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  • DIR $file "File Not Found" vs DIR $filedir shows it....not permissions, not USB

    - by Kev
    I was having this problem before on a USB drive, but now it's happening on my main RAID5-backed hard disk: 2013-10-17 9:37 C:\>dir "C:\Shares\Shared\Reference\Safety Management System\Vid eo CD\AutoPlay\Docs\Manuel*" Volume in drive C has no label. Volume Serial Number is 3C18-E114 Directory of C:\Shares\Shared\Reference\Safety Management System\Video CD\AutoP lay\Docs 2003-09-09 11:29 PM 1,056,768 Manuel d'intervention d'urgence MFC.doc 2004-06-20 10:36 PM 139,849 Manuel d'intervention d'urgence MFC.pdf 2 File(s) 1,196,617 bytes 0 Dir(s) 196,068,691,968 bytes free 2013-10-17 9:38 C:\>dir "C:\Shares\Shared\Reference\Safety Management System\Vid eo CD\AutoPlay\Docs\Manuel d'intervention d'urgence MFC.doc" Volume in drive C has no label. Volume Serial Number is 3C18-E114 Directory of C:\Shares\Shared\Reference\Safety Management System\Video CD\AutoP lay\Docs File Not Found 2013-10-17 9:38 C:\> This is from a Command Prompt window where I went to Properties and told it I wanted to modify who it ran as. I opened it, had it run as me with the "restricted access" unchecked, then ran the above. The file in question has the following ACLs: Administrators, SYSTEM, and OurCompanyUsers. All three have full control of everything. Nobody has any Deny bits set. I am a member of Administrators. So I don't believe it's a permissions issue. It's not a USB drive, so this time there is no question of USB hardware. Windows Server 2003 Standard Edition SP2. What does this mean? Is this more likely a hardware or software problem?

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  • Is there such a thing as a file hosted container which deduplicates data held within?

    - by Mallow
    Background I have backups of a website which stores all of it's data into a single file. This file is several gigs large and I have many different backups of this file. Most of the data within is mostly the same plus whatever was added or changed to it. I want to keep all the concurrent backups I've made through the years in case I find a horrible surprise of data corruption along the line. However storing a 10gig file every month gets expensive. Seeking Solution I've often thought about different ways of alleviating this problem. One thought that comes up very often combines the idea of a duplicating file system which doesn't require it's own partitioned volume on a hard drive. Something like what truecrypt does, what it calls, "file hosted containers" which when using the truecrypt program allows you to mount and dismount that volume as a regular hard drive. Question Is there a virtual hard drive mounter which uses file-based container which uses data deduplicaiton file system? (This question is a little awkward to put into words, if you have a better idea on how to ask this question please feel free to help out.)

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • Java compiler error: "cannot find symbol" when trying to access local variable

    - by HH
    $ javac GetAllDirs.java GetAllDirs.java:16: cannot find symbol symbol : variable checkFile location: class GetAllDirs System.out.println(checkFile.getName()); ^ 1 error $ cat GetAllDirs.java import java.util.*; import java.io.*; public class GetAllDirs { public void getAllDirs(File file) { if(file.isDirectory()){ System.out.println(file.getName()); File checkFile = new File(file.getCanonicalPath()); }else if(file.isFile()){ System.out.println(file.getName()); File checkFile = new File(file.getParent()); }else{ // checkFile should get Initialized at least HERE! File checkFile = file; } System.out.println(file.getName()); // WHY ERROR HERE: checkfile not found System.out.println(checkFile.getName()); } public static void main(String[] args) { GetAllDirs dirs = new GetAllDirs(); File current = new File("."); dirs.getAllDirs(current); } }

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  • Visual Studio 2008 project file does not load because of an unexpected encoding change.

    - by Xenan
    In our team we have a database project in visual Studio 2008 which is under source control by Team Foundation Server. Every two weeks or so, after one co-worker checks in, the project file won't load on the other developers machines. The error message is: The project file could not be loaded. Data at the root level is invalid. Line 1, position 1. When I look at the project file in Notepad++, the file looks like this: ??<NUL?NULxNULmNULlNUL NULvNULeNULrNULsNULiNULoNULnNUL ... and so on (you can see <?xml version in this) whereas an normal project file looks like: <?xml version="1.0" encoding="utf-16"?> ... So probably something is wrong with the encoding of the file. This is a problem for us because it turns out to be impossible to get the file encoding correct again. The 'solution' is to throw away the project file an get the last know working version from source control. According to the file, the encoding should be UTF-16. According to Notepad++, the corrupted file is actually UTF-8. My questions are: Why is Visual Studio messing up the encoding of the project file, apparently at random times and at random machines? What should we do to prevent this? When it has happened, is there a possibility to restore the current file in the correct encoding instead of pulling an older version from source control? As a last note: the problem is with one single project file, all other project files don't expose this problem.

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  • File.Move does not inherit permissions from target directory?

    - by Joseph Kingry
    In case something goes wrong in creating a file, I've been writing to a temporary file and then moving to the destination. Something like: var destination = @"C:\foo\bar.txt"; var tempFile = Path.GetTempFileName(); using (var stream = File.OpenWrite(tempFile)) { // write to file here here } string backupFile = null; try { var dir = Path.GetDirectoryName(destination); if (!Directory.Exists(dir)) { Directory.CreateDirectory(dir); Util.SetPermissions(dir); } if (File.Exists(destination)) { backupFile = Path.Combine(Path.GetTempPath(), new Guid().ToString()); File.Move(destination, backupFile); } File.Move(tempFile, destination); if (backupFile != null) { File.Delete(backupFile); } } catch(IOException) { if(backupFile != null && !File.Exists(destination) && File.Exists(backupFile)) { File.Move(backupFile, destination); } } The problem is that the new "bar.txt" in this case does not inherit permissions from the "C:\foo" directory. Yet if I create a file via explorer/notepad etc directly in the "C:\foo" there's no issues, so I believe the permissions are correctly set on "C:\foo". Update Found Inherited permissions are not automatically updated when you move folders, maybe it applies to folders as well. Now looking for a way to force an update of file permissions. Is there a better way overall of doing this?

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  • Can't access my files in ASP.NET web site

    - by jumbojs
    I'm having a very difficult time. I am running windows 2008 server, I have an Able Commerce site using ASP.NET with C#. I'm writing an automated task that will ftp some xml files down into a local directory on our web server and then the program parses the xml file and saves information to our database. The problem, once I save the files to our local directory, my program has no access to the files. The NETWORK SERVICE user permissions isn't being inherited by the xml files so my program can't do anything with them. I can manually change the permissions, but this wouldn't be automated and won't work. How can I get this to work? help please, it's very frustrating.

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  • XML File as Excel file.

    - by FrustratedWithFormsDesigner
    I have a number of reports that I run against my database that need to eventually go to the end-users as Excel spreadsheets. Initially, I was creating text reports, but the steps to convert the text to a spreadsheet were a bit cumbersome. There were too many steps to import text to the spreadsheet, and multi-line text rows were imported as individual rows in Excel (which was incorrect). Currently, I am generating simple XML saving the file with an ".xls" extension. This works better, but there is still the problem of Excel prompting the user with an XML import dialogue every time they open the file, and then having to save a new file if they add notes or change the layout to the file (which they almost certainly will be doing). Sample "xls" file: <?xml version="1.0" standalone="yes"?> <report_rows> <row> <NAME>Test Data</NAME> <COUNT>345</COUNT> </row> <!-- many more row elements... --> </report_rows> Is there any way to add markup to the file to hint to Excel how it should import and handle the file? Ideally, the end user should be able to open and save the file like any othe spreadsheet they create directly from Excel. Is this even possible? UPDATE: We are running Office 2003 here. UPDATE: The XML is generated from a sqlplus script, no option to use C#/.NET here.

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  • General question: Filesystem or database?

    - by poeschlorn
    Hey guys, i want to create a small document management system. there are several users who store their files. each file which is uploaded contains an info which user uploaded it and the document content itself. In a view there are displayed all files of ONE specific user, ordered by date. What would be better: 1) giving the documents a name or metadata(XML) which contain the date and user (and iterate through them to get the metadata) or 2) giving the files a random/unique name and store metadata in a DB? something like this: date | user | filename What would you say and why? The used programming language is java and the DB is MySQL.

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  • Is it possible to compute the minimum of three numbers by using two comparisons at the same time?

    - by Milo Hou
    I've been trying to think up of some way that I could do two comparisons at the same time to find the greatest/least of three numbers. Arithmetic operations on them are considered "free" in this case. That is to say, the classical way of finding the greater of two, and then comparing it to the third number isn't valid in this case because one comparison depends on the result of the other. Is it possible to use two comparisons where this isn't the case? I was thinking maybe comparing the differences of the numbers somehow or their products or something, but came up with nothing. Just to reemphasize, two comparisons are still done, just that neither comparison relies on the result of the other comparison. EDIT: what about: boolA = A^2 + B^2 < C^2 boolB = A > B if boolA then max=C else if boolB then max=A else max=B

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  • What would happen if a same file being read and appended at the same time(python programming)?

    - by Shane
    I'm writing a script using two separate thread one doing file reading operation and the other doing appending, both threads run fairly frequently. My question is, if one thread happens to read the file while the other is just in the middle of appending strings such as "This is a test" into this file, what would happen? I know if you are appending a smaller-than-buffer string, no matter how frequently you read the file in other threads, there would never be incomplete line such as "This i" appearing in your read file, I mean the os would either do: append "This is a test" - read info from the file; or: read info from the file - append "This is a test" to the file; and such would never happen: append "This i" - read info from the file - append "s a test". But if "This is a test" is big enough(assuming it's a bigger-than-buffer string), the os can't do appending job in one operation, so the appending job would be divided into two: first append "This i" to the file, then append "s a test", so in this kind of situation if I happen to read the file in the middle of the whole appending operation, would I get such result: append "This i" - read info from the file - append "s a test", which means I might read a file that includes an incomplete string?

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  • Utility to LOGICALLY compare two xml files?

    - by Matthew
    Right now we are attempting to build golden configurations for our environment. One piece of software that we use relies on large XML files to contain the bulk of its configuration. We want tot ake our lab environment, catalog it as our "golden configuration" and then be able to audit against that configuration in the future. Since diff is bytewise comparison and NOT logical comparison, we can't use it to compare files in this case (XML is unordered, so it won't work). What I am looking for is something that can parse the two XML files, and compare them element by element. So far we have yet to find any utilities that can do this. OS doesn't matter, I can do it on anything where it will work. The preference is something off the shelf. Any ideas? Edit: One issue we have run into is one vendor's config files will occasionally mention the same element several times, each time with different attributes. Whatever diff utility we use would need to be able to identify either the set of attributes or identify them all as part of one element. Tall order :)

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  • Efficient way to check for changes to the contents of folders

    - by MrVimes
    I am creating an application that maintains a database of files of a certain type in a given folder (and all subfolders) Initially the program will recurse the folders and add any file it finds of that type to the database. I want the application to have the ability to re-scan the folder and add any files that were not there the last time the folders were scanned. It can't use the date created property of the file because there is a high chance of a file being added to the folders that isn't a new file. I am wondering what the most efficient way of doing this is, and if there is a way that doesn't involve checking each file is in the database already (which, if there are 5000 files would mean 5000 queries of a list 5000 items in size, or 25 million 'checks' for the sql engine to perform) I suppose a more specific question to acheive the same goal would be - is there a property of a file (in Microsoft Windows) that will reliably tell you when that file arrived in that folder.

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  • Best way to rename existing unique field names in database?

    - by Rajdeep Siddhapura
    I have a database table that contains id, filename, userId id is unique identifier filename should also be unique table may contain 10000 records When a user uploads a file it should be entered in database with given rules: If there is no record with same filename, it should be added as it is (Ex. foobar.pdf) If there is record with same filename, it should be added as uploadedName(2).ext (foobar(2).pdf) If there are n records with same base filename (foobar), it should be added as uploadedName(n+1).ext (foobar(20).pdf) Now if foobar(2).pdf is uploaded, it should be added as foobar(2)(2).pdf & so on This pattern needs to be followed because the file is already being uploaded at client side using ajax before sending the details to server and the file hosting service follows the above rules to name the files. My solution: maintain a file that contains all the names and the number of times it has occurred. if a filename that exists in file is entered, increase occurrence count and new name is generated, else add to it to file if the new name generated is in database, add it to file and generate new name

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  • SFTP jail & Keeping file ownership the same / File owner per folder

    - by Dragonshadow
    I want to setup a jailed SFTP account for a subfolder of another user's home folder, but want the owner of everything in that subfolder to stay the same, including new files and folders uploaded and created by the sftp user, while still allowing access to the files and folders of that subfolder as if the SFTP user was the parent user. rawny bawb-sftp /home/rawny <- rawny owns this /home/rawny/sftp <- rawny owns this too, but bawb-sftp can upload to it, edit files, etc bawb-sftp uploads a file /home/rawny/sftp/lol.txt rawny should still own the file, as if he made it in the first place, even though bawb-sftp was the one that uploaded it. Basically I guess I'm asking for an sftp jail that acts as a highly limited passthrough/puppet for another user?

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  • I started getting a weird message "Encrypting file system - Back up your file encryption key"

    - by user22559
    Hello I started getting a strange message when I start my computer. An icon appears in the system tray, and a popup tells me "Encrypting file system - Back up your file encryption key". I know what EFS is, but I don't use it. To my knowledge, I don't have any encrypted files on my partition. I have searched using Total Commander on all the partitions for files that have the "encrypted" attribute, but I found nothing. So I don't have any encrypted files. Does anyone know what I did to get this message?

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  • merge values from excel file into .html file opened in word 2007

    - by Kelbizzle
    I have this newsletter I've written. I want to be able to use the values in the rows and some how have them merged into this html file I have opened in word. Sort of like a mail merge. In the newsletter I have 3 urls that look like: www.mydomain.com/php?id= I want to be able to replace all of the urls for all 230 records in the excel file. With something like: www.mydomain.com/?id=$id Where $id would get replaced with the id of the record. And the same goes for the rest of the rows like $firstname $lastname $email $phone number Is there a simple way to do this?

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  • Ubuntu 12.04 Samba File Server timeout on large file

    - by phileaton
    I am a beginner with servers. I checked the error logs for Samba and it appears that Samba is timing out when I transfer large files. I can successfully add pdfs for instance to my file server. However, I tried to add a large 1.2gb video file and it did not succeed. This is the error in the log: smbd/process.c:244(read_packet_remainder) read_fd_with_timeout failed for client 0.0.0.0 read error = NT_STATUS_CONNECT$ Is there a way I can stop it from timing out? Any pointers would be great! Thanks!

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  • I started getting a weird message "Encrypting file system - Back up your file encryption key"

    - by Ove
    I started getting a strange message when I start my computer. An icon appears in the system tray, and a popup tells me "Encrypting file system - Back up your file encryption key". I know what EFS is, but I don't use it. To my knowledge, I don't have any encrypted files on my partition. I have searched using Total Commander on all the partitions for files that have the "encrypted" attribute, but I found nothing. So I don't have any encrypted files. Does anyone know what I did to get this message?

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  • Is there a way to force/manage file locking in windows?

    - by JPbuntu
    I have a 2 Windows machines networked and I am having trouble with simultaneous access to files. I would like only one user to be able to open a file at a time, which I thought was automatic, using file locks.... if the program used to access the file is locking the file. I believe the problem I am having is some of the programs I use, don't lock the file, and there for can be modified simultaneously by multiple users, which is very much not desired. Currently I am having this problem with only two computers, although as soon as I can figure out a solution to this problem the network is going to be expanded to 6 computers, which will include Windows 7, Vista, and XP, as well as a central file server (Samba). Is there a way to ensure that all files opened in windows get locked? Any suggestions are appreciated, thanks.

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  • replaceAll() method using parameter from text file

    - by Herman Plani Ginting
    i have a collection of raw text in a table in database, i need to replace some words in this collection using a set of words. i put all the term to be replace and its substitutes in a text file as below min=admin lelet=lambat lemot=lambat nii=nih ntu=itu and so on. i have successfully initiate a variabel of File and Scanner to read the collection of the term and its substitutes. i loop all the dataset and save the raw text in a string in the same loop i loop all the term collection and save its row to a string name 'pattern', and split the pattern into two string named 'term' and 'replacer' in this loop i initiate a new string which its value is the string from the dataset modified by replaceAll(term,replacer) end loop for term collection then i insert the new string to another table in database end loop for dataset i do it manualy as below replaceAll("min","admin") and its works but its really something to code it manually for almost 2000 terms to be replace it. anyone ever face this kind of really something.. i really need a help now desperate :( package sentimenrepo; import javax.swing.*; import java.sql.*; import java.io.*; //import java.util.HashMap; import java.util.Scanner; //import java.util.Map; /** * * @author herman */ public class synonimReplaceV2 extends SwingWorker { protected Object doInBackground() throws Exception { new skripsisentimen.sentimenttwitter().setVisible(true); Integer row = 0; File synonimV2 = new File("synV2/catatan_kata_sinonim.txt"); String newTweet = ""; DB db = new DB(); Connection conn = db.dbConnect("jdbc:mysql://localhost:3306/tweet", "root", ""); try{ Statement select = conn.createStatement(); select.executeQuery("select * from synonimtweet"); ResultSet RS = select.getResultSet(); Scanner scSynV2 = new Scanner(synonimV2); while(RS.next()){ row++; String no = RS.getString("no"); String tweet = " "+ RS.getString("tweet"); String published = RS.getString("published"); String label = RS.getString("label"); clean2 cleanv2 = new clean2(); newTweet = cleanv2.cleanTweet(tweet); try{ Statement insert = conn.createStatement(); insert.executeUpdate("INSERT INTO synonimtweet_v2(no,tweet,published,label) values('" +no+"','"+newTweet+"','"+published+"','"+label+"')"); String current = skripsisentimen.sentimenttwitter.txtAreaResult.getText(); skripsisentimen.sentimenttwitter.txtAreaResult.setText(current+"\n"+row+"original : "+tweet+"\n"+newTweet+"\n______________________\n"); skripsisentimen.sentimenttwitter.lblStat.setText(row+" tweet read"); skripsisentimen.sentimenttwitter.txtAreaResult.setCaretPosition(skripsisentimen.sentimenttwitter.txtAreaResult.getText().length() - 1); }catch(Exception e){ skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } }catch(Exception e){ skripsisentimen.sentimenttwitter.lblStat.setText(e.getMessage()); } return row; } class clean2{ public clean2(){} public String cleanTweet(String tweet){ File synonimV2 = new File("synV2/catatan_kata_sinonim.txt"); String pattern = ""; String term = ""; String replacer = ""; String newTweet=""; try{ Scanner scSynV2 = new Scanner(synonimV2); while(scSynV2.hasNext()){ pattern = scSynV2.next(); term = pattern.split("=")[0]; replacer = pattern.split("=")[1]; newTweet = tweet.replace(term, replacer); } }catch(Exception e){ e.printStackTrace(); } System.out.println(newTweet+"\n"+tweet); return newTweet; } } }

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  • How to handle editing a large file for a non-technical user

    - by Luke
    I have a client who is given a tab delimited .txt file containing hundreds of thousands of rows. I have a user story as follows: As a user I want to take the text file and add a new value at the end of each line which contains the concatenated value of two of the columns. for example if the file read text_one text_two I need to output the following (preferably to a .txt file) text_one text_two text_onetext_two My first approach was to ask the vendor supplying the file to do the concatenation before providing the file, the easiest way to solve a problem is to eliminate it right? however they are very uncooperative and have point blank refused. I've looked at building a simple javascript application that does this client side so a non-technical user could select the file using a file selector. This approach has a few problems The file could be over a GB in size and so can't be loaded straight into memory, I've tried and the browser crashes There is no means to write a file in javascript so I'd need to output the content to the screen and have the user save it (somehow) I was thinking if I could get around the filesize limitations I could just output the edited content to the page and have the user save the page as a .txt file, however I think there is a better way than using javascript that will still accommodate the users lack of technical know-how. Please consider this question to be stack agnostic, but bear in mind that a nice little shell script or python script would be deemed unsuitable for a non technical user unless there is a way of "packaging" it nicely for a non-technical user. Updates The file is too large to open in excel. The process needs to be run weekly, but it doesn't require scheduling or automation...(yet)

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  • File Adapter FileName Macros

    - by IntegrationOverload
    I can never find these when I need them...   Macro name Substitute value %datetime% Coordinated Universal Time (UTC) date time in the format YYYY-MM-DDThhmmss (for example, 1997-07-12T103508). %datetime_bts2000% UTC date time in the format YYYYMMDDhhmmsss, where sss means seconds and milliseconds (for example, 199707121035234 means 1997/07/12, 10:35:23 and 400 milliseconds). %datetime.tz% Local date time plus time zone from GMT in the format YYYY-MM-DDThhmmssTZD, (for example, 1997-07-12T103508+800). %DestinationParty% Name of the destination party. The value comes from the message context property BTS.DestinationParty. %DestinationPartyQualifier% Qualifier of the destination party. The value comes from the message context property BTS.DestinationPartyQualifier. %MessageID% Globally unique identifier (GUID) of the message in BizTalk Server. The value comes directly from the message context property BTS.MessageID. %SourceFileName% Name of the file from where the File adapter read the message. The file name includes the extension and excludes the file path, for example, Sample.xml. When substituting this property, the File adapter extracts the file name from the absolute file path stored in the FILE.ReceivedFileName context property. If the context property does not have a value, for example, if a message was received on an adapter other than the File adapter, the macro will not be substituted and will remain in the file name as is (for example, C:\Drop\%SourceFileName%). %SourceParty% Name of the source party from which the File adapter received the message. %SourcePartyQualifier% Qualifier of the source party from which the File adapter received the message. %time% UTC time in the format hhmmss. %time.tz% Local time plus time zone from GMT in the format hhmmssTZD (for example, 124525+530).

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  • Beginner - C# iteration through directory to produce a file list

    - by dassouki
    The end goal is to have some form of a data structure that stores a hierarchal structure of a directory to be stored in a txt file. I'm using the following code and so far, and I'm struggling with combining dirs, subdirs, and files. /// <summary> /// code based on http://msdn.microsoft.com/en-us/library/bb513869.aspx /// </summary> /// <param name="strFolder"></param> public static void TraverseTree ( string strFolder ) { // Data structure to hold names of subfolders to be // examined for files. Stack<string> dirs = new Stack<string>( 20 ); if ( !System.IO.Directory.Exists( strFolder ) ) { throw new ArgumentException(); } dirs.Push( strFolder ); while ( dirs.Count > 0 ) { string currentDir = dirs.Pop(); string[] subDirs; try { subDirs = System.IO.Directory.GetDirectories( currentDir ); } catch ( UnauthorizedAccessException e ) { MessageBox.Show( "Error: " + e.Message ); continue; } catch ( System.IO.DirectoryNotFoundException e ) { MessageBox.Show( "Error: " + e.Message ); continue; } string[] files = null; try { files = System.IO.Directory.GetFiles( currentDir ); } catch ( UnauthorizedAccessException e ) { MessageBox.Show( "Error: " + e.Message ); continue; } catch ( System.IO.DirectoryNotFoundException e ) { MessageBox.Show( "Error: " + e.Message ); continue; } // Perform the required action on each file here. // Modify this block to perform your required task. /* foreach ( string file in files ) { try { // Perform whatever action is required in your scenario. System.IO.FileInfo fi = new System.IO.FileInfo( file ); Console.WriteLine( "{0}: {1}, {2}", fi.Name, fi.Length, fi.CreationTime ); } catch ( System.IO.FileNotFoundException e ) { // If file was deleted by a separate application // or thread since the call to TraverseTree() // then just continue. MessageBox.Show( "Error: " + e.Message ); continue; } } */ // Push the subdirectories onto the stack for traversal. // This could also be done before handing the files. foreach ( string str in subDirs ) dirs.Push( str ); foreach ( string str in files ) MessageBox.Show( str ); }

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  • load Javascript object from file

    - by megapool020
    Hi there, I asked a question in this thread Stackoverflow, and it works perfect. So tnx to all the users who gave me a reply. But now I have a other question. I would like to have the object in a seperate file, so I only need to update the file in stead of the JS file (otherwise it will be very big). I'm using JQUERY. I now looks like this (with all the info in the JS file). IBANInfo is used to fill a selectbox var IBANInfo = { "ccAL":{ countryCode:"AL", countryName:"Albani&euml;", IBANlength:"28", bankFormCode:"0 8n 0 ", accountNum:"0 16 0 " }, "ccAD":{ countryCode:"AD", countryName:"Andorra", IBANlength:"24", bankFormCode:"0 4n 4n", accountNum:"0 12 0 " }, "ccBE":{ countryCode:"BE", countryName:"Belgi&euml;", IBANlength:"16", bankFormCode:"0 3n 0 ", accountNum:"0 7n 2n" } }; //---- then this function is used to build the selectList function createSelect(){ var selectList = ''; var key; selectList += "<option value=''>Kies een land</option>\n"; for (key in IBANInfo) { if (IBANInfo.hasOwnProperty(key)) { var countryInfo = IBANInfo[key]; selectList += "<option value='"+countryInfo.countryCode+"'>"+countryInfo.countryName+"</option>\n"; } } $('#selectBox').html(selectList); } I thought I could do it like this, but I get the message undefined in my selectbox. var IBANInfo = $.get('include/countryCodes.txt'); // also tried var IBANInfo = $.getJSON('include/countryCodes.txt'); //---- then this function is used to build the selectList function createSelect(){ var selectList = ''; var key; selectList += "<option value=''>Kies een land</option>\n"; for (key in IBANInfo) { if (IBANInfo.hasOwnProperty(key)) { var countryInfo = IBANInfo[key]; selectList += "<option value='"+countryInfo.countryCode+"'>"+countryInfo.countryName+"</option>\n"; } } $('#selectBox').html(selectList); } /* the countryCodes.txt file is like this: { "ccAL":{ countryCode:"AL", countryName:"Albani&euml;", IBANlength:"28", bankFormCode:"0 8n 0 ", accountNum:"0 16 0 " }, "ccAD":{ countryCode:"AD", countryName:"Andorra", IBANlength:"24", bankFormCode:"0 4n 4n", accountNum:"0 12 0 " }, "ccBE":{ countryCode:"BE", countryName:"Belgi&euml;", IBANlength:"16", bankFormCode:"0 3n 0 ", accountNum:"0 7n 2n" } } */ What am I doing wrong. Tnx in advance

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