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  • How can I check with a regex that a string contains only certain allowed characters?

    - by Camran
    I need a special regular expression, have no experience in them whatsoever so I am turning to you guys on this one: I need to validate a classifieds title field so it doesn't have any special characters in it, almost. Only letters and numbers should be allowed, and also the swedish three letters å, ä, ö, and also not case sensitive. Besides the above, these should also be allowed: The "&" sign. Parenthesis sign "()" Mathematical signs "-", "+", "%", "/", "*" Dollar and Euro signs One accent signed letter: "é". //Only this one is required Double quote and singel quote signs. The comma "," and point "." signs Thanks

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  • Regex for Password Must be contain at least 8 characters, least 1 number and both lower and uppercase letters and special characters

    - by user2442653
    I want a regular expression to check that Password Must be contain at least 8 characters, including at least 1 number and includes both lower and uppercase letters and special characters (e.g., #, ?, !) Cannot be your old password or contain your username, "password", or "websitename" And here is my validation expression which is for 8 characters including 1 uppercase letter, 1 lowercase letter, 1 number or special character. (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$" How I can write it for password must be 8 characters including 1 uppercase letter, 1 special character and alphanumeric characters?

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  • What's the RegEx to make sure that delimiters are escaped?

    - by Kuyenda
    I'm looking for a regular expression that will check whether or not delimiters in a string are escaped with a backward slash. The delimiters I am concerned about are comma (\,), colon (\:), semicolon (\;) and of course the backward slash itself has to be escaped (\). For example, the string "test" should return a match because there are no delimiters in it, and no escaping is necessary. The string "te\;st" would return a match because the semicolon delimiter is escaped. "te;st" and "t\;s:t" would both fail because the both contain at least one delimiter that is not escaped. I know that I need a conditional and a positive look behind, and this is what I have so far, but it is not giving me the expected answer. ^(?<delimiter>[:;,\\])?(?(delimiter)\(?<=(?:\\\\)*\\)k<delimiter>|.)$ Any suggestions on how I can make this work? Thanks.

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  • After grouping by, can I refer to the elements of the original IEnumerable in a LINQ query?

    - by michielvoo
    Example: from OriginalObject in ListOfOriginalObjects group new CustomObject { X = OriginalObject.A, Y = OriginalObject.B } by OriginalObject.Z into grouping select new GroupOfCustomObjects { Z = grouping.Key, C = OriginalObject.C, group = grouping } In the select part of the query, I'd like to add a property (OriginalObject.C) to the type GroupOfCustomObjects. But it seems that OriginalObject is out of scope in that part of the query. I can sort of understand why, since I am not grouping on that property and I am also not making that property part of CustomObject that I'm grouping. One workaround is to add a property C to CustomObject and the in the GroupOfCustomObjects read the value of the first CustomObject in the grouping. My issue with that is that I'm adding a property to an object that doesn't need it (CustomObject), just to be able to add it to the GroupOfCustomObjects. I hope I have explained this properly! Is there a way to refer to the OriginalObject that the query starts with? Thanks!

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  • Regex to catch all files but those starting with "."

    - by tmslnz
    In a directory with mixed content such as: .afile .anotherfile bfile.file bnotherfile.file .afolder/ .anotherfolder/ bfolder/ bnotherfolder/ How would you catch everything but the files (not dirs) starting with .? I have tried with a negative lookahead ^(?!\.).+? but it doesn't seem to work right. Please note that I would like to avoid doing it by excluding the . by using [a-zA-Z< plus all other possible chars minus the dot >] Any suggestions?

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  • How to replace href using javascript regex in Firefox?

    - by Andrei
    I try to change some links on a webpage using the following code for jQuery on Rails $(function () { $('#lesson a').live('click', function () { $.getScript(this.href.replace(/^(http...[^\/]+)?\/+(.*)$/,'/ajax/\\$2')); return false; }); }) This trick works for Chrome and Safari, but fails (nothing happens on click) for Firefox and Opera. What can be wrong with the code? EDIT1: The webpage contains: <div id="lesson"> <a href="/subj1">Subject 1</a> ... </div> On click, a browser (i.e. Firefox and Opera) should make an ajax-request of /ajax/subj1.

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  • Removing certain characters in all rows that match a regex?

    - by user001
    I'd like to change {foo, {bar}, foobar} to {foo, bar, foobar} in all rows that match '{.*{'. I.e. remove all curly braces { and } except the outer most pair. So doing mysql -h $H -u $U -p$P $DB -B -e "SELECT id FROM t WHERE col REGEXP '{.*{'" > bad.txt selects all the rows that will need this substitution. How do I make this substitution very quickly? EDIT: Could I do it by update table set column = REPLACE(column,'{',''); Then restore the out most pair update table set column = REPLACE(column,'^','{'); update table set column = REPLACE(column,'$','}');

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  • How to understand the output of the PHP regex matching below?

    - by smarty
    $file = '{include file="{$COMMON_TPL_PATH}common/header_admin.tpl"} {include file="{$mainPage}"} {include file="{$COMMON_TPL_PATH}common/footer_admin.tpl"}'; preg_match('/^(\{\})|^(\{\*([\S\s]*?)\*\})|^(<\?(?:php\w+|=|[a-zA-Z]+)?)|^([ ]*[ ]+[ ]*)|^(\{strip\})|^(\{\/strip\})|^(\{literal\})|^(\{\s{1,}\/)|^(\{\s{1,})|^(\{\/)|^(\{)|^(([\S\s]*?)(?=([ ]*[ ]+[ ]*|\{|<\?)))|^([\S\s]+)/', $file, $matches); var_dump($matches); Why the output is: array(13) { [0]=> string(1) "{" [1]=> string(0) "" [2]=> string(0) "" [3]=> string(0) "" [4]=> string(0) "" [5]=> string(0) "" [6]=> string(0) "" [7]=> string(0) "" [8]=> string(0) "" [9]=> string(0) "" [10]=> string(0) "" [11]=> string(0) "" [12]=> string(1) "{" } It seems to me that ^([\S\s]+) can match the whole string..

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  • Regex to split a string (in Java) so that spaces are preserved?

    - by david
    I need to split a string (in Java) into individual words ... but I need to preserve spaces. An example of the text I need to split is something like this: ABC . . . . DEF . . . . GHI I need to see "ABC", " . . . .", "DEF", ". . . .", and "GHI". Obviously splitting on the space character \s isn't going to work, as all the spaces get swallowed up as one space. Any suggestions? Thanks

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  • Extracting two strings from quotations in Java using regex?

    - by user656710
    Hi everyone, I'm new to using patterns and looked everywhere on the internet for an explanation to this problem. Say I have a string: String info = "Data I need to extract is 'here' and 'also here'"; How would I extract the words: here also here without the single quotes using a pattern? This is what I have so far... Pattern p = Pattern.compile("(?<=\').*(?=\')"); But it returns ( here and 'also here ) minus the brackets, that is just for viewing. It skips over the second piece of data and goes straight to the last quote... Thank you!

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  • PHP Regex. How to remove all element anchor tags but keep anchor tags with certain href attribute contain JPG|PNG|GIF

    - by namaku doni
    input <a href="http://mysite.com">My Site</a> <a href="http://mysite.com/image.jpg"><img src="http://mysite.com/image.jpg"/></a> <a href="http://mysite.com/image.gif"><img src="http://mysite.com/image.gif"/></a> <a href="http://yoursite.com">Your Site</a> output <a href="http://mysite.com/image.jpg"><img src="http://mysite.com/image.jpg"/></a> <a href="http://mysite.com/image.gif"><img src="http://mysite.com/image.gif"/></a> Thank's for help

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  • meaning of (\/?) in regex / is (\w+)([^>]*?) a redundancy?

    - by thomas
    this regular expression should match an html start tag, I think. var results = html.match(/<(\/?)(\w+)([^>]*?)>/); I see it should first capture the <, but then I am confused what this capture (\/?) accomplishes. Am I correct in reasoning that the ([^>]*?)> searches for every character except > = 0 times? If so, why is the (\w+) capture necessary? Doesn't it fall within the purview of [^>]*?

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  • Python - Find where in string regex match was found?

    - by nb
    I'm currently using regular expressions to search through RSS feeds to find if certain words and phrases are mentioned, and would then like to extract the text on either side of the match as well. For example: String = "This is an example sentence, it is for demonstration only" re.search("is", String) I'd like to know where the is was found so that I can extract and output something like this: 1 match found: "This is an example sentence" I know that it would be easy to do with splits, but I'd need to know what the index of first character of the match was in the string, which I don't know how to find

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  • What be the regex to determine whether there is date in the string or not with different date format

    - by Harikrishna
    I am parsing table information from the html table.Now I want to check whether there is date in the records for one particular column.Means I want to check whether there is date in the string or not .And date can be in different format like the string can be FUTIDX 26FEB2009 NIFTY 0 -- There is date in the string. FUTIDX MINIFTY 30 Jul 2009 -- There is date in the string. FUTSTK ONGC 27 Mar 2008 -- There is date in the string. What should be the regular expression for that ?

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  • How to match !x but not !!x in JS regex?

    - by mpeterson
    Given the following text: This is!!xa simple string!xpattern I would like to get a regexp that matches the !x that's between "string" and "pattern" but not !!xa that's between "is" and "a". This regexp is to be used inside a string split(). I have tried several combinations but I cannot get a regexp that meets my needs. Perhaps my expression is not so regular after all =) Thanks in advance!

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  • Using Find/Replace with regular expressions inside a SSIS package

    - by jamiet
    Another one of those might-be-useful-again-one-day-so-I’ll-share-it-in-a-blog-post blog posts I am currently working on a SQL Server Integration Services (SSIS) 2012 implementation where each package contains a parameter called ETLIfcHist_ID: During normal execution this will get altered when the package is executed from the Execute Package Task however we want to make sure that at deployment-time they all have a default value of –1. Of course, they tend to get changed during development so I wanted a way of easily changing them all back to the default value. Opening up each package in turn and editing them was an option but given that we have over 40 packages and we might want to carry out this reset fairly frequently I needed a more automated method so I turned to Visual Studio’s Find/Replace… feature Of course, we don’t know what value will be in that parameter so I can’t simply search for a particular value; hence I opted to use a regular expression to identify the value to be change. In the rest of this blog post I’ll explain how to do that. For demonstration purposes I have taken the contents of a .dtsx file and stripped out everything except the element containing the parameters (<DTS:PackageParameters>), if you want to play along at home you can copy-paste the XML document below into a new XML file and open it up in Visual Studio: <?xml version="1.0"?> <DTS:Executable xmlns:DTS="www.microsoft.com/SqlServer/Dts">   <DTS:PackageParameters>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="InterfaceHistory_ID: used for Lineage"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25846C7E}"       DTS:ObjectName="ETLIfcHist_ID">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">VALUE_TO_BE_CHANGED</DTS:Property>     </DTS:PackageParameter>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="Some other description"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25845C7E}"       DTS:ObjectName="SomeOtherObjectName">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">SomeOtherValue</DTS:Property>     </DTS:PackageParameter>   </DTS:PackageParameters> </DTS:Executable> We are trying to identify the value of the parameter whose name is ETLIfcHist_ID – notice that in the XML document above that value is VALUE_TO_BE_CHANGED. The following regular expression will find the appropriate portion of the XML document: {\<DTS\:PackageParameter[\n ]*DTS\:CreationName="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:DataType="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:Description="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:DTSID="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:ObjectName="ETLIfcHist_ID"\>[\n ]*\<DTS\:Property[\n ]*DTS\:DataType="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:Name="ParameterValue"\>}[A-Za-z0-9\:_\{\}- ]*{\<\/DTS\:Property\>} I have highlighted the name of the parameter that we’re looking for. I have also highlighted two portions identified by pairs of curly braces “{…}”; these are important because they pick out the two portions either side of the value I want to replace, in other words the portions highlighted here: <DTS:PackageParameters>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="InterfaceHistory_ID: used for Lineage"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25846C7E}"       DTS:ObjectName="ETLIfcHist_ID">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">VALUE_TO_BE_CHANGED</DTS:Property>     </DTS:PackageParameter> Those sections in the curly braces are termed tag expressions and can be identified in the replace expression using a backslash and a number identifying which tag expression you’re referring to according to its ordinal position. Hence, our replace expression is simply: \1-1\2 We’re saying the portion of our file identified by the regular expression should be replaced by the first curly brace section, then the literal –1, then the second curly brace section. Make sense? Give it a go yourself by plugging those two expressions into Visual Studio’s Find and Replace dialog. If you set it to look in “All Open Documents” then you can open up the code-behind of all your packages and change all of them at once. The Find and Replace dialog will look like this: That’s it! I realise that not everyone will be looking to change the value of a parameter but hopefully I have shown you a technique that you can modify to work for your own scenario. Given that this blog post is, y’know, on the web I have no doubt that someone is going to find a fault with my find regex expression and if that person is you….that’s OK. Let me know about it in the comments below and perhaps we can work together to come up with something better! Note that some parameters may have a different set of properties (for example some, but not all, of my parameters have a DTS:Required attribute) so your find regular expression may have to change accordingly. When researching this I found the following article to be invaluable: Visual Studio Find/Replace Regular Expression Usage @Jamiet

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