem is that I need to save a PDF file that gets returned, and I am not sure how to do this with the IE object. Here is the relevant HTML code snippet: <div class="loginHome-left"> <fieldset> <h3>Log in Using</h3> <form> <label for="standardLogin" accesskey="s"> <input name="useLogin" id="standardLogin" value="standard" type="radio" checked="true">Standard Login</label> &nbsp; <label for="rsaSecurID" accesskey="r"> <input name="useLogin" value="rsaSecur" type="radio" id="rsaSecurID" onclick="redirectLogin('ct_logon_securid');return false;">RSA SecurID</label> &nbsp; <label for="employeeNTXP" accesskey="e"> <input name="useLogin" id="employeeNTXP" value="employee" type="radio" onclick="redirectLogin('ct_logon_external_nt');return false; "> Employee Windows Login<br></label> </form> <br> <div class="error">Error: ...</div><br> <form onSubmit="if(validate(this)) {formSubmit();} return false;" name="passwdForm" method="post" action="/UAB/ct_logon"> <input value="custom" name="pageId" type="hidden"> <input value="custom" name="auth_mode" type="hidden"> <input value="/UAB/ct_logon" name="ct_orig_uri" type="hidden"> <INPUT VALUE="" NAME="orig_url" TYPE="hidden"> <input value="" name="lpSp" type="hidden"> <label for="user"> <strong>Username</strong> </label> <input autocomplete="off" name="user" type="text" value="" class="txtFld" onkeypress="return handleEnter(this, event);"> <br> <label for="EnterPassword"> <strong>Password</strong>&nbsp;&nbsp;(<a tabindex="-1" href="/UAB/BCResetWithSecrets">Forgot Your Password?</a>) </label> <input autocomplete="off" name="password" type="password" class="txtFld" onkeypress="return handleEnter(this, event);"> <INPUT id="rememberLogin" name="lpCookie" type="checkbox"> <label for="rememberLogin">Remember My Login Information</label><br> </form> <div class="right"> <br> <input type="image" src="/BC_S/images/bclogin/btn_login.gif" name="" value="Submit" onClick="if(validate(document.forms['passwdForm'])){formSubmit();}return false;"> </div> <div class="clearfix"></div> </fieldset> </div> In order to log in through InternetExplorer, I do the following: Sub TestLogin() Dim ie As InternetExplorer, doc As HTMLDocument, form As HTMLFormElement, inp As Variant Set ie = New InternetExplorer ie.Visible = True ie.navigate "https://URL of the login page" Do Until ie.readyState = READYSTATE_COMPLETE Loop Set doc = ie.document For Each form In doc.forms If InStr(form.innerText, "Password") <> 0 Then form.elements("user").Value = "my_name" form.elements("password").Value = "my_password" Exit For Else End If Next 'This is the unnamed input with an image that is used to submit the form' doc.all(78).Click ie.navigate "https://url of the PDF" Do Until ie.readyState = READYSTATE_COMPLETE Loop Dim filename As String, filenum As Integer filename = "somefile.pdf" filenum = FreeFile Open filename For Binary Access Write As #filenum Write #filenum, doc.DocumentElement.innerText Close #filenum ie.Quit Debug.Print Set ie = Nothing End Sub What I really would like to do is something along the lines of the following: Sub TestLogin3() Dim whr As New WinHttpRequest, postData As String whr.Open "POST", "https://live.barcap.com/UAB/ct_logon", False whr.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)" whr.setRequestHeader "Connection", "Keep-Alive" whr.Send whr.WaitForResponse postData = "user=paschom1&password=change01" 'Or the following?' postData = "user=paschom1&password=change01&orig_url=&pageId=custom&auth_mode=custom&ct_orig_uri=/BC/dispatcher&lpSp=&lpCookie=off" whr.Send postData whr.WaitForResponse Debug.Print whr.responseText End Sub It just refuses to work though. Not sure if I need to use more setRequestHeader with Content-Form or something similar, and if I do, not sure what exactly I am supposed to pass it. If anyone has any advice regarding this, it would be hugely appreciated. I could probably use a perl module to do it, but I would rather keep it all in VBA if possible. Thanks, Marc.

    Read the article

< Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >