Search Results

Search found 3120 results on 125 pages for 'php5 oop'.

Page 52/125 | < Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >

  • What should I put into classes and what stuff I shouldnt?

    - by jpjp
    I am learning about classes right now in PHP and their examples are like.. class table { //makes a table private $tag ; function Begin($border=0, $align="center", $width='100%', $cellpadding=2, $cellspacing=2, $class='', $id='', $bgcolor='', $style='') { $this->tag = '<table ' ; if ($align) $this->tag .= 'align="' . $align . '" ' ; if ($width) $this->tag .= 'width="' . $width . '" ' ; if ($border > 0) $this->tag .= 'border="' . $border . '" ' ; if ($cellpadding > 0) $this->tag .= 'cellpadding="' . $cellpadding . '" ' ; if ($cellspacing > 0) $this->tag .= 'cellspacing="' . $cellspacing . '" ' ; if ($class) $this->tag .= 'class="' . $class . '" ' ; if ($id) $this->tag .= 'id="' . $id . '" ' ; if ($bgcolor) $this->tag .= 'bgcolor="' . $bgcolor . '" ' ; if ($style) $this->tag .= 'style="' . $style . '" ' ; $this->tag .= ">" ; return $this->tag ; } Then you just instantiate it and make a table by $table =new table; $table->$table($border=2, $align='center', etc); Should I be coding like this where html, css are in classes? i feel making tables and forms this way is more confusing then actually just typing . Should I only put like validation, getting data from db, and the logic stuff in classes? What should I use classes for and not?

    Read the article

  • Extend base class properties

    - by user1888033
    I need your help to extend my base class, here is the similar structure i have. public class ShowRoomA { public audi AudiModelA { get; set; } public benz benzModelA { get; set; } } public class audi { public string Name { get; set; } public string AC { get; set; } public string PowerStearing { get; set; } } public class benz { public string Name { get; set; } public string AC { get; set; } public string AirBag { get; set; } public string MusicSystem { get; set; } } //My Implementation class like this class Main() { private void UpdateDetails() { ShowRoomA ojbMahi = new ShowRoomA(); GetDetails( ojbMahi ); // this works fine } private void GetDetails(ShowRoomA objShowRoom) { objShowRoom = new objShowRoom(); objShowRoom.audi = new audi(); objShowRoom.audi.Name = "AUDIMODEL94CD698"; objShowRoom.audi.AC = "6 TON"; objShowRoom.audi.PowerStearing = "Electric"; objShowRoom.benz= new benz(); objShowRoom.audi.Name = "BENZMODEL34LCX"; objShowRoom.audi.AC = "8 TON"; objShowRoom.audi.AirBag = "Two (1+1)"; objShowRoom.audi.MusicSystem = "Poineer 3500W"; } } // Till this cool. // Now I got requirement for ShowRoomB with replacement of old audi and benz with new models and new other brand cars also added. // I don't want to modify GetDetails() method. by reusing this method additional logic i want to apply to my new extended model. // Here I struck in designing my new model of ShowRoomB (base of ShowRoomA) ... I have tried some thing like... but not sure. public class audiModelB:audi { public string JetEngine { get; set; } } public class benzModelB:benz { public string JetEngine { get; set; } } public class ShowRoomB { public audiModelB AudiModelB { get; set; } public benzModelB benzModelB { get; set; } } // My new code to Implementation class like this class Main() { private void UpdateDetails() { ShowRoomB ojbNahi = new ShowRoomB(); GetDetails( ojbNahi ); // this is NOT working! I know this object does not contain base class directly, still some what i want fill my new model with old properties. Kindly suggest here } } Can any one please give me solutions how to achieve my extending requirement for base class "ShowroomA" Really appreciated your time and suggestions. Thanks in advance,

    Read the article

  • Is it possible for a parent to use a child's constant or static variables from inside a static metho

    - by ryeguy
    Below is an example of what I'm trying to do. The parent can't access any of the child's variables. It doesn't matter what technique I use (static or constants), I just need some kind of functionality like this. class ParentClass { public static function staticFunc() { //both of these will throw a (static|const) not defined error echo self::$myStatic; echo self::MY_CONSTANT; } } class ChildClass extends ParentClass { const MY_CONSTANT = 1; public static $myStatic = 2; } ChildClass::staticFunc();

    Read the article

  • Get data from Joomla jos_users table

    - by RobertR
    Hello, world! I'm trying to build a little bit advanced users system using Joomla, but I stuck at one spot. I added new field on Joomla's jos_users table, but when I wanted to get that field out, like "echo" - it didn't worked at all. Any other data, even password field I can get without problems. Of course, I added new value in /var/www/<project>/libraries/joomla/user/user.php like this after line 40. /** * The users address name * @var string */ var $address = null; What might be the problem here? Or what I did wrong, or what I didn't do at all? Thanks for replies! Cheerio

    Read the article

  • Using Zend_Db and multiple tables

    - by Yacoby
    I have a normalized database that stores locations of files on the internet. A file may have multiple locations spread across different sites. I am storing the urls in two parts (Site.UrlStart, FileLocation.UrlEnd). The UrlEnd is the part unique to that file (for the site). Simplified Db structure: I am using Zend_Db as my ORM (If it is that), with classes for the tables inheriting from Zend_Db_Table_Abstract. The issue is that retrieving the location data (e.g. the url) requires the use of multiple tables and as far as I can make out and I would either have to use both table classes (thereby exposing my table structure) or scatter sql all over my application, neither of which sound appealing. The only solution I can see is to create a façade that acts like Zend_Db_Table_Abstract (Maybe inherits from it?) and hides the fact that the data is actually on two tables. My questions are as follows: Am I going in the right direction in creating a façade class (Are there other alternatives)? Should the facade class inherit from Zend_Db_Table_Abstract?

    Read the article

  • JavaScript prototype(ing) question

    - by OneNerd
    Trying to grasp Prototyping in Javascript. Trying to create my own namespace to extend the String object in JavaScript. Here is what I have so far (a snippet): var ns { alert: function() { alert (this); } } String.prototype.$ns = ns; As you can see, I am trying to place what will be a series of functions into the ns namespace. So I can execute a command like this: "hello world".$ns.alert(); But the problem is, the this doesn't seem to reference the text being sent (in this case, "hello world"). What I get is an alert box with the following: [object Object] Not having a full grasp of the object-oriented nature of JavaScript, I am at a loss, but I am guessing I am missing something simple. Does anyone know how to achieve this? Thanks -

    Read the article

  • Is fetching data from database a get-method thing?

    - by theva
    I have a small class that I call Viewer. This class is supposed to view the proper layout of each page or something like that... I have a method called getFirstPage, when called the user of this method will get a setting value for which page is currently set as the first page. I have some code here, I think it works but I am not really shure that I have done it the right way: class Viewer { private $db; private $user; private $firstPage; function __construct($db, $user) { $this->db = $db; if(isset($user)) { $this->user = $user; } else { $this->user = 'default'; } } function getFistPage() { $std = $db->prepare("SELECT firstPage FROM settings WHERE user = ':user'"); $std->execute(array(':user' => $user)); $result = $std->fetch(); $this->firstPage = $result['firstPage']; return $this->firstPage; } } My get method is fetching the setting from databse (so far so good?). The problem is that then I have to use this get method to set the private variable firstPage. It seems like I should have a set method to do this, but I cannot really have a set method that just fetch some setting from database, right? Because the user of this object should be able to assume that there already is a setting defined in the object... How should I do that?

    Read the article

  • What pattern is this? php

    - by user151841
    I have several classes that are basically interfaces to database rows. Since the class assumes that a row already exists ( __construct expects a field value ), there is a public static function that allows creation of the row and returns an instance of the class. Here's an example ( without the actual database inserts ): class selfStarter { public $type; public function __construct( $type ) { $this->type = $type; } public static function create( $type ) { if ( ! empty($type) ) { $starter = & new selfStarter($type); return $starter; } } } $obj1 = selfStarter::create( "apple" ); $obj2 = & new selfStarter( "banana" ); What is this pattern called?

    Read the article

  • Interesting OOPS puzzle

    - by user3714387
    Recently, faced the below question from one of the interviewer. Initially thought that the question was wrong, but the interviewer mentioned there is solution for this. Quite interesting. Can anyone shed light please ? Program as below. public class BaseHome { public static void main() { Console.WriteLine("A"); } } Required output : B A C Condition : Should not make any change in the Main function. Should not create any additional class. Please advice if this can be done with the condition met.

    Read the article

  • How to access constant defined in child class from parent class functions?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

    Read the article

  • private classes inside namespaces

    - by blacklion
    Is there a way to restrict access to a class from outside a namespace? What I want is to have a class that is only accessible to other classes inside the same namespace without having to put the namespace in it's own assembly. Is there a reason this is not possible in C#?

    Read the article

  • pass variable by reference within class? in php

    - by user151841
    I'm working on a hex color class where you can change the color values of any hex code color. In my example, I haven't finished the hex math, but it's not completely relevant to what I'm explaining here. Naively, I wanted to start to do something that I don't think can be done. I wanted to pass object properties in a method call. Is this possible? class rgb { private $r; private $b; private $g; public function __construct( $hexRgb ) { $this->r = substr($hexRgb, 0, 2 ); $this->g = substr($hexRgb, 2, 2 ); $this->b = substr($hexRgb, 4, 2 ); } private function add( & $color, $amount ) { $color += amount; // $color should be a class property, $this->r, etc. } public function addRed( $amount ) { self::add( $this->r, $amount ); } public function addGreen( $amount ) { self::add( $this->g, $amount ); } public function addBlue( $amount ) { self::add( $this->b, $amount ); } } If this is not possible in PHP, what is this called and in what languages is it possible? I know I could do something like public function add( $var, $amount ) { if ( $var == "r" ) { $this->r += $amount } else if ( $var == "g" ) { $this->g += $amount } ... } But I want to do it this cool way.

    Read the article

  • PHP class extends not working why and is this how to correctly extend a class?

    - by Matthew
    Hi so I'm trying to understand how inherteince works in PHP using object oriented programming. The main class is Computer, the class that is inheriting is Mouse. I'm extedning the Computer class with the mouse class. I use __construct in each class, when I istinate the class I use the pc type first and if it has mouse after. For some reason computer returns null? why is this? class Computer { protected $type = 'null'; public function __construct($type) { $this->type = $type; } public function computertype() { $this->type = strtoupper($this->type); return $this->type; } } class Mouse extends Computer { protected $hasmouse = 'null'; public function __construct($hasmouse){ $this->hasmouse = $hasmouse; } public function computermouse() { if($this->hasmouse == 'Y') { return 'This Computer has a mouse'; } } } $pc = new Computer('PC', 'Y'); echo $pc->computertype; echo $pc->computermouse;

    Read the article

  • Three customer addresses in one table or in separate tables?

    - by DR
    In my application I have a Customer class and an Address class. The Customer class has three instances of the Address class: customerAddress, deliveryAddress, invoiceAddress. Whats the best way to reflect this structure in a database? The straightforward way would be a customer table and a separate address table. A more denormalized way would be just a customer table with columns for every address (Example for "street": customer_street, delivery_street, invoice_street) What are your experiences with that? Are there any advantages and disadvantages of these approaches?

    Read the article

  • How to iterate over numerically named object properties

    - by Scott Schluer
    So I have a horribly designed class that I can't change that has properties like this: object.Color1 object.Color2 object.Color3 etc... How can I iterate through those with a for loop. In other words, something like this: for (int i = 0; i <= 40; i++) { string PropertyName = "Color" + i; if (object.PropertyName != "") { // do something } } Obviously this code wouldn't work but it gives you an idea of what I'm after. I have to do some processing on each property and I don't want to repeat my code 40 times. :) A loop would be perfect, I'm just not sure how to create the name of the property on the fly.

    Read the article

  • An issue on object orientation in php

    - by rabidmachine9
    Hello people, I have come up to issues while I'm trying to write some classes, here is an example: I have this class called TwitterGrub and I cant call it like that: $c = new TwitterGrub(); $c->twitterDisplay(); here is the class itself: <?php class TwitterGrub{ function twitterCapture($user = 'username',$password = 'pass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum = 2){ $xml = $this::twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class= 'curvebox'>".$xml->status[$i]->text."</div>"; } } } ?> The problem is that everytime I want to change the username or password I have to jump back to class definition and that makes things not modular... and in many ways it feels wrong. So the question is what would be the proper way to chance my username and password through the objects interface and then call twitterDisplay() method with the new data?Hope that makes sense. Thanks in advance

    Read the article

  • Do you use Python mostly for its functional or object-oriented features?

    - by Eric
    I see what seems like a majority of Python developers on StackOverflow endorsing the use of concise functional tools like lambdas, maps, filters, etc., while others say their code is clearer and more maintainable by not using them. What is your preference? Also, if you are a die-hard functional programmer or hardcore into OO, what other specific programming practices do you use that you think are best for your style? Thanks in advance for your opinions!

    Read the article

  • How to manage member variable in C++

    - by rhapsodyn
    In brief, my question is about member variables as pointers in unmanaged C++. In java or c#, we have "advanced pointer". In fact, we can't aware the "pointer" in them. We usually initialize the member of a class like this: member = new Member(); or member = null; But in c++, it becomes more confusing. I have seen many styles: using new, or leave the member variable in stack. In my point of view, using boost::shared_ptr seems friendly, but in boost itself source code there are news everywhere. It's the matter of efficiency,isn't it? Is there a guildline like "try your best to avoid new" or something?

    Read the article

  • Why does this program stop running?

    - by designloper
    Hi everyone....I am developing a card making system...nothing fancy. Right got this far but program now stops running with no error when running after the first card sample i.e. " Enter 'OK' if this card is OK, otherwise enter an alternative border character: + ". Any suggestions Java Masters? //Ask user for input //makes use of print line method System.out.println("Enter name: "); //took the variables //called the object of the scanner 'cardOrder' //and use the Scanner objects method '.nextLine' //to read the next line of the input firstName = cardOrder.nextLine(); mInitial = cardOrder.nextLine(); lastName = cardOrder.nextLine(); //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); //test if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } else if(b == optionA) { //Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n+ +" + "\n+" + " " + firstName + mInitial + lastName + " +" + "\n+ +\n" + firstName + mInitial + lastName +"++++++++++++++" + "++++++++++++++" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: OK "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } } else if (c == optionA) {//Print out the "Here is a sample card" + the first name, middle initial and last name System.out.println("Here is a sample card: \n\n" + firstName + mInitial + lastName + "**************" + "**************" + firstName + mInitial + lastName + "\n* *" + "\n*" + " " + firstName + mInitial + lastName + " *" + "\n* *\n" + firstName + mInitial + lastName +"**************" + "**************" + firstName + mInitial + lastName + "\n"); //Ask user is the card is OK to proceed to order query or if they want an alternative border character: + System.out.println("Enter 'OK' if this card is OK, otherwise enter an alternative border character: + "); //Check if user entered "OK" and store it in var optionA optionA = cardOrder.nextLine(); if (a == optionA){ System.out.println("\nHow many cards would you like? "); cardsOrdered = cardOrder.nextInt(); equals = (int) (cardPriceA * cardsOrdered); System.out.println("The price of " + cardsOrdered + " cards"+ " is £" + equals + ".\n"); System.out.println("No Discount given."); } }

    Read the article

< Previous Page | 48 49 50 51 52 53 54 55 56 57 58 59  | Next Page >